\(\int e^{3 \coth ^{-1}(a x)} (c-\frac {c}{a x})^{9/2} \, dx\) [470]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [A] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [B] (verification not implemented)

Optimal result

Integrand size = 24, antiderivative size = 235 \[ \int e^{3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{9/2} \, dx=\frac {33 c^6 \left (1-\frac {1}{a^2 x^2}\right )^{3/2}}{35 a \left (c-\frac {c}{a x}\right )^{3/2}}+\frac {3 c^5 \sqrt {1-\frac {1}{a^2 x^2}}}{a \sqrt {c-\frac {c}{a x}}}+\frac {51 c^5 \left (1-\frac {1}{a^2 x^2}\right )^{3/2}}{35 a \sqrt {c-\frac {c}{a x}}}+\frac {9 c^4 \left (1-\frac {1}{a^2 x^2}\right )^{3/2} \sqrt {c-\frac {c}{a x}}}{7 a}+c^3 \left (1-\frac {1}{a^2 x^2}\right )^{3/2} \left (c-\frac {c}{a x}\right )^{3/2} x-\frac {3 c^{9/2} \text {arctanh}\left (\frac {\sqrt {c} \sqrt {1-\frac {1}{a^2 x^2}}}{\sqrt {c-\frac {c}{a x}}}\right )}{a} \] Output:

33/35*c^6*(1-1/a^2/x^2)^(3/2)/a/(c-c/a/x)^(3/2)+3*c^5*(1-1/a^2/x^2)^(1/2)/ 
a/(c-c/a/x)^(1/2)+51/35*c^5*(1-1/a^2/x^2)^(3/2)/a/(c-c/a/x)^(1/2)+9/7*c^4* 
(1-1/a^2/x^2)^(3/2)*(c-c/a/x)^(1/2)/a+c^3*(1-1/a^2/x^2)^(3/2)*(c-c/a/x)^(3 
/2)*x-3*c^(9/2)*arctanh(c^(1/2)*(1-1/a^2/x^2)^(1/2)/(c-c/a/x)^(1/2))/a
 

Mathematica [A] (verified)

Time = 0.12 (sec) , antiderivative size = 109, normalized size of antiderivative = 0.46 \[ \int e^{3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{9/2} \, dx=\frac {c^4 \sqrt {c-\frac {c}{a x}} \left (\sqrt {1+\frac {1}{a x}} \left (10-26 a x-12 a^2 x^2+164 a^3 x^3+35 a^4 x^4\right )-105 a^3 x^3 \text {arctanh}\left (\sqrt {1+\frac {1}{a x}}\right )\right )}{35 a^4 \sqrt {1-\frac {1}{a x}} x^3} \] Input:

Integrate[E^(3*ArcCoth[a*x])*(c - c/(a*x))^(9/2),x]
 

Output:

(c^4*Sqrt[c - c/(a*x)]*(Sqrt[1 + 1/(a*x)]*(10 - 26*a*x - 12*a^2*x^2 + 164* 
a^3*x^3 + 35*a^4*x^4) - 105*a^3*x^3*ArcTanh[Sqrt[1 + 1/(a*x)]]))/(35*a^4*S 
qrt[1 - 1/(a*x)]*x^3)
 

Rubi [A] (verified)

Time = 0.66 (sec) , antiderivative size = 168, normalized size of antiderivative = 0.71, number of steps used = 12, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.458, Rules used = {6731, 585, 27, 108, 27, 170, 27, 164, 60, 73, 221}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \left (c-\frac {c}{a x}\right )^{9/2} e^{3 \coth ^{-1}(a x)} \, dx\)

\(\Big \downarrow \) 6731

\(\displaystyle -c^3 \int \left (1-\frac {1}{a^2 x^2}\right )^{3/2} \left (c-\frac {c}{a x}\right )^{3/2} x^2d\frac {1}{x}\)

