\(\int \frac {A+B x^2}{x^4 (c+d x^2) (a-c x^4)^{3/2}} \, dx\) [20]

Optimal result
Mathematica [C] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [F]
Sympy [F]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 32, antiderivative size = 460 \[ \int \frac {A+B x^2}{x^4 \left (c+d x^2\right ) \left (a-c x^4\right )^{3/2}} \, dx=\frac {A c^2-a B d+c (B c-A d) x^2}{2 a \left (c^3-a d^2\right ) x^3 \sqrt {a-c x^4}}-\frac {\left (5 A c^3-3 a B c d-2 a A d^2\right ) \sqrt {a-c x^4}}{6 a^2 c \left (c^3-a d^2\right ) x^3}-\frac {(B c-A d) \left (3 c^3-2 a d^2\right ) \sqrt {a-c x^4}}{2 a^2 c^2 \left (c^3-a d^2\right ) x}-\frac {(B c-A d) \left (3 c^3-2 a d^2\right ) \sqrt {1-\frac {c x^4}{a}} E\left (\left .\arcsin \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )\right |-1\right )}{2 a^{5/4} c^{7/4} \left (c^3-a d^2\right ) \sqrt {a-c x^4}}+\frac {\left (5 A c^3+\sqrt {a} c^{3/2} (9 B c-4 A d)+6 a d (B c-A d)\right ) \sqrt {1-\frac {c x^4}{a}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),-1\right )}{6 a^{7/4} c^{7/4} \left (c^{3/2}+\sqrt {a} d\right ) \sqrt {a-c x^4}}+\frac {\sqrt [4]{a} d^3 (B c-A d) \sqrt {1-\frac {c x^4}{a}} \operatorname {EllipticPi}\left (-\frac {\sqrt {a} d}{c^{3/2}},\arcsin \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),-1\right )}{c^{13/4} \left (c^3-a d^2\right ) \sqrt {a-c x^4}} \] Output:

1/2*(A*c^2-B*a*d+c*(-A*d+B*c)*x^2)/a/(-a*d^2+c^3)/x^3/(-c*x^4+a)^(1/2)-1/6 
*(-2*A*a*d^2+5*A*c^3-3*B*a*c*d)*(-c*x^4+a)^(1/2)/a^2/c/(-a*d^2+c^3)/x^3-1/ 
2*(-A*d+B*c)*(-2*a*d^2+3*c^3)*(-c*x^4+a)^(1/2)/a^2/c^2/(-a*d^2+c^3)/x-1/2* 
(-A*d+B*c)*(-2*a*d^2+3*c^3)*(1-c*x^4/a)^(1/2)*EllipticE(c^(1/4)*x/a^(1/4), 
I)/a^(5/4)/c^(7/4)/(-a*d^2+c^3)/(-c*x^4+a)^(1/2)+1/6*(5*A*c^3+a^(1/2)*c^(3 
/2)*(-4*A*d+9*B*c)+6*a*d*(-A*d+B*c))*(1-c*x^4/a)^(1/2)*EllipticF(c^(1/4)*x 
/a^(1/4),I)/a^(7/4)/c^(7/4)/(c^(3/2)+a^(1/2)*d)/(-c*x^4+a)^(1/2)+a^(1/4)*d 
^3*(-A*d+B*c)*(1-c*x^4/a)^(1/2)*EllipticPi(c^(1/4)*x/a^(1/4),-a^(1/2)*d/c^ 
(3/2),I)/c^(13/4)/(-a*d^2+c^3)/(-c*x^4+a)^(1/2)
 

Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 11.68 (sec) , antiderivative size = 727, normalized size of antiderivative = 1.58 \[ \int \frac {A+B x^2}{x^4 \left (c+d x^2\right ) \left (a-c x^4\right )^{3/2}} \, dx=\frac {2 a A \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^5-2 a^2 A \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^2 d^2+6 a B \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^5 x^2-6 a A \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^4 d x^2-6 a^2 B \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^2 d^2 x^2+6 a^2 A \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c d^3 x^2-5 A \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^6 x^4+3 a B \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^4 d x^4+2 a A \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^3 d^2 x^4-9 B \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^6 x^6+9 A \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^5 d x^6+6 a B \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^3 d^2 x^6-6 a A \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^2 d^3 x^6+3 i \sqrt {a} c^{3/2} (B c-A d) \left (-3 c^3+2 a d^2\right ) x^3 \sqrt {1-\frac {c x^4}{a}} E\left (\left .i \text {arcsinh}\left (\sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} x\right )\right |-1\right )-i c^{3/2} \left (-c^{3/2}+\sqrt {a} d\right ) \left (5 A c^3+\sqrt {a} c^{3/2} (9 B c-4 A d)+6 a d (B c-A d)\right ) x^3 \sqrt {1-\frac {c x^4}{a}} \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} x\right ),-1\right )+6 i a^2 B c d^3 x^3 \sqrt {1-\frac {c x^4}{a}} \operatorname {EllipticPi}\left (-\frac {\sqrt {a} d}{c^{3/2}},i \text {arcsinh}\left (\sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} x\right ),-1\right )-6 i a^2 A d^4 x^3 \sqrt {1-\frac {c x^4}{a}} \operatorname {EllipticPi}\left (-\frac {\sqrt {a} d}{c^{3/2}},i \text {arcsinh}\left (\sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} x\right ),-1\right )}{6 a^2 \sqrt {-\frac {\sqrt {c}}{\sqrt {a}}} c^3 \left (-c^3+a d^2\right ) x^3 \sqrt {a-c x^4}} \] Input:

Integrate[(A + B*x^2)/(x^4*(c + d*x^2)*(a - c*x^4)^(3/2)),x]
 

Output:

(2*a*A*Sqrt[-(Sqrt[c]/Sqrt[a])]*c^5 - 2*a^2*A*Sqrt[-(Sqrt[c]/Sqrt[a])]*c^2 
*d^2 + 6*a*B*Sqrt[-(Sqrt[c]/Sqrt[a])]*c^5*x^2 - 6*a*A*Sqrt[-(Sqrt[c]/Sqrt[ 
a])]*c^4*d*x^2 - 6*a^2*B*Sqrt[-(Sqrt[c]/Sqrt[a])]*c^2*d^2*x^2 + 6*a^2*A*Sq 
rt[-(Sqrt[c]/Sqrt[a])]*c*d^3*x^2 - 5*A*Sqrt[-(Sqrt[c]/Sqrt[a])]*c^6*x^4 + 
3*a*B*Sqrt[-(Sqrt[c]/Sqrt[a])]*c^4*d*x^4 + 2*a*A*Sqrt[-(Sqrt[c]/Sqrt[a])]* 
c^3*d^2*x^4 - 9*B*Sqrt[-(Sqrt[c]/Sqrt[a])]*c^6*x^6 + 9*A*Sqrt[-(Sqrt[c]/Sq 
rt[a])]*c^5*d*x^6 + 6*a*B*Sqrt[-(Sqrt[c]/Sqrt[a])]*c^3*d^2*x^6 - 6*a*A*Sqr 
t[-(Sqrt[c]/Sqrt[a])]*c^2*d^3*x^6 + (3*I)*Sqrt[a]*c^(3/2)*(B*c - A*d)*(-3* 
c^3 + 2*a*d^2)*x^3*Sqrt[1 - (c*x^4)/a]*EllipticE[I*ArcSinh[Sqrt[-(Sqrt[c]/ 
Sqrt[a])]*x], -1] - I*c^(3/2)*(-c^(3/2) + Sqrt[a]*d)*(5*A*c^3 + Sqrt[a]*c^ 
(3/2)*(9*B*c - 4*A*d) + 6*a*d*(B*c - A*d))*x^3*Sqrt[1 - (c*x^4)/a]*Ellipti 
cF[I*ArcSinh[Sqrt[-(Sqrt[c]/Sqrt[a])]*x], -1] + (6*I)*a^2*B*c*d^3*x^3*Sqrt 
[1 - (c*x^4)/a]*EllipticPi[-((Sqrt[a]*d)/c^(3/2)), I*ArcSinh[Sqrt[-(Sqrt[c 
]/Sqrt[a])]*x], -1] - (6*I)*a^2*A*d^4*x^3*Sqrt[1 - (c*x^4)/a]*EllipticPi[- 
((Sqrt[a]*d)/c^(3/2)), I*ArcSinh[Sqrt[-(Sqrt[c]/Sqrt[a])]*x], -1])/(6*a^2* 
Sqrt[-(Sqrt[c]/Sqrt[a])]*c^3*(-c^3 + a*d^2)*x^3*Sqrt[a - c*x^4])
 

