Integrand size = 10, antiderivative size = 68 \[ \int e^{3 \text {arctanh}(a+b x)} \, dx=\frac {3 \sqrt {1-a-b x} \sqrt {1+a+b x}}{b}+\frac {2 (1+a+b x)^{3/2}}{b \sqrt {1-a-b x}}-\frac {3 \arcsin (a+b x)}{b} \] Output:
3*(-b*x-a+1)^(1/2)*(b*x+a+1)^(1/2)/b+2*(b*x+a+1)^(3/2)/b/(-b*x-a+1)^(1/2)- 3*arcsin(b*x+a)/b
Time = 0.04 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.63 \[ \int e^{3 \text {arctanh}(a+b x)} \, dx=\frac {\left (1-\frac {4}{-1+a+b x}\right ) \sqrt {1-(a+b x)^2}}{b}-\frac {3 \arcsin (a+b x)}{b} \] Input:
Integrate[E^(3*ArcTanh[a + b*x]),x]
Output:
((1 - 4/(-1 + a + b*x))*Sqrt[1 - (a + b*x)^2])/b - (3*ArcSin[a + b*x])/b
Time = 0.41 (sec) , antiderivative size = 84, normalized size of antiderivative = 1.24, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {6711, 57, 60, 62, 1090, 223}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int e^{3 \text {arctanh}(a+b x)} \, dx\) |
\(\Big \downarrow \) 6711 |
\(\displaystyle \int \frac {(a+b x+1)^{3/2}}{(-a-b x+1)^{3/2}}dx\) |
\(\Big \downarrow \) 57 |
\(\displaystyle \frac {2 (a+b x+1)^{3/2}}{b \sqrt {-a-b x+1}}-3 \int \frac {\sqrt {a+b x+1}}{\sqrt {-a-b x+1}}dx\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {2 (a+b x+1)^{3/2}}{b \sqrt {-a-b x+1}}-3 \left (\int \frac {1}{\sqrt {-a-b x+1} \sqrt {a+b x+1}}dx-\frac {\sqrt {-a-b x+1} \sqrt {a+b x+1}}{b}\right )\) |
\(\Big \downarrow \) 62 |
\(\displaystyle \frac {2 (a+b x+1)^{3/2}}{b \sqrt {-a-b x+1}}-3 \left (\int \frac {1}{\sqrt {-b^2 x^2-2 a b x+(1-a) (a+1)}}dx-\frac {\sqrt {-a-b x+1} \sqrt {a+b x+1}}{b}\right )\) |
\(\Big \downarrow \) 1090 |
\(\displaystyle \frac {2 (a+b x+1)^{3/2}}{b \sqrt {-a-b x+1}}-3 \left (-\frac {\int \frac {1}{\sqrt {1-\frac {\left (-2 x b^2-2 a b\right )^2}{4 b^2}}}d\left (-2 x b^2-2 a b\right )}{2 b^2}-\frac {\sqrt {-a-b x+1} \sqrt {a+b x+1}}{b}\right )\) |
\(\Big \downarrow \) 223 |
\(\displaystyle \frac {2 (a+b x+1)^{3/2}}{b \sqrt {-a-b x+1}}-3 \left (-\frac {\arcsin \left (\frac {-2 a b-2 b^2 x}{2 b}\right )}{b}-\frac {\sqrt {-a-b x+1} \sqrt {a+b x+1}}{b}\right )\) |
Input:
Int[E^(3*ArcTanh[a + b*x]),x]
Output:
(2*(1 + a + b*x)^(3/2))/(b*Sqrt[1 - a - b*x]) - 3*(-((Sqrt[1 - a - b*x]*Sq rt[1 + a + b*x])/b) - ArcSin[(-2*a*b - 2*b^2*x)/(2*b)]/b)
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] & & GtQ[n, 0] && LtQ[m, -1] && !(IntegerQ[n] && !IntegerQ[m]) && !(ILeQ[m + n + 2, 0] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c , d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Int[ 1/Sqrt[a*c - b*(a - c)*x - b^2*x^2], x] /; FreeQ[{a, b, c, d}, x] && EqQ[b + d, 0] && GtQ[a + c, 0]
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt [a])]/Rt[-b, 2], x] /; FreeQ[{a, b}, x] && GtQ[a, 0] && NegQ[b]
Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[1/(2*c*(-4* (c/(b^2 - 4*a*c)))^p) Subst[Int[Simp[1 - x^2/(b^2 - 4*a*c), x]^p, x], x, b + 2*c*x], x] /; FreeQ[{a, b, c, p}, x] && GtQ[4*a - b^2/c, 0]
Int[E^(ArcTanh[(c_.)*((a_) + (b_.)*(x_))]*(n_.)), x_Symbol] :> Int[(1 + a*c + b*c*x)^(n/2)/(1 - a*c - b*c*x)^(n/2), x] /; FreeQ[{a, b, c, n}, x]
Leaf count of result is larger than twice the leaf count of optimal. \(135\) vs. \(2(60)=120\).
