\(\int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx\) [290]

Optimal result
Mathematica [C] (verified)
Rubi [A] (verified)
Maple [B] (verified)
Fricas [B] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [B] (verification not implemented)
Reduce [F]

Optimal result

Integrand size = 13, antiderivative size = 112 \[ \int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx=-\frac {3 \arctan \left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{4 \sqrt {2}}+\frac {3 \arctan \left (1+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{4 \sqrt {2}}-\frac {3 \text {arctanh}\left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)} (1+\tan (x))}\right )}{4 \sqrt {2}}-\frac {1}{2} \sqrt {\cos (x)} \sin ^{\frac {3}{2}}(x) \] Output:

-3/8*arctan(1-2^(1/2)*sin(x)^(1/2)/cos(x)^(1/2))*2^(1/2)+3/8*arctan(1+2^(1 
/2)*sin(x)^(1/2)/cos(x)^(1/2))*2^(1/2)-3/8*arctanh(2^(1/2)*sin(x)^(1/2)/co 
s(x)^(1/2)/(1+tan(x)))*2^(1/2)-1/2*cos(x)^(1/2)*sin(x)^(3/2)
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.02 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.34 \[ \int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx=\frac {2 \cos ^2(x)^{3/4} \operatorname {Hypergeometric2F1}\left (\frac {3}{4},\frac {7}{4},\frac {11}{4},\sin ^2(x)\right ) \sin ^{\frac {7}{2}}(x)}{7 \cos ^{\frac {3}{2}}(x)} \] Input:

Integrate[Sin[x]^(5/2)/Sqrt[Cos[x]],x]
 

Output:

(2*(Cos[x]^2)^(3/4)*Hypergeometric2F1[3/4, 7/4, 11/4, Sin[x]^2]*Sin[x]^(7/ 
2))/(7*Cos[x]^(3/2))
 

Rubi [A] (verified)

Time = 0.39 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.37, number of steps used = 13, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.923, Rules used = {3042, 3048, 3042, 3054, 826, 1476, 1082, 217, 1479, 25, 27, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\sin (x)^{5/2}}{\sqrt {\cos (x)}}dx\)

\(\Big \downarrow \) 3048

\(\displaystyle \frac {3}{4} \int \frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}dx-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {3}{4} \int \frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}dx-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 3054

\(\displaystyle \frac {3}{2} \int \frac {\tan (x)}{\tan ^2(x)+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 826

\(\displaystyle \frac {3}{2} \left (\frac {1}{2} \int \frac {\tan (x)+1}{\tan ^2(x)+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}-\frac {1}{2} \int \frac {1-\tan (x)}{\tan ^2(x)+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 1476

\(\displaystyle \frac {3}{2} \left (\frac {1}{2} \left (\frac {1}{2} \int \frac {1}{\tan (x)-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}+\frac {1}{2} \int \frac {1}{\tan (x)+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )-\frac {1}{2} \int \frac {1-\tan (x)}{\tan ^2(x)+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 1082

\(\displaystyle \frac {3}{2} \left (\frac {1}{2} \left (\frac {\int \frac {1}{-\tan (x)-1}d\left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\tan (x)-1}d\left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-\tan (x)}{\tan ^2(x)+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {3}{2} \left (\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-\tan (x)}{\tan ^2(x)+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 1479

\(\displaystyle \frac {3}{2} \left (\frac {1}{2} \left (\frac {\int -\frac {\sqrt {2}-\frac {2 \sqrt {\sin (x)}}{\sqrt {\cos (x)}}}{\tan (x)-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}}{2 \sqrt {2}}+\frac {\int -\frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{\tan (x)+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}\right )\right )-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {3}{2} \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt {\sin (x)}}{\sqrt {\cos (x)}}}{\tan (x)-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}}{2 \sqrt {2}}-\frac {\int \frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{\tan (x)+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}\right )\right )-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {3}{2} \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt {\sin (x)}}{\sqrt {\cos (x)}}}{\tan (x)-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}}{2 \sqrt {2}}-\frac {1}{2} \int \frac {\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1}{\tan (x)+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1}d\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}\right )\right )-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {3}{2} \left (\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}\right )+\frac {1}{2} \left (\frac {\log \left (\tan (x)-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\tan (x)+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{2 \sqrt {2}}\right )\right )-\frac {1}{2} \sin ^{\frac {3}{2}}(x) \sqrt {\cos (x)}\)

