\(\int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx\) [102]

Optimal result

Integrand size = 16, antiderivative size = 233 \[ \int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx=\frac {2467 a^4 \sqrt [4]{1+i a x}}{192 \sqrt [4]{1-i a x}}-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}-\frac {17 i a \sqrt [4]{1+i a x}}{24 x^3 \sqrt [4]{1-i a x}}+\frac {113 a^2 \sqrt [4]{1+i a x}}{96 x^2 \sqrt [4]{1-i a x}}+\frac {521 i a^3 \sqrt [4]{1+i a x}}{192 x \sqrt [4]{1-i a x}}-\frac {475}{64} a^4 \arctan \left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )-\frac {475}{64} a^4 \text {arctanh}\left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right ) \] Output:

2467/192*a^4*(1+I*a*x)^(1/4)/(1-I*a*x)^(1/4)-1/4*(1+I*a*x)^(1/4)/x^4/(1-I* 
a*x)^(1/4)-17/24*I*a*(1+I*a*x)^(1/4)/x^3/(1-I*a*x)^(1/4)+113/96*a^2*(1+I*a 
*x)^(1/4)/x^2/(1-I*a*x)^(1/4)+521/192*I*a^3*(1+I*a*x)^(1/4)/x/(1-I*a*x)^(1 
/4)-475/64*a^4*arctan((1+I*a*x)^(1/4)/(1-I*a*x)^(1/4))-475/64*a^4*arctanh( 
(1+I*a*x)^(1/4)/(1-I*a*x)^(1/4))
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.05 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.51 \[ \int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx=\frac {-48-184 i a x+362 a^2 x^2+747 i a^3 x^3+1946 a^4 x^4+2467 i a^5 x^5+950 i a^4 x^4 (i+a x) \operatorname {Hypergeometric2F1}\left (\frac {3}{4},1,\frac {7}{4},\frac {i+a x}{i-a x}\right )}{192 x^4 \sqrt [4]{1-i a x} (1+i a x)^{3/4}} \] Input:

Integrate[E^(((5*I)/2)*ArcTan[a*x])/x^5,x]
 

Output:

(-48 - (184*I)*a*x + 362*a^2*x^2 + (747*I)*a^3*x^3 + 1946*a^4*x^4 + (2467* 
I)*a^5*x^5 + (950*I)*a^4*x^4*(I + a*x)*Hypergeometric2F1[3/4, 1, 7/4, (I + 
 a*x)/(I - a*x)])/(192*x^4*(1 - I*a*x)^(1/4)*(1 + I*a*x)^(3/4))
 

Rubi [A] (verified)

Time = 0.58 (sec) , antiderivative size = 240, normalized size of antiderivative = 1.03, number of steps used = 16, number of rules used = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.938, Rules used = {5585, 109, 27, 168, 27, 168, 27, 168, 27, 172, 27, 104, 756, 216, 219}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx\)

\(\Big \downarrow \) 5585

\(\displaystyle \int \frac {(1+i a x)^{5/4}}{x^5 (1-i a x)^{5/4}}dx\)

\(\Big \downarrow \) 109

\(\displaystyle -\frac {1}{4} \int -\frac {a (17 i-16 a x)}{2 x^4 (1-i a x)^{5/4} (i a x+1)^{3/4}}dx-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{8} a \int \frac {17 i-16 a x}{x^4 (1-i a x)^{5/4} (i a x+1)^{3/4}}dx-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 168

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{3} \int \frac {a (102 i a x+113)}{2 x^3 (1-i a x)^{5/4} (i a x+1)^{3/4}}dx-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \int \frac {102 i a x+113}{x^3 (1-i a x)^{5/4} (i a x+1)^{3/4}}dx-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 168

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (-\frac {1}{2} \int -\frac {a (521 i-452 a x)}{2 x^2 (1-i a x)^{5/4} (i a x+1)^{3/4}}dx-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (\frac {1}{4} a \int \frac {521 i-452 a x}{x^2 (1-i a x)^{5/4} (i a x+1)^{3/4}}dx-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 168

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (\frac {1}{4} a \left (-\int \frac {a (1042 i a x+1425)}{2 x (1-i a x)^{5/4} (i a x+1)^{3/4}}dx-\frac {521 i \sqrt [4]{1+i a x}}{x \sqrt [4]{1-i a x}}\right )-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (\frac {1}{4} a \left (-\frac {1}{2} a \int \frac {1042 i a x+1425}{x (1-i a x)^{5/4} (i a x+1)^{3/4}}dx-\frac {521 i \sqrt [4]{1+i a x}}{x \sqrt [4]{1-i a x}}\right )-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 172

