Integrand size = 24, antiderivative size = 232 \[ \int e^{-3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{7/2} \, dx=\frac {1049 c^4 \sqrt {1-\frac {1}{a^2 x^2}}}{15 a \sqrt {c-\frac {c}{a x}}}+\frac {311 c^3 \sqrt {1-\frac {1}{a^2 x^2}} \sqrt {c-\frac {c}{a x}}}{15 a}+\frac {47 c^2 \sqrt {1-\frac {1}{a^2 x^2}} \left (c-\frac {c}{a x}\right )^{3/2}}{5 a}+\frac {10 \left (c-\frac {c}{a x}\right )^{7/2}}{a \sqrt {1-\frac {1}{a^2 x^2}}}+\frac {\left (c-\frac {c}{a x}\right )^{9/2} x}{c \sqrt {1-\frac {1}{a^2 x^2}}}-\frac {13 c^{7/2} \text {arctanh}\left (\frac {\sqrt {c} \sqrt {1-\frac {1}{a^2 x^2}}}{\sqrt {c-\frac {c}{a x}}}\right )}{a} \] Output:
1049/15*c^4*(1-1/a^2/x^2)^(1/2)/a/(c-c/a/x)^(1/2)+311/15*c^3*(1-1/a^2/x^2) ^(1/2)*(c-c/a/x)^(1/2)/a+47/5*c^2*(1-1/a^2/x^2)^(1/2)*(c-c/a/x)^(3/2)/a+10 *(c-c/a/x)^(7/2)/a/(1-1/a^2/x^2)^(1/2)+(c-c/a/x)^(9/2)*x/c/(1-1/a^2/x^2)^( 1/2)-13*c^(7/2)*arctanh(c^(1/2)*(1-1/a^2/x^2)^(1/2)/(c-c/a/x)^(1/2))/a
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.13 (sec) , antiderivative size = 132, normalized size of antiderivative = 0.57 \[ \int e^{-3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{7/2} \, dx=\frac {c^3 \sqrt {c-\frac {c}{a x}} \left (6-62 a x+548 a^2 x^2+1441 a^3 x^3+15 a^4 x^4-45 a^3 \sqrt {1+\frac {1}{a x}} x^3 \text {arctanh}\left (\sqrt {1+\frac {1}{a x}}\right )+150 a^3 x^3 \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1,\frac {1}{2},1+\frac {1}{a x}\right )\right )}{15 a^4 \sqrt {1-\frac {1}{a^2 x^2}} x^3} \] Input:
Integrate[(c - c/(a*x))^(7/2)/E^(3*ArcCoth[a*x]),x]
Output:
(c^3*Sqrt[c - c/(a*x)]*(6 - 62*a*x + 548*a^2*x^2 + 1441*a^3*x^3 + 15*a^4*x ^4 - 45*a^3*Sqrt[1 + 1/(a*x)]*x^3*ArcTanh[Sqrt[1 + 1/(a*x)]] + 150*a^3*x^3 *Hypergeometric2F1[-1/2, 1, 1/2, 1 + 1/(a*x)]))/(15*a^4*Sqrt[1 - 1/(a^2*x^ 2)]*x^3)
Time = 0.67 (sec) , antiderivative size = 177, normalized size of antiderivative = 0.76, number of steps used = 13, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6731, 585, 27, 109, 27, 167, 27, 170, 27, 164, 73, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \left (c-\frac {c}{a x}\right )^{7/2} e^{-3 \coth ^{-1}(a x)} \, dx\) |
| \(\Big \downarrow \) 6731 |
| \(\displaystyle -\frac {\int \frac {\left (c-\frac {c}{a x}\right )^{13/2} x^2}{\left (1-\frac {1}{a^2 x^2}\right )^{3/2}}d\frac {1}{x}}{c^3}\) |
