Integrand size = 23, antiderivative size = 643 \[ \int \frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{d+e x} \, dx=\frac {3 d p x}{e^2}-\frac {3 p x^2}{4 e}+\frac {\sqrt {3} \sqrt [3]{a} d p \arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt [3]{b} e^2}-\frac {\sqrt {3} a^{2/3} p \arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{2 b^{2/3} e}-\frac {\sqrt [3]{a} d p \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{b} e^2}-\frac {a^{2/3} p \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{2 b^{2/3} e}-\frac {d^2 p \log \left (-\frac {e \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{b} d-\sqrt [3]{a} e}\right ) \log (d+e x)}{e^3}-\frac {d^2 p \log \left (-\frac {e \left ((-1)^{2/3} \sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{b} d-(-1)^{2/3} \sqrt [3]{a} e}\right ) \log (d+e x)}{e^3}-\frac {d^2 p \log \left (\frac {\sqrt [3]{-1} e \left (\sqrt [3]{a}+(-1)^{2/3} \sqrt [3]{b} x\right )}{\sqrt [3]{b} d+\sqrt [3]{-1} \sqrt [3]{a} e}\right ) \log (d+e x)}{e^3}+\frac {\sqrt [3]{a} d p \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{2 \sqrt [3]{b} e^2}+\frac {a^{2/3} p \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{4 b^{2/3} e}-\frac {d x \log \left (c \left (a+b x^3\right )^p\right )}{e^2}+\frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{2 e}+\frac {d^2 \log (d+e x) \log \left (c \left (a+b x^3\right )^p\right )}{e^3}-\frac {d^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt [3]{b} (d+e x)}{\sqrt [3]{b} d-\sqrt [3]{a} e}\right )}{e^3}-\frac {d^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt [3]{b} (d+e x)}{\sqrt [3]{b} d+\sqrt [3]{-1} \sqrt [3]{a} e}\right )}{e^3}-\frac {d^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt [3]{b} (d+e x)}{\sqrt [3]{b} d-(-1)^{2/3} \sqrt [3]{a} e}\right )}{e^3} \] Output:
3*d*p*x/e^2-3/4*p*x^2/e+3^(1/2)*a^(1/3)*d*p*arctan(1/3*(a^(1/3)-2*b^(1/3)* x)*3^(1/2)/a^(1/3))/b^(1/3)/e^2-1/2*3^(1/2)*a^(2/3)*p*arctan(1/3*(a^(1/3)- 2*b^(1/3)*x)*3^(1/2)/a^(1/3))/b^(2/3)/e-a^(1/3)*d*p*ln(a^(1/3)+b^(1/3)*x)/ b^(1/3)/e^2-1/2*a^(2/3)*p*ln(a^(1/3)+b^(1/3)*x)/b^(2/3)/e-d^2*p*ln(-e*(a^( 1/3)+b^(1/3)*x)/(b^(1/3)*d-a^(1/3)*e))*ln(e*x+d)/e^3-d^2*p*ln(-e*((-1)^(2/ 3)*a^(1/3)+b^(1/3)*x)/(b^(1/3)*d-(-1)^(2/3)*a^(1/3)*e))*ln(e*x+d)/e^3-d^2* p*ln((-1)^(1/3)*e*(a^(1/3)+(-1)^(2/3)*b^(1/3)*x)/(b^(1/3)*d+(-1)^(1/3)*a^( 1/3)*e))*ln(e*x+d)/e^3+1/2*a^(1/3)*d*p*ln(a^(2/3)-a^(1/3)*b^(1/3)*x+b^(2/3 )*x^2)/b^(1/3)/e^2+1/4*a^(2/3)*p*ln(a^(2/3)-a^(1/3)*b^(1/3)*x+b^(2/3)*x^2) /b^(2/3)/e-d*x*ln(c*(b*x^3+a)^p)/e^2+1/2*x^2*ln(c*(b*x^3+a)^p)/e+d^2*ln(e* x+d)*ln(c*(b*x^3+a)^p)/e^3-d^2*p*polylog(2,b^(1/3)*(e*x+d)/(b^(1/3)*d-a^(1 /3)*e))/e^3-d^2*p*polylog(2,b^(1/3)*(e*x+d)/(b^(1/3)*d+(-1)^(1/3)*a^(1/3)* e))/e^3-d^2*p*polylog(2,b^(1/3)*(e*x+d)/(b^(1/3)*d-(-1)^(2/3)*a^(1/3)*e))/ e^3
