\(\int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx\) [351]

Optimal result

Integrand size = 19, antiderivative size = 129 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx=\frac {a c^3 \sqrt {1-a^2 x^2}}{2 x^4}-\frac {a^3 c^3 \sqrt {1-a^2 x^2}}{4 x^2}-\frac {c^3 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}-\frac {7 a^2 c^3 \left (1-a^2 x^2\right )^{3/2}}{15 x^3}-\frac {1}{4} a^5 c^3 \text {arctanh}\left (\sqrt {1-a^2 x^2}\right ) \] Output:

1/2*a*c^3*(-a^2*x^2+1)^(1/2)/x^4-1/4*a^3*c^3*(-a^2*x^2+1)^(1/2)/x^2-1/5*c^ 
3*(-a^2*x^2+1)^(3/2)/x^5-7/15*a^2*c^3*(-a^2*x^2+1)^(3/2)/x^3-1/4*a^5*c^3*a 
rctanh((-a^2*x^2+1)^(1/2))
 

Mathematica [A] (verified)

Time = 0.05 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.83 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx=-\frac {c^3 \left (12-30 a x+4 a^2 x^2+45 a^3 x^3-44 a^4 x^4-15 a^5 x^5+28 a^6 x^6+15 a^5 x^5 \sqrt {1-a^2 x^2} \text {arctanh}\left (\sqrt {1-a^2 x^2}\right )\right )}{60 x^5 \sqrt {1-a^2 x^2}} \] Input:

Integrate[(E^ArcTanh[a*x]*(c - a*c*x)^3)/x^6,x]
 

Output:

-1/60*(c^3*(12 - 30*a*x + 4*a^2*x^2 + 45*a^3*x^3 - 44*a^4*x^4 - 15*a^5*x^5 
 + 28*a^6*x^6 + 15*a^5*x^5*Sqrt[1 - a^2*x^2]*ArcTanh[Sqrt[1 - a^2*x^2]]))/ 
(x^5*Sqrt[1 - a^2*x^2])
 

Rubi [A] (verified)

Time = 0.58 (sec) , antiderivative size = 124, normalized size of antiderivative = 0.96, number of steps used = 12, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.579, Rules used = {6678, 27, 540, 27, 539, 27, 534, 243, 51, 73, 221}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx\)

\(\Big \downarrow \) 6678

\(\displaystyle c \int \frac {c^2 (1-a x)^2 \sqrt {1-a^2 x^2}}{x^6}dx\)

\(\Big \downarrow \) 27

\(\displaystyle c^3 \int \frac {(1-a x)^2 \sqrt {1-a^2 x^2}}{x^6}dx\)

\(\Big \downarrow \) 540

\(\displaystyle c^3 \left (-\frac {1}{5} \int \frac {a (10-7 a x) \sqrt {1-a^2 x^2}}{x^5}dx-\frac {\left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle c^3 \left (-\frac {1}{5} a \int \frac {(10-7 a x) \sqrt {1-a^2 x^2}}{x^5}dx-\frac {\left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )\)

\(\Big \downarrow \) 539

\(\displaystyle c^3 \left (-\frac {1}{5} a \left (-\frac {1}{4} \int \frac {2 a (14-5 a x) \sqrt {1-a^2 x^2}}{x^4}dx-\frac {5 \left (1-a^2 x^2\right )^{3/2}}{2 x^4}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle c^3 \left (-\frac {1}{5} a \left (-\frac {1}{2} a \int \frac {(14-5 a x) \sqrt {1-a^2 x^2}}{x^4}dx-\frac {5 \left (1-a^2 x^2\right )^{3/2}}{2 x^4}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )\)

\(\Big \downarrow \) 534

\(\displaystyle c^3 \left (-\frac {1}{5} a \left (-\frac {1}{2} a \left (-5 a \int \frac {\sqrt {1-a^2 x^2}}{x^3}dx-\frac {14 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {5 \left (1-a^2 x^2\right )^{3/2}}{2 x^4}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )\)

\(\Big \downarrow \) 243

\(\displaystyle c^3 \left (-\frac {1}{5} a \left (-\frac {1}{2} a \left (-\frac {5}{2} a \int \frac {\sqrt {1-a^2 x^2}}{x^4}dx^2-\frac {14 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {5 \left (1-a^2 x^2\right )^{3/2}}{2 x^4}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )\)

