\(\int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {-d e+(d^2+e^2) x^2-d e x^4}} \, dx\) [139]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [B] (verified)
Fricas [A] (verification not implemented)
Sympy [F]
Maxima [F]
Giac [F(-1)]
Mupad [F(-1)]
Reduce [B] (verification not implemented)

Optimal result

Integrand size = 47, antiderivative size = 148 \[ \int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}} \, dx=-\frac {B \text {arctanh}\left (\frac {\sqrt {d} x \sqrt {d-e x^2}}{\sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}}\right )}{\sqrt {d} e}+\frac {(B d+A e) \text {arctanh}\left (\frac {\sqrt {d^2-e^2} x \sqrt {d-e x^2}}{\sqrt {d} \sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}}\right )}{\sqrt {d} e \sqrt {d^2-e^2}} \] Output:

-B*arctanh(d^(1/2)*x*(-e*x^2+d)^(1/2)/(-d*e+(d^2+e^2)*x^2-d*e*x^4)^(1/2))/ 
d^(1/2)/e+(A*e+B*d)*arctanh((d^2-e^2)^(1/2)*x*(-e*x^2+d)^(1/2)/d^(1/2)/(-d 
*e+(d^2+e^2)*x^2-d*e*x^4)^(1/2))/d^(1/2)/e/(d^2-e^2)^(1/2)
 

Mathematica [A] (verified)

Time = 0.55 (sec) , antiderivative size = 183, normalized size of antiderivative = 1.24 \[ \int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}} \, dx=\frac {\sqrt {-e+d x^2} \sqrt {d-e x^2} \left ((B d+A e) \sqrt {-d^2+e^2} \arctan \left (\frac {d^{3/2}-\sqrt {d} e x^2+e x \sqrt {-e+d x^2}}{\sqrt {d} \sqrt {-d^2+e^2}}\right )+B \left (d^2-e^2\right ) \log \left (-\sqrt {d} x+\sqrt {-e+d x^2}\right )\right )}{\sqrt {d} (d-e) e (d+e) \sqrt {d^2 x^2+e^2 x^2-d e \left (1+x^4\right )}} \] Input:

Integrate[(A + B*x^2)/(Sqrt[d - e*x^2]*Sqrt[-(d*e) + (d^2 + e^2)*x^2 - d*e 
*x^4]),x]
 

Output:

(Sqrt[-e + d*x^2]*Sqrt[d - e*x^2]*((B*d + A*e)*Sqrt[-d^2 + e^2]*ArcTan[(d^ 
(3/2) - Sqrt[d]*e*x^2 + e*x*Sqrt[-e + d*x^2])/(Sqrt[d]*Sqrt[-d^2 + e^2])] 
+ B*(d^2 - e^2)*Log[-(Sqrt[d]*x) + Sqrt[-e + d*x^2]]))/(Sqrt[d]*(d - e)*e* 
(d + e)*Sqrt[d^2*x^2 + e^2*x^2 - d*e*(1 + x^4)])
 

Rubi [A] (verified)

Time = 0.31 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.01, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.128, Rules used = {1395, 398, 224, 219, 291, 221}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {x^2 \left (d^2+e^2\right )-d e x^4-d e}} \, dx\)

\(\Big \downarrow \) 1395

\(\displaystyle \frac {\sqrt {d x^2-e} \sqrt {d-e x^2} \int \frac {B x^2+A}{\sqrt {d x^2-e} \left (d-e x^2\right )}dx}{\sqrt {x^2 \left (d^2+e^2\right )-d e x^4-d e}}\)

\(\Big \downarrow \) 398

\(\displaystyle \frac {\sqrt {d x^2-e} \sqrt {d-e x^2} \left (\frac {(A e+B d) \int \frac {1}{\sqrt {d x^2-e} \left (d-e x^2\right )}dx}{e}-\frac {B \int \frac {1}{\sqrt {d x^2-e}}dx}{e}\right )}{\sqrt {x^2 \left (d^2+e^2\right )-d e x^4-d e}}\)

\(\Big \downarrow \) 224

\(\displaystyle \frac {\sqrt {d x^2-e} \sqrt {d-e x^2} \left (\frac {(A e+B d) \int \frac {1}{\sqrt {d x^2-e} \left (d-e x^2\right )}dx}{e}-\frac {B \int \frac {1}{1-\frac {d x^2}{d x^2-e}}d\frac {x}{\sqrt {d x^2-e}}}{e}\right )}{\sqrt {x^2 \left (d^2+e^2\right )-d e x^4-d e}}\)