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.45 (sec) , antiderivative size = 504, normalized size of antiderivative = 0.78 \[ \int \frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{d+e x} \, dx=-\frac {-12 d e p x+3 e^2 p x^2-\frac {4 \sqrt {3} \sqrt [3]{a} d e p \arctan \left (\frac {1-\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{\sqrt [3]{b}}-3 e^2 p x^2 \operatorname {Hypergeometric2F1}\left (\frac {2}{3},1,\frac {5}{3},-\frac {b x^3}{a}\right )+\frac {4 \sqrt [3]{a} d e p \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{b}}+4 d^2 p \log \left (\frac {e \left (\sqrt [3]{-1} \sqrt [3]{a}-\sqrt [3]{b} x\right )}{\sqrt [3]{b} d+\sqrt [3]{-1} \sqrt [3]{a} e}\right ) \log (d+e x)+4 d^2 p \log \left (\frac {e \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{-\sqrt [3]{b} d+\sqrt [3]{a} e}\right ) \log (d+e x)+4 d^2 p \log \left (\frac {e \left ((-1)^{2/3} \sqrt [3]{a}+\sqrt [3]{b} x\right )}{-\sqrt [3]{b} d+(-1)^{2/3} \sqrt [3]{a} e}\right ) \log (d+e x)-\frac {2 \sqrt [3]{a} d e p \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{\sqrt [3]{b}}+4 d e x \log \left (c \left (a+b x^3\right )^p\right )-2 e^2 x^2 \log \left (c \left (a+b x^3\right )^p\right )-4 d^2 \log (d+e x) \log \left (c \left (a+b x^3\right )^p\right )+4 d^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt [3]{b} (d+e x)}{\sqrt [3]{b} d-\sqrt [3]{a} e}\right )+4 d^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt [3]{b} (d+e x)}{\sqrt [3]{b} d+\sqrt [3]{-1} \sqrt [3]{a} e}\right )+4 d^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt [3]{b} (d+e x)}{\sqrt [3]{b} d-(-1)^{2/3} \sqrt [3]{a} e}\right )}{4 e^3} \] Input:
Integrate[(x^2*Log[c*(a + b*x^3)^p])/(d + e*x),x]
Output:
-1/4*(-12*d*e*p*x + 3*e^2*p*x^2 - (4*Sqrt[3]*a^(1/3)*d*e*p*ArcTan[(1 - (2* b^(1/3)*x)/a^(1/3))/Sqrt[3]])/b^(1/3) - 3*e^2*p*x^2*Hypergeometric2F1[2/3, 1, 5/3, -((b*x^3)/a)] + (4*a^(1/3)*d*e*p*Log[a^(1/3) + b^(1/3)*x])/b^(1/3 ) + 4*d^2*p*Log[(e*((-1)^(1/3)*a^(1/3) - b^(1/3)*x))/(b^(1/3)*d + (-1)^(1/ 3)*a^(1/3)*e)]*Log[d + e*x] + 4*d^2*p*Log[(e*(a^(1/3) + b^(1/3)*x))/(-(b^( 1/3)*d) + a^(1/3)*e)]*Log[d + e*x] + 4*d^2*p*Log[(e*((-1)^(2/3)*a^(1/3) + b^(1/3)*x))/(-(b^(1/3)*d) + (-1)^(2/3)*a^(1/3)*e)]*Log[d + e*x] - (2*a^(1/ 3)*d*e*p*Log[a^(2/3) - a^(1/3)*b^(1/3)*x + b^(2/3)*x^2])/b^(1/3) + 4*d*e*x *Log[c*(a + b*x^3)^p] - 2*e^2*x^2*Log[c*(a + b*x^3)^p] - 4*d^2*Log[d + e*x ]*Log[c*(a + b*x^3)^p] + 4*d^2*p*PolyLog[2, (b^(1/3)*(d + e*x))/(b^(1/3)*d - a^(1/3)*e)] + 4*d^2*p*PolyLog[2, (b^(1/3)*(d + e*x))/(b^(1/3)*d + (-1)^ (1/3)*a^(1/3)*e)] + 4*d^2*p*PolyLog[2, (b^(1/3)*(d + e*x))/(b^(1/3)*d - (- 1)^(2/3)*a^(1/3)*e)])/e^3
