Integrand size = 7, antiderivative size = 49 \[ \int \log \left (a \tan ^2(x)\right ) \, dx=4 x \text {arctanh}\left (e^{2 i x}\right )+x \log \left (a \tan ^2(x)\right )-i \operatorname {PolyLog}\left (2,-e^{2 i x}\right )+i \operatorname {PolyLog}\left (2,e^{2 i x}\right ) \] Output:
4*x*arctanh(exp(2*I*x))+x*ln(a*tan(x)^2)-I*polylog(2,-exp(2*I*x))+I*polylo g(2,exp(2*I*x))
Time = 0.02 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.53 \[ \int \log \left (a \tan ^2(x)\right ) \, dx=-\frac {1}{2} i \log (-i (i-\tan (x))) \log \left (a \tan ^2(x)\right )+\frac {1}{2} i \log \left (a \tan ^2(x)\right ) \log (-i (i+\tan (x)))-i \operatorname {PolyLog}(2,-i \tan (x))+i \operatorname {PolyLog}(2,i \tan (x)) \] Input:
Integrate[Log[a*Tan[x]^2],x]
Output:
(-1/2*I)*Log[(-I)*(I - Tan[x])]*Log[a*Tan[x]^2] + (I/2)*Log[a*Tan[x]^2]*Lo g[(-I)*(I + Tan[x])] - I*PolyLog[2, (-I)*Tan[x]] + I*PolyLog[2, I*Tan[x]]
Time = 0.36 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.14, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.000, Rules used = {3028, 27, 4919, 3042, 4671, 2715, 2838}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \log \left (a \tan ^2(x)\right ) \, dx\) |
\(\Big \downarrow \) 3028 |
\(\displaystyle x \log \left (a \tan ^2(x)\right )-\int 2 x \csc (x) \sec (x)dx\) |
\(\Big \downarrow \) 27 |
\(\displaystyle x \log \left (a \tan ^2(x)\right )-2 \int x \csc (x) \sec (x)dx\) |
\(\Big \downarrow \) 4919 |
\(\displaystyle x \log \left (a \tan ^2(x)\right )-4 \int x \csc (2 x)dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle x \log \left (a \tan ^2(x)\right )-4 \int x \csc (2 x)dx\) |
\(\Big \downarrow \) 4671 |
\(\displaystyle x \log \left (a \tan ^2(x)\right )-4 \left (-\frac {1}{2} \int \log \left (1-e^{2 i x}\right )dx+\frac {1}{2} \int \log \left (1+e^{2 i x}\right )dx-x \text {arctanh}\left (e^{2 i x}\right )\right )\) |
\(\Big \downarrow \) 2715 |
\(\displaystyle x \log \left (a \tan ^2(x)\right )-4 \left (\frac {1}{4} i \int e^{-2 i x} \log \left (1-e^{2 i x}\right )de^{2 i x}-\frac {1}{4} i \int e^{-2 i x} \log \left (1+e^{2 i x}\right )de^{2 i x}-x \text {arctanh}\left (e^{2 i x}\right )\right )\) |
\(\Big \downarrow \) 2838 |
\(\displaystyle x \log \left (a \tan ^2(x)\right )-4 \left (-x \text {arctanh}\left (e^{2 i x}\right )+\frac {1}{4} i \operatorname {PolyLog}\left (2,-e^{2 i x}\right )-\frac {1}{4} i \operatorname {PolyLog}\left (2,e^{2 i x}\right )\right )\) |
Input:
Int[Log[a*Tan[x]^2],x]
Output:
x*Log[a*Tan[x]^2] - 4*(-(x*ArcTanh[E^((2*I)*x)]) + (I/4)*PolyLog[2, -E^((2 *I)*x)] - (I/4)*PolyLog[2, E^((2*I)*x)])