| \(\Big \downarrow \) 585 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \int \frac {\left (a-\frac {1}{x}\right )^5 x^2}{a^5 \left (1+\frac {1}{a x}\right )^{3/2}}d\frac {1}{x}}{\sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \int \frac {\left (a-\frac {1}{x}\right )^5 x^2}{\left (1+\frac {1}{a x}\right )^{3/2}}d\frac {1}{x}}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 109 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \left (-\int \frac {\left (a-\frac {1}{x}\right )^3 \left (13 a+\frac {3}{x}\right ) x}{2 \left (1+\frac {1}{a x}\right )^{3/2}}d\frac {1}{x}-\frac {a x \left (a-\frac {1}{x}\right )^4}{\sqrt {\frac {1}{a x}+1}}\right )}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \left (-\frac {1}{2} \int \frac {\left (a-\frac {1}{x}\right )^3 \left (13 a+\frac {3}{x}\right ) x}{\left (1+\frac {1}{a x}\right )^{3/2}}d\frac {1}{x}-\frac {a x \left (a-\frac {1}{x}\right )^4}{\sqrt {\frac {1}{a x}+1}}\right )}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 167 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \left (\frac {1}{2} \left (2 a \int -\frac {\left (a-\frac {1}{x}\right )^2 \left (13 a+\frac {47}{x}\right ) x}{2 \sqrt {1+\frac {1}{a x}}}d\frac {1}{x}-\frac {20 a \left (a-\frac {1}{x}\right )^3}{\sqrt {\frac {1}{a x}+1}}\right )-\frac {a x \left (a-\frac {1}{x}\right )^4}{\sqrt {\frac {1}{a x}+1}}\right )}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \left (\frac {1}{2} \left (-a \int \frac {\left (a-\frac {1}{x}\right )^2 \left (13 a+\frac {47}{x}\right ) x}{\sqrt {1+\frac {1}{a x}}}d\frac {1}{x}-\frac {20 a \left (a-\frac {1}{x}\right )^3}{\sqrt {\frac {1}{a x}+1}}\right )-\frac {a x \left (a-\frac {1}{x}\right )^4}{\sqrt {\frac {1}{a x}+1}}\right )}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 170 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \left (\frac {1}{2} \left (-a \left (\frac {2}{5} a \int \frac {\left (a-\frac {1}{x}\right ) \left (65 a+\frac {311}{x}\right ) x}{2 \sqrt {1+\frac {1}{a x}}}d\frac {1}{x}+\frac {94}{5} a \sqrt {\frac {1}{a x}+1} \left (a-\frac {1}{x}\right )^2\right )-\frac {20 a \left (a-\frac {1}{x}\right )^3}{\sqrt {\frac {1}{a x}+1}}\right )-\frac {a x \left (a-\frac {1}{x}\right )^4}{\sqrt {\frac {1}{a x}+1}}\right )}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \left (\frac {1}{2} \left (-a \left (\frac {1}{5} a \int \frac {\left (a-\frac {1}{x}\right ) \left (65 a+\frac {311}{x}\right ) x}{\sqrt {1+\frac {1}{a x}}}d\frac {1}{x}+\frac {94}{5} a \sqrt {\frac {1}{a x}+1} \left (a-\frac {1}{x}\right )^2\right )-\frac {20 a \left (a-\frac {1}{x}\right )^3}{\sqrt {\frac {1}{a x}+1}}\right )-\frac {a x \left (a-\frac {1}{x}\right )^4}{\sqrt {\frac {1}{a x}+1}}\right )}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 164 