Integrand size = 27, antiderivative size = 172 \[ \int e^{2 \text {arctanh}(a x)} x^m \left (c-a^2 c x^2\right )^{3/2} \, dx=-\frac {x^{1+m} \left (c-a^2 c x^2\right )^{3/2}}{4+m}+\frac {c (5+2 m) x^{1+m} \sqrt {c-a^2 c x^2} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},a^2 x^2\right )}{(1+m) (4+m) \sqrt {1-a^2 x^2}}+\frac {2 a c x^{2+m} \sqrt {c-a^2 c x^2} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {2+m}{2},\frac {4+m}{2},a^2 x^2\right )}{(2+m) \sqrt {1-a^2 x^2}} \] Output:
-x^(1+m)*(-a^2*c*x^2+c)^(3/2)/(4+m)+c*(5+2*m)*x^(1+m)*(-a^2*c*x^2+c)^(1/2) *hypergeom([-1/2, 1/2+1/2*m],[3/2+1/2*m],a^2*x^2)/(1+m)/(4+m)/(-a^2*x^2+1) ^(1/2)+2*a*c*x^(2+m)*(-a^2*c*x^2+c)^(1/2)*hypergeom([-1/2, 1+1/2*m],[2+1/2 *m],a^2*x^2)/(2+m)/(-a^2*x^2+1)^(1/2)
Time = 0.08 (sec) , antiderivative size = 158, normalized size of antiderivative = 0.92 \[ \int e^{2 \text {arctanh}(a x)} x^m \left (c-a^2 c x^2\right )^{3/2} \, dx=\frac {c x^{1+m} \sqrt {c-a^2 c x^2} \left (2 a \left (3+4 m+m^2\right ) x \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1+\frac {m}{2},2+\frac {m}{2},a^2 x^2\right )+(2+m) \left ((3+m) \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},a^2 x^2\right )+a^2 (1+m) x^2 \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {3+m}{2},\frac {5+m}{2},a^2 x^2\right )\right )\right )}{(1+m) (2+m) (3+m) \sqrt {1-a^2 x^2}} \] Input:
Integrate[E^(2*ArcTanh[a*x])*x^m*(c - a^2*c*x^2)^(3/2),x]
Output:
(c*x^(1 + m)*Sqrt[c - a^2*c*x^2]*(2*a*(3 + 4*m + m^2)*x*Hypergeometric2F1[ -1/2, 1 + m/2, 2 + m/2, a^2*x^2] + (2 + m)*((3 + m)*Hypergeometric2F1[-1/2 , (1 + m)/2, (3 + m)/2, a^2*x^2] + a^2*(1 + m)*x^2*Hypergeometric2F1[-1/2, (3 + m)/2, (5 + m)/2, a^2*x^2])))/((1 + m)*(2 + m)*(3 + m)*Sqrt[1 - a^2*x ^2])
Time = 0.49 (sec) , antiderivative size = 180, normalized size of antiderivative = 1.05, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.259, Rules used = {6701, 559, 25, 27, 557, 279, 278}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^m e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^{3/2} \, dx\) |
\(\Big \downarrow \) 6701 |
\(\displaystyle c \int x^m (a x+1)^2 \sqrt {c-a^2 c x^2}dx\) |
\(\Big \downarrow \) 559 |
\(\displaystyle c \left (-\frac {\int -a^2 c x^m (2 m+2 a (m+4) x+5) \sqrt {c-a^2 c x^2}dx}{a^2 c (m+4)}-\frac {x^{m+1} \left (c-a^2 c x^2\right )^{3/2}}{c (m+4)}\right )\) |
\(\Big \downarrow \) 25 |
\(\displaystyle c \left (\frac {\int a^2 c x^m (2 m+2 a (m+4) x+5) \sqrt {c-a^2 c x^2}dx}{a^2 c (m+4)}-\frac {x^{m+1} \left (c-a^2 c x^2\right )^{3/2}}{c (m+4)}\right )\) |
\(\Big \downarrow \) 27 |
\(\displaystyle c \left (\frac {\int x^m (2 m+2 a (m+4) x+5) \sqrt {c-a^2 c x^2}dx}{m+4}-\frac {x^{m+1} \left (c-a^2 c x^2\right )^{3/2}}{c (m+4)}\right )\) |
\(\Big \downarrow \) 557 |
\(\displaystyle c \left (\frac {2 a (m+4) \int x^{m+1} \sqrt {c-a^2 c x^2}dx+(2 m+5) \int x^m \sqrt {c-a^2 c x^2}dx}{m+4}-\frac {x^{m+1} \left (c-a^2 c x^2\right )^{3/2}}{c (m+4)}\right )\) |
\(\Big \downarrow \) 279 |
