Integrand size = 29, antiderivative size = 79 \[ \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx=\frac {4 \sqrt [8]{2} a \sqrt [8]{1-a^2 x^2} \operatorname {AppellF1}\left (-\frac {3}{8},\frac {7}{8},2,\frac {5}{8},\frac {1}{2} (1-a x),1-a x\right )}{3 c (1-a x)^{3/8} \sqrt [8]{c-a^2 c x^2}} \] Output:
4/3*2^(1/8)*a*(-a^2*x^2+1)^(1/8)*AppellF1(-3/8,7/8,2,5/8,-1/2*a*x+1/2,-a*x +1)/c/(-a*x+1)^(3/8)/(-a^2*c*x^2+c)^(1/8)
\[ \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx=\int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx \] Input:
Integrate[E^(ArcTanh[a*x]/2)/(x^2*(c - a^2*c*x^2)^(9/8)),x]
Output:
Integrate[E^(ArcTanh[a*x]/2)/(x^2*(c - a^2*c*x^2)^(9/8)), x]
Time = 0.50 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.94, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {6703, 6700, 153}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx\) |
\(\Big \downarrow \) 6703 |
\(\displaystyle \frac {\sqrt [8]{1-a^2 x^2} \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (1-a^2 x^2\right )^{9/8}}dx}{c \sqrt [8]{c-a^2 c x^2}}\) |
\(\Big \downarrow \) 6700 |
\(\displaystyle \frac {\sqrt [8]{1-a^2 x^2} \int \frac {1}{x^2 (1-a x)^{11/8} (a x+1)^{7/8}}dx}{c \sqrt [8]{c-a^2 c x^2}}\) |
\(\Big \downarrow \) 153 |
\(\displaystyle \frac {2\ 2^{5/8} a \sqrt [8]{a x+1} \sqrt [8]{1-a^2 x^2} \operatorname {AppellF1}\left (\frac {1}{8},\frac {11}{8},2,\frac {9}{8},\frac {1}{2} (a x+1),a x+1\right )}{c \sqrt [8]{c-a^2 c x^2}}\) |
Input:
Int[E^(ArcTanh[a*x]/2)/(x^2*(c - a^2*c*x^2)^(9/8)),x]
Output:
(2*2^(5/8)*a*(1 + a*x)^(1/8)*(1 - a^2*x^2)^(1/8)*AppellF1[1/8, 11/8, 2, 9/ 8, (1 + a*x)/2, 1 + a*x])/(c*(c - a^2*c*x^2)^(1/8))
Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_)) ^(p_), x_] :> Simp[(b*e - a*f)^p*((a + b*x)^(m + 1)/(b^(p + 1)*(m + 1)*Simp lify[b/(b*c - a*d)]^n))*AppellF1[m + 1, -n, -p, m + 2, (-d)*((a + b*x)/(b*c - a*d)), (-f)*((a + b*x)/(b*e - a*f))], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && !IntegerQ[m] && !IntegerQ[n] && IntegerQ[p] && GtQ[Simplify[b/( b*c - a*d)], 0] && !(GtQ[Simplify[d/(d*a - c*b)], 0] && SimplerQ[c + d*x, a + b*x])
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x _Symbol] :> Simp[c^p Int[x^m*(1 - a*x)^(p - n/2)*(1 + a*x)^(p + n/2), x], x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || GtQ[c, 0])
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_), x_ Symbol] :> Simp[c^IntPart[p]*((c + d*x^2)^FracPart[p]/(1 - a^2*x^2)^FracPar t[p]) Int[x^m*(1 - a^2*x^2)^p*E^(n*ArcTanh[a*x]), x], x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && !(IntegerQ[p] || GtQ[c, 0]) && !I ntegerQ[n/2]
\[\int \frac {\sqrt {\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}}}{x^{2} \left (-a^{2} c \,x^{2}+c \right )^{\frac {9}{8}}}d x\]
Input:
int(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^2/(-a^2*c*x^2+c)^(9/8),x)
Output:
int(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^2/(-a^2*c*x^2+c)^(9/8),x)
Timed out. \[ \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx=\text {Timed out} \] Input:
integrate(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^2/(-a^2*c*x^2+c)^(9/8),x, a lgorithm="fricas")
Output:
Timed out
Timed out. \[ \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx=\text {Timed out} \] Input:
integrate(((a*x+1)/(-a**2*x**2+1)**(1/2))**(1/2)/x**2/(-a**2*c*x**2+c)**(9 /8),x)
Output:
Timed out
\[ \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx=\int { \frac {\sqrt {\frac {a x + 1}{\sqrt {-a^{2} x^{2} + 1}}}}{{\left (-a^{2} c x^{2} + c\right )}^{\frac {9}{8}} x^{2}} \,d x } \] Input:
integrate(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^2/(-a^2*c*x^2+c)^(9/8),x, a lgorithm="maxima")
Output:
integrate(sqrt((a*x + 1)/sqrt(-a^2*x^2 + 1))/((-a^2*c*x^2 + c)^(9/8)*x^2), x)
\[ \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx=\int { \frac {\sqrt {\frac {a x + 1}{\sqrt {-a^{2} x^{2} + 1}}}}{{\left (-a^{2} c x^{2} + c\right )}^{\frac {9}{8}} x^{2}} \,d x } \] Input:
integrate(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^2/(-a^2*c*x^2+c)^(9/8),x, a lgorithm="giac")
Output:
integrate(sqrt((a*x + 1)/sqrt(-a^2*x^2 + 1))/((-a^2*c*x^2 + c)^(9/8)*x^2), x)
Timed out. \[ \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx=\int \frac {\sqrt {\frac {a\,x+1}{\sqrt {1-a^2\,x^2}}}}{x^2\,{\left (c-a^2\,c\,x^2\right )}^{9/8}} \,d x \] Input:
int(((a*x + 1)/(1 - a^2*x^2)^(1/2))^(1/2)/(x^2*(c - a^2*c*x^2)^(9/8)),x)
Output:
int(((a*x + 1)/(1 - a^2*x^2)^(1/2))^(1/2)/(x^2*(c - a^2*c*x^2)^(9/8)), x)
\[ \int \frac {e^{\frac {1}{2} \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )^{9/8}} \, dx=\frac {-52 \sqrt {a x +1}\, \left (-a^{2} x^{2}+1\right )^{\frac {7}{8}}+648 \sqrt {a x +1}\, \left (-a^{2} x^{2}+1\right )^{\frac {7}{8}} a^{3} x^{3}+36 \sqrt {a x +1}\, \left (-a^{2} x^{2}+1\right )^{\frac {7}{8}} a^{2} x^{2}-648 \sqrt {a x +1}\, \left (-a^{2} x^{2}+1\right )^{\frac {7}{8}} a x +405 \left (-a^{2} x^{2}+1\right )^{\frac {5}{4}} \left (\int \frac {\sqrt {a x +1}\, \left (-a^{2} x^{2}+1\right )^{\frac {1}{4}} x^{2}}{\left (-a^{2} x^{2}+1\right )^{\frac {5}{8}} a^{2} x^{2}-\left (-a^{2} x^{2}+1\right )^{\frac {5}{8}}}d x \right ) a^{4} x +18 \left (-a^{2} x^{2}+1\right )^{\frac {5}{4}} \left (\int \frac {\sqrt {a x +1}\, \left (-a^{2} x^{2}+1\right )^{\frac {1}{4}} x}{\left (-a^{2} x^{2}+1\right )^{\frac {5}{8}} a^{2} x^{2}-\left (-a^{2} x^{2}+1\right )^{\frac {5}{8}}}d x \right ) a^{3} x -26 \left (-a^{2} x^{2}+1\right )^{\frac {5}{4}} \left (\int \frac {\sqrt {a x +1}\, \left (-a^{2} x^{2}+1\right )^{\frac {1}{4}}}{\left (-a^{2} x^{2}+1\right )^{\frac {5}{8}} a^{2} x^{3}-\left (-a^{2} x^{2}+1\right )^{\frac {5}{8}} x}d x \right ) a x -477 \left (-a^{2} x^{2}+1\right )^{\frac {5}{4}} \left (\int \frac {\sqrt {a x +1}\, \left (-a^{2} x^{2}+1\right )^{\frac {1}{4}}}{\left (-a^{2} x^{2}+1\right )^{\frac {5}{8}} a^{2} x^{2}-\left (-a^{2} x^{2}+1\right )^{\frac {5}{8}}}d x \right ) a^{2} x}{52 c^{\frac {5}{8}} \sqrt {c}\, \left (-a^{2} x^{2}+1\right )^{\frac {5}{4}} x} \] Input:
int(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/x^2/(-a^2*c*x^2+c)^(9/8),x)
Output:
(c**(3/8)*( - 16*sqrt(a*x + 1)*( - a**2*x**2 + 1)**(7/8) + 648*sqrt(a*x + 1)*( - a**2*x**2 + 1)**(7/8)*a**3*x**3 + 36*sqrt(a*x + 1)*( - a**2*x**2 + 1)**(7/8)*a**2*x**2 - 648*sqrt(a*x + 1)*( - a**2*x**2 + 1)**(7/8)*a*x - 36 *sqrt(a*x + 1)*( - a**2*x**2 + 1)**(7/8) + 405*( - a**2*x**2 + 1)**(5/4)*i nt((sqrt(a*x + 1)*( - a**2*x**2 + 1)**(1/4)*x**2)/(( - a**2*x**2 + 1)**(5/ 8)*a**2*x**2 - ( - a**2*x**2 + 1)**(5/8)),x)*a**4*x + 18*( - a**2*x**2 + 1 )**(5/4)*int((sqrt(a*x + 1)*( - a**2*x**2 + 1)**(1/4)*x)/(( - a**2*x**2 + 1)**(5/8)*a**2*x**2 - ( - a**2*x**2 + 1)**(5/8)),x)*a**3*x - 26*( - a**2*x **2 + 1)**(5/4)*int((sqrt(a*x + 1)*( - a**2*x**2 + 1)**(1/4))/(( - a**2*x* *2 + 1)**(5/8)*a**2*x**3 - ( - a**2*x**2 + 1)**(5/8)*x),x)*a*x - 477*( - a **2*x**2 + 1)**(5/4)*int((sqrt(a*x + 1)*( - a**2*x**2 + 1)**(1/4))/(( - a* *2*x**2 + 1)**(5/8)*a**2*x**2 - ( - a**2*x**2 + 1)**(5/8)),x)*a**2*x))/(52 *sqrt(c)*( - a**2*x**2 + 1)**(5/4)*c*x)