Integrand size = 20, antiderivative size = 98 \[ \int e^{n \coth ^{-1}(a x)} (c-a c x)^{3/2} \, dx=\frac {2}{5} \left (\frac {a-\frac {1}{x}}{a+\frac {1}{x}}\right )^{\frac {1}{2} (-3+n)} \left (1-\frac {1}{a x}\right )^{-n/2} \left (1+\frac {1}{a x}\right )^{\frac {2+n}{2}} x (c-a c x)^{3/2} \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},\frac {1}{2} (-3+n),-\frac {3}{2},\frac {2}{\left (a+\frac {1}{x}\right ) x}\right ) \] Output:
2/5*((a-1/x)/(a+1/x))^(-3/2+1/2*n)*(1+1/a/x)^(1+1/2*n)*x*(-a*c*x+c)^(3/2)* hypergeom([-5/2, -3/2+1/2*n],[-3/2],2/(a+1/x)/x)/((1-1/a/x)^(1/2*n))
Time = 0.09 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.03 \[ \int e^{n \coth ^{-1}(a x)} (c-a c x)^{3/2} \, dx=-\frac {2 c \left (1-\frac {1}{a x}\right )^{-n/2} \left (1+\frac {1}{a x}\right )^{n/2} \left (\frac {-1+a x}{1+a x}\right )^{\frac {1}{2} (-1+n)} (1+a x)^2 \sqrt {c-a c x} \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},\frac {1}{2} (-3+n),-\frac {3}{2},\frac {2}{1+a x}\right )}{5 a} \] Input:
Integrate[E^(n*ArcCoth[a*x])*(c - a*c*x)^(3/2),x]
Output:
(-2*c*(1 + 1/(a*x))^(n/2)*((-1 + a*x)/(1 + a*x))^((-1 + n)/2)*(1 + a*x)^2* Sqrt[c - a*c*x]*Hypergeometric2F1[-5/2, (-3 + n)/2, -3/2, 2/(1 + a*x)])/(5 *a*(1 - 1/(a*x))^(n/2))
Time = 0.47 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.08, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {6727, 142}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (c-a c x)^{3/2} e^{n \coth ^{-1}(a x)} \, dx\) |
\(\Big \downarrow \) 6727 |
\(\displaystyle -\frac {\left (\frac {1}{x}\right )^{3/2} (c-a c x)^{3/2} \int \frac {\left (1-\frac {1}{a x}\right )^{\frac {3-n}{2}} \left (1+\frac {1}{a x}\right )^{n/2}}{\left (\frac {1}{x}\right )^{7/2}}d\frac {1}{x}}{\left (1-\frac {1}{a x}\right )^{3/2}}\) |
\(\Big \downarrow \) 142 |
\(\displaystyle \frac {2}{5} x (c-a c x)^{3/2} \left (\frac {a-\frac {1}{x}}{a+\frac {1}{x}}\right )^{\frac {n-3}{2}} \left (1-\frac {1}{a x}\right )^{\frac {3-n}{2}-\frac {3}{2}} \left (\frac {1}{a x}+1\right )^{\frac {n+2}{2}} \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},\frac {n-3}{2},-\frac {3}{2},\frac {2}{\left (a+\frac {1}{x}\right ) x}\right )\) |
Input:
Int[E^(n*ArcCoth[a*x])*(c - a*c*x)^(3/2),x]
Output:
(2*((a - x^(-1))/(a + x^(-1)))^((-3 + n)/2)*(1 - 1/(a*x))^(-3/2 + (3 - n)/ 2)*(1 + 1/(a*x))^((2 + n)/2)*x*(c - a*c*x)^(3/2)*Hypergeometric2F1[-5/2, ( -3 + n)/2, -3/2, 2/((a + x^(-1))*x)])/5
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/((b*e - a*f)*(m + 1)))*Hypergeometric2F1[m + 1, -n, m + 2, (-(d*e - c*f))*((a + b*x)/((b*c - a*d)*(e + f*x)))])/((b*e - a*f)*((c + d*x)/((b*c - a*d)*(e + f *x))))^n, x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && EqQ[m + n + p + 2, 0] && !IntegerQ[n]
Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_))^(p_), x_Symbol] :> Si mp[(-(1/x)^p)*((c + d*x)^p/(1 + c/(d*x))^p) Subst[Int[((1 + c*(x/d))^p*(( 1 + x/a)^(n/2)/x^(p + 2)))/(1 - x/a)^(n/2), x], x, 1/x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] && !IntegerQ[p]
\[\int {\mathrm e}^{n \,\operatorname {arccoth}\left (a x \right )} \left (-a c x +c \right )^{\frac {3}{2}}d x\]
Input:
int(exp(n*arccoth(a*x))*(-a*c*x+c)^(3/2),x)
Output:
int(exp(n*arccoth(a*x))*(-a*c*x+c)^(3/2),x)
\[ \int e^{n \coth ^{-1}(a x)} (c-a c x)^{3/2} \, dx=\int { {\left (-a c x + c\right )}^{\frac {3}{2}} \left (\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n} \,d x } \] Input:
integrate(exp(n*arccoth(a*x))*(-a*c*x+c)^(3/2),x, algorithm="fricas")
Output:
integral(-(a*c*x - c)*sqrt(-a*c*x + c)*((a*x + 1)/(a*x - 1))^(1/2*n), x)
\[ \int e^{n \coth ^{-1}(a x)} (c-a c x)^{3/2} \, dx=\int \left (- c \left (a x - 1\right )\right )^{\frac {3}{2}} e^{n \operatorname {acoth}{\left (a x \right )}}\, dx \] Input:
integrate(exp(n*acoth(a*x))*(-a*c*x+c)**(3/2),x)
Output:
Integral((-c*(a*x - 1))**(3/2)*exp(n*acoth(a*x)), x)
\[ \int e^{n \coth ^{-1}(a x)} (c-a c x)^{3/2} \, dx=\int { {\left (-a c x + c\right )}^{\frac {3}{2}} \left (\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n} \,d x } \] Input:
integrate(exp(n*arccoth(a*x))*(-a*c*x+c)^(3/2),x, algorithm="maxima")
Output:
integrate((-a*c*x + c)^(3/2)*((a*x + 1)/(a*x - 1))^(1/2*n), x)
\[ \int e^{n \coth ^{-1}(a x)} (c-a c x)^{3/2} \, dx=\int { {\left (-a c x + c\right )}^{\frac {3}{2}} \left (\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n} \,d x } \] Input:
integrate(exp(n*arccoth(a*x))*(-a*c*x+c)^(3/2),x, algorithm="giac")
Output:
integrate((-a*c*x + c)^(3/2)*((a*x + 1)/(a*x - 1))^(1/2*n), x)
Timed out. \[ \int e^{n \coth ^{-1}(a x)} (c-a c x)^{3/2} \, dx=\int {\mathrm {e}}^{n\,\mathrm {acoth}\left (a\,x\right )}\,{\left (c-a\,c\,x\right )}^{3/2} \,d x \] Input:
int(exp(n*acoth(a*x))*(c - a*c*x)^(3/2),x)
Output:
int(exp(n*acoth(a*x))*(c - a*c*x)^(3/2), x)
\[ \int e^{n \coth ^{-1}(a x)} (c-a c x)^{3/2} \, dx=\sqrt {c}\, c \left (-\left (\int e^{\mathit {acoth} \left (a x \right ) n} \sqrt {-a x +1}\, x d x \right ) a +\int e^{\mathit {acoth} \left (a x \right ) n} \sqrt {-a x +1}d x \right ) \] Input:
int(exp(n*acoth(a*x))*(-a*c*x+c)^(3/2),x)
Output:
sqrt(c)*c*( - int(e**(acoth(a*x)*n)*sqrt( - a*x + 1)*x,x)*a + int(e**(acot h(a*x)*n)*sqrt( - a*x + 1),x))