\(\int \frac {e^{-\text {arctanh}(a x)}}{(c-\frac {c}{a^2 x^2})^3} \, dx\) [694]

Optimal result

Integrand size = 22, antiderivative size = 152 \[ \int \frac {e^{-\text {arctanh}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^3} \, dx=-\frac {1}{a c^3 \left (1-a^2 x^2\right )^{3/2}}+\frac {11 x}{15 c^3 \left (1-a^2 x^2\right )^{3/2}}+\frac {1}{5 a c^3 (1+a x) \left (1-a^2 x^2\right )^{3/2}}+\frac {3}{a c^3 \sqrt {1-a^2 x^2}}-\frac {23 x}{15 c^3 \sqrt {1-a^2 x^2}}+\frac {\sqrt {1-a^2 x^2}}{a c^3}+\frac {\arcsin (a x)}{a c^3} \] Output:

-1/a/c^3/(-a^2*x^2+1)^(3/2)+11/15*x/c^3/(-a^2*x^2+1)^(3/2)+1/5/a/c^3/(a*x+ 
1)/(-a^2*x^2+1)^(3/2)+3/a/c^3/(-a^2*x^2+1)^(1/2)-23/15*x/c^3/(-a^2*x^2+1)^ 
(1/2)+(-a^2*x^2+1)^(1/2)/a/c^3+arcsin(a*x)/a/c^3
                                                                                    
                                                                                    
 

Mathematica [A] (verified)

Time = 0.05 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.71 \[ \int \frac {e^{-\text {arctanh}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^3} \, dx=\frac {-48-33 a x+87 a^2 x^2+52 a^3 x^3-38 a^4 x^4-15 a^5 x^5+15 (-1+a x) (1+a x)^2 \sqrt {1-a^2 x^2} \arcsin (a x)}{15 a c^3 (-1+a x) (1+a x)^2 \sqrt {1-a^2 x^2}} \] Input:

Integrate[1/(E^ArcTanh[a*x]*(c - c/(a^2*x^2))^3),x]
 

Output:

(-48 - 33*a*x + 87*a^2*x^2 + 52*a^3*x^3 - 38*a^4*x^4 - 15*a^5*x^5 + 15*(-1 
 + a*x)*(1 + a*x)^2*Sqrt[1 - a^2*x^2]*ArcSin[a*x])/(15*a*c^3*(-1 + a*x)*(1 
 + a*x)^2*Sqrt[1 - a^2*x^2])
 

Rubi [A] (verified)

Time = 0.57 (sec) , antiderivative size = 130, normalized size of antiderivative = 0.86, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {6707, 6699, 529, 2345, 2345, 27, 455, 223}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {e^{-\text {arctanh}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^3} \, dx\)

\(\Big \downarrow \) 6707

\(\displaystyle -\frac {a^6 \int \frac {e^{-\text {arctanh}(a x)} x^6}{\left (1-a^2 x^2\right )^3}dx}{c^3}\)

\(\Big \downarrow \) 6699

\(\displaystyle -\frac {a^6 \int \frac {x^6 (1-a x)}{\left (1-a^2 x^2\right )^{7/2}}dx}{c^3}\)

\(\Big \downarrow \) 529

\(\displaystyle -\frac {a^6 \left (-\frac {1}{5} \int \frac {-\frac {5 x^5}{a}+\frac {5 x^4}{a^2}-\frac {5 x^3}{a^3}+\frac {5 x^2}{a^4}-\frac {5 x}{a^5}+\frac {1}{a^6}}{\left (1-a^2 x^2\right )^{5/2}}dx-\frac {1-a x}{5 a^7 \left (1-a^2 x^2\right )^{5/2}}\right )}{c^3}\)

