\(\int \frac {(a+b \log (c (d+\frac {e}{\sqrt [3]{x}})))^p}{x^3} \, dx\) [586]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [F]
Fricas [F]
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 22, antiderivative size = 554 \[ \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^3} \, dx=-\frac {2^{-1-p} 3^{-p} e^{-\frac {6 a}{b}} \Gamma \left (1+p,-\frac {6 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p}}{c^6 e^6}+\frac {3\ 5^{-p} d e^{-\frac {5 a}{b}} \Gamma \left (1+p,-\frac {5 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p}}{c^5 e^6}-\frac {15\ 2^{-1-2 p} d^2 e^{-\frac {4 a}{b}} \Gamma \left (1+p,-\frac {4 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p}}{c^4 e^6}+\frac {10\ 3^{-p} d^3 e^{-\frac {3 a}{b}} \Gamma \left (1+p,-\frac {3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p}}{c^3 e^6}-\frac {15\ 2^{-1-p} d^4 e^{-\frac {2 a}{b}} \Gamma \left (1+p,-\frac {2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p}}{c^2 e^6}+\frac {3 d^5 e^{-\frac {a}{b}} \Gamma \left (1+p,-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p}}{c e^6} \] Output:

-2^(-1-p)*GAMMA(p+1,(-6*a-6*b*ln(c*(d+e/x^(1/3))))/b)*(a+b*ln(c*(d+e/x^(1/ 
3))))^p/(3^p)/c^6/e^6/exp(6*a/b)/((-(a+b*ln(c*(d+e/x^(1/3))))/b)^p)+3*d*GA 
MMA(p+1,(-5*a-5*b*ln(c*(d+e/x^(1/3))))/b)*(a+b*ln(c*(d+e/x^(1/3))))^p/(5^p 
)/c^5/e^6/exp(5*a/b)/((-(a+b*ln(c*(d+e/x^(1/3))))/b)^p)-15*2^(-1-2*p)*d^2* 
GAMMA(p+1,(-4*a-4*b*ln(c*(d+e/x^(1/3))))/b)*(a+b*ln(c*(d+e/x^(1/3))))^p/c^ 
4/e^6/exp(4*a/b)/((-(a+b*ln(c*(d+e/x^(1/3))))/b)^p)+10*d^3*GAMMA(p+1,(-3*a 
-3*b*ln(c*(d+e/x^(1/3))))/b)*(a+b*ln(c*(d+e/x^(1/3))))^p/(3^p)/c^3/e^6/exp 
(3*a/b)/((-(a+b*ln(c*(d+e/x^(1/3))))/b)^p)-15*2^(-1-p)*d^4*GAMMA(p+1,(-2*a 
-2*b*ln(c*(d+e/x^(1/3))))/b)*(a+b*ln(c*(d+e/x^(1/3))))^p/c^2/e^6/exp(2*a/b 
)/((-(a+b*ln(c*(d+e/x^(1/3))))/b)^p)+3*d^5*GAMMA(p+1,-(a+b*ln(c*(d+e/x^(1/ 
3))))/b)*(a+b*ln(c*(d+e/x^(1/3))))^p/c/e^6/exp(a/b)/((-(a+b*ln(c*(d+e/x^(1 
/3))))/b)^p)
                                                                                    
                                                                                    
 

Mathematica [A] (verified)

Time = 1.33 (sec) , antiderivative size = 325, normalized size of antiderivative = 0.59 \[ \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^3} \, dx=\frac {2^{-1-2 p} 15^{-p} e^{-\frac {6 a}{b}} \left (-10^p \Gamma \left (1+p,-\frac {6 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )+c d e^{a/b} \left (2^{1+2 p} 3^{1+p} \Gamma \left (1+p,-\frac {5 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )+5^p c d e^{a/b} \left (-5 3^{1+p} \Gamma \left (1+p,-\frac {4 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )+2^p c d e^{a/b} \left (5\ 2^{2+p} \Gamma \left (1+p,-\frac {3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )+3^{1+p} c d e^{a/b} \left (-5 \Gamma \left (1+p,-\frac {2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )+2^{1+p} c d e^{a/b} \Gamma \left (1+p,-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )\right )\right )\right )\right )\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p}}{c^6 e^6} \] Input:

Integrate[(a + b*Log[c*(d + e/x^(1/3))])^p/x^3,x]
 

Output:

(2^(-1 - 2*p)*(-(10^p*Gamma[1 + p, (-6*(a + b*Log[c*(d + e/x^(1/3))]))/b]) 
 + c*d*E^(a/b)*(2^(1 + 2*p)*3^(1 + p)*Gamma[1 + p, (-5*(a + b*Log[c*(d + e 
/x^(1/3))]))/b] + 5^p*c*d*E^(a/b)*(-5*3^(1 + p)*Gamma[1 + p, (-4*(a + b*Lo 
g[c*(d + e/x^(1/3))]))/b] + 2^p*c*d*E^(a/b)*(5*2^(2 + p)*Gamma[1 + p, (-3* 
(a + b*Log[c*(d + e/x^(1/3))]))/b] + 3^(1 + p)*c*d*E^(a/b)*(-5*Gamma[1 + p 
, (-2*(a + b*Log[c*(d + e/x^(1/3))]))/b] + 2^(1 + p)*c*d*E^(a/b)*Gamma[1 + 
 p, -((a + b*Log[c*(d + e/x^(1/3))])/b)])))))*(a + b*Log[c*(d + e/x^(1/3)) 
])^p)/(15^p*c^6*e^6*E^((6*a)/b)*(-((a + b*Log[c*(d + e/x^(1/3))])/b))^p)
 