Time = 0.46 (sec) , antiderivative size = 136, normalized size of antiderivative = 2.00
method | result | size |
risch | \(-\frac {b^{2} x^{2}+2 a b x +a^{2}-1}{b \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}-\frac {3 \arctan \left (\frac {\sqrt {b^{2}}\, \left (x +\frac {a}{b}\right )}{\sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}\right )}{\sqrt {b^{2}}}-\frac {4 \sqrt {-\left (x +\frac {-1+a}{b}\right )^{2} b^{2}-2 \left (x +\frac {-1+a}{b}\right ) b}}{b^{2} \left (x +\frac {-1+a}{b}\right )}\) | \(136\) |
default | \(\frac {2 \left (a +1\right )^{3} \left (-2 b^{2} x -2 a b \right )}{\left (-4 b^{2} \left (-a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}+b^{3} \left (-\frac {x^{2}}{b^{2} \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}-\frac {3 a \left (\frac {x}{b^{2} \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}-\frac {a \left (\frac {1}{b^{2} \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}-\frac {2 a \left (-2 b^{2} x -2 a b \right )}{b \left (-4 b^{2} \left (-a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}\right )}{b}-\frac {\arctan \left (\frac {\sqrt {b^{2}}\, \left (x +\frac {a}{b}\right )}{\sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}\right )}{b^{2} \sqrt {b^{2}}}\right )}{b}+\frac {2 \left (-a^{2}+1\right ) \left (\frac {1}{b^{2} \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}-\frac {2 a \left (-2 b^{2} x -2 a b \right )}{b \left (-4 b^{2} \left (-a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}\right )}{b^{2}}\right )+3 \left (a +1\right ) b^{2} \left (\frac {x}{b^{2} \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}-\frac {a \left (\frac {1}{b^{2} \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}-\frac {2 a \left (-2 b^{2} x -2 a b \right )}{b \left (-4 b^{2} \left (-a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}\right )}{b}-\frac {\arctan \left (\frac {\sqrt {b^{2}}\, \left (x +\frac {a}{b}\right )}{\sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}\right )}{b^{2} \sqrt {b^{2}}}\right )+3 \left (a +1\right )^{2} b \left (\frac {1}{b^{2} \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}-\frac {2 a \left (-2 b^{2} x -2 a b \right )}{b \left (-4 b^{2} \left (-a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}\right )\) | \(650\) |
Input:
int((b*x+a+1)^3/(1-(b*x+a)^2)^(3/2),x,method=_RETURNVERBOSE)
Output:
-1/b*(b^2*x^2+2*a*b*x+a^2-1)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-3/(b^2)^(1/2)* arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))-4/b^2/(x+(-1+ a)/b)*(-(x+(-1+a)/b)^2*b^2-2*(x+(-1+a)/b)*b)^(1/2)
Time = 0.10 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.47 \[ \int e^{3 \text {arctanh}(a+b x)} \, dx=\frac {3 \, {\left (b x + a - 1\right )} \arctan \left (\frac {\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left (b x + a\right )}}{b^{2} x^{2} + 2 \, a b x + a^{2} - 1}\right ) + \sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left (b x + a - 5\right )}}{b^{2} x + {\left (a - 1\right )} b} \] Input:
integrate((b*x+a+1)^3/(1-(b*x+a)^2)^(3/2),x, algorithm="fricas")
Output:
(3*(b*x + a - 1)*arctan(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*(b*x + a)/(b^2* x^2 + 2*a*b*x + a^2 - 1)) + sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*(b*x + a - 5))/(b^2*x + (a - 1)*b)
\[ \int e^{3 \text {arctanh}(a+b x)} \, dx=\int \frac {\left (a + b x + 1\right )^{3}}{\left (- \left (a + b x - 1\right ) \left (a + b x + 1\right )\right )^{\frac {3}{2}}}\, dx \] Input:
integrate((b*x+a+1)**3/(1-(b*x+a)**2)**(3/2),x)
Output:
Integral((a + b*x + 1)**3/(-(a + b*x - 1)*(a + b*x + 1))**(3/2), x)
Leaf count of result is larger than twice the leaf count of optimal. 753 vs. \(2 (60) = 120\).
