Integrand size = 23, antiderivative size = 164 \[ \int \frac {e^{3 \text {arctanh}(a x)} \sqrt {c-a c x}}{x^3} \, dx=-\frac {c \sqrt {1-a^2 x^2}}{2 x^2 \sqrt {c-a c x}}-\frac {9 a c \sqrt {1-a^2 x^2}}{4 x \sqrt {c-a c x}}-\frac {23}{4} a^2 \sqrt {c} \text {arctanh}\left (\frac {\sqrt {c} \sqrt {1-a^2 x^2}}{\sqrt {c-a c x}}\right )+4 \sqrt {2} a^2 \sqrt {c} \text {arctanh}\left (\frac {\sqrt {c} \sqrt {1-a^2 x^2}}{\sqrt {2} \sqrt {c-a c x}}\right ) \] Output:
-1/2*c*(-a^2*x^2+1)^(1/2)/x^2/(-a*c*x+c)^(1/2)-9/4*a*c*(-a^2*x^2+1)^(1/2)/ x/(-a*c*x+c)^(1/2)-23/4*a^2*c^(1/2)*arctanh(c^(1/2)*(-a^2*x^2+1)^(1/2)/(-a *c*x+c)^(1/2))+4*2^(1/2)*a^2*c^(1/2)*arctanh(1/2*c^(1/2)*(-a^2*x^2+1)^(1/2 )*2^(1/2)/(-a*c*x+c)^(1/2))
Time = 0.08 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.56 \[ \int \frac {e^{3 \text {arctanh}(a x)} \sqrt {c-a c x}}{x^3} \, dx=-\frac {\sqrt {c-a c x} \left (\sqrt {1+a x} (2+9 a x)+23 a^2 x^2 \text {arctanh}\left (\sqrt {1+a x}\right )-16 \sqrt {2} a^2 x^2 \text {arctanh}\left (\frac {\sqrt {1+a x}}{\sqrt {2}}\right )\right )}{4 x^2 \sqrt {1-a x}} \] Input:
Integrate[(E^(3*ArcTanh[a*x])*Sqrt[c - a*c*x])/x^3,x]
Output:
-1/4*(Sqrt[c - a*c*x]*(Sqrt[1 + a*x]*(2 + 9*a*x) + 23*a^2*x^2*ArcTanh[Sqrt [1 + a*x]] - 16*Sqrt[2]*a^2*x^2*ArcTanh[Sqrt[1 + a*x]/Sqrt[2]]))/(x^2*Sqrt [1 - a*x])
Time = 0.59 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.61, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {6680, 37, 109, 27, 168, 27, 174, 73, 219, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {e^{3 \text {arctanh}(a x)} \sqrt {c-a c x}}{x^3} \, dx\) |
\(\Big \downarrow \) 6680 |
\(\displaystyle \int \frac {(a x+1)^{3/2} \sqrt {c-a c x}}{x^3 (1-a x)^{3/2}}dx\) |
\(\Big \downarrow \) 37 |
\(\displaystyle \frac {\sqrt {c-a c x} \int \frac {(a x+1)^{3/2}}{x^3 (1-a x)}dx}{\sqrt {1-a x}}\) |
\(\Big \downarrow \) 109 |
\(\displaystyle \frac {\sqrt {c-a c x} \left (-\frac {1}{2} \int -\frac {a (7 a x+9)}{2 x^2 (1-a x) \sqrt {a x+1}}dx-\frac {\sqrt {a x+1}}{2 x^2}\right )}{\sqrt {1-a x}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\sqrt {c-a c x} \left (\frac {1}{4} a \int \frac {7 a x+9}{x^2 (1-a x) \sqrt {a x+1}}dx-\frac {\sqrt {a x+1}}{2 x^2}\right )}{\sqrt {1-a x}}\) |
\(\Big \downarrow \) 168 |
\(\displaystyle \frac {\sqrt {c-a c x} \left (\frac {1}{4} a \left (-\int -\frac {a (9 a x+23)}{2 x (1-a x) \sqrt {a x+1}}dx-\frac {9 \sqrt {a x+1}}{x}\right )-\frac {\sqrt {a x+1}}{2 x^2}\right )}{\sqrt {1-a x}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\sqrt {c-a c x} \left (\frac {1}{4} a \left (\frac {1}{2} a \int \frac {9 a x+23}{x (1-a x) \sqrt {a x+1}}dx-\frac {9 \sqrt {a x+1}}{x}\right )-\frac {\sqrt {a x+1}}{2 x^2}\right )}{\sqrt {1-a x}}\) |
\(\Big \downarrow \) 174 |
