\(\int \frac {a+b \log (c x^n)}{d+e \log (f x^m)} \, dx\) [178]

Optimal result
Mathematica [A] (verified)
Rubi [A] (warning: unable to verify)
Maple [C] (warning: unable to verify)
Fricas [A] (verification not implemented)
Sympy [F]
Maxima [F]
Giac [A] (verification not implemented)
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 23, antiderivative size = 130 \[ \int \frac {a+b \log \left (c x^n\right )}{d+e \log \left (f x^m\right )} \, dx=\frac {b n x}{e m}-\frac {b e^{-\frac {d}{e m}} n x \left (f x^m\right )^{-1/m} \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right ) \left (d+e \log \left (f x^m\right )\right )}{e^2 m^2}+\frac {e^{-\frac {d}{e m}} x \left (f x^m\right )^{-1/m} \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right ) \left (a+b \log \left (c x^n\right )\right )}{e m} \] Output:

b*n*x/e/m-b*n*x*Ei((d+e*ln(f*x^m))/e/m)*(d+e*ln(f*x^m))/e^2/exp(d/e/m)/m^2 
/((f*x^m)^(1/m))+x*Ei((d+e*ln(f*x^m))/e/m)*(a+b*ln(c*x^n))/e/exp(d/e/m)/m/ 
((f*x^m)^(1/m))
 

Mathematica [A] (verified)

Time = 0.15 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.66 \[ \int \frac {a+b \log \left (c x^n\right )}{d+e \log \left (f x^m\right )} \, dx=\frac {x \left (b e m n+e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right ) \left (a e m-b d n-b e n \log \left (f x^m\right )+b e m \log \left (c x^n\right )\right )\right )}{e^2 m^2} \] Input:

Integrate[(a + b*Log[c*x^n])/(d + e*Log[f*x^m]),x]
 

Output:

(x*(b*e*m*n + (ExpIntegralEi[(d + e*Log[f*x^m])/(e*m)]*(a*e*m - b*d*n - b* 
e*n*Log[f*x^m] + b*e*m*Log[c*x^n]))/(E^(d/(e*m))*(f*x^m)^m^(-1))))/(e^2*m^ 
2)
 

Rubi [A] (warning: unable to verify)

Time = 0.59 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.07, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.261, Rules used = {2808, 27, 34, 3039, 7281, 7036}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {a+b \log \left (c x^n\right )}{d+e \log \left (f x^m\right )} \, dx\)

\(\Big \downarrow \) 2808

\(\displaystyle \frac {x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \left (a+b \log \left (c x^n\right )\right ) \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )}{e m}-b n \int \frac {e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )}{e m}dx\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \left (a+b \log \left (c x^n\right )\right ) \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )}{e m}-\frac {b n e^{-\frac {d}{e m}} \int \left (f x^m\right )^{-1/m} \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )dx}{e m}\)

\(\Big \downarrow \) 34

\(\displaystyle \frac {x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \left (a+b \log \left (c x^n\right )\right ) \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )}{e m}-\frac {b n x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \int \frac {\operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )}{x}dx}{e m}\)

\(\Big \downarrow \) 3039

\(\displaystyle \frac {x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \left (a+b \log \left (c x^n\right )\right ) \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )}{e m}-\frac {b n x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \int \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )d\log \left (f x^m\right )}{e m^2}\)

\(\Big \downarrow \) 7281

\(\displaystyle \frac {x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \left (a+b \log \left (c x^n\right )\right ) \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )}{e m}-\frac {b n x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \int \operatorname {ExpIntegralEi}\left (\frac {d}{e m}+\frac {\log \left (f x^m\right )}{m}\right )d\left (\frac {d}{e m}+\frac {\log \left (f x^m\right )}{m}\right )}{e m}\)

