Integrand size = 39, antiderivative size = 368 \[ \int \frac {A+B x^2+C x^4}{x^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \, dx=-\frac {A \sqrt {d+e x^2} \sqrt {a-c x^4}}{3 a d x^3}+\frac {c (3 B d-2 A e) \left (d+\frac {\sqrt {a} e}{\sqrt {c}}\right ) \sqrt {1-\frac {a}{c x^4}} x^3 \sqrt {\frac {\sqrt {a} \left (d+e x^2\right )}{\left (\sqrt {c} d+\sqrt {a} e\right ) x^2}} E\left (\arcsin \left (\frac {\sqrt {1-\frac {\sqrt {a}}{\sqrt {c} x^2}}}{\sqrt {2}}\right )|\frac {2 d}{d+\frac {\sqrt {a} e}{\sqrt {c}}}\right )}{3 a d^2 \sqrt {d+e x^2} \sqrt {a-c x^4}}+\frac {\sqrt {c} \left (3 a d (C d-B e)+A \left (c d^2+2 a e^2\right )\right ) \sqrt {1-\frac {a}{c x^4}} x^3 \sqrt {\frac {\sqrt {a} \left (d+e x^2\right )}{\left (\sqrt {c} d+\sqrt {a} e\right ) x^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {1-\frac {\sqrt {a}}{\sqrt {c} x^2}}}{\sqrt {2}}\right ),\frac {2 d}{d+\frac {\sqrt {a} e}{\sqrt {c}}}\right )}{3 a^{3/2} d^2 \sqrt {d+e x^2} \sqrt {a-c x^4}} \] Output:
-1/3*A*(e*x^2+d)^(1/2)*(-c*x^4+a)^(1/2)/a/d/x^3+1/3*c*(-2*A*e+3*B*d)*(d+a^ (1/2)*e/c^(1/2))*(1-a/c/x^4)^(1/2)*x^3*(a^(1/2)*(e*x^2+d)/(c^(1/2)*d+a^(1/ 2)*e)/x^2)^(1/2)*EllipticE(1/2*(1-a^(1/2)/c^(1/2)/x^2)^(1/2)*2^(1/2),2^(1/ 2)*(d/(d+a^(1/2)*e/c^(1/2)))^(1/2))/a/d^2/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2) +1/3*c^(1/2)*(3*a*d*(-B*e+C*d)+A*(2*a*e^2+c*d^2))*(1-a/c/x^4)^(1/2)*x^3*(a ^(1/2)*(e*x^2+d)/(c^(1/2)*d+a^(1/2)*e)/x^2)^(1/2)*EllipticF(1/2*(1-a^(1/2) /c^(1/2)/x^2)^(1/2)*2^(1/2),2^(1/2)*(d/(d+a^(1/2)*e/c^(1/2)))^(1/2))/a^(3/ 2)/d^2/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2)
\[ \int \frac {A+B x^2+C x^4}{x^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \, dx=\int \frac {A+B x^2+C x^4}{x^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \, dx \] Input:
Integrate[(A + B*x^2 + C*x^4)/(x^4*Sqrt[d + e*x^2]*Sqrt[a - c*x^4]),x]
Output:
Integrate[(A + B*x^2 + C*x^4)/(x^4*Sqrt[d + e*x^2]*Sqrt[a - c*x^4]), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {A+B x^2+C x^4}{x^4 \sqrt {a-c x^4} \sqrt {d+e x^2}} \, dx\) |
\(\Big \downarrow \) 2251 |
\(\displaystyle \int \frac {A+B x^2+C x^4}{x^4 \sqrt {a-c x^4} \sqrt {d+e x^2}}dx\) |
Input:
Int[(A + B*x^2 + C*x^4)/(x^4*Sqrt[d + e*x^2]*Sqrt[a - c*x^4]),x]
Output:
$Aborted
Int[(Px_)*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (c_.)*(x_) ^4)^(p_.), x_Symbol] :> Unintegrable[Px*(f*x)^m*(d + e*x^2)^q*(a + c*x^4)^p , x] /; FreeQ[{a, c, d, e, f, m, p, q}, x] && PolyQ[Px, x]
\[\int \frac {C \,x^{4}+B \,x^{2}+A}{x^{4} \sqrt {e \,x^{2}+d}\, \sqrt {-c \,x^{4}+a}}d x\]
Input:
int((C*x^4+B*x^2+A)/x^4/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2),x)
Output:
int((C*x^4+B*x^2+A)/x^4/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2),x)
\[ \int \frac {A+B x^2+C x^4}{x^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \, dx=\int { \frac {C x^{4} + B x^{2} + A}{\sqrt {-c x^{4} + a} \sqrt {e x^{2} + d} x^{4}} \,d x } \] Input:
integrate((C*x^4+B*x^2+A)/x^4/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2),x, algorith m="fricas")
Output:
integral(-(C*x^4 + B*x^2 + A)*sqrt(-c*x^4 + a)*sqrt(e*x^2 + d)/(c*e*x^10 + c*d*x^8 - a*e*x^6 - a*d*x^4), x)
\[ \int \frac {A+B x^2+C x^4}{x^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \, dx=\int \frac {A + B x^{2} + C x^{4}}{x^{4} \sqrt {a - c x^{4}} \sqrt {d + e x^{2}}}\, dx \] Input:
integrate((C*x**4+B*x**2+A)/x**4/(e*x**2+d)**(1/2)/(-c*x**4+a)**(1/2),x)
Output:
Integral((A + B*x**2 + C*x**4)/(x**4*sqrt(a - c*x**4)*sqrt(d + e*x**2)), x )
\[ \int \frac {A+B x^2+C x^4}{x^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \, dx=\int { \frac {C x^{4} + B x^{2} + A}{\sqrt {-c x^{4} + a} \sqrt {e x^{2} + d} x^{4}} \,d x } \] Input:
integrate((C*x^4+B*x^2+A)/x^4/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2),x, algorith m="maxima")
Output:
integrate((C*x^4 + B*x^2 + A)/(sqrt(-c*x^4 + a)*sqrt(e*x^2 + d)*x^4), x)
\[ \int \frac {A+B x^2+C x^4}{x^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \, dx=\int { \frac {C x^{4} + B x^{2} + A}{\sqrt {-c x^{4} + a} \sqrt {e x^{2} + d} x^{4}} \,d x } \] Input:
integrate((C*x^4+B*x^2+A)/x^4/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2),x, algorith m="giac")
Output:
integrate((C*x^4 + B*x^2 + A)/(sqrt(-c*x^4 + a)*sqrt(e*x^2 + d)*x^4), x)
Timed out. \[ \int \frac {A+B x^2+C x^4}{x^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \, dx=\int \frac {C\,x^4+B\,x^2+A}{x^4\,\sqrt {a-c\,x^4}\,\sqrt {e\,x^2+d}} \,d x \] Input:
int((A + B*x^2 + C*x^4)/(x^4*(a - c*x^4)^(1/2)*(d + e*x^2)^(1/2)),x)
Output:
int((A + B*x^2 + C*x^4)/(x^4*(a - c*x^4)^(1/2)*(d + e*x^2)^(1/2)), x)
\[ \int \frac {A+B x^2+C x^4}{x^4 \sqrt {d+e x^2} \sqrt {a-c x^4}} \, dx=\frac {-\sqrt {e \,x^{2}+d}\, \sqrt {-c \,x^{4}+a}\, b +2 \left (\int \frac {\sqrt {e \,x^{2}+d}\, \sqrt {-c \,x^{4}+a}}{-c e \,x^{10}-c d \,x^{8}+a e \,x^{6}+a d \,x^{4}}d x \right ) a^{2} e \,x^{3}-3 \left (\int \frac {\sqrt {e \,x^{2}+d}\, \sqrt {-c \,x^{4}+a}}{-c e \,x^{10}-c d \,x^{8}+a e \,x^{6}+a d \,x^{4}}d x \right ) a b d \,x^{3}+2 \left (\int \frac {\sqrt {e \,x^{2}+d}\, \sqrt {-c \,x^{4}+a}}{-c e \,x^{6}-c d \,x^{4}+a e \,x^{2}+a d}d x \right ) a c e \,x^{3}+\left (\int \frac {\sqrt {e \,x^{2}+d}\, \sqrt {-c \,x^{4}+a}}{-c e \,x^{6}-c d \,x^{4}+a e \,x^{2}+a d}d x \right ) b c d \,x^{3}}{2 a e \,x^{3}} \] Input:
int((C*x^4+B*x^2+A)/x^4/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2),x)
Output:
( - sqrt(d + e*x**2)*sqrt(a - c*x**4)*b + 2*int((sqrt(d + e*x**2)*sqrt(a - c*x**4))/(a*d*x**4 + a*e*x**6 - c*d*x**8 - c*e*x**10),x)*a**2*e*x**3 - 3* int((sqrt(d + e*x**2)*sqrt(a - c*x**4))/(a*d*x**4 + a*e*x**6 - c*d*x**8 - c*e*x**10),x)*a*b*d*x**3 + 2*int((sqrt(d + e*x**2)*sqrt(a - c*x**4))/(a*d + a*e*x**2 - c*d*x**4 - c*e*x**6),x)*a*c*e*x**3 + int((sqrt(d + e*x**2)*sq rt(a - c*x**4))/(a*d + a*e*x**2 - c*d*x**4 - c*e*x**6),x)*b*c*d*x**3)/(2*a *e*x**3)