Integrand size = 22, antiderivative size = 157 \[ \int \frac {(d x)^m}{\sqrt {a+b x^3+c x^6}} \, dx=\frac {(d x)^{1+m} \sqrt {1+\frac {2 c x^3}{b-\sqrt {b^2-4 a c}}} \sqrt {1+\frac {2 c x^3}{b+\sqrt {b^2-4 a c}}} \operatorname {AppellF1}\left (\frac {1+m}{3},\frac {1}{2},\frac {1}{2},\frac {4+m}{3},-\frac {2 c x^3}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^3}{b+\sqrt {b^2-4 a c}}\right )}{d (1+m) \sqrt {a+b x^3+c x^6}} \] Output:
(d*x)^(1+m)*(1+2*c*x^3/(b-(-4*a*c+b^2)^(1/2)))^(1/2)*(1+2*c*x^3/(b+(-4*a*c +b^2)^(1/2)))^(1/2)*AppellF1(1/3+1/3*m,1/2,1/2,4/3+1/3*m,-2*c*x^3/(b-(-4*a *c+b^2)^(1/2)),-2*c*x^3/(b+(-4*a*c+b^2)^(1/2)))/d/(1+m)/(c*x^6+b*x^3+a)^(1 /2)
Time = 2.36 (sec) , antiderivative size = 181, normalized size of antiderivative = 1.15 \[ \int \frac {(d x)^m}{\sqrt {a+b x^3+c x^6}} \, dx=\frac {x (d x)^m \sqrt {\frac {b-\sqrt {b^2-4 a c}+2 c x^3}{b-\sqrt {b^2-4 a c}}} \sqrt {\frac {b+\sqrt {b^2-4 a c}+2 c x^3}{b+\sqrt {b^2-4 a c}}} \operatorname {AppellF1}\left (\frac {1+m}{3},\frac {1}{2},\frac {1}{2},\frac {4+m}{3},-\frac {2 c x^3}{b+\sqrt {b^2-4 a c}},\frac {2 c x^3}{-b+\sqrt {b^2-4 a c}}\right )}{(1+m) \sqrt {a+b x^3+c x^6}} \] Input:
Integrate[(d*x)^m/Sqrt[a + b*x^3 + c*x^6],x]
Output:
(x*(d*x)^m*Sqrt[(b - Sqrt[b^2 - 4*a*c] + 2*c*x^3)/(b - Sqrt[b^2 - 4*a*c])] *Sqrt[(b + Sqrt[b^2 - 4*a*c] + 2*c*x^3)/(b + Sqrt[b^2 - 4*a*c])]*AppellF1[ (1 + m)/3, 1/2, 1/2, (4 + m)/3, (-2*c*x^3)/(b + Sqrt[b^2 - 4*a*c]), (2*c*x ^3)/(-b + Sqrt[b^2 - 4*a*c])])/((1 + m)*Sqrt[a + b*x^3 + c*x^6])
Time = 0.32 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {1721, 1012}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(d x)^m}{\sqrt {a+b x^3+c x^6}} \, dx\) |
\(\Big \downarrow \) 1721 |
\(\displaystyle \frac {\sqrt {\frac {2 c x^3}{b-\sqrt {b^2-4 a c}}+1} \sqrt {\frac {2 c x^3}{\sqrt {b^2-4 a c}+b}+1} \int \frac {(d x)^m}{\sqrt {\frac {2 c x^3}{b-\sqrt {b^2-4 a c}}+1} \sqrt {\frac {2 c x^3}{b+\sqrt {b^2-4 a c}}+1}}dx}{\sqrt {a+b x^3+c x^6}}\) |
\(\Big \downarrow \) 1012 |
\(\displaystyle \frac {(d x)^{m+1} \sqrt {\frac {2 c x^3}{b-\sqrt {b^2-4 a c}}+1} \sqrt {\frac {2 c x^3}{\sqrt {b^2-4 a c}+b}+1} \operatorname {AppellF1}\left (\frac {m+1}{3},\frac {1}{2},\frac {1}{2},\frac {m+4}{3},-\frac {2 c x^3}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^3}{b+\sqrt {b^2-4 a c}}\right )}{d (m+1) \sqrt {a+b x^3+c x^6}}\) |
Input:
Int[(d*x)^m/Sqrt[a + b*x^3 + c*x^6],x]
Output:
((d*x)^(1 + m)*Sqrt[1 + (2*c*x^3)/(b - Sqrt[b^2 - 4*a*c])]*Sqrt[1 + (2*c*x ^3)/(b + Sqrt[b^2 - 4*a*c])]*AppellF1[(1 + m)/3, 1/2, 1/2, (4 + m)/3, (-2* c*x^3)/(b - Sqrt[b^2 - 4*a*c]), (-2*c*x^3)/(b + Sqrt[b^2 - 4*a*c])])/(d*(1 + m)*Sqrt[a + b*x^3 + c*x^6])
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ ))^(q_), x_Symbol] :> Simp[a^p*c^q*((e*x)^(m + 1)/(e*(m + 1)))*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, (-b)*(x^n/a), (-d)*(x^n/c)], x] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])
Int[((d_.)*(x_))^(m_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_), x _Symbol] :> Simp[a^IntPart[p]*((a + b*x^n + c*x^(2*n))^FracPart[p]/((1 + 2* c*(x^n/(b + Rt[b^2 - 4*a*c, 2])))^FracPart[p]*(1 + 2*c*(x^n/(b - Rt[b^2 - 4 *a*c, 2])))^FracPart[p])) Int[(d*x)^m*(1 + 2*c*(x^n/(b + Sqrt[b^2 - 4*a*c ])))^p*(1 + 2*c*(x^n/(b - Sqrt[b^2 - 4*a*c])))^p, x], x] /; FreeQ[{a, b, c, d, m, n, p}, x] && EqQ[n2, 2*n]
\[\int \frac {\left (d x \right )^{m}}{\sqrt {c \,x^{6}+b \,x^{3}+a}}d x\]
Input:
int((d*x)^m/(c*x^6+b*x^3+a)^(1/2),x)
Output:
int((d*x)^m/(c*x^6+b*x^3+a)^(1/2),x)
\[ \int \frac {(d x)^m}{\sqrt {a+b x^3+c x^6}} \, dx=\int { \frac {\left (d x\right )^{m}}{\sqrt {c x^{6} + b x^{3} + a}} \,d x } \] Input:
integrate((d*x)^m/(c*x^6+b*x^3+a)^(1/2),x, algorithm="fricas")
Output:
integral((d*x)^m/sqrt(c*x^6 + b*x^3 + a), x)
\[ \int \frac {(d x)^m}{\sqrt {a+b x^3+c x^6}} \, dx=\int \frac {\left (d x\right )^{m}}{\sqrt {a + b x^{3} + c x^{6}}}\, dx \] Input:
integrate((d*x)**m/(c*x**6+b*x**3+a)**(1/2),x)
Output:
Integral((d*x)**m/sqrt(a + b*x**3 + c*x**6), x)
\[ \int \frac {(d x)^m}{\sqrt {a+b x^3+c x^6}} \, dx=\int { \frac {\left (d x\right )^{m}}{\sqrt {c x^{6} + b x^{3} + a}} \,d x } \] Input:
integrate((d*x)^m/(c*x^6+b*x^3+a)^(1/2),x, algorithm="maxima")
Output:
integrate((d*x)^m/sqrt(c*x^6 + b*x^3 + a), x)
\[ \int \frac {(d x)^m}{\sqrt {a+b x^3+c x^6}} \, dx=\int { \frac {\left (d x\right )^{m}}{\sqrt {c x^{6} + b x^{3} + a}} \,d x } \] Input:
integrate((d*x)^m/(c*x^6+b*x^3+a)^(1/2),x, algorithm="giac")
Output:
integrate((d*x)^m/sqrt(c*x^6 + b*x^3 + a), x)
Timed out. \[ \int \frac {(d x)^m}{\sqrt {a+b x^3+c x^6}} \, dx=\int \frac {{\left (d\,x\right )}^m}{\sqrt {c\,x^6+b\,x^3+a}} \,d x \] Input:
int((d*x)^m/(a + b*x^3 + c*x^6)^(1/2),x)
Output:
int((d*x)^m/(a + b*x^3 + c*x^6)^(1/2), x)
\[ \int \frac {(d x)^m}{\sqrt {a+b x^3+c x^6}} \, dx=d^{m} \left (\int \frac {x^{m} \sqrt {c \,x^{6}+b \,x^{3}+a}}{c \,x^{6}+b \,x^{3}+a}d x \right ) \] Input:
int((d*x)^m/(c*x^6+b*x^3+a)^(1/2),x)
Output:
d**m*int((x**m*sqrt(a + b*x**3 + c*x**6))/(a + b*x**3 + c*x**6),x)