\(\int \frac {e^{2 \coth ^{-1}(a x)}}{(c-\frac {c}{a^2 x^2})^4} \, dx\) [764]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [A] (verification not implemented)
Sympy [A] (verification not implemented)
Maxima [A] (verification not implemented)
Giac [A] (verification not implemented)
Mupad [B] (verification not implemented)
Reduce [B] (verification not implemented)

Optimal result

Integrand size = 22, antiderivative size = 145 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {x}{c^4}-\frac {1}{32 a c^4 (1-a x)^4}+\frac {13}{48 a c^4 (1-a x)^3}-\frac {35}{32 a c^4 (1-a x)^2}+\frac {99}{32 a c^4 (1-a x)}+\frac {1}{64 a c^4 (1+a x)^2}-\frac {11}{64 a c^4 (1+a x)}+\frac {303 \log (1-a x)}{128 a c^4}-\frac {47 \log (1+a x)}{128 a c^4} \] Output:

x/c^4-1/32/a/c^4/(-a*x+1)^4+13/48/a/c^4/(-a*x+1)^3-35/32/a/c^4/(-a*x+1)^2+ 
99/32/a/c^4/(-a*x+1)+1/64/a/c^4/(a*x+1)^2-11/64/a/c^4/(a*x+1)+303/128*ln(- 
a*x+1)/a/c^4-47/128*ln(a*x+1)/a/c^4
                                                                                    
                                                                                    
 

Mathematica [A] (verified)

Time = 0.13 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.68 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {\frac {2 \left (400-275 a x-1258 a^2 x^2+866 a^3 x^3+1254 a^4 x^4-819 a^5 x^5-384 a^6 x^6+192 a^7 x^7\right )}{(-1+a x)^4 (1+a x)^2}+909 \log (1-a x)-141 \log (1+a x)}{384 a c^4} \] Input:

Integrate[E^(2*ArcCoth[a*x])/(c - c/(a^2*x^2))^4,x]
 

Output:

((2*(400 - 275*a*x - 1258*a^2*x^2 + 866*a^3*x^3 + 1254*a^4*x^4 - 819*a^5*x 
^5 - 384*a^6*x^6 + 192*a^7*x^7))/((-1 + a*x)^4*(1 + a*x)^2) + 909*Log[1 - 
a*x] - 141*Log[1 + a*x])/(384*a*c^4)
 

Rubi [A] (verified)

Time = 0.93 (sec) , antiderivative size = 130, normalized size of antiderivative = 0.90, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {6717, 27, 6707, 6700, 99, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx\)

\(\Big \downarrow \) 6717

\(\displaystyle -\int \frac {a^8 e^{2 \text {arctanh}(a x)}}{c^4 \left (a^2-\frac {1}{x^2}\right )^4}dx\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {a^8 \int \frac {e^{2 \text {arctanh}(a x)}}{\left (a^2-\frac {1}{x^2}\right )^4}dx}{c^4}\)

\(\Big \downarrow \) 6707

\(\displaystyle -\frac {a^8 \int \frac {e^{2 \text {arctanh}(a x)} x^8}{\left (1-a^2 x^2\right )^4}dx}{c^4}\)

\(\Big \downarrow \) 6700

\(\displaystyle -\frac {a^8 \int \frac {x^8}{(1-a x)^5 (a x+1)^3}dx}{c^4}\)

\(\Big \downarrow \) 99

\(\displaystyle -\frac {a^8 \int \left (\frac {47}{128 a^8 (a x+1)}-\frac {11}{64 a^8 (a x+1)^2}+\frac {1}{32 a^8 (a x+1)^3}-\frac {1}{a^8}-\frac {303}{128 a^8 (a x-1)}-\frac {99}{32 a^8 (a x-1)^2}-\frac {35}{16 a^8 (a x-1)^3}-\frac {13}{16 a^8 (a x-1)^4}-\frac {1}{8 a^8 (a x-1)^5}\right )dx}{c^4}\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {a^8 \left (-\frac {99}{32 a^9 (1-a x)}+\frac {11}{64 a^9 (a x+1)}+\frac {35}{32 a^9 (1-a x)^2}-\frac {1}{64 a^9 (a x+1)^2}-\frac {13}{48 a^9 (1-a x)^3}+\frac {1}{32 a^9 (1-a x)^4}-\frac {303 \log (1-a x)}{128 a^9}+\frac {47 \log (a x+1)}{128 a^9}-\frac {x}{a^8}\right )}{c^4}\)