\(\displaystyle \frac {\sqrt {c-a c x} \left (\frac {1}{4} a \left (\frac {1}{2} a \left (23 \int \frac {1}{x \sqrt {a x+1}}dx+32 a \int \frac {1}{(1-a x) \sqrt {a x+1}}dx\right )-\frac {9 \sqrt {a x+1}}{x}\right )-\frac {\sqrt {a x+1}}{2 x^2}\right )}{\sqrt {1-a x}}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {\sqrt {c-a c x} \left (\frac {1}{4} a \left (\frac {1}{2} a \left (64 \int \frac {1}{1-a x}d\sqrt {a x+1}+\frac {46 \int \frac {1}{\frac {a x+1}{a}-\frac {1}{a}}d\sqrt {a x+1}}{a}\right )-\frac {9 \sqrt {a x+1}}{x}\right )-\frac {\sqrt {a x+1}}{2 x^2}\right )}{\sqrt {1-a x}}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle \frac {\sqrt {c-a c x} \left (\frac {1}{4} a \left (\frac {1}{2} a \left (\frac {46 \int \frac {1}{\frac {a x+1}{a}-\frac {1}{a}}d\sqrt {a x+1}}{a}+32 \sqrt {2} \text {arctanh}\left (\frac {\sqrt {a x+1}}{\sqrt {2}}\right )\right )-\frac {9 \sqrt {a x+1}}{x}\right )-\frac {\sqrt {a x+1}}{2 x^2}\right )}{\sqrt {1-a x}}\) |
\(\Big \downarrow \) 221 |
\(\displaystyle \frac {\left (\frac {1}{4} a \left (\frac {1}{2} a \left (32 \sqrt {2} \text {arctanh}\left (\frac {\sqrt {a x+1}}{\sqrt {2}}\right )-46 \text {arctanh}\left (\sqrt {a x+1}\right )\right )-\frac {9 \sqrt {a x+1}}{x}\right )-\frac {\sqrt {a x+1}}{2 x^2}\right ) \sqrt {c-a c x}}{\sqrt {1-a x}}\) |
Input:
Int[(E^(3*ArcTanh[a*x])*Sqrt[c - a*c*x])/x^3,x]
Output:
(Sqrt[c - a*c*x]*(-1/2*Sqrt[1 + a*x]/x^2 + (a*((-9*Sqrt[1 + a*x])/x + (a*( -46*ArcTanh[Sqrt[1 + a*x]] + 32*Sqrt[2]*ArcTanh[Sqrt[1 + a*x]/Sqrt[2]]))/2 ))/4))/Sqrt[1 - a*x]
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[(u_.)*((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> S imp[(a + b*x)^m/(c + d*x)^m Int[u*(c + d*x)^(m + n), x], x] /; FreeQ[{a, b, c, d, m, n}, x] && EqQ[b*c - a*d, 0] && !SimplerQ[a + b*x, c + d*x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[(b*c - a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*((e + f *x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] + Simp[1/(b*(b*e - a*f)*(m + 1)) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + S imp[1/((m + 1)*(b*c - a*d)*(b*e - a*f)) Int[(a + b*x)^(m + 1)*(c + d*x)^n *(e + f*x)^p*Simp[(a*d*f*g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a* h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && ILtQ[m, -1]
Int[(((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/(((a_.) + (b_.)*(x_))* ((c_.) + (d_.)*(x_))), x_] :> Simp[(b*g - a*h)/(b*c - a*d) Int[(e + f*x)^ p/(a + b*x), x], x] - Simp[(d*g - c*h)/(b*c - a*d) Int[(e + f*x)^p/(c + d *x), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_))^(p_.), x_Symbol ] :> Int[u*(c + d*x)^p*((1 + a*x)^(n/2)/(1 - a*x)^(n/2)), x] /; FreeQ[{a, c , d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] && !(IntegerQ[p] || GtQ[c, 0])
Time = 0.14 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.80
method | result | size |
default | \(-\frac {\sqrt {-a^{2} x^{2}+1}\, \sqrt {-c \left (a x -1\right )}\, \left (16 \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c \left (a x +1\right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) a^{2} c \,x^{2}-23 c \,\operatorname {arctanh}\left (\frac {\sqrt {c \left (a x +1\right )}}{\sqrt {c}}\right ) a^{2} x^{2}-9 a x \sqrt {c \left (a x +1\right )}\, \sqrt {c}-2 \sqrt {c \left (a x +1\right )}\, \sqrt {c}\right )}{4 \sqrt {c}\, \left (a x -1\right ) \sqrt {c \left (a x +1\right )}\, x^{2}}\) | \(131\) |
