Integrand size = 36, antiderivative size = 261 \[ \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}} \, dx=\frac {b g p \sqrt {f-g x^2}}{4 f^2 x^2}+\frac {b g^2 p \text {arctanh}\left (\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right )}{f^{5/2}}-\frac {\sqrt {f-g x^2} \left (a+b \log \left (c \left (d f-d g x^2\right )^p\right )\right )}{4 f x^4}-\frac {3 g \sqrt {f-g x^2} \left (a+b \log \left (c \left (d f-d g x^2\right )^p\right )\right )}{8 f^2 x^2}-\frac {3 g^2 \text {arctanh}\left (\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right ) \left (a+b \log \left (c \left (d f-d g x^2\right )^p\right )\right )}{8 f^{5/2}}-\frac {3 b g^2 p \operatorname {PolyLog}\left (2,-\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right )}{8 f^{5/2}}+\frac {3 b g^2 p \operatorname {PolyLog}\left (2,\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right )}{8 f^{5/2}} \] Output:
1/4*b*g*p*(-g*x^2+f)^(1/2)/f^2/x^2+b*g^2*p*arctanh((-g*x^2+f)^(1/2)/f^(1/2 ))/f^(5/2)-1/4*(-g*x^2+f)^(1/2)*(a+b*ln(c*(-d*g*x^2+d*f)^p))/f/x^4-3/8*g*( -g*x^2+f)^(1/2)*(a+b*ln(c*(-d*g*x^2+d*f)^p))/f^2/x^2-3/8*g^2*arctanh((-g*x ^2+f)^(1/2)/f^(1/2))*(a+b*ln(c*(-d*g*x^2+d*f)^p))/f^(5/2)-3/8*b*g^2*p*poly log(2,-(-g*x^2+f)^(1/2)/f^(1/2))/f^(5/2)+3/8*b*g^2*p*polylog(2,(-g*x^2+f)^ (1/2)/f^(1/2))/f^(5/2)
Time = 0.44 (sec) , antiderivative size = 429, normalized size of antiderivative = 1.64 \[ \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}} \, dx=-\frac {4 a f^{3/2} \sqrt {f-g x^2}+6 a \sqrt {f} g x^2 \sqrt {f-g x^2}-4 b \sqrt {f} g p x^2 \sqrt {f-g x^2}+4 b f^{3/2} \sqrt {f-g x^2} \log \left (c \left (d \left (f-g x^2\right )\right )^p\right )+6 b \sqrt {f} g x^2 \sqrt {f-g x^2} \log \left (c \left (d \left (f-g x^2\right )\right )^p\right )+8 b g^2 p x^4 \log \left (\sqrt {f}-\sqrt {f-g x^2}\right )-8 b g^2 p x^4 \log \left (\sqrt {f}+\sqrt {f-g x^2}\right )-3 a g^2 x^4 \log \left (1-\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right )-3 b g^2 x^4 \log \left (c \left (d \left (f-g x^2\right )\right )^p\right ) \log \left (1-\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right )+3 a g^2 x^4 \log \left (1+\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right )+3 b g^2 x^4 \log \left (c \left (d \left (f-g x^2\right )\right )^p\right ) \log \left (1+\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right )+6 b g^2 p x^4 \operatorname {PolyLog}\left (2,-\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right )-6 b g^2 p x^4 \operatorname {PolyLog}\left (2,\frac {\sqrt {f-g x^2}}{\sqrt {f}}\right )}{16 f^{5/2} x^4} \] Input:
Integrate[(a + b*Log[c*(d*f - d*g*x^2)^p])/(x^5*Sqrt[f - g*x^2]),x]
Output:
-1/16*(4*a*f^(3/2)*Sqrt[f - g*x^2] + 6*a*Sqrt[f]*g*x^2*Sqrt[f - g*x^2] - 4 *b*Sqrt[f]*g*p*x^2*Sqrt[f - g*x^2] + 4*b*f^(3/2)*Sqrt[f - g*x^2]*Log[c*(d* (f - g*x^2))^p] + 6*b*Sqrt[f]*g*x^2*Sqrt[f - g*x^2]*Log[c*(d*(f - g*x^2))^ p] + 8*b*g^2*p*x^4*Log[Sqrt[f] - Sqrt[f - g*x^2]] - 8*b*g^2*p*x^4*Log[Sqrt [f] + Sqrt[f - g*x^2]] - 3*a*g^2*x^4*Log[1 - Sqrt[f - g*x^2]/Sqrt[f]] - 3* b*g^2*x^4*Log[c*(d*(f - g*x^2))^p]*Log[1 - Sqrt[f - g*x^2]/Sqrt[f]] + 3*a* g^2*x^4*Log[1 + Sqrt[f - g*x^2]/Sqrt[f]] + 3*b*g^2*x^4*Log[c*(d*(f - g*x^2 ))^p]*Log[1 + Sqrt[f - g*x^2]/Sqrt[f]] + 6*b*g^2*p*x^4*PolyLog[2, -(Sqrt[f - g*x^2]/Sqrt[f])] - 6*b*g^2*p*x^4*PolyLog[2, Sqrt[f - g*x^2]/Sqrt[f]])/( f^(5/2)*x^4)
