\(\int \frac {1}{(a^2+2 a b x^3+b^2 x^6)^{5/2}} \, dx\) [100]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [C] (warning: unable to verify)
Fricas [A] (verification not implemented)
Sympy [F]
Maxima [A] (verification not implemented)
Giac [A] (verification not implemented)
Mupad [F(-1)]
Reduce [B] (verification not implemented)

Optimal result

Integrand size = 22, antiderivative size = 351 \[ \int \frac {1}{\left (a^2+2 a b x^3+b^2 x^6\right )^{5/2}} \, dx=\frac {55 x}{243 a^4 \sqrt {a^2+2 a b x^3+b^2 x^6}}+\frac {x}{12 a \left (a+b x^3\right )^3 \sqrt {a^2+2 a b x^3+b^2 x^6}}+\frac {11 x}{108 a^2 \left (a+b x^3\right )^2 \sqrt {a^2+2 a b x^3+b^2 x^6}}+\frac {11 x}{81 a^3 \left (a+b x^3\right ) \sqrt {a^2+2 a b x^3+b^2 x^6}}-\frac {110 \left (a+b x^3\right ) \arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{243 \sqrt {3} a^{14/3} \sqrt [3]{b} \sqrt {a^2+2 a b x^3+b^2 x^6}}+\frac {110 \left (a+b x^3\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{729 a^{14/3} \sqrt [3]{b} \sqrt {a^2+2 a b x^3+b^2 x^6}}-\frac {55 \left (a+b x^3\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{729 a^{14/3} \sqrt [3]{b} \sqrt {a^2+2 a b x^3+b^2 x^6}} \] Output:

55/243*x/a^4/((b*x^3+a)^2)^(1/2)+1/12*x/a/(b*x^3+a)^3/((b*x^3+a)^2)^(1/2)+ 
11/108*x/a^2/(b*x^3+a)^2/((b*x^3+a)^2)^(1/2)+11/81*x/a^3/(b*x^3+a)/((b*x^3 
+a)^2)^(1/2)-110/729*(b*x^3+a)*arctan(1/3*(a^(1/3)-2*b^(1/3)*x)*3^(1/2)/a^ 
(1/3))*3^(1/2)/a^(14/3)/b^(1/3)/((b*x^3+a)^2)^(1/2)+110/729*(b*x^3+a)*ln(a 
^(1/3)+b^(1/3)*x)/a^(14/3)/b^(1/3)/((b*x^3+a)^2)^(1/2)-55/729*(b*x^3+a)*ln 
(a^(2/3)-a^(1/3)*b^(1/3)*x+b^(2/3)*x^2)/a^(14/3)/b^(1/3)/((b*x^3+a)^2)^(1/ 
2)
 

Mathematica [A] (verified)

Time = 1.15 (sec) , antiderivative size = 211, normalized size of antiderivative = 0.60 \[ \int \frac {1}{\left (a^2+2 a b x^3+b^2 x^6\right )^{5/2}} \, dx=\frac {\left (a+b x^3\right ) \left (243 a^{11/3} x+297 a^{8/3} x \left (a+b x^3\right )+396 a^{5/3} x \left (a+b x^3\right )^2+660 a^{2/3} x \left (a+b x^3\right )^3+\frac {440 \sqrt {3} \left (a+b x^3\right )^4 \arctan \left (\frac {-\sqrt [3]{a}+2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt [3]{b}}+\frac {440 \left (a+b x^3\right )^4 \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{b}}-\frac {220 \left (a+b x^3\right )^4 \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{\sqrt [3]{b}}\right )}{2916 a^{14/3} \left (\left (a+b x^3\right )^2\right )^{5/2}} \] Input:

Integrate[(a^2 + 2*a*b*x^3 + b^2*x^6)^(-5/2),x]
 

Output:

((a + b*x^3)*(243*a^(11/3)*x + 297*a^(8/3)*x*(a + b*x^3) + 396*a^(5/3)*x*( 
a + b*x^3)^2 + 660*a^(2/3)*x*(a + b*x^3)^3 + (440*Sqrt[3]*(a + b*x^3)^4*Ar 
cTan[(-a^(1/3) + 2*b^(1/3)*x)/(Sqrt[3]*a^(1/3))])/b^(1/3) + (440*(a + b*x^ 
3)^4*Log[a^(1/3) + b^(1/3)*x])/b^(1/3) - (220*(a + b*x^3)^4*Log[a^(2/3) - 
a^(1/3)*b^(1/3)*x + b^(2/3)*x^2])/b^(1/3)))/(2916*a^(14/3)*((a + b*x^3)^2) 
^(5/2))
 