Time = 1.68 (sec) , antiderivative size = 643, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {2916, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{d+e x} \, dx\) |
| \(\Big \downarrow \) 2916 |
| \(\displaystyle \int \left (\frac {d^2 \log \left (c \left (a+b x^3\right )^p\right )}{e^2 (d+e x)}-\frac {d \log \left (c \left (a+b x^3\right )^p\right )}{e^2}+\frac {x \log \left (c \left (a+b x^3\right )^p\right )}{e}\right )dx\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle -\frac {\sqrt {3} a^{2/3} p \arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{2 b^{2/3} e}+\frac {\sqrt [3]{a} d p \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{2 \sqrt [3]{b} e^2}+\frac {a^{2/3} p \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{4 b^{2/3} e}-\frac {a^{2/3} p \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{2 b^{2/3} e}+\frac {\sqrt {3} \sqrt [3]{a} d p \arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt [3]{b} e^2}+\frac {d^2 \log (d+e x) \log \left (c \left (a+b x^3\right )^p\right )}{e^3}-\frac {d x \log \left (c \left (a+b x^3\right )^p\right )}{e^2}+\frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{2 e}-\frac {d^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt [3]{b} (d+e x)}{\sqrt [3]{b} d-\sqrt [3]{a} e}\right )}{e^3}-\frac {d^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt [3]{b} (d+e x)}{\sqrt [3]{b} d+\sqrt [3]{-1} \sqrt [3]{a} e}\right )}{e^3}-\frac {d^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt [3]{b} (d+e x)}{\sqrt [3]{b} d-(-1)^{2/3} \sqrt [3]{a} e}\right )}{e^3}-\frac {d^2 p \log (d+e x) \log \left (-\frac {e \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{b} d-\sqrt [3]{a} e}\right )}{e^3}-\frac {d^2 p \log (d+e x) \log \left (-\frac {e \left ((-1)^{2/3} \sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{b} d-(-1)^{2/3} \sqrt [3]{a} e}\right )}{e^3}-\frac {d^2 p \log (d+e x) \log \left (\frac {\sqrt [3]{-1} e \left (\sqrt [3]{a}+(-1)^{2/3} \sqrt [3]{b} x\right )}{\sqrt [3]{-1} \sqrt [3]{a} e+\sqrt [3]{b} d}\right )}{e^3}-\frac {\sqrt [3]{a} d p \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{b} e^2}+\frac {3 d p x}{e^2}-\frac {3 p x^2}{4 e}\) |
Input:
Int[(x^2*Log[c*(a + b*x^3)^p])/(d + e*x),x]
Output:
(3*d*p*x)/e^2 - (3*p*x^2)/(4*e) + (Sqrt[3]*a^(1/3)*d*p*ArcTan[(a^(1/3) - 2 *b^(1/3)*x)/(Sqrt[3]*a^(1/3))])/(b^(1/3)*e^2) - (Sqrt[3]*a^(2/3)*p*ArcTan[ (a^(1/3) - 2*b^(1/3)*x)/(Sqrt[3]*a^(1/3))])/(2*b^(2/3)*e) - (a^(1/3)*d*p*L og[a^(1/3) + b^(1/3)*x])/(b^(1/3)*e^2) - (a^(2/3)*p*Log[a^(1/3) + b^(1/3)* x])/(2*b^(2/3)*e) - (d^2*p*Log[-((e*(a^(1/3) + b^(1/3)*x))/(b^(1/3)*d - a^ (1/3)*e))]*Log[d + e*x])/e^3 - (d^2*p*Log[-((e*((-1)^(2/3)*a^(1/3) + b^(1/ 3)*x))/(b^(1/3)*d - (-1)^(2/3)*a^(1/3)*e))]*Log[d + e*x])/e^3 - (d^2*p*Log [((-1)^(1/3)*e*(a^(1/3) + (-1)^(2/3)*b^(1/3)*x))/(b^(1/3)*d + (-1)^(1/3)*a ^(1/3)*e)]*Log[d + e*x])/e^3 + (a^(1/3)*d*p*Log[a^(2/3) - a^(1/3)*b^(1/3)* x + b^(2/3)*x^2])/(2*b^(1/3)*e^2) + (a^(2/3)*p*Log[a^(2/3) - a^(1/3)*b^(1/ 3)*x + b^(2/3)*x^2])/(4*b^(2/3)*e) - (d*x*Log[c*(a + b*x^3)^p])/e^2 + (x^2 *Log[c*(a + b*x^3)^p])/(2*e) + (d^2*Log[d + e*x]*Log[c*(a + b*x^3)^p])/e^3 - (d^2*p*PolyLog[2, (b^(1/3)*(d + e*x))/(b^(1/3)*d - a^(1/3)*e)])/e^3 - ( d^2*p*PolyLog[2, (b^(1/3)*(d + e*x))/(b^(1/3)*d + (-1)^(1/3)*a^(1/3)*e)])/ e^3 - (d^2*p*PolyLog[2, (b^(1/3)*(d + e*x))/(b^(1/3)*d - (-1)^(2/3)*a^(1/3 )*e)])/e^3
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m _.)*((f_.) + (g_.)*(x_))^(r_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*Log [c*(d + e*x^n)^p])^q, x^m*(f + g*x)^r, x], x] /; FreeQ[{a, b, c, d, e, f, g , n, p, q}, x] && IntegerQ[m] && IntegerQ[r]
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 2.04 (sec) , antiderivative size = 250, normalized size of antiderivative = 0.39
| method | result | size |
| parts | \(\frac {x^{2} \ln \left (c \left (b \,x^{3}+a \right )^{p}\right )}{2 e}-\frac {d x \ln \left (c \left (b \,x^{3}+a \right )^{p}\right )}{e^{2}}+\frac {d^{2} \ln \left (e x +d \right ) \ln \left (c \left (b \,x^{3}+a \right )^{p}\right )}{e^{3}}-\frac {3 p b \left (\frac {d^{2} \left (\munderset {\textit {\_R1} =\operatorname {RootOf}\left (\textit {\_Z}^{3} b -3 \textit {\_Z}^{2} b d +3 b \,d^{2} \textit {\_Z} +a \,e^{3}-b \,d^{3}\right )}{\sum }\left (\ln \left (e x +d \right ) \ln \left (\frac {-e x +\textit {\_R1} -d}{\textit {\_R1}}\right )+\operatorname {dilog}\left (\frac {-e x +\textit {\_R1} -d}{\textit {\_R1}}\right )\right )\right )}{3 b}+\frac {\left (e x +d \right )^{2}}{4 b}-\frac {3 \left (e x +d \right ) d}{2 b}+\frac {\left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{3} b -3 \textit {\_Z}^{2} b d +3 b \,d^{2} \textit {\_Z} +a \,e^{3}-b \,d^{3}\right )}{\sum }\frac {\left (-\textit {\_R} +3 d \right ) \ln \left (e x -\textit {\_R} +d \right )}{\textit {\_R}^{2}-2 \textit {\_R} d +d^{2}}\right ) a \,e^{3}}{6 b^{2}}\right )}{e^{3}}\) | \(250\) |
| risch | \(\frac {\ln \left (\left (b \,x^{3}+a \right )^{p}\right ) x^{2}}{2 e}-\frac {\ln \left (\left (b \,x^{3}+a \right )^{p}\right ) d x}{e^{2}}+\frac {\ln \left (\left (b \,x^{3}+a \right )^{p}\right ) d^{2} \ln \left (e x +d \right )}{e^{3}}-\frac {p \,d^{2} \left (\munderset {\textit {\_R1} =\operatorname {RootOf}\left (\textit {\_Z}^{3} b -3 \textit {\_Z}^{2} b d +3 b \,d^{2} \textit {\_Z} +a \,e^{3}-b \,d^{3}\right )}{\sum }\left (\ln \left (e x +d \right ) \ln \left (\frac {-e x +\textit {\_R1} -d}{\textit {\_R1}}\right )+\operatorname {dilog}\left (\frac {-e x +\textit {\_R1} -d}{\textit {\_R1}}\right )\right )\right )}{e^{3}}-\frac {3 p \,x^{2}}{4 e}+\frac {3 d p x}{e^{2}}+\frac {15 p \,d^{2}}{4 e^{3}}+\frac {p \left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{3} b -3 \textit {\_Z}^{2} b d +3 b \,d^{2} \textit {\_Z} +a \,e^{3}-b \,d^{3}\right )}{\sum }\frac {\left (\textit {\_R} -3 d \right ) \ln \left (e x -\textit {\_R} +d \right )}{\textit {\_R}^{2}-2 \textit {\_R} d +d^{2}}\right ) a}{2 b}+\left (\frac {i \pi \,\operatorname {csgn}\left (i \left (b \,x^{3}+a \right )^{p}\right ) {\operatorname {csgn}\left (i c \left (b \,x^{3}+a \right )^{p}\right )}^{2}}{2}-\frac {i \pi \,\operatorname {csgn}\left (i \left (b \,x^{3}+a \right )^{p}\right ) \operatorname {csgn}\left (i c \left (b \,x^{3}+a \right )^{p}\right ) \operatorname {csgn}\left (i c \right )}{2}-\frac {i \pi {\operatorname {csgn}\left (i c \left (b \,x^{3}+a \right )^{p}\right )}^{3}}{2}+\frac {i \pi {\operatorname {csgn}\left (i c \left (b \,x^{3}+a \right )^{p}\right )}^{2} \operatorname {csgn}\left (i c \right )}{2}+\ln \left (c \right )\right ) \left (\frac {\frac {1}{2} e \,x^{2}-d x}{e^{2}}+\frac {d^{2} \ln \left (e x +d \right )}{e^{3}}\right )\) | \(383\) |
Input:
int(x^2*ln(c*(b*x^3+a)^p)/(e*x+d),x,method=_RETURNVERBOSE)
Output:
1/2*x^2*ln(c*(b*x^3+a)^p)/e-d*x*ln(c*(b*x^3+a)^p)/e^2+d^2*ln(e*x+d)*ln(c*( b*x^3+a)^p)/e^3-3*p*b/e^3*(1/3*d^2/b*sum(ln(e*x+d)*ln((-e*x+_R1-d)/_R1)+di log((-e*x+_R1-d)/_R1),_R1=RootOf(_Z^3*b-3*_Z^2*b*d+3*_Z*b*d^2+a*e^3-b*d^3) )+1/4/b*(e*x+d)^2-3/2/b*(e*x+d)*d+1/6/b^2*sum((-_R+3*d)/(_R^2-2*_R*d+d^2)* ln(e*x-_R+d),_R=RootOf(_Z^3*b-3*_Z^2*b*d+3*_Z*b*d^2+a*e^3-b*d^3))*a*e^3)
\[ \int \frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{d+e x} \, dx=\int { \frac {x^{2} \log \left ({\left (b x^{3} + a\right )}^{p} c\right )}{e x + d} \,d x } \] Input:
integrate(x^2*log(c*(b*x^3+a)^p)/(e*x+d),x, algorithm="fricas")
Output:
integral(x^2*log((b*x^3 + a)^p*c)/(e*x + d), x)
Timed out. \[ \int \frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{d+e x} \, dx=\text {Timed out} \] Input:
integrate(x**2*ln(c*(b*x**3+a)**p)/(e*x+d),x)
Output:
Timed out
\[ \int \frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{d+e x} \, dx=\int { \frac {x^{2} \log \left ({\left (b x^{3} + a\right )}^{p} c\right )}{e x + d} \,d x } \] Input:
integrate(x^2*log(c*(b*x^3+a)^p)/(e*x+d),x, algorithm="maxima")
Output:
integrate(x^2*log((b*x^3 + a)^p*c)/(e*x + d), x)
\[ \int \frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{d+e x} \, dx=\int { \frac {x^{2} \log \left ({\left (b x^{3} + a\right )}^{p} c\right )}{e x + d} \,d x } \] Input:
integrate(x^2*log(c*(b*x^3+a)^p)/(e*x+d),x, algorithm="giac")
Output:
integrate(x^2*log((b*x^3 + a)^p*c)/(e*x + d), x)
