\(\int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx\) [472]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [A] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 25, antiderivative size = 391 \[ \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx=-\frac {7 a^{9/2} \arctan \left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}\right ) \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)}}{128 \sqrt {2} b^{5/2} f}+\frac {7 a^{9/2} \arctan \left (1+\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}\right ) \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)}}{128 \sqrt {2} b^{5/2} f}-\frac {7 a^{9/2} \text {arctanh}\left (\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)} \left (\sqrt {a}+\sqrt {a} \tan (e+f x)\right )}\right ) \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)}}{128 \sqrt {2} b^{5/2} f}-\frac {7 a^3 (a \sin (e+f x))^{3/2}}{192 b f \sqrt {b \sec (e+f x)}}-\frac {a (a \sin (e+f x))^{7/2}}{48 b f \sqrt {b \sec (e+f x)}}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}} \] Output:

-7/256*a^(9/2)*arctan(1-2^(1/2)*b^(1/2)*(a*sin(f*x+e))^(1/2)/a^(1/2)/(b*co 
s(f*x+e))^(1/2))*(b*cos(f*x+e))^(1/2)*(b*sec(f*x+e))^(1/2)*2^(1/2)/b^(5/2) 
/f+7/256*a^(9/2)*arctan(1+2^(1/2)*b^(1/2)*(a*sin(f*x+e))^(1/2)/a^(1/2)/(b* 
cos(f*x+e))^(1/2))*(b*cos(f*x+e))^(1/2)*(b*sec(f*x+e))^(1/2)*2^(1/2)/b^(5/ 
2)/f-7/256*a^(9/2)*arctanh(2^(1/2)*b^(1/2)*(a*sin(f*x+e))^(1/2)/(b*cos(f*x 
+e))^(1/2)/(a^(1/2)+a^(1/2)*tan(f*x+e)))*(b*cos(f*x+e))^(1/2)*(b*sec(f*x+e 
))^(1/2)*2^(1/2)/b^(5/2)/f-7/192*a^3*(a*sin(f*x+e))^(3/2)/b/f/(b*sec(f*x+e 
))^(1/2)-1/48*a*(a*sin(f*x+e))^(7/2)/b/f/(b*sec(f*x+e))^(1/2)+1/6*(a*sin(f 
*x+e))^(11/2)/a/b/f/(b*sec(f*x+e))^(1/2)
 

Mathematica [A] (verified)

Time = 2.91 (sec) , antiderivative size = 176, normalized size of antiderivative = 0.45 \[ \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx=-\frac {a^5 \left (4 (-3+14 \cos (2 (e+f x))-4 \cos (4 (e+f x))) \sin ^2(e+f x)-21 \sqrt {2} \arctan \left (\frac {-1+\sqrt {\tan ^2(e+f x)}}{\sqrt {2} \sqrt [4]{\tan ^2(e+f x)}}\right ) \sqrt [4]{\tan ^2(e+f x)}+21 \sqrt {2} \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{\tan ^2(e+f x)}}{1+\sqrt {\tan ^2(e+f x)}}\right ) \sqrt [4]{\tan ^2(e+f x)}\right )}{768 b f \sqrt {b \sec (e+f x)} \sqrt {a \sin (e+f x)}} \] Input:

Integrate[(a*Sin[e + f*x])^(9/2)/(b*Sec[e + f*x])^(3/2),x]
 

Output:

-1/768*(a^5*(4*(-3 + 14*Cos[2*(e + f*x)] - 4*Cos[4*(e + f*x)])*Sin[e + f*x 
]^2 - 21*Sqrt[2]*ArcTan[(-1 + Sqrt[Tan[e + f*x]^2])/(Sqrt[2]*(Tan[e + f*x] 
^2)^(1/4))]*(Tan[e + f*x]^2)^(1/4) + 21*Sqrt[2]*ArcTanh[(Sqrt[2]*(Tan[e + 
f*x]^2)^(1/4))/(1 + Sqrt[Tan[e + f*x]^2])]*(Tan[e + f*x]^2)^(1/4)))/(b*f*S 
qrt[b*Sec[e + f*x]]*Sqrt[a*Sin[e + f*x]])
 

Rubi [A] (verified)