\(\Big \downarrow \) 585

\(\displaystyle -\frac {c^4 \sqrt {c-\frac {c}{a x}} \int \frac {\left (a-\frac {1}{x}\right )^3 \left (1+\frac {1}{a x}\right )^{3/2} x^2}{a^3}d\frac {1}{x}}{\sqrt {1-\frac {1}{a x}}}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {c^4 \sqrt {c-\frac {c}{a x}} \int \left (a-\frac {1}{x}\right )^3 \left (1+\frac {1}{a x}\right )^{3/2} x^2d\frac {1}{x}}{a^3 \sqrt {1-\frac {1}{a x}}}\)

\(\Big \downarrow \) 108

\(\displaystyle -\frac {c^4 \sqrt {c-\frac {c}{a x}} \left (\int -\frac {3 \left (a-\frac {1}{x}\right )^2 \left (a+\frac {3}{x}\right ) \sqrt {1+\frac {1}{a x}} x}{2 a}d\frac {1}{x}-x \left (a-\frac {1}{x}\right )^3 \left (\frac {1}{a x}+1\right )^{3/2}\right )}{a^3 \sqrt {1-\frac {1}{a x}}}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {c^4 \sqrt {c-\frac {c}{a x}} \left (x \left (-\left (\frac {1}{a x}+1\right )^{3/2}\right ) \left (a-\frac {1}{x}\right )^3-\frac {3 \int \left (a-\frac {1}{x}\right )^2 \left (a+\frac {3}{x}\right ) \sqrt {1+\frac {1}{a x}} xd\frac {1}{x}}{2 a}\right )}{a^3 \sqrt {1-\frac {1}{a x}}}\)

\(\Big \downarrow \) 170

\(\displaystyle -\frac {c^4 \sqrt {c-\frac {c}{a x}} \left (x \left (-\left (\frac {1}{a x}+1\right )^{3/2}\right ) \left (a-\frac {1}{x}\right )^3-\frac {3 \left (\frac {2}{7} a \int \frac {1}{2} \left (a-\frac {1}{x}\right ) \left (7 a+\frac {17}{x}\right ) \sqrt {1+\frac {1}{a x}} xd\frac {1}{x}+\frac {6}{7} a \left (\frac {1}{a x}+1\right )^{3/2} \left (a-\frac {1}{x}\right )^2\right )}{2 a}\right )}{a^3 \sqrt {1-\frac {1}{a x}}}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {c^4 \sqrt {c-\frac {c}{a x}} \left (x \left (-\left (\frac {1}{a x}+1\right )^{3/2}\right ) \left (a-\frac {1}{x}\right )^3-\frac {3 \left (\frac {1}{7} a \int \left (a-\frac {1}{x}\right ) \left (7 a+\frac {17}{x}\right ) \sqrt {1+\frac {1}{a x}} xd\frac {1}{x}+\frac {6}{7} a \left (\frac {1}{a x}+1\right )^{3/2} \left (a-\frac {1}{x}\right )^2\right )}{2 a}\right )}{a^3 \sqrt {1-\frac {1}{a x}}}\)

\(\Big \downarrow \) 164

\(\displaystyle -\frac {c^4 \sqrt {c-\frac {c}{a x}} \left (x \left (-\left (\frac {1}{a x}+1\right )^{3/2}\right ) \left (a-\frac {1}{x}\right )^3-\frac {3 \left (\frac {1}{7} a \left (7 a^2 \int \sqrt {1+\frac {1}{a x}} xd\frac {1}{x}+\frac {2}{5} a \left (28 a-\frac {17}{x}\right ) \left (\frac {1}{a x}+1\right )^{3/2}\right )+\frac {6}{7} a \left (\frac {1}{a x}+1\right )^{3/2} \left (a-\frac {1}{x}\right )^2\right )}{2 a}\right )}{a^3 \sqrt {1-\frac {1}{a x}}}\)

\(\Big \downarrow \) 60

\(\displaystyle -\frac {c^4 \sqrt {c-\frac {c}{a x}} \left (x \left (-\left (\frac {1}{a x}+1\right )^{3/2}\right ) \left (a-\frac {1}{x}\right )^3-\frac {3 \left (\frac {1}{7} a \left (7 a^2 \left (\int \frac {x}{\sqrt {1+\frac {1}{a x}}}d\frac {1}{x}+2 \sqrt {\frac {1}{a x}+1}\right )+\frac {2}{5} a \left (28 a-\frac {17}{x}\right ) \left (\frac {1}{a x}+1\right )^{3/2}\right )+\frac {6}{7} a \left (\frac {1}{a x}+1\right )^{3/2} \left (a-\frac {1}{x}\right )^2\right )}{2 a}\right )}{a^3 \sqrt {1-\frac {1}{a x}}}\)

