Integrand size = 24, antiderivative size = 53 \[ \int e^{-2 i p \arctan (a x)} \left (c+a^2 c x^2\right )^p \, dx=\frac {i (1-i a x)^{1+2 p} \left (1+a^2 x^2\right )^{-p} \left (c+a^2 c x^2\right )^p}{a (1+2 p)} \] Output:
I*(1-I*a*x)^(1+2*p)*(a^2*c*x^2+c)^p/a/(1+2*p)/((a^2*x^2+1)^p)
Time = 0.04 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.74 \[ \int e^{-2 i p \arctan (a x)} \left (c+a^2 c x^2\right )^p \, dx=\frac {e^{-2 i p \arctan (a x)} (i+a x) \left (c+a^2 c x^2\right )^p}{a+2 a p} \] Input:
Integrate[(c + a^2*c*x^2)^p/E^((2*I)*p*ArcTan[a*x]),x]
Output:
((I + a*x)*(c + a^2*c*x^2)^p)/(E^((2*I)*p*ArcTan[a*x])*(a + 2*a*p))
Time = 0.51 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {5599, 5596, 17}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int e^{-2 i p \arctan (a x)} \left (a^2 c x^2+c\right )^p \, dx\) |
\(\Big \downarrow \) 5599 |
\(\displaystyle \left (a^2 x^2+1\right )^{-p} \left (a^2 c x^2+c\right )^p \int e^{-2 i p \arctan (a x)} \left (a^2 x^2+1\right )^pdx\) |
\(\Big \downarrow \) 5596 |
\(\displaystyle \left (a^2 x^2+1\right )^{-p} \left (a^2 c x^2+c\right )^p \int (1-i a x)^{2 p}dx\) |
\(\Big \downarrow \) 17 |
\(\displaystyle \frac {i (1-i a x)^{2 p+1} \left (a^2 x^2+1\right )^{-p} \left (a^2 c x^2+c\right )^p}{a (2 p+1)}\) |
Input:
Int[(c + a^2*c*x^2)^p/E^((2*I)*p*ArcTan[a*x]),x]
Output:
(I*(1 - I*a*x)^(1 + 2*p)*(c + a^2*c*x^2)^p)/(a*(1 + 2*p)*(1 + a^2*x^2)^p)
Int[(c_.)*((a_.) + (b_.)*(x_))^(m_.), x_Symbol] :> Simp[c*((a + b*x)^(m + 1 )/(b*(m + 1))), x] /; FreeQ[{a, b, c, m}, x] && NeQ[m, -1]
Int[E^(ArcTan[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[c^p Int[(1 - I*a*x)^(p + I*(n/2))*(1 + I*a*x)^(p - I*(n/2)), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[d, a^2*c] && (IntegerQ[p] || GtQ[c, 0])
Int[E^(ArcTan[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_)^2)^(p_), x_Symbol] :> S imp[c^IntPart[p]*((c + d*x^2)^FracPart[p]/(1 + a^2*x^2)^FracPart[p]) Int[ (1 + a^2*x^2)^p*E^(n*ArcTan[a*x]), x], x] /; FreeQ[{a, c, d, n, p}, x] && E qQ[d, a^2*c] && !(IntegerQ[p] || GtQ[c, 0])
Time = 0.64 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.77
method | result | size |
gosper | \(\frac {\left (a x +i\right ) \left (a^{2} c \,x^{2}+c \right )^{p} {\mathrm e}^{-2 i p \arctan \left (a x \right )}}{a \left (2 p +1\right )}\) | \(41\) |
orering | \(\frac {\left (a x +i\right ) \left (a^{2} c \,x^{2}+c \right )^{p} {\mathrm e}^{-2 i p \arctan \left (a x \right )}}{a \left (2 p +1\right )}\) | \(41\) |
parallelrisch | \(\frac {\left (x \left (a^{2} c \,x^{2}+c \right )^{p} a +i \left (a^{2} c \,x^{2}+c \right )^{p}\right ) {\mathrm e}^{-2 i p \arctan \left (a x \right )}}{a \left (2 p +1\right )}\) | \(54\) |