risch | \(\frac {\left (9 a^{2} x^{2}+11 a x +2\right ) \sqrt {-\frac {\left (-a^{2} x^{2}+1\right ) c}{a x -1}}\, \left (a x -1\right ) c}{4 x^{2} \sqrt {c \left (a x +1\right )}\, \sqrt {-a^{2} x^{2}+1}\, \sqrt {-c \left (a x -1\right )}}-\frac {a^{2} \left (\frac {32 \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {a c x +c}\, \sqrt {2}}{2 \sqrt {c}}\right )}{\sqrt {c}}-\frac {46 \,\operatorname {arctanh}\left (\frac {\sqrt {a c x +c}}{\sqrt {c}}\right )}{\sqrt {c}}\right ) \sqrt {-\frac {\left (-a^{2} x^{2}+1\right ) c}{a x -1}}\, \left (a x -1\right ) c}{8 \sqrt {-a^{2} x^{2}+1}\, \sqrt {-c \left (a x -1\right )}}\) | \(179\) |
Input:
int((a*x+1)^3/(-a^2*x^2+1)^(3/2)*(-a*c*x+c)^(1/2)/x^3,x,method=_RETURNVERB OSE)
Output:
-1/4*(-a^2*x^2+1)^(1/2)*(-c*(a*x-1))^(1/2)*(16*2^(1/2)*arctanh(1/2*(c*(a*x +1))^(1/2)*2^(1/2)/c^(1/2))*a^2*c*x^2-23*c*arctanh((c*(a*x+1))^(1/2)/c^(1/ 2))*a^2*x^2-9*a*x*(c*(a*x+1))^(1/2)*c^(1/2)-2*(c*(a*x+1))^(1/2)*c^(1/2))/c ^(1/2)/(a*x-1)/(c*(a*x+1))^(1/2)/x^2
Time = 0.15 (sec) , antiderivative size = 384, normalized size of antiderivative = 2.34 \[ \int \frac {e^{3 \text {arctanh}(a x)} \sqrt {c-a c x}}{x^3} \, dx=\left [\frac {16 \, \sqrt {2} {\left (a^{3} x^{3} - a^{2} x^{2}\right )} \sqrt {c} \log \left (-\frac {a^{2} c x^{2} + 2 \, a c x - 2 \, \sqrt {2} \sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c} \sqrt {c} - 3 \, c}{a^{2} x^{2} - 2 \, a x + 1}\right ) + 23 \, {\left (a^{3} x^{3} - a^{2} x^{2}\right )} \sqrt {c} \log \left (-\frac {a^{2} c x^{2} + a c x + 2 \, \sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c} \sqrt {c} - 2 \, c}{a x^{2} - x}\right ) + 2 \, \sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c} {\left (9 \, a x + 2\right )}}{8 \, {\left (a x^{3} - x^{2}\right )}}, \frac {16 \, \sqrt {2} {\left (a^{3} x^{3} - a^{2} x^{2}\right )} \sqrt {-c} \arctan \left (\frac {\sqrt {2} \sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c} \sqrt {-c}}{2 \, {\left (a c x - c\right )}}\right ) - 23 \, {\left (a^{3} x^{3} - a^{2} x^{2}\right )} \sqrt {-c} \arctan \left (\frac {\sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c} \sqrt {-c}}{a c x - c}\right ) + \sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c} {\left (9 \, a x + 2\right )}}{4 \, {\left (a x^{3} - x^{2}\right )}}\right ] \] Input:
integrate((a*x+1)^3/(-a^2*x^2+1)^(3/2)*(-a*c*x+c)^(1/2)/x^3,x, algorithm=" fricas")
Output:
[1/8*(16*sqrt(2)*(a^3*x^3 - a^2*x^2)*sqrt(c)*log(-(a^2*c*x^2 + 2*a*c*x - 2 *sqrt(2)*sqrt(-a^2*x^2 + 1)*sqrt(-a*c*x + c)*sqrt(c) - 3*c)/(a^2*x^2 - 2*a *x + 1)) + 23*(a^3*x^3 - a^2*x^2)*sqrt(c)*log(-(a^2*c*x^2 + a*c*x + 2*sqrt (-a^2*x^2 + 1)*sqrt(-a*c*x + c)*sqrt(c) - 2*c)/(a*x^2 - x)) + 2*sqrt(-a^2* x^2 + 1)*sqrt(-a*c*x + c)*(9*a*x + 2))/(a*x^3 - x^2), 1/4*(16*sqrt(2)*(a^3 *x^3 - a^2*x^2)*sqrt(-c)*arctan(1/2*sqrt(2)*sqrt(-a^2*x^2 + 1)*sqrt(-a*c*x + c)*sqrt(-c)/(a*c*x - c)) - 23*(a^3*x^3 - a^2*x^2)*sqrt(-c)*arctan(sqrt( -a^2*x^2 + 1)*sqrt(-a*c*x + c)*sqrt(-c)/(a*c*x - c)) + sqrt(-a^2*x^2 + 1)* sqrt(-a*c*x + c)*(9*a*x + 2))/(a*x^3 - x^2)]
