Integrand size = 23, antiderivative size = 68 \[ \int \frac {e^{-\text {arctanh}(a x)} \sqrt {c-a c x}}{x} \, dx=-\frac {2 c \sqrt {1-a^2 x^2}}{\sqrt {c-a c x}}-2 \sqrt {c} \text {arctanh}\left (\frac {\sqrt {c} \sqrt {1-a^2 x^2}}{\sqrt {c-a c x}}\right ) \] Output:
-2*c*(-a^2*x^2+1)^(1/2)/(-a*c*x+c)^(1/2)-2*c^(1/2)*arctanh(c^(1/2)*(-a^2*x ^2+1)^(1/2)/(-a*c*x+c)^(1/2))
Time = 0.02 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.65 \[ \int \frac {e^{-\text {arctanh}(a x)} \sqrt {c-a c x}}{x} \, dx=-\frac {2 c \sqrt {1-a x} \left (\sqrt {1+a x}+\text {arctanh}\left (\sqrt {1+a x}\right )\right )}{\sqrt {c-a c x}} \] Input:
Integrate[Sqrt[c - a*c*x]/(E^ArcTanh[a*x]*x),x]
Output:
(-2*c*Sqrt[1 - a*x]*(Sqrt[1 + a*x] + ArcTanh[Sqrt[1 + a*x]]))/Sqrt[c - a*c *x]
Time = 0.35 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.09, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {6678, 574, 573, 219}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {e^{-\text {arctanh}(a x)} \sqrt {c-a c x}}{x} \, dx\) |
\(\Big \downarrow \) 6678 |
\(\displaystyle \frac {\int \frac {(c-a c x)^{3/2}}{x \sqrt {1-a^2 x^2}}dx}{c}\) |
\(\Big \downarrow \) 574 |
\(\displaystyle \frac {c \int \frac {\sqrt {c-a c x}}{x \sqrt {1-a^2 x^2}}dx-\frac {2 c^2 \sqrt {1-a^2 x^2}}{\sqrt {c-a c x}}}{c}\) |
\(\Big \downarrow \) 573 |
\(\displaystyle \frac {-2 c^2 \int \frac {1}{1-\frac {c \left (1-a^2 x^2\right )}{c-a c x}}d\frac {\sqrt {1-a^2 x^2}}{\sqrt {c-a c x}}-\frac {2 c^2 \sqrt {1-a^2 x^2}}{\sqrt {c-a c x}}}{c}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle \frac {-2 c^{3/2} \text {arctanh}\left (\frac {\sqrt {c} \sqrt {1-a^2 x^2}}{\sqrt {c-a c x}}\right )-\frac {2 c^2 \sqrt {1-a^2 x^2}}{\sqrt {c-a c x}}}{c}\) |
Input:
Int[Sqrt[c - a*c*x]/(E^ArcTanh[a*x]*x),x]
Output:
((-2*c^2*Sqrt[1 - a^2*x^2])/Sqrt[c - a*c*x] - 2*c^(3/2)*ArcTanh[(Sqrt[c]*S qrt[1 - a^2*x^2])/Sqrt[c - a*c*x]])/c
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Int[Sqrt[(c_) + (d_.)*(x_)]/((x_)*Sqrt[(a_) + (b_.)*(x_)^2]), x_Symbol] :> Simp[-2*c Subst[Int[1/(a - c*x^2), x], x, Sqrt[a + b*x^2]/Sqrt[c + d*x]], x] /; FreeQ[{a, b, c, d}, x] && EqQ[b*c^2 + a*d^2, 0]
Int[((e_.)*(x_))^(n_)*((c_) + (d_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[d^2*(e*x)^(n + 1)*(c + d*x)^(m - 2)*((a + b*x^2)^(p + 1)/ (b*e*(n + p + 2))), x] + Simp[c*((2*n + p + 3)/(n + p + 2)) Int[(e*x)^n*( c + d*x)^(m - 1)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x ] && EqQ[b*c^2 + a*d^2, 0] && EqQ[m + p - 1, 0] && !LtQ[n, -1] && IntegerQ [2*p]
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_))^(p_.)*((e_.) + (f_.)* (x_))^(m_.), x_Symbol] :> Simp[c^n Int[(e + f*x)^m*(c + d*x)^(p - n)*(1 - a^2*x^2)^(n/2), x], x] /; FreeQ[{a, c, d, e, f, m, p}, x] && EqQ[a*c + d, 0] && IntegerQ[(n - 1)/2] && (IntegerQ[p] || EqQ[p, n/2] || EqQ[p - n/2 - 1 , 0]) && IntegerQ[2*p]
Time = 0.21 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.01
method | result | size |
default | \(\frac {2 \sqrt {-c \left (a x -1\right )}\, \sqrt {-a^{2} x^{2}+1}\, \left (\sqrt {c}\, \operatorname {arctanh}\left (\frac {\sqrt {c \left (a x +1\right )}}{\sqrt {c}}\right )+\sqrt {c \left (a x +1\right )}\right )}{\left (a x -1\right ) \sqrt {c \left (a x +1\right )}}\) | \(69\) |
Input:
int((-a*c*x+c)^(1/2)/(a*x+1)*(-a^2*x^2+1)^(1/2)/x,x,method=_RETURNVERBOSE)
Output:
2*(-c*(a*x-1))^(1/2)*(-a^2*x^2+1)^(1/2)*(c^(1/2)*arctanh((c*(a*x+1))^(1/2) /c^(1/2))+(c*(a*x+1))^(1/2))/(a*x-1)/(c*(a*x+1))^(1/2)
Time = 0.09 (sec) , antiderivative size = 180, normalized size of antiderivative = 2.65 \[ \int \frac {e^{-\text {arctanh}(a x)} \sqrt {c-a c x}}{x} \, dx=\left [\frac {{\left (a x - 1\right )} \sqrt {c} \log \left (-\frac {a^{2} c x^{2} + a c x + 2 \, \sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c} \sqrt {c} - 2 \, c}{a x^{2} - x}\right ) + 2 \, \sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c}}{a x - 1}, -\frac {2 \, {\left ({\left (a x - 1\right )} \sqrt {-c} \arctan \left (\frac {\sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c} \sqrt {-c}}{a c x - c}\right ) - \sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c}\right )}}{a x - 1}\right ] \] Input:
integrate((-a*c*x+c)^(1/2)/(a*x+1)*(-a^2*x^2+1)^(1/2)/x,x, algorithm="fric as")
Output:
[((a*x - 1)*sqrt(c)*log(-(a^2*c*x^2 + a*c*x + 2*sqrt(-a^2*x^2 + 1)*sqrt(-a *c*x + c)*sqrt(c) - 2*c)/(a*x^2 - x)) + 2*sqrt(-a^2*x^2 + 1)*sqrt(-a*c*x + c))/(a*x - 1), -2*((a*x - 1)*sqrt(-c)*arctan(sqrt(-a^2*x^2 + 1)*sqrt(-a*c *x + c)*sqrt(-c)/(a*c*x - c)) - sqrt(-a^2*x^2 + 1)*sqrt(-a*c*x + c))/(a*x - 1)]
\[ \int \frac {e^{-\text {arctanh}(a x)} \sqrt {c-a c x}}{x} \, dx=\int \frac {\sqrt {- c \left (a x - 1\right )} \sqrt {- \left (a x - 1\right ) \left (a x + 1\right )}}{x \left (a x + 1\right )}\, dx \] Input:
integrate((-a*c*x+c)**(1/2)/(a*x+1)*(-a**2*x**2+1)**(1/2)/x,x)
Output:
Integral(sqrt(-c*(a*x - 1))*sqrt(-(a*x - 1)*(a*x + 1))/(x*(a*x + 1)), x)
\[ \int \frac {e^{-\text {arctanh}(a x)} \sqrt {c-a c x}}{x} \, dx=\int { \frac {\sqrt {-a^{2} x^{2} + 1} \sqrt {-a c x + c}}{{\left (a x + 1\right )} x} \,d x } \] Input:
integrate((-a*c*x+c)^(1/2)/(a*x+1)*(-a^2*x^2+1)^(1/2)/x,x, algorithm="maxi ma")
Output:
integrate(sqrt(-a^2*x^2 + 1)*sqrt(-a*c*x + c)/((a*x + 1)*x), x)
Time = 0.13 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.21 \[ \int \frac {e^{-\text {arctanh}(a x)} \sqrt {c-a c x}}{x} \, dx=2 \, {\left (\frac {\arctan \left (\frac {\sqrt {a c x + c}}{\sqrt {-c}}\right )}{\sqrt {-c}} - \frac {\sqrt {a c x + c}}{c}\right )} {\left | c \right |} - \frac {2 \, {\left (\sqrt {c} {\left | c \right |} \arctan \left (\frac {\sqrt {2} \sqrt {c}}{\sqrt {-c}}\right ) - \sqrt {2} \sqrt {-c} {\left | c \right |}\right )}}{\sqrt {-c} \sqrt {c}} \] Input:
integrate((-a*c*x+c)^(1/2)/(a*x+1)*(-a^2*x^2+1)^(1/2)/x,x, algorithm="giac ")
Output:
2*(arctan(sqrt(a*c*x + c)/sqrt(-c))/sqrt(-c) - sqrt(a*c*x + c)/c)*abs(c) - 2*(sqrt(c)*abs(c)*arctan(sqrt(2)*sqrt(c)/sqrt(-c)) - sqrt(2)*sqrt(-c)*abs (c))/(sqrt(-c)*sqrt(c))
Timed out. \[ \int \frac {e^{-\text {arctanh}(a x)} \sqrt {c-a c x}}{x} \, dx=\int \frac {\sqrt {1-a^2\,x^2}\,\sqrt {c-a\,c\,x}}{x\,\left (a\,x+1\right )} \,d x \] Input:
int(((1 - a^2*x^2)^(1/2)*(c - a*c*x)^(1/2))/(x*(a*x + 1)),x)
Output:
int(((1 - a^2*x^2)^(1/2)*(c - a*c*x)^(1/2))/(x*(a*x + 1)), x)
Time = 0.16 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.47 \[ \int \frac {e^{-\text {arctanh}(a x)} \sqrt {c-a c x}}{x} \, dx=\sqrt {c}\, \left (-2 \sqrt {a x +1}+\mathrm {log}\left (\sqrt {a x +1}-1\right )-\mathrm {log}\left (\sqrt {a x +1}+1\right )\right ) \] Input:
int((-a*c*x+c)^(1/2)/(a*x+1)*(-a^2*x^2+1)^(1/2)/x,x)
Output:
sqrt(c)*( - 2*sqrt(a*x + 1) + log(sqrt(a*x + 1) - 1) - log(sqrt(a*x + 1) + 1))