Rubi [A] (verified)

Time = 0.47 (sec) , antiderivative size = 269, normalized size of antiderivative = 0.77, number of steps used = 15, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.636, Rules used = {1384, 749, 749, 749, 749, 750, 16, 27, 1142, 25, 27, 1082, 217, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{\left (a^2+2 a b x^3+b^2 x^6\right )^{5/2}} \, dx\)

\(\Big \downarrow \) 1384

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \int \frac {1}{\left (b^2 x^3+a b\right )^5}dx}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 749

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \int \frac {1}{\left (b^2 x^3+a b\right )^4}dx}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 749

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \int \frac {1}{\left (b^2 x^3+a b\right )^3}dx}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 749

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \int \frac {1}{\left (b^2 x^3+a b\right )^2}dx}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 749

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \int \frac {1}{b^2 x^3+a b}dx}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 750

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \left (\frac {\int \frac {\sqrt [3]{b} \left (2 \sqrt [3]{a}-\sqrt [3]{b} x\right )}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx}{3 a^{2/3} b^{2/3}}+\frac {\int \frac {1}{b^{2/3} x+\sqrt [3]{a} \sqrt [3]{b}}dx}{3 a^{2/3} b^{2/3}}\right )}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 16

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \left (\frac {\int \frac {\sqrt [3]{b} \left (2 \sqrt [3]{a}-\sqrt [3]{b} x\right )}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx}{3 a^{2/3} b^{2/3}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} b^{4/3}}\right )}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \left (\frac {\int \frac {2 \sqrt [3]{a}-\sqrt [3]{b} x}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx}{3 a^{2/3} \sqrt [3]{b}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} b^{4/3}}\right )}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 1142

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \left (\frac {\frac {3}{2} \sqrt [3]{a} \int \frac {1}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx-\frac {\int -\frac {b \left (\sqrt [3]{a}-2 \sqrt [3]{b} x\right )}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx}{2 b}}{3 a^{2/3} \sqrt [3]{b}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} b^{4/3}}\right )}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \left (\frac {\frac {3}{2} \sqrt [3]{a} \int \frac {1}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx+\frac {\int \frac {b \left (\sqrt [3]{a}-2 \sqrt [3]{b} x\right )}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx}{2 b}}{3 a^{2/3} \sqrt [3]{b}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} b^{4/3}}\right )}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \left (\frac {\frac {3}{2} \sqrt [3]{a} \int \frac {1}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx+\frac {1}{2} \int \frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx}{3 a^{2/3} \sqrt [3]{b}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} b^{4/3}}\right )}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 1082

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \left (\frac {\frac {1}{2} \int \frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx+\frac {3 \int \frac {1}{-\left (1-\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}\right )^2-3}d\left (1-\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}\right )}{b}}{3 a^{2/3} \sqrt [3]{b}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} b^{4/3}}\right )}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \left (\frac {\frac {1}{2} \int \frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{b^{4/3} x^2-\sqrt [3]{a} b x+a^{2/3} b^{2/3}}dx-\frac {\sqrt {3} \arctan \left (\frac {1-\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{b}}{3 a^{2/3} \sqrt [3]{b}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} b^{4/3}}\right )}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {b^5 \left (a+b x^3\right ) \left (\frac {11 \left (\frac {8 \left (\frac {5 \left (\frac {2 \left (\frac {-\frac {\log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{2 b}-\frac {\sqrt {3} \arctan \left (\frac {1-\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{b}}{3 a^{2/3} \sqrt [3]{b}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} b^{4/3}}\right )}{3 a b}+\frac {x}{3 a b^2 \left (a+b x^3\right )}\right )}{6 a b}+\frac {x}{6 a b^3 \left (a+b x^3\right )^2}\right )}{9 a b}+\frac {x}{9 a b^4 \left (a+b x^3\right )^3}\right )}{12 a b}+\frac {x}{12 a b^5 \left (a+b x^3\right )^4}\right )}{\sqrt {a^2+2 a b x^3+b^2 x^6}}\)

Input:

Int[(a^2 + 2*a*b*x^3 + b^2*x^6)^(-5/2),x]
 

Output:

(b^5*(a + b*x^3)*(x/(12*a*b^5*(a + b*x^3)^4) + (11*(x/(9*a*b^4*(a + b*x^3) 
^3) + (8*(x/(6*a*b^3*(a + b*x^3)^2) + (5*(x/(3*a*b^2*(a + b*x^3)) + (2*(Lo 
g[a^(1/3) + b^(1/3)*x]/(3*a^(2/3)*b^(4/3)) + (-((Sqrt[3]*ArcTan[(1 - (2*b^ 
(1/3)*x)/a^(1/3))/Sqrt[3]])/b) - Log[a^(2/3) - a^(1/3)*b^(1/3)*x + b^(2/3) 
*x^2]/(2*b))/(3*a^(2/3)*b^(1/3))))/(3*a*b)))/(6*a*b)))/(9*a*b)))/(12*a*b)) 
)/Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6]
 

Defintions of rubi rules used

rule 16
Int[(c_.)/((a_.) + (b_.)*(x_)), x_Symbol] :> Simp[c*(Log[RemoveContent[a + 
b*x, x]]/b), x] /; FreeQ[{a, b, c}, x]
 

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 749
Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(-x)*((a + b*x^n)^(p + 
 1)/(a*n*(p + 1))), x] + Simp[(n*(p + 1) + 1)/(a*n*(p + 1))   Int[(a + b*x^ 
n)^(p + 1), x], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[p, -1] && (Inte 
gerQ[2*p] || Denominator[p + 1/n] < Denominator[p])
 

rule 750
Int[((a_) + (b_.)*(x_)^3)^(-1), x_Symbol] :> Simp[1/(3*Rt[a, 3]^2)   Int[1/ 
(Rt[a, 3] + Rt[b, 3]*x), x], x] + Simp[1/(3*Rt[a, 3]^2)   Int[(2*Rt[a, 3] - 
 Rt[b, 3]*x)/(Rt[a, 3]^2 - Rt[a, 3]*Rt[b, 3]*x + Rt[b, 3]^2*x^2), x], x] /; 
 FreeQ[{a, b}, x]
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1142
Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[(2*c*d - b*e)/(2*c)   Int[1/(a + b*x + c*x^2), x], x] + Simp[e/(2*c) 
Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x]
 

rule 1384
Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> S 
imp[(a + b*x^n + c*x^(2*n))^FracPart[p]/(c^IntPart[p]*(b/2 + c*x^n)^(2*Frac 
Part[p]))   Int[u*(b/2 + c*x^n)^(2*p), x], x] /; FreeQ[{a, b, c, n, p}, x] 
&& EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p - 1/2] && NeQ[u, x^(n 
- 1)] && NeQ[u, x^(2*n - 1)] &&  !(EqQ[p, 1/2] && EqQ[u, x^(-2*n - 1)])
 
Maple [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 3.

Time = 1.04 (sec) , antiderivative size = 110, normalized size of antiderivative = 0.31

method result size
risch \(\frac {\sqrt {\left (b \,x^{3}+a \right )^{2}}\, \left (\frac {55 b^{3} x^{10}}{243 a^{4}}+\frac {22 b^{2} x^{7}}{27 a^{3}}+\frac {341 b \,x^{4}}{324 a^{2}}+\frac {133 x}{243 a}\right )}{\left (b \,x^{3}+a \right )^{5}}+\frac {110 \sqrt {\left (b \,x^{3}+a \right )^{2}}\, \left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (b \,\textit {\_Z}^{3}+a \right )}{\sum }\frac {\ln \left (x -\textit {\_R} \right )}{\textit {\_R}^{2}}\right )}{729 \left (b \,x^{3}+a \right ) a^{4} b}\) \(110\)
default \(\frac {\left (-440 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (-2 x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right ) b^{4} x^{12}+440 \ln \left (x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right ) b^{4} x^{12}-220 \ln \left (x^{2}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x +\left (\frac {a}{b}\right )^{\frac {2}{3}}\right ) b^{4} x^{12}+660 \left (\frac {a}{b}\right )^{\frac {2}{3}} b^{4} x^{10}-1760 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (-2 x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right ) a \,b^{3} x^{9}+1760 \ln \left (x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right ) a \,b^{3} x^{9}-880 \ln \left (x^{2}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x +\left (\frac {a}{b}\right )^{\frac {2}{3}}\right ) a \,b^{3} x^{9}+2376 \left (\frac {a}{b}\right )^{\frac {2}{3}} a \,b^{3} x^{7}-2640 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (-2 x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right ) a^{2} b^{2} x^{6}+2640 \ln \left (x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right ) a^{2} b^{2} x^{6}-1320 \ln \left (x^{2}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x +\left (\frac {a}{b}\right )^{\frac {2}{3}}\right ) a^{2} b^{2} x^{6}+3069 \left (\frac {a}{b}\right )^{\frac {2}{3}} a^{2} b^{2} x^{4}-1760 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (-2 x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right ) a^{3} b \,x^{3}+1760 \ln \left (x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right ) a^{3} b \,x^{3}-880 \ln \left (x^{2}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x +\left (\frac {a}{b}\right )^{\frac {2}{3}}\right ) a^{3} b \,x^{3}+1596 \left (\frac {a}{b}\right )^{\frac {2}{3}} a^{3} b x -440 \sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (-2 x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right ) a^{4}+440 \ln \left (x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right ) a^{4}-220 \ln \left (x^{2}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x +\left (\frac {a}{b}\right )^{\frac {2}{3}}\right ) a^{4}\right ) \left (b \,x^{3}+a \right )}{2916 \left (\frac {a}{b}\right )^{\frac {2}{3}} b \,a^{4} {\left (\left (b \,x^{3}+a \right )^{2}\right )}^{\frac {5}{2}}}\) \(519\)