\(\Big \downarrow \) 51

\(\displaystyle c^3 \left (-\frac {1}{5} a \left (-\frac {1}{2} a \left (-\frac {5}{2} a \left (-\frac {1}{2} a^2 \int \frac {1}{x^2 \sqrt {1-a^2 x^2}}dx^2-\frac {\sqrt {1-a^2 x^2}}{x^2}\right )-\frac {14 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {5 \left (1-a^2 x^2\right )^{3/2}}{2 x^4}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )\)

\(\Big \downarrow \) 73

\(\displaystyle c^3 \left (-\frac {1}{5} a \left (-\frac {1}{2} a \left (-\frac {5}{2} a \left (\int \frac {1}{\frac {1}{a^2}-\frac {x^4}{a^2}}d\sqrt {1-a^2 x^2}-\frac {\sqrt {1-a^2 x^2}}{x^2}\right )-\frac {14 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {5 \left (1-a^2 x^2\right )^{3/2}}{2 x^4}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )\)

\(\Big \downarrow \) 221

\(\displaystyle c^3 \left (-\frac {1}{5} a \left (-\frac {1}{2} a \left (-\frac {5}{2} a \left (a^2 \text {arctanh}\left (\sqrt {1-a^2 x^2}\right )-\frac {\sqrt {1-a^2 x^2}}{x^2}\right )-\frac {14 \left (1-a^2 x^2\right )^{3/2}}{3 x^3}\right )-\frac {5 \left (1-a^2 x^2\right )^{3/2}}{2 x^4}\right )-\frac {\left (1-a^2 x^2\right )^{3/2}}{5 x^5}\right )\)

Input:

Int[(E^ArcTanh[a*x]*(c - a*c*x)^3)/x^6,x]
 

Output:

c^3*(-1/5*(1 - a^2*x^2)^(3/2)/x^5 - (a*((-5*(1 - a^2*x^2)^(3/2))/(2*x^4) - 
 (a*((-14*(1 - a^2*x^2)^(3/2))/(3*x^3) - (5*a*(-(Sqrt[1 - a^2*x^2]/x^2) + 
a^2*ArcTanh[Sqrt[1 - a^2*x^2]]))/2))/2))/5)
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ 
(a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) 
Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d, n}, x 
] && ILtQ[m, -1] && FractionQ[n] && GtQ[n, 0]
 

rule 73

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 221

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 243

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[1/2   Subst[In 
t[x^((m - 1)/2)*(a + b*x)^p, x], x, x^2], x] /; FreeQ[{a, b, m, p}, x] && I 
ntegerQ[(m - 1)/2]
 

rule 534

Int[(x_)^(m_)*((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> 
Simp[(-c)*x^(m + 1)*((a + b*x^2)^(p + 1)/(2*a*(p + 1))), x] + Simp[d   Int[ 
x^(m + 1)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, m, p}, x] && ILtQ[m, 
0] && GtQ[p, -1] && EqQ[m + 2*p + 3, 0]
 

rule 539

Int[(x_)^(m_)*((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> 
Simp[c*x^(m + 1)*((a + b*x^2)^(p + 1)/(a*(m + 1))), x] + Simp[1/(a*(m + 1)) 
   Int[x^(m + 1)*(a + b*x^2)^p*(a*d*(m + 1) - b*c*(m + 2*p + 3)*x), x], x] 
/; FreeQ[{a, b, c, d, p}, x] && ILtQ[m, -1] && GtQ[p, -1] && IntegerQ[2*p]
 

rule 540

Int[(x_)^(m_)*((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol 
] :> With[{Qx = PolynomialQuotient[(c + d*x)^n, x, x], R = PolynomialRemain 
der[(c + d*x)^n, x, x]}, Simp[R*x^(m + 1)*((a + b*x^2)^(p + 1)/(a*(m + 1))) 
, x] + Simp[1/(a*(m + 1))   Int[x^(m + 1)*(a + b*x^2)^p*ExpandToSum[a*(m + 
1)*Qx - b*R*(m + 2*p + 3)*x, x], x], x]] /; FreeQ[{a, b, c, d, p}, x] && IG 
tQ[n, 1] && ILtQ[m, -1] && GtQ[p, -1] && IntegerQ[2*p]
 

rule 6678

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_))^(p_.)*((e_.) + (f_.)* 
(x_))^(m_.), x_Symbol] :> Simp[c^n   Int[(e + f*x)^m*(c + d*x)^(p - n)*(1 - 
 a^2*x^2)^(n/2), x], x] /; FreeQ[{a, c, d, e, f, m, p}, x] && EqQ[a*c + d, 
0] && IntegerQ[(n - 1)/2] && (IntegerQ[p] || EqQ[p, n/2] || EqQ[p - n/2 - 1 
, 0]) && IntegerQ[2*p]
 