\(\Big \downarrow \) 2345

\(\displaystyle -\frac {a^6 \left (\frac {1}{5} \left (\frac {1}{3} \int \frac {-\frac {15 x^3}{a^3}+\frac {15 x^2}{a^4}-\frac {30 x}{a^5}+\frac {8}{a^6}}{\left (1-a^2 x^2\right )^{3/2}}dx+\frac {15-11 a x}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}\right )-\frac {1-a x}{5 a^7 \left (1-a^2 x^2\right )^{5/2}}\right )}{c^3}\)

\(\Big \downarrow \) 2345

\(\displaystyle -\frac {a^6 \left (\frac {1}{5} \left (\frac {1}{3} \left (-\int \frac {15 (1-a x)}{a^6 \sqrt {1-a^2 x^2}}dx-\frac {45-23 a x}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {15-11 a x}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}\right )-\frac {1-a x}{5 a^7 \left (1-a^2 x^2\right )^{5/2}}\right )}{c^3}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {a^6 \left (\frac {1}{5} \left (\frac {1}{3} \left (-\frac {15 \int \frac {1-a x}{\sqrt {1-a^2 x^2}}dx}{a^6}-\frac {45-23 a x}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {15-11 a x}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}\right )-\frac {1-a x}{5 a^7 \left (1-a^2 x^2\right )^{5/2}}\right )}{c^3}\)

\(\Big \downarrow \) 455

\(\displaystyle -\frac {a^6 \left (\frac {1}{5} \left (\frac {1}{3} \left (-\frac {15 \left (\int \frac {1}{\sqrt {1-a^2 x^2}}dx+\frac {\sqrt {1-a^2 x^2}}{a}\right )}{a^6}-\frac {45-23 a x}{a^7 \sqrt {1-a^2 x^2}}\right )+\frac {15-11 a x}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}\right )-\frac {1-a x}{5 a^7 \left (1-a^2 x^2\right )^{5/2}}\right )}{c^3}\)

\(\Big \downarrow \) 223

\(\displaystyle -\frac {a^6 \left (\frac {1}{5} \left (\frac {15-11 a x}{3 a^7 \left (1-a^2 x^2\right )^{3/2}}+\frac {1}{3} \left (-\frac {45-23 a x}{a^7 \sqrt {1-a^2 x^2}}-\frac {15 \left (\frac {\sqrt {1-a^2 x^2}}{a}+\frac {\arcsin (a x)}{a}\right )}{a^6}\right )\right )-\frac {1-a x}{5 a^7 \left (1-a^2 x^2\right )^{5/2}}\right )}{c^3}\)

Input:

Int[1/(E^ArcTanh[a*x]*(c - c/(a^2*x^2))^3),x]
 

Output:

-((a^6*(-1/5*(1 - a*x)/(a^7*(1 - a^2*x^2)^(5/2)) + ((15 - 11*a*x)/(3*a^7*( 
1 - a^2*x^2)^(3/2)) + (-((45 - 23*a*x)/(a^7*Sqrt[1 - a^2*x^2])) - (15*(Sqr 
t[1 - a^2*x^2]/a + ArcSin[a*x]/a))/a^6)/3)/5))/c^3)
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 223

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt 
[a])]/Rt[-b, 2], x] /; FreeQ[{a, b}, x] && GtQ[a, 0] && NegQ[b]
 

rule 455

Int[((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[d*(( 
a + b*x^2)^(p + 1)/(2*b*(p + 1))), x] + Simp[c   Int[(a + b*x^2)^p, x], x] 
/; FreeQ[{a, b, c, d, p}, x] &&  !LeQ[p, -1]
 

rule 529

Int[(x_)^(m_)*((c_) + (d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbo 
l] :> With[{Qx = PolynomialQuotient[x^m, a*d + b*c*x, x], R = PolynomialRem 
ainder[x^m, a*d + b*c*x, x]}, Simp[(-c)*R*(c + d*x)^n*((a + b*x^2)^(p + 1)/ 
(2*a*d*(p + 1))), x] + Simp[c/(2*a*(p + 1))   Int[(c + d*x)^(n - 1)*(a + b* 
x^2)^(p + 1)*ExpandToSum[2*a*d*(p + 1)*Qx + R*(n + 2*p + 2), x], x], x]] /; 
 FreeQ[{a, b, c, d}, x] && IGtQ[n, 0] && IGtQ[m, 1] && LtQ[p, -1] && EqQ[b* 
c^2 + a*d^2, 0]
 