Rubi [A] (verified)

Time = 0.89 (sec) , antiderivative size = 546, normalized size of antiderivative = 1.19, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {2249, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {A+B x^2}{x^4 \left (a-c x^4\right )^{3/2} \left (c+d x^2\right )} \, dx\)

\(\Big \downarrow \) 2249

\(\displaystyle \int \left (\frac {B c-A d}{a c^2 x^2 \sqrt {a-c x^4}}+\frac {c \left (-a B d+c x^2 (B c-A d)+A c^2\right )}{a \left (c^3-a d^2\right ) \left (a-c x^4\right )^{3/2}}+\frac {d^3 (B c-A d)}{c^2 \left (c^3-a d^2\right ) \sqrt {a-c x^4} \left (c+d x^2\right )}+\frac {A}{a c x^4 \sqrt {a-c x^4}}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {\sqrt {1-\frac {c x^4}{a}} (B c-A d) \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),-1\right )}{a^{5/4} c^{7/4} \sqrt {a-c x^4}}+\frac {c^{3/4} \sqrt {1-\frac {c x^4}{a}} \left (\sqrt {a} B+A \sqrt {c}\right ) \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),-1\right )}{2 a^{7/4} \left (\sqrt {a} d+c^{3/2}\right ) \sqrt {a-c x^4}}-\frac {\sqrt {1-\frac {c x^4}{a}} (B c-A d) E\left (\left .\arcsin \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )\right |-1\right )}{a^{5/4} c^{7/4} \sqrt {a-c x^4}}-\frac {c^{5/4} \sqrt {1-\frac {c x^4}{a}} (B c-A d) E\left (\left .\arcsin \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )\right |-1\right )}{2 a^{5/4} \left (c^3-a d^2\right ) \sqrt {a-c x^4}}+\frac {A \sqrt {1-\frac {c x^4}{a}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),-1\right )}{3 a^{7/4} \sqrt [4]{c} \sqrt {a-c x^4}}-\frac {\sqrt {a-c x^4} (B c-A d)}{a^2 c^2 x}+\frac {c x \left (-a B d+c x^2 (B c-A d)+A c^2\right )}{2 a^2 \left (c^3-a d^2\right ) \sqrt {a-c x^4}}-\frac {A \sqrt {a-c x^4}}{3 a^2 c x^3}+\frac {\sqrt [4]{a} d^3 \sqrt {1-\frac {c x^4}{a}} (B c-A d) \operatorname {EllipticPi}\left (-\frac {\sqrt {a} d}{c^{3/2}},\arcsin \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),-1\right )}{c^{13/4} \left (c^3-a d^2\right ) \sqrt {a-c x^4}}\)

Input:

Int[(A + B*x^2)/(x^4*(c + d*x^2)*(a - c*x^4)^(3/2)),x]
 

Output:

(c*x*(A*c^2 - a*B*d + c*(B*c - A*d)*x^2))/(2*a^2*(c^3 - a*d^2)*Sqrt[a - c* 
x^4]) - (A*Sqrt[a - c*x^4])/(3*a^2*c*x^3) - ((B*c - A*d)*Sqrt[a - c*x^4])/ 
(a^2*c^2*x) - ((B*c - A*d)*Sqrt[1 - (c*x^4)/a]*EllipticE[ArcSin[(c^(1/4)*x 
)/a^(1/4)], -1])/(a^(5/4)*c^(7/4)*Sqrt[a - c*x^4]) - (c^(5/4)*(B*c - A*d)* 
Sqrt[1 - (c*x^4)/a]*EllipticE[ArcSin[(c^(1/4)*x)/a^(1/4)], -1])/(2*a^(5/4) 
*(c^3 - a*d^2)*Sqrt[a - c*x^4]) + (A*Sqrt[1 - (c*x^4)/a]*EllipticF[ArcSin[ 
(c^(1/4)*x)/a^(1/4)], -1])/(3*a^(7/4)*c^(1/4)*Sqrt[a - c*x^4]) + ((Sqrt[a] 
*B + A*Sqrt[c])*c^(3/4)*Sqrt[1 - (c*x^4)/a]*EllipticF[ArcSin[(c^(1/4)*x)/a 
^(1/4)], -1])/(2*a^(7/4)*(c^(3/2) + Sqrt[a]*d)*Sqrt[a - c*x^4]) + ((B*c - 
A*d)*Sqrt[1 - (c*x^4)/a]*EllipticF[ArcSin[(c^(1/4)*x)/a^(1/4)], -1])/(a^(5 
/4)*c^(7/4)*Sqrt[a - c*x^4]) + (a^(1/4)*d^3*(B*c - A*d)*Sqrt[1 - (c*x^4)/a 
]*EllipticPi[-((Sqrt[a]*d)/c^(3/2)), ArcSin[(c^(1/4)*x)/a^(1/4)], -1])/(c^ 
(13/4)*(c^3 - a*d^2)*Sqrt[a - c*x^4])
 

Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2249
Int[(Px_)*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (c_.)*(x_) 
^4)^(p_), x_Symbol] :> Int[ExpandIntegrand[1/Sqrt[a + c*x^4], Px*(f*x)^m*(d 
 + e*x^2)^q*(a + c*x^4)^(p + 1/2), x], x] /; FreeQ[{a, c, d, e, f, m}, x] & 
& PolyQ[Px, x] && IntegerQ[p + 1/2] && IntegerQ[q]
 
Maple [A] (verified)

Time = 7.48 (sec) , antiderivative size = 663, normalized size of antiderivative = 1.44

method result size
risch \(-\frac {\sqrt {-c \,x^{4}+a}\, \left (-3 A d \,x^{2}+3 B c \,x^{2}+A c \right )}{3 c^{2} a^{2} x^{3}}+\frac {\frac {A \,c^{2} \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \operatorname {EllipticF}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )}{\sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}+\frac {3 B \,c^{\frac {3}{2}} \sqrt {a}\, \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (\operatorname {EllipticF}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )-\operatorname {EllipticE}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )\right )}{\sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}-\frac {3 A \sqrt {c}\, d \sqrt {a}\, \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (\operatorname {EllipticF}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )-\operatorname {EllipticE}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )\right )}{\sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}-\frac {3 a \,c^{3} \left (\frac {2 c \left (-\frac {\left (A d -B c \right ) x^{3}}{4 a}+\frac {\left (A \,c^{2}-B a d \right ) x}{4 a c}\right )}{\sqrt {-\left (x^{4}-\frac {a}{c}\right ) c}}+\frac {\left (A \,c^{2}-B a d \right ) \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \operatorname {EllipticF}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )}{2 a \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}-\frac {\left (A d -B c \right ) \sqrt {c}\, \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (\operatorname {EllipticF}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )-\operatorname {EllipticE}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )\right )}{2 \sqrt {a}\, \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}\right )}{a \,d^{2}-c^{3}}+\frac {3 a^{2} d^{3} \left (A d -B c \right ) \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \operatorname {EllipticPi}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, -\frac {\sqrt {a}\, d}{c^{\frac {3}{2}}}, \frac {\sqrt {-\frac {\sqrt {c}}{\sqrt {a}}}}{\sqrt {\frac {\sqrt {c}}{\sqrt {a}}}}\right )}{\left (a \,d^{2}-c^{3}\right ) c \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}}{3 a^{2} c^{2}}\) \(663\)
default \(\frac {A \left (-\frac {\sqrt {-c \,x^{4}+a}}{3 a^{2} x^{3}}+\frac {c x}{2 a^{2} \sqrt {-\left (x^{4}-\frac {a}{c}\right ) c}}+\frac {5 c \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \operatorname {EllipticF}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )}{6 a^{2} \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}\right )}{c}-\frac {\left (A d -B c \right ) \left (\frac {c \,x^{3}}{2 a^{2} \sqrt {-\left (x^{4}-\frac {a}{c}\right ) c}}-\frac {\sqrt {-c \,x^{4}+a}}{a^{2} x}+\frac {3 \sqrt {c}\, \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \left (\operatorname {EllipticF}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )-\operatorname {EllipticE}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )\right )}{2 a^{\frac {3}{2}} \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}\right )}{c^{2}}+\frac {d \left (A d -B c \right ) \left (\frac {2 c \left (\frac {d \,x^{3}}{4 a \left (a \,d^{2}-c^{3}\right )}-\frac {c x}{4 a \left (a \,d^{2}-c^{3}\right )}\right )}{\sqrt {-\left (x^{4}-\frac {a}{c}\right ) c}}-\frac {c^{2} \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \operatorname {EllipticF}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )}{2 a \left (a \,d^{2}-c^{3}\right ) \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}+\frac {\sqrt {c}\, d \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \operatorname {EllipticF}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )}{2 \sqrt {a}\, \left (a \,d^{2}-c^{3}\right ) \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}-\frac {\sqrt {c}\, d \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \operatorname {EllipticE}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, i\right )}{2 \sqrt {a}\, \left (a \,d^{2}-c^{3}\right ) \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}+\frac {d^{2} \sqrt {1-\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {\sqrt {c}\, x^{2}}{\sqrt {a}}}\, \operatorname {EllipticPi}\left (x \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}, -\frac {\sqrt {a}\, d}{c^{\frac {3}{2}}}, \frac {\sqrt {-\frac {\sqrt {c}}{\sqrt {a}}}}{\sqrt {\frac {\sqrt {c}}{\sqrt {a}}}}\right )}{\left (a \,d^{2}-c^{3}\right ) c \sqrt {\frac {\sqrt {c}}{\sqrt {a}}}\, \sqrt {-c \,x^{4}+a}}\right )}{c^{2}}\) \(694\)
elliptic \(\text {Expression too large to display}\) \(1209\)