\(\Big \downarrow \) 219

\(\displaystyle \frac {\sqrt {d x^2-e} \sqrt {d-e x^2} \left (\frac {(A e+B d) \int \frac {1}{\sqrt {d x^2-e} \left (d-e x^2\right )}dx}{e}-\frac {B \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {d x^2-e}}\right )}{\sqrt {d} e}\right )}{\sqrt {x^2 \left (d^2+e^2\right )-d e x^4-d e}}\)

\(\Big \downarrow \) 291

\(\displaystyle \frac {\sqrt {d x^2-e} \sqrt {d-e x^2} \left (\frac {(A e+B d) \int \frac {1}{d-\frac {\left (d^2-e^2\right ) x^2}{d x^2-e}}d\frac {x}{\sqrt {d x^2-e}}}{e}-\frac {B \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {d x^2-e}}\right )}{\sqrt {d} e}\right )}{\sqrt {x^2 \left (d^2+e^2\right )-d e x^4-d e}}\)

\(\Big \downarrow \) 221

\(\displaystyle \frac {\sqrt {d x^2-e} \sqrt {d-e x^2} \left (\frac {(A e+B d) \text {arctanh}\left (\frac {x \sqrt {d^2-e^2}}{\sqrt {d} \sqrt {d x^2-e}}\right )}{\sqrt {d} e \sqrt {d^2-e^2}}-\frac {B \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {d x^2-e}}\right )}{\sqrt {d} e}\right )}{\sqrt {x^2 \left (d^2+e^2\right )-d e x^4-d e}}\)

Input:

Int[(A + B*x^2)/(Sqrt[d - e*x^2]*Sqrt[-(d*e) + (d^2 + e^2)*x^2 - d*e*x^4]) 
,x]
 

Output:

(Sqrt[-e + d*x^2]*Sqrt[d - e*x^2]*(-((B*ArcTanh[(Sqrt[d]*x)/Sqrt[-e + d*x^ 
2]])/(Sqrt[d]*e)) + ((B*d + A*e)*ArcTanh[(Sqrt[d^2 - e^2]*x)/(Sqrt[d]*Sqrt 
[-e + d*x^2])])/(Sqrt[d]*e*Sqrt[d^2 - e^2])))/Sqrt[-(d*e) + (d^2 + e^2)*x^ 
2 - d*e*x^4]
 

Defintions of rubi rules used

rule 219
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 221
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 224
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], 
x, x/Sqrt[a + b*x^2]] /; FreeQ[{a, b}, x] &&  !GtQ[a, 0]
 

rule 291
Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*((c_) + (d_.)*(x_)^2)), x_Symbol] :> Subst 
[Int[1/(c - (b*c - a*d)*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a, b, c, 
d}, x] && NeQ[b*c - a*d, 0]
 

rule 398
Int[((e_) + (f_.)*(x_)^2)/(((a_) + (b_.)*(x_)^2)*Sqrt[(c_) + (d_.)*(x_)^2]) 
, x_Symbol] :> Simp[f/b   Int[1/Sqrt[c + d*x^2], x], x] + Simp[(b*e - a*f)/ 
b   Int[1/((a + b*x^2)*Sqrt[c + d*x^2]), x], x] /; FreeQ[{a, b, c, d, e, f} 
, x]
 

rule 1395
Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_)*((d_) + (e_.)*( 
x_)^(n_))^(q_.), x_Symbol] :> Simp[(a + b*x^n + c*x^(2*n))^FracPart[p]/((d 
+ e*x^n)^FracPart[p]*(a/d + c*(x^n/e))^FracPart[p])   Int[u*(d + e*x^n)^(p 
+ q)*(a/d + (c/e)*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, n, p, q}, x] && E 
qQ[n2, 2*n] && EqQ[c*d^2 - b*d*e + a*e^2, 0] &&  !IntegerQ[p] &&  !(EqQ[q, 
1] && EqQ[n, 2])
 
Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(828\) vs. \(2(128)=256\).