rule 2345

Int[(Pq_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{Q = PolynomialQuot 
ient[Pq, a + b*x^2, x], f = Coeff[PolynomialRemainder[Pq, a + b*x^2, x], x, 
 0], g = Coeff[PolynomialRemainder[Pq, a + b*x^2, x], x, 1]}, Simp[(a*g - b 
*f*x)*((a + b*x^2)^(p + 1)/(2*a*b*(p + 1))), x] + Simp[1/(2*a*(p + 1))   In 
t[(a + b*x^2)^(p + 1)*ExpandToSum[2*a*(p + 1)*Q + f*(2*p + 3), x], x], x]] 
/; FreeQ[{a, b}, x] && PolyQ[Pq, x] && LtQ[p, -1]
 

rule 6699

Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x_ 
Symbol] :> Simp[c^p   Int[x^m*((1 - a^2*x^2)^(p + n/2)/(1 - a*x)^n), x], x] 
 /; FreeQ[{a, c, d, m, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || GtQ[c 
, 0]) && ILtQ[(n - 1)/2, 0] &&  !IntegerQ[p - n/2]
 

rule 6707

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_.), x_Symb 
ol] :> Simp[d^p   Int[(u/x^(2*p))*(1 - a^2*x^2)^p*E^(n*ArcTanh[a*x]), x], x 
] /; FreeQ[{a, c, d, n}, x] && EqQ[c + a^2*d, 0] && IntegerQ[p]
 

Maple [A] (verified)

Time = 0.38 (sec) , antiderivative size = 257, normalized size of antiderivative = 1.69

method	result	size
risch	\(-\frac {a^{2} x^{2}-1}{a \sqrt {-a^{2} x^{2}+1}\, c^{3}}-\frac {\left (-\frac {\arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-a^{2} x^{2}+1}}\right )}{a^{6} \sqrt {a^{2}}}-\frac {493 \sqrt {-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )}}{240 a^{8} \left (x +\frac {1}{a}\right )}+\frac {\sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}{24 a^{9} \left (x -\frac {1}{a}\right )^{2}}+\frac {25 \sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}{48 a^{8} \left (x -\frac {1}{a}\right )}-\frac {\sqrt {-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )}}{20 a^{10} \left (x +\frac {1}{a}\right )^{3}}+\frac {23 \sqrt {-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )}}{60 a^{9} \left (x +\frac {1}{a}\right )^{2}}\right ) a^{6}}{c^{3}}\)	\(257\)
default	\(\frac {a^{6} \left (\frac {\left (-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )\right )^{\frac {3}{2}}}{48 a^{10} \left (x -\frac {1}{a}\right )^{3}}+\frac {\frac {\left (-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )\right )^{\frac {3}{2}}}{a \left (x -\frac {1}{a}\right )^{2}}+a \left (\sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}-\frac {a \arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}\right )}{\sqrt {a^{2}}}\right )}{4 a^{8}}+\frac {\frac {11 \sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}{32}-\frac {11 a \arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2}-2 a \left (x -\frac {1}{a}\right )}}\right )}{32 \sqrt {a^{2}}}}{a^{7}}-\frac {-\frac {\left (-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )\right )^{\frac {3}{2}}}{5 a \left (x +\frac {1}{a}\right )^{4}}-\frac {\left (-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )\right )^{\frac {3}{2}}}{15 \left (x +\frac {1}{a}\right )^{3}}}{8 a^{10}}-\frac {3 \left (-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )\right )^{\frac {3}{2}}}{16 a^{10} \left (x +\frac {1}{a}\right )^{3}}-\frac {15 \left (-\frac {\left (-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )\right )^{\frac {3}{2}}}{a \left (x +\frac {1}{a}\right )^{2}}-a \left (\sqrt {-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )}+\frac {a \arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )}}\right )}{\sqrt {a^{2}}}\right )\right )}{16 a^{8}}+\frac {\frac {21 \sqrt {-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )}}{32}+\frac {21 a \arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-a^{2} \left (x +\frac {1}{a}\right )^{2}+2 a \left (x +\frac {1}{a}\right )}}\right )}{32 \sqrt {a^{2}}}}{a^{7}}\right )}{c^{3}}\)	\(526\)