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (\frac {1}{4} a \left (-\frac {1}{2} a \left (\frac {2 i \int -\frac {1425 i a}{2 x \sqrt [4]{1-i a x} (i a x+1)^{3/4}}dx}{a}+\frac {4934 \sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )-\frac {521 i \sqrt [4]{1+i a x}}{x \sqrt [4]{1-i a x}}\right )-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (\frac {1}{4} a \left (-\frac {1}{2} a \left (1425 \int \frac {1}{x \sqrt [4]{1-i a x} (i a x+1)^{3/4}}dx+\frac {4934 \sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )-\frac {521 i \sqrt [4]{1+i a x}}{x \sqrt [4]{1-i a x}}\right )-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 104

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (\frac {1}{4} a \left (-\frac {1}{2} a \left (5700 \int \frac {1}{\frac {i a x+1}{1-i a x}-1}d\frac {\sqrt [4]{i a x+1}}{\sqrt [4]{1-i a x}}+\frac {4934 \sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )-\frac {521 i \sqrt [4]{1+i a x}}{x \sqrt [4]{1-i a x}}\right )-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 756

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (\frac {1}{4} a \left (-\frac {1}{2} a \left (5700 \left (-\frac {1}{2} \int \frac {1}{1-\frac {\sqrt {i a x+1}}{\sqrt {1-i a x}}}d\frac {\sqrt [4]{i a x+1}}{\sqrt [4]{1-i a x}}-\frac {1}{2} \int \frac {1}{\frac {\sqrt {i a x+1}}{\sqrt {1-i a x}}+1}d\frac {\sqrt [4]{i a x+1}}{\sqrt [4]{1-i a x}}\right )+\frac {4934 \sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )-\frac {521 i \sqrt [4]{1+i a x}}{x \sqrt [4]{1-i a x}}\right )-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 216

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (\frac {1}{4} a \left (-\frac {1}{2} a \left (5700 \left (-\frac {1}{2} \int \frac {1}{1-\frac {\sqrt {i a x+1}}{\sqrt {1-i a x}}}d\frac {\sqrt [4]{i a x+1}}{\sqrt [4]{1-i a x}}-\frac {1}{2} \arctan \left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )\right )+\frac {4934 \sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )-\frac {521 i \sqrt [4]{1+i a x}}{x \sqrt [4]{1-i a x}}\right )-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

\(\Big \downarrow \) 219

\(\displaystyle \frac {1}{8} a \left (-\frac {1}{6} a \left (\frac {1}{4} a \left (-\frac {1}{2} a \left (5700 \left (-\frac {1}{2} \arctan \left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )-\frac {1}{2} \text {arctanh}\left (\frac {\sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )\right )+\frac {4934 \sqrt [4]{1+i a x}}{\sqrt [4]{1-i a x}}\right )-\frac {521 i \sqrt [4]{1+i a x}}{x \sqrt [4]{1-i a x}}\right )-\frac {113 \sqrt [4]{1+i a x}}{2 x^2 \sqrt [4]{1-i a x}}\right )-\frac {17 i \sqrt [4]{1+i a x}}{3 x^3 \sqrt [4]{1-i a x}}\right )-\frac {\sqrt [4]{1+i a x}}{4 x^4 \sqrt [4]{1-i a x}}\)

Input:

Int[E^(((5*I)/2)*ArcTan[a*x])/x^5,x]
 

Output:

-1/4*(1 + I*a*x)^(1/4)/(x^4*(1 - I*a*x)^(1/4)) + (a*((((-17*I)/3)*(1 + I*a 
*x)^(1/4))/(x^3*(1 - I*a*x)^(1/4)) - (a*((-113*(1 + I*a*x)^(1/4))/(2*x^2*( 
1 - I*a*x)^(1/4)) + (a*(((-521*I)*(1 + I*a*x)^(1/4))/(x*(1 - I*a*x)^(1/4)) 
 - (a*((4934*(1 + I*a*x)^(1/4))/(1 - I*a*x)^(1/4) + 5700*(-1/2*ArcTan[(1 + 
 I*a*x)^(1/4)/(1 - I*a*x)^(1/4)] - ArcTanh[(1 + I*a*x)^(1/4)/(1 - I*a*x)^( 
1/4)]/2)))/2))/4))/6))/8
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 104