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \left (\frac {1}{2} \left (-a \left (\frac {1}{5} a \left (65 a^2 \int \frac {x}{\sqrt {1+\frac {1}{a x}}}d\frac {1}{x}+\frac {2}{3} a \left (1360 a-\frac {311}{x}\right ) \sqrt {\frac {1}{a x}+1}\right )+\frac {94}{5} a \sqrt {\frac {1}{a x}+1} \left (a-\frac {1}{x}\right )^2\right )-\frac {20 a \left (a-\frac {1}{x}\right )^3}{\sqrt {\frac {1}{a x}+1}}\right )-\frac {a x \left (a-\frac {1}{x}\right )^4}{\sqrt {\frac {1}{a x}+1}}\right )}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 73 |
| \(\displaystyle -\frac {c^3 \sqrt {c-\frac {c}{a x}} \left (\frac {1}{2} \left (-a \left (\frac {1}{5} a \left (130 a^3 \int \frac {1}{\frac {a}{x^2}-a}d\sqrt {1+\frac {1}{a x}}+\frac {2}{3} a \left (1360 a-\frac {311}{x}\right ) \sqrt {\frac {1}{a x}+1}\right )+\frac {94}{5} a \sqrt {\frac {1}{a x}+1} \left (a-\frac {1}{x}\right )^2\right )-\frac {20 a \left (a-\frac {1}{x}\right )^3}{\sqrt {\frac {1}{a x}+1}}\right )-\frac {a x \left (a-\frac {1}{x}\right )^4}{\sqrt {\frac {1}{a x}+1}}\right )}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
| \(\Big \downarrow \) 221 |
| \(\displaystyle -\frac {c^3 \left (\frac {1}{2} \left (-a \left (\frac {1}{5} a \left (\frac {2}{3} a \left (1360 a-\frac {311}{x}\right ) \sqrt {\frac {1}{a x}+1}-130 a^2 \text {arctanh}\left (\sqrt {\frac {1}{a x}+1}\right )\right )+\frac {94}{5} a \sqrt {\frac {1}{a x}+1} \left (a-\frac {1}{x}\right )^2\right )-\frac {20 a \left (a-\frac {1}{x}\right )^3}{\sqrt {\frac {1}{a x}+1}}\right )-\frac {a x \left (a-\frac {1}{x}\right )^4}{\sqrt {\frac {1}{a x}+1}}\right ) \sqrt {c-\frac {c}{a x}}}{a^5 \sqrt {1-\frac {1}{a x}}}\) |
Input:
Int[(c - c/(a*x))^(7/2)/E^(3*ArcCoth[a*x]),x]
Output:
-((c^3*Sqrt[c - c/(a*x)]*(-((a*(a - x^(-1))^4*x)/Sqrt[1 + 1/(a*x)]) + ((-2 0*a*(a - x^(-1))^3)/Sqrt[1 + 1/(a*x)] - a*((94*a*(a - x^(-1))^2*Sqrt[1 + 1 /(a*x)])/5 + (a*((2*a*(1360*a - 311/x)*Sqrt[1 + 1/(a*x)])/3 - 130*a^2*ArcT anh[Sqrt[1 + 1/(a*x)]]))/5))/2))/(a^5*Sqrt[1 - 1/(a*x)]))
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[(b*c - a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*((e + f *x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] + Simp[1/(b*(b*e - a*f)*(m + 1)) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_ ))*((g_.) + (h_.)