Integrand size = 14, antiderivative size = 248 \[ \int e^{-\frac {3}{2} \text {arctanh}(a x)} x^3 \, dx=-\frac {41 (1-a x)^{3/4} \sqrt [4]{1+a x}}{64 a^4}-\frac {15 (1-a x)^{7/4} \sqrt [4]{1+a x}}{32 a^4}+\frac {3 (1-a x)^{11/4} \sqrt [4]{1+a x}}{8 a^4}-\frac {(1-a x)^{15/4} \sqrt [4]{1+a x}}{4 a^4}+\frac {123 \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right )}{64 \sqrt {2} a^4}-\frac {123 \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right )}{64 \sqrt {2} a^4}-\frac {123 \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{1+a x}}{\sqrt [4]{1-a x} \left (1+\frac {\sqrt {1+a x}}{\sqrt {1-a x}}\right )}\right )}{64 \sqrt {2} a^4} \] Output:
-41/64*(-a*x+1)^(3/4)*(a*x+1)^(1/4)/a^4-15/32*(-a*x+1)^(7/4)*(a*x+1)^(1/4) /a^4+3/8*(-a*x+1)^(11/4)*(a*x+1)^(1/4)/a^4-1/4*(-a*x+1)^(15/4)*(a*x+1)^(1/ 4)/a^4+123/128*arctan(1-2^(1/2)*(a*x+1)^(1/4)/(-a*x+1)^(1/4))*2^(1/2)/a^4- 123/128*arctan(1+2^(1/2)*(a*x+1)^(1/4)/(-a*x+1)^(1/4))*2^(1/2)/a^4-123/128 *arctanh(2^(1/2)*(a*x+1)^(1/4)/(-a*x+1)^(1/4)/(1+(a*x+1)^(1/2)/(-a*x+1)^(1 /2)))*2^(1/2)/a^4
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.14 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.47 \[ \int e^{-\frac {3}{2} \text {arctanh}(a x)} x^3 \, dx=\frac {(1-a x)^{7/4} \left (-7 a^2 x^2 \sqrt [4]{1+a x}+12 \sqrt [4]{2} \operatorname {Hypergeometric2F1}\left (-\frac {5}{4},\frac {7}{4},\frac {11}{4},\frac {1}{2} (1-a x)\right )-20 \sqrt [4]{2} \operatorname {Hypergeometric2F1}\left (-\frac {1}{4},\frac {7}{4},\frac {11}{4},\frac {1}{2} (1-a x)\right )+7 \sqrt [4]{2} \operatorname {Hypergeometric2F1}\left (\frac {3}{4},\frac {7}{4},\frac {11}{4},\frac {1}{2} (1-a x)\right )\right )}{28 a^4} \] Input:
Integrate[x^3/E^((3*ArcTanh[a*x])/2),x]
Output:
((1 - a*x)^(7/4)*(-7*a^2*x^2*(1 + a*x)^(1/4) + 12*2^(1/4)*Hypergeometric2F 1[-5/4, 7/4, 11/4, (1 - a*x)/2] - 20*2^(1/4)*Hypergeometric2F1[-1/4, 7/4, 11/4, (1 - a*x)/2] + 7*2^(1/4)*Hypergeometric2F1[3/4, 7/4, 11/4, (1 - a*x) /2]))/(28*a^4)
Time = 0.86 (sec) , antiderivative size = 282, normalized size of antiderivative = 1.14, number of steps used = 16, number of rules used = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.071, Rules used = {6676, 111, 27, 164, 60, 73, 854, 826, 1476, 1082, 217, 1479, 25, 27, 1103}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^3 e^{-\frac {3}{2} \text {arctanh}(a x)} \, dx\) |
\(\Big \downarrow \) 6676 |
\(\displaystyle \int \frac {x^3 (1-a x)^{3/4}}{(a x+1)^{3/4}}dx\) |
\(\Big \downarrow \) 111 |
\(\displaystyle -\frac {\int -\frac {x (4-3 a x) (1-a x)^{3/4}}{2 (a x+1)^{3/4}}dx}{4 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\int \frac {x (4-3 a x) (1-a x)^{3/4}}{(a x+1)^{3/4}}dx}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 164 |
\(\displaystyle \frac {-\frac {41 \int \frac {(1-a x)^{3/4}}{(a x+1)^{3/4}}dx}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {-\frac {41 \left (\frac {3}{2} \int \frac {1}{\sqrt [4]{1-a x} (a x+1)^{3/4}}dx+\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \int \frac {\sqrt {1-a x}}{(a x+1)^{3/4}}d\sqrt [4]{1-a x}}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 854 |
