\(\int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx\) [275]

Optimal result

Integrand size = 20, antiderivative size = 242 \[ \int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx=-\frac {a^3 \left (1-\frac {1}{a x}\right )^{9/2} x^2}{4 \left (a-\frac {1}{x}\right )^2 \sqrt {1+\frac {1}{a x}} (c-a c x)^{9/2}}+\frac {5 a^3 \left (1-\frac {1}{a x}\right )^{9/2} x^3}{16 \left (a-\frac {1}{x}\right ) \sqrt {1+\frac {1}{a x}} (c-a c x)^{9/2}}+\frac {15 a^3 \left (1-\frac {1}{a x}\right )^{9/2} x^4}{32 \sqrt {1+\frac {1}{a x}} (c-a c x)^{9/2}}-\frac {15 \left (1-\frac {1}{a x}\right )^{9/2} \text {arctanh}\left (\frac {\sqrt {2} \sqrt {\frac {1}{a x}}}{\sqrt {1+\frac {1}{a x}}}\right )}{32 \sqrt {2} a \left (\frac {1}{a x}\right )^{9/2} (c-a c x)^{9/2}} \] Output:

-1/4*a^3*(1-1/a/x)^(9/2)*x^2/(a-1/x)^2/(1+1/a/x)^(1/2)/(-a*c*x+c)^(9/2)+5/ 
16*a^3*(1-1/a/x)^(9/2)*x^3/(a-1/x)/(1+1/a/x)^(1/2)/(-a*c*x+c)^(9/2)+15/32* 
a^3*(1-1/a/x)^(9/2)*x^4/(1+1/a/x)^(1/2)/(-a*c*x+c)^(9/2)-15/64*(1-1/a/x)^( 
9/2)*arctanh(2^(1/2)*(1/a/x)^(1/2)/(1+1/a/x)^(1/2))*2^(1/2)/a/(1/a/x)^(9/2 
)/(-a*c*x+c)^(9/2)
 

Mathematica [A] (verified)

Time = 0.28 (sec) , antiderivative size = 140, normalized size of antiderivative = 0.58 \[ \int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx=-\frac {\sqrt {1-\frac {1}{a x}} \left (6+40 a x-30 a^2 x^2+\frac {15 \sqrt {2} \sqrt {a} \sqrt {1+\frac {1}{a x}} (-1+a x)^2 \text {arctanh}\left (\frac {\sqrt {2} \sqrt {\frac {1}{x}}}{\sqrt {a} \sqrt {1+\frac {1}{a x}}}\right )}{\sqrt {\frac {1}{x}}}\right )}{64 a c^4 \sqrt {1+\frac {1}{a x}} (-1+a x)^2 \sqrt {c-a c x}} \] Input:

Integrate[1/(E^(3*ArcCoth[a*x])*(c - a*c*x)^(9/2)),x]
 

Output:

-1/64*(Sqrt[1 - 1/(a*x)]*(6 + 40*a*x - 30*a^2*x^2 + (15*Sqrt[2]*Sqrt[a]*Sq 
rt[1 + 1/(a*x)]*(-1 + a*x)^2*ArcTanh[(Sqrt[2]*Sqrt[x^(-1)])/(Sqrt[a]*Sqrt[ 
1 + 1/(a*x)])])/Sqrt[x^(-1)]))/(a*c^4*Sqrt[1 + 1/(a*x)]*(-1 + a*x)^2*Sqrt[ 
c - a*c*x])
 

Rubi [A] (verified)

Time = 0.54 (sec) , antiderivative size = 179, normalized size of antiderivative = 0.74, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.350, Rules used = {6727, 27, 105, 105, 105, 104, 219}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx\)