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x 
_)), x_] :> With[{q = Denominator[m]}, Simp[q   Subst[Int[x^(q*(m + 1) - 1) 
/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^(1/q)], x] 
] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && L 
tQ[-1, m, 0] && SimplerQ[a + b*x, c + d*x]
 

rule 109

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Simp[(b*c - a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*((e + f 
*x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] + Simp[1/(b*(b*e - a*f)*(m + 1)) 
 Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) 
+ c*f*(p + 1)) + b*c*(d*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) 
 + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /; FreeQ[{a, b, c, 
d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || 
IntegersQ[m, n + p] || IntegersQ[p, m + n])
 

rule 168

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + 
 d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + S 
imp[1/((m + 1)*(b*c - a*d)*(b*e - a*f))   Int[(a + b*x)^(m + 1)*(c + d*x)^n 
*(e + f*x)^p*Simp[(a*d*f*g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a* 
h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p + 3)*x, x], x], 
 x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && ILtQ[m, -1]
 

rule 172

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_)*((g_.) + (h_.)*(x_)), x_] :> With[{mnp = Simplify[m + n + p]}, Simp[ 
(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1) 
*(b*c - a*d)*(b*e - a*f))), x] + Simp[1/((m + 1)*(b*c - a*d)*(b*e - a*f)) 
 Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*g - b*(d*e + c*f 
)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g 
 - a*h)*(mnp + 3)*x, x], x], x] /; ILtQ[mnp + 2, 0] && (SumSimplerQ[m, 1] | 
| ( !(NeQ[n, -1] && SumSimplerQ[n, 1]) &&  !(NeQ[p, -1] && SumSimplerQ[p, 1 
])))] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && NeQ[m, -1]
 

rule 216

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A 
rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a 
, 0] || GtQ[b, 0])
 

rule 219

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 756

Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2 
]], s = Denominator[Rt[-a/b, 2]]}, Simp[r/(2*a)   Int[1/(r - s*x^2), x], x] 
 + Simp[r/(2*a)   Int[1/(r + s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !GtQ[a 
/b, 0]
 

rule 5585

Int[E^(ArcTan[(a_.)*(x_)]*(n_.))*(x_)^(m_.), x_Symbol] :> Int[x^m*((1 - I*a 
*x)^(I*(n/2))/(1 + I*a*x)^(I*(n/2))), x] /; FreeQ[{a, m, n}, x] &&  !Intege 
rQ[(I*n - 1)/2]
 

Maple [F]

\[\int \frac {{\left (\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}\right )}^{\frac {5}{2}}}{x^{5}}d x\]

Input:

int(((1+I*a*x)/(a^2*x^2+1)^(1/2))^(5/2)/x^5,x)
 

Output:

int(((1+I*a*x)/(a^2*x^2+1)^(1/2))^(5/2)/x^5,x)
 

Fricas [A] (verification not implemented)

Time = 0.11 (sec) , antiderivative size = 192, normalized size of antiderivative = 0.82 \[ \int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx=-\frac {1425 \, a^{4} x^{4} \log \left (\sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}} + 1\right ) + 1425 i \, a^{4} x^{4} \log \left (\sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}} + i\right ) - 1425 i \, a^{4} x^{4} \log \left (\sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}} - i\right ) - 1425 \, a^{4} x^{4} \log \left (\sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}} - 1\right ) - 2 \, {\left (2467 \, a^{4} x^{4} + 521 i \, a^{3} x^{3} + 226 \, a^{2} x^{2} - 136 i \, a x - 48\right )} \sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}}}{384 \, x^{4}} \] Input:

integrate(((1+I*a*x)/(a^2*x^2+1)^(1/2))^(5/2)/x^5,x, algorithm="fricas")
 

Output:

-1/384*(1425*a^4*x^4*log(sqrt(I*sqrt(a^2*x^2 + 1)/(a*x + I)) + 1) + 1425*I 
*a^4*x^4*log(sqrt(I*sqrt(a^2*x^2 + 1)/(a*x + I)) + I) - 1425*I*a^4*x^4*log 
(sqrt(I*sqrt(a^2*x^2 + 1)/(a*x + I)) - I) - 1425*a^4*x^4*log(sqrt(I*sqrt(a 
^2*x^2 + 1)/(a*x + I)) - 1) - 2*(2467*a^4*x^4 + 521*I*a^3*x^3 + 226*a^2*x^ 
2 - 136*I*a*x - 48)*sqrt(I*sqrt(a^2*x^2 + 1)/(a*x + I)))/x^4
 

