\(\int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx\) [212]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [B] (verification not implemented)
Sympy [F]
Maxima [F]
Giac [F]
Mupad [B] (verification not implemented)
Reduce [F]

Optimal result

Integrand size = 21, antiderivative size = 49 \[ \int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx=-\frac {F^a \Gamma \left (-\frac {9}{2},-b (c+d x)^2 \log (F)\right ) \left (-b (c+d x)^2 \log (F)\right )^{9/2}}{2 d (c+d x)^9} \] Output:

-1/2*F^a*(-32/945*Pi^(1/2)*erfc((-b*(d*x+c)^2*ln(F))^(1/2))+32/945/(-b*(d* 
x+c)^2*ln(F))^(1/2)*exp(b*(d*x+c)^2*ln(F))-16/945/(-b*(d*x+c)^2*ln(F))^(3/ 
2)*exp(b*(d*x+c)^2*ln(F))+8/315/(-b*(d*x+c)^2*ln(F))^(5/2)*exp(b*(d*x+c)^2 
*ln(F))-4/63/(-b*(d*x+c)^2*ln(F))^(7/2)*exp(b*(d*x+c)^2*ln(F))+2/9/(-b*(d* 
x+c)^2*ln(F))^(9/2)*exp(b*(d*x+c)^2*ln(F)))*(-b*(d*x+c)^2*ln(F))^(9/2)/d/( 
d*x+c)^9
 

Mathematica [A] (verified)

Time = 0.47 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00 \[ \int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx=-\frac {F^a \Gamma \left (-\frac {9}{2},-b (c+d x)^2 \log (F)\right ) \left (-b (c+d x)^2 \log (F)\right )^{9/2}}{2 d (c+d x)^9} \] Input:

Integrate[F^(a + b*(c + d*x)^2)/(c + d*x)^10,x]
 

Output:

-1/2*(F^a*Gamma[-9/2, -(b*(c + d*x)^2*Log[F])]*(-(b*(c + d*x)^2*Log[F]))^( 
9/2))/(d*(c + d*x)^9)
 

Rubi [A] (verified)

Time = 0.34 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {2648}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx\)

\(\Big \downarrow \) 2648

\(\displaystyle -\frac {F^a \left (-b \log (F) (c+d x)^2\right )^{9/2} \Gamma \left (-\frac {9}{2},-b (c+d x)^2 \log (F)\right )}{2 d (c+d x)^9}\)

Input:

Int[F^(a + b*(c + d*x)^2)/(c + d*x)^10,x]
 

Output:

-1/2*(F^a*Gamma[-9/2, -(b*(c + d*x)^2*Log[F])]*(-(b*(c + d*x)^2*Log[F]))^( 
9/2))/(d*(c + d*x)^9)
 

Defintions of rubi rules used

rule 2648
Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((e_.) + (f_.)*(x_))^(m_ 
.), x_Symbol] :> Simp[(-F^a)*((e + f*x)^(m + 1)/(f*n*((-b)*(c + d*x)^n*Log[ 
F])^((m + 1)/n)))*Gamma[(m + 1)/n, (-b)*(c + d*x)^n*Log[F]], x] /; FreeQ[{F 
, a, b, c, d, e, f, m, n}, x] && EqQ[d*e - c*f, 0]
 
Maple [A] (verified)

Time = 0.81 (sec) , antiderivative size = 195, normalized size of antiderivative = 3.98

method result size
risch \(-\frac {F^{b \left (d x +c \right )^{2}} F^{a}}{9 d \left (d x +c \right )^{9}}-\frac {2 b \ln \left (F \right ) F^{b \left (d x +c \right )^{2}} F^{a}}{63 d \left (d x +c \right )^{7}}-\frac {4 b^{2} \ln \left (F \right )^{2} F^{b \left (d x +c \right )^{2}} F^{a}}{315 d \left (d x +c \right )^{5}}-\frac {8 b^{3} \ln \left (F \right )^{3} F^{b \left (d x +c \right )^{2}} F^{a}}{945 d \left (d x +c \right )^{3}}-\frac {16 b^{4} \ln \left (F \right )^{4} F^{b \left (d x +c \right )^{2}} F^{a}}{945 d \left (d x +c \right )}+\frac {16 b^{5} \ln \left (F \right )^{5} \sqrt {\pi }\, F^{a} \operatorname {erf}\left (\sqrt {-b \ln \left (F \right )}\, \left (d x +c \right )\right )}{945 d \sqrt {-b \ln \left (F \right )}}\) \(195\)