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Simp[1/(d*e*n*Log[F]) Subst[Int[Log[a + b*x]/x, x], x, (F^(e*(c + d*x) ))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]
Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2 , (-c)*e*x^n]/n, x] /; FreeQ[{c, d, e, n}, x] && EqQ[c*d, 1]
Int[Log[u_], x_Symbol] :> Simp[x*Log[u], x] - Int[SimplifyIntegrand[x*(D[u, x]/u), x], x] /; InverseFunctionFreeQ[u, x]
Int[csc[(e_.) + (f_.)*(x_)]*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[- 2*(c + d*x)^m*(ArcTanh[E^(I*(e + f*x))]/f), x] + (-Simp[d*(m/f) Int[(c + d*x)^(m - 1)*Log[1 - E^(I*(e + f*x))], x], x] + Simp[d*(m/f) Int[(c + d*x )^(m - 1)*Log[1 + E^(I*(e + f*x))], x], x]) /; FreeQ[{c, d, e, f}, x] && IG tQ[m, 0]
Int[Csc[(a_.) + (b_.)*(x_)]^(n_.)*((c_.) + (d_.)*(x_))^(m_.)*Sec[(a_.) + (b _.)*(x_)]^(n_.), x_Symbol] :> Simp[2^n Int[(c + d*x)^m*Csc[2*a + 2*b*x]^n , x], x] /; FreeQ[{a, b, c, d, m}, x] && IntegerQ[n] && RationalQ[m]
Time = 0.49 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.67
method | result | size |
derivativedivides | \(-\frac {i \left (\ln \left (\tan \left (x \right )-i\right ) \ln \left (a \tan \left (x \right )^{2}\right )-2 \operatorname {dilog}\left (-i \tan \left (x \right )\right )-2 \ln \left (\tan \left (x \right )-i\right ) \ln \left (-i \tan \left (x \right )\right )\right )}{2}+\frac {i \left (\ln \left (\tan \left (x \right )+i\right ) \ln \left (a \tan \left (x \right )^{2}\right )-2 \operatorname {dilog}\left (i \tan \left (x \right )\right )-2 \ln \left (\tan \left (x \right )+i\right ) \ln \left (i \tan \left (x \right )\right )\right )}{2}\) | \(82\) |
default | \(-\frac {i \left (\ln \left (\tan \left (x \right )-i\right ) \ln \left (a \tan \left (x \right )^{2}\right )-2 \operatorname {dilog}\left (-i \tan \left (x \right )\right )-2 \ln \left (\tan \left (x \right )-i\right ) \ln \left (-i \tan \left (x \right )\right )\right )}{2}+\frac {i \left (\ln \left (\tan \left (x \right )+i\right ) \ln \left (a \tan \left (x \right )^{2}\right )-2 \operatorname {dilog}\left (i \tan \left (x \right )\right )-2 \ln \left (\tan \left (x \right )+i\right ) \ln \left (i \tan \left (x \right )\right )\right )}{2}\) | \(82\) |
risch | \(\text {Expression too large to display}\) | \(664\) |
Input:
int(ln(a*tan(x)^2),x,method=_RETURNVERBOSE)
Output:
-1/2*I*(ln(tan(x)-I)*ln(a*tan(x)^2)-2*dilog(-I*tan(x))-2*ln(tan(x)-I)*ln(- I*tan(x)))+1/2*I*(ln(tan(x)+I)*ln(a*tan(x)^2)-2*dilog(I*tan(x))-2*ln(tan(x )+I)*ln(I*tan(x)))
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 184 vs. \(2 (34) = 68\).