Input:

int(1/(a*x+1)*(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^3,x,method=_RETURNVERBOSE)
 

Output:

-1/a*(a^2*x^2-1)/(-a^2*x^2+1)^(1/2)/c^3-(-1/a^6/(a^2)^(1/2)*arctan((a^2)^( 
1/2)*x/(-a^2*x^2+1)^(1/2))-493/240/a^8/(x+1/a)*(-a^2*(x+1/a)^2+2*a*(x+1/a) 
)^(1/2)+1/24/a^9/(x-1/a)^2*(-(x-1/a)^2*a^2-2*a*(x-1/a))^(1/2)+25/48/a^8/(x 
-1/a)*(-(x-1/a)^2*a^2-2*a*(x-1/a))^(1/2)-1/20/a^10/(x+1/a)^3*(-a^2*(x+1/a) 
^2+2*a*(x+1/a))^(1/2)+23/60/a^9/(x+1/a)^2*(-a^2*(x+1/a)^2+2*a*(x+1/a))^(1/ 
2))*a^6/c^3
 

Fricas [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 208, normalized size of antiderivative = 1.37 \[ \int \frac {e^{-\text {arctanh}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^3} \, dx=\frac {48 \, a^{5} x^{5} + 48 \, a^{4} x^{4} - 96 \, a^{3} x^{3} - 96 \, a^{2} x^{2} + 48 \, a x - 30 \, {\left (a^{5} x^{5} + a^{4} x^{4} - 2 \, a^{3} x^{3} - 2 \, a^{2} x^{2} + a x + 1\right )} \arctan \left (\frac {\sqrt {-a^{2} x^{2} + 1} - 1}{a x}\right ) + {\left (15 \, a^{5} x^{5} + 38 \, a^{4} x^{4} - 52 \, a^{3} x^{3} - 87 \, a^{2} x^{2} + 33 \, a x + 48\right )} \sqrt {-a^{2} x^{2} + 1} + 48}{15 \, {\left (a^{6} c^{3} x^{5} + a^{5} c^{3} x^{4} - 2 \, a^{4} c^{3} x^{3} - 2 \, a^{3} c^{3} x^{2} + a^{2} c^{3} x + a c^{3}\right )}} \] Input:

integrate(1/(a*x+1)*(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^3,x, algorithm="frica 
s")
 

Output:

1/15*(48*a^5*x^5 + 48*a^4*x^4 - 96*a^3*x^3 - 96*a^2*x^2 + 48*a*x - 30*(a^5 
*x^5 + a^4*x^4 - 2*a^3*x^3 - 2*a^2*x^2 + a*x + 1)*arctan((sqrt(-a^2*x^2 + 
1) - 1)/(a*x)) + (15*a^5*x^5 + 38*a^4*x^4 - 52*a^3*x^3 - 87*a^2*x^2 + 33*a 
*x + 48)*sqrt(-a^2*x^2 + 1) + 48)/(a^6*c^3*x^5 + a^5*c^3*x^4 - 2*a^4*c^3*x 
^3 - 2*a^3*c^3*x^2 + a^2*c^3*x + a*c^3)
 