Maple [A] (verified)

Time = 0.18 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.69

method	result	size
risch	\(-\frac {\left (28 x^{6} a^{6}-15 a^{5} x^{5}-44 a^{4} x^{4}+45 a^{3} x^{3}+4 a^{2} x^{2}-30 a x +12\right ) c^{3}}{60 x^{5} \sqrt {-a^{2} x^{2}+1}}-\frac {a^{5} \operatorname {arctanh}\left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right ) c^{3}}{4}\)	\(89\)
default	\(-c^{3} \left (-\frac {a^{4} \sqrt {-a^{2} x^{2}+1}}{x}+\frac {\sqrt {-a^{2} x^{2}+1}}{5 x^{5}}-\frac {4 a^{2} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{3 x^{3}}-\frac {2 a^{2} \sqrt {-a^{2} x^{2}+1}}{3 x}\right )}{5}+2 a \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{4 x^{4}}+\frac {3 a^{2} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{2 x^{2}}-\frac {a^{2} \operatorname {arctanh}\left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right )}{2}\right )}{4}\right )-2 a^{3} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{2 x^{2}}-\frac {a^{2} \operatorname {arctanh}\left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right )}{2}\right )\right )\)	\(190\)
meijerg	\(\frac {a^{4} c^{3} \sqrt {-a^{2} x^{2}+1}}{x}-\frac {a^{5} c^{3} \left (\frac {\sqrt {\pi }}{x^{2} a^{2}}-\frac {\left (1-2 \ln \left (2\right )+2 \ln \left (x \right )+\ln \left (-a^{2}\right )\right ) \sqrt {\pi }}{2}-\frac {\sqrt {\pi }\, \left (-4 a^{2} x^{2}+8\right )}{8 a^{2} x^{2}}+\frac {\sqrt {\pi }\, \sqrt {-a^{2} x^{2}+1}}{a^{2} x^{2}}+\sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {-a^{2} x^{2}+1}}{2}\right )\right )}{\sqrt {\pi }}-\frac {a^{5} c^{3} \left (-\frac {\sqrt {\pi }}{2 x^{4} a^{4}}-\frac {\sqrt {\pi }}{2 x^{2} a^{2}}+\frac {3 \left (\frac {7}{6}-2 \ln \left (2\right )+2 \ln \left (x \right )+\ln \left (-a^{2}\right )\right ) \sqrt {\pi }}{8}+\frac {\sqrt {\pi }\, \left (-7 a^{4} x^{4}+8 a^{2} x^{2}+8\right )}{16 a^{4} x^{4}}-\frac {\sqrt {\pi }\, \left (12 a^{2} x^{2}+8\right ) \sqrt {-a^{2} x^{2}+1}}{16 a^{4} x^{4}}-\frac {3 \sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {-a^{2} x^{2}+1}}{2}\right )}{4}\right )}{\sqrt {\pi }}-\frac {c^{3} \left (\frac {8}{3} a^{4} x^{4}+\frac {4}{3} a^{2} x^{2}+1\right ) \sqrt {-a^{2} x^{2}+1}}{5 x^{5}}\)	\(308\)

Input:

int((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^3/x^6,x,method=_RETURNVERBOSE)
 

Output:

-1/60*(28*a^6*x^6-15*a^5*x^5-44*a^4*x^4+45*a^3*x^3+4*a^2*x^2-30*a*x+12)/x^ 
5/(-a^2*x^2+1)^(1/2)*c^3-1/4*a^5*arctanh(1/(-a^2*x^2+1)^(1/2))*c^3
 

Fricas [A] (verification not implemented)

