\(\int \frac {\log ^q(c (d+e x^n)^p)}{x (f+g x^{2 n})} \, dx\) [385]

Optimal result

Integrand size = 29, antiderivative size = 29 \[ \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx=\text {Int}\left (\frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )},x\right ) \] Output:

Defer(Int)(ln(c*(d+e*x^n)^p)^q/x/(f+g*x^(2*n)),x)
 

Mathematica [N/A]

Not integrable

Time = 1.49 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07 \[ \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx=\int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx \] Input:

Integrate[Log[c*(d + e*x^n)^p]^q/(x*(f + g*x^(2*n))),x]
 

Output:

Integrate[Log[c*(d + e*x^n)^p]^q/(x*(f + g*x^(2*n))), x]
 

Rubi [N/A]

Not integrable

Time = 0.41 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {2929}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx\)

\(\Big \downarrow \) 2929

\(\displaystyle \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )}dx\)

Input:

Int[Log[c*(d + e*x^n)^p]^q/(x*(f + g*x^(2*n))),x]
 

Output:

$Aborted
 

Defintions of rubi rules used

rule 2929

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*((h_.)* 
(x_))^(m_.)*((f_) + (g_.)*(x_)^(s_))^(r_.), x_Symbol] :> Unintegrable[(h*x) 
^m*(f + g*x^s)^r*(a + b*Log[c*(d + e*x^n)^p])^q, x] /; FreeQ[{a, b, c, d, e 
, f, g, h, m, n, p, q, r, s}, x]
 

Maple [N/A]

Not integrable

Time = 0.87 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00

\[\int \frac {{\ln \left (c \left (d +e \,x^{n}\right )^{p}\right )}^{q}}{x \left (f +g \,x^{2 n}\right )}d x\]

Input:

int(ln(c*(d+e*x^n)^p)^q/x/(f+g*x^(2*n)),x)
 

Output:

int(ln(c*(d+e*x^n)^p)^q/x/(f+g*x^(2*n)),x)
 

Fricas [N/A]

Not integrable

Time = 0.09 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07 \[ \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx=\int { \frac {\log \left ({\left (e x^{n} + d\right )}^{p} c\right )^{q}}{{\left (g x^{2 \, n} + f\right )} x} \,d x } \] Input:

integrate(log(c*(d+e*x^n)^p)^q/x/(f+g*x^(2*n)),x, algorithm="fricas")
 

Output:

integral(log((e*x^n + d)^p*c)^q/(g*x*x^(2*n) + f*x), x)
 

Sympy [F(-1)]

Timed out. \[ \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx=\text {Timed out} \] Input:

integrate(ln(c*(d+e*x**n)**p)**q/x/(f+g*x**(2*n)),x)
 

Output:

Timed out
 

Maxima [F(-2)]

Exception generated. \[ \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx=\text {Exception raised: RuntimeError} \] Input:

integrate(log(c*(d+e*x^n)^p)^q/x/(f+g*x^(2*n)),x, algorithm="maxima")
 

Output:

Exception raised: RuntimeError >> ECL says: In function CAR, the value of 
the first argument is  0which is not of the expected type LIST
 

Giac [N/A]

Not integrable

Time = 2.54 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07 \[ \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx=\int { \frac {\log \left ({\left (e x^{n} + d\right )}^{p} c\right )^{q}}{{\left (g x^{2 \, n} + f\right )} x} \,d x } \] Input:

integrate(log(c*(d+e*x^n)^p)^q/x/(f+g*x^(2*n)),x, algorithm="giac")
 

Output:

integrate(log((e*x^n + d)^p*c)^q/((g*x^(2*n) + f)*x), x)
 

Mupad [N/A]

Not integrable

Time = 15.84 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07 \[ \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx=\int \frac {{\ln \left (c\,{\left (d+e\,x^n\right )}^p\right )}^q}{x\,\left (f+g\,x^{2\,n}\right )} \,d x \] Input:

int(log(c*(d + e*x^n)^p)^q/(x*(f + g*x^(2*n))),x)
 

Output:

int(log(c*(d + e*x^n)^p)^q/(x*(f + g*x^(2*n))), x)
 

Reduce [N/A]

Not integrable

Time = 0.26 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07 \[ \int \frac {\log ^q\left (c \left (d+e x^n\right )^p\right )}{x \left (f+g x^{2 n}\right )} \, dx=\int \frac {{\mathrm {log}\left (\left (x^{n} e +d \right )^{p} c \right )}^{q}}{x^{2 n} g x +f x}d x \] Input:

int(log(c*(d+e*x^n)^p)^q/x/(f+g*x^(2*n)),x)
 

Output:

int(log((x**n*e + d)**p*c)**q/(x**(2*n)*g*x + f*x),x)