\(\Big \downarrow \) 73

\(\displaystyle -\frac {c^4 \sqrt {c-\frac {c}{a x}} \left (x \left (-\left (\frac {1}{a x}+1\right )^{3/2}\right ) \left (a-\frac {1}{x}\right )^3-\frac {3 \left (\frac {1}{7} a \left (7 a^2 \left (2 a \int \frac {1}{\frac {a}{x^2}-a}d\sqrt {1+\frac {1}{a x}}+2 \sqrt {\frac {1}{a x}+1}\right )+\frac {2}{5} a \left (28 a-\frac {17}{x}\right ) \left (\frac {1}{a x}+1\right )^{3/2}\right )+\frac {6}{7} a \left (\frac {1}{a x}+1\right )^{3/2} \left (a-\frac {1}{x}\right )^2\right )}{2 a}\right )}{a^3 \sqrt {1-\frac {1}{a x}}}\)

\(\Big \downarrow \) 221

\(\displaystyle -\frac {c^4 \left (x \left (-\left (\frac {1}{a x}+1\right )^{3/2}\right ) \left (a-\frac {1}{x}\right )^3-\frac {3 \left (\frac {1}{7} a \left (7 a^2 \left (2 \sqrt {\frac {1}{a x}+1}-2 \text {arctanh}\left (\sqrt {\frac {1}{a x}+1}\right )\right )+\frac {2}{5} a \left (28 a-\frac {17}{x}\right ) \left (\frac {1}{a x}+1\right )^{3/2}\right )+\frac {6}{7} a \left (\frac {1}{a x}+1\right )^{3/2} \left (a-\frac {1}{x}\right )^2\right )}{2 a}\right ) \sqrt {c-\frac {c}{a x}}}{a^3 \sqrt {1-\frac {1}{a x}}}\)

Input:

Int[E^(3*ArcCoth[a*x])*(c - c/(a*x))^(9/2),x]
 

Output:

-((c^4*Sqrt[c - c/(a*x)]*(-((a - x^(-1))^3*(1 + 1/(a*x))^(3/2)*x) - (3*((6 
*a*(a - x^(-1))^2*(1 + 1/(a*x))^(3/2))/7 + (a*((2*a*(28*a - 17/x)*(1 + 1/( 
a*x))^(3/2))/5 + 7*a^2*(2*Sqrt[1 + 1/(a*x)] - 2*ArcTanh[Sqrt[1 + 1/(a*x)]] 
)))/7))/(2*a)))/(a^3*Sqrt[1 - 1/(a*x)]))
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 60
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ 
(a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( 
b*(m + n + 1)))   Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, 
 c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !Integer 
Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinear 
Q[a, b, c, d, m, n, x]
 

rule 73
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 108
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Simp[(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^p/(b*(m + 1))) 
, x] - Simp[1/(b*(m + 1))   Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f* 
x)^(p - 1)*Simp[d*e*n + c*f*p + d*f*(n + p)*x, x], x], x] /; FreeQ[{a, b, c 
, d, e, f}, x] && LtQ[m, -1] && GtQ[n, 0] && GtQ[p, 0] && (IntegersQ[2*m, 2 
*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])
 

rule 164
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_ 
))*((g_.) + (h_.)*(x_)), x_] :> Simp[(-(a*d*f*h*(n + 2) + b*c*f*h*(m + 2) - 
 b*d*(f*g + e*h)*(m + n + 3) - b*d*f*h*(m + n + 2)*x))*(a + b*x)^(m + 1)*(( 
c + d*x)^(n + 1)/(b^2*d^2*(m + n + 2)*(m + n + 3))), x] + Simp[(a^2*d^2*f*h 
*(n + 1)*(n + 2) + a*b*d*(n + 1)*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(m + n + 
3)) + b^2*(c^2*f*h*(m + 1)*(m + 2) - c*d*(f*g + e*h)*(m + 1)*(m + n + 3) + 
d^2*e*g*(m + n + 2)*(m + n + 3)))/(b^2*d^2*(m + n + 2)*(m + n + 3))   Int[( 
a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] 
&& NeQ[m + n + 2, 0] && NeQ[m + n + 3, 0]
 