\(\Big \downarrow \) 6727

\(\displaystyle -\frac {\left (1-\frac {1}{a x}\right )^{9/2} \int \frac {a^3 \left (\frac {1}{x}\right )^{5/2}}{\left (a-\frac {1}{x}\right )^3 \left (1+\frac {1}{a x}\right )^{3/2}}d\frac {1}{x}}{\left (\frac {1}{x}\right )^{9/2} (c-a c x)^{9/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {a^3 \left (1-\frac {1}{a x}\right )^{9/2} \int \frac {\left (\frac {1}{x}\right )^{5/2}}{\left (a-\frac {1}{x}\right )^3 \left (1+\frac {1}{a x}\right )^{3/2}}d\frac {1}{x}}{\left (\frac {1}{x}\right )^{9/2} (c-a c x)^{9/2}}\)

\(\Big \downarrow \) 105

\(\displaystyle -\frac {a^3 \left (1-\frac {1}{a x}\right )^{9/2} \left (\frac {\left (\frac {1}{x}\right )^{5/2}}{4 \left (a-\frac {1}{x}\right )^2 \sqrt {\frac {1}{a x}+1}}-\frac {5}{8} \int \frac {\left (\frac {1}{x}\right )^{3/2}}{\left (a-\frac {1}{x}\right )^2 \left (1+\frac {1}{a x}\right )^{3/2}}d\frac {1}{x}\right )}{\left (\frac {1}{x}\right )^{9/2} (c-a c x)^{9/2}}\)

\(\Big \downarrow \) 105

\(\displaystyle -\frac {a^3 \left (1-\frac {1}{a x}\right )^{9/2} \left (\frac {\left (\frac {1}{x}\right )^{5/2}}{4 \left (a-\frac {1}{x}\right )^2 \sqrt {\frac {1}{a x}+1}}-\frac {5}{8} \left (\frac {\left (\frac {1}{x}\right )^{3/2}}{2 \left (a-\frac {1}{x}\right ) \sqrt {\frac {1}{a x}+1}}-\frac {3}{4} \int \frac {\sqrt {\frac {1}{x}}}{\left (a-\frac {1}{x}\right ) \left (1+\frac {1}{a x}\right )^{3/2}}d\frac {1}{x}\right )\right )}{\left (\frac {1}{x}\right )^{9/2} (c-a c x)^{9/2}}\)

\(\Big \downarrow \) 105

\(\displaystyle -\frac {a^3 \left (1-\frac {1}{a x}\right )^{9/2} \left (\frac {\left (\frac {1}{x}\right )^{5/2}}{4 \left (a-\frac {1}{x}\right )^2 \sqrt {\frac {1}{a x}+1}}-\frac {5}{8} \left (\frac {\left (\frac {1}{x}\right )^{3/2}}{2 \left (a-\frac {1}{x}\right ) \sqrt {\frac {1}{a x}+1}}-\frac {3}{4} \left (\frac {1}{2} a \int \frac {1}{\left (a-\frac {1}{x}\right ) \sqrt {1+\frac {1}{a x}} \sqrt {\frac {1}{x}}}d\frac {1}{x}-\frac {\sqrt {\frac {1}{x}}}{\sqrt {\frac {1}{a x}+1}}\right )\right )\right )}{\left (\frac {1}{x}\right )^{9/2} (c-a c x)^{9/2}}\)

\(\Big \downarrow \) 104

\(\displaystyle -\frac {a^3 \left (1-\frac {1}{a x}\right )^{9/2} \left (\frac {\left (\frac {1}{x}\right )^{5/2}}{4 \left (a-\frac {1}{x}\right )^2 \sqrt {\frac {1}{a x}+1}}-\frac {5}{8} \left (\frac {\left (\frac {1}{x}\right )^{3/2}}{2 \left (a-\frac {1}{x}\right ) \sqrt {\frac {1}{a x}+1}}-\frac {3}{4} \left (a \int \frac {1}{a-\frac {2}{x^2}}d\frac {\sqrt {\frac {1}{x}}}{\sqrt {1+\frac {1}{a x}}}-\frac {\sqrt {\frac {1}{x}}}{\sqrt {\frac {1}{a x}+1}}\right )\right )\right )}{\left (\frac {1}{x}\right )^{9/2} (c-a c x)^{9/2}}\)

