\(\int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx\) [119]

Optimal result
Mathematica [C] (verified)
Rubi [A] (verified)
Maple [F]
Fricas [A] (verification not implemented)
Sympy [F]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 14, antiderivative size = 168 \[ \int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx=-\frac {(1-a x)^{3/4} \sqrt [4]{1+a x}}{4 x^4}+\frac {3 a (1-a x)^{3/4} \sqrt [4]{1+a x}}{8 x^3}-\frac {15 a^2 (1-a x)^{3/4} \sqrt [4]{1+a x}}{32 x^2}+\frac {63 a^3 (1-a x)^{3/4} \sqrt [4]{1+a x}}{64 x}-\frac {123}{64} a^4 \arctan \left (\frac {\sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right )-\frac {123}{64} a^4 \text {arctanh}\left (\frac {\sqrt [4]{1+a x}}{\sqrt [4]{1-a x}}\right ) \] Output:

-1/4*(-a*x+1)^(3/4)*(a*x+1)^(1/4)/x^4+3/8*a*(-a*x+1)^(3/4)*(a*x+1)^(1/4)/x 
^3-15/32*a^2*(-a*x+1)^(3/4)*(a*x+1)^(1/4)/x^2+63/64*a^3*(-a*x+1)^(3/4)*(a* 
x+1)^(1/4)/x-123/64*a^4*arctan((a*x+1)^(1/4)/(-a*x+1)^(1/4))-123/64*a^4*ar 
ctanh((a*x+1)^(1/4)/(-a*x+1)^(1/4))
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.04 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.51 \[ \int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx=\frac {(1-a x)^{3/4} \left (-16+8 a x-6 a^2 x^2+33 a^3 x^3+63 a^4 x^4-82 a^4 x^4 \operatorname {Hypergeometric2F1}\left (\frac {3}{4},1,\frac {7}{4},\frac {1-a x}{1+a x}\right )\right )}{64 x^4 (1+a x)^{3/4}} \] Input:

Integrate[1/(E^((3*ArcTanh[a*x])/2)*x^5),x]
 

Output:

((1 - a*x)^(3/4)*(-16 + 8*a*x - 6*a^2*x^2 + 33*a^3*x^3 + 63*a^4*x^4 - 82*a 
^4*x^4*Hypergeometric2F1[3/4, 1, 7/4, (1 - a*x)/(1 + a*x)]))/(64*x^4*(1 + 
a*x)^(3/4))
 

Rubi [A] (verified)

Time = 0.56 (sec) , antiderivative size = 173, normalized size of antiderivative = 1.03, number of steps used = 14, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.929, Rules used = {6676, 110, 27, 168, 27, 168, 27, 168, 27, 104, 756, 216, 219}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx\)

\(\Big \downarrow \) 6676

\(\displaystyle \int \frac {(1-a x)^{3/4}}{x^5 (a x+1)^{3/4}}dx\)

\(\Big \downarrow \) 110

\(\displaystyle \frac {1}{4} \int -\frac {3 a (3-2 a x)}{2 x^4 \sqrt [4]{1-a x} (a x+1)^{3/4}}dx-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {3}{8} a \int \frac {3-2 a x}{x^4 \sqrt [4]{1-a x} (a x+1)^{3/4}}dx-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 168

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{3} \int \frac {3 a (5-4 a x)}{2 x^3 \sqrt [4]{1-a x} (a x+1)^{3/4}}dx-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{2} a \int \frac {5-4 a x}{x^3 \sqrt [4]{1-a x} (a x+1)^{3/4}}dx-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 168

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{2} a \left (-\frac {1}{2} \int \frac {a (21-10 a x)}{2 x^2 \sqrt [4]{1-a x} (a x+1)^{3/4}}dx-\frac {5 (1-a x)^{3/4} \sqrt [4]{a x+1}}{2 x^2}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{2} a \left (-\frac {1}{4} a \int \frac {21-10 a x}{x^2 \sqrt [4]{1-a x} (a x+1)^{3/4}}dx-\frac {5 (1-a x)^{3/4} \sqrt [4]{a x+1}}{2 x^2}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 168

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{2} a \left (-\frac {1}{4} a \left (-\int \frac {41 a}{2 x \sqrt [4]{1-a x} (a x+1)^{3/4}}dx-\frac {21 (1-a x)^{3/4} \sqrt [4]{a x+1}}{x}\right )-\frac {5 (1-a x)^{3/4} \sqrt [4]{a x+1}}{2 x^2}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{2} a \left (-\frac {1}{4} a \left (-\frac {41}{2} a \int \frac {1}{x \sqrt [4]{1-a x} (a x+1)^{3/4}}dx-\frac {21 (1-a x)^{3/4} \sqrt [4]{a x+1}}{x}\right )-\frac {5 (1-a x)^{3/4} \sqrt [4]{a x+1}}{2 x^2}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 104

