Integrand size = 31, antiderivative size = 294 \[ \int (g+h x) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2 \, dx=\frac {B^2 (b c-a d)^2 h n^2 \log (c+d x)}{b^2 d^2}-\frac {B (b c-a d) h n (a+b x) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )}{b^2 d}+\frac {B (b c-a d) (2 b d g-b c h-a d h) n \log \left (\frac {b c-a d}{b (c+d x)}\right ) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )}{b^2 d^2}-\frac {(b g-a h)^2 \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2}{2 b^2 h}+\frac {(g+h x)^2 \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2}{2 h}+\frac {B^2 (b c-a d) (2 b d g-b c h-a d h) n^2 \operatorname {PolyLog}\left (2,\frac {d (a+b x)}{b (c+d x)}\right )}{b^2 d^2} \] Output:
B^2*(-a*d+b*c)^2*h*n^2*ln(d*x+c)/b^2/d^2-B*(-a*d+b*c)*h*n*(b*x+a)*(A+B*ln( e*(b*x+a)^n/((d*x+c)^n)))/b^2/d+B*(-a*d+b*c)*(-a*d*h-b*c*h+2*b*d*g)*n*ln(( -a*d+b*c)/b/(d*x+c))*(A+B*ln(e*(b*x+a)^n/((d*x+c)^n)))/b^2/d^2-1/2*(-a*h+b *g)^2*(A+B*ln(e*(b*x+a)^n/((d*x+c)^n)))^2/b^2/h+1/2*(h*x+g)^2*(A+B*ln(e*(b *x+a)^n/((d*x+c)^n)))^2/h+B^2*(-a*d+b*c)*(-a*d*h-b*c*h+2*b*d*g)*n^2*polylo g(2,d*(b*x+a)/b/(d*x+c))/b^2/d^2
Time = 1.01 (sec) , antiderivative size = 472, normalized size of antiderivative = 1.61 \[ \int (g+h x) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2 \, dx=\frac {a B^2 d^2 (-2 b g+a h) n^2 \log ^2(a+b x)-2 B n \log (a+b x) \left (b^2 B c (-2 d g+c h) n \log (c+d x)-B (b c-a d) (-2 b d g+b c h+a d h) n \log \left (\frac {b (c+d x)}{b c-a d}\right )+a d \left (A (-2 b d g+a d h)+B (-2 b d g+b c h-a d h) n+B d (-2 b g+a h) \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )\right )+b \left (b B^2 c (-2 d g+c h) n^2 \log ^2(c+d x)+2 B n \log (c+d x) \left (A b c (-2 d g+c h)+B \left (b c^2 h-a d (2 d g+c h)\right ) n+b B c (-2 d g+c h) \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )+d \left (A b x (2 A d g-2 B c h n+A d h x)+2 a B n (-2 A d g-2 B d g n+B c h n+A d h x)+2 B (a B d n (-2 g+h x)+b x (2 A d g-B c h n+A d h x)) \log \left (e (a+b x)^n (c+d x)^{-n}\right )+b B^2 d x (2 g+h x) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )\right )\right )+2 B^2 (b c-a d) (-2 b d g+b c h+a d h) n^2 \operatorname {PolyLog}\left (2,\frac {d (a+b x)}{-b c+a d}\right )}{2 b^2 d^2} \] Input:
Integrate[(g + h*x)*(A + B*Log[(e*(a + b*x)^n)/(c + d*x)^n])^2,x]
Output:
(a*B^2*d^2*(-2*b*g + a*h)*n^2*Log[a + b*x]^2 - 2*B*n*Log[a + b*x]*(b^2*B*c *(-2*d*g + c*h)*n*Log[c + d*x] - B*(b*c - a*d)*(-2*b*d*g + b*c*h + a*d*h)* n*Log[(b*(c + d*x))/(b*c - a*d)] + a*d*(A*(-2*b*d*g + a*d*h) + B*(-2*b*d*g + b*c*h - a*d*h)*n + B*d*(-2*b*g + a*h)*Log[(e*(a + b*x)^n)/(c + d*x)^n]) ) + b*(b*B^2*c*(-2*d*g + c*h)*n^2*Log[c + d*x]^2 + 2*B*n*Log[c + d*x]*(A*b *c*(-2*d*g + c*h) + B*(b*c^2*h - a*d*(2*d*g + c*h))*n + b*B*c*(-2*d*g + c* h)*Log[(e*(a + b*x)^n)/(c + d*x)^n]) + d*(A*b*x*(2*A*d*g - 2*B*c*h*n + A*d *h*x) + 2*a*B*n*(-2*A*d*g - 2*B*d*g*n + B*c*h*n + A*d*h*x) + 2*B*(a*B*d*n* (-2*g + h*x) + b*x*(2*A*d*g - B*c*h*n + A*d*h*x))*Log[(e*(a + b*x)^n)/(c + d*x)^n] + b*B^2*d*x*(2*g + h*x)*Log[(e*(a + b*x)^n)/(c + d*x)^n]^2)) + 2* B^2*(b*c - a*d)*(-2*b*d*g + b*c*h + a*d*h)*n^2*PolyLog[2, (d*(a + b*x))/(- (b*c) + a*d)])/(2*b^2*d^2)
Time = 0.97 (sec) , antiderivative size = 410, normalized size of antiderivative = 1.39, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.161, Rules used = {2973, 2953, 2798, 2804, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (g+h x) \left (B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A\right )^2 \, dx\) |
\(\Big \downarrow \) 2973 |
\(\displaystyle \int (g+h x) \left (B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A\right )^2dx\) |
\(\Big \downarrow \) 2953 |
\(\displaystyle (b c-a d) \int \frac {\left (b g-a h-\frac {(d g-c h) (a+b x)}{c+d x}\right ) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )^2}{\left (b-\frac {d (a+b x)}{c+d x}\right )^3}d\frac {a+b x}{c+d x}\) |
\(\Big \downarrow \) 2798 |
\(\displaystyle (b c-a d) \left (\frac {\left (-\frac {(a+b x) (d g-c h)}{c+d x}-a h+b g\right )^2 \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )^2}{2 h (b c-a d) \left (b-\frac {d (a+b x)}{c+d x}\right )^2}-\frac {B n \int \frac {(c+d x) \left (b g-a h-\frac {(d g-c h) (a+b x)}{c+d x}\right )^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{(a+b x) \left (b-\frac {d (a+b x)}{c+d x}\right )^2}d\frac {a+b x}{c+d x}}{h (b c-a d)}\right )\) |
\(\Big \downarrow \) 2804 |
\(\displaystyle (b c-a d) \left (\frac {\left (-\frac {(a+b x) (d g-c h)}{c+d x}-a h+b g\right )^2 \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )^2}{2 h (b c-a d) \left (b-\frac {d (a+b x)}{c+d x}\right )^2}-\frac {B n \int \left (\frac {(b c-a d)^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) h^2}{b d \left (b-\frac {d (a+b x)}{c+d x}\right )^2}+\frac {(b c-a d) (2 b d g-b c h-a d h) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) h}{b^2 