\(\Big \downarrow \) 219

\(\displaystyle -\frac {a^3 \left (1-\frac {1}{a x}\right )^{9/2} \left (\frac {\left (\frac {1}{x}\right )^{5/2}}{4 \left (a-\frac {1}{x}\right )^2 \sqrt {\frac {1}{a x}+1}}-\frac {5}{8} \left (\frac {\left (\frac {1}{x}\right )^{3/2}}{2 \left (a-\frac {1}{x}\right ) \sqrt {\frac {1}{a x}+1}}-\frac {3}{4} \left (\frac {\sqrt {a} \text {arctanh}\left (\frac {\sqrt {2} \sqrt {\frac {1}{x}}}{\sqrt {a} \sqrt {\frac {1}{a x}+1}}\right )}{\sqrt {2}}-\frac {\sqrt {\frac {1}{x}}}{\sqrt {\frac {1}{a x}+1}}\right )\right )\right )}{\left (\frac {1}{x}\right )^{9/2} (c-a c x)^{9/2}}\)

Input:

Int[1/(E^(3*ArcCoth[a*x])*(c - a*c*x)^(9/2)),x]
 

Output:

-((a^3*(1 - 1/(a*x))^(9/2)*((x^(-1))^(5/2)/(4*(a - x^(-1))^2*Sqrt[1 + 1/(a 
*x)]) - (5*((x^(-1))^(3/2)/(2*(a - x^(-1))*Sqrt[1 + 1/(a*x)]) - (3*(-(Sqrt 
[x^(-1)]/Sqrt[1 + 1/(a*x)]) + (Sqrt[a]*ArcTanh[(Sqrt[2]*Sqrt[x^(-1)])/(Sqr 
t[a]*Sqrt[1 + 1/(a*x)])])/Sqrt[2]))/4))/8))/((x^(-1))^(9/2)*(c - a*c*x)^(9 
/2)))
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 104

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x 
_)), x_] :> With[{q = Denominator[m]}, Simp[q   Subst[Int[x^(q*(m + 1) - 1) 
/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^(1/q)], x] 
] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && L 
tQ[-1, m, 0] && SimplerQ[a + b*x, c + d*x]
 

rule 105

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Simp[(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/((m + 
1)*(b*e - a*f))), x] - Simp[n*((d*e - c*f)/((m + 1)*(b*e - a*f)))   Int[(a 
+ b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, 
e, f, m, p}, x] && EqQ[m + n + p + 2, 0] && GtQ[n, 0] && (SumSimplerQ[m, 1] 
 ||  !SumSimplerQ[p, 1]) && NeQ[m, -1]
 

rule 219

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 6727

Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_))^(p_), x_Symbol] :> Si 
mp[(-(1/x)^p)*((c + d*x)^p/(1 + c/(d*x))^p)   Subst[Int[((1 + c*(x/d))^p*(( 
1 + x/a)^(n/2)/x^(p + 2)))/(1 - x/a)^(n/2), x], x, 1/x], x] /; FreeQ[{a, c, 
 d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] &&  !IntegerQ[p]
 

Maple [A] (verified)

Time = 0.14 (sec) , antiderivative size = 180, normalized size of antiderivative = 0.74

method	result	size
default	\(-\frac {\left (\frac {a x -1}{a x +1}\right )^{\frac {3}{2}} \left (a x +1\right ) \sqrt {-c \left (a x -1\right )}\, \left (15 \sqrt {2}\, \arctan \left (\frac {\sqrt {-c \left (a x +1\right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) a^{2} x^{2} \sqrt {-c \left (a x +1\right )}-30 \sqrt {2}\, \arctan \left (\frac {\sqrt {-c \left (a x +1\right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) a x \sqrt {-c \left (a x +1\right )}+30 \sqrt {c}\, a^{2} x^{2}+15 \arctan \left (\frac {\sqrt {-c \left (a x +1\right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) \sqrt {2}\, \sqrt {-c \left (a x +1\right )}-40 \sqrt {c}\, a x -6 \sqrt {c}\right )}{64 \left (a x -1\right )^{4} c^{\frac {11}{2}} a}\)	\(180\)