\(\displaystyle c \left (\frac {\frac {2 a (m+4) \sqrt {c-a^2 c x^2} \int x^{m+1} \sqrt {1-a^2 x^2}dx}{\sqrt {1-a^2 x^2}}+\frac {(2 m+5) \sqrt {c-a^2 c x^2} \int x^m \sqrt {1-a^2 x^2}dx}{\sqrt {1-a^2 x^2}}}{m+4}-\frac {x^{m+1} \left (c-a^2 c x^2\right )^{3/2}}{c (m+4)}\right )\) |
\(\Big \downarrow \) 278 |
\(\displaystyle c \left (\frac {\frac {(2 m+5) x^{m+1} \sqrt {c-a^2 c x^2} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {m+1}{2},\frac {m+3}{2},a^2 x^2\right )}{(m+1) \sqrt {1-a^2 x^2}}+\frac {2 a (m+4) x^{m+2} \sqrt {c-a^2 c x^2} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {m+2}{2},\frac {m+4}{2},a^2 x^2\right )}{(m+2) \sqrt {1-a^2 x^2}}}{m+4}-\frac {x^{m+1} \left (c-a^2 c x^2\right )^{3/2}}{c (m+4)}\right )\) |
Input:
Int[E^(2*ArcTanh[a*x])*x^m*(c - a^2*c*x^2)^(3/2),x]
Output:
c*(-((x^(1 + m)*(c - a^2*c*x^2)^(3/2))/(c*(4 + m))) + (((5 + 2*m)*x^(1 + m )*Sqrt[c - a^2*c*x^2]*Hypergeometric2F1[-1/2, (1 + m)/2, (3 + m)/2, a^2*x^ 2])/((1 + m)*Sqrt[1 - a^2*x^2]) + (2*a*(4 + m)*x^(2 + m)*Sqrt[c - a^2*c*x^ 2]*Hypergeometric2F1[-1/2, (2 + m)/2, (4 + m)/2, a^2*x^2])/((2 + m)*Sqrt[1 - a^2*x^2]))/(4 + m))
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[a^p*(( c*x)^(m + 1)/(c*(m + 1)))*Hypergeometric2F1[-p, (m + 1)/2, (m + 1)/2 + 1, ( -b)*(x^2/a)], x] /; FreeQ[{a, b, c, m, p}, x] && !IGtQ[p, 0] && (ILtQ[p, 0 ] || GtQ[a, 0])
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[a^IntP art[p]*((a + b*x^2)^FracPart[p]/(1 + b*(x^2/a))^FracPart[p]) Int[(c*x)^m* (1 + b*(x^2/a))^p, x], x] /; FreeQ[{a, b, c, m, p}, x] && !IGtQ[p, 0] && !(ILtQ[p, 0] || GtQ[a, 0])
Int[((e_.)*(x_))^(m_)*((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_), x_Sym bol] :> Simp[c Int[(e*x)^m*(a + b*x^2)^p, x], x] + Simp[d/e Int[(e*x)^( m + 1)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m, p}, x]
Int[((e_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[d^n*(e*x)^(m + n - 1)*((a + b*x^2)^(p + 1)/(b*e^(n - 1)*( m + n + 2*p + 1))), x] + Simp[1/(b*(m + n + 2*p + 1)) Int[(e*x)^m*(a + b* x^2)^p*ExpandToSum[b*(m + n + 2*p + 1)*(c + d*x)^n - b*d^n*(m + n + 2*p + 1 )*x^n - a*d^n*(m + n - 1)*x^(n - 2), x], x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && IGtQ[n, 1] && !IntegerQ[m] && NeQ[m + n + 2*p + 1, 0]
Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x_ Symbol] :> Simp[c^(n/2) Int[x^m*(c + d*x^2)^(p - n/2)*(1 + a*x)^n, x], x] /; FreeQ[{a, c, d, m, p}, x] && EqQ[a^2*c + d, 0] && !(IntegerQ[p] || GtQ [c, 0]) && IGtQ[n/2, 0]
\[\int \frac {\left (a x +1\right )^{2} x^{m} \left (-a^{2} c \,x^{2}+c \right )^{\frac {3}{2}}}{-a^{2} x^{2}+1}d x\]
Input:
int((a*x+1)^2/(-a^2*x^2+1)*x^m*(-a^2*c*x^2+c)^(3/2),x)
Output:
int((a*x+1)^2/(-a^2*x^2+1)*x^m*(-a^2*c*x^2+c)^(3/2),x)
\[ \int e^{2 \text {arctanh}(a x)} x^m \left (c-a^2 c x^2\right )^{3/2} \, dx=\int { -\frac {{\left (-a^{2} c x^{2} + c\right )}^{\frac {3}{2}} {\left (a x + 1\right )}^{2} x^{m}}{a^{2} x^{2} - 1} \,d x } \] Input:
integrate((a*x+1)^2/(-a^2*x^2+1)*x^m*(-a^2*c*x^2+c)^(3/2),x, algorithm="fr icas")
Output:
integral((a^2*c*x^2 + 2*a*c*x + c)*sqrt(-a^2*c*x^2 + c)*x^m, x)
Result contains complex when optimal does not.