Input:

Int[E^(2*ArcCoth[a*x])/(c - c/(a^2*x^2))^4,x]
 

Output:

-((a^8*(-(x/a^8) + 1/(32*a^9*(1 - a*x)^4) - 13/(48*a^9*(1 - a*x)^3) + 35/( 
32*a^9*(1 - a*x)^2) - 99/(32*a^9*(1 - a*x)) - 1/(64*a^9*(1 + a*x)^2) + 11/ 
(64*a^9*(1 + a*x)) - (303*Log[1 - a*x])/(128*a^9) + (47*Log[1 + a*x])/(128 
*a^9)))/c^4)
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 99
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], 
 x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | 
| (GtQ[m, 0] && GeQ[n, -1]))
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 6700
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x 
_Symbol] :> Simp[c^p   Int[x^m*(1 - a*x)^(p - n/2)*(1 + a*x)^(p + n/2), x], 
 x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || 
 GtQ[c, 0])
 

rule 6707
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_.), x_Symb 
ol] :> Simp[d^p   Int[(u/x^(2*p))*(1 - a^2*x^2)^p*E^(n*ArcTanh[a*x]), x], x 
] /; FreeQ[{a, c, d, n}, x] && EqQ[c + a^2*d, 0] && IntegerQ[p]
 

rule 6717
Int[E^(ArcCoth[(a_.)*(x_)]*(n_))*(u_.), x_Symbol] :> Simp[(-1)^(n/2)   Int[ 
u*E^(n*ArcTanh[a*x]), x], x] /; FreeQ[a, x] && IntegerQ[n/2]
 
Maple [A] (verified)

Time = 0.17 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.74

method result size
default \(\frac {a^{8} \left (\frac {x}{a^{8}}-\frac {47 \ln \left (a x +1\right )}{128 a^{9}}+\frac {1}{64 a^{9} \left (a x +1\right )^{2}}-\frac {11}{64 a^{9} \left (a x +1\right )}-\frac {13}{48 a^{9} \left (a x -1\right )^{3}}-\frac {35}{32 a^{9} \left (a x -1\right )^{2}}-\frac {99}{32 a^{9} \left (a x -1\right )}+\frac {303 \ln \left (a x -1\right )}{128 a^{9}}-\frac {1}{32 a^{9} \left (a x -1\right )^{4}}\right )}{c^{4}}\) \(108\)
risch \(\frac {x}{c^{4}}+\frac {-\frac {209 a^{4} c^{4} x^{5}}{64}+\frac {81 a^{3} c^{4} x^{4}}{32}+\frac {529 a^{2} c^{4} x^{3}}{96}-\frac {437 a \,c^{4} x^{2}}{96}-\frac {467 c^{4} x}{192}+\frac {25 c^{4}}{12 a}}{c^{8} \left (a x -1\right )^{2} \left (a^{2} x^{2}-1\right )^{2}}+\frac {303 \ln \left (-a x +1\right )}{128 a \,c^{4}}-\frac {47 \ln \left (a x +1\right )}{128 a \,c^{4}}\) \(115\)
norman \(\frac {\frac {a^{7} x^{8}}{c}+\frac {175 x}{64 c}-\frac {111 a \,x^{2}}{64 c}-\frac {199 a^{2} x^{3}}{24 c}+\frac {115 a^{3} x^{4}}{24 c}+\frac {545 a^{4} x^{5}}{64 c}-\frac {803 a^{5} x^{6}}{192 c}-\frac {37 a^{6} x^{7}}{12 c}}{c^{3} \left (a x -1\right )^{4} \left (a x +1\right )^{3}}+\frac {303 \ln \left (a x -1\right )}{128 a \,c^{4}}-\frac {47 \ln \left (a x +1\right )}{128 a \,c^{4}}\) \(129\)
parallelrisch \(\frac {-1468 a^{3} x^{3}+1050 a x +3308 a^{4} x^{4}-38 a^{5} x^{5}-1568 x^{6} a^{6}+282 \ln \left (a x +1\right ) x a +384 a^{7} x^{7}-141 \ln \left (a x +1\right )-1716 a^{2} x^{2}+909 \ln \left (a x -1\right )+141 \ln \left (a x +1\right ) x^{2} a^{2}-909 \ln \left (a x -1\right ) x^{4} a^{4}+141 \ln \left (a x +1\right ) x^{4} a^{4}-564 \ln \left (a x +1\right ) x^{3} a^{3}-1818 a \ln \left (a x -1\right ) x +3636 a^{3} \ln \left (a x -1\right ) x^{3}-1818 \ln \left (a x -1\right ) x^{5} a^{5}+282 \ln \left (a x +1\right ) x^{5} a^{5}-909 a^{2} \ln \left (a x -1\right ) x^{2}+909 \ln \left (a x -1\right ) x^{6} a^{6}-141 \ln \left (a x +1\right ) x^{6} a^{6}}{384 c^{4} \left (a x -1\right )^{2} \left (a^{2} x^{2}-1\right )^{2} a}\) \(256\)