Time = 0.11 (sec) , antiderivative size = 753, normalized size of antiderivative = 11.07 \[ \int e^{3 \text {arctanh}(a+b x)} \, dx =\text {Too large to display} \] Input:
integrate((b*x+a+1)^3/(1-(b*x+a)^2)^(3/2),x, algorithm="maxima")
Output:
-6*a^3*b^2*x/((a^2*b^2 - (a^2 - 1)*b^2)*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1) ) + 5*(a^2 - 1)*a*b^2*x/((a^2*b^2 - (a^2 - 1)*b^2)*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)) - (a^2 - 1)*a^2*b/((a^2*b^2 - (a^2 - 1)*b^2)*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)) + 6*(a*b^2 + b^2)*a^2*x/((a^2*b^2 - (a^2 - 1)*b^2)*sqr t(-b^2*x^2 - 2*a*b*x - a^2 + 1)) - 3*(a^2*b + 2*a*b + b)*a*b*x/((a^2*b^2 - (a^2 - 1)*b^2)*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)) + (a^3 + 3*a^2 + 3*a + 1)*b^2*x/((a^2*b^2 - (a^2 - 1)*b^2)*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)) - b*x^2/sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1) - 3*(a^2*b + 2*a*b + b)*a^2/((a^ 2*b^2 - (a^2 - 1)*b^2)*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)) + (a^3 + 3*a^2 + 3*a + 1)*a*b/((a^2*b^2 - (a^2 - 1)*b^2)*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)) - 3*(a*b^2 + b^2)*(a^2 - 1)*x/((a^2*b^2 - (a^2 - 1)*b^2)*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)) - 3*a*arcsin(-(b^2*x + a*b)/sqrt(a^2*b^2 - (a^2 - 1 )*b^2))/b + 3*(a*b^2 + b^2)*(a^2 - 1)*a/((a^2*b^2 - (a^2 - 1)*b^2)*sqrt(-b ^2*x^2 - 2*a*b*x - a^2 + 1)*b) - 2*(a^2 - 1)/(sqrt(-b^2*x^2 - 2*a*b*x - a^ 2 + 1)*b) + 3*(a*b^2 + b^2)*arcsin(-(b^2*x + a*b)/sqrt(a^2*b^2 - (a^2 - 1) *b^2))/b^3 + 3*(a^2*b + 2*a*b + b)/(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*b^2 )
Time = 0.14 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.37 \[ \int e^{3 \text {arctanh}(a+b x)} \, dx=\frac {3 \, \arcsin \left (-b x - a\right ) \mathrm {sgn}\left (b\right )}{{\left | b \right |}} + \frac {\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{b} + \frac {8}{{\left (\frac {\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b}{b^{2} x + a b} - 1\right )} {\left | b \right |}} \] Input:
integrate((b*x+a+1)^3/(1-(b*x+a)^2)^(3/2),x, algorithm="giac")
Output:
3*arcsin(-b*x - a)*sgn(b)/abs(b) + sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)/b + 8/(((sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)/(b^2*x + a*b) - 1)*abs (b))
Timed out. \[ \int e^{3 \text {arctanh}(a+b x)} \, dx=\int \frac {{\left (a+b\,x+1\right )}^3}{{\left (1-{\left (a+b\,x\right )}^2\right )}^{3/2}} \,d x \] Input:
int((a + b*x + 1)^3/(1 - (a + b*x)^2)^(3/2),x)
Output:
int((a + b*x + 1)^3/(1 - (a + b*x)^2)^(3/2), x)
Time = 0.14 (sec) , antiderivative size = 183, normalized size of antiderivative = 2.69 \[ \int e^{3 \text {arctanh}(a+b x)} \, dx=\frac {-3 \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}\, \mathit {asin} \left (b x +a \right )-3 \mathit {asin} \left (b x +a \right ) a -3 \mathit {asin} \left (b x +a \right ) b x +3 \mathit {asin} \left (b x +a \right )+\sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}\, a +\sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}\, b x -8 \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}-a^{2}-2 a b x +a -b^{2} x^{2}+b x +8}{b \left (\sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}+a +b x -1\right )} \] Input:
int((b*x+a+1)^3/(1-(b*x+a)^2)^(3/2),x)
Output:
( - 3*sqrt( - a**2 - 2*a*b*x - b**2*x**2 + 1)*asin(a + b*x) - 3*asin(a + b *x)*a - 3*asin(a + b*x)*b*x + 3*asin(a + b*x) + sqrt( - a**2 - 2*a*b*x - b **2*x**2 + 1)*a + sqrt( - a**2 - 2*a*b*x - b**2*x**2 + 1)*b*x - 8*sqrt( - a**2 - 2*a*b*x - b**2*x**2 + 1) - a**2 - 2*a*b*x + a - b**2*x**2 + b*x + 8 )/(b*(sqrt( - a**2 - 2*a*b*x - b**2*x**2 + 1) + a + b*x - 1))