Integrand size = 14, antiderivative size = 359 \[ \int e^{\text {arcsinh}(a+b x)^2} x^3 \, dx=-\frac {\sqrt {\pi } \text {erfi}(1-\text {arcsinh}(a+b x))}{16 b^4 e}+\frac {3 a^2 \sqrt {\pi } \text {erfi}(1-\text {arcsinh}(a+b x))}{8 b^4 e}+\frac {\sqrt {\pi } \text {erfi}(2-\text {arcsinh}(a+b x))}{32 b^4 e^4}-\frac {\sqrt {\pi } \text {erfi}(1+\text {arcsinh}(a+b x))}{16 b^4 e}+\frac {3 a^2 \sqrt {\pi } \text {erfi}(1+\text {arcsinh}(a+b x))}{8 b^4 e}+\frac {\sqrt {\pi } \text {erfi}(2+\text {arcsinh}(a+b x))}{32 b^4 e^4}-\frac {3 a \sqrt {\pi } \text {erfi}\left (\frac {1}{2} (-3+2 \text {arcsinh}(a+b x))\right )}{16 b^4 e^{9/4}}+\frac {3 a \sqrt {\pi } \text {erfi}\left (\frac {1}{2} (-1+2 \text {arcsinh}(a+b x))\right )}{16 b^4 \sqrt [4]{e}}-\frac {a^3 \sqrt {\pi } \text {erfi}\left (\frac {1}{2} (-1+2 \text {arcsinh}(a+b x))\right )}{4 b^4 \sqrt [4]{e}}+\frac {3 a \sqrt {\pi } \text {erfi}\left (\frac {1}{2} (1+2 \text {arcsinh}(a+b x))\right )}{16 b^4 \sqrt [4]{e}}-\frac {a^3 \sqrt {\pi } \text {erfi}\left (\frac {1}{2} (1+2 \text {arcsinh}(a+b x))\right )}{4 b^4 \sqrt [4]{e}}-\frac {3 a \sqrt {\pi } \text {erfi}\left (\frac {1}{2} (3+2 \text {arcsinh}(a+b x))\right )}{16 b^4 e^{9/4}} \] Output:
1/16*Pi^(1/2)*erfi(-1+arcsinh(b*x+a))/b^4*exp(-1)-3/8*a^2*Pi^(1/2)*erfi(-1 +arcsinh(b*x+a))/b^4*exp(-1)-1/32*Pi^(1/2)*erfi(-2+arcsinh(b*x+a))/b^4*exp (-4)-1/16*Pi^(1/2)*erfi(1+arcsinh(b*x+a))/b^4*exp(-1)+3/8*a^2*Pi^(1/2)*erf i(1+arcsinh(b*x+a))/b^4*exp(-1)+1/32*Pi^(1/2)*erfi(2+arcsinh(b*x+a))/b^4*e xp(-4)-3/16*a*Pi^(1/2)*erfi(-3/2+arcsinh(b*x+a))/b^4*exp(-9/4)+3/16*a*Pi^( 1/2)*erfi(-1/2+arcsinh(b*x+a))/b^4*exp(-1/4)-1/4*a^3*Pi^(1/2)*erfi(-1/2+ar csinh(b*x+a))/b^4*exp(-1/4)+3/16*a*Pi^(1/2)*erfi(1/2+arcsinh(b*x+a))/b^4*e xp(-1/4)-1/4*a^3*Pi^(1/2)*erfi(1/2+arcsinh(b*x+a))/b^4*exp(-1/4)-3/16*a*Pi ^(1/2)*erfi(3/2+arcsinh(b*x+a))/b^4*exp(-9/4)
Time = 0.42 (sec) , antiderivative size = 198, normalized size of antiderivative = 0.55 \[ \int e^{\text {arcsinh}(a+b x)^2} x^3 \, dx=\frac {\sqrt {\pi } \left (2 a \left (-3+4 a^2\right ) e^{15/4} \text {erfi}\left (\frac {1}{2}-\text {arcsinh}(a+b x)\right )+2 \left (-1+6 a^2\right ) e^3 \text {erfi}(1-\text {arcsinh}(a+b x))+6 a e^{7/4} \text {erfi}\left (\frac {3}{2}-\text {arcsinh}(a+b x)\right )+\text {erfi}(2-\text {arcsinh}(a+b x))+6 a e^{15/4} \text {erfi}\left (\frac {1}{2}+\text {arcsinh}(a+b x)\right )-8 a^3 e^{15/4} \text {erfi}\left (\frac {1}{2}+\text {arcsinh}(a+b x)\right )-2 e^3 \text {erfi}(1+\text {arcsinh}(a+b x))+12 a^2 e^3 \text {erfi}(1+\text {arcsinh}(a+b x))-6 a e^{7/4} \text {erfi}\left (\frac {3}{2}+\text {arcsinh}(a+b x)\right )+\text {erfi}(2+\text {arcsinh}(a+b x))\right )}{32 b^4 e^4} \] Input:
Integrate[E^ArcSinh[a + b*x]^2*x^3,x]
Output:
(Sqrt[Pi]*(2*a*(-3 + 4*a^2)*E^(15/4)*Erfi[1/2 - ArcSinh[a + b*x]] + 2*(-1 + 6*a^2)*E^3*Erfi[1 - ArcSinh[a + b*x]] + 6*a*E^(7/4)*Erfi[3/2 - ArcSinh[a + b*x]] + Erfi[2 - ArcSinh[a + b*x]] + 6*a*E^(15/4)*Erfi[1/2 + ArcSinh[a + b*x]] - 8*a^3*E^(15/4)*Erfi[1/2 + ArcSinh[a + b*x]] - 2*E^3*Erfi[1 + Arc Sinh[a + b*x]] + 12*a^2*E^3*Erfi[1 + ArcSinh[a + b*x]] - 6*a*E^(7/4)*Erfi[ 3/2 + ArcSinh[a + b*x]] + Erfi[2 + ArcSinh[a + b*x]]))/(32*b^4*E^4)
Time = 1.59 (sec) , antiderivative size = 328, normalized size of antiderivative = 0.91, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {6288, 25, 7292, 27, 7293, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^3 e^{\text {arcsinh}(a+b x)^2} \, dx\) |
\(\Big \downarrow \) 6288 |
\(\displaystyle \frac {\int -e^{\text {arcsinh}(a+b x)^2} \left (\frac {a}{b}-\frac {a+b x}{b}\right )^3 \sqrt {(a+b x)^2+1}d\text {arcsinh}(a+b x)}{b}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\frac {\int e^{\text {arcsinh}(a+b x)^2} \left (\frac {a}{b}-\frac {a+b x}{b}\right )^3 \sqrt {(a+b x)^2+1}d\text {arcsinh}(a+b x)}{b}\) |
\(\Big \downarrow \) 7292 |
\(\displaystyle -\frac {\int -e^{\text {arcsinh}(a+b x)^2} x^3 \sqrt {(a+b x)^2+1}d\text {arcsinh}(a+b x)}{b}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {\int -b^3 e^{\text {arcsinh}(a+b x)^2} x^3 \sqrt {(a+b x)^2+1}d\text {arcsinh}(a+b x)}{b^4}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (e^{\text {arcsinh}(a+b x)^2} \sqrt {(a+b x)^2+1} a^3-3 e^{\text {arcsinh}(a+b x)^2} (a+b x) \sqrt {(a+b x)^2+1} a^2+3 e^{\text {arcsinh}(a+b x)^2} (a+b x)^2 \sqrt {(a+b x)^2+1} a-e^{\text {arcsinh}(a+b x)^2} (a+b x)^3 \sqrt {(a+b x)^2+1}\right )d\text {arcsinh}(a+b x)}{b^4}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -\frac {\frac {\sqrt {\pi } a^3 \text {erfi}\left (\frac {1}{2} (2 \text {arcsinh}(a+b x)-1)\right )}{4 \sqrt [4]{e}}+\frac {\sqrt {\pi } a^3 \text {erfi}\left (\frac {1}{2} (2 \text {arcsinh}(a+b x)+1)\right )}{4 \sqrt [4]{e}}-\frac {3 \sqrt {\pi } a^2 \text {erfi}(1-\text {arcsinh}(a+b x))}{8 e}-\frac {3 \sqrt {\pi } a^2 \text {erfi}(\text {arcsinh}(a+b x)+1)}{8 e}+\frac {3 \sqrt {\pi } a \text {erfi}\left (\frac {1}{2} (2 \text {arcsinh}(a+b x)-3)\right )}{16 e^{9/4}}-\frac {3 \sqrt {\pi } a \text {erfi}\left (\frac {1}{2} (2 \text {arcsinh}(a+b x)-1)\right )}{16 \sqrt [4]{e}}-\frac {3 \sqrt {\pi } a \text {erfi}\left (\frac {1}{2} (2 \text {arcsinh}(a+b x)+1)\right )}{16 \sqrt [4]{e}}+\frac {3 \sqrt {\pi } a \text {erfi}\left (\frac {1}{2} (2 \text {arcsinh}(a+b x)+3)\right )}{16 e^{9/4}}+\frac {\sqrt {\pi } \text {erfi}(1-\text {arcsinh}(a+b x))}{16 e}-\frac {\sqrt {\pi } \text {erfi}(2-\text {arcsinh}(a+b x))}{32 e^4}+\frac {\sqrt {\pi } \text {erfi}(\text {arcsinh}(a+b x)+1)}{16 e}-\frac {\sqrt {\pi } \text {erfi}(\text {arcsinh}(a+b x)+2)}{32 e^4}}{b^4}\) |