Input:

int(F^(a+b*(d*x+c)^2)/(d*x+c)^10,x,method=_RETURNVERBOSE)
 

Output:

-1/9/d/(d*x+c)^9*F^(b*(d*x+c)^2)*F^a-2/63/d*b*ln(F)/(d*x+c)^7*F^(b*(d*x+c) 
^2)*F^a-4/315/d*b^2*ln(F)^2/(d*x+c)^5*F^(b*(d*x+c)^2)*F^a-8/945/d*b^3*ln(F 
)^3/(d*x+c)^3*F^(b*(d*x+c)^2)*F^a-16/945/d*b^4*ln(F)^4/(d*x+c)*F^(b*(d*x+c 
)^2)*F^a+16/945/d*b^5*ln(F)^5*Pi^(1/2)*F^a/(-b*ln(F))^(1/2)*erf((-b*ln(F)) 
^(1/2)*(d*x+c))
 

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 598 vs. \(2 (185) = 370\).

Time = 0.09 (sec) , antiderivative size = 598, normalized size of antiderivative = 12.20 \[ \int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx=-\frac {16 \, \sqrt {\pi } {\left (b^{4} d^{9} x^{9} + 9 \, b^{4} c d^{8} x^{8} + 36 \, b^{4} c^{2} d^{7} x^{7} + 84 \, b^{4} c^{3} d^{6} x^{6} + 126 \, b^{4} c^{4} d^{5} x^{5} + 126 \, b^{4} c^{5} d^{4} x^{4} + 84 \, b^{4} c^{6} d^{3} x^{3} + 36 \, b^{4} c^{7} d^{2} x^{2} + 9 \, b^{4} c^{8} d x + b^{4} c^{9}\right )} \sqrt {-b d^{2} \log \left (F\right )} F^{a} \operatorname {erf}\left (\frac {\sqrt {-b d^{2} \log \left (F\right )} {\left (d x + c\right )}}{d}\right ) \log \left (F\right )^{4} + {\left (16 \, {\left (b^{4} d^{9} x^{8} + 8 \, b^{4} c d^{8} x^{7} + 28 \, b^{4} c^{2} d^{7} x^{6} + 56 \, b^{4} c^{3} d^{6} x^{5} + 70 \, b^{4} c^{4} d^{5} x^{4} + 56 \, b^{4} c^{5} d^{4} x^{3} + 28 \, b^{4} c^{6} d^{3} x^{2} + 8 \, b^{4} c^{7} d^{2} x + b^{4} c^{8} d\right )} \log \left (F\right )^{4} + 8 \, {\left (b^{3} d^{7} x^{6} + 6 \, b^{3} c d^{6} x^{5} + 15 \, b^{3} c^{2} d^{5} x^{4} + 20 \, b^{3} c^{3} d^{4} x^{3} + 15 \, b^{3} c^{4} d^{3} x^{2} + 6 \, b^{3} c^{5} d^{2} x + b^{3} c^{6} d\right )} \log \left (F\right )^{3} + 12 \, {\left (b^{2} d^{5} x^{4} + 4 \, b^{2} c d^{4} x^{3} + 6 \, b^{2} c^{2} d^{3} x^{2} + 4 \, b^{2} c^{3} d^{2} x + b^{2} c^{4} d\right )} \log \left (F\right )^{2} + 30 \, {\left (b d^{3} x^{2} + 2 \, b c d^{2} x + b c^{2} d\right )} \log \left (F\right ) + 105 \, d\right )} F^{b d^{2} x^{2} + 2 \, b c d x + b c^{2} + a}}{945 \, {\left (d^{11} x^{9} + 9 \, c d^{10} x^{8} + 36 \, c^{2} d^{9} x^{7} + 84 \, c^{3} d^{8} x^{6} + 126 \, c^{4} d^{7} x^{5} + 126 \, c^{5} d^{6} x^{4} + 84 \, c^{6} d^{5} x^{3} + 36 \, c^{7} d^{4} x^{2} + 9 \, c^{8} d^{3} x + c^{9} d^{2}\right )}} \] Input:

integrate(F^(a+b*(d*x+c)^2)/(d*x+c)^10,x, algorithm="fricas")
 

Output:

-1/945*(16*sqrt(pi)*(b^4*d^9*x^9 + 9*b^4*c*d^8*x^8 + 36*b^4*c^2*d^7*x^7 + 
84*b^4*c^3*d^6*x^6 + 126*b^4*c^4*d^5*x^5 + 126*b^4*c^5*d^4*x^4 + 84*b^4*c^ 
6*d^3*x^3 + 36*b^4*c^7*d^2*x^2 + 9*b^4*c^8*d*x + b^4*c^9)*sqrt(-b*d^2*log( 
F))*F^a*erf(sqrt(-b*d^2*log(F))*(d*x + c)/d)*log(F)^4 + (16*(b^4*d^9*x^8 + 
 8*b^4*c*d^8*x^7 + 28*b^4*c^2*d^7*x^6 + 56*b^4*c^3*d^6*x^5 + 70*b^4*c^4*d^ 
5*x^4 + 56*b^4*c^5*d^4*x^3 + 28*b^4*c^6*d^3*x^2 + 8*b^4*c^7*d^2*x + b^4*c^ 
8*d)*log(F)^4 + 8*(b^3*d^7*x^6 + 6*b^3*c*d^6*x^5 + 15*b^3*c^2*d^5*x^4 + 20 
*b^3*c^3*d^4*x^3 + 15*b^3*c^4*d^3*x^2 + 6*b^3*c^5*d^2*x + b^3*c^6*d)*log(F 
)^3 + 12*(b^2*d^5*x^4 + 4*b^2*c*d^4*x^3 + 6*b^2*c^2*d^3*x^2 + 4*b^2*c^3*d^ 
2*x + b^2*c^4*d)*log(F)^2 + 30*(b*d^3*x^2 + 2*b*c*d^2*x + b*c^2*d)*log(F) 
+ 105*d)*F^(b*d^2*x^2 + 2*b*c*d*x + b*c^2 + a))/(d^11*x^9 + 9*c*d^10*x^8 + 
 36*c^2*d^9*x^7 + 84*c^3*d^8*x^6 + 126*c^4*d^7*x^5 + 126*c^5*d^6*x^4 + 84* 
c^6*d^5*x^3 + 36*c^7*d^4*x^2 + 9*c^8*d^3*x + c^9*d^2)
 

Sympy [F]

\[ \int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx=\int \frac {F^{a + b \left (c + d x\right )^{2}}}{\left (c + d x\right )^{10}}\, dx \] Input:

integrate(F**(a+b*(d*x+c)**2)/(d*x+c)**10,x)
 

Output:

Integral(F**(a + b*(c + d*x)**2)/(c + d*x)**10, x)
                                                                                    
                                                                                    
 

Maxima [F]

\[ \int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx=\int { \frac {F^{{\left (d x + c\right )}^{2} b + a}}{{\left (d x + c\right )}^{10}} \,d x } \] Input:

integrate(F^(a+b*(d*x+c)^2)/(d*x+c)^10,x, algorithm="maxima")
 

Output:

integrate(F^((d*x + c)^2*b + a)/(d*x + c)^10, x)
 

Giac [F]

\[ \int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx=\int { \frac {F^{{\left (d x + c\right )}^{2} b + a}}{{\left (d x + c\right )}^{10}} \,d x } \] Input:

integrate(F^(a+b*(d*x+c)^2)/(d*x+c)^10,x, algorithm="giac")
 

Output:

integrate(F^((d*x + c)^2*b + a)/(d*x + c)^10, x)
 

Mupad [B] (verification not implemented)

Time = 0.42 (sec) , antiderivative size = 234, normalized size of antiderivative = 4.78 \[ \int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx=\frac {16\,F^a\,\sqrt {\pi }\,\mathrm {erfc}\left (\sqrt {-b\,\ln \left (F\right )\,{\left (c+d\,x\right )}^2}\right )\,{\left (-b\,\ln \left (F\right )\,{\left (c+d\,x\right )}^2\right )}^{9/2}}{945\,d\,{\left (c+d\,x\right )}^9}-\frac {16\,F^a\,\sqrt {\pi }\,{\left (-b\,\ln \left (F\right )\,{\left (c+d\,x\right )}^2\right )}^{9/2}}{945\,d\,{\left (c+d\,x\right )}^9}-\frac {4\,F^a\,F^{b\,{\left (c+d\,x\right )}^2}\,b^2\,{\ln \left (F\right )}^2}{315\,d\,{\left (c+d\,x\right )}^5}-\frac {8\,F^a\,F^{b\,{\left (c+d\,x\right )}^2}\,b^3\,{\ln \left (F\right )}^3}{945\,d\,{\left (c+d\,x\right )}^3}-\frac {16\,F^a\,F^{b\,{\left (c+d\,x\right )}^2}\,b^4\,{\ln \left (F\right )}^4}{945\,d\,\left (c+d\,x\right )}-\frac {2\,F^a\,F^{b\,{\left (c+d\,x\right )}^2}\,b\,\ln \left (F\right )}{63\,d\,{\left (c+d\,x\right )}^7}-\frac {F^a\,F^{b\,{\left (c+d\,x\right )}^2}}{9\,d\,{\left (c+d\,x\right )}^9} \] Input:

int(F^(a + b*(c + d*x)^2)/(c + d*x)^10,x)
 