\[ \int \frac {e^{3 \text {arctanh}(a x)} \sqrt {c-a c x}}{x^3} \, dx=\int \frac {\sqrt {- c \left (a x - 1\right )} \left (a x + 1\right )^{3}}{x^{3} \left (- \left (a x - 1\right ) \left (a x + 1\right )\right )^{\frac {3}{2}}}\, dx \] Input:
integrate((a*x+1)**3/(-a**2*x**2+1)**(3/2)*(-a*c*x+c)**(1/2)/x**3,x)
Output:
Integral(sqrt(-c*(a*x - 1))*(a*x + 1)**3/(x**3*(-(a*x - 1)*(a*x + 1))**(3/ 2)), x)
\[ \int \frac {e^{3 \text {arctanh}(a x)} \sqrt {c-a c x}}{x^3} \, dx=\int { \frac {\sqrt {-a c x + c} {\left (a x + 1\right )}^{3}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}} x^{3}} \,d x } \] Input:
integrate((a*x+1)^3/(-a^2*x^2+1)^(3/2)*(-a*c*x+c)^(1/2)/x^3,x, algorithm=" maxima")
Output:
integrate(sqrt(-a*c*x + c)*(a*x + 1)^3/((-a^2*x^2 + 1)^(3/2)*x^3), x)
Exception generated. \[ \int \frac {e^{3 \text {arctanh}(a x)} \sqrt {c-a c x}}{x^3} \, dx=\text {Exception raised: TypeError} \] Input:
integrate((a*x+1)^3/(-a^2*x^2+1)^(3/2)*(-a*c*x+c)^(1/2)/x^3,x, algorithm=" giac")
Output:
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value
Timed out. \[ \int \frac {e^{3 \text {arctanh}(a x)} \sqrt {c-a c x}}{x^3} \, dx=\int \frac {\sqrt {c-a\,c\,x}\,{\left (a\,x+1\right )}^3}{x^3\,{\left (1-a^2\,x^2\right )}^{3/2}} \,d x \] Input:
int(((c - a*c*x)^(1/2)*(a*x + 1)^3)/(x^3*(1 - a^2*x^2)^(3/2)),x)
Output:
int(((c - a*c*x)^(1/2)*(a*x + 1)^3)/(x^3*(1 - a^2*x^2)^(3/2)), x)
Time = 0.17 (sec) , antiderivative size = 183, normalized size of antiderivative = 1.12 \[ \int \frac {e^{3 \text {arctanh}(a x)} \sqrt {c-a c x}}{x^3} \, dx=\frac {\sqrt {c}\, \left (-18 \sqrt {a x +1}\, a x -4 \sqrt {a x +1}-32 \sqrt {2}\, \mathrm {log}\left (\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )\right ) a^{2} x^{2}+22 \sqrt {2}\, a^{2} x^{2}-23 \,\mathrm {log}\left (-\sqrt {2}+\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )-1\right ) a^{2} x^{2}+23 \,\mathrm {log}\left (-\sqrt {2}+\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )+1\right ) a^{2} x^{2}+23 \,\mathrm {log}\left (\sqrt {2}+\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )-1\right ) a^{2} x^{2}-23 \,\mathrm {log}\left (\sqrt {2}+\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )+1\right ) a^{2} x^{2}\right )}{8 x^{2}} \] Input:
int((a*x+1)^3/(-a^2*x^2+1)^(3/2)*(-a*c*x+c)^(1/2)/x^3,x)
Output:
(sqrt(c)*( - 18*sqrt(a*x + 1)*a*x - 4*sqrt(a*x + 1) - 32*sqrt(2)*log(tan(a sin(sqrt( - a*x + 1)/sqrt(2))/2))*a**2*x**2 + 22*sqrt(2)*a**2*x**2 - 23*lo g( - sqrt(2) + tan(asin(sqrt( - a*x + 1)/sqrt(2))/2) - 1)*a**2*x**2 + 23*l og( - sqrt(2) + tan(asin(sqrt( - a*x + 1)/sqrt(2))/2) + 1)*a**2*x**2 + 23* log(sqrt(2) + tan(asin(sqrt( - a*x + 1)/sqrt(2))/2) - 1)*a**2*x**2 - 23*lo g(sqrt(2) + tan(asin(sqrt( - a*x + 1)/sqrt(2))/2) + 1)*a**2*x**2))/(8*x**2 )