Input:

int((B*x^2+A)/x^4/(d*x^2+c)/(-c*x^4+a)^(3/2),x,method=_RETURNVERBOSE)
 

Output:

-1/3*(-c*x^4+a)^(1/2)*(-3*A*d*x^2+3*B*c*x^2+A*c)/c^2/a^2/x^3+1/3/a^2/c^2*( 
A*c^2/(c^(1/2)/a^(1/2))^(1/2)*(1-c^(1/2)*x^2/a^(1/2))^(1/2)*(1+c^(1/2)*x^2 
/a^(1/2))^(1/2)/(-c*x^4+a)^(1/2)*EllipticF(x*(c^(1/2)/a^(1/2))^(1/2),I)+3* 
B*c^(3/2)*a^(1/2)/(c^(1/2)/a^(1/2))^(1/2)*(1-c^(1/2)*x^2/a^(1/2))^(1/2)*(1 
+c^(1/2)*x^2/a^(1/2))^(1/2)/(-c*x^4+a)^(1/2)*(EllipticF(x*(c^(1/2)/a^(1/2) 
)^(1/2),I)-EllipticE(x*(c^(1/2)/a^(1/2))^(1/2),I))-3*A*c^(1/2)*d*a^(1/2)/( 
c^(1/2)/a^(1/2))^(1/2)*(1-c^(1/2)*x^2/a^(1/2))^(1/2)*(1+c^(1/2)*x^2/a^(1/2 
))^(1/2)/(-c*x^4+a)^(1/2)*(EllipticF(x*(c^(1/2)/a^(1/2))^(1/2),I)-Elliptic 
E(x*(c^(1/2)/a^(1/2))^(1/2),I))-3*a*c^3/(a*d^2-c^3)*(2*c*(-1/4*(A*d-B*c)/a 
*x^3+1/4*(A*c^2-B*a*d)/a/c*x)/(-(x^4-a/c)*c)^(1/2)+1/2*(A*c^2-B*a*d)/a/(c^ 
(1/2)/a^(1/2))^(1/2)*(1-c^(1/2)*x^2/a^(1/2))^(1/2)*(1+c^(1/2)*x^2/a^(1/2)) 
^(1/2)/(-c*x^4+a)^(1/2)*EllipticF(x*(c^(1/2)/a^(1/2))^(1/2),I)-1/2*(A*d-B* 
c)*c^(1/2)/a^(1/2)/(c^(1/2)/a^(1/2))^(1/2)*(1-c^(1/2)*x^2/a^(1/2))^(1/2)*( 
1+c^(1/2)*x^2/a^(1/2))^(1/2)/(-c*x^4+a)^(1/2)*(EllipticF(x*(c^(1/2)/a^(1/2 
))^(1/2),I)-EllipticE(x*(c^(1/2)/a^(1/2))^(1/2),I)))+3*a^2*d^3*(A*d-B*c)/( 
a*d^2-c^3)/c/(c^(1/2)/a^(1/2))^(1/2)*(1-c^(1/2)*x^2/a^(1/2))^(1/2)*(1+c^(1 
/2)*x^2/a^(1/2))^(1/2)/(-c*x^4+a)^(1/2)*EllipticPi(x*(c^(1/2)/a^(1/2))^(1/ 
2),-a^(1/2)*d/c^(3/2),(-c^(1/2)/a^(1/2))^(1/2)/(c^(1/2)/a^(1/2))^(1/2)))
 