Output:

(16*F^a*pi^(1/2)*erfc((-b*log(F)*(c + d*x)^2)^(1/2))*(-b*log(F)*(c + d*x)^ 
2)^(9/2))/(945*d*(c + d*x)^9) - (16*F^a*pi^(1/2)*(-b*log(F)*(c + d*x)^2)^( 
9/2))/(945*d*(c + d*x)^9) - (4*F^a*F^(b*(c + d*x)^2)*b^2*log(F)^2)/(315*d* 
(c + d*x)^5) - (8*F^a*F^(b*(c + d*x)^2)*b^3*log(F)^3)/(945*d*(c + d*x)^3) 
- (16*F^a*F^(b*(c + d*x)^2)*b^4*log(F)^4)/(945*d*(c + d*x)) - (2*F^a*F^(b* 
(c + d*x)^2)*b*log(F))/(63*d*(c + d*x)^7) - (F^a*F^(b*(c + d*x)^2))/(9*d*( 
c + d*x)^9)
 

Reduce [F]

\[ \int \frac {F^{a+b (c+d x)^2}}{(c+d x)^{10}} \, dx=\text {too large to display} \] Input:

int(F^(a+b*(d*x+c)^2)/(d*x+c)^10,x)
 

Output:

(f**(a + b*c**2)*( - f**(2*b*c*d*x + b*d**2*x**2) + 8*int(f**(2*b*c*d*x + 
b*d**2*x**2)/(2*log(f)*b*c**12 + 20*log(f)*b*c**11*d*x + 90*log(f)*b*c**10 
*d**2*x**2 + 240*log(f)*b*c**9*d**3*x**3 + 420*log(f)*b*c**8*d**4*x**4 + 5 
04*log(f)*b*c**7*d**5*x**5 + 420*log(f)*b*c**6*d**6*x**6 + 240*log(f)*b*c* 
*5*d**7*x**7 + 90*log(f)*b*c**4*d**8*x**8 + 20*log(f)*b*c**3*d**9*x**9 + 2 
*log(f)*b*c**2*d**10*x**10 - 9*c**10 - 90*c**9*d*x - 405*c**8*d**2*x**2 - 
1080*c**7*d**3*x**3 - 1890*c**6*d**4*x**4 - 2268*c**5*d**5*x**5 - 1890*c** 
4*d**6*x**6 - 1080*c**3*d**7*x**7 - 405*c**2*d**8*x**8 - 90*c*d**9*x**9 - 
9*d**10*x**10),x)*log(f)**2*b**2*c**13*d + 72*int(f**(2*b*c*d*x + b*d**2*x 
**2)/(2*log(f)*b*c**12 + 20*log(f)*b*c**11*d*x + 90*log(f)*b*c**10*d**2*x* 
*2 + 240*log(f)*b*c**9*d**3*x**3 + 420*log(f)*b*c**8*d**4*x**4 + 504*log(f 
)*b*c**7*d**5*x**5 + 420*log(f)*b*c**6*d**6*x**6 + 240*log(f)*b*c**5*d**7* 
x**7 + 90*log(f)*b*c**4*d**8*x**8 + 20*log(f)*b*c**3*d**9*x**9 + 2*log(f)* 
b*c**2*d**10*x**10 - 9*c**10 - 90*c**9*d*x - 405*c**8*d**2*x**2 - 1080*c** 
7*d**3*x**3 - 1890*c**6*d**4*x**4 - 2268*c**5*d**5*x**5 - 1890*c**4*d**6*x 
**6 - 1080*c**3*d**7*x**7 - 405*c**2*d**8*x**8 - 90*c*d**9*x**9 - 9*d**10* 
x**10),x)*log(f)**2*b**2*c**12*d**2*x + 288*int(f**(2*b*c*d*x + b*d**2*x** 
2)/(2*log(f)*b*c**12 + 20*log(f)*b*c**11*d*x + 90*log(f)*b*c**10*d**2*x**2 
 + 240*log(f)*b*c**9*d**3*x**3 + 420*log(f)*b*c**8*d**4*x**4 + 504*log(f)* 
b*c**7*d**5*x**5 + 420*log(f)*b*c**6*d**6*x**6 + 240*log(f)*b*c**5*d**7...