Rubi [A] (verified)

Time = 2.01 (sec) , antiderivative size = 552, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {2904, 2848, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^3} \, dx\)

\(\Big \downarrow \) 2904

\(\displaystyle -3 \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^{5/3}}d\frac {1}{\sqrt [3]{x}}\)

\(\Big \downarrow \) 2848

\(\displaystyle -3 \int \left (\frac {\left (d+\frac {e}{\sqrt [3]{x}}\right )^5 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{e^5}-\frac {5 d \left (d+\frac {e}{\sqrt [3]{x}}\right )^4 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{e^5}+\frac {10 d^2 \left (d+\frac {e}{\sqrt [3]{x}}\right )^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{e^5}-\frac {10 d^3 \left (d+\frac {e}{\sqrt [3]{x}}\right )^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{e^5}+\frac {5 d^4 \left (d+\frac {e}{\sqrt [3]{x}}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{e^5}-\frac {d^5 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{e^5}\right )d\frac {1}{\sqrt [3]{x}}\)

\(\Big \downarrow \) 2009

\(\displaystyle -3 \left (\frac {6^{-p-1} e^{-\frac {6 a}{b}} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {6 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )}{c^6 e^6}-\frac {d 5^{-p} e^{-\frac {5 a}{b}} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {5 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )}{c^5 e^6}+\frac {5 d^2 2^{-2 p-1} e^{-\frac {4 a}{b}} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {4 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )}{c^4 e^6}-\frac {10 d^3 3^{-p-1} e^{-\frac {3 a}{b}} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )}{c^3 e^6}+\frac {5 d^4 2^{-p-1} e^{-\frac {2 a}{b}} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )}{b}\right )}{c^2 e^6}-\frac {d^5 e^{-\frac {a}{b}} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )}{b}\right )}{c e^6}\right )\)

Input:

Int[(a + b*Log[c*(d + e/x^(1/3))])^p/x^3,x]
 

Output:

-3*((6^(-1 - p)*Gamma[1 + p, (-6*(a + b*Log[c*(d + e/x^(1/3))]))/b]*(a + b 
*Log[c*(d + e/x^(1/3))])^p)/(c^6*e^6*E^((6*a)/b)*(-((a + b*Log[c*(d + e/x^ 
(1/3))])/b))^p) - (d*Gamma[1 + p, (-5*(a + b*Log[c*(d + e/x^(1/3))]))/b]*( 
a + b*Log[c*(d + e/x^(1/3))])^p)/(5^p*c^5*e^6*E^((5*a)/b)*(-((a + b*Log[c* 
(d + e/x^(1/3))])/b))^p) + (5*2^(-1 - 2*p)*d^2*Gamma[1 + p, (-4*(a + b*Log 
[c*(d + e/x^(1/3))]))/b]*(a + b*Log[c*(d + e/x^(1/3))])^p)/(c^4*e^6*E^((4* 
a)/b)*(-((a + b*Log[c*(d + e/x^(1/3))])/b))^p) - (10*3^(-1 - p)*d^3*Gamma[ 
1 + p, (-3*(a + b*Log[c*(d + e/x^(1/3))]))/b]*(a + b*Log[c*(d + e/x^(1/3)) 
])^p)/(c^3*e^6*E^((3*a)/b)*(-((a + b*Log[c*(d + e/x^(1/3))])/b))^p) + (5*2 
^(-1 - p)*d^4*Gamma[1 + p, (-2*(a + b*Log[c*(d + e/x^(1/3))]))/b]*(a + b*L 
og[c*(d + e/x^(1/3))])^p)/(c^2*e^6*E^((2*a)/b)*(-((a + b*Log[c*(d + e/x^(1 
/3))])/b))^p) - (d^5*Gamma[1 + p, -((a + b*Log[c*(d + e/x^(1/3))])/b)]*(a 
+ b*Log[c*(d + e/x^(1/3))])^p)/(c*e^6*E^(a/b)*(-((a + b*Log[c*(d + e/x^(1/ 
3))])/b))^p))
 

Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2848
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)*((f_.) + (g_. 
)*(x_))^(q_.), x_Symbol] :> Int[ExpandIntegrand[(f + g*x)^q*(a + b*Log[c*(d 
 + e*x)^n])^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && NeQ[e*f - 
 d*g, 0] && IGtQ[q, 0]
 

rule 2904
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m 
_.), x_Symbol] :> Simp[1/n   Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a + b*L 
og[c*(d + e*x)^p])^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p, q}, 
 x] && IntegerQ[Simplify[(m + 1)/n]] && (GtQ[(m + 1)/n, 0] || IGtQ[q, 0]) & 
&  !(EqQ[q, 1] && ILtQ[n, 0] && IGtQ[m, 0])
 