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}} \, dx\) |
\(\Big \downarrow \) 2929 |
\(\displaystyle \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}}dx\) |
Input:
Int[(a + b*Log[c*(d*f - d*g*x^2)^p])/(x^5*Sqrt[f - g*x^2]),x]
Output:
$Aborted
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*((h_.)* (x_))^(m_.)*((f_) + (g_.)*(x_)^(s_))^(r_.), x_Symbol] :> Unintegrable[(h*x) ^m*(f + g*x^s)^r*(a + b*Log[c*(d + e*x^n)^p])^q, x] /; FreeQ[{a, b, c, d, e , f, g, h, m, n, p, q, r, s}, x]
\[\int \frac {a +b \ln \left (c \left (-d g \,x^{2}+d f \right )^{p}\right )}{x^{5} \sqrt {-g \,x^{2}+f}}d x\]
Input:
int((a+b*ln(c*(-d*g*x^2+d*f)^p))/x^5/(-g*x^2+f)^(1/2),x)
Output:
int((a+b*ln(c*(-d*g*x^2+d*f)^p))/x^5/(-g*x^2+f)^(1/2),x)
\[ \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}} \, dx=\int { \frac {b \log \left ({\left (-d g x^{2} + d f\right )}^{p} c\right ) + a}{\sqrt {-g x^{2} + f} x^{5}} \,d x } \] Input:
integrate((a+b*log(c*(-d*g*x^2+d*f)^p))/x^5/(-g*x^2+f)^(1/2),x, algorithm= "fricas")
Output:
integral(-(sqrt(-g*x^2 + f)*b*log((-d*g*x^2 + d*f)^p*c) + sqrt(-g*x^2 + f) *a)/(g*x^7 - f*x^5), x)
Timed out. \[ \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}} \, dx=\text {Timed out} \] Input:
integrate((a+b*ln(c*(-d*g*x**2+d*f)**p))/x**5/(-g*x**2+f)**(1/2),x)
Output:
Timed out
\[ \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}} \, dx=\int { \frac {b \log \left ({\left (-d g x^{2} + d f\right )}^{p} c\right ) + a}{\sqrt {-g x^{2} + f} x^{5}} \,d x } \] Input:
integrate((a+b*log(c*(-d*g*x^2+d*f)^p))/x^5/(-g*x^2+f)^(1/2),x, algorithm= "maxima")
Output:
-1/8*a*(3*g^2*log(2*sqrt(-g*x^2 + f)*sqrt(f)/abs(x) + 2*f/abs(x))/f^(5/2) + 3*sqrt(-g*x^2 + f)*g/(f^2*x^2) + 2*sqrt(-g*x^2 + f)/(f*x^4)) + b*integra te((p*log(d) + log((-g*x^2 + f)^p) + log(c))/(sqrt(-g*x^2 + f)*x^5), x)
\[ \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}} \, dx=\int { \frac {b \log \left ({\left (-d g x^{2} + d f\right )}^{p} c\right ) + a}{\sqrt {-g x^{2} + f} x^{5}} \,d x } \] Input:
integrate((a+b*log(c*(-d*g*x^2+d*f)^p))/x^5/(-g*x^2+f)^(1/2),x, algorithm= "giac")
Output:
integrate((b*log((-d*g*x^2 + d*f)^p*c) + a)/(sqrt(-g*x^2 + f)*x^5), x)
Timed out. \[ \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}} \, dx=\int \frac {a+b\,\ln \left (c\,{\left (d\,f-d\,g\,x^2\right )}^p\right )}{x^5\,\sqrt {f-g\,x^2}} \,d x \] Input:
int((a + b*log(c*(d*f - d*g*x^2)^p))/(x^5*(f - g*x^2)^(1/2)),x)
Output:
int((a + b*log(c*(d*f - d*g*x^2)^p))/(x^5*(f - g*x^2)^(1/2)), x)
\[ \int \frac {a+b \log \left (c \left (d f-d g x^2\right )^p\right )}{x^5 \sqrt {f-g x^2}} \, dx=\frac {-2 \sqrt {-g \,x^{2}+f}\, a \,f^{2}-3 \sqrt {-g \,x^{2}+f}\, a f g \,x^{2}+3 \sqrt {f}\, \mathrm {log}\left (\tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {g}\, x}{\sqrt {f}}\right )}{2}\right )\right ) a \,g^{2} x^{4}+8 \left (\int \frac {\mathrm {log}\left (\left (-d g \,x^{2}+d f \right )^{p} c \right )}{\sqrt {-g \,x^{2}+f}\, x^{5}}d x \right ) b \,f^{3} x^{4}}{8 f^{3} x^{4}} \] Input:
int((a+b*log(c*(-d*g*x^2+d*f)^p))/x^5/(-g*x^2+f)^(1/2),x)
Output:
( - 2*sqrt(f - g*x**2)*a*f**2 - 3*sqrt(f - g*x**2)*a*f*g*x**2 + 3*sqrt(f)* log(tan(asin((sqrt(g)*x)/sqrt(f))/2))*a*g**2*x**4 + 8*int(log((d*f - d*g*x **2)**p*c)/(sqrt(f - g*x**2)*x**5),x)*b*f**3*x**4)/(8*f**3*x**4)