Time = 0.08 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.74 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx=\frac {15 \, a^{5} c^{3} x^{5} \log \left (\frac {\sqrt {-a^{2} x^{2} + 1} - 1}{x}\right ) + {\left (28 \, a^{4} c^{3} x^{4} - 15 \, a^{3} c^{3} x^{3} - 16 \, a^{2} c^{3} x^{2} + 30 \, a c^{3} x - 12 \, c^{3}\right )} \sqrt {-a^{2} x^{2} + 1}}{60 \, x^{5}} \] Input:

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^3/x^6,x, algorithm="fricas 
")
 

Output:

1/60*(15*a^5*c^3*x^5*log((sqrt(-a^2*x^2 + 1) - 1)/x) + (28*a^4*c^3*x^4 - 1 
5*a^3*c^3*x^3 - 16*a^2*c^3*x^2 + 30*a*c^3*x - 12*c^3)*sqrt(-a^2*x^2 + 1))/ 
x^5
 

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 5.81 (sec) , antiderivative size = 474, normalized size of antiderivative = 3.67 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx=- a^{4} c^{3} \left (\begin {cases} - \frac {i \sqrt {a^{2} x^{2} - 1}}{x} & \text {for}\: \left |{a^{2} x^{2}}\right | > 1 \\- \frac {\sqrt {- a^{2} x^{2} + 1}}{x} & \text {otherwise} \end {cases}\right ) + 2 a^{3} c^{3} \left (\begin {cases} - \frac {a^{2} \operatorname {acosh}{\left (\frac {1}{a x} \right )}}{2} + \frac {a}{2 x \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {1}{2 a x^{3} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} & \text {for}\: \frac {1}{\left |{a^{2} x^{2}}\right |} > 1 \\\frac {i a^{2} \operatorname {asin}{\left (\frac {1}{a x} \right )}}{2} - \frac {i a \sqrt {1 - \frac {1}{a^{2} x^{2}}}}{2 x} & \text {otherwise} \end {cases}\right ) - 2 a c^{3} \left (\begin {cases} - \frac {3 a^{4} \operatorname {acosh}{\left (\frac {1}{a x} \right )}}{8} + \frac {3 a^{3}}{8 x \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {a}{8 x^{3} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {1}{4 a x^{5} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} & \text {for}\: \frac {1}{\left |{a^{2} x^{2}}\right |} > 1 \\\frac {3 i a^{4} \operatorname {asin}{\left (\frac {1}{a x} \right )}}{8} - \frac {3 i a^{3}}{8 x \sqrt {1 - \frac {1}{a^{2} x^{2}}}} + \frac {i a}{8 x^{3} \sqrt {1 - \frac {1}{a^{2} x^{2}}}} + \frac {i}{4 a x^{5} \sqrt {1 - \frac {1}{a^{2} x^{2}}}} & \text {otherwise} \end {cases}\right ) + c^{3} \left (\begin {cases} - \frac {8 a^{5} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}}{15} - \frac {4 a^{3} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}}{15 x^{2}} - \frac {a \sqrt {-1 + \frac {1}{a^{2} x^{2}}}}{5 x^{4}} & \text {for}\: \frac {1}{\left |{a^{2} x^{2}}\right |} > 1 \\- \frac {8 i a^{5} \sqrt {1 - \frac {1}{a^{2} x^{2}}}}{15} - \frac {4 i a^{3} \sqrt {1 - \frac {1}{a^{2} x^{2}}}}{15 x^{2}} - \frac {i a \sqrt {1 - \frac {1}{a^{2} x^{2}}}}{5 x^{4}} & \text {otherwise} \end {cases}\right ) \] Input:

integrate((a*x+1)/(-a**2*x**2+1)**(1/2)*(-a*c*x+c)**3/x**6,x)
 

Output:

-a**4*c**3*Piecewise((-I*sqrt(a**2*x**2 - 1)/x, Abs(a**2*x**2) > 1), (-sqr 
t(-a**2*x**2 + 1)/x, True)) + 2*a**3*c**3*Piecewise((-a**2*acosh(1/(a*x))/ 
2 + a/(2*x*sqrt(-1 + 1/(a**2*x**2))) - 1/(2*a*x**3*sqrt(-1 + 1/(a**2*x**2) 
)), 1/Abs(a**2*x**2) > 1), (I*a**2*asin(1/(a*x))/2 - I*a*sqrt(1 - 1/(a**2* 
x**2))/(2*x), True)) - 2*a*c**3*Piecewise((-3*a**4*acosh(1/(a*x))/8 + 3*a* 
*3/(8*x*sqrt(-1 + 1/(a**2*x**2))) - a/(8*x**3*sqrt(-1 + 1/(a**2*x**2))) - 
1/(4*a*x**5*sqrt(-1 + 1/(a**2*x**2))), 1/Abs(a**2*x**2) > 1), (3*I*a**4*as 
in(1/(a*x))/8 - 3*I*a**3/(8*x*sqrt(1 - 1/(a**2*x**2))) + I*a/(8*x**3*sqrt( 
1 - 1/(a**2*x**2))) + I/(4*a*x**5*sqrt(1 - 1/(a**2*x**2))), True)) + c**3* 
Piecewise((-8*a**5*sqrt(-1 + 1/(a**2*x**2))/15 - 4*a**3*sqrt(-1 + 1/(a**2* 
x**2))/(15*x**2) - a*sqrt(-1 + 1/(a**2*x**2))/(5*x**4), 1/Abs(a**2*x**2) > 
 1), (-8*I*a**5*sqrt(1 - 1/(a**2*x**2))/15 - 4*I*a**3*sqrt(1 - 1/(a**2*x** 
2))/(15*x**2) - I*a*sqrt(1 - 1/(a**2*x**2))/(5*x**4), True))
                                                                                    
                                                                                    
 

Maxima [A] (verification not implemented)

Time = 0.12 (sec) , antiderivative size = 145, normalized size of antiderivative = 1.12 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx=-\frac {1}{4} \, a^{5} c^{3} \log \left (\frac {2 \, \sqrt {-a^{2} x^{2} + 1}}{{\left | x \right |}} + \frac {2}{{\left | x \right |}}\right ) + \frac {7 \, \sqrt {-a^{2} x^{2} + 1} a^{4} c^{3}}{15 \, x} - \frac {\sqrt {-a^{2} x^{2} + 1} a^{3} c^{3}}{4 \, x^{2}} - \frac {4 \, \sqrt {-a^{2} x^{2} + 1} a^{2} c^{3}}{15 \, x^{3}} + \frac {\sqrt {-a^{2} x^{2} + 1} a c^{3}}{2 \, x^{4}} - \frac {\sqrt {-a^{2} x^{2} + 1} c^{3}}{5 \, x^{5}} \] Input:

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^3/x^6,x, algorithm="maxima 
")
 

Output:

-1/4*a^5*c^3*log(2*sqrt(-a^2*x^2 + 1)/abs(x) + 2/abs(x)) + 7/15*sqrt(-a^2* 
x^2 + 1)*a^4*c^3/x - 1/4*sqrt(-a^2*x^2 + 1)*a^3*c^3/x^2 - 4/15*sqrt(-a^2*x 
^2 + 1)*a^2*c^3/x^3 + 1/2*sqrt(-a^2*x^2 + 1)*a*c^3/x^4 - 1/5*sqrt(-a^2*x^2 
 + 1)*c^3/x^5
 

Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 297 vs. \(2 (109) = 218\).

Time = 0.15 (sec) , antiderivative size = 297, normalized size of antiderivative = 2.30 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx=\frac {{\left (3 \, a^{6} c^{3} - \frac {15 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )} a^{4} c^{3}}{x} + \frac {25 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{2} a^{2} c^{3}}{x^{2}} - \frac {90 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{4} c^{3}}{a^{2} x^{4}}\right )} a^{10} x^{5}}{480 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{5} {\left | a \right |}} - \frac {a^{6} c^{3} \log \left (\frac {{\left | -2 \, \sqrt {-a^{2} x^{2} + 1} {\left | a \right |} - 2 \, a \right |}}{2 \, a^{2} {\left | x \right |}}\right )}{4 \, {\left | a \right |}} + \frac {\frac {90 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )} a^{8} c^{3}}{x} - \frac {25 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{3} a^{4} c^{3}}{x^{3}} + \frac {15 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{4} a^{2} c^{3}}{x^{4}} - \frac {3 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{5} c^{3}}{x^{5}}}{480 \, a^{4} {\left | a \right |}} \] Input:

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^3/x^6,x, algorithm="giac")
 

Output:

1/480*(3*a^6*c^3 - 15*(sqrt(-a^2*x^2 + 1)*abs(a) + a)*a^4*c^3/x + 25*(sqrt 
(-a^2*x^2 + 1)*abs(a) + a)^2*a^2*c^3/x^2 - 90*(sqrt(-a^2*x^2 + 1)*abs(a) + 
 a)^4*c^3/(a^2*x^4))*a^10*x^5/((sqrt(-a^2*x^2 + 1)*abs(a) + a)^5*abs(a)) - 
 1/4*a^6*c^3*log(1/2*abs(-2*sqrt(-a^2*x^2 + 1)*abs(a) - 2*a)/(a^2*abs(x))) 
/abs(a) + 1/480*(90*(sqrt(-a^2*x^2 + 1)*abs(a) + a)*a^8*c^3/x - 25*(sqrt(- 
a^2*x^2 + 1)*abs(a) + a)^3*a^4*c^3/x^3 + 15*(sqrt(-a^2*x^2 + 1)*abs(a) + a 
)^4*a^2*c^3/x^4 - 3*(sqrt(-a^2*x^2 + 1)*abs(a) + a)^5*c^3/x^5)/(a^4*abs(a) 
)
 

Mupad [B] (verification not implemented)

Time = 0.05 (sec) , antiderivative size = 136, normalized size of antiderivative = 1.05 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx=\frac {a\,c^3\,\sqrt {1-a^2\,x^2}}{2\,x^4}-\frac {c^3\,\sqrt {1-a^2\,x^2}}{5\,x^5}-\frac {4\,a^2\,c^3\,\sqrt {1-a^2\,x^2}}{15\,x^3}-\frac {a^3\,c^3\,\sqrt {1-a^2\,x^2}}{4\,x^2}+\frac {7\,a^4\,c^3\,\sqrt {1-a^2\,x^2}}{15\,x}+\frac {a^5\,c^3\,\mathrm {atan}\left (\sqrt {1-a^2\,x^2}\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{4} \] Input:

int(((c - a*c*x)^3*(a*x + 1))/(x^6*(1 - a^2*x^2)^(1/2)),x)
 

Output:

(a^5*c^3*atan((1 - a^2*x^2)^(1/2)*1i)*1i)/4 - (c^3*(1 - a^2*x^2)^(1/2))/(5 
*x^5) + (a*c^3*(1 - a^2*x^2)^(1/2))/(2*x^4) - (4*a^2*c^3*(1 - a^2*x^2)^(1/ 
2))/(15*x^3) - (a^3*c^3*(1 - a^2*x^2)^(1/2))/(4*x^2) + (7*a^4*c^3*(1 - a^2 
*x^2)^(1/2))/(15*x)
 

Reduce [B] (verification not implemented)

Time = 0.16 (sec) , antiderivative size = 110, normalized size of antiderivative = 0.85 \[ \int \frac {e^{\text {arctanh}(a x)} (c-a c x)^3}{x^6} \, dx=\frac {c^{3} \left (28 \sqrt {-a^{2} x^{2}+1}\, a^{4} x^{4}-15 \sqrt {-a^{2} x^{2}+1}\, a^{3} x^{3}-16 \sqrt {-a^{2} x^{2}+1}\, a^{2} x^{2}+30 \sqrt {-a^{2} x^{2}+1}\, a x -12 \sqrt {-a^{2} x^{2}+1}+15 \,\mathrm {log}\left (\tan \left (\frac {\mathit {asin} \left (a x \right )}{2}\right )\right ) a^{5} x^{5}\right )}{60 x^{5}} \] Input:

int((a*x+1)/(-a^2*x^2+1)^(1/2)*(-a*c*x+c)^3/x^6,x)
 

Output:

(c**3*(28*sqrt( - a**2*x**2 + 1)*a**4*x**4 - 15*sqrt( - a**2*x**2 + 1)*a** 
3*x**3 - 16*sqrt( - a**2*x**2 + 1)*a**2*x**2 + 30*sqrt( - a**2*x**2 + 1)*a 
*x - 12*sqrt( - a**2*x**2 + 1) + 15*log(tan(asin(a*x)/2))*a**5*x**5))/(60* 
x**5)