Integrand size = 27, antiderivative size = 121 \[ \int \frac {e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}}}{x^5} \, dx=-4 a^4 \sqrt {c-\frac {c}{a x}}+\frac {14 a^4 \left (c-\frac {c}{a x}\right )^{3/2}}{3 c}-\frac {18 a^4 \left (c-\frac {c}{a x}\right )^{5/2}}{5 c^2}+\frac {10 a^4 \left (c-\frac {c}{a x}\right )^{7/2}}{7 c^3}-\frac {2 a^4 \left (c-\frac {c}{a x}\right )^{9/2}}{9 c^4} \] Output:
-4*a^4*(c-c/a/x)^(1/2)+14/3*a^4*(c-c/a/x)^(3/2)/c-18/5*a^4*(c-c/a/x)^(5/2) /c^2+10/7*a^4*(c-c/a/x)^(7/2)/c^3-2/9*a^4*(c-c/a/x)^(9/2)/c^4
Time = 0.08 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.43 \[ \int \frac {e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}}}{x^5} \, dx=-\frac {2 \sqrt {c-\frac {c}{a x}} \left (35+85 a x+102 a^2 x^2+136 a^3 x^3+272 a^4 x^4\right )}{315 x^4} \] Input:
Integrate[(E^(2*ArcTanh[a*x])*Sqrt[c - c/(a*x)])/x^5,x]
Output:
(-2*Sqrt[c - c/(a*x)]*(35 + 85*a*x + 102*a^2*x^2 + 136*a^3*x^3 + 272*a^4*x ^4))/(315*x^4)
Time = 0.90 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.07, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {6683, 1070, 281, 948, 86, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}}}{x^5} \, dx\) |
\(\Big \downarrow \) 6683 |
\(\displaystyle \int \frac {(a x+1) \sqrt {c-\frac {c}{a x}}}{x^5 (1-a x)}dx\) |
\(\Big \downarrow \) 1070 |
\(\displaystyle \int \frac {\left (a+\frac {1}{x}\right ) \sqrt {c-\frac {c}{a x}}}{x^5 \left (\frac {1}{x}-a\right )}dx\) |
\(\Big \downarrow \) 281 |
\(\displaystyle -\frac {c \int \frac {a+\frac {1}{x}}{\sqrt {c-\frac {c}{a x}} x^5}dx}{a}\) |
\(\Big \downarrow \) 948 |
\(\displaystyle \frac {c \int \frac {a+\frac {1}{x}}{\sqrt {c-\frac {c}{a x}} x^3}d\frac {1}{x}}{a}\) |
\(\Big \downarrow \) 86 |
\(\displaystyle \frac {c \int \left (\frac {\left (c-\frac {c}{a x}\right )^{7/2} a^4}{c^4}-\frac {5 \left (c-\frac {c}{a x}\right )^{5/2} a^4}{c^3}+\frac {9 \left (c-\frac {c}{a x}\right )^{3/2} a^4}{c^2}-\frac {7 \sqrt {c-\frac {c}{a x}} a^4}{c}+\frac {2 a^4}{\sqrt {c-\frac {c}{a x}}}\right )d\frac {1}{x}}{a}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {c \left (-\frac {2 a^5 \left (c-\frac {c}{a x}\right )^{9/2}}{9 c^5}+\frac {10 a^5 \left (c-\frac {c}{a x}\right )^{7/2}}{7 c^4}-\frac {18 a^5 \left (c-\frac {c}{a x}\right )^{5/2}}{5 c^3}+\frac {14 a^5 \left (c-\frac {c}{a x}\right )^{3/2}}{3 c^2}-\frac {4 a^5 \sqrt {c-\frac {c}{a x}}}{c}\right )}{a}\) |
Input:
Int[(E^(2*ArcTanh[a*x])*Sqrt[c - c/(a*x)])/x^5,x]
Output:
(c*((-4*a^5*Sqrt[c - c/(a*x)])/c + (14*a^5*(c - c/(a*x))^(3/2))/(3*c^2) - (18*a^5*(c - c/(a*x))^(5/2))/(5*c^3) + (10*a^5*(c - c/(a*x))^(7/2))/(7*c^4 ) - (2*a^5*(c - c/(a*x))^(9/2))/(9*c^5)))/a
Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_ .), x_] :> Int[ExpandIntegrand[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && ((ILtQ[n, 0] && ILtQ[p, 0]) || EqQ[p, 1 ] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))
Int[(u_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_ Symbol] :> Simp[(b/d)^p Int[u*(c + d*x^n)^(p + q), x], x] /; FreeQ[{a, b, c, d, n, p, q}, x] && EqQ[b*c - a*d, 0] && IntegerQ[p] && !(IntegerQ[q] & & SimplerQ[a + b*x^n, c + d*x^n])
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_. ), x_Symbol] :> Simp[1/n Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^ p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] && NeQ [b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]
Int[(x_)^(m_.)*((c_) + (d_.)*(x_)^(mn_.))^(q_.)*((a_.) + (b_.)*(x_)^(n_.))^ (p_.)*((e_) + (f_.)*(x_)^(n_.))^(r_.), x_Symbol] :> Int[x^(m + n*(p + r))*( b + a/x^n)^p*(c + d/x^n)^q*(f + e/x^n)^r, x] /; FreeQ[{a, b, c, d, e, f, m, n, q}, x] && EqQ[mn, -n] && IntegerQ[p] && IntegerQ[r]
Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*(u_.)*((c_) + (d_.)/(x_))^(p_), x_Symbol] :> Int[u*(c + d/x)^p*((1 + a*x)^(n/2)/(1 - a*x)^(n/2)), x] /; FreeQ[{a, c, d, p}, x] && EqQ[c^2 - a^2*d^2, 0] && !IntegerQ[p] && IntegerQ[n/2] && !G tQ[c, 0]
Time = 0.10 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.42
method | result | size |
gosper | \(-\frac {2 \sqrt {\frac {c \left (a x -1\right )}{a x}}\, \left (272 a^{4} x^{4}+136 a^{3} x^{3}+102 a^{2} x^{2}+85 a x +35\right )}{315 x^{4}}\) | \(51\) |
trager | \(-\frac {2 \left (272 a^{4} x^{4}+136 a^{3} x^{3}+102 a^{2} x^{2}+85 a x +35\right ) \sqrt {-\frac {-a c x +c}{a x}}}{315 x^{4}}\) | \(53\) |
risch | \(-\frac {2 \sqrt {\frac {c \left (a x -1\right )}{a x}}\, \left (272 a^{5} x^{5}-136 a^{4} x^{4}-34 a^{3} x^{3}-17 a^{2} x^{2}-50 a x -35\right )}{315 \left (a x -1\right ) x^{4}}\) | \(66\) |
orering | \(\frac {2 \left (272 a^{4} x^{4}+136 a^{3} x^{3}+102 a^{2} x^{2}+85 a x +35\right ) \left (a x -1\right ) \left (a x +1\right ) \sqrt {c -\frac {c}{a x}}}{315 x^{4} \left (-a^{2} x^{2}+1\right )}\) | \(71\) |
default | \(-\frac {\sqrt {\frac {c \left (a x -1\right )}{a x}}\, \left (630 \sqrt {x \left (a x -1\right )}\, a^{\frac {11}{2}} x^{6}+630 \sqrt {a \,x^{2}-x}\, a^{\frac {11}{2}} x^{6}-1260 \left (a \,x^{2}-x \right )^{\frac {3}{2}} a^{\frac {9}{2}} x^{4}-315 \ln \left (\frac {2 \sqrt {a \,x^{2}-x}\, \sqrt {a}+2 a x -1}{2 \sqrt {a}}\right ) a^{5} x^{6}+315 \ln \left (\frac {2 \sqrt {x \left (a x -1\right )}\, \sqrt {a}+2 a x -1}{2 \sqrt {a}}\right ) a^{5} x^{6}-716 \left (a \,x^{2}-x \right )^{\frac {3}{2}} a^{\frac {7}{2}} x^{3}-444 a^{\frac {5}{2}} \left (a \,x^{2}-x \right )^{\frac {3}{2}} x^{2}-240 a^{\frac {3}{2}} \left (a \,x^{2}-x \right )^{\frac {3}{2}} x -70 \left (a \,x^{2}-x \right )^{\frac {3}{2}} \sqrt {a}\right )}{315 x^{5} \sqrt {x \left (a x -1\right )}\, \sqrt {a}}\) | \(230\) |
Input:
int((a*x+1)^2/(-a^2*x^2+1)*(c-c/a/x)^(1/2)/x^5,x,method=_RETURNVERBOSE)
Output:
-2/315*(c*(a*x-1)/a/x)^(1/2)*(272*a^4*x^4+136*a^3*x^3+102*a^2*x^2+85*a*x+3 5)/x^4
Time = 0.07 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.43 \[ \int \frac {e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}}}{x^5} \, dx=-\frac {2 \, {\left (272 \, a^{4} x^{4} + 136 \, a^{3} x^{3} + 102 \, a^{2} x^{2} + 85 \, a x + 35\right )} \sqrt {\frac {a c x - c}{a x}}}{315 \, x^{4}} \] Input:
integrate((a*x+1)^2/(-a^2*x^2+1)*(c-c/a/x)^(1/2)/x^5,x, algorithm="fricas" )
Output:
-2/315*(272*a^4*x^4 + 136*a^3*x^3 + 102*a^2*x^2 + 85*a*x + 35)*sqrt((a*c*x - c)/(a*x))/x^4
\[ \int \frac {e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}}}{x^5} \, dx=- \int \frac {\sqrt {c - \frac {c}{a x}}}{a x^{6} - x^{5}}\, dx - \int \frac {a x \sqrt {c - \frac {c}{a x}}}{a x^{6} - x^{5}}\, dx \] Input:
integrate((a*x+1)**2/(-a**2*x**2+1)*(c-c/a/x)**(1/2)/x**5,x)
Output:
-Integral(sqrt(c - c/(a*x))/(a*x**6 - x**5), x) - Integral(a*x*sqrt(c - c/ (a*x))/(a*x**6 - x**5), x)
\[ \int \frac {e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}}}{x^5} \, dx=\int { -\frac {{\left (a x + 1\right )}^{2} \sqrt {c - \frac {c}{a x}}}{{\left (a^{2} x^{2} - 1\right )} x^{5}} \,d x } \] Input:
integrate((a*x+1)^2/(-a^2*x^2+1)*(c-c/a/x)^(1/2)/x^5,x, algorithm="maxima" )
Output:
-integrate((a*x + 1)^2*sqrt(c - c/(a*x))/((a^2*x^2 - 1)*x^5), x)
Leaf count of result is larger than twice the leaf count of optimal. 243 vs. \(2 (103) = 206\).