*(x_)), x_] :> Simp[(-(a*d*f*h*(n + 2) + b*c*f*h*(m + 2) - b*d*(f*g + e*h)*(m + n + 3) - b*d*f*h*(m + n + 2)*x))*(a + b*x)^(m + 1)*(( c + d*x)^(n + 1)/(b^2*d^2*(m + n + 2)*(m + n + 3))), x] + Simp[(a^2*d^2*f*h *(n + 1)*(n + 2) + a*b*d*(n + 1)*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(m + n + 3)) + b^2*(c^2*f*h*(m + 1)*(m + 2) - c*d*(f*g + e*h)*(m + 1)*(m + n + 3) + d^2*e*g*(m + n + 2)*(m + n + 3)))/(b^2*d^2*(m + n + 2)*(m + n + 3)) Int[( a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] && NeQ[m + n + 2, 0] && NeQ[m + n + 3, 0]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] - Simp[1/(b*(b*e - a*f)*(m + 1)) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b* c*(f*g - e*h)*(m + 1) + (b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h )*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegersQ[2*m, 2*n, 2*p]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[h*(a + b*x)^m*(c + d*x)^(n + 1)*(( e + f*x)^(p + 1)/(d*f*(m + n + p + 2))), x] + Simp[1/(d*f*(m + n + p + 2)) Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2 ) - h*(b*c*e*m + a*(d*e*(n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x], x], x] /; Fre eQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegerQ[m]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[((e_.)*(x_))^(m_.)*((c_) + (d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_)^2)^(p_) , x_Symbol] :> Simp[a^p*c^IntPart[n]*((c + d*x)^FracPart[n]/(1 + d*(x/c))^F racPart[n]) Int[(e*x)^m*(1 - d*(x/c))^p*(1 + d*(x/c))^(n + p), x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && EqQ[b*c^2 + a*d^2, 0] && GtQ[a, 0]
Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*((c_) + (d_.)/(x_))^(p_.), x_Symbol] :> S imp[-c^n Subst[Int[(c + d*x)^(p - n)*((1 - x^2/a^2)^(n/2)/x^2), x], x, 1/ x], x] /; FreeQ[{a, c, d, p}, x] && EqQ[c + a*d, 0] && IntegerQ[(n - 1)/2] && IntegerQ[2*p]
Time = 0.14 (sec) , antiderivative size = 212, normalized size of antiderivative = 0.91
| method | result | size |
| default | \(\frac {\left (\frac {a x -1}{a x +1}\right )^{\frac {3}{2}} \left (a x +1\right ) \sqrt {\frac {c \left (a x -1\right )}{a x}}\, c^{3} \left (30 a^{\frac {9}{2}} \sqrt {x \left (a x +1\right )}\, x^{4}+3182 a^{\frac {7}{2}} x^{3} \sqrt {x \left (a x +1\right )}-195 \ln \left (\frac {2 \sqrt {x \left (a x +1\right )}\, \sqrt {a}+2 a x +1}{2 \sqrt {a}}\right ) a^{4} x^{4}+1096 a^{\frac {5}{2}} x^{2} \sqrt {x \left (a x +1\right )}-195 \ln \left (\frac {2 \sqrt {x \left (a x +1\right )}\, \sqrt {a}+2 a x +1}{2 \sqrt {a}}\right ) a^{3} x^{3}-124 a^{\frac {3}{2}} x \sqrt {x \left (a x +1\right )}+12 \sqrt {x \left (a x +1\right )}\, \sqrt {a}\right )}{30 \left (a x -1\right )^{2} x^{2} a^{\frac {7}{2}} \sqrt {x \left (a x +1\right )}}\) | \(212\) |