Input:
Int[E^ArcSinh[a + b*x]^2*x^3,x]
Output:
-(((Sqrt[Pi]*Erfi[1 - ArcSinh[a + b*x]])/(16*E) - (3*a^2*Sqrt[Pi]*Erfi[1 - ArcSinh[a + b*x]])/(8*E) - (Sqrt[Pi]*Erfi[2 - ArcSinh[a + b*x]])/(32*E^4) + (Sqrt[Pi]*Erfi[1 + ArcSinh[a + b*x]])/(16*E) - (3*a^2*Sqrt[Pi]*Erfi[1 + ArcSinh[a + b*x]])/(8*E) - (Sqrt[Pi]*Erfi[2 + ArcSinh[a + b*x]])/(32*E^4) + (3*a*Sqrt[Pi]*Erfi[(-3 + 2*ArcSinh[a + b*x])/2])/(16*E^(9/4)) - (3*a*Sq rt[Pi]*Erfi[(-1 + 2*ArcSinh[a + b*x])/2])/(16*E^(1/4)) + (a^3*Sqrt[Pi]*Erf i[(-1 + 2*ArcSinh[a + b*x])/2])/(4*E^(1/4)) - (3*a*Sqrt[Pi]*Erfi[(1 + 2*Ar cSinh[a + b*x])/2])/(16*E^(1/4)) + (a^3*Sqrt[Pi]*Erfi[(1 + 2*ArcSinh[a + b *x])/2])/(4*E^(1/4)) + (3*a*Sqrt[Pi]*Erfi[(3 + 2*ArcSinh[a + b*x])/2])/(16 *E^(9/4)))/b^4)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[(f_)^(ArcSinh[(a_.) + (b_.)*(x_)]^(n_.)*(c_.))*(x_)^(m_.), x_Symbol] :> Simp[1/b Subst[Int[(-a/b + Sinh[x]/b)^m*f^(c*x^n)*Cosh[x], x], x, ArcSin h[a + b*x]], x] /; FreeQ[{a, b, c, f}, x] && IGtQ[m, 0] && IGtQ[n, 0]
\[\int {\mathrm e}^{\operatorname {arcsinh}\left (b x +a \right )^{2}} x^{3}d x\]
Input:
int(exp(arcsinh(b*x+a)^2)*x^3,x)
Output:
int(exp(arcsinh(b*x+a)^2)*x^3,x)
\[ \int e^{\text {arcsinh}(a+b x)^2} x^3 \, dx=\int { x^{3} e^{\left (\operatorname {arsinh}\left (b x + a\right )^{2}\right )} \,d x } \] Input:
integrate(exp(arcsinh(b*x+a)^2)*x^3,x, algorithm="fricas")
Output:
integral(x^3*e^(arcsinh(b*x + a)^2), x)
\[ \int e^{\text {arcsinh}(a+b x)^2} x^3 \, dx=\int x^{3} e^{\operatorname {asinh}^{2}{\left (a + b x \right )}}\, dx \] Input:
integrate(exp(asinh(b*x+a)**2)*x**3,x)
Output:
Integral(x**3*exp(asinh(a + b*x)**2), x)
\[ \int e^{\text {arcsinh}(a+b x)^2} x^3 \, dx=\int { x^{3} e^{\left (\operatorname {arsinh}\left (b x + a\right )^{2}\right )} \,d x } \] Input:
integrate(exp(arcsinh(b*x+a)^2)*x^3,x, algorithm="maxima")
Output:
integrate(x^3*e^(arcsinh(b*x + a)^2), x)
\[ \int e^{\text {arcsinh}(a+b x)^2} x^3 \, dx=\int { x^{3} e^{\left (\operatorname {arsinh}\left (b x + a\right )^{2}\right )} \,d x } \] Input:
integrate(exp(arcsinh(b*x+a)^2)*x^3,x, algorithm="giac")
Output:
integrate(x^3*e^(arcsinh(b*x + a)^2), x)
Timed out. \[ \int e^{\text {arcsinh}(a+b x)^2} x^3 \, dx=\int x^3\,{\mathrm {e}}^{{\mathrm {asinh}\left (a+b\,x\right )}^2} \,d x \] Input:
int(x^3*exp(asinh(a + b*x)^2),x)
Output:
int(x^3*exp(asinh(a + b*x)^2), x)
\[ \int e^{\text {arcsinh}(a+b x)^2} x^3 \, dx=\int e^{\mathit {asinh} \left (b x +a \right )^{2}} x^{3}d x \] Input:
int(exp(asinh(b*x+a)^2)*x^3,x)
Output:
int(e**(asinh(a + b*x)**2)*x**3,x)