Input:

int(1/(a*x-1)*(a*x+1)/(c-c/a^2/x^2)^4,x,method=_RETURNVERBOSE)
 

Output:

a^8/c^4*(x/a^8-47/128/a^9*ln(a*x+1)+1/64/a^9/(a*x+1)^2-11/64/a^9/(a*x+1)-1 
3/48/a^9/(a*x-1)^3-35/32/a^9/(a*x-1)^2-99/32/a^9/(a*x-1)+303/128/a^9*ln(a* 
x-1)-1/32/a^9/(a*x-1)^4)
 

Fricas [A] (verification not implemented)

Time = 0.08 (sec) , antiderivative size = 233, normalized size of antiderivative = 1.61 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {384 \, a^{7} x^{7} - 768 \, a^{6} x^{6} - 1638 \, a^{5} x^{5} + 2508 \, a^{4} x^{4} + 1732 \, a^{3} x^{3} - 2516 \, a^{2} x^{2} - 550 \, a x - 141 \, {\left (a^{6} x^{6} - 2 \, a^{5} x^{5} - a^{4} x^{4} + 4 \, a^{3} x^{3} - a^{2} x^{2} - 2 \, a x + 1\right )} \log \left (a x + 1\right ) + 909 \, {\left (a^{6} x^{6} - 2 \, a^{5} x^{5} - a^{4} x^{4} + 4 \, a^{3} x^{3} - a^{2} x^{2} - 2 \, a x + 1\right )} \log \left (a x - 1\right ) + 800}{384 \, {\left (a^{7} c^{4} x^{6} - 2 \, a^{6} c^{4} x^{5} - a^{5} c^{4} x^{4} + 4 \, a^{4} c^{4} x^{3} - a^{3} c^{4} x^{2} - 2 \, a^{2} c^{4} x + a c^{4}\right )}} \] Input:

integrate(1/(a*x-1)*(a*x+1)/(c-c/a^2/x^2)^4,x, algorithm="fricas")
 

Output:

1/384*(384*a^7*x^7 - 768*a^6*x^6 - 1638*a^5*x^5 + 2508*a^4*x^4 + 1732*a^3* 
x^3 - 2516*a^2*x^2 - 550*a*x - 141*(a^6*x^6 - 2*a^5*x^5 - a^4*x^4 + 4*a^3* 
x^3 - a^2*x^2 - 2*a*x + 1)*log(a*x + 1) + 909*(a^6*x^6 - 2*a^5*x^5 - a^4*x 
^4 + 4*a^3*x^3 - a^2*x^2 - 2*a*x + 1)*log(a*x - 1) + 800)/(a^7*c^4*x^6 - 2 
*a^6*c^4*x^5 - a^5*c^4*x^4 + 4*a^4*c^4*x^3 - a^3*c^4*x^2 - 2*a^2*c^4*x + a 
*c^4)
 

Sympy [A] (verification not implemented)