Time = 0.29 (sec) , antiderivative size = 243, normalized size of antiderivative = 2.01 \[ \int \frac {e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}}}{x^5} \, dx=-\frac {2 \, {\left (630 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - a c x}\right )}^{5} a^{4} c^{\frac {5}{2}} {\left | a \right |} + 252 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - a c x}\right )}^{4} a^{5} c^{3} - 1365 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - a c x}\right )}^{3} a^{4} c^{\frac {7}{2}} {\left | a \right |} + 1035 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - a c x}\right )}^{2} a^{5} c^{4} - 315 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - a c x}\right )} a^{4} c^{\frac {9}{2}} {\left | a \right |} + 35 \, a^{5} c^{5}\right )}}{315 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - a c x}\right )}^{9} {\left | a \right |} \mathrm {sgn}\left (x\right )} \] Input:
integrate((a*x+1)^2/(-a^2*x^2+1)*(c-c/a/x)^(1/2)/x^5,x, algorithm="giac")
Output:
-2/315*(630*(sqrt(a^2*c)*x - sqrt(a^2*c*x^2 - a*c*x))^5*a^4*c^(5/2)*abs(a) + 252*(sqrt(a^2*c)*x - sqrt(a^2*c*x^2 - a*c*x))^4*a^5*c^3 - 1365*(sqrt(a^ 2*c)*x - sqrt(a^2*c*x^2 - a*c*x))^3*a^4*c^(7/2)*abs(a) + 1035*(sqrt(a^2*c) *x - sqrt(a^2*c*x^2 - a*c*x))^2*a^5*c^4 - 315*(sqrt(a^2*c)*x - sqrt(a^2*c* x^2 - a*c*x))*a^4*c^(9/2)*abs(a) + 35*a^5*c^5)/((sqrt(a^2*c)*x - sqrt(a^2* c*x^2 - a*c*x))^9*abs(a)*sgn(x))
Time = 22.94 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.81 \[ \int \frac {e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}}}{x^5} \, dx=-\frac {544\,a^4\,\sqrt {c-\frac {c}{a\,x}}}{315}-\frac {2\,\sqrt {c-\frac {c}{a\,x}}}{9\,x^4}-\frac {34\,a\,\sqrt {c-\frac {c}{a\,x}}}{63\,x^3}-\frac {68\,a^2\,\sqrt {c-\frac {c}{a\,x}}}{105\,x^2}-\frac {272\,a^3\,\sqrt {c-\frac {c}{a\,x}}}{315\,x} \] Input:
int(-((c - c/(a*x))^(1/2)*(a*x + 1)^2)/(x^5*(a^2*x^2 - 1)),x)
Output:
- (544*a^4*(c - c/(a*x))^(1/2))/315 - (2*(c - c/(a*x))^(1/2))/(9*x^4) - (3 4*a*(c - c/(a*x))^(1/2))/(63*x^3) - (68*a^2*(c - c/(a*x))^(1/2))/(105*x^2) - (272*a^3*(c - c/(a*x))^(1/2))/(315*x)
Time = 0.15 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.82 \[ \int \frac {e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a x}}}{x^5} \, dx=\frac {2 \sqrt {c}\, \left (-272 \sqrt {x}\, \sqrt {a}\, \sqrt {a x -1}\, a^{4} x^{4}-136 \sqrt {x}\, \sqrt {a}\, \sqrt {a x -1}\, a^{3} x^{3}-102 \sqrt {x}\, \sqrt {a}\, \sqrt {a x -1}\, a^{2} x^{2}-85 \sqrt {x}\, \sqrt {a}\, \sqrt {a x -1}\, a x -35 \sqrt {x}\, \sqrt {a}\, \sqrt {a x -1}+272 a^{5} x^{5}\right )}{315 a \,x^{5}} \] Input:
int((a*x+1)^2/(-a^2*x^2+1)*(c-c/a/x)^(1/2)/x^5,x)
Output:
(2*sqrt(c)*( - 272*sqrt(x)*sqrt(a)*sqrt(a*x - 1)*a**4*x**4 - 136*sqrt(x)*s qrt(a)*sqrt(a*x - 1)*a**3*x**3 - 102*sqrt(x)*sqrt(a)*sqrt(a*x - 1)*a**2*x* *2 - 85*sqrt(x)*sqrt(a)*sqrt(a*x - 1)*a*x - 35*sqrt(x)*sqrt(a)*sqrt(a*x - 1) + 272*a**5*x**5))/(315*a*x**5)