Integrand size = 23, antiderivative size = 145 \[ \int \frac {e^{\text {arctanh}(a x)} x^6}{\left (c-a^2 c x^2\right )^2} \, dx=\frac {1+a x}{3 a^7 c^2 \left (1-a^2 x^2\right )^{3/2}}-\frac {9+7 a x}{3 a^7 c^2 \sqrt {1-a^2 x^2}}-\frac {3 \sqrt {1-a^2 x^2}}{a^7 c^2}-\frac {x \sqrt {1-a^2 x^2}}{2 a^6 c^2}+\frac {\left (1-a^2 x^2\right )^{3/2}}{3 a^7 c^2}+\frac {5 \arcsin (a x)}{2 a^7 c^2} \] Output:
1/3*(a*x+1)/a^7/c^2/(-a^2*x^2+1)^(3/2)-1/3*(7*a*x+9)/a^7/c^2/(-a^2*x^2+1)^ (1/2)-3*(-a^2*x^2+1)^(1/2)/a^7/c^2-1/2*x*(-a^2*x^2+1)^(1/2)/a^6/c^2+1/3*(- a^2*x^2+1)^(3/2)/a^7/c^2+5/2*arcsin(a*x)/a^7/c^2
Time = 0.08 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.64 \[ \int \frac {e^{\text {arctanh}(a x)} x^6}{\left (c-a^2 c x^2\right )^2} \, dx=\frac {32-17 a x-31 a^2 x^2+11 a^3 x^3+a^4 x^4+2 a^5 x^5+15 (-1+a x) \sqrt {1-a^2 x^2} \arcsin (a x)}{6 a^7 c^2 (-1+a x) \sqrt {1-a^2 x^2}} \] Input:
Integrate[(E^ArcTanh[a*x]*x^6)/(c - a^2*c*x^2)^2,x]
Output:
(32 - 17*a*x - 31*a^2*x^2 + 11*a^3*x^3 + a^4*x^4 + 2*a^5*x^5 + 15*(-1 + a* x)*Sqrt[1 - a^2*x^2]*ArcSin[a*x])/(6*a^7*c^2*(-1 + a*x)*Sqrt[1 - a^2*x^2])
Time = 0.93 (sec) , antiderivative size = 154, normalized size of antiderivative = 1.06, number of steps used = 11, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.478, Rules used = {6698, 529, 2345, 27, 2346, 25, 2346, 25, 27, 455, 223}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^6 e^{\text {arctanh}(a x)}}{\left (c-a^2 c x^2\right )^2} \, dx\) |
\(\Big \downarrow \) 6698 |
\(\displaystyle \frac {\int \frac {x^6 (a x+1)}{\left (1-a^2 x^2\right )^{5/2}}dx}{c^2}\) |
\(\Big \downarrow \) 529 |
\(\displaystyle \frac {\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}-\frac {1}{3} \int \frac {\frac {3 x^5}{a}+\frac {3 x^4}{a^2}+\frac {3 x^3}{a^3}+\frac {3 x^2}{a^4}+\frac {3 x}{a^5}+\frac {1}{a^6}}{\left (1-a^2 x^2\right )^{3/2}}dx}{c^2}\) |
\(\Big \downarrow \) 2345 |
\(\displaystyle \frac {\frac {1}{3} \left (\int \frac {3 \left (\frac {x^3}{a^3}+\frac {x^2}{a^4}+\frac {2 x}{a^5}+\frac {2}{a^6}\right )}{\sqrt {1-a^2 x^2}}dx-\frac {7 a x+9}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}}{c^2}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\frac {1}{3} \left (3 \int \frac {\frac {x^3}{a^3}+\frac {x^2}{a^4}+\frac {2 x}{a^5}+\frac {2}{a^6}}{\sqrt {1-a^2 x^2}}dx-\frac {7 a x+9}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}}{c^2}\) |
\(\Big \downarrow \) 2346 |
