Integrand size = 24, antiderivative size = 1490 \[ \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}} \, dx =\text {Too large to display} \] Output:
e^4*x/(a*e^4+b*d^2*e^2+c*d^4)/(-e^2*x^2+d^2)/(c*x^4+b*x^2+a)^(1/2)+2*d*e*( b*c*d^2+b^2*e^2-2*a*c*e^2+c*(b*e^2+2*c*d^2)*x^2)/(-4*a*c+b^2)/(a*e^4+b*d^2 *e^2+c*d^4)/(-e^2*x^2+d^2)/(c*x^4+b*x^2+a)^(1/2)-x*(a*e^2*(-b*e^2+2*c*d^2) *(b*c*d^2+(-2*a*c+b^2)*e^2)-(c*(-2*a*c+b^2)*d^2+b*(-3*a*c+b^2)*e^2)*(-3*a* e^4+b*d^2*e^2+c*d^4)-c*((b*c*d^2+(-2*a*c+b^2)*e^2)*(-3*a*e^4+b*d^2*e^2+c*d ^4)-a*e^2*(-b^2*e^4+4*c^2*d^4))*x^2)/a/(-4*a*c+b^2)/(a*e^4+b*d^2*e^2+c*d^4 )^2/(c*x^4+b*x^2+a)^(1/2)-c^(1/2)*(b^3*d^2*e^4+b*c*d^2*(-5*a*e^4+c*d^4)-6* a*c*e^2*(-a*e^4+c*d^4)+2*b^2*(-a*e^6+c*d^4*e^2))*x*(c*x^4+b*x^2+a)^(1/2)/a /(-4*a*c+b^2)/(a*e^4+b*d^2*e^2+c*d^4)^2/(a^(1/2)+c^(1/2)*x^2)-d*e^3*(-8*a* c*e^4+3*b^2*e^4+4*b*c*d^2*e^2+4*c^2*d^4)*(c*x^4+b*x^2+a)^(1/2)/(-4*a*c+b^2 )/(a*e^4+b*d^2*e^2+c*d^4)^2/(-e^2*x^2+d^2)+3/2*d*e^5*(b*e^2+2*c*d^2)*arcta nh((a*e^4+b*d^2*e^2+c*d^4)^(1/2)*x/d/e/(c*x^4+b*x^2+a)^(1/2))/(a*e^4+b*d^2 *e^2+c*d^4)^(5/2)-3/2*d*e^5*(b*e^2+2*c*d^2)*arctanh(1/2*(b*d^2+2*a*e^2+(b* e^2+2*c*d^2)*x^2)/(a*e^4+b*d^2*e^2+c*d^4)^(1/2)/(c*x^4+b*x^2+a)^(1/2))/(a* e^4+b*d^2*e^2+c*d^4)^(5/2)+c^(1/4)*(b^3*d^2*e^4+b*c*d^2*(-5*a*e^4+c*d^4)-6 *a*c*e^2*(-a*e^4+c*d^4)+2*b^2*(-a*e^6+c*d^4*e^2))*(a^(1/2)+c^(1/2)*x^2)*(( c*x^4+b*x^2+a)/(a^(1/2)+c^(1/2)*x^2)^2)^(1/2)*EllipticE(sin(2*arctan(c^(1/ 4)*x/a^(1/4))),1/2*(2-b/a^(1/2)/c^(1/2))^(1/2))/a^(3/4)/(-4*a*c+b^2)/(a*e^ 4+b*d^2*e^2+c*d^4)^2/(c*x^4+b*x^2+a)^(1/2)-1/2*c^(1/4)*(c^(3/2)*d^4-2*a^(1 /2)*c*d^2*e^2-2*a^(1/2)*b*e^4+c^(1/2)*(3*a*e^4+b*d^2*e^2))*(a^(1/2)+c^(...
Result contains complex when optimal does not.