d \left (b-\frac {d (a+b x)}{c+d x}\right )}+\frac {(b g-a h)^2 (c+d x) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{b^2 (a+b x)}\right )d\frac {a+b x}{c+d x}}{h (b c-a d)}\right )\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle (b c-a d) \left (\frac {\left (-\frac {(a+b x) (d g-c h)}{c+d x}-a h+b g\right )^2 \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )^2}{2 h (b c-a d) \left (b-\frac {d (a+b x)}{c+d x}\right )^2}-\frac {B n \left (-\frac {h (b c-a d) (-a d h-b c h+2 b d g) \log \left (1-\frac {d (a+b x)}{b (c+d x)}\right ) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )}{b^2 d^2}+\frac {(b g-a h)^2 \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )^2}{2 b^2 B n}+\frac {h^2 (a+b x) (b c-a d)^2 \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )}{b^2 d (c+d x) \left (b-\frac {d (a+b x)}{c+d x}\right )}-\frac {B h n (b c-a d) (-a d h-b c h+2 b d g) \operatorname {PolyLog}\left (2,\frac {d (a+b x)}{b (c+d x)}\right )}{b^2 d^2}+\frac {B h^2 n (b c-a d)^2 \log \left (b-\frac {d (a+b x)}{c+d x}\right )}{b^2 d^2}\right )}{h (b c-a d)}\right )\) |
Input:
Int[(g + h*x)*(A + B*Log[(e*(a + b*x)^n)/(c + d*x)^n])^2,x]
Output:
(b*c - a*d)*(((b*g - a*h - ((d*g - c*h)*(a + b*x))/(c + d*x))^2*(A + B*Log [e*((a + b*x)/(c + d*x))^n])^2)/(2*(b*c - a*d)*h*(b - (d*(a + b*x))/(c + d *x))^2) - (B*n*(((b*c - a*d)^2*h^2*(a + b*x)*(A + B*Log[e*((a + b*x)/(c + d*x))^n]))/(b^2*d*(c + d*x)*(b - (d*(a + b*x))/(c + d*x))) + ((b*g - a*h)^ 2*(A + B*Log[e*((a + b*x)/(c + d*x))^n])^2)/(2*b^2*B*n) + (B*(b*c - a*d)^2 *h^2*n*Log[b - (d*(a + b*x))/(c + d*x)])/(b^2*d^2) - ((b*c - a*d)*h*(2*b*d *g - b*c*h - a*d*h)*(A + B*Log[e*((a + b*x)/(c + d*x))^n])*Log[1 - (d*(a + b*x))/(b*(c + d*x))])/(b^2*d^2) - (B*(b*c - a*d)*h*(2*b*d*g - b*c*h - a*d *h)*n*PolyLog[2, (d*(a + b*x))/(b*(c + d*x))])/(b^2*d^2)))/((b*c - a*d)*h) )
Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_)*(( f_) + (g_.)*(x_))^(m_.), x_Symbol] :> Simp[(f + g*x)^(m + 1)*(d + e*x)^(q + 1)*((a + b*Log[c*x^n])^p/((q + 1)*(e*f - d*g))), x] - Simp[b*n*(p/((q + 1) *(e*f - d*g))) Int[(f + g*x)^(m + 1)*(d + e*x)^(q + 1)*((a + b*Log[c*x^n] )^(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, f, g, m, n, q}, x] && NeQ[e*f - d*g, 0] && EqQ[m + q + 2, 0] && IGtQ[p, 0] && LtQ[q, -1]
Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*(RFx_), x_Symbol] :> With[{ u = ExpandIntegrand[(a + b*Log[c*x^n])^p, RFx, x]}, Int[u, x] /; SumQ[u]] / ; FreeQ[{a, b, c, n}, x] && RationalFunctionQ[RFx, x] && IGtQ[p, 0]