Fricas [F]

\[ \int \frac {A+B x^2}{x^4 \left (c+d x^2\right ) \left (a-c x^4\right )^{3/2}} \, dx=\int { \frac {B x^{2} + A}{{\left (-c x^{4} + a\right )}^{\frac {3}{2}} {\left (d x^{2} + c\right )} x^{4}} \,d x } \] Input:

integrate((B*x^2+A)/x^4/(d*x^2+c)/(-c*x^4+a)^(3/2),x, algorithm="fricas")
 

Output:

integral(sqrt(-c*x^4 + a)*(B*x^2 + A)/(c^2*d*x^14 + c^3*x^12 - 2*a*c*d*x^1 
0 - 2*a*c^2*x^8 + a^2*d*x^6 + a^2*c*x^4), x)
 

Sympy [F]

\[ \int \frac {A+B x^2}{x^4 \left (c+d x^2\right ) \left (a-c x^4\right )^{3/2}} \, dx=\int \frac {A + B x^{2}}{x^{4} \left (a - c x^{4}\right )^{\frac {3}{2}} \left (c + d x^{2}\right )}\, dx \] Input:

integrate((B*x**2+A)/x**4/(d*x**2+c)/(-c*x**4+a)**(3/2),x)
 

Output:

Integral((A + B*x**2)/(x**4*(a - c*x**4)**(3/2)*(c + d*x**2)), x)
 

Maxima [F]

\[ \int \frac {A+B x^2}{x^4 \left (c+d x^2\right ) \left (a-c x^4\right )^{3/2}} \, dx=\int { \frac {B x^{2} + A}{{\left (-c x^{4} + a\right )}^{\frac {3}{2}} {\left (d x^{2} + c\right )} x^{4}} \,d x } \] Input:

integrate((B*x^2+A)/x^4/(d*x^2+c)/(-c*x^4+a)^(3/2),x, algorithm="maxima")
 

Output:

integrate((B*x^2 + A)/((-c*x^4 + a)^(3/2)*(d*x^2 + c)*x^4), x)
 

Giac [F]

\[ \int \frac {A+B x^2}{x^4 \left (c+d x^2\right ) \left (a-c x^4\right )^{3/2}} \, dx=\int { \frac {B x^{2} + A}{{\left (-c x^{4} + a\right )}^{\frac {3}{2}} {\left (d x^{2} + c\right )} x^{4}} \,d x } \] Input:

integrate((B*x^2+A)/x^4/(d*x^2+c)/(-c*x^4+a)^(3/2),x, algorithm="giac")
 

Output:

integrate((B*x^2 + A)/((-c*x^4 + a)^(3/2)*(d*x^2 + c)*x^4), x)
                                                                                    