\(\displaystyle \frac {\frac {1}{3} \left (3 \left (-\frac {\int -\frac {\frac {3 x^2}{a^2}+\frac {8 x}{a^3}+\frac {6}{a^4}}{\sqrt {1-a^2 x^2}}dx}{3 a^2}-\frac {x^2 \sqrt {1-a^2 x^2}}{3 a^5}\right )-\frac {7 a x+9}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}}{c^2}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {\frac {1}{3} \left (3 \left (\frac {\int \frac {\frac {3 x^2}{a^2}+\frac {8 x}{a^3}+\frac {6}{a^4}}{\sqrt {1-a^2 x^2}}dx}{3 a^2}-\frac {x^2 \sqrt {1-a^2 x^2}}{3 a^5}\right )-\frac {7 a x+9}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}}{c^2}\) |
\(\Big \downarrow \) 2346 |
\(\displaystyle \frac {\frac {1}{3} \left (3 \left (\frac {-\frac {\int -\frac {16 a x+15}{a^2 \sqrt {1-a^2 x^2}}dx}{2 a^2}-\frac {3 x \sqrt {1-a^2 x^2}}{2 a^4}}{3 a^2}-\frac {x^2 \sqrt {1-a^2 x^2}}{3 a^5}\right )-\frac {7 a x+9}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}}{c^2}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {\frac {1}{3} \left (3 \left (\frac {\frac {\int \frac {16 a x+15}{a^2 \sqrt {1-a^2 x^2}}dx}{2 a^2}-\frac {3 x \sqrt {1-a^2 x^2}}{2 a^4}}{3 a^2}-\frac {x^2 \sqrt {1-a^2 x^2}}{3 a^5}\right )-\frac {7 a x+9}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}}{c^2}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\frac {1}{3} \left (3 \left (\frac {\frac {\int \frac {16 a x+15}{\sqrt {1-a^2 x^2}}dx}{2 a^4}-\frac {3 x \sqrt {1-a^2 x^2}}{2 a^4}}{3 a^2}-\frac {x^2 \sqrt {1-a^2 x^2}}{3 a^5}\right )-\frac {7 a x+9}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}}{c^2}\) |
\(\Big \downarrow \) 455 |
\(\displaystyle \frac {\frac {1}{3} \left (3 \left (\frac {\frac {15 \int \frac {1}{\sqrt {1-a^2 x^2}}dx-\frac {16 \sqrt {1-a^2 x^2}}{a}}{2 a^4}-\frac {3 x \sqrt {1-a^2 x^2}}{2 a^4}}{3 a^2}-\frac {x^2 \sqrt {1-a^2 x^2}}{3 a^5}\right )-\frac {7 a x+9}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}}{c^2}\) |
\(\Big \downarrow \) 223 |
\(\displaystyle \frac {\frac {a x+1}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}+\frac {1}{3} \left (3 \left (\frac {\frac {\frac {15 \arcsin (a x)}{a}-\frac {16 \sqrt {1-a^2 x^2}}{a}}{2 a^4}-\frac {3 x \sqrt {1-a^2 x^2}}{2 a^4}}{3 a^2}-\frac {x^2 \sqrt {1-a^2 x^2}}{3 a^5}\right )-\frac {7 a x+9}{a^7 \sqrt {1-a^2 x^2}}\right )}{c^2}\) |
Input:
Int[(E^ArcTanh[a*x]*x^6)/(c - a^2*c*x^2)^2,x]
Output:
((1 + a*x)/(3*a^7*(1 - a^2*x^2)^(3/2)) + (-((9 + 7*a*x)/(a^7*Sqrt[1 - a^2* x^2])) + 3*(-1/3*(x^2*Sqrt[1 - a^2*x^2])/a^5 + ((-3*x*Sqrt[1 - a^2*x^2])/( 2*a^4) + ((-16*Sqrt[1 - a^2*x^2])/a + (15*ArcSin[a*x])/a)/(2*a^4))/(3*a^2) ))/3)/c^2
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt [a])]/Rt[-b, 2], x] /; FreeQ[{a, b}, x] && GtQ[a, 0] && NegQ[b]
Int[((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[d*(( a + b*x^2)^(p + 1)/(2*b*(p + 1))), x] + Simp[c Int[(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, p}, x] && !LeQ[p, -1]
