Integrand size = 32, antiderivative size = 484 \[ \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right ) \, dx=-\frac {(b D (9+4 p)-c C (13+8 p)) x \left (a+b x^4+c x^8\right )^{1+p}}{c^2 (9+8 p) (13+8 p)}+\frac {D x^5 \left (a+b x^4+c x^8\right )^{1+p}}{c (13+8 p)}+\frac {\left (A c^2 \left (117+176 p+64 p^2\right )+a (b D (9+4 p)-c C (13+8 p))\right ) x \left (1+\frac {2 c x^4}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (1+\frac {2 c x^4}{b+\sqrt {b^2-4 a c}}\right )^{-p} \left (a+b x^4+c x^8\right )^p \operatorname {AppellF1}\left (\frac {1}{4},-p,-p,\frac {5}{4},-\frac {2 c x^4}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^4}{b+\sqrt {b^2-4 a c}}\right )}{c^2 (9+8 p) (13+8 p)}-\frac {\left (5 a c D (9+8 p)-b^2 D \left (45+56 p+16 p^2\right )+b c C \left (65+92 p+32 p^2\right )-B c^2 \left (117+176 p+64 p^2\right )\right ) x^5 \left (1+\frac {2 c x^4}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (1+\frac {2 c x^4}{b+\sqrt {b^2-4 a c}}\right )^{-p} \left (a+b x^4+c x^8\right )^p \operatorname {AppellF1}\left (\frac {5}{4},-p,-p,\frac {9}{4},-\frac {2 c x^4}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^4}{b+\sqrt {b^2-4 a c}}\right )}{5 c^2 (9+8 p) (13+8 p)} \] Output:
-(b*D*(9+4*p)-c*C*(13+8*p))*x*(c*x^8+b*x^4+a)^(p+1)/c^2/(9+8*p)/(13+8*p)+D *x^5*(c*x^8+b*x^4+a)^(p+1)/c/(13+8*p)+(A*c^2*(64*p^2+176*p+117)+a*(b*D*(9+ 4*p)-c*C*(13+8*p)))*x*(c*x^8+b*x^4+a)^p*AppellF1(1/4,-p,-p,5/4,-2*c*x^4/(b -(-4*a*c+b^2)^(1/2)),-2*c*x^4/(b+(-4*a*c+b^2)^(1/2)))/c^2/(9+8*p)/(13+8*p) /((1+2*c*x^4/(b-(-4*a*c+b^2)^(1/2)))^p)/((1+2*c*x^4/(b+(-4*a*c+b^2)^(1/2)) )^p)-1/5*(5*a*c*D*(9+8*p)-b^2*D*(16*p^2+56*p+45)+b*c*C*(32*p^2+92*p+65)-B* c^2*(64*p^2+176*p+117))*x^5*(c*x^8+b*x^4+a)^p*AppellF1(5/4,-p,-p,9/4,-2*c* x^4/(b-(-4*a*c+b^2)^(1/2)),-2*c*x^4/(b+(-4*a*c+b^2)^(1/2)))/c^2/(9+8*p)/(1 3+8*p)/((1+2*c*x^4/(b-(-4*a*c+b^2)^(1/2)))^p)/((1+2*c*x^4/(b+(-4*a*c+b^2)^ (1/2)))^p)
Time = 2.45 (sec) , antiderivative size = 363, normalized size of antiderivative = 0.75 \[ \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right ) \, dx=\frac {1}{585} x \left (\frac {b-\sqrt {b^2-4 a c}+2 c x^4}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (\frac {b+\sqrt {b^2-4 a c}+2 c x^4}{b+\sqrt {b^2-4 a c}}\right )^{-p} \left (a+b x^4+c x^8\right )^p \left (585 A \operatorname {AppellF1}\left (\frac {1}{4},-p,-p,\frac {5}{4},-\frac {2 c x^4}{b+\sqrt {b^2-4 a c}},\frac {2 c x^4}{-b+\sqrt {b^2-4 a c}}\right )+117 B x^4 \operatorname {AppellF1}\left (\frac {5}{4},-p,-p,\frac {9}{4},-\frac {2 c x^4}{b+\sqrt {b^2-4 a c}},\frac {2 c x^4}{-b+\sqrt {b^2-4 a c}}\right )+65 C x^8 \operatorname {AppellF1}\left (\frac {9}{4},-p,-p,\frac {13}{4},-\frac {2 c x^4}{b+\sqrt {b^2-4 a c}},\frac {2 c x^4}{-b+\sqrt {b^2-4 a c}}\right )+45 D x^{12} \operatorname {AppellF1}\left (\frac {13}{4},-p,-p,\frac {17}{4},-\frac {2 c x^4}{b+\sqrt {b^2-4 a c}},\frac {2 c x^4}{-b+\sqrt {b^2-4 a c}}\right )\right ) \] Input:
Integrate[(a + b*x^4 + c*x^8)^p*(A + B*x^4 + C*x^8 + D*x^12),x]
Output:
(x*(a + b*x^4 + c*x^8)^p*(585*A*AppellF1[1/4, -p, -p, 5/4, (-2*c*x^4)/(b + Sqrt[b^2 - 4*a*c]), (2*c*x^4)/(-b + Sqrt[b^2 - 4*a*c])] + 117*B*x^4*Appel lF1[5/4, -p, -p, 9/4, (-2*c*x^4)/(b + Sqrt[b^2 - 4*a*c]), (2*c*x^4)/(-b + Sqrt[b^2 - 4*a*c])] + 65*C*x^8*AppellF1[9/4, -p, -p, 13/4, (-2*c*x^4)/(b + Sqrt[b^2 - 4*a*c]), (2*c*x^4)/(-b + Sqrt[b^2 - 4*a*c])] + 45*D*x^12*Appel lF1[13/4, -p, -p, 17/4, (-2*c*x^4)/(b + Sqrt[b^2 - 4*a*c]), (2*c*x^4)/(-b + Sqrt[b^2 - 4*a*c])]))/(585*((b - Sqrt[b^2 - 4*a*c] + 2*c*x^4)/(b - Sqrt[ b^2 - 4*a*c]))^p*((b + Sqrt[b^2 - 4*a*c] + 2*c*x^4)/(b + Sqrt[b^2 - 4*a*c] ))^p)
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right ) \, dx\) |
\(\Big \downarrow \) 2329 |
\(\displaystyle \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right )dx\) |
Input:
Int[(a + b*x^4 + c*x^8)^p*(A + B*x^4 + C*x^8 + D*x^12),x]
Output:
$Aborted
Int[(Pq_)*((a_) + (b_.)*(x_)^(n_.) + (c_.)*(x_)^(n2_.))^(p_.), x_Symbol] :> Unintegrable[Pq*(a + b*x^n + c*x^(2*n))^p, x] /; FreeQ[{a, b, c, n, p}, x] && EqQ[n2, 2*n] && (PolyQ[Pq, x] || PolyQ[Pq, x^n])
\[\int \left (c \,x^{8}+b \,x^{4}+a \right )^{p} \left (D x^{12}+C \,x^{8}+B \,x^{4}+A \right )d x\]
Input:
int((c*x^8+b*x^4+a)^p*(D*x^12+C*x^8+B*x^4+A),x)
Output:
int((c*x^8+b*x^4+a)^p*(D*x^12+C*x^8+B*x^4+A),x)
\[ \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right ) \, dx=\int { {\left (D x^{12} + C x^{8} + B x^{4} + A\right )} {\left (c x^{8} + b x^{4} + a\right )}^{p} \,d x } \] Input:
integrate((c*x^8+b*x^4+a)^p*(D*x^12+C*x^8+B*x^4+A),x, algorithm="fricas")
Output:
integral((D*x^12 + C*x^8 + B*x^4 + A)*(c*x^8 + b*x^4 + a)^p, x)
Timed out. \[ \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right ) \, dx=\text {Timed out} \] Input:
integrate((c*x**8+b*x**4+a)**p*(D*x**12+C*x**8+B*x**4+A),x)
Output:
Timed out
\[ \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right ) \, dx=\int { {\left (D x^{12} + C x^{8} + B x^{4} + A\right )} {\left (c x^{8} + b x^{4} + a\right )}^{p} \,d x } \] Input:
integrate((c*x^8+b*x^4+a)^p*(D*x^12+C*x^8+B*x^4+A),x, algorithm="maxima")
Output:
integrate((D*x^12 + C*x^8 + B*x^4 + A)*(c*x^8 + b*x^4 + a)^p, x)
\[ \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right ) \, dx=\int { {\left (D x^{12} + C x^{8} + B x^{4} + A\right )} {\left (c x^{8} + b x^{4} + a\right )}^{p} \,d x } \] Input:
integrate((c*x^8+b*x^4+a)^p*(D*x^12+C*x^8+B*x^4+A),x, algorithm="giac")
Output:
integrate((D*x^12 + C*x^8 + B*x^4 + A)*(c*x^8 + b*x^4 + a)^p, x)
Timed out. \[ \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right ) \, dx=\int {\left (c\,x^8+b\,x^4+a\right )}^p\,\left (A+B\,x^4+C\,x^8+x^{12}\,D\right ) \,d x \] Input:
int((a + b*x^4 + c*x^8)^p*(A + B*x^4 + C*x^8 + x^12*D),x)
Output:
int((a + b*x^4 + c*x^8)^p*(A + B*x^4 + C*x^8 + x^12*D), x)
\[ \int \left (a+b x^4+c x^8\right )^p \left (A+B x^4+C x^8+D x^{12}\right ) \, dx=\text {too large to display} \] Input:
int((c*x^8+b*x^4+a)^p*(D*x^12+C*x^8+B*x^4+A),x)
Output:
( - 256*(a + b*x**4 + c*x**8)**p*a*b*c*d*p**3*x - 896*(a + b*x**4 + c*x**8 )**p*a*b*c*d*p**2*x - 540*(a + b*x**4 + c*x**8)**p*a*b*c*d*p*x + 1024*(a + b*x**4 + c*x**8)**p*a*c**3*p**3*x + 2880*(a + b*x**4 + c*x**8)**p*a*c**3* p**2*x + 2336*(a + b*x**4 + c*x**8)**p*a*c**3*p*x + 585*(a + b*x**4 + c*x* *8)**p*a*c**3*x + 512*(a + b*x**4 + c*x**8)**p*a*c**2*d*p**3*x**5 + 640*(a + b*x**4 + c*x**8)**p*a*c**2*d*p**2*x**5 + 72*(a + b*x**4 + c*x**8)**p*a* c**2*d*p*x**5 + 64*(a + b*x**4 + c*x**8)**p*b**3*d*p**3*x + 224*(a + b*x** 4 + c*x**8)**p*b**3*d*p**2*x + 180*(a + b*x**4 + c*x**8)**p*b**3*d*p*x + 1 28*(a + b*x**4 + c*x**8)**p*b**2*c**2*p**3*x + 336*(a + b*x**4 + c*x**8)** p*b**2*c**2*p**2*x + 208*(a + b*x**4 + c*x**8)**p*b**2*c**2*p*x - 128*(a + b*x**4 + c*x**8)**p*b**2*c*d*p**3*x**5 - 304*(a + b*x**4 + c*x**8)**p*b** 2*c*d*p**2*x**5 - 36*(a + b*x**4 + c*x**8)**p*b**2*c*d*p*x**5 + 768*(a + b *x**4 + c*x**8)**p*b*c**3*p**3*x**5 + 1920*(a + b*x**4 + c*x**8)**p*b*c**3 *p**2*x**5 + 1164*(a + b*x**4 + c*x**8)**p*b*c**3*p*x**5 + 117*(a + b*x**4 + c*x**8)**p*b*c**3*x**5 + 256*(a + b*x**4 + c*x**8)**p*b*c**2*d*p**3*x** 9 + 192*(a + b*x**4 + c*x**8)**p*b*c**2*d*p**2*x**9 + 20*(a + b*x**4 + c*x **8)**p*b*c**2*d*p*x**9 + 512*(a + b*x**4 + c*x**8)**p*c**4*p**3*x**9 + 12 16*(a + b*x**4 + c*x**8)**p*c**4*p**2*x**9 + 664*(a + b*x**4 + c*x**8)**p* c**4*p*x**9 + 65*(a + b*x**4 + c*x**8)**p*c**4*x**9 + 512*(a + b*x**4 + c* x**8)**p*c**3*d*p**3*x**13 + 960*(a + b*x**4 + c*x**8)**p*c**3*d*p**2*x...