risch | \(\frac {\left (\left (a x +i\right )^{p}\right )^{2} c^{p} \left (a x +i\right ) {\mathrm e}^{-\frac {i p \pi \left (\operatorname {csgn}\left (i \left (a x -i\right ) \left (a x +i\right )\right )^{3}-\operatorname {csgn}\left (i \left (a x -i\right ) \left (a x +i\right )\right )^{2} \operatorname {csgn}\left (i \left (a x +i\right )\right )-\operatorname {csgn}\left (i \left (a x -i\right ) \left (a x +i\right )\right )^{2} \operatorname {csgn}\left (i \left (a x -i\right )\right )-\operatorname {csgn}\left (i \left (a x -i\right ) \left (a x +i\right )\right ) \operatorname {csgn}\left (i c \left (a x +i\right ) \left (a x -i\right )\right )^{2}+\operatorname {csgn}\left (i \left (a x -i\right ) \left (a x +i\right )\right ) \operatorname {csgn}\left (i c \left (a x +i\right ) \left (a x -i\right )\right ) \operatorname {csgn}\left (i c \right )+\operatorname {csgn}\left (i \left (a x -i\right ) \left (a x +i\right )\right ) \operatorname {csgn}\left (i \left (a x +i\right )\right ) \operatorname {csgn}\left (i \left (a x -i\right )\right )+\operatorname {csgn}\left (i c \left (a x +i\right ) \left (a x -i\right )\right )^{3}-\operatorname {csgn}\left (i c \left (a x +i\right ) \left (a x -i\right )\right )^{2} \operatorname {csgn}\left (i c \right )+\operatorname {csgn}\left (a x +i\right )^{3}-\operatorname {csgn}\left (a x +i\right )^{2} \operatorname {csgn}\left (i \left (a x +i\right )\right )+\operatorname {csgn}\left (a x -i\right )^{3}+\operatorname {csgn}\left (a x -i\right )^{2} \operatorname {csgn}\left (i \left (a x -i\right )\right )-\operatorname {csgn}\left (a x +i\right )^{2}+\operatorname {csgn}\left (a x +i\right ) \operatorname {csgn}\left (i \left (a x +i\right )\right )-\operatorname {csgn}\left (a x -i\right )^{2}-\operatorname {csgn}\left (a x -i\right ) \operatorname {csgn}\left (i \left (a x -i\right )\right )+2\right )}{2}}}{\left (2 p +1\right ) a}\) | \(403\) |
Input:
int((a^2*c*x^2+c)^p/exp(2*I*p*arctan(a*x)),x,method=_RETURNVERBOSE)
Output:
(I+a*x)/a/(2*p+1)*(a^2*c*x^2+c)^p/exp(2*I*p*arctan(a*x))
Time = 0.08 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.79 \[ \int e^{-2 i p \arctan (a x)} \left (c+a^2 c x^2\right )^p \, dx=\frac {{\left (a x + i\right )} {\left (a^{2} c x^{2} + c\right )}^{p} \left (-\frac {a x + i}{a x - i}\right )^{p}}{2 \, a p + a} \] Input:
integrate((a^2*c*x^2+c)^p/exp(2*I*p*arctan(a*x)),x, algorithm="fricas")
Output:
(a*x + I)*(a^2*c*x^2 + c)^p*(-(a*x + I)/(a*x - I))^p/(2*a*p + a)
\[ \int e^{-2 i p \arctan (a x)} \left (c+a^2 c x^2\right )^p \, dx=\begin {cases} \frac {x}{\sqrt {c}} & \text {for}\: a = 0 \wedge p = - \frac {1}{2} \\c^{p} x & \text {for}\: a = 0 \\\int \frac {e^{i \operatorname {atan}{\left (a x \right )}}}{\sqrt {c \left (a^{2} x^{2} + 1\right )}}\, dx & \text {for}\: p = - \frac {1}{2} \\\frac {a x \left (a^{2} c x^{2} + c\right )^{p}}{2 a p e^{2 i p \operatorname {atan}{\left (a x \right )}} + a e^{2 i p \operatorname {atan}{\left (a x \right )}}} + \frac {i \left (a^{2} c x^{2} + c\right )^{p}}{2 a p e^{2 i p \operatorname {atan}{\left (a x \right )}} + a e^{2 i p \operatorname {atan}{\left (a x \right )}}} & \text {otherwise} \end {cases} \] Input:
integrate((a**2*c*x**2+c)**p/exp(2*I*p*atan(a*x)),x)
Output:
Piecewise((x/sqrt(c), Eq(a, 0) & Eq(p, -1/2)), (c**p*x, Eq(a, 0)), (Integr al(exp(I*atan(a*x))/sqrt(c*(a**2*x**2 + 1)), x), Eq(p, -1/2)), (a*x*(a**2* c*x**2 + c)**p/(2*a*p*exp(2*I*p*atan(a*x)) + a*exp(2*I*p*atan(a*x))) + I*( a**2*c*x**2 + c)**p/(2*a*p*exp(2*I*p*atan(a*x)) + a*exp(2*I*p*atan(a*x))), True))
Time = 0.05 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.43 \[ \int e^{-2 i p \arctan (a x)} \left (c+a^2 c x^2\right )^p \, dx=\frac {{\left (a c^{p} x + i \, c^{p}\right )} {\left (a^{2} x^{2} + 1\right )}^{p} \cos \left (2 \, p \arctan \left (a x\right )\right ) - {\left (i \, a c^{p} x - c^{p}\right )} {\left (a^{2} x^{2} + 1\right )}^{p} \sin \left (2 \, p \arctan \left (a x\right )\right )}{2 \, a p + a} \] Input:
integrate((a^2*c*x^2+c)^p/exp(2*I*p*arctan(a*x)),x, algorithm="maxima")
Output:
((a*c^p*x + I*c^p)*(a^2*x^2 + 1)^p*cos(2*p*arctan(a*x)) - (I*a*c^p*x - c^p )*(a^2*x^2 + 1)^p*sin(2*p*arctan(a*x)))/(2*a*p + a)
Time = 0.26 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.00 \[ \int e^{-2 i p \arctan (a x)} \left (c+a^2 c x^2\right )^p \, dx=\frac {a x e^{\left (-i \, \pi p + 2 \, p \log \left (a x + i\right ) + p \log \left (c\right )\right )} + i \, e^{\left (-i \, \pi p + 2 \, p \log \left (a x + i\right ) + p \log \left (c\right )\right )}}{2 \, a p + a} \] Input:
integrate((a^2*c*x^2+c)^p/exp(2*I*p*arctan(a*x)),x, algorithm="giac")
Output:
(a*x*e^(-I*pi*p + 2*p*log(a*x + I) + p*log(c)) + I*e^(-I*pi*p + 2*p*log(a* x + I) + p*log(c)))/(2*a*p + a)
Time = 0.21 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.02 \[ \int e^{-2 i p \arctan (a x)} \left (c+a^2 c x^2\right )^p \, dx=\left (\frac {x\,{\mathrm {e}}^{-p\,\mathrm {atan}\left (a\,x\right )\,2{}\mathrm {i}}}{2\,p+1}+\frac {{\mathrm {e}}^{-p\,\mathrm {atan}\left (a\,x\right )\,2{}\mathrm {i}}\,1{}\mathrm {i}}{a\,\left (2\,p+1\right )}\right )\,{\left (c\,a^2\,x^2+c\right )}^p \] Input:
int(exp(-p*atan(a*x)*2i)*(c + a^2*c*x^2)^p,x)
Output:
((x*exp(-p*atan(a*x)*2i))/(2*p + 1) + (exp(-p*atan(a*x)*2i)*1i)/(a*(2*p + 1)))*(c + a^2*c*x^2)^p
Time = 0.15 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.75 \[ \int e^{-2 i p \arctan (a x)} \left (c+a^2 c x^2\right )^p \, dx=\frac {\left (a^{2} c \,x^{2}+c \right )^{p} \left (a x +i \right )}{e^{2 \mathit {atan} \left (a x \right ) i p} a \left (2 p +1\right )} \] Input:
int((a^2*c*x^2+c)^p/exp(2*I*p*atan(a*x)),x)
Output:
((a**2*c*x**2 + c)**p*(a*x + i))/(e**(2*atan(a*x)*i*p)*a*(2*p + 1))