Input:

Int[Sin[x]^(5/2)/Sqrt[Cos[x]],x]
 

Output:

(3*((-(ArcTan[1 - (Sqrt[2]*Sqrt[Sin[x]])/Sqrt[Cos[x]]]/Sqrt[2]) + ArcTan[1 
 + (Sqrt[2]*Sqrt[Sin[x]])/Sqrt[Cos[x]]]/Sqrt[2])/2 + (Log[1 - (Sqrt[2]*Sqr 
t[Sin[x]])/Sqrt[Cos[x]] + Tan[x]]/(2*Sqrt[2]) - Log[1 + (Sqrt[2]*Sqrt[Sin[ 
x]])/Sqrt[Cos[x]] + Tan[x]]/(2*Sqrt[2]))/2))/2 - (Sqrt[Cos[x]]*Sin[x]^(3/2 
))/2
 

Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 826
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 
2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s)   Int[(r + s*x^2)/(a + b*x^ 
4), x], x] - Simp[1/(2*s)   Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ 
a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] 
 && AtomQ[SplitProduct[SumBaseQ, b]]))
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3048
Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> Simp[(-a)*(b*Cos[e + f*x])^(n + 1)*((a*Sin[e + f*x])^(m - 
1)/(b*f*(m + n))), x] + Simp[a^2*((m - 1)/(m + n))   Int[(b*Cos[e + f*x])^n 
*(a*Sin[e + f*x])^(m - 2), x], x] /; FreeQ[{a, b, e, f, n}, x] && GtQ[m, 1] 
 && NeQ[m + n, 0] && IntegersQ[2*m, 2*n]
 

rule 3054
Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> With[{k = Denominator[m]}, Simp[k*a*(b/f)   Subst[Int[x^(k 
*(m + 1) - 1)/(a^2 + b^2*x^(2*k)), x], x, (a*Sin[e + f*x])^(1/k)/(b*Cos[e + 
 f*x])^(1/k)], x]] /; FreeQ[{a, b, e, f}, x] && EqQ[m + n, 0] && GtQ[m, 0] 
&& LtQ[m, 1]
 
Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(253\) vs. \(2(76)=152\).

Time = 2.34 (sec) , antiderivative size = 254, normalized size of antiderivative = 2.27

method result size
default \(\frac {\sqrt {2}\, \sqrt {\cos \left (x \right )}\, \sin \left (x \right )^{\frac {3}{2}} \left (\left (3 \cos \left (x \right )-3\right ) \ln \left (-\frac {2 \sqrt {2}\, \sqrt {\frac {\sin \left (x \right ) \cos \left (x \right )}{\left (\cos \left (x \right )+1\right )^{2}}}\, \sin \left (x \right )-\cot \left (x \right ) \cos \left (x \right )+2 \cot \left (x \right )+\sin \left (x \right )-2 \cos \left (x \right )-\csc \left (x \right )+2}{-1+\cos \left (x \right )}\right )+\left (-3 \cos \left (x \right )+3\right ) \ln \left (\frac {2 \sqrt {2}\, \sqrt {\frac {\sin \left (x \right ) \cos \left (x \right )}{\left (\cos \left (x \right )+1\right )^{2}}}\, \sin \left (x \right )+\cot \left (x \right ) \cos \left (x \right )-2 \cot \left (x \right )-\sin \left (x \right )+2 \cos \left (x \right )+\csc \left (x \right )-2}{-1+\cos \left (x \right )}\right )+\left (-6 \cos \left (x \right )+6\right ) \arctan \left (\frac {\sqrt {2}\, \sqrt {\frac {\sin \left (x \right ) \cos \left (x \right )}{\left (\cos \left (x \right )+1\right )^{2}}}\, \sin \left (x \right )-\cos \left (x \right )+1}{-1+\cos \left (x \right )}\right )+\left (-6 \cos \left (x \right )+6\right ) \arctan \left (\frac {\sqrt {2}\, \sqrt {\frac {\sin \left (x \right ) \cos \left (x \right )}{\left (\cos \left (x \right )+1\right )^{2}}}\, \sin \left (x \right )+\cos \left (x \right )-1}{-1+\cos \left (x \right )}\right )-4 \sqrt {2}\, \sqrt {\frac {\sin \left (x \right ) \cos \left (x \right )}{\left (\cos \left (x \right )+1\right )^{2}}}\, \sin \left (x \right )^{3}\right ) \sec \left (\frac {x}{2}\right )^{3} \csc \left (\frac {x}{2}\right )^{3}}{128 \sqrt {\frac {\sin \left (x \right ) \cos \left (x \right )}{\left (\cos \left (x \right )+1\right )^{2}}}}\) \(254\)