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{2} a \left (-\frac {1}{4} a \left (-82 a \int \frac {1}{\frac {a x+1}{1-a x}-1}d\frac {\sqrt [4]{a x+1}}{\sqrt [4]{1-a x}}-\frac {21 (1-a x)^{3/4} \sqrt [4]{a x+1}}{x}\right )-\frac {5 (1-a x)^{3/4} \sqrt [4]{a x+1}}{2 x^2}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 756

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{2} a \left (-\frac {1}{4} a \left (-82 a \left (-\frac {1}{2} \int \frac {1}{1-\frac {\sqrt {a x+1}}{\sqrt {1-a x}}}d\frac {\sqrt [4]{a x+1}}{\sqrt [4]{1-a x}}-\frac {1}{2} \int \frac {1}{\frac {\sqrt {a x+1}}{\sqrt {1-a x}}+1}d\frac {\sqrt [4]{a x+1}}{\sqrt [4]{1-a x}}\right )-\frac {21 (1-a x)^{3/4} \sqrt [4]{a x+1}}{x}\right )-\frac {5 (1-a x)^{3/4} \sqrt [4]{a x+1}}{2 x^2}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 216

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{2} a \left (-\frac {1}{4} a \left (-82 a \left (-\frac {1}{2} \int \frac {1}{1-\frac {\sqrt {a x+1}}{\sqrt {1-a x}}}d\frac {\sqrt [4]{a x+1}}{\sqrt [4]{1-a x}}-\frac {1}{2} \arctan \left (\frac {\sqrt [4]{a x+1}}{\sqrt [4]{1-a x}}\right )\right )-\frac {21 (1-a x)^{3/4} \sqrt [4]{a x+1}}{x}\right )-\frac {5 (1-a x)^{3/4} \sqrt [4]{a x+1}}{2 x^2}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

\(\Big \downarrow \) 219

\(\displaystyle -\frac {3}{8} a \left (-\frac {1}{2} a \left (-\frac {1}{4} a \left (-82 a \left (-\frac {1}{2} \arctan \left (\frac {\sqrt [4]{a x+1}}{\sqrt [4]{1-a x}}\right )-\frac {1}{2} \text {arctanh}\left (\frac {\sqrt [4]{a x+1}}{\sqrt [4]{1-a x}}\right )\right )-\frac {21 (1-a x)^{3/4} \sqrt [4]{a x+1}}{x}\right )-\frac {5 (1-a x)^{3/4} \sqrt [4]{a x+1}}{2 x^2}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{x^3}\right )-\frac {(1-a x)^{3/4} \sqrt [4]{a x+1}}{4 x^4}\)

Input:

Int[1/(E^((3*ArcTanh[a*x])/2)*x^5),x]
 

Output:

-1/4*((1 - a*x)^(3/4)*(1 + a*x)^(1/4))/x^4 - (3*a*(-(((1 - a*x)^(3/4)*(1 + 
 a*x)^(1/4))/x^3) - (a*((-5*(1 - a*x)^(3/4)*(1 + a*x)^(1/4))/(2*x^2) - (a* 
((-21*(1 - a*x)^(3/4)*(1 + a*x)^(1/4))/x - 82*a*(-1/2*ArcTan[(1 + a*x)^(1/ 
4)/(1 - a*x)^(1/4)] - ArcTanh[(1 + a*x)^(1/4)/(1 - a*x)^(1/4)]/2)))/4))/2) 
)/8
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 104
Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x 
_)), x_] :> With[{q = Denominator[m]}, Simp[q   Subst[Int[x^(q*(m + 1) - 1) 
/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^(1/q)], x] 
] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && L 
tQ[-1, m, 0] && SimplerQ[a + b*x, c + d*x]
 

rule 110
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Simp[(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/((m + 
1)*(b*e - a*f))), x] - Simp[1/((m + 1)*(b*e - a*f))   Int[(a + b*x)^(m + 1) 
*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[d*e*n + c*f*(m + p + 2) + d*f*(m + n + 
p + 2)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && Gt 
Q[n, 0] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, 
 m + n])
 