\(\displaystyle \frac {-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \int \frac {\sqrt {1-a x}}{2-a x}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 826 |
\(\displaystyle \frac {-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \left (\frac {1}{2} \int \frac {\sqrt {1-a x}+1}{2-a x}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}-\frac {1}{2} \int \frac {1-\sqrt {1-a x}}{2-a x}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 1476 |
\(\displaystyle \frac {-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \left (\frac {1}{2} \left (\frac {1}{2} \int \frac {1}{\sqrt {1-a x}-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+\frac {1}{2} \int \frac {1}{\sqrt {1-a x}+\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )-\frac {1}{2} \int \frac {1-\sqrt {1-a x}}{2-a x}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 1082 |
\(\displaystyle \frac {-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \left (\frac {1}{2} \left (\frac {\int \frac {1}{-\sqrt {1-a x}-1}d\left (1-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\sqrt {1-a x}-1}d\left (\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-\sqrt {1-a x}}{2-a x}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle \frac {-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \left (\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-\sqrt {1-a x}}{2-a x}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 1479 |
\(\displaystyle \frac {-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \left (\frac {1}{2} \left (\frac {\int -\frac {\sqrt {2}-\frac {2 \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}}{\sqrt {1-a x}-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}}{2 \sqrt {2}}+\frac {\int -\frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{\sqrt {1-a x}+\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{\sqrt {2}}\right )\right )}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}}{\sqrt {1-a x}-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}}{2 \sqrt {2}}-\frac {\int \frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{\sqrt {1-a x}+\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{\sqrt {2}}\right )\right )}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}}{\sqrt {1-a x}-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}}{2 \sqrt {2}}-\frac {1}{2} \int \frac {\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1}{\sqrt {1-a x}+\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1}d\frac {\sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{\sqrt {2}}\right )\right )}{a}\right )}{8 a}-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
\(\Big \downarrow \) 1103 |
\(\displaystyle \frac {-\frac {(11-4 a x) \sqrt [4]{a x+1} (1-a x)^{7/4}}{4 a^2}-\frac {41 \left (\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{a}-\frac {6 \left (\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}\right )}{\sqrt {2}}\right )+\frac {1}{2} \left (\frac {\log \left (\sqrt {1-a x}-\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\sqrt {1-a x}+\frac {\sqrt {2} \sqrt [4]{1-a x}}{\sqrt [4]{a x+1}}+1\right )}{2 \sqrt {2}}\right )\right )}{a}\right )}{8 a}}{8 a^2}-\frac {x^2 (1-a x)^{7/4} \sqrt [4]{a x+1}}{4 a^2}\) |
