Integrand size = 25, antiderivative size = 78 \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a^2 x^2}} x \, dx=\frac {2 \sqrt {c-\frac {c}{a^2 x^2}} x}{a}+\frac {1}{2} \sqrt {c-\frac {c}{a^2 x^2}} x^2+\frac {3 \sqrt {c} \text {arctanh}\left (\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{\sqrt {c}}\right )}{2 a^2} \] Output:
2*(c-c/a^2/x^2)^(1/2)*x/a+1/2*(c-c/a^2/x^2)^(1/2)*x^2+3/2*c^(1/2)*arctanh( (c-c/a^2/x^2)^(1/2)/c^(1/2))/a^2
Time = 0.08 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.99 \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a^2 x^2}} x \, dx=\frac {\sqrt {c-\frac {c}{a^2 x^2}} x \left ((4+a x) \sqrt {1-a^2 x^2}+6 \arcsin \left (\frac {\sqrt {1-a x}}{\sqrt {2}}\right )\right )}{2 a \sqrt {1-a^2 x^2}} \] Input:
Integrate[E^(2*ArcCoth[a*x])*Sqrt[c - c/(a^2*x^2)]*x,x]
Output:
(Sqrt[c - c/(a^2*x^2)]*x*((4 + a*x)*Sqrt[1 - a^2*x^2] + 6*ArcSin[Sqrt[1 - a*x]/Sqrt[2]]))/(2*a*Sqrt[1 - a^2*x^2])
Time = 0.82 (sec) , antiderivative size = 91, normalized size of antiderivative = 1.17, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {6717, 6709, 469, 455, 223}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x \sqrt {c-\frac {c}{a^2 x^2}} e^{2 \coth ^{-1}(a x)} \, dx\) |
\(\Big \downarrow \) 6717 |
\(\displaystyle -\int e^{2 \text {arctanh}(a x)} \sqrt {c-\frac {c}{a^2 x^2}} xdx\) |
\(\Big \downarrow \) 6709 |
\(\displaystyle -\frac {x \sqrt {c-\frac {c}{a^2 x^2}} \int \frac {(a x+1)^2}{\sqrt {1-a^2 x^2}}dx}{\sqrt {1-a^2 x^2}}\) |
\(\Big \downarrow \) 469 |
\(\displaystyle -\frac {x \sqrt {c-\frac {c}{a^2 x^2}} \left (\frac {3}{2} \int \frac {a x+1}{\sqrt {1-a^2 x^2}}dx-\frac {(a x+1) \sqrt {1-a^2 x^2}}{2 a}\right )}{\sqrt {1-a^2 x^2}}\) |
\(\Big \downarrow \) 455 |
\(\displaystyle -\frac {x \sqrt {c-\frac {c}{a^2 x^2}} \left (\frac {3}{2} \left (\int \frac {1}{\sqrt {1-a^2 x^2}}dx-\frac {\sqrt {1-a^2 x^2}}{a}\right )-\frac {(a x+1) \sqrt {1-a^2 x^2}}{2 a}\right )}{\sqrt {1-a^2 x^2}}\) |
\(\Big \downarrow \) 223 |
\(\displaystyle -\frac {x \left (\frac {3}{2} \left (\frac {\arcsin (a x)}{a}-\frac {\sqrt {1-a^2 x^2}}{a}\right )-\frac {(a x+1) \sqrt {1-a^2 x^2}}{2 a}\right ) \sqrt {c-\frac {c}{a^2 x^2}}}{\sqrt {1-a^2 x^2}}\) |
Input:
Int[E^(2*ArcCoth[a*x])*Sqrt[c - c/(a^2*x^2)]*x,x]
Output:
-((Sqrt[c - c/(a^2*x^2)]*x*(-1/2*((1 + a*x)*Sqrt[1 - a^2*x^2])/a + (3*(-(S qrt[1 - a^2*x^2]/a) + ArcSin[a*x]/a))/2))/Sqrt[1 - a^2*x^2])
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt [a])]/Rt[-b, 2], x] /; FreeQ[{a, b}, x] && GtQ[a, 0] && NegQ[b]
Int[((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[d*(( a + b*x^2)^(p + 1)/(2*b*(p + 1))), x] + Simp[c Int[(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, p}, x] && !LeQ[p, -1]