Input:

int(sin(x)^(5/2)/cos(x)^(1/2),x,method=_RETURNVERBOSE)
 

Output:

1/128*2^(1/2)*cos(x)^(1/2)*sin(x)^(3/2)*((3*cos(x)-3)*ln(-(2*2^(1/2)*(sin( 
x)*cos(x)/(cos(x)+1)^2)^(1/2)*sin(x)-cot(x)*cos(x)+2*cot(x)+sin(x)-2*cos(x 
)-csc(x)+2)/(-1+cos(x)))+(-3*cos(x)+3)*ln((2*2^(1/2)*(sin(x)*cos(x)/(cos(x 
)+1)^2)^(1/2)*sin(x)+cot(x)*cos(x)-2*cot(x)-sin(x)+2*cos(x)+csc(x)-2)/(-1+ 
cos(x)))+(-6*cos(x)+6)*arctan((2^(1/2)*(sin(x)*cos(x)/(cos(x)+1)^2)^(1/2)* 
sin(x)-cos(x)+1)/(-1+cos(x)))+(-6*cos(x)+6)*arctan((2^(1/2)*(sin(x)*cos(x) 
/(cos(x)+1)^2)^(1/2)*sin(x)+cos(x)-1)/(-1+cos(x)))-4*2^(1/2)*(sin(x)*cos(x 
)/(cos(x)+1)^2)^(1/2)*sin(x)^3)/(sin(x)*cos(x)/(cos(x)+1)^2)^(1/2)*sec(1/2 
*x)^3*csc(1/2*x)^3
 

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 230 vs. \(2 (76) = 152\).

Time = 0.13 (sec) , antiderivative size = 230, normalized size of antiderivative = 2.05 \[ \int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx=-\frac {1}{2} \, \sqrt {\cos \left (x\right )} \sin \left (x\right )^{\frac {3}{2}} - \frac {3}{32} \, \sqrt {2} \arctan \left (\frac {2 \, \cos \left (x\right )^{3} - 2 \, \cos \left (x\right )^{2} \sin \left (x\right ) + \sqrt {2} \sqrt {\cos \left (x\right )} \sqrt {\sin \left (x\right )} - 2 \, \cos \left (x\right )}{2 \, {\left (\cos \left (x\right )^{3} + \cos \left (x\right )^{2} \sin \left (x\right ) - \cos \left (x\right )\right )}}\right ) - \frac {3}{32} \, \sqrt {2} \arctan \left (-\frac {2 \, \cos \left (x\right )^{3} - 2 \, \cos \left (x\right )^{2} \sin \left (x\right ) - \sqrt {2} \sqrt {\cos \left (x\right )} \sqrt {\sin \left (x\right )} - 2 \, \cos \left (x\right )}{2 \, {\left (\cos \left (x\right )^{3} + \cos \left (x\right )^{2} \sin \left (x\right ) - \cos \left (x\right )\right )}}\right ) + \frac {3}{16} \, \sqrt {2} \arctan \left (-\frac {\sqrt {2} \cos \left (x\right ) - \sqrt {2} \sin \left (x\right )}{2 \, \sqrt {\cos \left (x\right )} \sqrt {\sin \left (x\right )}}\right ) - \frac {3}{32} \, \sqrt {2} \log \left (2 \, {\left (\sqrt {2} \cos \left (x\right ) + \sqrt {2} \sin \left (x\right )\right )} \sqrt {\cos \left (x\right )} \sqrt {\sin \left (x\right )} + 4 \, \cos \left (x\right ) \sin \left (x\right ) + 1\right ) + \frac {3}{32} \, \sqrt {2} \log \left (-2 \, {\left (\sqrt {2} \cos \left (x\right ) + \sqrt {2} \sin \left (x\right )\right )} \sqrt {\cos \left (x\right )} \sqrt {\sin \left (x\right )} + 4 \, \cos \left (x\right ) \sin \left (x\right ) + 1\right ) \] Input:

integrate(sin(x)^(5/2)/cos(x)^(1/2),x, algorithm="fricas")
 