Time = 5.83 (sec) , antiderivative size = 168, normalized size of antiderivative = 0.98 \[ \int e^{2 \text {arctanh}(a x)} x^m \left (c-a^2 c x^2\right )^{3/2} \, dx=\frac {a^{2} c^{\frac {3}{2}} x^{m + 3} \Gamma \left (\frac {m}{2} + \frac {3}{2}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {m}{2} + \frac {3}{2} \\ \frac {m}{2} + \frac {5}{2} \end {matrix}\middle | {a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )} + \frac {a c^{\frac {3}{2}} x^{m + 2} \Gamma \left (\frac {m}{2} + 1\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {m}{2} + 1 \\ \frac {m}{2} + 2 \end {matrix}\middle | {a^{2} x^{2} e^{2 i \pi }} \right )}}{\Gamma \left (\frac {m}{2} + 2\right )} + \frac {c^{\frac {3}{2}} x^{m + 1} \Gamma \left (\frac {m}{2} + \frac {1}{2}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {m}{2} + \frac {1}{2} \\ \frac {m}{2} + \frac {3}{2} \end {matrix}\middle | {a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} \] Input:
integrate((a*x+1)**2/(-a**2*x**2+1)*x**m*(-a**2*c*x**2+c)**(3/2),x)
Output:
a**2*c**(3/2)*x**(m + 3)*gamma(m/2 + 3/2)*hyper((-1/2, m/2 + 3/2), (m/2 + 5/2,), a**2*x**2*exp_polar(2*I*pi))/(2*gamma(m/2 + 5/2)) + a*c**(3/2)*x**( m + 2)*gamma(m/2 + 1)*hyper((-1/2, m/2 + 1), (m/2 + 2,), a**2*x**2*exp_pol ar(2*I*pi))/gamma(m/2 + 2) + c**(3/2)*x**(m + 1)*gamma(m/2 + 1/2)*hyper((- 1/2, m/2 + 1/2), (m/2 + 3/2,), a**2*x**2*exp_polar(2*I*pi))/(2*gamma(m/2 + 3/2))
\[ \int e^{2 \text {arctanh}(a x)} x^m \left (c-a^2 c x^2\right )^{3/2} \, dx=\int { -\frac {{\left (-a^{2} c x^{2} + c\right )}^{\frac {3}{2}} {\left (a x + 1\right )}^{2} x^{m}}{a^{2} x^{2} - 1} \,d x } \] Input:
integrate((a*x+1)^2/(-a^2*x^2+1)*x^m*(-a^2*c*x^2+c)^(3/2),x, algorithm="ma xima")
Output:
-integrate((-a^2*c*x^2 + c)^(3/2)*(a*x + 1)^2*x^m/(a^2*x^2 - 1), x)
Exception generated. \[ \int e^{2 \text {arctanh}(a x)} x^m \left (c-a^2 c x^2\right )^{3/2} \, dx=\text {Exception raised: TypeError} \] Input:
integrate((a*x+1)^2/(-a^2*x^2+1)*x^m*(-a^2*c*x^2+c)^(3/2),x, algorithm="gi ac")
Output:
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value
Timed out. \[ \int e^{2 \text {arctanh}(a x)} x^m \left (c-a^2 c x^2\right )^{3/2} \, dx=\int -\frac {x^m\,{\left (c-a^2\,c\,x^2\right )}^{3/2}\,{\left (a\,x+1\right )}^2}{a^2\,x^2-1} \,d x \] Input:
int(-(x^m*(c - a^2*c*x^2)^(3/2)*(a*x + 1)^2)/(a^2*x^2 - 1),x)
Output:
int(-(x^m*(c - a^2*c*x^2)^(3/2)*(a*x + 1)^2)/(a^2*x^2 - 1), x)
\[ \int e^{2 \text {arctanh}(a x)} x^m \left (c-a^2 c x^2\right )^{3/2} \, dx=\sqrt {c}\, c \left (\left (\int x^{m} \sqrt {-a^{2} x^{2}+1}\, x^{2}d x \right ) a^{2}+2 \left (\int x^{m} \sqrt {-a^{2} x^{2}+1}\, x d x \right ) a +\int x^{m} \sqrt {-a^{2} x^{2}+1}d x \right ) \] Input:
int((a*x+1)^2/(-a^2*x^2+1)*x^m*(-a^2*c*x^2+c)^(3/2),x)
Output:
sqrt(c)*c*(int(x**m*sqrt( - a**2*x**2 + 1)*x**2,x)*a**2 + 2*int(x**m*sqrt( - a**2*x**2 + 1)*x,x)*a + int(x**m*sqrt( - a**2*x**2 + 1),x))