Time = 0.48 (sec) , antiderivative size = 156, normalized size of antiderivative = 1.08 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=a^{8} \left (\frac {- 627 a^{5} x^{5} + 486 a^{4} x^{4} + 1058 a^{3} x^{3} - 874 a^{2} x^{2} - 467 a x + 400}{192 a^{15} c^{4} x^{6} - 384 a^{14} c^{4} x^{5} - 192 a^{13} c^{4} x^{4} + 768 a^{12} c^{4} x^{3} - 192 a^{11} c^{4} x^{2} - 384 a^{10} c^{4} x + 192 a^{9} c^{4}} + \frac {x}{a^{8} c^{4}} + \frac {\frac {303 \log {\left (x - \frac {1}{a} \right )}}{128} - \frac {47 \log {\left (x + \frac {1}{a} \right )}}{128}}{a^{9} c^{4}}\right ) \] Input:

integrate(1/(a*x-1)*(a*x+1)/(c-c/a**2/x**2)**4,x)
 

Output:

a**8*((-627*a**5*x**5 + 486*a**4*x**4 + 1058*a**3*x**3 - 874*a**2*x**2 - 4 
67*a*x + 400)/(192*a**15*c**4*x**6 - 384*a**14*c**4*x**5 - 192*a**13*c**4* 
x**4 + 768*a**12*c**4*x**3 - 192*a**11*c**4*x**2 - 384*a**10*c**4*x + 192* 
a**9*c**4) + x/(a**8*c**4) + (303*log(x - 1/a)/128 - 47*log(x + 1/a)/128)/ 
(a**9*c**4))
 

Maxima [A] (verification not implemented)

Time = 0.04 (sec) , antiderivative size = 145, normalized size of antiderivative = 1.00 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=-\frac {627 \, a^{5} x^{5} - 486 \, a^{4} x^{4} - 1058 \, a^{3} x^{3} + 874 \, a^{2} x^{2} + 467 \, a x - 400}{192 \, {\left (a^{7} c^{4} x^{6} - 2 \, a^{6} c^{4} x^{5} - a^{5} c^{4} x^{4} + 4 \, a^{4} c^{4} x^{3} - a^{3} c^{4} x^{2} - 2 \, a^{2} c^{4} x + a c^{4}\right )}} + \frac {x}{c^{4}} - \frac {47 \, \log \left (a x + 1\right )}{128 \, a c^{4}} + \frac {303 \, \log \left (a x - 1\right )}{128 \, a c^{4}} \] Input:

integrate(1/(a*x-1)*(a*x+1)/(c-c/a^2/x^2)^4,x, algorithm="maxima")
                                                                                    
                                                                                    
 

Output:

-1/192*(627*a^5*x^5 - 486*a^4*x^4 - 1058*a^3*x^3 + 874*a^2*x^2 + 467*a*x - 
 400)/(a^7*c^4*x^6 - 2*a^6*c^4*x^5 - a^5*c^4*x^4 + 4*a^4*c^4*x^3 - a^3*c^4 
*x^2 - 2*a^2*c^4*x + a*c^4) + x/c^4 - 47/128*log(a*x + 1)/(a*c^4) + 303/12 
8*log(a*x - 1)/(a*c^4)
 

Giac [A] (verification not implemented)

Time = 0.12 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.66 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {x}{c^{4}} - \frac {47 \, \log \left ({\left | a x + 1 \right |}\right )}{128 \, a c^{4}} + \frac {303 \, \log \left ({\left | a x - 1 \right |}\right )}{128 \, a c^{4}} - \frac {627 \, a^{5} x^{5} - 486 \, a^{4} x^{4} - 1058 \, a^{3} x^{3} + 874 \, a^{2} x^{2} + 467 \, a x - 400}{192 \, {\left (a x + 1\right )}^{2} {\left (a x - 1\right )}^{4} a c^{4}} \] Input:

integrate(1/(a*x-1)*(a*x+1)/(c-c/a^2/x^2)^4,x, algorithm="giac")
 

Output:

x/c^4 - 47/128*log(abs(a*x + 1))/(a*c^4) + 303/128*log(abs(a*x - 1))/(a*c^ 
4) - 1/192*(627*a^5*x^5 - 486*a^4*x^4 - 1058*a^3*x^3 + 874*a^2*x^2 + 467*a 
*x - 400)/((a*x + 1)^2*(a*x - 1)^4*a*c^4)
 

Mupad [B] (verification not implemented)

