Integrand size = 44, antiderivative size = 669 \[ \int \frac {A+B x^2+C x^4+D x^6}{x^6 \left (d+e x^2\right )^{3/2} \sqrt {a-c x^4}} \, dx=\frac {\left (d^3 D-C d^2 e+B d e^2-A e^3\right ) \sqrt {a-c x^4}}{d e \left (c d^2-a e^2\right ) x^5 \sqrt {d+e x^2}}-\frac {\left (\frac {A c d}{a}-5 C d+\frac {5 d^2 D}{e}+5 B e-\frac {6 A e^2}{d}\right ) \sqrt {d+e x^2} \sqrt {a-c x^4}}{5 d \left (c d^2-a e^2\right ) x^5}-\frac {\left (5 B c d^3-15 a d^3 D-9 A c d^2 e+15 a C d^2 e-20 a B d e^2+24 a A e^3\right ) \sqrt {d+e x^2} \sqrt {a-c x^4}}{15 a d^3 \left (c d^2-a e^2\right ) x^3}+\frac {\sqrt {c} \left (3 A \left (3 c^2 d^4+8 a c d^2 e^2-16 a^2 e^4\right )+5 a d \left (c d^2 (3 C d-5 B e)+a e \left (3 d^2 D-6 C d e+8 B e^2\right )\right )\right ) \sqrt {1-\frac {a}{c x^4}} x^3 \sqrt {\frac {\sqrt {a} \left (d+e x^2\right )}{\left (\sqrt {c} d+\sqrt {a} e\right ) x^2}} E\left (\arcsin \left (\frac {\sqrt {1-\frac {\sqrt {a}}{\sqrt {c} x^2}}}{\sqrt {2}}\right )|\frac {2 d}{d+\frac {\sqrt {a} e}{\sqrt {c}}}\right )}{15 a^2 d^4 \left (\sqrt {c} d-\sqrt {a} e\right ) \sqrt {d+e x^2} \sqrt {a-c x^4}}+\frac {\sqrt {c} \left (5 B c d^3+15 a d^3 D-12 A c d^2 e-30 a C d^2 e+40 a B d e^2-48 a A e^3\right ) \sqrt {1-\frac {a}{c x^4}} x^3 \sqrt {\frac {\sqrt {a} \left (d+e x^2\right )}{\left (\sqrt {c} d+\sqrt {a} e\right ) x^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {1-\frac {\sqrt {a}}{\sqrt {c} x^2}}}{\sqrt {2}}\right ),\frac {2 d}{d+\frac {\sqrt {a} e}{\sqrt {c}}}\right )}{15 a^{3/2} d^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \] Output:
(-A*e^3+B*d*e^2-C*d^2*e+D*d^3)*(-c*x^4+a)^(1/2)/d/e/(-a*e^2+c*d^2)/x^5/(e* x^2+d)^(1/2)-1/5*(A*c*d/a-5*C*d+5*d^2*D/e+5*B*e-6*A*e^2/d)*(e*x^2+d)^(1/2) *(-c*x^4+a)^(1/2)/d/(-a*e^2+c*d^2)/x^5-1/15*(24*A*a*e^3-9*A*c*d^2*e-20*B*a *d*e^2+5*B*c*d^3+15*C*a*d^2*e-15*D*a*d^3)*(e*x^2+d)^(1/2)*(-c*x^4+a)^(1/2) /a/d^3/(-a*e^2+c*d^2)/x^3+1/15*c^(1/2)*(3*A*(-16*a^2*e^4+8*a*c*d^2*e^2+3*c ^2*d^4)+5*a*d*(c*d^2*(-5*B*e+3*C*d)+a*e*(8*B*e^2-6*C*d*e+3*D*d^2)))*(1-a/c /x^4)^(1/2)*x^3*(a^(1/2)*(e*x^2+d)/(c^(1/2)*d+a^(1/2)*e)/x^2)^(1/2)*Ellipt icE(1/2*(1-a^(1/2)/c^(1/2)/x^2)^(1/2)*2^(1/2),2^(1/2)*(d/(d+a^(1/2)*e/c^(1 /2)))^(1/2))/a^2/d^4/(c^(1/2)*d-a^(1/2)*e)/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2 )+1/15*c^(1/2)*(-48*A*a*e^3-12*A*c*d^2*e+40*B*a*d*e^2+5*B*c*d^3-30*C*a*d^2 *e+15*D*a*d^3)*(1-a/c/x^4)^(1/2)*x^3*(a^(1/2)*(e*x^2+d)/(c^(1/2)*d+a^(1/2) *e)/x^2)^(1/2)*EllipticF(1/2*(1-a^(1/2)/c^(1/2)/x^2)^(1/2)*2^(1/2),2^(1/2) *(d/(d+a^(1/2)*e/c^(1/2)))^(1/2))/a^(3/2)/d^4/(e*x^2+d)^(1/2)/(-c*x^4+a)^( 1/2)