Int[((A_.) + Log[(e_.)*(((a_.) + (b_.)*(x_))/((c_.) + (d_.)*(x_)))^(n_.)]*( B_.))^(p_.)*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> Simp[(b*c - a*d) Sub st[Int[(b*f - a*g - (d*f - c*g)*x)^m*((A + B*Log[e*x^n])^p/(b - d*x)^(m + 2 )), x], x, (a + b*x)/(c + d*x)], x] /; FreeQ[{a, b, c, d, e, f, g, A, B, n} , x] && NeQ[b*c - a*d, 0] && IntegerQ[m] && IGtQ[p, 0]
Int[((A_.) + Log[(e_.)*(u_)^(n_.)*(v_)^(mn_)]*(B_.))^(p_.)*(w_.), x_Symbol] :> Subst[Int[w*(A + B*Log[e*(u/v)^n])^p, x], e*(u/v)^n, e*(u^n/v^n)] /; Fr eeQ[{e, A, B, n, p}, x] && EqQ[n + mn, 0] && LinearQ[{u, v}, x] && !Intege rQ[n]
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 27.59 (sec) , antiderivative size = 4692, normalized size of antiderivative = 15.96
Input:
int((h*x+g)*(A+B*ln(e*(b*x+a)^n/((d*x+c)^n)))^2,x,method=_RETURNVERBOSE)
Output:
1/2*B^2*x*(h*x+2*g)*ln((b*x+a)^n)^2+B^2/d*n*ln((d*x+c)^n)*x*c*h-B^2/d^2*n* ln((d*x+c)^n)*c^2*ln(d*x+c)*h+2*B^2/d*n*ln((d*x+c)^n)*c*ln(d*x+c)*g+(-B^2* x*(h*x+2*g)*ln((d*x+c)^n)+1/2*B*(4*B*ln(e)*b^2*d^2*g*x+2*B*ln(e)*b^2*d^2*h *x^2+2*B*a*b*d^2*h*n*x-2*B*b^2*c*d*h*n*x-2*B*ln(b*x+a)*a^2*d^2*h*n+2*A*b^2 *d^2*h*x^2+4*A*b^2*d^2*g*x+4*B*ln(b*x+a)*a*b*d^2*g*n-4*B*ln(d*x+c)*b^2*c*d *g*n+2*B*ln(d*x+c)*b^2*c^2*h*n+I*B*Pi*b^2*d^2*h*x^2*csgn(I*(b*x+a)^n)*csgn (I/((d*x+c)^n)*(b*x+a)^n)^2+I*B*Pi*b^2*d^2*h*x^2*csgn(I/((d*x+c)^n)*(b*x+a )^n)*csgn(I*e*(b*x+a)^n/((d*x+c)^n))^2+I*B*Pi*b^2*d^2*h*x^2*csgn(I*e*(b*x+ a)^n/((d*x+c)^n))^2*csgn(I*e)+2*I*B*Pi*b^2*d^2*g*x*csgn(I/((d*x+c)^n))*csg n(I/((d*x+c)^n)*(b*x+a)^n)^2+2*I*B*Pi*b^2*d^2*g*x*csgn(I*(b*x+a)^n)*csgn(I /((d*x+c)^n)*(b*x+a)^n)^2+2*I*B*Pi*b^2*d^2*g*x*csgn(I/((d*x+c)^n)*(b*x+a)^ n)*csgn(I*e*(b*x+a)^n/((d*x+c)^n))^2+2*I*B*Pi*b^2*d^2*g*x*csgn(I*e*(b*x+a) ^n/((d*x+c)^n))^2*csgn(I*e)+I*B*Pi*b^2*d^2*h*x^2*csgn(I/((d*x+c)^n))*csgn( I/((d*x+c)^n)*(b*x+a)^n)^2-I*B*Pi*b^2*d^2*h*x^2*csgn(I/((d*x+c)^n)*(b*x+a) ^n)*csgn(I*e*(b*x+a)^n/((d*x+c)^n))*csgn(I*e)-2*I*B*Pi*b^2*d^2*g*x*csgn(I/ ((d*x+c)^n))*csgn(I*(b*x+a)^n)*csgn(I/((d*x+c)^n)*(b*x+a)^n)-2*I*B*Pi*b^2* d^2*g*x*csgn(I/((d*x+c)^n)*(b*x+a)^n)*csgn(I*e*(b*x+a)^n/((d*x+c)^n))*csgn (I*e)-I*B*Pi*b^2*d^2*h*x^2*csgn(I/((d*x+c)^n))*csgn(I*(b*x+a)^n)*csgn(I/(( d*x+c)^n)*(b*x+a)^n)-I*B*Pi*b^2*d^2*h*x^2*csgn(I/((d*x+c)^n)*(b*x+a)^n)^3- I*B*Pi*b^2*d^2*h*x^2*csgn(I*e*(b*x+a)^n/((d*x+c)^n))^3-2*I*B*Pi*b^2*d^2...