rule 170
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[h*(a + b*x)^m*(c + d*x)^(n + 1)*(( 
e + f*x)^(p + 1)/(d*f*(m + n + p + 2))), x] + Simp[1/(d*f*(m + n + p + 2)) 
  Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2 
) - h*(b*c*e*m + a*(d*e*(n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) 
+ h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x], x], x] /; Fre 
eQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] 
 && IntegerQ[m]
 

rule 221
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 585
Int[((e_.)*(x_))^(m_.)*((c_) + (d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_)^2)^(p_) 
, x_Symbol] :> Simp[a^p*c^IntPart[n]*((c + d*x)^FracPart[n]/(1 + d*(x/c))^F 
racPart[n])   Int[(e*x)^m*(1 - d*(x/c))^p*(1 + d*(x/c))^(n + p), x], x] /; 
FreeQ[{a, b, c, d, e, m, n, p}, x] && EqQ[b*c^2 + a*d^2, 0] && GtQ[a, 0]
 

rule 6731
Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*((c_) + (d_.)/(x_))^(p_.), x_Symbol] :> S 
imp[-c^n   Subst[Int[(c + d*x)^(p - n)*((1 - x^2/a^2)^(n/2)/x^2), x], x, 1/ 
x], x] /; FreeQ[{a, c, d, p}, x] && EqQ[c + a*d, 0] && IntegerQ[(n - 1)/2] 
&& IntegerQ[2*p]
 
Maple [A] (verified)

Time = 0.09 (sec) , antiderivative size = 178, normalized size of antiderivative = 0.76

method result size
default \(-\frac {\left (a x -1\right ) \sqrt {\frac {c \left (a x -1\right )}{a x}}\, c^{4} \left (-70 a^{\frac {9}{2}} \sqrt {x \left (a x +1\right )}\, x^{4}+105 \ln \left (\frac {2 \sqrt {x \left (a x +1\right )}\, \sqrt {a}+2 a x +1}{2 \sqrt {a}}\right ) a^{4} x^{4}-328 a^{\frac {7}{2}} x^{3} \sqrt {x \left (a x +1\right )}+24 a^{\frac {5}{2}} x^{2} \sqrt {x \left (a x +1\right )}+52 a^{\frac {3}{2}} x \sqrt {x \left (a x +1\right )}-20 \sqrt {x \left (a x +1\right )}\, \sqrt {a}\right )}{70 \left (\frac {a x -1}{a x +1}\right )^{\frac {3}{2}} \left (a x +1\right ) x^{3} a^{\frac {9}{2}} \sqrt {x \left (a x +1\right )}}\) \(178\)
risch \(\frac {\left (35 a^{5} x^{5}+199 a^{4} x^{4}+152 a^{3} x^{3}-38 a^{2} x^{2}-16 a x +10\right ) c^{4} \sqrt {\frac {c \left (a x -1\right )}{a x}}}{35 x^{3} a^{4} \sqrt {\frac {a x -1}{a x +1}}\, \left (a x +1\right )}-\frac {3 \ln \left (\frac {\frac {1}{2} a c +a^{2} c x}{\sqrt {a^{2} c}}+\sqrt {a^{2} c \,x^{2}+a c x}\right ) c^{4} \sqrt {\frac {c \left (a x -1\right )}{a x}}\, \sqrt {\left (a x +1\right ) a c x}}{2 \sqrt {a^{2} c}\, \sqrt {\frac {a x -1}{a x +1}}\, \left (a x +1\right )}\) \(184\)

Input:

int(1/((a*x-1)/(a*x+1))^(3/2)*(c-c/a/x)^(9/2),x,method=_RETURNVERBOSE)
 

Output:

-1/70/((a*x-1)/(a*x+1))^(3/2)*(a*x-1)/(a*x+1)*(c*(a*x-1)/a/x)^(1/2)/x^3*c^ 
4/a^(9/2)*(-70*a^(9/2)*(x*(a*x+1))^(1/2)*x^4+105*ln(1/2*(2*(x*(a*x+1))^(1/ 
2)*a^(1/2)+2*a*x+1)/a^(1/2))*a^4*x^4-328*a^(7/2)*x^3*(x*(a*x+1))^(1/2)+24* 
a^(5/2)*x^2*(x*(a*x+1))^(1/2)+52*a^(3/2)*x*(x*(a*x+1))^(1/2)-20*(x*(a*x+1) 
)^(1/2)*a^(1/2))/(x*(a*x+1))^(1/2)
 

Fricas [A] (verification not implemented)

Time = 0.12 (sec) , antiderivative size = 437, normalized size of antiderivative = 1.86 \[ \int e^{3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{9/2} \, dx=\left [\frac {105 \, {\left (a^{4} c^{4} x^{4} - a^{3} c^{4} x^{3}\right )} \sqrt {c} \log \left (-\frac {8 \, a^{3} c x^{3} - 7 \, a c x - 4 \, {\left (2 \, a^{3} x^{3} + 3 \, a^{2} x^{2} + a x\right )} \sqrt {c} \sqrt {\frac {a x - 1}{a x + 1}} \sqrt {\frac {a c x - c}{a x}} - c}{a x - 1}\right ) + 4 \, {\left (35 \, a^{5} c^{4} x^{5} + 199 \, a^{4} c^{4} x^{4} + 152 \, a^{3} c^{4} x^{3} - 38 \, a^{2} c^{4} x^{2} - 16 \, a c^{4} x + 10 \, c^{4}\right )} \sqrt {\frac {a x - 1}{a x + 1}} \sqrt {\frac {a c x - c}{a x}}}{140 \, {\left (a^{5} x^{4} - a^{4} x^{3}\right )}}, \frac {105 \, {\left (a^{4} c^{4} x^{4} - a^{3} c^{4} x^{3}\right )} \sqrt {-c} \arctan \left (\frac {2 \, {\left (a^{2} x^{2} + a x\right )} \sqrt {-c} \sqrt {\frac {a x - 1}{a x + 1}} \sqrt {\frac {a c x - c}{a x}}}{2 \, a^{2} c x^{2} - a c x - c}\right ) + 2 \, {\left (35 \, a^{5} c^{4} x^{5} + 199 \, a^{4} c^{4} x^{4} + 152 \, a^{3} c^{4} x^{3} - 38 \, a^{2} c^{4} x^{2} - 16 \, a c^{4} x + 10 \, c^{4}\right )} \sqrt {\frac {a x - 1}{a x + 1}} \sqrt {\frac {a c x - c}{a x}}}{70 \, {\left (a^{5} x^{4} - a^{4} x^{3}\right )}}\right ] \] Input:

integrate(1/((a*x-1)/(a*x+1))^(3/2)*(c-c/a/x)^(9/2),x, algorithm="fricas")
 

Output:

[1/140*(105*(a^4*c^4*x^4 - a^3*c^4*x^3)*sqrt(c)*log(-(8*a^3*c*x^3 - 7*a*c* 
x - 4*(2*a^3*x^3 + 3*a^2*x^2 + a*x)*sqrt(c)*sqrt((a*x - 1)/(a*x + 1))*sqrt 
((a*c*x - c)/(a*x)) - c)/(a*x - 1)) + 4*(35*a^5*c^4*x^5 + 199*a^4*c^4*x^4 
+ 152*a^3*c^4*x^3 - 38*a^2*c^4*x^2 - 16*a*c^4*x + 10*c^4)*sqrt((a*x - 1)/( 
a*x + 1))*sqrt((a*c*x - c)/(a*x)))/(a^5*x^4 - a^4*x^3), 1/70*(105*(a^4*c^4 
*x^4 - a^3*c^4*x^3)*sqrt(-c)*arctan(2*(a^2*x^2 + a*x)*sqrt(-c)*sqrt((a*x - 
 1)/(a*x + 1))*sqrt((a*c*x - c)/(a*x))/(2*a^2*c*x^2 - a*c*x - c)) + 2*(35* 
a^5*c^4*x^5 + 199*a^4*c^4*x^4 + 152*a^3*c^4*x^3 - 38*a^2*c^4*x^2 - 16*a*c^ 
4*x + 10*c^4)*sqrt((a*x - 1)/(a*x + 1))*sqrt((a*c*x - c)/(a*x)))/(a^5*x^4 
- a^4*x^3)]
 