\[ \int \frac {A+B x^2+C x^4+D x^6}{x^6 \left (d+e x^2\right )^{3/2} \sqrt {a-c x^4}} \, dx=\int \frac {A+B x^2+C x^4+D x^6}{x^6 \left (d+e x^2\right )^{3/2} \sqrt {a-c x^4}} \, dx \] Input:
Integrate[(A + B*x^2 + C*x^4 + D*x^6)/(x^6*(d + e*x^2)^(3/2)*Sqrt[a - c*x^ 4]),x]
Output:
Integrate[(A + B*x^2 + C*x^4 + D*x^6)/(x^6*(d + e*x^2)^(3/2)*Sqrt[a - c*x^ 4]), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {A+B x^2+C x^4+D x^6}{x^6 \sqrt {a-c x^4} \left (d+e x^2\right )^{3/2}} \, dx\) |
\(\Big \downarrow \) 2251 |
\(\displaystyle \int \frac {A+B x^2+C x^4+D x^6}{x^6 \sqrt {a-c x^4} \left (d+e x^2\right )^{3/2}}dx\) |
Input:
Int[(A + B*x^2 + C*x^4 + D*x^6)/(x^6*(d + e*x^2)^(3/2)*Sqrt[a - c*x^4]),x]
Output:
$Aborted
Int[(Px_)*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (c_.)*(x_) ^4)^(p_.), x_Symbol] :> Unintegrable[Px*(f*x)^m*(d + e*x^2)^q*(a + c*x^4)^p , x] /; FreeQ[{a, c, d, e, f, m, p, q}, x] && PolyQ[Px, x]
\[\int \frac {D x^{6}+C \,x^{4}+B \,x^{2}+A}{x^{6} \left (e \,x^{2}+d \right )^{\frac {3}{2}} \sqrt {-c \,x^{4}+a}}d x\]
Input:
int((D*x^6+C*x^4+B*x^2+A)/x^6/(e*x^2+d)^(3/2)/(-c*x^4+a)^(1/2),x)
Output:
int((D*x^6+C*x^4+B*x^2+A)/x^6/(e*x^2+d)^(3/2)/(-c*x^4+a)^(1/2),x)
\[ \int \frac {A+B x^2+C x^4+D x^6}{x^6 \left (d+e x^2\right )^{3/2} \sqrt {a-c x^4}} \, dx=\int { \frac {D x^{6} + C x^{4} + B x^{2} + A}{\sqrt {-c x^{4} + a} {\left (e x^{2} + d\right )}^{\frac {3}{2}} x^{6}} \,d x } \] Input:
integrate((D*x^6+C*x^4+B*x^2+A)/x^6/(e*x^2+d)^(3/2)/(-c*x^4+a)^(1/2),x, al gorithm="fricas")
Output:
integral(-(D*x^6 + C*x^4 + B*x^2 + A)*sqrt(-c*x^4 + a)*sqrt(e*x^2 + d)/(c* e^2*x^14 + 2*c*d*e*x^12 - 2*a*d*e*x^8 + (c*d^2 - a*e^2)*x^10 - a*d^2*x^6), x)
\[ \int \frac {A+B x^2+C x^4+D x^6}{x^6 \left (d+e x^2\right )^{3/2} \sqrt {a-c x^4}} \, dx=\int \frac {A + B x^{2} + C x^{4} + D x^{6}}{x^{6} \sqrt {a - c x^{4}} \left (d + e x^{2}\right )^{\frac {3}{2}}}\, dx \] Input:
integrate((D*x**6+C*x**4+B*x**2+A)/x**6/(e*x**2+d)**(3/2)/(-c*x**4+a)**(1/ 2),x)
Output:
Integral((A + B*x**2 + C*x**4 + D*x**6)/(x**6*sqrt(a - c*x**4)*(d + e*x**2 )**(3/2)), x)
\[ \int \frac {A+B x^2+C x^4+D x^6}{x^6 \left (d+e x^2\right )^{3/2} \sqrt {a-c x^4}} \, dx=\int { \frac {D x^{6} + C x^{4} + B x^{2} + A}{\sqrt {-c x^{4} + a} {\left (e x^{2} + d\right )}^{\frac {3}{2}} x^{6}} \,d x } \] Input:
integrate((D*x^6+C*x^4+B*x^2+A)/x^6/(e*x^2+d)^(3/2)/(-c*x^4+a)^(1/2),x, al gorithm="maxima")
Output:
integrate((D*x^6 + C*x^4 + B*x^2 + A)/(sqrt(-c*x^4 + a)*(e*x^2 + d)^(3/2)* x^6), x)
