\(\int \frac {(A+B \log (\frac {e (a+b x)^2}{(c+d x)^2}))^2}{a g+b g x} \, dx\) [132]

Optimal result
Mathematica [B] (verified)
Rubi [A] (verified)
Maple [F]
Fricas [F]
Sympy [F]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 34, antiderivative size = 132 \[ \int \frac {\left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{a g+b g x} \, dx=-\frac {\left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2 \log \left (1-\frac {b (c+d x)}{d (a+b x)}\right )}{b g}+\frac {4 B \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right ) \operatorname {PolyLog}\left (2,\frac {b (c+d x)}{d (a+b x)}\right )}{b g}+\frac {8 B^2 \operatorname {PolyLog}\left (3,\frac {b (c+d x)}{d (a+b x)}\right )}{b g} \] Output:

-(A+B*ln(e*(b*x+a)^2/(d*x+c)^2))^2*ln(1-b*(d*x+c)/d/(b*x+a))/b/g+4*B*(A+B* 
ln(e*(b*x+a)^2/(d*x+c)^2))*polylog(2,b*(d*x+c)/d/(b*x+a))/b/g+8*B^2*polylo 
g(3,b*(d*x+c)/d/(b*x+a))/b/g
                                                                                    
                                                                                    
 

Mathematica [B] (verified)

Leaf count is larger than twice the leaf count of optimal. \(622\) vs. \(2(132)=264\).

Time = 1.59 (sec) , antiderivative size = 622, normalized size of antiderivative = 4.71 \[ \int \frac {\left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{a g+b g x} \, dx=\frac {A^2 \log (a+b x)}{b g}+\frac {2 A B \left (\frac {\log ^2\left (\frac {a}{b}+x\right )}{b}+\frac {\log (a+b x) \left (-2 \log \left (\frac {a}{b}+x\right )+2 \log \left (\frac {c}{d}+x\right )+\log \left (\frac {a^2 e}{(c+d x)^2}+\frac {2 a b e x}{(c+d x)^2}+\frac {b^2 e x^2}{(c+d x)^2}\right )\right )}{b}-\frac {2 \left (\log \left (\frac {c}{d}+x\right ) \log \left (1-\frac {b \left (\frac {c}{d}+x\right )}{-a+\frac {b c}{d}}\right )+\operatorname {PolyLog}\left (2,\frac {b \left (\frac {c}{d}+x\right )}{-a+\frac {b c}{d}}\right )\right )}{b}\right )}{g}+\frac {B^2 \left (\frac {4 \log ^3\left (\frac {a}{b}+x\right )}{3 b}+\frac {\log (a+b x) \left (-2 \log \left (\frac {a}{b}+x\right )+2 \log \left (\frac {c}{d}+x\right )+\log \left (\frac {a^2 e}{(c+d x)^2}+\frac {2 a b e x}{(c+d x)^2}+\frac {b^2 e x^2}{(c+d x)^2}\right )\right )^2}{b}+2 \left (-2 \log \left (\frac {a}{b}+x\right )+2 \log \left (\frac {c}{d}+x\right )+\log \left (\frac {a^2 e}{(c+d x)^2}+\frac {2 a b e x}{(c+d x)^2}+\frac {b^2 e x^2}{(c+d x)^2}\right )\right ) \left (\frac {\log ^2\left (\frac {a}{b}+x\right )}{b}-\frac {2 \left (\log \left (\frac {c}{d}+x\right ) \log \left (1-\frac {b \left (\frac {c}{d}+x\right )}{-a+\frac {b c}{d}}\right )+\operatorname {PolyLog}\left (2,\frac {b \left (\frac {c}{d}+x\right )}{-a+\frac {b c}{d}}\right )\right )}{b}\right )+\frac {8 \left (\frac {1}{2} \log ^2\left (\frac {c}{d}+x\right ) \log \left (1-\frac {b \left (\frac {c}{d}+x\right )}{-a+\frac {b c}{d}}\right )+\log \left (\frac {c}{d}+x\right ) \operatorname {PolyLog}\left (2,\frac {b \left (\frac {c}{d}+x\right )}{-a+\frac {b c}{d}}\right )-\operatorname {PolyLog}\left (3,\frac {b \left (\frac {c}{d}+x\right )}{-a+\frac {b c}{d}}\right )\right )}{b}-\frac {8 \left (\frac {1}{2} \log ^2\left (\frac {a}{b}+x\right ) \left (\log \left (\frac {c}{d}+x\right )-\log \left (\frac {b d \left (\frac {c}{d}+x\right )}{b c-a d}\right )\right )-\log \left (\frac {a}{b}+x\right ) \operatorname {PolyLog}\left (2,-\frac {d (a+b x)}{b c-a d}\right )+\operatorname {PolyLog}\left (3,-\frac {d (a+b x)}{b c-a d}\right )\right )}{b}\right )}{g} \] Input:

Integrate[(A + B*Log[(e*(a + b*x)^2)/(c + d*x)^2])^2/(a*g + b*g*x),x]
 

Output:

(A^2*Log[a + b*x])/(b*g) + (2*A*B*(Log[a/b + x]^2/b + (Log[a + b*x]*(-2*Lo 
g[a/b + x] + 2*Log[c/d + x] + Log[(a^2*e)/(c + d*x)^2 + (2*a*b*e*x)/(c + d 
*x)^2 + (b^2*e*x^2)/(c + d*x)^2]))/b - (2*(Log[c/d + x]*Log[1 - (b*(c/d + 
x))/(-a + (b*c)/d)] + PolyLog[2, (b*(c/d + x))/(-a + (b*c)/d)]))/b))/g + ( 
B^2*((4*Log[a/b + x]^3)/(3*b) + (Log[a + b*x]*(-2*Log[a/b + x] + 2*Log[c/d 
 + x] + Log[(a^2*e)/(c + d*x)^2 + (2*a*b*e*x)/(c + d*x)^2 + (b^2*e*x^2)/(c 
 + d*x)^2])^2)/b + 2*(-2*Log[a/b + x] + 2*Log[c/d + x] + Log[(a^2*e)/(c + 
d*x)^2 + (2*a*b*e*x)/(c + d*x)^2 + (b^2*e*x^2)/(c + d*x)^2])*(Log[a/b + x] 
^2/b - (2*(Log[c/d + x]*Log[1 - (b*(c/d + x))/(-a + (b*c)/d)] + PolyLog[2, 
 (b*(c/d + x))/(-a + (b*c)/d)]))/b) + (8*((Log[c/d + x]^2*Log[1 - (b*(c/d 
+ x))/(-a + (b*c)/d)])/2 + Log[c/d + x]*PolyLog[2, (b*(c/d + x))/(-a + (b* 
c)/d)] - PolyLog[3, (b*(c/d + x))/(-a + (b*c)/d)]))/b - (8*((Log[a/b + x]^ 
2*(Log[c/d + x] - Log[(b*d*(c/d + x))/(b*c - a*d)]))/2 - Log[a/b + x]*Poly 
Log[2, -((d*(a + b*x))/(b*c - a*d))] + PolyLog[3, -((d*(a + b*x))/(b*c - a 
*d))]))/b))/g
 

Rubi [A] (verified)

Time = 0.50 (sec) , antiderivative size = 124, normalized size of antiderivative = 0.94, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {2950, 2779, 2821, 7143}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\left (B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+A\right )^2}{a g+b g x} \, dx\)

\(\Big \downarrow \) 2950

\(\displaystyle \frac {\int \frac {(c+d x) \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{(a+b x) \left (b-\frac {d (a+b x)}{c+d x}\right )}d\frac {a+b x}{c+d x}}{g}\)

\(\Big \downarrow \) 2779

\(\displaystyle \frac {\frac {4 B \int \frac {(c+d x) \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right ) \log \left (1-\frac {b (c+d x)}{d (a+b x)}\right )}{a+b x}d\frac {a+b x}{c+d x}}{b}-\frac {\log \left (1-\frac {b (c+d x)}{d (a+b x)}\right ) \left (B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+A\right )^2}{b}}{g}\)

\(\Big \downarrow \) 2821

\(\displaystyle \frac {\frac {4 B \left (\operatorname {PolyLog}\left (2,\frac {b (c+d x)}{d (a+b x)}\right ) \left (B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+A\right )-2 B \int \frac {(c+d x) \operatorname {PolyLog}\left (2,\frac {b (c+d x)}{d (a+b x)}\right )}{a+b x}d\frac {a+b x}{c+d x}\right )}{b}-\frac {\log \left (1-\frac {b (c+d x)}{d (a+b x)}\right ) \left (B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+A\right )^2}{b}}{g}\)

\(\Big \downarrow \) 7143

\(\displaystyle \frac {\frac {4 B \left (\operatorname {PolyLog}\left (2,\frac {b (c+d x)}{d (a+b x)}\right ) \left (B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+A\right )+2 B \operatorname {PolyLog}\left (3,\frac {b (c+d x)}{d (a+b x)}\right )\right )}{b}-\frac {\log \left (1-\frac {b (c+d x)}{d (a+b x)}\right ) \left (B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+A\right )^2}{b}}{g}\)

Input:

Int[(A + B*Log[(e*(a + b*x)^2)/(c + d*x)^2])^2/(a*g + b*g*x),x]
 

Output:

(-(((A + B*Log[(e*(a + b*x)^2)/(c + d*x)^2])^2*Log[1 - (b*(c + d*x))/(d*(a 
 + b*x))])/b) + (4*B*((A + B*Log[(e*(a + b*x)^2)/(c + d*x)^2])*PolyLog[2, 
(b*(c + d*x))/(d*(a + b*x))] + 2*B*PolyLog[3, (b*(c + d*x))/(d*(a + b*x))] 
))/b)/g
 

Defintions of rubi rules used

rule 2779
Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_)^(r 
_.))), x_Symbol] :> Simp[(-Log[1 + d/(e*x^r)])*((a + b*Log[c*x^n])^p/(d*r)) 
, x] + Simp[b*n*(p/(d*r))   Int[Log[1 + d/(e*x^r)]*((a + b*Log[c*x^n])^(p - 
 1)/x), x], x] /; FreeQ[{a, b, c, d, e, n, r}, x] && IGtQ[p, 0]
 

rule 2821
Int[(Log[(d_.)*((e_) + (f_.)*(x_)^(m_.))]*((a_.) + Log[(c_.)*(x_)^(n_.)]*(b 
_.))^(p_.))/(x_), x_Symbol] :> Simp[(-PolyLog[2, (-d)*f*x^m])*((a + b*Log[c 
*x^n])^p/m), x] + Simp[b*n*(p/m)   Int[PolyLog[2, (-d)*f*x^m]*((a + b*Log[c 
*x^n])^(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[p, 
0] && EqQ[d*e, 1]
 

rule 2950
Int[((A_.) + Log[(e_.)*((a_.) + (b_.)*(x_))^(n_.)*((c_.) + (d_.)*(x_))^(mn_ 
)]*(B_.))^(p_.)*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> Simp[(b*c - a*d)^( 
m + 1)*(g/b)^m   Subst[Int[x^m*((A + B*Log[e*x^n])^p/(b - d*x)^(m + 2)), x] 
, x, (a + b*x)/(c + d*x)], x] /; FreeQ[{a, b, c, d, e, f, g, A, B, n}, x] & 
& EqQ[n + mn, 0] && IGtQ[n, 0] && NeQ[b*c - a*d, 0] && IntegersQ[m, p] && E 
qQ[b*f - a*g, 0] && (GtQ[p, 0] || LtQ[m, -1])
 

rule 7143
Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_S 
ymbol] :> Simp[PolyLog[n + 1, c*(a + b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d 
, e, n, p}, x] && EqQ[b*d, a*e]
 
Maple [F]

\[\int \frac {{\left (A +B \ln \left (\frac {e \left (b x +a \right )^{2}}{\left (d x +c \right )^{2}}\right )\right )}^{2}}{b g x +a g}d x\]

Input:

int((A+B*ln(e*(b*x+a)^2/(d*x+c)^2))^2/(b*g*x+a*g),x)
 

Output:

int((A+B*ln(e*(b*x+a)^2/(d*x+c)^2))^2/(b*g*x+a*g),x)
 

Fricas [F]

\[ \int \frac {\left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{a g+b g x} \, dx=\int { \frac {{\left (B \log \left (\frac {{\left (b x + a\right )}^{2} e}{{\left (d x + c\right )}^{2}}\right ) + A\right )}^{2}}{b g x + a g} \,d x } \] Input:

integrate((A+B*log(e*(b*x+a)^2/(d*x+c)^2))^2/(b*g*x+a*g),x, algorithm="fri 
cas")
 

Output:

integral((B^2*log((b^2*e*x^2 + 2*a*b*e*x + a^2*e)/(d^2*x^2 + 2*c*d*x + c^2 
))^2 + 2*A*B*log((b^2*e*x^2 + 2*a*b*e*x + a^2*e)/(d^2*x^2 + 2*c*d*x + c^2) 
) + A^2)/(b*g*x + a*g), x)
 

Sympy [F]

\[ \int \frac {\left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{a g+b g x} \, dx=\frac {\int \frac {A^{2}}{a + b x}\, dx + \int \frac {B^{2} \log {\left (\frac {a^{2} e}{c^{2} + 2 c d x + d^{2} x^{2}} + \frac {2 a b e x}{c^{2} + 2 c d x + d^{2} x^{2}} + \frac {b^{2} e x^{2}}{c^{2} + 2 c d x + d^{2} x^{2}} \right )}^{2}}{a + b x}\, dx + \int \frac {2 A B \log {\left (\frac {a^{2} e}{c^{2} + 2 c d x + d^{2} x^{2}} + \frac {2 a b e x}{c^{2} + 2 c d x + d^{2} x^{2}} + \frac {b^{2} e x^{2}}{c^{2} + 2 c d x + d^{2} x^{2}} \right )}}{a + b x}\, dx}{g} \] Input:

integrate((A+B*ln(e*(b*x+a)**2/(d*x+c)**2))**2/(b*g*x+a*g),x)
 

