Integrand size = 29, antiderivative size = 154 \[ \int x^{-1+n} \left (d x^n\right )^p \left (a+b x^n+c x^{2 n}\right )^q \, dx=\frac {\left (d x^n\right )^{1+p} \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^{-q} \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^{-q} \left (a+b x^n+c x^{2 n}\right )^q \operatorname {AppellF1}\left (1+p,-q,-q,2+p,-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )}{d n (1+p)} \] Output:
(d*x^n)^(p+1)*(a+b*x^n+c*x^(2*n))^q*AppellF1(p+1,-q,-q,2+p,-2*c*x^n/(b-(-4 *a*c+b^2)^(1/2)),-2*c*x^n/(b+(-4*a*c+b^2)^(1/2)))/d/n/(p+1)/((1+2*c*x^n/(b -(-4*a*c+b^2)^(1/2)))^q)/((1+2*c*x^n/(b+(-4*a*c+b^2)^(1/2)))^q)
Time = 0.95 (sec) , antiderivative size = 179, normalized size of antiderivative = 1.16 \[ \int x^{-1+n} \left (d x^n\right )^p \left (a+b x^n+c x^{2 n}\right )^q \, dx=\frac {x^n \left (d x^n\right )^p \left (\frac {b-\sqrt {b^2-4 a c}+2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^{-q} \left (\frac {b+\sqrt {b^2-4 a c}+2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^{-q} \left (a+x^n \left (b+c x^n\right )\right )^q \operatorname {AppellF1}\left (1+p,-q,-q,2+p,-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}},\frac {2 c x^n}{-b+\sqrt {b^2-4 a c}}\right )}{n (1+p)} \] Input:
Integrate[x^(-1 + n)*(d*x^n)^p*(a + b*x^n + c*x^(2*n))^q,x]
Output:
(x^n*(d*x^n)^p*(a + x^n*(b + c*x^n))^q*AppellF1[1 + p, -q, -q, 2 + p, (-2* c*x^n)/(b + Sqrt[b^2 - 4*a*c]), (2*c*x^n)/(-b + Sqrt[b^2 - 4*a*c])])/(n*(1 + p)*((b - Sqrt[b^2 - 4*a*c] + 2*c*x^n)/(b - Sqrt[b^2 - 4*a*c]))^q*((b + Sqrt[b^2 - 4*a*c] + 2*c*x^n)/(b + Sqrt[b^2 - 4*a*c]))^q)
Time = 0.60 (sec) , antiderivative size = 161, normalized size of antiderivative = 1.05, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {31, 1721, 1012}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^{n-1} \left (d x^n\right )^p \left (a+b x^n+c x^{2 n}\right )^q \, dx\) |
\(\Big \downarrow \) 31 |
\(\displaystyle x^{-n p} \left (d x^n\right )^p \int x^{p n+n-1} \left (b x^n+c x^{2 n}+a\right )^qdx\) |
\(\Big \downarrow \) 1721 |
\(\displaystyle x^{-n p} \left (d x^n\right )^p \left (\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}+1\right )^{-q} \left (\frac {2 c x^n}{\sqrt {b^2-4 a c}+b}+1\right )^{-q} \left (a+b x^n+c x^{2 n}\right )^q \int x^{p n+n-1} \left (\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}+1\right )^q \left (\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}+1\right )^qdx\) |