Time = 13.14 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.98 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {x}{c^4}+\frac {\frac {467\,x}{192}+\frac {437\,a\,x^2}{96}-\frac {25}{12\,a}-\frac {529\,a^2\,x^3}{96}-\frac {81\,a^3\,x^4}{32}+\frac {209\,a^4\,x^5}{64}}{-a^6\,c^4\,x^6+2\,a^5\,c^4\,x^5+a^4\,c^4\,x^4-4\,a^3\,c^4\,x^3+a^2\,c^4\,x^2+2\,a\,c^4\,x-c^4}+\frac {303\,\ln \left (a\,x-1\right )}{128\,a\,c^4}-\frac {47\,\ln \left (a\,x+1\right )}{128\,a\,c^4} \] Input:

int((a*x + 1)/((c - c/(a^2*x^2))^4*(a*x - 1)),x)
 

Output:

x/c^4 + ((467*x)/192 + (437*a*x^2)/96 - 25/(12*a) - (529*a^2*x^3)/96 - (81 
*a^3*x^4)/32 + (209*a^4*x^5)/64)/(a^2*c^4*x^2 - c^4 - 4*a^3*c^4*x^3 + a^4* 
c^4*x^4 + 2*a^5*c^4*x^5 - a^6*c^4*x^6 + 2*a*c^4*x) + (303*log(a*x - 1))/(1 
28*a*c^4) - (47*log(a*x + 1))/(128*a*c^4)
 

Reduce [B] (verification not implemented)

Time = 0.16 (sec) , antiderivative size = 277, normalized size of antiderivative = 1.91 \[ \int \frac {e^{2 \coth ^{-1}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^4} \, dx=\frac {909 \,\mathrm {log}\left (a x -1\right ) a^{6} x^{6}-1818 \,\mathrm {log}\left (a x -1\right ) a^{5} x^{5}-909 \,\mathrm {log}\left (a x -1\right ) a^{4} x^{4}+3636 \,\mathrm {log}\left (a x -1\right ) a^{3} x^{3}-909 \,\mathrm {log}\left (a x -1\right ) a^{2} x^{2}-1818 \,\mathrm {log}\left (a x -1\right ) a x +909 \,\mathrm {log}\left (a x -1\right )-141 \,\mathrm {log}\left (a x +1\right ) a^{6} x^{6}+282 \,\mathrm {log}\left (a x +1\right ) a^{5} x^{5}+141 \,\mathrm {log}\left (a x +1\right ) a^{4} x^{4}-564 \,\mathrm {log}\left (a x +1\right ) a^{3} x^{3}+141 \,\mathrm {log}\left (a x +1\right ) a^{2} x^{2}+282 \,\mathrm {log}\left (a x +1\right ) a x -141 \,\mathrm {log}\left (a x +1\right )+384 a^{7} x^{7}-1587 a^{6} x^{6}+3327 a^{4} x^{4}-1544 a^{3} x^{3}-1697 a^{2} x^{2}+1088 a x -19}{384 a \,c^{4} \left (a^{6} x^{6}-2 a^{5} x^{5}-a^{4} x^{4}+4 a^{3} x^{3}-a^{2} x^{2}-2 a x +1\right )} \] Input:

int(1/(a*x-1)*(a*x+1)/(c-c/a^2/x^2)^4,x)
 

Output:

(909*log(a*x - 1)*a**6*x**6 - 1818*log(a*x - 1)*a**5*x**5 - 909*log(a*x - 
1)*a**4*x**4 + 3636*log(a*x - 1)*a**3*x**3 - 909*log(a*x - 1)*a**2*x**2 - 
1818*log(a*x - 1)*a*x + 909*log(a*x - 1) - 141*log(a*x + 1)*a**6*x**6 + 28 
2*log(a*x + 1)*a**5*x**5 + 141*log(a*x + 1)*a**4*x**4 - 564*log(a*x + 1)*a 
**3*x**3 + 141*log(a*x + 1)*a**2*x**2 + 282*log(a*x + 1)*a*x - 141*log(a*x 
 + 1) + 384*a**7*x**7 - 1587*a**6*x**6 + 3327*a**4*x**4 - 1544*a**3*x**3 - 
 1697*a**2*x**2 + 1088*a*x - 19)/(384*a*c**4*(a**6*x**6 - 2*a**5*x**5 - a* 
*4*x**4 + 4*a**3*x**3 - a**2*x**2 - 2*a*x + 1))