Sympy [F]

\[ \int \frac {e^{-\text {arctanh}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^3} \, dx=\frac {a^{6} \int \frac {x^{6} \sqrt {- a^{2} x^{2} + 1}}{a^{7} x^{7} + a^{6} x^{6} - 3 a^{5} x^{5} - 3 a^{4} x^{4} + 3 a^{3} x^{3} + 3 a^{2} x^{2} - a x - 1}\, dx}{c^{3}} \] Input:

integrate(1/(a*x+1)*(-a**2*x**2+1)**(1/2)/(c-c/a**2/x**2)**3,x)
 

Output:

a**6*Integral(x**6*sqrt(-a**2*x**2 + 1)/(a**7*x**7 + a**6*x**6 - 3*a**5*x* 
*5 - 3*a**4*x**4 + 3*a**3*x**3 + 3*a**2*x**2 - a*x - 1), x)/c**3
 

Maxima [F]

\[ \int \frac {e^{-\text {arctanh}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^3} \, dx=\int { \frac {\sqrt {-a^{2} x^{2} + 1}}{{\left (a x + 1\right )} {\left (c - \frac {c}{a^{2} x^{2}}\right )}^{3}} \,d x } \] Input:

integrate(1/(a*x+1)*(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^3,x, algorithm="maxim 
a")
 

Output:

integrate(sqrt(-a^2*x^2 + 1)/((a*x + 1)*(c - c/(a^2*x^2))^3), x)
 

Giac [F]

\[ \int \frac {e^{-\text {arctanh}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^3} \, dx=\int { \frac {\sqrt {-a^{2} x^{2} + 1}}{{\left (a x + 1\right )} {\left (c - \frac {c}{a^{2} x^{2}}\right )}^{3}} \,d x } \] Input:

integrate(1/(a*x+1)*(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^3,x, algorithm="giac" 
)
 

Output:

integrate(sqrt(-a^2*x^2 + 1)/((a*x + 1)*(c - c/(a^2*x^2))^3), x)
 

Mupad [B] (verification not implemented)

Time = 14.34 (sec) , antiderivative size = 365, normalized size of antiderivative = 2.40 \[ \int \frac {e^{-\text {arctanh}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^3} \, dx=\frac {\mathrm {asinh}\left (x\,\sqrt {-a^2}\right )}{c^3\,\sqrt {-a^2}}-\frac {5\,a\,\sqrt {1-a^2\,x^2}}{12\,\left (a^4\,c^3\,x^2+2\,a^3\,c^3\,x+a^2\,c^3\right )}-\frac {a\,\sqrt {1-a^2\,x^2}}{24\,\left (a^4\,c^3\,x^2-2\,a^3\,c^3\,x+a^2\,c^3\right )}+\frac {a^6\,\sqrt {1-a^2\,x^2}}{30\,\left (a^9\,c^3\,x^2+2\,a^8\,c^3\,x+a^7\,c^3\right )}+\frac {\sqrt {1-a^2\,x^2}}{a\,c^3}-\frac {493\,\sqrt {1-a^2\,x^2}}{240\,\sqrt {-a^2}\,\left (c^3\,x\,\sqrt {-a^2}+\frac {c^3\,\sqrt {-a^2}}{a}\right )}+\frac {25\,\sqrt {1-a^2\,x^2}}{48\,\sqrt {-a^2}\,\left (c^3\,x\,\sqrt {-a^2}-\frac {c^3\,\sqrt {-a^2}}{a}\right )}-\frac {\sqrt {1-a^2\,x^2}}{20\,\sqrt {-a^2}\,\left (3\,c^3\,x\,\sqrt {-a^2}+\frac {c^3\,\sqrt {-a^2}}{a}+a^2\,c^3\,x^3\,\sqrt {-a^2}+3\,a\,c^3\,x^2\,\sqrt {-a^2}\right )} \] Input:

int((1 - a^2*x^2)^(1/2)/((c - c/(a^2*x^2))^3*(a*x + 1)),x)
 