Input:

int(((a*x-1)/(a*x+1))^(3/2)/(-a*c*x+c)^(9/2),x,method=_RETURNVERBOSE)
 

Output:

-1/64*((a*x-1)/(a*x+1))^(3/2)/(a*x-1)^4*(a*x+1)*(-c*(a*x-1))^(1/2)/c^(11/2 
)*(15*2^(1/2)*arctan(1/2*(-c*(a*x+1))^(1/2)*2^(1/2)/c^(1/2))*a^2*x^2*(-c*( 
a*x+1))^(1/2)-30*2^(1/2)*arctan(1/2*(-c*(a*x+1))^(1/2)*2^(1/2)/c^(1/2))*a* 
x*(-c*(a*x+1))^(1/2)+30*c^(1/2)*a^2*x^2+15*arctan(1/2*(-c*(a*x+1))^(1/2)*2 
^(1/2)/c^(1/2))*2^(1/2)*(-c*(a*x+1))^(1/2)-40*c^(1/2)*a*x-6*c^(1/2))/a
 

Fricas [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 347, normalized size of antiderivative = 1.43 \[ \int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx=\left [-\frac {15 \, \sqrt {2} {\left (a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1\right )} \sqrt {-c} \log \left (-\frac {a^{2} c x^{2} + 2 \, a c x + 2 \, \sqrt {2} \sqrt {-a c x + c} {\left (a x + 1\right )} \sqrt {-c} \sqrt {\frac {a x - 1}{a x + 1}} - 3 \, c}{a^{2} x^{2} - 2 \, a x + 1}\right ) + 4 \, {\left (15 \, a^{2} x^{2} - 20 \, a x - 3\right )} \sqrt {-a c x + c} \sqrt {\frac {a x - 1}{a x + 1}}}{128 \, {\left (a^{4} c^{5} x^{3} - 3 \, a^{3} c^{5} x^{2} + 3 \, a^{2} c^{5} x - a c^{5}\right )}}, \frac {15 \, \sqrt {2} {\left (a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1\right )} \sqrt {c} \arctan \left (\frac {\sqrt {2} \sqrt {-a c x + c} {\left (a x + 1\right )} \sqrt {c} \sqrt {\frac {a x - 1}{a x + 1}}}{2 \, {\left (a c x - c\right )}}\right ) - 2 \, {\left (15 \, a^{2} x^{2} - 20 \, a x - 3\right )} \sqrt {-a c x + c} \sqrt {\frac {a x - 1}{a x + 1}}}{64 \, {\left (a^{4} c^{5} x^{3} - 3 \, a^{3} c^{5} x^{2} + 3 \, a^{2} c^{5} x - a c^{5}\right )}}\right ] \] Input:

integrate(((a*x-1)/(a*x+1))^(3/2)/(-a*c*x+c)^(9/2),x, algorithm="fricas")
 

Output:

[-1/128*(15*sqrt(2)*(a^3*x^3 - 3*a^2*x^2 + 3*a*x - 1)*sqrt(-c)*log(-(a^2*c 
*x^2 + 2*a*c*x + 2*sqrt(2)*sqrt(-a*c*x + c)*(a*x + 1)*sqrt(-c)*sqrt((a*x - 
 1)/(a*x + 1)) - 3*c)/(a^2*x^2 - 2*a*x + 1)) + 4*(15*a^2*x^2 - 20*a*x - 3) 
*sqrt(-a*c*x + c)*sqrt((a*x - 1)/(a*x + 1)))/(a^4*c^5*x^3 - 3*a^3*c^5*x^2 
+ 3*a^2*c^5*x - a*c^5), 1/64*(15*sqrt(2)*(a^3*x^3 - 3*a^2*x^2 + 3*a*x - 1) 
*sqrt(c)*arctan(1/2*sqrt(2)*sqrt(-a*c*x + c)*(a*x + 1)*sqrt(c)*sqrt((a*x - 
 1)/(a*x + 1))/(a*c*x - c)) - 2*(15*a^2*x^2 - 20*a*x - 3)*sqrt(-a*c*x + c) 
*sqrt((a*x - 1)/(a*x + 1)))/(a^4*c^5*x^3 - 3*a^3*c^5*x^2 + 3*a^2*c^5*x - a 
*c^5)]
 