                                                                                    
 

Mupad [F(-1)]

Timed out. \[ \int \frac {A+B x^2}{x^4 \left (c+d x^2\right ) \left (a-c x^4\right )^{3/2}} \, dx=\int \frac {B\,x^2+A}{x^4\,{\left (a-c\,x^4\right )}^{3/2}\,\left (d\,x^2+c\right )} \,d x \] Input:

int((A + B*x^2)/(x^4*(a - c*x^4)^(3/2)*(c + d*x^2)),x)
 

Output:

int((A + B*x^2)/(x^4*(a - c*x^4)^(3/2)*(c + d*x^2)), x)
 

Reduce [F]

\[ \int \frac {A+B x^2}{x^4 \left (c+d x^2\right ) \left (a-c x^4\right )^{3/2}} \, dx =\text {Too large to display} \] Input:

int((B*x^2+A)/x^4/(d*x^2+c)/(-c*x^4+a)^(3/2),x)
 

Output:

( - sqrt(a - c*x**4)*a - 3*sqrt(a - c*x**4)*b*x**2 - 3*int(sqrt(a - c*x**4 
)/(a**2*c*x**2 + a**2*d*x**4 - 2*a*c**2*x**6 - 2*a*c*d*x**8 + c**3*x**10 + 
 c**2*d*x**12),x)*a**3*d*x**3 + 3*int(sqrt(a - c*x**4)/(a**2*c*x**2 + a**2 
*d*x**4 - 2*a*c**2*x**6 - 2*a*c*d*x**8 + c**3*x**10 + c**2*d*x**12),x)*a** 
2*c*d*x**7 - 3*int(sqrt(a - c*x**4)/(a**2*c + a**2*d*x**2 - 2*a*c**2*x**4 
- 2*a*c*d*x**6 + c**3*x**8 + c**2*d*x**10),x)*a**2*b*d*x**3 + 5*int(sqrt(a 
 - c*x**4)/(a**2*c + a**2*d*x**2 - 2*a*c**2*x**4 - 2*a*c*d*x**6 + c**3*x** 
8 + c**2*d*x**10),x)*a**2*c**2*x**3 + 3*int(sqrt(a - c*x**4)/(a**2*c + a** 
2*d*x**2 - 2*a*c**2*x**4 - 2*a*c*d*x**6 + c**3*x**8 + c**2*d*x**10),x)*a*b 
*c*d*x**7 - 5*int(sqrt(a - c*x**4)/(a**2*c + a**2*d*x**2 - 2*a*c**2*x**4 - 
 2*a*c*d*x**6 + c**3*x**8 + c**2*d*x**10),x)*a*c**3*x**7 + 9*int((sqrt(a - 
 c*x**4)*x**4)/(a**2*c + a**2*d*x**2 - 2*a*c**2*x**4 - 2*a*c*d*x**6 + c**3 
*x**8 + c**2*d*x**10),x)*a*b*c*d*x**3 - 9*int((sqrt(a - c*x**4)*x**4)/(a** 
2*c + a**2*d*x**2 - 2*a*c**2*x**4 - 2*a*c*d*x**6 + c**3*x**8 + c**2*d*x**1 
0),x)*b*c**2*d*x**7 + 5*int((sqrt(a - c*x**4)*x**2)/(a**2*c + a**2*d*x**2 
- 2*a*c**2*x**4 - 2*a*c*d*x**6 + c**3*x**8 + c**2*d*x**10),x)*a**2*c*d*x** 
3 + 9*int((sqrt(a - c*x**4)*x**2)/(a**2*c + a**2*d*x**2 - 2*a*c**2*x**4 - 
2*a*c*d*x**6 + c**3*x**8 + c**2*d*x**10),x)*a*b*c**2*x**3 - 5*int((sqrt(a 
- c*x**4)*x**2)/(a**2*c + a**2*d*x**2 - 2*a*c**2*x**4 - 2*a*c*d*x**6 + c** 
3*x**8 + c**2*d*x**10),x)*a*c**2*d*x**7 - 9*int((sqrt(a - c*x**4)*x**2)...