Output:

asinh(x*(-a^2)^(1/2))/(c^3*(-a^2)^(1/2)) - (5*a*(1 - a^2*x^2)^(1/2))/(12*( 
a^2*c^3 + 2*a^3*c^3*x + a^4*c^3*x^2)) - (a*(1 - a^2*x^2)^(1/2))/(24*(a^2*c 
^3 - 2*a^3*c^3*x + a^4*c^3*x^2)) + (a^6*(1 - a^2*x^2)^(1/2))/(30*(a^7*c^3 
+ 2*a^8*c^3*x + a^9*c^3*x^2)) + (1 - a^2*x^2)^(1/2)/(a*c^3) - (493*(1 - a^ 
2*x^2)^(1/2))/(240*(-a^2)^(1/2)*(c^3*x*(-a^2)^(1/2) + (c^3*(-a^2)^(1/2))/a 
)) + (25*(1 - a^2*x^2)^(1/2))/(48*(-a^2)^(1/2)*(c^3*x*(-a^2)^(1/2) - (c^3* 
(-a^2)^(1/2))/a)) - (1 - a^2*x^2)^(1/2)/(20*(-a^2)^(1/2)*(3*c^3*x*(-a^2)^( 
1/2) + (c^3*(-a^2)^(1/2))/a + a^2*c^3*x^3*(-a^2)^(1/2) + 3*a*c^3*x^2*(-a^2 
)^(1/2)))
 

Reduce [B] (verification not implemented)

Time = 0.16 (sec) , antiderivative size = 229, normalized size of antiderivative = 1.51 \[ \int \frac {e^{-\text {arctanh}(a x)}}{\left (c-\frac {c}{a^2 x^2}\right )^3} \, dx=\frac {15 \sqrt {-a^{2} x^{2}+1}\, \mathit {asin} \left (a x \right ) a^{3} x^{3}+15 \sqrt {-a^{2} x^{2}+1}\, \mathit {asin} \left (a x \right ) a^{2} x^{2}-15 \sqrt {-a^{2} x^{2}+1}\, \mathit {asin} \left (a x \right ) a x -15 \sqrt {-a^{2} x^{2}+1}\, \mathit {asin} \left (a x \right )+33 \sqrt {-a^{2} x^{2}+1}\, a^{3} x^{3}+33 \sqrt {-a^{2} x^{2}+1}\, a^{2} x^{2}-33 \sqrt {-a^{2} x^{2}+1}\, a x -33 \sqrt {-a^{2} x^{2}+1}-15 a^{5} x^{5}-38 a^{4} x^{4}+52 a^{3} x^{3}+87 a^{2} x^{2}-33 a x -48}{15 \sqrt {-a^{2} x^{2}+1}\, a \,c^{3} \left (a^{3} x^{3}+a^{2} x^{2}-a x -1\right )} \] Input:

int(1/(a*x+1)*(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^3,x)
 

Output:

(15*sqrt( - a**2*x**2 + 1)*asin(a*x)*a**3*x**3 + 15*sqrt( - a**2*x**2 + 1) 
*asin(a*x)*a**2*x**2 - 15*sqrt( - a**2*x**2 + 1)*asin(a*x)*a*x - 15*sqrt( 
- a**2*x**2 + 1)*asin(a*x) + 33*sqrt( - a**2*x**2 + 1)*a**3*x**3 + 33*sqrt 
( - a**2*x**2 + 1)*a**2*x**2 - 33*sqrt( - a**2*x**2 + 1)*a*x - 33*sqrt( - 
a**2*x**2 + 1) - 15*a**5*x**5 - 38*a**4*x**4 + 52*a**3*x**3 + 87*a**2*x**2 
 - 33*a*x - 48)/(15*sqrt( - a**2*x**2 + 1)*a*c**3*(a**3*x**3 + a**2*x**2 - 
 a*x - 1))