rule 168
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + 
 d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + S 
imp[1/((m + 1)*(b*c - a*d)*(b*e - a*f))   Int[(a + b*x)^(m + 1)*(c + d*x)^n 
*(e + f*x)^p*Simp[(a*d*f*g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a* 
h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p + 3)*x, x], x], 
 x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && ILtQ[m, -1]
 

rule 216
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A 
rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a 
, 0] || GtQ[b, 0])
 

rule 219
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 756
Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2 
]], s = Denominator[Rt[-a/b, 2]]}, Simp[r/(2*a)   Int[1/(r - s*x^2), x], x] 
 + Simp[r/(2*a)   Int[1/(r + s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !GtQ[a 
/b, 0]
 

rule 6676
Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*((c_.)*(x_))^(m_.), x_Symbol] :> Int[(c*x) 
^m*((1 + a*x)^(n/2)/(1 - a*x)^(n/2)), x] /; FreeQ[{a, c, m, n}, x] &&  !Int 
egerQ[(n - 1)/2]
 
Maple [F]

\[\int \frac {1}{{\left (\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )}^{\frac {3}{2}} x^{5}}d x\]

Input:

int(1/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2)/x^5,x)
 

Output:

int(1/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2)/x^5,x)
 

Fricas [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 161, normalized size of antiderivative = 0.96 \[ \int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx=-\frac {246 \, a^{4} x^{4} \arctan \left (\sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}}\right ) + 123 \, a^{4} x^{4} \log \left (\sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}} + 1\right ) - 123 \, a^{4} x^{4} \log \left (\sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}} - 1\right ) + 2 \, {\left (63 \, a^{4} x^{4} - 93 \, a^{3} x^{3} + 54 \, a^{2} x^{2} - 40 \, a x + 16\right )} \sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}}}{128 \, x^{4}} \] Input:

integrate(1/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2)/x^5,x, algorithm="fricas")
                                                                                    
                                                                                    
 

Output:

-1/128*(246*a^4*x^4*arctan(sqrt(-sqrt(-a^2*x^2 + 1)/(a*x - 1))) + 123*a^4* 
x^4*log(sqrt(-sqrt(-a^2*x^2 + 1)/(a*x - 1)) + 1) - 123*a^4*x^4*log(sqrt(-s 
qrt(-a^2*x^2 + 1)/(a*x - 1)) - 1) + 2*(63*a^4*x^4 - 93*a^3*x^3 + 54*a^2*x^ 
2 - 40*a*x + 16)*sqrt(-sqrt(-a^2*x^2 + 1)/(a*x - 1)))/x^4
 

Sympy [F]

\[ \int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx=\int \frac {1}{x^{5} \left (\frac {a x + 1}{\sqrt {- a^{2} x^{2} + 1}}\right )^{\frac {3}{2}}}\, dx \] Input:

integrate(1/((a*x+1)/(-a**2*x**2+1)**(1/2))**(3/2)/x**5,x)
 

Output:

Integral(1/(x**5*((a*x + 1)/sqrt(-a**2*x**2 + 1))**(3/2)), x)
 

Maxima [F]

\[ \int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx=\int { \frac {1}{x^{5} \left (\frac {a x + 1}{\sqrt {-a^{2} x^{2} + 1}}\right )^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2)/x^5,x, algorithm="maxima")
 

Output:

integrate(1/(x^5*((a*x + 1)/sqrt(-a^2*x^2 + 1))^(3/2)), x)
 

Giac [F]

\[ \int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx=\int { \frac {1}{x^{5} \left (\frac {a x + 1}{\sqrt {-a^{2} x^{2} + 1}}\right )^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2)/x^5,x, algorithm="giac")
 

Output:

integrate(1/(x^5*((a*x + 1)/sqrt(-a^2*x^2 + 1))^(3/2)), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx=\int \frac {1}{x^5\,{\left (\frac {a\,x+1}{\sqrt {1-a^2\,x^2}}\right )}^{3/2}} \,d x \] Input:

int(1/(x^5*((a*x + 1)/(1 - a^2*x^2)^(1/2))^(3/2)),x)
 

Output:

int(1/(x^5*((a*x + 1)/(1 - a^2*x^2)^(1/2))^(3/2)), x)
 

Reduce [F]

\[ \int \frac {e^{-\frac {3}{2} \text {arctanh}(a x)}}{x^5} \, dx=\int \frac {1}{{\left (\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )}^{\frac {3}{2}} x^{5}}d x \] Input:

int(1/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2)/x^5,x)
 

Output:

int(1/((a*x+1)/(-a^2*x^2+1)^(1/2))^(3/2)/x^5,x)