\(\Big \downarrow \) 1012 |
\(\displaystyle \frac {x^{n (p+1)-n p} \left (d x^n\right )^p \left (\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}+1\right )^{-q} \left (\frac {2 c x^n}{\sqrt {b^2-4 a c}+b}+1\right )^{-q} \left (a+b x^n+c x^{2 n}\right )^q \operatorname {AppellF1}\left (p+1,-q,-q,p+2,-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )}{n (p+1)}\) |
Input:
Int[x^(-1 + n)*(d*x^n)^p*(a + b*x^n + c*x^(2*n))^q,x]
Output:
(x^(-(n*p) + n*(1 + p))*(d*x^n)^p*(a + b*x^n + c*x^(2*n))^q*AppellF1[1 + p , -q, -q, 2 + p, (-2*c*x^n)/(b - Sqrt[b^2 - 4*a*c]), (-2*c*x^n)/(b + Sqrt[ b^2 - 4*a*c])])/(n*(1 + p)*(1 + (2*c*x^n)/(b - Sqrt[b^2 - 4*a*c]))^q*(1 + (2*c*x^n)/(b + Sqrt[b^2 - 4*a*c]))^q)
Int[(u_.)*((a_.)*(x_))^(m_.)*((b_.)*(x_)^(i_.))^(p_), x_Symbol] :> Simp[(b* x^i)^p/(a*x)^(i*p) Int[u*(a*x)^(m + i*p), x], x] /; FreeQ[{a, b, i, m, p} , x] && !IntegerQ[p]
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ ))^(q_), x_Symbol] :> Simp[a^p*c^q*((e*x)^(m + 1)/(e*(m + 1)))*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, (-b)*(x^n/a), (-d)*(x^n/c)], x] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])
Int[((d_.)*(x_))^(m_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_), x _Symbol] :> Simp[a^IntPart[p]*((a + b*x^n + c*x^(2*n))^FracPart[p]/((1 + 2* c*(x^n/(b + Rt[b^2 - 4*a*c, 2])))^FracPart[p]*(1 + 2*c*(x^n/(b - Rt[b^2 - 4 *a*c, 2])))^FracPart[p])) Int[(d*x)^m*(1 + 2*c*(x^n/(b + Sqrt[b^2 - 4*a*c ])))^p*(1 + 2*c*(x^n/(b - Sqrt[b^2 - 4*a*c])))^p, x], x] /; FreeQ[{a, b, c, d, m, n, p}, x] && EqQ[n2, 2*n]
\[\int x^{-1+n} \left (d \,x^{n}\right )^{p} \left (a +b \,x^{n}+c \,x^{2 n}\right )^{q}d x\]
Input:
int(x^(-1+n)*(d*x^n)^p*(a+b*x^n+c*x^(2*n))^q,x)
Output:
int(x^(-1+n)*(d*x^n)^p*(a+b*x^n+c*x^(2*n))^q,x)
\[ \int x^{-1+n} \left (d x^n\right )^p \left (a+b x^n+c x^{2 n}\right )^q \, dx=\int { {\left (c x^{2 \, n} + b x^{n} + a\right )}^{q} \left (d x^{n}\right )^{p} x^{n - 1} \,d x } \] Input:
integrate(x^(-1+n)*(d*x^n)^p*(a+b*x^n+c*x^(2*n))^q,x, algorithm="fricas")
Output:
integral((c*x^(2*n) + b*x^n + a)^q*(d*x^n)^p*x^(n - 1), x)
Timed out. \[ \int x^{-1+n} \left (d x^n\right )^p \left (a+b x^n+c x^{2 n}\right )^q \, dx=\text {Timed out} \] Input:
integrate(x**(-1+n)*(d*x**n)**p*(a+b*x**n+c*x**(2*n))**q,x)
Output:
Timed out
\[ \int x^{-1+n} \left (d x^n\right )^p \left (a+b x^n+c x^{2 n}\right )^q \, dx=\int { {\left (c x^{2 \, n} + b x^{n} + a\right )}^{q} \left (d x^{n}\right )^{p} x^{n - 1} \,d x } \] Input:
integrate(x^(-1+n)*(d*x^n)^p*(a+b*x^n+c*x^(2*n))^q,x, algorithm="maxima")
Output:
integrate((c*x^(2*n) + b*x^n + a)^q*(d*x^n)^p*x^(n - 1), x)
\[ \int x^{-1+n} \left (d x^n\right )^p \left (a+b x^n+c x^{2 n}\right )^q \, dx=\int { {\left (c x^{2 \, n} + b x^{n} + a\right )}^{q} \left (d x^{n}\right )^{p} x^{n - 1} \,d x } \] Input:
integrate(x^(-1+n)*(d*x^n)^p*(a+b*x^n+c*x^(2*n))^q,x, algorithm="giac")
Output:
integrate((c*x^(2*n) + b*x^n + a)^q*(d*x^n)^p*x^(n - 1), x)
Timed out. \[ \int x^{-1+n} \left (d x^n\right )^p \left (a+b x^n+c x^{2 n}\right )^q \, dx=\int x^{n-1}\,{\left (d\,x^n\right )}^p\,{\left (a+b\,x^n+c\,x^{2\,n}\right )}^q \,d x \] Input:
int(x^(n - 1)*(d*x^n)^p*(a + b*x^n + c*x^(2*n))^q,x)
Output:
int(x^(n - 1)*(d*x^n)^p*(a + b*x^n + c*x^(2*n))^q, x)
\[ \int x^{-1+n} \left (d x^n\right )^p \left (a+b x^n+c x^{2 n}\right )^q \, dx=\text {too large to display} \] Input:
int(x^(-1+n)*(d*x^n)^p*(a+b*x^n+c*x^(2*n))^q,x)
Output:
(d**p*(x**(n*p + n)*(x**(2*n)*c + x**n*b + a)**q*b*p + x**(n*p + n)*(x**(2 *n)*c + x**n*b + a)**q*b*q + 2*x**(n*p)*(x**(2*n)*c + x**n*b + a)**q*a*q - 2*int((x**(n*p + 2*n)*(x**(2*n)*c + x**n*b + a)**q)/(x**(2*n)*c*p**2*x + 3*x**(2*n)*c*p*q*x + x**(2*n)*c*p*x + 2*x**(2*n)*c*q**2*x + x**(2*n)*c*q*x + x**n*b*p**2*x + 3*x**n*b*p*q*x + x**n*b*p*x + 2*x**n*b*q**2*x + x**n*b* q*x + a*p**2*x + 3*a*p*q*x + a*p*x + 2*a*q**2*x + a*q*x),x)*a*c*n*p**3*q - 10*int((x**(n*p + 2*n)*(x**(2*n)*c + x**n*b + a)**q)/(x**(2*n)*c*p**2*x + 3*x**(2*n)*c*p*q*x + x**(2*n)*c*p*x + 2*x**(2*n)*c*q**2*x + x**(2*n)*c*q* x + x**n*b*p**2*x + 3*x**n*b*p*q*x + x**n*b*p*x + 2*x**n*b*q**2*x + x**n*b *q*x + a*p**2*x + 3*a*p*q*x + a*p*x + 2*a*q**2*x + a*q*x),x)*a*c*n*p**2*q* *2 - 2*int((x**(n*p + 2*n)*(x**(2*n)*c + x**n*b + a)**q)/(x**(2*n)*c*p**2* x + 3*x**(2*n)*c*p*q*x + x**(2*n)*c*p*x + 2*x**(2*n)*c*q**2*x + x**(2*n)*c *q*x + x**n*b*p**2*x + 3*x**n*b*p*q*x + x**n*b*p*x + 2*x**n*b*q**2*x + x** n*b*q*x + a*p**2*x + 3*a*p*q*x + a*p*x + 2*a*q**2*x + a*q*x),x)*a*c*n*p**2 *q - 16*int((x**(n*p + 2*n)*(x**(2*n)*c + x**n*b + a)**q)/(x**(2*n)*c*p**2 *x + 3*x**(2*n)*c*p*q*x + x**(2*n)*c*p*x + 2*x**(2*n)*c*q**2*x + x**(2*n)* c*q*x + x**n*b*p**2*x + 3*x**n*b*p*q*x + x**n*b*p*x + 2*x**n*b*q**2*x + x* *n*b*q*x + a*p**2*x + 3*a*p*q*x + a*p*x + 2*a*q**2*x + a*q*x),x)*a*c*n*p*q **3 - 6*int((x**(n*p + 2*n)*(x**(2*n)*c + x**n*b + a)**q)/(x**(2*n)*c*p**2 *x + 3*x**(2*n)*c*p*q*x + x**(2*n)*c*p*x + 2*x**(2*n)*c*q**2*x + x**(2*...