Time = 0.09 (sec) , antiderivative size = 184, normalized size of antiderivative = 3.76 \[ \int \log \left (a \tan ^2(x)\right ) \, dx=x \log \left (a \tan \left (x\right )^{2}\right ) - x \log \left (\frac {2 \, {\left (\tan \left (x\right )^{2} + i \, \tan \left (x\right )\right )}}{\tan \left (x\right )^{2} + 1}\right ) - x \log \left (\frac {2 \, {\left (\tan \left (x\right )^{2} - i \, \tan \left (x\right )\right )}}{\tan \left (x\right )^{2} + 1}\right ) + x \log \left (-\frac {2 \, {\left (i \, \tan \left (x\right ) - 1\right )}}{\tan \left (x\right )^{2} + 1}\right ) + x \log \left (-\frac {2 \, {\left (-i \, \tan \left (x\right ) - 1\right )}}{\tan \left (x\right )^{2} + 1}\right ) - \frac {1}{2} i \, {\rm Li}_2\left (-\frac {2 \, {\left (\tan \left (x\right )^{2} + i \, \tan \left (x\right )\right )}}{\tan \left (x\right )^{2} + 1} + 1\right ) + \frac {1}{2} i \, {\rm Li}_2\left (-\frac {2 \, {\left (\tan \left (x\right )^{2} - i \, \tan \left (x\right )\right )}}{\tan \left (x\right )^{2} + 1} + 1\right ) + \frac {1}{2} i \, {\rm Li}_2\left (\frac {2 \, {\left (i \, \tan \left (x\right ) - 1\right )}}{\tan \left (x\right )^{2} + 1} + 1\right ) - \frac {1}{2} i \, {\rm Li}_2\left (\frac {2 \, {\left (-i \, \tan \left (x\right ) - 1\right )}}{\tan \left (x\right )^{2} + 1} + 1\right ) \] Input:
integrate(log(a*tan(x)^2),x, algorithm="fricas")
Output:
x*log(a*tan(x)^2) - x*log(2*(tan(x)^2 + I*tan(x))/(tan(x)^2 + 1)) - x*log( 2*(tan(x)^2 - I*tan(x))/(tan(x)^2 + 1)) + x*log(-2*(I*tan(x) - 1)/(tan(x)^ 2 + 1)) + x*log(-2*(-I*tan(x) - 1)/(tan(x)^2 + 1)) - 1/2*I*dilog(-2*(tan(x )^2 + I*tan(x))/(tan(x)^2 + 1) + 1) + 1/2*I*dilog(-2*(tan(x)^2 - I*tan(x)) /(tan(x)^2 + 1) + 1) + 1/2*I*dilog(2*(I*tan(x) - 1)/(tan(x)^2 + 1) + 1) - 1/2*I*dilog(2*(-I*tan(x) - 1)/(tan(x)^2 + 1) + 1)
\[ \int \log \left (a \tan ^2(x)\right ) \, dx=\int \log {\left (a \tan ^{2}{\left (x \right )} \right )}\, dx \] Input:
integrate(ln(a*tan(x)**2),x)
Output:
Integral(log(a*tan(x)**2), x)
Time = 0.11 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.90 \[ \int \log \left (a \tan ^2(x)\right ) \, dx=x \log \left (a \tan \left (x\right )^{2}\right ) + \frac {1}{2} \, \pi \log \left (\tan \left (x\right )^{2} + 1\right ) - 2 \, x \log \left (\tan \left (x\right )\right ) + i \, {\rm Li}_2\left (i \, \tan \left (x\right ) + 1\right ) - i \, {\rm Li}_2\left (-i \, \tan \left (x\right ) + 1\right ) \] Input:
integrate(log(a*tan(x)^2),x, algorithm="maxima")
Output:
x*log(a*tan(x)^2) + 1/2*pi*log(tan(x)^2 + 1) - 2*x*log(tan(x)) + I*dilog(I *tan(x) + 1) - I*dilog(-I*tan(x) + 1)
\[ \int \log \left (a \tan ^2(x)\right ) \, dx=\int { \log \left (a \tan \left (x\right )^{2}\right ) \,d x } \] Input:
integrate(log(a*tan(x)^2),x, algorithm="giac")
Output:
integrate(log(a*tan(x)^2), x)
Time = 0.06 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.84 \[ \int \log \left (a \tan ^2(x)\right ) \, dx=x\,\ln \left (a\,{\mathrm {tan}\left (x\right )}^2\right )-\mathrm {polylog}\left (2,-{\mathrm {e}}^{x\,2{}\mathrm {i}}\right )\,1{}\mathrm {i}+4\,x\,\mathrm {atanh}\left ({\mathrm {e}}^{x\,2{}\mathrm {i}}\right )+\mathrm {polylog}\left (2,{\mathrm {e}}^{x\,2{}\mathrm {i}}\right )\,1{}\mathrm {i} \] Input:
int(log(a*tan(x)^2),x)
Output:
x*log(a*tan(x)^2) - polylog(2, -exp(x*2i))*1i + 4*x*atanh(exp(x*2i)) + pol ylog(2, exp(x*2i))*1i
\[ \int \log \left (a \tan ^2(x)\right ) \, dx=\int \mathrm {log}\left (\tan \left (x \right )^{2} a \right )d x \] Input:
int(log(a*tan(x)^2),x)
Output:
int(log(tan(x)**2*a),x)