Input:

int(1/(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x,method=_RETURNVERBOSE)
 

Output:

((b*x^3+a)^2)^(1/2)/(b*x^3+a)^5*(55/243/a^4*b^3*x^10+22/27/a^3*b^2*x^7+341 
/324/a^2*b*x^4+133/243/a*x)+110/729*((b*x^3+a)^2)^(1/2)/(b*x^3+a)/a^4/b*su 
m(1/_R^2*ln(x-_R),_R=RootOf(_Z^3*b+a))
 

Fricas [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 719, normalized size of antiderivative = 2.05 \[ \int \frac {1}{\left (a^2+2 a b x^3+b^2 x^6\right )^{5/2}} \, dx =\text {Too large to display} \] Input:

integrate(1/(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x, algorithm="fricas")
 

Output:

[1/2916*(660*a^2*b^4*x^10 + 2376*a^3*b^3*x^7 + 3069*a^4*b^2*x^4 + 1596*a^5 
*b*x + 660*sqrt(1/3)*(a*b^5*x^12 + 4*a^2*b^4*x^9 + 6*a^3*b^3*x^6 + 4*a^4*b 
^2*x^3 + a^5*b)*sqrt(-(a^2*b)^(1/3)/b)*log((2*a*b*x^3 - 3*(a^2*b)^(1/3)*a* 
x - a^2 + 3*sqrt(1/3)*(2*a*b*x^2 + (a^2*b)^(2/3)*x - (a^2*b)^(1/3)*a)*sqrt 
(-(a^2*b)^(1/3)/b))/(b*x^3 + a)) - 220*(b^4*x^12 + 4*a*b^3*x^9 + 6*a^2*b^2 
*x^6 + 4*a^3*b*x^3 + a^4)*(a^2*b)^(2/3)*log(a*b*x^2 - (a^2*b)^(2/3)*x + (a 
^2*b)^(1/3)*a) + 440*(b^4*x^12 + 4*a*b^3*x^9 + 6*a^2*b^2*x^6 + 4*a^3*b*x^3 
 + a^4)*(a^2*b)^(2/3)*log(a*b*x + (a^2*b)^(2/3)))/(a^6*b^5*x^12 + 4*a^7*b^ 
4*x^9 + 6*a^8*b^3*x^6 + 4*a^9*b^2*x^3 + a^10*b), 1/2916*(660*a^2*b^4*x^10 
+ 2376*a^3*b^3*x^7 + 3069*a^4*b^2*x^4 + 1596*a^5*b*x + 1320*sqrt(1/3)*(a*b 
^5*x^12 + 4*a^2*b^4*x^9 + 6*a^3*b^3*x^6 + 4*a^4*b^2*x^3 + a^5*b)*sqrt((a^2 
*b)^(1/3)/b)*arctan(sqrt(1/3)*(2*(a^2*b)^(2/3)*x - (a^2*b)^(1/3)*a)*sqrt(( 
a^2*b)^(1/3)/b)/a^2) - 220*(b^4*x^12 + 4*a*b^3*x^9 + 6*a^2*b^2*x^6 + 4*a^3 
*b*x^3 + a^4)*(a^2*b)^(2/3)*log(a*b*x^2 - (a^2*b)^(2/3)*x + (a^2*b)^(1/3)* 
a) + 440*(b^4*x^12 + 4*a*b^3*x^9 + 6*a^2*b^2*x^6 + 4*a^3*b*x^3 + a^4)*(a^2 
*b)^(2/3)*log(a*b*x + (a^2*b)^(2/3)))/(a^6*b^5*x^12 + 4*a^7*b^4*x^9 + 6*a^ 
8*b^3*x^6 + 4*a^9*b^2*x^3 + a^10*b)]
 