Int[((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[ d*(c + d*x)^(n - 1)*((a + b*x^2)^(p + 1)/(b*(n + 2*p + 1))), x] + Simp[2*c* ((n + p)/(n + 2*p + 1)) Int[(c + d*x)^(n - 1)*(a + b*x^2)^p, x], x] /; Fr eeQ[{a, b, c, d, p}, x] && EqQ[b*c^2 + a*d^2, 0] && GtQ[n, 0] && NeQ[n + 2* p + 1, 0] && IntegerQ[2*p]
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_), x_Symbo l] :> Simp[x^(2*p)*((c + d/x^2)^p/(1 - a^2*x^2)^p) Int[u*((1 + a*x)^n/(x^ (2*p)*(1 - a^2*x^2)^(n/2 - p))), x], x] /; FreeQ[{a, c, d, p}, x] && EqQ[c + a^2*d, 0] && !IntegerQ[p] && IntegerQ[n/2] && !GtQ[c, 0]
Int[E^(ArcCoth[(a_.)*(x_)]*(n_))*(u_.), x_Symbol] :> Simp[(-1)^(n/2) Int[ u*E^(n*ArcTanh[a*x]), x], x] /; FreeQ[a, x] && IntegerQ[n/2]
Time = 0.22 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.46
method | result | size |
risch | \(\frac {\left (a x +4\right ) \sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2} x^{2}}}\, x}{2 a}+\frac {3 \ln \left (\frac {a^{2} c x}{\sqrt {a^{2} c}}+\sqrt {a^{2} c \,x^{2}-c}\right ) \sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2} x^{2}}}\, \sqrt {c \left (a^{2} x^{2}-1\right )}\, x}{2 \sqrt {a^{2} c}\, \left (a^{2} x^{2}-1\right )}\) | \(114\) |
default | \(\frac {\sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2} x^{2}}}\, x \left (x \sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}}\, a^{2}-\sqrt {c}\, \ln \left (x \sqrt {c}+\sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}}\right )+4 \sqrt {c}\, \ln \left (\frac {\sqrt {c}\, \sqrt {\frac {c \left (a x -1\right ) \left (a x +1\right )}{a^{2}}}+x c}{\sqrt {c}}\right )+4 \sqrt {\frac {c \left (a x -1\right ) \left (a x +1\right )}{a^{2}}}\, a \right )}{2 \sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}}\, a^{2}}\) | \(147\) |
Input:
int(1/(a*x-1)*(a*x+1)*(c-c/a^2/x^2)^(1/2)*x,x,method=_RETURNVERBOSE)
Output:
1/2*(a*x+4)/a*(c*(a^2*x^2-1)/a^2/x^2)^(1/2)*x+3/2*ln(a^2*c*x/(a^2*c)^(1/2) +(a^2*c*x^2-c)^(1/2))/(a^2*c)^(1/2)*(c*(a^2*x^2-1)/a^2/x^2)^(1/2)*(c*(a^2* x^2-1))^(1/2)/(a^2*x^2-1)*x
Time = 0.11 (sec) , antiderivative size = 188, normalized size of antiderivative = 2.41 \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a^2 x^2}} x \, dx=\left [\frac {2 \, {\left (a^{2} x^{2} + 4 \, a x\right )} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}} + 3 \, \sqrt {c} \log \left (2 \, a^{2} c x^{2} + 2 \, a^{2} \sqrt {c} x^{2} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}} - c\right )}{4 \, a^{2}}, \frac {{\left (a^{2} x^{2} + 4 \, a x\right )} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}} - 3 \, \sqrt {-c} \arctan \left (\frac {a^{2} \sqrt {-c} x^{2} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}}}{a^{2} c x^{2} - c}\right )}{2 \, a^{2}}\right ] \] Input:
integrate(1/(a*x-1)*(a*x+1)*(c-c/a^2/x^2)^(1/2)*x,x, algorithm="fricas")
Output:
[1/4*(2*(a^2*x^2 + 4*a*x)*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) + 3*sqrt(c)*log( 2*a^2*c*x^2 + 2*a^2*sqrt(c)*x^2*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) - c))/a^2, 1/2*((a^2*x^2 + 4*a*x)*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) - 3*sqrt(-c)*arcta n(a^2*sqrt(-c)*x^2*sqrt((a^2*c*x^2 - c)/(a^2*x^2))/(a^2*c*x^2 - c)))/a^2]
\[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a^2 x^2}} x \, dx=\int \frac {x \sqrt {- c \left (-1 + \frac {1}{a x}\right ) \left (1 + \frac {1}{a x}\right )} \left (a x + 1\right )}{a x - 1}\, dx \] Input:
integrate(1/(a*x-1)*(a*x+1)*(c-c/a**2/x**2)**(1/2)*x,x)
Output:
Integral(x*sqrt(-c*(-1 + 1/(a*x))*(1 + 1/(a*x)))*(a*x + 1)/(a*x - 1), x)
\[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a^2 x^2}} x \, dx=\int { \frac {{\left (a x + 1\right )} \sqrt {c - \frac {c}{a^{2} x^{2}}} x}{a x - 1} \,d x } \] Input:
integrate(1/(a*x-1)*(a*x+1)*(c-c/a^2/x^2)^(1/2)*x,x, algorithm="maxima")
Output:
integrate((a*x + 1)*sqrt(c - c/(a^2*x^2))*x/(a*x - 1), x)
Time = 0.13 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.36 \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a^2 x^2}} x \, dx=\frac {1}{4} \, {\left (2 \, \sqrt {a^{2} c x^{2} - c} {\left (\frac {x \mathrm {sgn}\left (x\right )}{a^{2}} + \frac {4 \, \mathrm {sgn}\left (x\right )}{a^{3}}\right )} - \frac {6 \, \sqrt {c} \log \left ({\left | -\sqrt {a^{2} c} x + \sqrt {a^{2} c x^{2} - c} \right |}\right ) \mathrm {sgn}\left (x\right )}{a^{2} {\left | a \right |}} + \frac {{\left (3 \, a \sqrt {c} \log \left ({\left | c \right |}\right ) - 8 \, \sqrt {-c} {\left | a \right |}\right )} \mathrm {sgn}\left (x\right )}{a^{3} {\left | a \right |}}\right )} {\left | a \right |} \] Input:
integrate(1/(a*x-1)*(a*x+1)*(c-c/a^2/x^2)^(1/2)*x,x, algorithm="giac")
Output:
1/4*(2*sqrt(a^2*c*x^2 - c)*(x*sgn(x)/a^2 + 4*sgn(x)/a^3) - 6*sqrt(c)*log(a bs(-sqrt(a^2*c)*x + sqrt(a^2*c*x^2 - c)))*sgn(x)/(a^2*abs(a)) + (3*a*sqrt( c)*log(abs(c)) - 8*sqrt(-c)*abs(a))*sgn(x)/(a^3*abs(a)))*abs(a)
Timed out. \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a^2 x^2}} x \, dx=\int \frac {x\,\sqrt {c-\frac {c}{a^2\,x^2}}\,\left (a\,x+1\right )}{a\,x-1} \,d x \] Input:
int((x*(c - c/(a^2*x^2))^(1/2)*(a*x + 1))/(a*x - 1),x)
Output:
int((x*(c - c/(a^2*x^2))^(1/2)*(a*x + 1))/(a*x - 1), x)
Time = 0.14 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.64 \[ \int e^{2 \coth ^{-1}(a x)} \sqrt {c-\frac {c}{a^2 x^2}} x \, dx=\frac {\sqrt {c}\, \left (\sqrt {a^{2} x^{2}-1}\, a x +4 \sqrt {a^{2} x^{2}-1}+3 \,\mathrm {log}\left (\sqrt {a^{2} x^{2}-1}+a x \right )\right )}{2 a^{2}} \] Input:
int(1/(a*x-1)*(a*x+1)*(c-c/a^2/x^2)^(1/2)*x,x)
Output:
(sqrt(c)*(sqrt(a**2*x**2 - 1)*a*x + 4*sqrt(a**2*x**2 - 1) + 3*log(sqrt(a** 2*x**2 - 1) + a*x)))/(2*a**2)