Int[(x_)^(m_)*((c_) + (d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbo l] :> With[{Qx = PolynomialQuotient[x^m, a*d + b*c*x, x], R = PolynomialRem ainder[x^m, a*d + b*c*x, x]}, Simp[(-c)*R*(c + d*x)^n*((a + b*x^2)^(p + 1)/ (2*a*d*(p + 1))), x] + Simp[c/(2*a*(p + 1)) Int[(c + d*x)^(n - 1)*(a + b* x^2)^(p + 1)*ExpandToSum[2*a*d*(p + 1)*Qx + R*(n + 2*p + 2), x], x], x]] /; FreeQ[{a, b, c, d}, x] && IGtQ[n, 0] && IGtQ[m, 1] && LtQ[p, -1] && EqQ[b* c^2 + a*d^2, 0]
Int[(Pq_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{Q = PolynomialQuot ient[Pq, a + b*x^2, x], f = Coeff[PolynomialRemainder[Pq, a + b*x^2, x], x, 0], g = Coeff[PolynomialRemainder[Pq, a + b*x^2, x], x, 1]}, Simp[(a*g - b *f*x)*((a + b*x^2)^(p + 1)/(2*a*b*(p + 1))), x] + Simp[1/(2*a*(p + 1)) In t[(a + b*x^2)^(p + 1)*ExpandToSum[2*a*(p + 1)*Q + f*(2*p + 3), x], x], x]] /; FreeQ[{a, b}, x] && PolyQ[Pq, x] && LtQ[p, -1]
Int[(Pq_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{q = Expon[Pq, x], e = Coeff[Pq, x, Expon[Pq, x]]}, Simp[e*x^(q - 1)*((a + b*x^2)^(p + 1)/(b*( q + 2*p + 1))), x] + Simp[1/(b*(q + 2*p + 1)) Int[(a + b*x^2)^p*ExpandToS um[b*(q + 2*p + 1)*Pq - a*e*(q - 1)*x^(q - 2) - b*e*(q + 2*p + 1)*x^q, x], x], x]] /; FreeQ[{a, b, p}, x] && PolyQ[Pq, x] && !LeQ[p, -1]
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x _Symbol] :> Simp[c^p Int[x^m*(1 - a^2*x^2)^(p - n/2)*(1 + a*x)^n, x], x] /; FreeQ[{a, c, d, m, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || GtQ[c, 0]) && IGtQ[(n + 1)/2, 0] && !IntegerQ[p - n/2]
Time = 0.19 (sec) , antiderivative size = 198, normalized size of antiderivative = 1.37
method | result | size |
risch | \(\frac {\left (2 a^{2} x^{2}+3 a x +16\right ) \left (a^{2} x^{2}-1\right )}{6 a^{7} \sqrt {-a^{2} x^{2}+1}\, c^{2}}-\frac {-\frac {\sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}{6 a^{9} \left (x -\frac {1}{a}\right )^{2}}-\frac {31 \sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}{12 a^{8} \left (x -\frac {1}{a}\right )}-\frac {5 \arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-a^{2} x^{2}+1}}\right )}{2 a^{6} \sqrt {a^{2}}}+\frac {\sqrt {-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )}}{4 a^{8} \left (x +\frac {1}{a}\right )}}{c^{2}}\) | \(198\) |
default | \(\frac {\frac {-\frac {x \sqrt {-a^{2} x^{2}+1}}{2 a^{2}}+\frac {\arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-a^{2} x^{2}+1}}\right )}{2 a^{2} \sqrt {a^{2}}}}{a^{4}}+\frac {-\frac {x^{2} \sqrt {-a^{2} x^{2}+1}}{3 a^{2}}-\frac {2 \sqrt {-a^{2} x^{2}+1}}{3 a^{4}}}{a^{3}}+\frac {2 \arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-a^{2} x^{2}+1}}\right )}{a^{6} \sqrt {a^{2}}}-\frac {\sqrt {-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )}}{4 a^{8} \left (x +\frac {1}{a}\right )}-\frac {2 \sqrt {-a^{2} x^{2}+1}}{a^{7}}+\frac {\frac {\sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}{3 a \left (x -\frac {1}{a}\right )^{2}}-\frac {\sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}{3 \left (x -\frac {1}{a}\right )}}{2 a^{8}}+\frac {11 \sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}{4 a^{8} \left (x -\frac {1}{a}\right )}}{c^{2}}\) | \(309\) |
Input:
int((a*x+1)/(-a^2*x^2+1)^(1/2)*x^6/(-a^2*c*x^2+c)^2,x,method=_RETURNVERBOS E)
Output:
1/6*(2*a^2*x^2+3*a*x+16)*(a^2*x^2-1)/a^7/(-a^2*x^2+1)^(1/2)/c^2-(-1/6/a^9/ (x-1/a)^2*(-(x-1/a)^2*a^2-2*a*(x-1/a))^(1/2)-31/12/a^8/(x-1/a)*(-(x-1/a)^2 *a^2-2*a*(x-1/a))^(1/2)-5/2/a^6/(a^2)^(1/2)*arctan((a^2)^(1/2)*x/(-a^2*x^2 +1)^(1/2))+1/4/a^8/(x+1/a)*(-a^2*(x+1/a)^2+2*a*(x+1/a))^(1/2))/c^2
Time = 0.08 (sec) , antiderivative size = 159, normalized size of antiderivative = 1.10 \[ \int \frac {e^{\text {arctanh}(a x)} x^6}{\left (c-a^2 c x^2\right )^2} \, dx=-\frac {32 \, a^{3} x^{3} - 32 \, a^{2} x^{2} - 32 \, a x + 30 \, {\left (a^{3} x^{3} - a^{2} x^{2} - a x + 1\right )} \arctan \left (\frac {\sqrt {-a^{2} x^{2} + 1} - 1}{a x}\right ) + {\left (2 \, a^{5} x^{5} + a^{4} x^{4} + 11 \, a^{3} x^{3} - 31 \, a^{2} x^{2} - 17 \, a x + 32\right )} \sqrt {-a^{2} x^{2} + 1} + 32}{6 \, {\left (a^{10} c^{2} x^{3} - a^{9} c^{2} x^{2} - a^{8} c^{2} x + a^{7} c^{2}\right )}} \] Input:
integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*x^6/(-a^2*c*x^2+c)^2,x, algorithm="fr icas")
Output:
-1/6*(32*a^3*x^3 - 32*a^2*x^2 - 32*a*x + 30*(a^3*x^3 - a^2*x^2 - a*x + 1)* arctan((sqrt(-a^2*x^2 + 1) - 1)/(a*x)) + (2*a^5*x^5 + a^4*x^4 + 11*a^3*x^3 - 31*a^2*x^2 - 17*a*x + 32)*sqrt(-a^2*x^2 + 1) + 32)/(a^10*c^2*x^3 - a^9* c^2*x^2 - a^8*c^2*x + a^7*c^2)
\[ \int \frac {e^{\text {arctanh}(a x)} x^6}{\left (c-a^2 c x^2\right )^2} \, dx=\frac {\int \frac {x^{6}}{a^{4} x^{4} \sqrt {- a^{2} x^{2} + 1} - 2 a^{2} x^{2} \sqrt {- a^{2} x^{2} + 1} + \sqrt {- a^{2} x^{2} + 1}}\, dx + \int \frac {a x^{7}}{a^{4} x^{4} \sqrt {- a^{2} x^{2} + 1} - 2 a^{2} x^{2} \sqrt {- a^{2} x^{2} + 1} + \sqrt {- a^{2} x^{2} + 1}}\, dx}{c^{2}} \] Input:
integrate((a*x+1)/(-a**2*x**2+1)**(1/2)*x**6/(-a**2*c*x**2+c)**2,x)
Output:
(Integral(x**6/(a**4*x**4*sqrt(-a**2*x**2 + 1) - 2*a**2*x**2*sqrt(-a**2*x* *2 + 1) + sqrt(-a**2*x**2 + 1)), x) + Integral(a*x**7/(a**4*x**4*sqrt(-a** 2*x**2 + 1) - 2*a**2*x**2*sqrt(-a**2*x**2 + 1) + sqrt(-a**2*x**2 + 1)), x) )/c**2
\[ \int \frac {e^{\text {arctanh}(a x)} x^6}{\left (c-a^2 c x^2\right )^2} \, dx=\int { \frac {{\left (a x + 1\right )} x^{6}}{{\left (a^{2} c x^{2} - c\right )}^{2} \sqrt {-a^{2} x^{2} + 1}} \,d x } \] Input:
integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*x^6/(-a^2*c*x^2+c)^2,x, algorithm="ma xima")
Output:
integrate((a*x + 1)*x^6/((a^2*c*x^2 - c)^2*sqrt(-a^2*x^2 + 1)), x)
\[ \int \frac {e^{\text {arctanh}(a x)} x^6}{\left (c-a^2 c x^2\right )^2} \, dx=\int { \frac {{\left (a x + 1\right )} x^{6}}{{\left (a^{2} c x^{2} - c\right )}^{2} \sqrt {-a^{2} x^{2} + 1}} \,d x } \] Input:
integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*x^6/(-a^2*c*x^2+c)^2,x, algorithm="gi ac")
Output:
integrate((a*x + 1)*x^6/((a^2*c*x^2 - c)^2*sqrt(-a^2*x^2 + 1)), x)
Time = 0.08 (sec) , antiderivative size = 241, normalized size of antiderivative = 1.66 \[ \int \frac {e^{\text {arctanh}(a x)} x^6}{\left (c-a^2 c x^2\right )^2} \, dx=\frac {\sqrt {1-a^2\,x^2}}{6\,\left (a^9\,c^2\,x^2-2\,a^8\,c^2\,x+a^7\,c^2\right )}+\frac {\sqrt {1-a^2\,x^2}}{4\,\left (a^5\,c^2\,\sqrt {-a^2}+a^6\,c^2\,x\,\sqrt {-a^2}\right )\,\sqrt {-a^2}}+\frac {31\,\sqrt {1-a^2\,x^2}}{12\,\left (a^5\,c^2\,\sqrt {-a^2}-a^6\,c^2\,x\,\sqrt {-a^2}\right )\,\sqrt {-a^2}}-\frac {8\,\sqrt {1-a^2\,x^2}}{3\,a^7\,c^2}-\frac {x\,\sqrt {1-a^2\,x^2}}{2\,a^6\,c^2}+\frac {5\,\mathrm {asinh}\left (x\,\sqrt {-a^2}\right )}{2\,a^6\,c^2\,\sqrt {-a^2}}-\frac {x^2\,\sqrt {1-a^2\,x^2}}{3\,a^5\,c^2} \] Input:
int((x^6*(a*x + 1))/((c - a^2*c*x^2)^2*(1 - a^2*x^2)^(1/2)),x)
Output:
(1 - a^2*x^2)^(1/2)/(6*(a^7*c^2 - 2*a^8*c^2*x + a^9*c^2*x^2)) + (1 - a^2*x ^2)^(1/2)/(4*(a^5*c^2*(-a^2)^(1/2) + a^6*c^2*x*(-a^2)^(1/2))*(-a^2)^(1/2)) + (31*(1 - a^2*x^2)^(1/2))/(12*(a^5*c^2*(-a^2)^(1/2) - a^6*c^2*x*(-a^2)^( 1/2))*(-a^2)^(1/2)) - (8*(1 - a^2*x^2)^(1/2))/(3*a^7*c^2) - (x*(1 - a^2*x^ 2)^(1/2))/(2*a^6*c^2) + (5*asinh(x*(-a^2)^(1/2)))/(2*a^6*c^2*(-a^2)^(1/2)) - (x^2*(1 - a^2*x^2)^(1/2))/(3*a^5*c^2)
Time = 0.15 (sec) , antiderivative size = 129, normalized size of antiderivative = 0.89 \[ \int \frac {e^{\text {arctanh}(a x)} x^6}{\left (c-a^2 c x^2\right )^2} \, dx=\frac {15 \sqrt {-a^{2} x^{2}+1}\, \mathit {asin} \left (a x \right ) a x -15 \sqrt {-a^{2} x^{2}+1}\, \mathit {asin} \left (a x \right )-17 \sqrt {-a^{2} x^{2}+1}\, a x +17 \sqrt {-a^{2} x^{2}+1}+2 a^{5} x^{5}+a^{4} x^{4}+11 a^{3} x^{3}-31 a^{2} x^{2}-17 a x +32}{6 \sqrt {-a^{2} x^{2}+1}\, a^{7} c^{2} \left (a x -1\right )} \] Input:
int((a*x+1)/(-a^2*x^2+1)^(1/2)*x^6/(-a^2*c*x^2+c)^2,x)
Output:
(15*sqrt( - a**2*x**2 + 1)*asin(a*x)*a*x - 15*sqrt( - a**2*x**2 + 1)*asin( a*x) - 17*sqrt( - a**2*x**2 + 1)*a*x + 17*sqrt( - a**2*x**2 + 1) + 2*a**5* x**5 + a**4*x**4 + 11*a**3*x**3 - 31*a**2*x**2 - 17*a*x + 32)/(6*sqrt( - a **2*x**2 + 1)*a**7*c**2*(a*x - 1))