Sympy [F]

\[ \int \frac {1}{\left (a^2+2 a b x^3+b^2 x^6\right )^{5/2}} \, dx=\int \frac {1}{\left (a^{2} + 2 a b x^{3} + b^{2} x^{6}\right )^{\frac {5}{2}}}\, dx \] Input:

integrate(1/(b**2*x**6+2*a*b*x**3+a**2)**(5/2),x)
 

Output:

Integral((a**2 + 2*a*b*x**3 + b**2*x**6)**(-5/2), x)
 

Maxima [A] (verification not implemented)

Time = 0.12 (sec) , antiderivative size = 189, normalized size of antiderivative = 0.54 \[ \int \frac {1}{\left (a^2+2 a b x^3+b^2 x^6\right )^{5/2}} \, dx=\frac {220 \, b^{3} x^{10} + 792 \, a b^{2} x^{7} + 1023 \, a^{2} b x^{4} + 532 \, a^{3} x}{972 \, {\left (a^{4} b^{4} x^{12} + 4 \, a^{5} b^{3} x^{9} + 6 \, a^{6} b^{2} x^{6} + 4 \, a^{7} b x^{3} + a^{8}\right )}} + \frac {110 \, \sqrt {3} \arctan \left (\frac {\sqrt {3} {\left (2 \, x - \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{729 \, a^{4} b \left (\frac {a}{b}\right )^{\frac {2}{3}}} - \frac {55 \, \log \left (x^{2} - x \left (\frac {a}{b}\right )^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{729 \, a^{4} b \left (\frac {a}{b}\right )^{\frac {2}{3}}} + \frac {110 \, \log \left (x + \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{729 \, a^{4} b \left (\frac {a}{b}\right )^{\frac {2}{3}}} \] Input:

integrate(1/(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x, algorithm="maxima")
 

Output:

1/972*(220*b^3*x^10 + 792*a*b^2*x^7 + 1023*a^2*b*x^4 + 532*a^3*x)/(a^4*b^4 
*x^12 + 4*a^5*b^3*x^9 + 6*a^6*b^2*x^6 + 4*a^7*b*x^3 + a^8) + 110/729*sqrt( 
3)*arctan(1/3*sqrt(3)*(2*x - (a/b)^(1/3))/(a/b)^(1/3))/(a^4*b*(a/b)^(2/3)) 
 - 55/729*log(x^2 - x*(a/b)^(1/3) + (a/b)^(2/3))/(a^4*b*(a/b)^(2/3)) + 110 
/729*log(x + (a/b)^(1/3))/(a^4*b*(a/b)^(2/3))
 

Giac [A] (verification not implemented)

Time = 0.13 (sec) , antiderivative size = 199, normalized size of antiderivative = 0.57 \[ \int \frac {1}{\left (a^2+2 a b x^3+b^2 x^6\right )^{5/2}} \, dx=-\frac {110 \, \left (-\frac {a}{b}\right )^{\frac {1}{3}} \log \left ({\left | x - \left (-\frac {a}{b}\right )^{\frac {1}{3}} \right |}\right )}{729 \, a^{5} \mathrm {sgn}\left (b x^{3} + a\right )} + \frac {110 \, \sqrt {3} \left (-a b^{2}\right )^{\frac {1}{3}} \arctan \left (\frac {\sqrt {3} {\left (2 \, x + \left (-\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (-\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{729 \, a^{5} b \mathrm {sgn}\left (b x^{3} + a\right )} + \frac {55 \, \left (-a b^{2}\right )^{\frac {1}{3}} \log \left (x^{2} + x \left (-\frac {a}{b}\right )^{\frac {1}{3}} + \left (-\frac {a}{b}\right )^{\frac {2}{3}}\right )}{729 \, a^{5} b \mathrm {sgn}\left (b x^{3} + a\right )} + \frac {220 \, b^{3} x^{10} + 792 \, a b^{2} x^{7} + 1023 \, a^{2} b x^{4} + 532 \, a^{3} x}{972 \, {\left (b x^{3} + a\right )}^{4} a^{4} \mathrm {sgn}\left (b x^{3} + a\right )} \] Input:

integrate(1/(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x, algorithm="giac")
 