\[ \int (g+h x) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2 \, dx=\int { {\left (h x + g\right )} {\left (B \log \left (\frac {{\left (b x + a\right )}^{n} e}{{\left (d x + c\right )}^{n}}\right ) + A\right )}^{2} \,d x } \] Input:
integrate((h*x+g)*(A+B*log(e*(b*x+a)^n/((d*x+c)^n)))^2,x, algorithm="frica s")
Output:
integral(A^2*h*x + A^2*g + (B^2*h*x + B^2*g)*log((b*x + a)^n*e/(d*x + c)^n )^2 + 2*(A*B*h*x + A*B*g)*log((b*x + a)^n*e/(d*x + c)^n), x)
Exception generated. \[ \int (g+h x) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2 \, dx=\text {Exception raised: HeuristicGCDFailed} \] Input:
integrate((h*x+g)*(A+B*ln(e*(b*x+a)**n/((d*x+c)**n)))**2,x)
Output:
Exception raised: HeuristicGCDFailed >> no luck
Leaf count of result is larger than twice the leaf count of optimal. 903 vs. \(2 (289) = 578\).
Time = 0.58 (sec) , antiderivative size = 903, normalized size of antiderivative = 3.07 \[ \int (g+h x) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2 \, dx =\text {Too large to display} \] Input:
integrate((h*x+g)*(A+B*log(e*(b*x+a)^n/((d*x+c)^n)))^2,x, algorithm="maxim a")
Output:
A*B*h*x^2*log((b*x + a)^n*e/(d*x + c)^n) + 1/2*A^2*h*x^2 + 2*A*B*g*x*log(( b*x + a)^n*e/(d*x + c)^n) + A^2*g*x + 2*(a*e*n*log(b*x + a)/b - c*e*n*log( d*x + c)/d)*A*B*g/e - (a^2*e*n*log(b*x + a)/b^2 - c^2*e*n*log(d*x + c)/d^2 + (b*c*e*n - a*d*e*n)*x/(b*d))*A*B*h/e - (a*c*d*h*n^2 + (2*c*d*g*n*log(e) - (h*n^2 + h*n*log(e))*c^2)*b)*B^2*log(d*x + c)/(b*d^2) + (2*a*b*d^2*g*n^ 2 - a^2*d^2*h*n^2 - (2*c*d*g*n^2 - c^2*h*n^2)*b^2)*(log(b*x + a)*log((b*d* x + a*d)/(b*c - a*d) + 1) + dilog(-(b*d*x + a*d)/(b*c - a*d)))*B^2/(b^2*d^ 2) + 1/2*(B^2*b^2*d^2*h*x^2*log(e)^2 + 2*(2*c*d*g*n^2 - c^2*h*n^2)*B^2*b^2 *log(b*x + a)*log(d*x + c) - (2*c*d*g*n^2 - c^2*h*n^2)*B^2*b^2*log(d*x + c )^2 - (2*a*b*d^2*g*n^2 - a^2*d^2*h*n^2)*B^2*log(b*x + a)^2 + 2*(a*b*d^2*h* n*log(e) - (c*d*h*n*log(e) - d^2*g*log(e)^2)*b^2)*B^2*x + 2*((h*n^2 - h*n* log(e))*a^2*d^2 - (c*d*h*n^2 - 2*d^2*g*n*log(e))*a*b)*B^2*log(b*x + a) + ( B^2*b^2*d^2*h*x^2 + 2*B^2*b^2*d^2*g*x)*log((b*x + a)^n)^2 + (B^2*b^2*d^2*h *x^2 + 2*B^2*b^2*d^2*g*x)*log((d*x + c)^n)^2 + 2*(B^2*b^2*d^2*h*x^2*log(e) - (2*c*d*g*n - c^2*h*n)*B^2*b^2*log(d*x + c) + (a*b*d^2*h*n - (c*d*h*n - 2*d^2*g*log(e))*b^2)*B^2*x + (2*a*b*d^2*g*n - a^2*d^2*h*n)*B^2*log(b*x + a ))*log((b*x + a)^n) - 2*(B^2*b^2*d^2*h*x^2*log(e) - (2*c*d*g*n - c^2*h*n)* B^2*b^2*log(d*x + c) + (a*b*d^2*h*n - (c*d*h*n - 2*d^2*g*log(e))*b^2)*B^2* x + (2*a*b*d^2*g*n - a^2*d^2*h*n)*B^2*log(b*x + a) + (B^2*b^2*d^2*h*x^2 + 2*B^2*b^2*d^2*g*x)*log((b*x + a)^n))*log((d*x + c)^n))/(b^2*d^2)