\(\Big \downarrow \) 7036

\(\displaystyle \frac {x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \left (a+b \log \left (c x^n\right )\right ) \operatorname {ExpIntegralEi}\left (\frac {d+e \log \left (f x^m\right )}{e m}\right )}{e m}-\frac {b n x e^{-\frac {d}{e m}} \left (f x^m\right )^{-1/m} \left (\left (\frac {d}{e m}+\frac {\log \left (f x^m\right )}{m}\right ) \operatorname {ExpIntegralEi}\left (\frac {d}{e m}+\frac {\log \left (f x^m\right )}{m}\right )-f x^m\right )}{e m}\)

Input:

Int[(a + b*Log[c*x^n])/(d + e*Log[f*x^m]),x]
 

Output:

-((b*n*x*(-(f*x^m) + ExpIntegralEi[d/(e*m) + Log[f*x^m]/m]*(d/(e*m) + Log[ 
f*x^m]/m)))/(e*E^(d/(e*m))*m*(f*x^m)^m^(-1))) + (x*ExpIntegralEi[(d + e*Lo 
g[f*x^m])/(e*m)]*(a + b*Log[c*x^n]))/(e*E^(d/(e*m))*m*(f*x^m)^m^(-1))
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 34
Int[(u_.)*((a_.)*(x_)^(m_))^(p_), x_Symbol] :> Simp[a^IntPart[p]*((a*x^m)^F 
racPart[p]/x^(m*FracPart[p]))   Int[u*x^(m*p), x], x] /; FreeQ[{a, m, p}, x 
] &&  !IntegerQ[p]
 

rule 2808
Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_.) + Log[(f_.)*(x_)^(r_ 
.)]*(e_.)), x_Symbol] :> With[{u = IntHide[(a + b*Log[c*x^n])^p, x]}, Simp[ 
(d + e*Log[f*x^r])   u, x] - Simp[e*r   Int[SimplifyIntegrand[u/x, x], x], 
x]] /; FreeQ[{a, b, c, d, e, f, n, p, r}, x]
 

rule 3039
Int[u_, x_Symbol] :> With[{lst = FunctionOfLog[Cancel[x*u], x]}, Simp[1/lst 
[[3]]   Subst[Int[lst[[1]], x], x, Log[lst[[2]]]], x] /;  !FalseQ[lst]] /; 
NonsumQ[u]
 

rule 7036
Int[ExpIntegralEi[(a_.) + (b_.)*(x_)], x_Symbol] :> Simp[(a + b*x)*(ExpInte 
gralEi[a + b*x]/b), x] - Simp[E^(a + b*x)/b, x] /; FreeQ[{a, b}, x]
 

rule 7281
Int[u_, x_Symbol] :> With[{lst = FunctionOfLinear[u, x]}, Simp[1/lst[[3]] 
 Subst[Int[lst[[1]], x], x, lst[[2]] + lst[[3]]*x], x] /;  !FalseQ[lst]]
 
Maple [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 1.05 (sec) , antiderivative size = 2329, normalized size of antiderivative = 17.92

method result size
risch \(\text {Expression too large to display}\) \(2329\)

Input:

int((a+b*ln(c*x^n))/(d+e*ln(f*x^m)),x,method=_RETURNVERBOSE)
 

Output:

-1/2*(I*Pi*b*csgn(I*x^n)*csgn(I*c*x^n)^2-I*Pi*b*csgn(I*x^n)*csgn(I*c*x^n)* 
csgn(I*c)-I*Pi*b*csgn(I*c*x^n)^3+I*Pi*b*csgn(I*c*x^n)^2*csgn(I*c)+2*b*ln(c 
)+2*a)/m/e*x*f^(-1/m)*(x^m)^(-1/m)*exp(-1/2*(-I*Pi*csgn(I*f)*csgn(I*x^m)*c 
sgn(I*f*x^m)*e+I*Pi*csgn(I*f)*csgn(I*f*x^m)^2*e+I*Pi*csgn(I*x^m)*csgn(I*f* 
x^m)^2*e-I*Pi*csgn(I*f*x^m)^3*e+2*d)/m/e)*Ei(1,-ln(x)+1/2*I*(e*Pi*csgn(I*f 
)*csgn(I*x^m)*csgn(I*f*x^m)-e*Pi*csgn(I*f)*csgn(I*f*x^m)^2-e*Pi*csgn(I*x^m 
)*csgn(I*f*x^m)^2+e*Pi*csgn(I*f*x^m)^3+2*I*e*ln(f)+2*I*e*(ln(x^m)-m*ln(x)) 
+2*I*d)/m/e)-b/m/e*x*f^(-1/m)*(x^m)^(-1/m)*exp(-1/2*(-I*Pi*csgn(I*f)*csgn( 
I*x^m)*csgn(I*f*x^m)*e+I*Pi*csgn(I*f)*csgn(I*f*x^m)^2*e+I*Pi*csgn(I*x^m)*c 
sgn(I*f*x^m)^2*e-I*Pi*csgn(I*f*x^m)^3*e+2*d)/m/e)*Ei(1,-ln(x)+1/2*I*(e*Pi* 
csgn(I*f)*csgn(I*x^m)*csgn(I*f*x^m)-e*Pi*csgn(I*f)*csgn(I*f*x^m)^2-e*Pi*cs 
gn(I*x^m)*csgn(I*f*x^m)^2+e*Pi*csgn(I*f*x^m)^3+2*I*e*ln(f)+2*I*e*(ln(x^m)- 
m*ln(x))+2*I*d)/m/e)*ln(x^n)+b*n*x/e/m-1/2*I*b*n/m^2/e*x*f^(-1/m)*(x^m)^(- 
1/m)*exp(-1/2*(-I*Pi*csgn(I*f)*csgn(I*x^m)*csgn(I*f*x^m)*e+I*Pi*csgn(I*f)* 
csgn(I*f*x^m)^2*e+I*Pi*csgn(I*x^m)*csgn(I*f*x^m)^2*e-I*Pi*csgn(I*f*x^m)^3* 
e+2*d)/m/e)*Ei(1,-ln(x)+1/2*I*(e*Pi*csgn(I*f)*csgn(I*x^m)*csgn(I*f*x^m)-e* 
Pi*csgn(I*f)*csgn(I*f*x^m)^2-e*Pi*csgn(I*x^m)*csgn(I*f*x^m)^2+e*Pi*csgn(I* 
f*x^m)^3+2*I*e*ln(f)+2*I*e*(ln(x^m)-m*ln(x))+2*I*d)/m/e)*Pi*csgn(I*f)*csgn 
(I*x^m)*csgn(I*f*x^m)+1/2*I*b*n/m^2/e*x*f^(-1/m)*(x^m)^(-1/m)*exp(-1/2*(-I 
*Pi*csgn(I*f)*csgn(I*x^m)*csgn(I*f*x^m)*e+I*Pi*csgn(I*f)*csgn(I*f*x^m)^...
 

Fricas [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.65 \[ \int \frac {a+b \log \left (c x^n\right )}{d+e \log \left (f x^m\right )} \, dx=\frac {{\left (b e m n x e^{\left (\frac {e \log \left (f\right ) + d}{e m}\right )} + {\left (b e m \log \left (c\right ) - b e n \log \left (f\right ) + a e m - b d n\right )} \operatorname {log\_integral}\left (x e^{\left (\frac {e \log \left (f\right ) + d}{e m}\right )}\right )\right )} e^{\left (-\frac {e \log \left (f\right ) + d}{e m}\right )}}{e^{2} m^{2}} \] Input:

integrate((a+b*log(c*x^n))/(d+e*log(f*x^m)),x, algorithm="fricas")
 

Output:

(b*e*m*n*x*e^((e*log(f) + d)/(e*m)) + (b*e*m*log(c) - b*e*n*log(f) + a*e*m 
 - b*d*n)*log_integral(x*e^((e*log(f) + d)/(e*m))))*e^(-(e*log(f) + d)/(e* 
m))/(e^2*m^2)
 

Sympy [F]

\[ \int \frac {a+b \log \left (c x^n\right )}{d+e \log \left (f x^m\right )} \, dx=\int \frac {a + b \log {\left (c x^{n} \right )}}{d + e \log {\left (f x^{m} \right )}}\, dx \] Input:

integrate((a+b*ln(c*x**n))/(d+e*ln(f*x**m)),x)
 