\[ \int \frac {A+B x^2+C x^4+D x^6}{x^6 \left (d+e x^2\right )^{3/2} \sqrt {a-c x^4}} \, dx=\int { \frac {D x^{6} + C x^{4} + B x^{2} + A}{\sqrt {-c x^{4} + a} {\left (e x^{2} + d\right )}^{\frac {3}{2}} x^{6}} \,d x } \] Input:
integrate((D*x^6+C*x^4+B*x^2+A)/x^6/(e*x^2+d)^(3/2)/(-c*x^4+a)^(1/2),x, al gorithm="giac")
Output:
integrate((D*x^6 + C*x^4 + B*x^2 + A)/(sqrt(-c*x^4 + a)*(e*x^2 + d)^(3/2)* x^6), x)
Timed out. \[ \int \frac {A+B x^2+C x^4+D x^6}{x^6 \left (d+e x^2\right )^{3/2} \sqrt {a-c x^4}} \, dx=\int \frac {A+B\,x^2+C\,x^4+x^6\,D}{x^6\,\sqrt {a-c\,x^4}\,{\left (e\,x^2+d\right )}^{3/2}} \,d x \] Input:
int((A + B*x^2 + C*x^4 + x^6*D)/(x^6*(a - c*x^4)^(1/2)*(d + e*x^2)^(3/2)), x)
Output:
int((A + B*x^2 + C*x^4 + x^6*D)/(x^6*(a - c*x^4)^(1/2)*(d + e*x^2)^(3/2)), x)
\[ \int \frac {A+B x^2+C x^4+D x^6}{x^6 \left (d+e x^2\right )^{3/2} \sqrt {a-c x^4}} \, dx=\text {too large to display} \] Input:
int((D*x^6+C*x^4+B*x^2+A)/x^6/(e*x^2+d)^(3/2)/(-c*x^4+a)^(1/2),x)
Output:
( - 12*sqrt(d + e*x**2)*sqrt(a - c*x**4)*a**3*d*e**2 - 6*sqrt(d + e*x**2)* sqrt(a - c*x**4)*a**2*c*d**2*e*x**2 - 12*sqrt(d + e*x**2)*sqrt(a - c*x**4) *a**2*c*d*e**2*x**4 + 24*sqrt(d + e*x**2)*sqrt(a - c*x**4)*a**2*c*e**3*x** 6 - 15*sqrt(d + e*x**2)*sqrt(a - c*x**4)*a**2*d**4*x**2 - 30*sqrt(d + e*x* *2)*sqrt(a - c*x**4)*a**2*d**3*e*x**4 - 5*sqrt(d + e*x**2)*sqrt(a - c*x**4 )*a*b*c*d**3*x**2 - 10*sqrt(d + e*x**2)*sqrt(a - c*x**4)*a*b*c*d**2*e*x**4 - 20*sqrt(d + e*x**2)*sqrt(a - c*x**4)*a*b*c*d*e**2*x**6 + 6*sqrt(d + e*x **2)*sqrt(a - c*x**4)*a*c**2*d**2*e*x**6 + 15*sqrt(d + e*x**2)*sqrt(a - c* x**4)*a*c*d**4*x**6 + 5*sqrt(d + e*x**2)*sqrt(a - c*x**4)*b*c**2*d**3*x**6 + 48*int((sqrt(d + e*x**2)*sqrt(a - c*x**4)*x**6)/(a*d**2 + 2*a*d*e*x**2 + a*e**2*x**4 - c*d**2*x**4 - 2*c*d*e*x**6 - c*e**2*x**8),x)*a**2*c**2*d*e **4*x**5 + 48*int((sqrt(d + e*x**2)*sqrt(a - c*x**4)*x**6)/(a*d**2 + 2*a*d *e*x**2 + a*e**2*x**4 - c*d**2*x**4 - 2*c*d*e*x**6 - c*e**2*x**8),x)*a**2* c**2*e**5*x**7 - 40*int((sqrt(d + e*x**2)*sqrt(a - c*x**4)*x**6)/(a*d**2 + 2*a*d*e*x**2 + a*e**2*x**4 - c*d**2*x**4 - 2*c*d*e*x**6 - c*e**2*x**8),x) *a*b*c**2*d**2*e**3*x**5 - 40*int((sqrt(d + e*x**2)*sqrt(a - c*x**4)*x**6) /(a*d**2 + 2*a*d*e*x**2 + a*e**2*x**4 - c*d**2*x**4 - 2*c*d*e*x**6 - c*e** 2*x**8),x)*a*b*c**2*d*e**4*x**7 + 12*int((sqrt(d + e*x**2)*sqrt(a - c*x**4 )*x**6)/(a*d**2 + 2*a*d*e*x**2 + a*e**2*x**4 - c*d**2*x**4 - 2*c*d*e*x**6 - c*e**2*x**8),x)*a*c**3*d**3*e**2*x**5 + 12*int((sqrt(d + e*x**2)*sqrt...