Time = 0.39 (sec) , antiderivative size = 829, normalized size of antiderivative = 5.60

method result size
default \(\frac {\sqrt {-d e \,x^{4}+d^{2} x^{2}+e^{2} x^{2}-d e}\, \left (B \,d^{\frac {7}{2}} \ln \left (\frac {2 \sqrt {d e}\, d x +2 \sqrt {d \,x^{2}-e}\, \sqrt {\frac {d^{2}-e^{2}}{e}}\, e -2 e^{2}}{e x -\sqrt {d e}}\right )-B \,d^{\frac {7}{2}} \ln \left (-\frac {2 \left (\sqrt {d e}\, d x -\sqrt {d \,x^{2}-e}\, \sqrt {\frac {d^{2}-e^{2}}{e}}\, e +e^{2}\right )}{e x +\sqrt {d e}}\right )+A \,d^{\frac {5}{2}} \ln \left (\frac {2 \sqrt {d e}\, d x +2 \sqrt {d \,x^{2}-e}\, \sqrt {\frac {d^{2}-e^{2}}{e}}\, e -2 e^{2}}{e x -\sqrt {d e}}\right ) e -A \,d^{\frac {5}{2}} \ln \left (-\frac {2 \left (\sqrt {d e}\, d x -\sqrt {d \,x^{2}-e}\, \sqrt {\frac {d^{2}-e^{2}}{e}}\, e +e^{2}\right )}{e x +\sqrt {d e}}\right ) e -B \,d^{\frac {3}{2}} \ln \left (\frac {2 \sqrt {d e}\, d x +2 \sqrt {d \,x^{2}-e}\, \sqrt {\frac {d^{2}-e^{2}}{e}}\, e -2 e^{2}}{e x -\sqrt {d e}}\right ) e^{2}+B \,d^{\frac {3}{2}} \ln \left (-\frac {2 \left (\sqrt {d e}\, d x -\sqrt {d \,x^{2}-e}\, \sqrt {\frac {d^{2}-e^{2}}{e}}\, e +e^{2}\right )}{e x +\sqrt {d e}}\right ) e^{2}-A \sqrt {d}\, \ln \left (\frac {2 \sqrt {d e}\, d x +2 \sqrt {d \,x^{2}-e}\, \sqrt {\frac {d^{2}-e^{2}}{e}}\, e -2 e^{2}}{e x -\sqrt {d e}}\right ) e^{3}+A \sqrt {d}\, \ln \left (-\frac {2 \left (\sqrt {d e}\, d x -\sqrt {d \,x^{2}-e}\, \sqrt {\frac {d^{2}-e^{2}}{e}}\, e +e^{2}\right )}{e x +\sqrt {d e}}\right ) e^{3}+2 A \sqrt {d e}\, \ln \left (\frac {\sqrt {d}\, \sqrt {-\frac {\left (d x +\sqrt {d e}\right ) \left (-d x +\sqrt {d e}\right )}{d}}+d x}{\sqrt {d}}\right ) \sqrt {\frac {d^{2}-e^{2}}{e}}\, d e -2 A d \sqrt {d e}\, \ln \left (\frac {\sqrt {d}\, \sqrt {d \,x^{2}-e}+d x}{\sqrt {d}}\right ) \sqrt {\frac {d^{2}-e^{2}}{e}}\, e +2 B \sqrt {d e}\, \ln \left (\frac {\sqrt {d}\, \sqrt {-\frac {\left (d x +\sqrt {d e}\right ) \left (-d x +\sqrt {d e}\right )}{d}}+d x}{\sqrt {d}}\right ) \sqrt {\frac {d^{2}-e^{2}}{e}}\, e^{2}-2 B \,d^{2} \sqrt {d e}\, \ln \left (\frac {\sqrt {d}\, \sqrt {d \,x^{2}-e}+d x}{\sqrt {d}}\right ) \sqrt {\frac {d^{2}-e^{2}}{e}}\right )}{2 \sqrt {-e \,x^{2}+d}\, \sqrt {d}\, \sqrt {d \,x^{2}-e}\, e \sqrt {d e}\, \left (d -e \right ) \left (d +e \right ) \sqrt {\frac {d^{2}-e^{2}}{e}}}\) \(829\)

Input:

int((B*x^2+A)/(-e*x^2+d)^(1/2)/(-d*e+(d^2+e^2)*x^2-d*e*x^4)^(1/2),x,method 
=_RETURNVERBOSE)
 

Output:

1/2/(-e*x^2+d)^(1/2)*(-d*e*x^4+d^2*x^2+e^2*x^2-d*e)^(1/2)/d^(1/2)*(B*d^(7/ 
2)*ln(2*((d*e)^(1/2)*d*x+(d*x^2-e)^(1/2)*((d^2-e^2)/e)^(1/2)*e-e^2)/(e*x-( 
d*e)^(1/2)))-B*d^(7/2)*ln(-2*((d*e)^(1/2)*d*x-(d*x^2-e)^(1/2)*((d^2-e^2)/e 
)^(1/2)*e+e^2)/(e*x+(d*e)^(1/2)))+A*d^(5/2)*ln(2*((d*e)^(1/2)*d*x+(d*x^2-e 
)^(1/2)*((d^2-e^2)/e)^(1/2)*e-e^2)/(e*x-(d*e)^(1/2)))*e-A*d^(5/2)*ln(-2*(( 
d*e)^(1/2)*d*x-(d*x^2-e)^(1/2)*((d^2-e^2)/e)^(1/2)*e+e^2)/(e*x+(d*e)^(1/2) 
))*e-B*d^(3/2)*ln(2*((d*e)^(1/2)*d*x+(d*x^2-e)^(1/2)*((d^2-e^2)/e)^(1/2)*e 
-e^2)/(e*x-(d*e)^(1/2)))*e^2+B*d^(3/2)*ln(-2*((d*e)^(1/2)*d*x-(d*x^2-e)^(1 
/2)*((d^2-e^2)/e)^(1/2)*e+e^2)/(e*x+(d*e)^(1/2)))*e^2-A*d^(1/2)*ln(2*((d*e 
)^(1/2)*d*x+(d*x^2-e)^(1/2)*((d^2-e^2)/e)^(1/2)*e-e^2)/(e*x-(d*e)^(1/2)))* 
e^3+A*d^(1/2)*ln(-2*((d*e)^(1/2)*d*x-(d*x^2-e)^(1/2)*((d^2-e^2)/e)^(1/2)*e 
+e^2)/(e*x+(d*e)^(1/2)))*e^3+2*A*(d*e)^(1/2)*ln((d^(1/2)*(-1/d*(d*x+(d*e)^ 
(1/2))*(-d*x+(d*e)^(1/2)))^(1/2)+d*x)/d^(1/2))*((d^2-e^2)/e)^(1/2)*d*e-2*A 
*d*(d*e)^(1/2)*ln((d^(1/2)*(d*x^2-e)^(1/2)+d*x)/d^(1/2))*((d^2-e^2)/e)^(1/ 
2)*e+2*B*(d*e)^(1/2)*ln((d^(1/2)*(-1/d*(d*x+(d*e)^(1/2))*(-d*x+(d*e)^(1/2) 
))^(1/2)+d*x)/d^(1/2))*((d^2-e^2)/e)^(1/2)*e^2-2*B*d^2*(d*e)^(1/2)*ln((d^( 
1/2)*(d*x^2-e)^(1/2)+d*x)/d^(1/2))*((d^2-e^2)/e)^(1/2))/(d*x^2-e)^(1/2)/e/ 
(d*e)^(1/2)/(d-e)/(d+e)/((d^2-e^2)/e)^(1/2)
 

Fricas [A] (verification not implemented)

Time = 0.12 (sec) , antiderivative size = 888, normalized size of antiderivative = 6.00 \[ \int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}} \, dx =\text {Too large to display} \] Input:

integrate((B*x^2+A)/(-e*x^2+d)^(1/2)/(-d*e+(d^2+e^2)*x^2-d*e*x^4)^(1/2),x, 
 algorithm="fricas")
 

Output:

[1/2*(sqrt(d^3 - d*e^2)*(B*d + A*e)*log(-(2*d^3*x^2 - (2*d^2*e - e^3)*x^4 
- d^2*e + 2*sqrt(-d*e*x^4 + (d^2 + e^2)*x^2 - d*e)*sqrt(d^3 - d*e^2)*sqrt( 
-e*x^2 + d)*x)/(e^2*x^4 - 2*d*e*x^2 + d^2)) + (B*d^2 - B*e^2)*sqrt(d)*log( 
-(2*d*e*x^4 - (2*d^2 + e^2)*x^2 + 2*sqrt(-d*e*x^4 + (d^2 + e^2)*x^2 - d*e) 
*sqrt(-e*x^2 + d)*sqrt(d)*x + d*e)/(e*x^2 - d)))/(d^3*e - d*e^3), 1/2*(2*s 
qrt(-d^3 + d*e^2)*(B*d + A*e)*arctan(sqrt(-d*e*x^4 + (d^2 + e^2)*x^2 - d*e 
)*sqrt(-d^3 + d*e^2)*sqrt(-e*x^2 + d)*x/(d^2*e*x^4 + d^2*e - (d^3 + d*e^2) 
*x^2)) + (B*d^2 - B*e^2)*sqrt(d)*log(-(2*d*e*x^4 - (2*d^2 + e^2)*x^2 + 2*s 
qrt(-d*e*x^4 + (d^2 + e^2)*x^2 - d*e)*sqrt(-e*x^2 + d)*sqrt(d)*x + d*e)/(e 
*x^2 - d)))/(d^3*e - d*e^3), -1/2*(2*(B*d^2 - B*e^2)*sqrt(-d)*arctan(sqrt( 
-d*e*x^4 + (d^2 + e^2)*x^2 - d*e)*sqrt(-e*x^2 + d)*sqrt(-d)*x/(d*e*x^4 - ( 
d^2 + e^2)*x^2 + d*e)) - sqrt(d^3 - d*e^2)*(B*d + A*e)*log(-(2*d^3*x^2 - ( 
2*d^2*e - e^3)*x^4 - d^2*e + 2*sqrt(-d*e*x^4 + (d^2 + e^2)*x^2 - d*e)*sqrt 
(d^3 - d*e^2)*sqrt(-e*x^2 + d)*x)/(e^2*x^4 - 2*d*e*x^2 + d^2)))/(d^3*e - d 
*e^3), (sqrt(-d^3 + d*e^2)*(B*d + A*e)*arctan(sqrt(-d*e*x^4 + (d^2 + e^2)* 
x^2 - d*e)*sqrt(-d^3 + d*e^2)*sqrt(-e*x^2 + d)*x/(d^2*e*x^4 + d^2*e - (d^3 
 + d*e^2)*x^2)) - (B*d^2 - B*e^2)*sqrt(-d)*arctan(sqrt(-d*e*x^4 + (d^2 + e 
^2)*x^2 - d*e)*sqrt(-e*x^2 + d)*sqrt(-d)*x/(d*e*x^4 - (d^2 + e^2)*x^2 + d* 
e)))/(d^3*e - d*e^3)]
 

Sympy [F]

\[ \int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}} \, dx=\int \frac {A + B x^{2}}{\sqrt {- \left (- d + e x^{2}\right ) \left (d x^{2} - e\right )} \sqrt {d - e x^{2}}}\, dx \] Input:

integrate((B*x**2+A)/(-e*x**2+d)**(1/2)/(-d*e+(d**2+e**2)*x**2-d*e*x**4)** 
(1/2),x)
 

Output:

Integral((A + B*x**2)/(sqrt(-(-d + e*x**2)*(d*x**2 - e))*sqrt(d - e*x**2)) 
, x)
 

Maxima [F]

\[ \int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}} \, dx=\int { \frac {B x^{2} + A}{\sqrt {-d e x^{4} + {\left (d^{2} + e^{2}\right )} x^{2} - d e} \sqrt {-e x^{2} + d}} \,d x } \] Input:

integrate((B*x^2+A)/(-e*x^2+d)^(1/2)/(-d*e+(d^2+e^2)*x^2-d*e*x^4)^(1/2),x, 
 algorithm="maxima")
 

Output:

integrate((B*x^2 + A)/(sqrt(-d*e*x^4 + (d^2 + e^2)*x^2 - d*e)*sqrt(-e*x^2 
+ d)), x)
 

Giac [F(-1)]

Timed out. \[ \int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}} \, dx=\text {Timed out} \] Input:

integrate((B*x^2+A)/(-e*x^2+d)^(1/2)/(-d*e+(d^2+e^2)*x^2-d*e*x^4)^(1/2),x, 
 algorithm="giac")
 

Output:

Timed out
 

Mupad [F(-1)]

Timed out. \[ \int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}} \, dx=\int \frac {B\,x^2+A}{\sqrt {d-e\,x^2}\,\sqrt {-d\,e\,x^4+\left (d^2+e^2\right )\,x^2-d\,e}} \,d x \] Input:

int((A + B*x^2)/((d - e*x^2)^(1/2)*(x^2*(d^2 + e^2) - d*e - d*e*x^4)^(1/2) 
),x)
 

Output:

int((A + B*x^2)/((d - e*x^2)^(1/2)*(x^2*(d^2 + e^2) - d*e - d*e*x^4)^(1/2) 
), x)
                                                                                    
                                                                                    
 

Reduce [B] (verification not implemented)