Input:
Int[x^3/E^((3*ArcTanh[a*x])/2),x]
Output:
-1/4*(x^2*(1 - a*x)^(7/4)*(1 + a*x)^(1/4))/a^2 + (-1/4*((11 - 4*a*x)*(1 - a*x)^(7/4)*(1 + a*x)^(1/4))/a^2 - (41*(((1 - a*x)^(3/4)*(1 + a*x)^(1/4))/a - (6*((-(ArcTan[1 - (Sqrt[2]*(1 - a*x)^(1/4))/(1 + a*x)^(1/4)]/Sqrt[2]) + ArcTan[1 + (Sqrt[2]*(1 - a*x)^(1/4))/(1 + a*x)^(1/4)]/Sqrt[2])/2 + (Log[1 + Sqrt[1 - a*x] - (Sqrt[2]*(1 - a*x)^(1/4))/(1 + a*x)^(1/4)]/(2*Sqrt[2]) - Log[1 + Sqrt[1 - a*x] + (Sqrt[2]*(1 - a*x)^(1/4))/(1 + a*x)^(1/4)]/(2*Sq rt[2]))/2))/a))/(8*a))/(8*a^2)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[b*(a + b*x)^(m - 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1 )/(d*f*(m + n + p + 1))), x] + Simp[1/(d*f*(m + n + p + 1)) Int[(a + b*x) ^(m - 2)*(c + d*x)^n*(e + f*x)^p*Simp[a^2*d*f*(m + n + p + 1) - b*(b*c*e*(m - 1) + a*(d*e*(n + 1) + c*f*(p + 1))) + b*(a*d*f*(2*m + n + p) - b*(d*e*(m + n) + c*f*(m + p)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] & & GtQ[m, 1] && NeQ[m + n + p + 1, 0] && IntegerQ[m]
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_ ))*((g_.) + (h_.)*(x_)), x_] :> Simp[(-(a*d*f*h*(n + 2) + b*c*f*h*(m + 2) - b*d*(f*g + e*h)*(m + n + 3) - b*d*f*h*(m + n + 2)*x))*(a + b*x)^(m + 1)*(( c + d*x)^(n + 1)/(b^2*d^2*(m + n + 2)*(m + n + 3))), x] + Simp[(a^2*d^2*f*h *(n + 1)*(n + 2) + a*b*d*(n + 1)*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(m + n + 3)) + b^2*(c^2*f*h*(m + 1)*(m + 2) - c*d*(f*g + e*h)*(m + 1)*(m + n + 3) + d^2*e*g*(m + n + 2)*(m + n + 3)))/(b^2*d^2*(m + n + 2)*(m + n + 3)) Int[( a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] && NeQ[m + n + 2, 0] && NeQ[m + n + 3, 0]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s) Int[(r + s*x^2)/(a + b*x^ 4), x], x] - Simp[1/(2*s) Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ, b]]))
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^(p + (m + 1)/n) Subst[Int[x^m/(1 - b*x^n)^(p + (m + 1)/n + 1), x], x, x/(a + b*x^n )^(1/n)], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[-1, p, 0] && NeQ[p, - 2^(-1)] && IntegersQ[m, p + (m + 1)/n]
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S implify[a*(c/b^2)]}, Simp[-2/b Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b )], x] /; RationalQ[q] && (EqQ[q^2, 1] || !RationalQ[b^2 - 4*a*c])] /; Fre eQ[{a, b, c}, x]
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 2*(d/e), 2]}, Simp[e/(2*c) Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ e/(2*c) Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ -2*(d/e), 2]}, Simp[e/(2*c*q) Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Simp[e/(2*c*q) Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*((c_.)*(x_))^(m_.), x_Symbol] :> Int[(c*x) ^m*((1 + a*x)^(n/2)/(1 - a*x)^(n/2)), x] /; FreeQ[{a, c, m, n}, x] && !Int egerQ[(n - 1)/2]
\[\int \frac {x^{3}}{{\left (\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )}^{\frac {3}{2}}}d x\]
Input:
int(x^3/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2),x)