Sympy [F(-1)]

Timed out. \[ \int e^{3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{9/2} \, dx=\text {Timed out} \] Input:

integrate(1/((a*x-1)/(a*x+1))**(3/2)*(c-c/a/x)**(9/2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int e^{3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{9/2} \, dx=\int { \frac {{\left (c - \frac {c}{a x}\right )}^{\frac {9}{2}}}{\left (\frac {a x - 1}{a x + 1}\right )^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/((a*x-1)/(a*x+1))^(3/2)*(c-c/a/x)^(9/2),x, algorithm="maxima")
 

Output:

integrate((c - c/(a*x))^(9/2)/((a*x - 1)/(a*x + 1))^(3/2), x)
 

Giac [F]

\[ \int e^{3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{9/2} \, dx=\int { \frac {{\left (c - \frac {c}{a x}\right )}^{\frac {9}{2}}}{\left (\frac {a x - 1}{a x + 1}\right )^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/((a*x-1)/(a*x+1))^(3/2)*(c-c/a/x)^(9/2),x, algorithm="giac")
 

Output:

integrate((c - c/(a*x))^(9/2)/((a*x - 1)/(a*x + 1))^(3/2), x)
 

Mupad [F(-1)]

Timed out. \[ \int e^{3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{9/2} \, dx=\int \frac {{\left (c-\frac {c}{a\,x}\right )}^{9/2}}{{\left (\frac {a\,x-1}{a\,x+1}\right )}^{3/2}} \,d x \] Input:

int((c - c/(a*x))^(9/2)/((a*x - 1)/(a*x + 1))^(3/2),x)
 

Output:

int((c - c/(a*x))^(9/2)/((a*x - 1)/(a*x + 1))^(3/2), x)
 

Reduce [B] (verification not implemented)

Time = 0.17 (sec) , antiderivative size = 123, normalized size of antiderivative = 0.52 \[ \int e^{3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{9/2} \, dx=\frac {\sqrt {c}\, c^{4} \left (35 \sqrt {x}\, \sqrt {a}\, \sqrt {a x +1}\, a^{4} x^{4}+164 \sqrt {x}\, \sqrt {a}\, \sqrt {a x +1}\, a^{3} x^{3}-12 \sqrt {x}\, \sqrt {a}\, \sqrt {a x +1}\, a^{2} x^{2}-26 \sqrt {x}\, \sqrt {a}\, \sqrt {a x +1}\, a x +10 \sqrt {x}\, \sqrt {a}\, \sqrt {a x +1}-105 \,\mathrm {log}\left (\sqrt {a x +1}+\sqrt {x}\, \sqrt {a}\right ) a^{4} x^{4}-99 a^{4} x^{4}\right )}{35 a^{5} x^{4}} \] Input:

int(1/((a*x-1)/(a*x+1))^(3/2)*(c-c/a/x)^(9/2),x)
 

Output:

(sqrt(c)*c**4*(35*sqrt(x)*sqrt(a)*sqrt(a*x + 1)*a**4*x**4 + 164*sqrt(x)*sq 
rt(a)*sqrt(a*x + 1)*a**3*x**3 - 12*sqrt(x)*sqrt(a)*sqrt(a*x + 1)*a**2*x**2 
 - 26*sqrt(x)*sqrt(a)*sqrt(a*x + 1)*a*x + 10*sqrt(x)*sqrt(a)*sqrt(a*x + 1) 
 - 105*log(sqrt(a*x + 1) + sqrt(x)*sqrt(a))*a**4*x**4 - 99*a**4*x**4))/(35 
*a**5*x**4)