| risch | \(\frac {\left (15 a^{4} x^{4}+631 a^{3} x^{3}+548 a^{2} x^{2}-62 a x +6\right ) c^{3} \sqrt {\frac {a x -1}{a x +1}}\, \sqrt {\frac {c \left (a x -1\right )}{a x}}}{15 x^{2} a^{3} \left (a x -1\right )}+\frac {\left (-\frac {13 a^{3} \ln \left (\frac {\frac {1}{2} a c +a^{2} c x}{\sqrt {a^{2} c}}+\sqrt {a^{2} c \,x^{2}+a c x}\right )}{2 \sqrt {a^{2} c}}+\frac {64 a \sqrt {\left (x +\frac {1}{a}\right )^{2} a^{2} c -\left (x +\frac {1}{a}\right ) a c}}{c \left (x +\frac {1}{a}\right )}\right ) c^{3} \sqrt {\frac {a x -1}{a x +1}}\, \sqrt {\frac {c \left (a x -1\right )}{a x}}\, \sqrt {\left (a x +1\right ) a c x}}{a^{3} \left (a x -1\right )}\) | \(221\) |
Input:
int((c-c/a/x)^(7/2)*((a*x-1)/(a*x+1))^(3/2),x,method=_RETURNVERBOSE)
Output:
1/30*((a*x-1)/(a*x+1))^(3/2)/(a*x-1)^2*(a*x+1)*(c*(a*x-1)/a/x)^(1/2)*c^3*( 30*a^(9/2)*(x*(a*x+1))^(1/2)*x^4+3182*a^(7/2)*x^3*(x*(a*x+1))^(1/2)-195*ln (1/2*(2*(x*(a*x+1))^(1/2)*a^(1/2)+2*a*x+1)/a^(1/2))*a^4*x^4+1096*a^(5/2)*x ^2*(x*(a*x+1))^(1/2)-195*ln(1/2*(2*(x*(a*x+1))^(1/2)*a^(1/2)+2*a*x+1)/a^(1 /2))*a^3*x^3-124*a^(3/2)*x*(x*(a*x+1))^(1/2)+12*(x*(a*x+1))^(1/2)*a^(1/2)) /x^2/a^(7/2)/(x*(a*x+1))^(1/2)
Time = 0.15 (sec) , antiderivative size = 415, normalized size of antiderivative = 1.79 \[ \int e^{-3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{7/2} \, dx=\left [\frac {195 \, {\left (a^{3} c^{3} x^{3} - a^{2} c^{3} x^{2}\right )} \sqrt {c} \log \left (-\frac {8 \, a^{3} c x^{3} - 7 \, a c x - 4 \, {\left (2 \, a^{3} x^{3} + 3 \, a^{2} x^{2} + a x\right )} \sqrt {c} \sqrt {\frac {a x - 1}{a x + 1}} \sqrt {\frac {a c x - c}{a x}} - c}{a x - 1}\right ) + 4 \, {\left (15 \, a^{4} c^{3} x^{4} + 1591 \, a^{3} c^{3} x^{3} + 548 \, a^{2} c^{3} x^{2} - 62 \, a c^{3} x + 6 \, c^{3}\right )} \sqrt {\frac {a x - 1}{a x + 1}} \sqrt {\frac {a c x - c}{a x}}}{60 \, {\left (a^{4} x^{3} - a^{3} x^{2}\right )}}, \frac {195 \, {\left (a^{3} c^{3} x^{3} - a^{2} c^{3} x^{2}\right )} \sqrt {-c} \arctan \left (\frac {2 \, {\left (a^{2} x^{2} + a x\right )} \sqrt {-c} \sqrt {\frac {a x - 1}{a x + 1}} \sqrt {\frac {a c x - c}{a x}}}{2 \, a^{2} c x^{2} - a c x - c}\right ) + 2 \, {\left (15 \, a^{4} c^{3} x^{4} + 1591 \, a^{3} c^{3} x^{3} + 548 \, a^{2} c^{3} x^{2} - 62 \, a c^{3} x + 6 \, c^{3}\right )} \sqrt {\frac {a x - 1}{a x + 1}} \sqrt {\frac {a c x - c}{a x}}}{30 \, {\left (a^{4} x^{3} - a^{3} x^{2}\right )}}\right ] \] Input:
integrate((c-c/a/x)^(7/2)*((a*x-1)/(a*x+1))^(3/2),x, algorithm="fricas")
Output:
[1/60*(195*(a^3*c^3*x^3 - a^2*c^3*x^2)*sqrt(c)*log(-(8*a^3*c*x^3 - 7*a*c*x - 4*(2*a^3*x^3 + 3*a^2*x^2 + a*x)*sqrt(c)*sqrt((a*x - 1)/(a*x + 1))*sqrt( (a*c*x - c)/(a*x)) - c)/(a*x - 1)) + 4*(15*a^4*c^3*x^4 + 1591*a^3*c^3*x^3 + 548*a^2*c^3*x^2 - 62*a*c^3*x + 6*c^3)*sqrt((a*x - 1)/(a*x + 1))*sqrt((a* c*x - c)/(a*x)))/(a^4*x^3 - a^3*x^2), 1/30*(195*(a^3*c^3*x^3 - a^2*c^3*x^2 )*sqrt(-c)*arctan(2*(a^2*x^2 + a*x)*sqrt(-c)*sqrt((a*x - 1)/(a*x + 1))*sqr t((a*c*x - c)/(a*x))/(2*a^2*c*x^2 - a*c*x - c)) + 2*(15*a^4*c^3*x^4 + 1591 *a^3*c^3*x^3 + 548*a^2*c^3*x^2 - 62*a*c^3*x + 6*c^3)*sqrt((a*x - 1)/(a*x + 1))*sqrt((a*c*x - c)/(a*x)))/(a^4*x^3 - a^3*x^2)]
Timed out. \[ \int e^{-3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{7/2} \, dx=\text {Timed out} \] Input:
integrate((c-c/a/x)**(7/2)*((a*x-1)/(a*x+1))**(3/2),x)
Output:
Timed out
\[ \int e^{-3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{7/2} \, dx=\int { {\left (c - \frac {c}{a x}\right )}^{\frac {7}{2}} \left (\frac {a x - 1}{a x + 1}\right )^{\frac {3}{2}} \,d x } \] Input:
integrate((c-c/a/x)^(7/2)*((a*x-1)/(a*x+1))^(3/2),x, algorithm="maxima")
Output:
integrate((c - c/(a*x))^(7/2)*((a*x - 1)/(a*x + 1))^(3/2), x)
Exception generated. \[ \int e^{-3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{7/2} \, dx=\text {Exception raised: TypeError} \] Input:
integrate((c-c/a/x)^(7/2)*((a*x-1)/(a*x+1))^(3/2),x, algorithm="giac")
Output:
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value
Timed out. \[ \int e^{-3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{7/2} \, dx=\int {\left (c-\frac {c}{a\,x}\right )}^{7/2}\,{\left (\frac {a\,x-1}{a\,x+1}\right )}^{3/2} \,d x \] Input:
int((c - c/(a*x))^(7/2)*((a*x - 1)/(a*x + 1))^(3/2),x)
Output:
int((c - c/(a*x))^(7/2)*((a*x - 1)/(a*x + 1))^(3/2), x)
Time = 0.16 (sec) , antiderivative size = 113, normalized size of antiderivative = 0.49 \[ \int e^{-3 \coth ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^{7/2} \, dx=\frac {\sqrt {c}\, c^{3} \left (-780 \sqrt {a x +1}\, \mathrm {log}\left (\sqrt {a x +1}+\sqrt {x}\, \sqrt {a}\right ) a^{3} x^{3}-7249 \sqrt {a x +1}\, a^{3} x^{3}+60 \sqrt {x}\, \sqrt {a}\, a^{4} x^{4}+6364 \sqrt {x}\, \sqrt {a}\, a^{3} x^{3}+2192 \sqrt {x}\, \sqrt {a}\, a^{2} x^{2}-248 \sqrt {x}\, \sqrt {a}\, a x +24 \sqrt {x}\, \sqrt {a}\right )}{60 \sqrt {a x +1}\, a^{4} x^{3}} \] Input:
int((c-c/a/x)^(7/2)*((a*x-1)/(a*x+1))^(3/2),x)
Output:
(sqrt(c)*c**3*( - 780*sqrt(a*x + 1)*log(sqrt(a*x + 1) + sqrt(x)*sqrt(a))*a **3*x**3 - 7249*sqrt(a*x + 1)*a**3*x**3 + 60*sqrt(x)*sqrt(a)*a**4*x**4 + 6 364*sqrt(x)*sqrt(a)*a**3*x**3 + 2192*sqrt(x)*sqrt(a)*a**2*x**2 - 248*sqrt( x)*sqrt(a)*a*x + 24*sqrt(x)*sqrt(a)))/(60*sqrt(a*x + 1)*a**4*x**3)