Output:
int(x^3/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2),x)
Time = 0.08 (sec) , antiderivative size = 262, normalized size of antiderivative = 1.06 \[ \int e^{-\frac {3}{2} \text {arctanh}(a x)} x^3 \, dx=-\frac {4 \, {\left (16 \, a^{4} x^{4} - 40 \, a^{3} x^{3} + 54 \, a^{2} x^{2} - 93 \, a x + 63\right )} \sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}} + 246 \, \sqrt {2} \arctan \left (\sqrt {2} \sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}} + 1\right ) + 246 \, \sqrt {2} \arctan \left (\sqrt {2} \sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}} - 1\right ) + 123 \, \sqrt {2} \log \left (\frac {a x + \sqrt {2} {\left (a x - 1\right )} \sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}} - \sqrt {-a^{2} x^{2} + 1} - 1}{a x - 1}\right ) - 123 \, \sqrt {2} \log \left (\frac {a x - \sqrt {2} {\left (a x - 1\right )} \sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}} - \sqrt {-a^{2} x^{2} + 1} - 1}{a x - 1}\right )}{256 \, a^{4}} \] Input:
integrate(x^3/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2),x, algorithm="fricas")
Output:
-1/256*(4*(16*a^4*x^4 - 40*a^3*x^3 + 54*a^2*x^2 - 93*a*x + 63)*sqrt(-sqrt( -a^2*x^2 + 1)/(a*x - 1)) + 246*sqrt(2)*arctan(sqrt(2)*sqrt(-sqrt(-a^2*x^2 + 1)/(a*x - 1)) + 1) + 246*sqrt(2)*arctan(sqrt(2)*sqrt(-sqrt(-a^2*x^2 + 1) /(a*x - 1)) - 1) + 123*sqrt(2)*log((a*x + sqrt(2)*(a*x - 1)*sqrt(-sqrt(-a^ 2*x^2 + 1)/(a*x - 1)) - sqrt(-a^2*x^2 + 1) - 1)/(a*x - 1)) - 123*sqrt(2)*l og((a*x - sqrt(2)*(a*x - 1)*sqrt(-sqrt(-a^2*x^2 + 1)/(a*x - 1)) - sqrt(-a^ 2*x^2 + 1) - 1)/(a*x - 1)))/a^4
\[ \int e^{-\frac {3}{2} \text {arctanh}(a x)} x^3 \, dx=\int \frac {x^{3}}{\left (\frac {a x + 1}{\sqrt {- a^{2} x^{2} + 1}}\right )^{\frac {3}{2}}}\, dx \] Input:
integrate(x**3/((a*x+1)/(-a**2*x**2+1)**(1/2))**(3/2),x)
Output:
Integral(x**3/((a*x + 1)/sqrt(-a**2*x**2 + 1))**(3/2), x)
\[ \int e^{-\frac {3}{2} \text {arctanh}(a x)} x^3 \, dx=\int { \frac {x^{3}}{\left (\frac {a x + 1}{\sqrt {-a^{2} x^{2} + 1}}\right )^{\frac {3}{2}}} \,d x } \] Input:
integrate(x^3/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2),x, algorithm="maxima")
Output:
integrate(x^3/((a*x + 1)/sqrt(-a^2*x^2 + 1))^(3/2), x)
Exception generated. \[ \int e^{-\frac {3}{2} \text {arctanh}(a x)} x^3 \, dx=\text {Exception raised: TypeError} \] Input:
integrate(x^3/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2),x, algorithm="giac")
Output:
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value
Timed out. \[ \int e^{-\frac {3}{2} \text {arctanh}(a x)} x^3 \, dx=\int \frac {x^3}{{\left (\frac {a\,x+1}{\sqrt {1-a^2\,x^2}}\right )}^{3/2}} \,d x \] Input:
int(x^3/((a*x + 1)/(1 - a^2*x^2)^(1/2))^(3/2),x)
Output:
int(x^3/((a*x + 1)/(1 - a^2*x^2)^(1/2))^(3/2), x)
\[ \int e^{-\frac {3}{2} \text {arctanh}(a x)} x^3 \, dx=\int \frac {x^{3}}{{\left (\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )}^{\frac {3}{2}}}d x \] Input:
int(x^3/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2),x)
Output:
int(x^3/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2),x)