Maple [F]

\[\int \frac {{\left (a +b \ln \left (c \left (d +\frac {e}{x^{\frac {1}{3}}}\right )\right )\right )}^{p}}{x^{3}}d x\]

Input:

int((a+b*ln(c*(d+e/x^(1/3))))^p/x^3,x)
 

Output:

int((a+b*ln(c*(d+e/x^(1/3))))^p/x^3,x)
 

Fricas [F]

\[ \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^3} \, dx=\int { \frac {{\left (b \log \left (c {\left (d + \frac {e}{x^{\frac {1}{3}}}\right )}\right ) + a\right )}^{p}}{x^{3}} \,d x } \] Input:

integrate((a+b*log(c*(d+e/x^(1/3))))^p/x^3,x, algorithm="fricas")
 

Output:

integral((b*log((c*d*x + c*e*x^(2/3))/x) + a)^p/x^3, x)
 

Sympy [F(-1)]

Timed out. \[ \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^3} \, dx=\text {Timed out} \] Input:

integrate((a+b*ln(c*(d+e/x**(1/3))))**p/x**3,x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^3} \, dx=\int { \frac {{\left (b \log \left (c {\left (d + \frac {e}{x^{\frac {1}{3}}}\right )}\right ) + a\right )}^{p}}{x^{3}} \,d x } \] Input:

integrate((a+b*log(c*(d+e/x^(1/3))))^p/x^3,x, algorithm="maxima")
 

Output:

integrate((b*log(c*(d + e/x^(1/3))) + a)^p/x^3, x)
 

Giac [F]

\[ \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^3} \, dx=\int { \frac {{\left (b \log \left (c {\left (d + \frac {e}{x^{\frac {1}{3}}}\right )}\right ) + a\right )}^{p}}{x^{3}} \,d x } \] Input:

integrate((a+b*log(c*(d+e/x^(1/3))))^p/x^3,x, algorithm="giac")
 

Output:

integrate((b*log(c*(d + e/x^(1/3))) + a)^p/x^3, x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^3} \, dx=\int \frac {{\left (a+b\,\ln \left (c\,\left (d+\frac {e}{x^{1/3}}\right )\right )\right )}^p}{x^3} \,d x \] Input:

int((a + b*log(c*(d + e/x^(1/3))))^p/x^3,x)
 

Output:

int((a + b*log(c*(d + e/x^(1/3))))^p/x^3, x)
 

Reduce [F]

\[ \int \frac {\left (a+b \log \left (c \left (d+\frac {e}{\sqrt [3]{x}}\right )\right )\right )^p}{x^3} \, dx=\text {too large to display} \] Input:

int((a+b*log(c*(d+e/x^(1/3))))^p/x^3,x)
 

Output:

( - 180*x**(2/3)*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*b*d**5*e*p* 
*2*x - 180*x**(2/3)*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*b*d**5*e 
*p*x + 45*x**(2/3)*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*b*d**2*e* 
*4*p**2 + 45*x**(2/3)*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*b*d**2 
*e**4*p + 90*x**(1/3)*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*b*d**4 
*e**2*p**2*x + 90*x**(1/3)*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*b 
*d**4*e**2*p*x - 36*x**(1/3)*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p 
*b*d*e**5*p**2 - 36*x**(1/3)*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p 
*b*d*e**5*p + 180*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*log((x**(1 
/3)*c*d + c*e)/x**(1/3))*b*d**6*p*x**2 + 180*(log((x**(1/3)*c*d + c*e)/x** 
(1/3))*b + a)**p*a*d**6*p*x**2 - 180*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b 
 + a)**p*a*e**6*p - 180*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*a*e* 
*6 - 60*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*b*d**3*e**3*p**2*x - 
 60*(log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p*b*d**3*e**3*p*x + 90*int 
((log((x**(1/3)*c*d + c*e)/x**(1/3))*b + a)**p/(6*x**(2/3)*log((x**(1/3)*c 
*d + c*e)/x**(1/3))*a*b*d*x**2 + x**(2/3)*log((x**(1/3)*c*d + c*e)/x**(1/3 
))*b**2*d*p*x**2 + 6*x**(2/3)*a**2*d*x**2 + x**(2/3)*a*b*d*p*x**2 + 6*x**( 
1/3)*log((x**(1/3)*c*d + c*e)/x**(1/3))*a*b*e*x**2 + x**(1/3)*log((x**(1/3 
)*c*d + c*e)/x**(1/3))*b**2*e*p*x**2 + 6*x**(1/3)*a**2*e*x**2 + x**(1/3)*a 
*b*e*p*x**2),x)*a*b**2*d**2*e**5*p**3*x**2 + 90*int((log((x**(1/3)*c*d ...