Time = 20.72 (sec) , antiderivative size = 10488, normalized size of antiderivative = 7.04 \[ \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}} \, dx=\text {Result too large to show} \] Input:
Integrate[1/((d + e*x)^2*(a + b*x^2 + c*x^4)^(3/2)),x]
Output:
Result too large to show
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}} \, dx\) |
\(\Big \downarrow \) 7299 |
\(\displaystyle \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}}dx\) |
Input:
Int[1/((d + e*x)^2*(a + b*x^2 + c*x^4)^(3/2)),x]
Output:
$Aborted
Time = 0.92 (sec) , antiderivative size = 1545, normalized size of antiderivative = 1.04
method | result | size |
default | \(\text {Expression too large to display}\) | \(1545\) |
elliptic | \(\text {Expression too large to display}\) | \(1545\) |
Input:
int(1/(e*x+d)^2/(c*x^4+b*x^2+a)^(3/2),x,method=_RETURNVERBOSE)
Output:
-e^7/(a*e^4+b*d^2*e^2+c*d^4)^2*(c*x^4+b*x^2+a)^(1/2)/(e*x+d)-2*c*(1/2*(2*a ^2*c*e^6-a*b^2*e^6-5*a*b*c*d^2*e^4-6*a*c^2*d^4*e^2+b^3*d^2*e^4+2*b^2*c*d^4 *e^2+b*c^2*d^6)/a/(4*a*c-b^2)/(a*e^4+b*d^2*e^2+c*d^4)^2*x^3-d*e*(2*a*c*e^4 -b^2*e^4-2*b*c*d^2*e^2-2*c^2*d^4)/(4*a*c-b^2)/(a*e^4+b*d^2*e^2+c*d^4)^2*x^ 2+1/2*(3*a^2*b*c*e^6+6*a^2*c^2*d^2*e^4-a*b^3*e^6-6*a*b^2*c*d^2*e^4-7*a*b*c ^2*d^4*e^2-2*a*c^3*d^6+b^4*d^2*e^4+2*b^3*c*d^4*e^2+b^2*c^2*d^6)/a/(4*a*c-b ^2)/c/(a*e^4+b*d^2*e^2+c*d^4)^2*x-d*e*(3*a*b*c*e^4+4*a*c^2*d^2*e^2-b^3*e^4 -2*b^2*c*d^2*e^2-b*c^2*d^4)/(4*a*c-b^2)/(a*e^4+b*d^2*e^2+c*d^4)^2/c)/((x^4 +b/c*x^2+a/c)*c)^(1/2)+1/4*(-c*d^2*e^4/(a*e^4+b*d^2*e^2+c*d^4)^2-(a*b*e^6+ 3*a*c*d^2*e^4-b^2*d^2*e^4-2*b*c*d^4*e^2-c^2*d^6)/a/(a*e^4+b*d^2*e^2+c*d^4) ^2+(3*a^2*b*c*e^6+6*a^2*c^2*d^2*e^4-a*b^3*e^6-6*a*b^2*c*d^2*e^4-7*a*b*c^2* d^4*e^2-2*a*c^3*d^6+b^4*d^2*e^4+2*b^3*c*d^4*e^2+b^2*c^2*d^6)/a/(4*a*c-b^2) /(a*e^4+b*d^2*e^2+c*d^4)^2)*2^(1/2)/((-b+(-4*a*c+b^2)^(1/2))/a)^(1/2)*(4-2 *(-b+(-4*a*c+b^2)^(1/2))/a*x^2)^(1/2)*(4+2*(b+(-4*a*c+b^2)^(1/2))/a*x^2)^( 1/2)/(c*x^4+b*x^2+a)^(1/2)*EllipticF(1/2*x*2^(1/2)*((-b+(-4*a*c+b^2)^(1/2) )/a)^(1/2),1/2*(-4+2*b*(b+(-4*a*c+b^2)^(1/2))/a/c)^(1/2))-1/2*(e^6*c/(a*e^ 4+b*d^2*e^2+c*d^4)^2+c*(2*a^2*c*e^6-a*b^2*e^6-5*a*b*c*d^2*e^4-6*a*c^2*d^4* e^2+b^3*d^2*e^4+2*b^2*c*d^4*e^2+b*c^2*d^6)/a/(4*a*c-b^2)/(a*e^4+b*d^2*e^2+ c*d^4)^2)*a*2^(1/2)/((-b+(-4*a*c+b^2)^(1/2))/a)^(1/2)*(4-2*(-b+(-4*a*c+b^2 )^(1/2))/a*x^2)^(1/2)*(4+2*(b+(-4*a*c+b^2)^(1/2))/a*x^2)^(1/2)/(c*x^4+b...
Timed out. \[ \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}} \, dx=\text {Timed out} \] Input:
integrate(1/(e*x+d)^2/(c*x^4+b*x^2+a)^(3/2),x, algorithm="fricas")
Output:
Timed out
\[ \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}} \, dx=\int \frac {1}{\left (d + e x\right )^{2} \left (a + b x^{2} + c x^{4}\right )^{\frac {3}{2}}}\, dx \] Input:
integrate(1/(e*x+d)**2/(c*x**4+b*x**2+a)**(3/2),x)
Output:
Integral(1/((d + e*x)**2*(a + b*x**2 + c*x**4)**(3/2)), x)
\[ \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}} \, dx=\int { \frac {1}{{\left (c x^{4} + b x^{2} + a\right )}^{\frac {3}{2}} {\left (e x + d\right )}^{2}} \,d x } \] Input:
integrate(1/(e*x+d)^2/(c*x^4+b*x^2+a)^(3/2),x, algorithm="maxima")
Output:
integrate(1/((c*x^4 + b*x^2 + a)^(3/2)*(e*x + d)^2), x)
\[ \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}} \, dx=\int { \frac {1}{{\left (c x^{4} + b x^{2} + a\right )}^{\frac {3}{2}} {\left (e x + d\right )}^{2}} \,d x } \] Input:
integrate(1/(e*x+d)^2/(c*x^4+b*x^2+a)^(3/2),x, algorithm="giac")
Output:
sage0*x
Timed out. \[ \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}} \, dx=\int \frac {1}{{\left (d+e\,x\right )}^2\,{\left (c\,x^4+b\,x^2+a\right )}^{3/2}} \,d x \] Input:
int(1/((d + e*x)^2*(a + b*x^2 + c*x^4)^(3/2)),x)
Output:
int(1/((d + e*x)^2*(a + b*x^2 + c*x^4)^(3/2)), x)
\[ \int \frac {1}{(d+e x)^2 \left (a+b x^2+c x^4\right )^{3/2}} \, dx=\int \frac {1}{\left (e x +d \right )^{2} \left (c \,x^{4}+b \,x^{2}+a \right )^{\frac {3}{2}}}d x \] Input:
int(1/(e*x+d)^2/(c*x^4+b*x^2+a)^(3/2),x)
Output:
int(1/(e*x+d)^2/(c*x^4+b*x^2+a)^(3/2),x)