\[ \int (g+h x) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2 \, dx=\int { {\left (h x + g\right )} {\left (B \log \left (\frac {{\left (b x + a\right )}^{n} e}{{\left (d x + c\right )}^{n}}\right ) + A\right )}^{2} \,d x } \] Input:
integrate((h*x+g)*(A+B*log(e*(b*x+a)^n/((d*x+c)^n)))^2,x, algorithm="giac" )
Output:
integrate((h*x + g)*(B*log((b*x + a)^n*e/(d*x + c)^n) + A)^2, x)
Timed out. \[ \int (g+h x) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2 \, dx=\int \left (g+h\,x\right )\,{\left (A+B\,\ln \left (\frac {e\,{\left (a+b\,x\right )}^n}{{\left (c+d\,x\right )}^n}\right )\right )}^2 \,d x \] Input:
int((g + h*x)*(A + B*log((e*(a + b*x)^n)/(c + d*x)^n))^2,x)
Output:
int((g + h*x)*(A + B*log((e*(a + b*x)^n)/(c + d*x)^n))^2, x)
\[ \int (g+h x) \left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2 \, dx =\text {Too large to display} \] Input:
int((h*x+g)*(A+B*log(e*(b*x+a)^n/((d*x+c)^n)))^2,x)
Output:
( - 2*int((log(((a + b*x)**n*e)/(c + d*x)**n)*x)/(a*c + a*d*x + b*c*x + b* d*x**2),x)*a**2*b**2*d**3*h*n + 4*int((log(((a + b*x)**n*e)/(c + d*x)**n)* x)/(a*c + a*d*x + b*c*x + b*d*x**2),x)*a*b**3*d**3*g*n + 2*int((log(((a + b*x)**n*e)/(c + d*x)**n)*x)/(a*c + a*d*x + b*c*x + b*d*x**2),x)*b**4*c**2* d*h*n - 4*int((log(((a + b*x)**n*e)/(c + d*x)**n)*x)/(a*c + a*d*x + b*c*x + b*d*x**2),x)*b**4*c*d**2*g*n - 2*log(c + d*x)*a**3*d**2*h*n + 4*log(c + d*x)*a**2*b*d**2*g*n + 2*log(c + d*x)*a**2*b*d**2*h*n**2 + 2*log(c + d*x)* a*b**2*c**2*h*n - 4*log(c + d*x)*a*b**2*c*d*g*n - 4*log(c + d*x)*a*b**2*c* d*h*n**2 + 2*log(c + d*x)*b**3*c**2*h*n**2 + log(((a + b*x)**n*e)/(c + d*x )**n)**2*a*b**2*c*d*h + 2*log(((a + b*x)**n*e)/(c + d*x)**n)**2*b**3*d**2* g*x + log(((a + b*x)**n*e)/(c + d*x)**n)**2*b**3*d**2*h*x**2 - 2*log(((a + b*x)**n*e)/(c + d*x)**n)*a**3*d**2*h + 4*log(((a + b*x)**n*e)/(c + d*x)** n)*a**2*b*d**2*g + 2*log(((a + b*x)**n*e)/(c + d*x)**n)*a**2*b*d**2*h*n - 2*log(((a + b*x)**n*e)/(c + d*x)**n)*a*b**2*c*d*h*n + 4*log(((a + b*x)**n* e)/(c + d*x)**n)*a*b**2*d**2*g*x + 2*log(((a + b*x)**n*e)/(c + d*x)**n)*a* b**2*d**2*h*n*x + 2*log(((a + b*x)**n*e)/(c + d*x)**n)*a*b**2*d**2*h*x**2 - 2*log(((a + b*x)**n*e)/(c + d*x)**n)*b**3*c*d*h*n*x + 2*a**2*b*d**2*g*x + 2*a**2*b*d**2*h*n*x + a**2*b*d**2*h*x**2 - 2*a*b**2*c*d*h*n*x)/(2*b*d**2 )