Sympy [F(-1)]

Timed out. \[ \int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx=\text {Timed out} \] Input:

integrate(((a*x-1)/(a*x+1))**(3/2)/(-a*c*x+c)**(9/2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx=\int { \frac {\left (\frac {a x - 1}{a x + 1}\right )^{\frac {3}{2}}}{{\left (-a c x + c\right )}^{\frac {9}{2}}} \,d x } \] Input:

integrate(((a*x-1)/(a*x+1))^(3/2)/(-a*c*x+c)^(9/2),x, algorithm="maxima")
 

Output:

integrate(((a*x - 1)/(a*x + 1))^(3/2)/(-a*c*x + c)^(9/2), x)
 

Giac [F(-2)]

Exception generated. \[ \int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx=\text {Exception raised: TypeError} \] Input:

integrate(((a*x-1)/(a*x+1))^(3/2)/(-a*c*x+c)^(9/2),x, algorithm="giac")
 

Output:

Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const 
index_m & i,const vecteur & l) Error: Bad Argument Value
 

Mupad [F(-1)]

Timed out. \[ \int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx=\int \frac {{\left (\frac {a\,x-1}{a\,x+1}\right )}^{3/2}}{{\left (c-a\,c\,x\right )}^{9/2}} \,d x \] Input:

int(((a*x - 1)/(a*x + 1))^(3/2)/(c - a*c*x)^(9/2),x)
 

Output:

int(((a*x - 1)/(a*x + 1))^(3/2)/(c - a*c*x)^(9/2), x)
 

Reduce [B] (verification not implemented)

Time = 0.15 (sec) , antiderivative size = 207, normalized size of antiderivative = 0.86 \[ \int \frac {e^{-3 \coth ^{-1}(a x)}}{(c-a c x)^{9/2}} \, dx=\frac {\sqrt {c}\, \sqrt {2}\, i \left (120 \,\mathrm {log}\left (\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )\right ) \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )^{6}-120 \,\mathrm {log}\left (\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )\right ) \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )^{4}+\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )^{10}+15 \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )^{8}-160 \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )^{6}+15 \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )^{2}+1\right )}{512 \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )^{4} a \,c^{5} \left (\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-a x +1}}{\sqrt {2}}\right )}{2}\right )^{2}-1\right )} \] Input:

int(((a*x-1)/(a*x+1))^(3/2)/(-a*c*x+c)^(9/2),x)
 

Output:

(sqrt(c)*sqrt(2)*i*(120*log(tan(asin(sqrt( - a*x + 1)/sqrt(2))/2))*tan(asi 
n(sqrt( - a*x + 1)/sqrt(2))/2)**6 - 120*log(tan(asin(sqrt( - a*x + 1)/sqrt 
(2))/2))*tan(asin(sqrt( - a*x + 1)/sqrt(2))/2)**4 + tan(asin(sqrt( - a*x + 
 1)/sqrt(2))/2)**10 + 15*tan(asin(sqrt( - a*x + 1)/sqrt(2))/2)**8 - 160*ta 
n(asin(sqrt( - a*x + 1)/sqrt(2))/2)**6 + 15*tan(asin(sqrt( - a*x + 1)/sqrt 
(2))/2)**2 + 1))/(512*tan(asin(sqrt( - a*x + 1)/sqrt(2))/2)**4*a*c**5*(tan 
(asin(sqrt( - a*x + 1)/sqrt(2))/2)**2 - 1))