Output:

(Integral(A**2/(a + b*x), x) + Integral(B**2*log(a**2*e/(c**2 + 2*c*d*x + 
d**2*x**2) + 2*a*b*e*x/(c**2 + 2*c*d*x + d**2*x**2) + b**2*e*x**2/(c**2 + 
2*c*d*x + d**2*x**2))**2/(a + b*x), x) + Integral(2*A*B*log(a**2*e/(c**2 + 
 2*c*d*x + d**2*x**2) + 2*a*b*e*x/(c**2 + 2*c*d*x + d**2*x**2) + b**2*e*x* 
*2/(c**2 + 2*c*d*x + d**2*x**2))/(a + b*x), x))/g
 

Maxima [F]

\[ \int \frac {\left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{a g+b g x} \, dx=\int { \frac {{\left (B \log \left (\frac {{\left (b x + a\right )}^{2} e}{{\left (d x + c\right )}^{2}}\right ) + A\right )}^{2}}{b g x + a g} \,d x } \] Input:

integrate((A+B*log(e*(b*x+a)^2/(d*x+c)^2))^2/(b*g*x+a*g),x, algorithm="max 
ima")
 

Output:

4*B^2*log(b*x + a)*log(d*x + c)^2/(b*g) + A^2*log(b*g*x + a*g)/(b*g) - int 
egrate(-(B^2*b*c*log(e)^2 + 2*A*B*b*c*log(e) + 4*(B^2*b*d*x + B^2*b*c)*log 
(b*x + a)^2 + (B^2*b*d*log(e)^2 + 2*A*B*b*d*log(e))*x + 4*(B^2*b*c*log(e) 
+ A*B*b*c + (B^2*b*d*log(e) + A*B*b*d)*x)*log(b*x + a) - 4*(B^2*b*c*log(e) 
 + A*B*b*c + (B^2*b*d*log(e) + A*B*b*d)*x + 2*(2*B^2*b*d*x + (b*c + a*d)*B 
^2)*log(b*x + a))*log(d*x + c))/(b^2*d*g*x^2 + a*b*c*g + (b^2*c*g + a*b*d* 
g)*x), x)
 

Giac [F]

\[ \int \frac {\left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{a g+b g x} \, dx=\int { \frac {{\left (B \log \left (\frac {{\left (b x + a\right )}^{2} e}{{\left (d x + c\right )}^{2}}\right ) + A\right )}^{2}}{b g x + a g} \,d x } \] Input:

integrate((A+B*log(e*(b*x+a)^2/(d*x+c)^2))^2/(b*g*x+a*g),x, algorithm="gia 
c")
 

Output:

integrate((B*log((b*x + a)^2*e/(d*x + c)^2) + A)^2/(b*g*x + a*g), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {\left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{a g+b g x} \, dx=\int \frac {{\left (A+B\,\ln \left (\frac {e\,{\left (a+b\,x\right )}^2}{{\left (c+d\,x\right )}^2}\right )\right )}^2}{a\,g+b\,g\,x} \,d x \] Input:

int((A + B*log((e*(a + b*x)^2)/(c + d*x)^2))^2/(a*g + b*g*x),x)
 

Output:

int((A + B*log((e*(a + b*x)^2)/(c + d*x)^2))^2/(a*g + b*g*x), x)
 

Reduce [F]

\[ \int \frac {\left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{a g+b g x} \, dx=\frac {\left (\int \frac {\mathrm {log}\left (\frac {b^{2} e \,x^{2}+2 a b e x +a^{2} e}{d^{2} x^{2}+2 c d x +c^{2}}\right )^{2}}{b x +a}d x \right ) b^{3}+2 \left (\int \frac {\mathrm {log}\left (\frac {b^{2} e \,x^{2}+2 a b e x +a^{2} e}{d^{2} x^{2}+2 c d x +c^{2}}\right )}{b x +a}d x \right ) a \,b^{2}+\mathrm {log}\left (b x +a \right ) a^{2}}{b g} \] Input:

int((A+B*log(e*(b*x+a)^2/(d*x+c)^2))^2/(b*g*x+a*g),x)
 

Output:

(int(log((a**2*e + 2*a*b*e*x + b**2*e*x**2)/(c**2 + 2*c*d*x + d**2*x**2))* 
*2/(a + b*x),x)*b**3 + 2*int(log((a**2*e + 2*a*b*e*x + b**2*e*x**2)/(c**2 
+ 2*c*d*x + d**2*x**2))/(a + b*x),x)*a*b**2 + log(a + b*x)*a**2)/(b*g)