Sympy [F(-1)]

Timed out. \[ \int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx=\text {Timed out} \] Input:

integrate(((1+I*a*x)/(a**2*x**2+1)**(1/2))**(5/2)/x**5,x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx=\int { \frac {\left (\frac {i \, a x + 1}{\sqrt {a^{2} x^{2} + 1}}\right )^{\frac {5}{2}}}{x^{5}} \,d x } \] Input:

integrate(((1+I*a*x)/(a^2*x^2+1)^(1/2))^(5/2)/x^5,x, algorithm="maxima")
 

Output:

integrate(((I*a*x + 1)/sqrt(a^2*x^2 + 1))^(5/2)/x^5, x)
 

Giac [F(-2)]

Exception generated. \[ \int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx=\text {Exception raised: TypeError} \] Input:

integrate(((1+I*a*x)/(a^2*x^2+1)^(1/2))^(5/2)/x^5,x, algorithm="giac")
 

Output:

Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:Warning, need to choose a branch fo 
r the root of a polynomial with parameters. This might be wrong.The choice 
 was done
 

Mupad [F(-1)]

Timed out. \[ \int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx=\int \frac {{\left (\frac {1+a\,x\,1{}\mathrm {i}}{\sqrt {a^2\,x^2+1}}\right )}^{5/2}}{x^5} \,d x \] Input:

int(((a*x*1i + 1)/(a^2*x^2 + 1)^(1/2))^(5/2)/x^5,x)
 

Output:

int(((a*x*1i + 1)/(a^2*x^2 + 1)^(1/2))^(5/2)/x^5, x)
 

Reduce [F]

\[ \int \frac {e^{\frac {5}{2} i \arctan (a x)}}{x^5} \, dx=\frac {-1808 \sqrt {a i x +1}\, \left (a^{2} x^{2}+1\right )^{\frac {3}{4}} a^{4} x^{4}-904 \sqrt {a i x +1}\, \left (a^{2} x^{2}+1\right )^{\frac {3}{4}} a^{3} i \,x^{3}+226 \sqrt {a i x +1}\, \left (a^{2} x^{2}+1\right )^{\frac {3}{4}} a^{2} x^{2}-136 \sqrt {a i x +1}\, \left (a^{2} x^{2}+1\right )^{\frac {3}{4}} a i x -48 \sqrt {a i x +1}\, \left (a^{2} x^{2}+1\right )^{\frac {3}{4}}-1425 \left (\int \frac {\sqrt {a i x +1}\, \left (a^{2} x^{2}+1\right )^{\frac {3}{4}}}{a^{4} x^{6}+2 a^{2} x^{4}+x^{2}}d x \right ) a^{5} i \,x^{6}-1425 \left (\int \frac {\sqrt {a i x +1}\, \left (a^{2} x^{2}+1\right )^{\frac {3}{4}}}{a^{4} x^{6}+2 a^{2} x^{4}+x^{2}}d x \right ) a^{3} i \,x^{4}}{192 x^{4} \left (a^{2} x^{2}+1\right )} \] Input:

int(((1+I*a*x)/(a^2*x^2+1)^(1/2))^(5/2)/x^5,x)
 

Output:

( - 1808*sqrt(a*i*x + 1)*(a**2*x**2 + 1)**(3/4)*a**4*x**4 - 904*sqrt(a*i*x 
 + 1)*(a**2*x**2 + 1)**(3/4)*a**3*i*x**3 + 226*sqrt(a*i*x + 1)*(a**2*x**2 
+ 1)**(3/4)*a**2*x**2 - 136*sqrt(a*i*x + 1)*(a**2*x**2 + 1)**(3/4)*a*i*x - 
 48*sqrt(a*i*x + 1)*(a**2*x**2 + 1)**(3/4) - 1425*int((sqrt(a*i*x + 1)*(a* 
*2*x**2 + 1)**(3/4))/(a**4*x**6 + 2*a**2*x**4 + x**2),x)*a**5*i*x**6 - 142 
5*int((sqrt(a*i*x + 1)*(a**2*x**2 + 1)**(3/4))/(a**4*x**6 + 2*a**2*x**4 + 
x**2),x)*a**3*i*x**4)/(192*x**4*(a**2*x**2 + 1))