Output:

Integral((a + b*log(c*x**n))/(d + e*log(f*x**m)), x)
 

Maxima [F]

\[ \int \frac {a+b \log \left (c x^n\right )}{d+e \log \left (f x^m\right )} \, dx=\int { \frac {b \log \left (c x^{n}\right ) + a}{e \log \left (f x^{m}\right ) + d} \,d x } \] Input:

integrate((a+b*log(c*x^n))/(d+e*log(f*x^m)),x, algorithm="maxima")
 

Output:

integrate((b*log(c*x^n) + a)/(e*log(f*x^m) + d), x)
 

Giac [A] (verification not implemented)

Time = 0.13 (sec) , antiderivative size = 192, normalized size of antiderivative = 1.48 \[ \int \frac {a+b \log \left (c x^n\right )}{d+e \log \left (f x^m\right )} \, dx=\frac {b n x}{e m} + \frac {b {\rm Ei}\left (\frac {\log \left (f\right )}{m} + \frac {d}{e m} + \log \left (x\right )\right ) e^{\left (-\frac {d}{e m}\right )} \log \left (c\right )}{e f^{\left (\frac {1}{m}\right )} m} - \frac {b n {\rm Ei}\left (\frac {\log \left (f\right )}{m} + \frac {d}{e m} + \log \left (x\right )\right ) e^{\left (-\frac {d}{e m}\right )} \log \left (f\right )}{e f^{\left (\frac {1}{m}\right )} m^{2}} + \frac {a {\rm Ei}\left (\frac {\log \left (f\right )}{m} + \frac {d}{e m} + \log \left (x\right )\right ) e^{\left (-\frac {d}{e m}\right )}}{e f^{\left (\frac {1}{m}\right )} m} - \frac {b d n {\rm Ei}\left (\frac {\log \left (f\right )}{m} + \frac {d}{e m} + \log \left (x\right )\right ) e^{\left (-\frac {d}{e m}\right )}}{e^{2} f^{\left (\frac {1}{m}\right )} m^{2}} \] Input:

integrate((a+b*log(c*x^n))/(d+e*log(f*x^m)),x, algorithm="giac")
 

Output:

b*n*x/(e*m) + b*Ei(log(f)/m + d/(e*m) + log(x))*e^(-d/(e*m))*log(c)/(e*f^( 
1/m)*m) - b*n*Ei(log(f)/m + d/(e*m) + log(x))*e^(-d/(e*m))*log(f)/(e*f^(1/ 
m)*m^2) + a*Ei(log(f)/m + d/(e*m) + log(x))*e^(-d/(e*m))/(e*f^(1/m)*m) - b 
*d*n*Ei(log(f)/m + d/(e*m) + log(x))*e^(-d/(e*m))/(e^2*f^(1/m)*m^2)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {a+b \log \left (c x^n\right )}{d+e \log \left (f x^m\right )} \, dx=\int \frac {a+b\,\ln \left (c\,x^n\right )}{d+e\,\ln \left (f\,x^m\right )} \,d x \] Input:

int((a + b*log(c*x^n))/(d + e*log(f*x^m)),x)
 

Output:

int((a + b*log(c*x^n))/(d + e*log(f*x^m)), x)
 

Reduce [F]

\[ \int \frac {a+b \log \left (c x^n\right )}{d+e \log \left (f x^m\right )} \, dx=\left (\int \frac {\mathrm {log}\left (x^{n} c \right )}{\mathrm {log}\left (x^{m} f \right ) e +d}d x \right ) b +\left (\int \frac {1}{\mathrm {log}\left (x^{m} f \right ) e +d}d x \right ) a \] Input:

int((a+b*log(c*x^n))/(d+e*log(f*x^m)),x)
 

Output:

int(log(x**n*c)/(log(x**m*f)*e + d),x)*b + int(1/(log(x**m*f)*e + d),x)*a