Timed out. \[ \int \frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{d+e x} \, dx=\int \frac {x^2\,\ln \left (c\,{\left (b\,x^3+a\right )}^p\right )}{d+e\,x} \,d x \] Input:
int((x^2*log(c*(a + b*x^3)^p))/(d + e*x),x)
Output:
int((x^2*log(c*(a + b*x^3)^p))/(d + e*x), x)
\[ \int \frac {x^2 \log \left (c \left (a+b x^3\right )^p\right )}{d+e x} \, dx=\frac {12 b^{\frac {1}{3}} a^{\frac {2}{3}} \sqrt {3}\, \mathit {atan} \left (\frac {a^{\frac {1}{3}}-2 b^{\frac {1}{3}} x}{a^{\frac {1}{3}} \sqrt {3}}\right ) d e \,p^{2}-6 \sqrt {3}\, \mathit {atan} \left (\frac {a^{\frac {1}{3}}-2 b^{\frac {1}{3}} x}{a^{\frac {1}{3}} \sqrt {3}}\right ) a \,e^{2} p^{2}-18 b^{\frac {1}{3}} a^{\frac {2}{3}} \mathrm {log}\left (a^{\frac {1}{3}}+b^{\frac {1}{3}} x \right ) d e \,p^{2}+6 b^{\frac {1}{3}} a^{\frac {2}{3}} \mathrm {log}\left (\left (b \,x^{3}+a \right )^{p} c \right ) d e p +12 b^{\frac {2}{3}} a^{\frac {4}{3}} \left (\int \frac {\mathrm {log}\left (\left (b \,x^{3}+a \right )^{p} c \right )}{b e \,x^{4}+b d \,x^{3}+a e x +a d}d x \right ) d^{2} e p -12 b^{\frac {5}{3}} a^{\frac {1}{3}} \left (\int \frac {\mathrm {log}\left (\left (b \,x^{3}+a \right )^{p} c \right ) x^{2}}{b e \,x^{4}+b d \,x^{3}+a e x +a d}d x \right ) d^{3} p +2 b^{\frac {2}{3}} a^{\frac {1}{3}} {\mathrm {log}\left (\left (b \,x^{3}+a \right )^{p} c \right )}^{2} d^{2}-12 b^{\frac {2}{3}} a^{\frac {1}{3}} \mathrm {log}\left (\left (b \,x^{3}+a \right )^{p} c \right ) d e p x +6 b^{\frac {2}{3}} a^{\frac {1}{3}} \mathrm {log}\left (\left (b \,x^{3}+a \right )^{p} c \right ) e^{2} p \,x^{2}+36 b^{\frac {2}{3}} a^{\frac {1}{3}} d e \,p^{2} x -9 b^{\frac {2}{3}} a^{\frac {1}{3}} e^{2} p^{2} x^{2}-9 \,\mathrm {log}\left (a^{\frac {1}{3}}+b^{\frac {1}{3}} x \right ) a \,e^{2} p^{2}+3 \,\mathrm {log}\left (\left (b \,x^{3}+a \right )^{p} c \right ) a \,e^{2} p}{12 b^{\frac {2}{3}} a^{\frac {1}{3}} e^{3} p} \] Input:
int(x^2*log(c*(b*x^3+a)^p)/(e*x+d),x)
Output:
(12*b**(1/3)*a**(2/3)*sqrt(3)*atan((a**(1/3) - 2*b**(1/3)*x)/(a**(1/3)*sqr t(3)))*d*e*p**2 - 6*sqrt(3)*atan((a**(1/3) - 2*b**(1/3)*x)/(a**(1/3)*sqrt( 3)))*a*e**2*p**2 - 18*b**(1/3)*a**(2/3)*log(a**(1/3) + b**(1/3)*x)*d*e*p** 2 + 6*b**(1/3)*a**(2/3)*log((a + b*x**3)**p*c)*d*e*p + 12*b**(2/3)*a**(1/3 )*int(log((a + b*x**3)**p*c)/(a*d + a*e*x + b*d*x**3 + b*e*x**4),x)*a*d**2 *e*p - 12*b**(2/3)*a**(1/3)*int((log((a + b*x**3)**p*c)*x**2)/(a*d + a*e*x + b*d*x**3 + b*e*x**4),x)*b*d**3*p + 2*b**(2/3)*a**(1/3)*log((a + b*x**3) **p*c)**2*d**2 - 12*b**(2/3)*a**(1/3)*log((a + b*x**3)**p*c)*d*e*p*x + 6*b **(2/3)*a**(1/3)*log((a + b*x**3)**p*c)*e**2*p*x**2 + 36*b**(2/3)*a**(1/3) *d*e*p**2*x - 9*b**(2/3)*a**(1/3)*e**2*p**2*x**2 - 9*log(a**(1/3) + b**(1/ 3)*x)*a*e**2*p**2 + 3*log((a + b*x**3)**p*c)*a*e**2*p)/(12*b**(2/3)*a**(1/ 3)*e**3*p)