Output:

-110/729*(-a/b)^(1/3)*log(abs(x - (-a/b)^(1/3)))/(a^5*sgn(b*x^3 + a)) + 11 
0/729*sqrt(3)*(-a*b^2)^(1/3)*arctan(1/3*sqrt(3)*(2*x + (-a/b)^(1/3))/(-a/b 
)^(1/3))/(a^5*b*sgn(b*x^3 + a)) + 55/729*(-a*b^2)^(1/3)*log(x^2 + x*(-a/b) 
^(1/3) + (-a/b)^(2/3))/(a^5*b*sgn(b*x^3 + a)) + 1/972*(220*b^3*x^10 + 792* 
a*b^2*x^7 + 1023*a^2*b*x^4 + 532*a^3*x)/((b*x^3 + a)^4*a^4*sgn(b*x^3 + a))
 

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{\left (a^2+2 a b x^3+b^2 x^6\right )^{5/2}} \, dx=\int \frac {1}{{\left (a^2+2\,a\,b\,x^3+b^2\,x^6\right )}^{5/2}} \,d x \] Input:

int(1/(a^2 + b^2*x^6 + 2*a*b*x^3)^(5/2),x)
 

Output:

int(1/(a^2 + b^2*x^6 + 2*a*b*x^3)^(5/2), x)
 

Reduce [B] (verification not implemented)

Time = 0.18 (sec) , antiderivative size = 492, normalized size of antiderivative = 1.40 \[ \int \frac {1}{\left (a^2+2 a b x^3+b^2 x^6\right )^{5/2}} \, dx =\text {Too large to display} \] Input:

int(1/(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x)
 

Output:

( - 440*a**(1/3)*sqrt(3)*atan((a**(1/3) - 2*b**(1/3)*x)/(a**(1/3)*sqrt(3)) 
)*a**4 - 1760*a**(1/3)*sqrt(3)*atan((a**(1/3) - 2*b**(1/3)*x)/(a**(1/3)*sq 
rt(3)))*a**3*b*x**3 - 2640*a**(1/3)*sqrt(3)*atan((a**(1/3) - 2*b**(1/3)*x) 
/(a**(1/3)*sqrt(3)))*a**2*b**2*x**6 - 1760*a**(1/3)*sqrt(3)*atan((a**(1/3) 
 - 2*b**(1/3)*x)/(a**(1/3)*sqrt(3)))*a*b**3*x**9 - 440*a**(1/3)*sqrt(3)*at 
an((a**(1/3) - 2*b**(1/3)*x)/(a**(1/3)*sqrt(3)))*b**4*x**12 - 220*a**(1/3) 
*log(a**(2/3) - b**(1/3)*a**(1/3)*x + b**(2/3)*x**2)*a**4 - 880*a**(1/3)*l 
og(a**(2/3) - b**(1/3)*a**(1/3)*x + b**(2/3)*x**2)*a**3*b*x**3 - 1320*a**( 
1/3)*log(a**(2/3) - b**(1/3)*a**(1/3)*x + b**(2/3)*x**2)*a**2*b**2*x**6 - 
880*a**(1/3)*log(a**(2/3) - b**(1/3)*a**(1/3)*x + b**(2/3)*x**2)*a*b**3*x* 
*9 - 220*a**(1/3)*log(a**(2/3) - b**(1/3)*a**(1/3)*x + b**(2/3)*x**2)*b**4 
*x**12 + 440*a**(1/3)*log(a**(1/3) + b**(1/3)*x)*a**4 + 1760*a**(1/3)*log( 
a**(1/3) + b**(1/3)*x)*a**3*b*x**3 + 2640*a**(1/3)*log(a**(1/3) + b**(1/3) 
*x)*a**2*b**2*x**6 + 1760*a**(1/3)*log(a**(1/3) + b**(1/3)*x)*a*b**3*x**9 
+ 440*a**(1/3)*log(a**(1/3) + b**(1/3)*x)*b**4*x**12 + 1596*b**(1/3)*a**4* 
x + 3069*b**(1/3)*a**3*b*x**4 + 2376*b**(1/3)*a**2*b**2*x**7 + 660*b**(1/3 
)*a*b**3*x**10)/(2916*b**(1/3)*a**5*(a**4 + 4*a**3*b*x**3 + 6*a**2*b**2*x* 
*6 + 4*a*b**3*x**9 + b**4*x**12))