Output:

-1/2*sqrt(cos(x))*sin(x)^(3/2) - 3/32*sqrt(2)*arctan(1/2*(2*cos(x)^3 - 2*c 
os(x)^2*sin(x) + sqrt(2)*sqrt(cos(x))*sqrt(sin(x)) - 2*cos(x))/(cos(x)^3 + 
 cos(x)^2*sin(x) - cos(x))) - 3/32*sqrt(2)*arctan(-1/2*(2*cos(x)^3 - 2*cos 
(x)^2*sin(x) - sqrt(2)*sqrt(cos(x))*sqrt(sin(x)) - 2*cos(x))/(cos(x)^3 + c 
os(x)^2*sin(x) - cos(x))) + 3/16*sqrt(2)*arctan(-1/2*(sqrt(2)*cos(x) - sqr 
t(2)*sin(x))/(sqrt(cos(x))*sqrt(sin(x)))) - 3/32*sqrt(2)*log(2*(sqrt(2)*co 
s(x) + sqrt(2)*sin(x))*sqrt(cos(x))*sqrt(sin(x)) + 4*cos(x)*sin(x) + 1) + 
3/32*sqrt(2)*log(-2*(sqrt(2)*cos(x) + sqrt(2)*sin(x))*sqrt(cos(x))*sqrt(si 
n(x)) + 4*cos(x)*sin(x) + 1)
 

Sympy [F(-1)]

Timed out. \[ \int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx=\text {Timed out} \] Input:

integrate(sin(x)**(5/2)/cos(x)**(1/2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx=\int { \frac {\sin \left (x\right )^{\frac {5}{2}}}{\sqrt {\cos \left (x\right )}} \,d x } \] Input:

integrate(sin(x)^(5/2)/cos(x)^(1/2),x, algorithm="maxima")
 

Output:

integrate(sin(x)^(5/2)/sqrt(cos(x)), x)
 

Giac [F]

\[ \int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx=\int { \frac {\sin \left (x\right )^{\frac {5}{2}}}{\sqrt {\cos \left (x\right )}} \,d x } \] Input:

integrate(sin(x)^(5/2)/cos(x)^(1/2),x, algorithm="giac")
 

Output:

integrate(sin(x)^(5/2)/sqrt(cos(x)), x)
 

Mupad [B] (verification not implemented)

Time = 25.73 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.22 \[ \int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx=-\frac {2\,\sqrt {\cos \left (x\right )}\,{\sin \left (x\right )}^{7/2}\,{{}}_2{\mathrm {F}}_1\left (-\frac {3}{4},\frac {1}{4};\ \frac {5}{4};\ {\cos \left (x\right )}^2\right )}{{\left ({\sin \left (x\right )}^2\right )}^{7/4}} \] Input:

int(sin(x)^(5/2)/cos(x)^(1/2),x)
 

Output:

-(2*cos(x)^(1/2)*sin(x)^(7/2)*hypergeom([-3/4, 1/4], 5/4, cos(x)^2))/(sin( 
x)^2)^(7/4)
 

Reduce [F]

\[ \int \frac {\sin ^{\frac {5}{2}}(x)}{\sqrt {\cos (x)}} \, dx=\int \frac {\sqrt {\sin \left (x \right )}\, \sqrt {\cos \left (x \right )}\, \sin \left (x \right )^{2}}{\cos \left (x \right )}d x \] Input:

int(sin(x)^(5/2)/cos(x)^(1/2),x)
 

Output:

int((sqrt(sin(x))*sqrt(cos(x))*sin(x)**2)/cos(x),x)