Time = 0.16 (sec) , antiderivative size = 412, normalized size of antiderivative = 2.78 \[ \int \frac {A+B x^2}{\sqrt {d-e x^2} \sqrt {-d e+\left (d^2+e^2\right ) x^2-d e x^4}} \, dx=\frac {\sqrt {d}\, \left (\sqrt {d^{2}-e^{2}}\, \mathrm {log}\left (2 \sqrt {d^{2}-e^{2}}\, d +2 \sqrt {d}\, \sqrt {d \,x^{2}-e}\, e x -2 d^{2}+2 d e \,x^{2}\right ) a e +\sqrt {d^{2}-e^{2}}\, \mathrm {log}\left (2 \sqrt {d^{2}-e^{2}}\, d +2 \sqrt {d}\, \sqrt {d \,x^{2}-e}\, e x -2 d^{2}+2 d e \,x^{2}\right ) b d -\sqrt {d^{2}-e^{2}}\, \mathrm {log}\left (\frac {-\sqrt {e}\, \sqrt {d^{2}-e^{2}}+\sqrt {d \,x^{2}-e}\, e +\sqrt {d}\, e x -\sqrt {e}\, d}{\sqrt {e}}\right ) a e -\sqrt {d^{2}-e^{2}}\, \mathrm {log}\left (\frac {-\sqrt {e}\, \sqrt {d^{2}-e^{2}}+\sqrt {d \,x^{2}-e}\, e +\sqrt {d}\, e x -\sqrt {e}\, d}{\sqrt {e}}\right ) b d -\sqrt {d^{2}-e^{2}}\, \mathrm {log}\left (\frac {\sqrt {e}\, \sqrt {d^{2}-e^{2}}+\sqrt {d \,x^{2}-e}\, e +\sqrt {d}\, e x +\sqrt {e}\, d}{\sqrt {e}}\right ) a e -\sqrt {d^{2}-e^{2}}\, \mathrm {log}\left (\frac {\sqrt {e}\, \sqrt {d^{2}-e^{2}}+\sqrt {d \,x^{2}-e}\, e +\sqrt {d}\, e x +\sqrt {e}\, d}{\sqrt {e}}\right ) b d -2 \,\mathrm {log}\left (\frac {\sqrt {d \,x^{2}-e}+\sqrt {d}\, x}{\sqrt {e}}\right ) b \,d^{2}+2 \,\mathrm {log}\left (\frac {\sqrt {d \,x^{2}-e}+\sqrt {d}\, x}{\sqrt {e}}\right ) b \,e^{2}\right )}{2 d e \left (d^{2}-e^{2}\right )} \] Input:

int((B*x^2+A)/(-e*x^2+d)^(1/2)/(-d*e+(d^2+e^2)*x^2-d*e*x^4)^(1/2),x)
 

Output:

(sqrt(d)*(sqrt(d**2 - e**2)*log(2*sqrt(d**2 - e**2)*d + 2*sqrt(d)*sqrt(d*x 
**2 - e)*e*x - 2*d**2 + 2*d*e*x**2)*a*e + sqrt(d**2 - e**2)*log(2*sqrt(d** 
2 - e**2)*d + 2*sqrt(d)*sqrt(d*x**2 - e)*e*x - 2*d**2 + 2*d*e*x**2)*b*d - 
sqrt(d**2 - e**2)*log(( - sqrt(e)*sqrt(d**2 - e**2) + sqrt(d*x**2 - e)*e + 
 sqrt(d)*e*x - sqrt(e)*d)/sqrt(e))*a*e - sqrt(d**2 - e**2)*log(( - sqrt(e) 
*sqrt(d**2 - e**2) + sqrt(d*x**2 - e)*e + sqrt(d)*e*x - sqrt(e)*d)/sqrt(e) 
)*b*d - sqrt(d**2 - e**2)*log((sqrt(e)*sqrt(d**2 - e**2) + sqrt(d*x**2 - e 
)*e + sqrt(d)*e*x + sqrt(e)*d)/sqrt(e))*a*e - sqrt(d**2 - e**2)*log((sqrt( 
e)*sqrt(d**2 - e**2) + sqrt(d*x**2 - e)*e + sqrt(d)*e*x + sqrt(e)*d)/sqrt( 
e))*b*d - 2*log((sqrt(d*x**2 - e) + sqrt(d)*x)/sqrt(e))*b*d**2 + 2*log((sq 
rt(d*x**2 - e) + sqrt(d)*x)/sqrt(e))*b*e**2))/(2*d*e*(d**2 - e**2))