Time = 1.79 (sec) , antiderivative size = 433, normalized size of antiderivative = 1.11, number of steps used = 19, number of rules used = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.720, Rules used = {3042, 3062, 3042, 3063, 3042, 3063, 3042, 3065, 3042, 3054, 826, 1476, 1082, 217, 1479, 25, 27, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}}dx\)

\(\Big \downarrow \) 3062

\(\displaystyle \frac {\int \sqrt {b \sec (e+f x)} (a \sin (e+f x))^{9/2}dx}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \sqrt {b \sec (e+f x)} (a \sin (e+f x))^{9/2}dx}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 3063

\(\displaystyle \frac {\frac {7}{8} a^2 \int \sqrt {b \sec (e+f x)} (a \sin (e+f x))^{5/2}dx-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {7}{8} a^2 \int \sqrt {b \sec (e+f x)} (a \sin (e+f x))^{5/2}dx-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 3063

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3}{4} a^2 \int \sqrt {b \sec (e+f x)} \sqrt {a \sin (e+f x)}dx-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3}{4} a^2 \int \sqrt {b \sec (e+f x)} \sqrt {a \sin (e+f x)}dx-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 3065

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3}{4} a^2 \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \int \frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}dx-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3}{4} a^2 \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \int \frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}dx-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 3054

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3 a^3 b \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \int \frac {a \tan (e+f x)}{b \left (\tan ^2(e+f x) a^2+a^2\right )}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 f}-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 826

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3 a^3 b \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \left (\frac {\int \frac {\tan (e+f x) a+a}{\tan ^2(e+f x) a^2+a^2}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 b}-\frac {\int \frac {a-a \tan (e+f x)}{\tan ^2(e+f x) a^2+a^2}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 b}\right )}{2 f}-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 1476

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3 a^3 b \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \left (\frac {\frac {\int \frac {1}{\frac {\tan (e+f x) a}{b}+\frac {a}{b}-\frac {\sqrt {2} \sqrt {a \sin (e+f x)} \sqrt {a}}{\sqrt {b} \sqrt {b \cos (e+f x)}}}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 b}+\frac {\int \frac {1}{\frac {\tan (e+f x) a}{b}+\frac {a}{b}+\frac {\sqrt {2} \sqrt {a \sin (e+f x)} \sqrt {a}}{\sqrt {b} \sqrt {b \cos (e+f x)}}}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 b}}{2 b}-\frac {\int \frac {a-a \tan (e+f x)}{\tan ^2(e+f x) a^2+a^2}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 b}\right )}{2 f}-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 1082

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3 a^3 b \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \left (\frac {\frac {\int \frac {1}{-\frac {a \tan (e+f x)}{b}-1}d\left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}-\frac {\int \frac {1}{-\frac {a \tan (e+f x)}{b}-1}d\left (\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}+1\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}}{2 b}-\frac {\int \frac {a-a \tan (e+f x)}{\tan ^2(e+f x) a^2+a^2}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 b}\right )}{2 f}-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3 a^3 b \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}+1\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}}{2 b}-\frac {\int \frac {a-a \tan (e+f x)}{\tan ^2(e+f x) a^2+a^2}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 b}\right )}{2 f}-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 1479

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3 a^3 b \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}+1\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}}{2 b}-\frac {-\frac {\int -\frac {\sqrt {2} \sqrt {a}-\frac {2 \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{\sqrt {b} \left (\frac {\tan (e+f x) a}{b}+\frac {a}{b}-\frac {\sqrt {2} \sqrt {a \sin (e+f x)} \sqrt {a}}{\sqrt {b} \sqrt {b \cos (e+f x)}}\right )}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 \sqrt {2} \sqrt {a} \sqrt {b}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {a}+\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}\right )}{\sqrt {b} \left (\frac {\tan (e+f x) a}{b}+\frac {a}{b}+\frac {\sqrt {2} \sqrt {a \sin (e+f x)} \sqrt {a}}{\sqrt {b} \sqrt {b \cos (e+f x)}}\right )}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 \sqrt {2} \sqrt {a} \sqrt {b}}}{2 b}\right )}{2 f}-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3 a^3 b \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}+1\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}}{2 b}-\frac {\frac {\int \frac {\sqrt {2} \sqrt {a}-\frac {2 \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{\sqrt {b} \left (\frac {\tan (e+f x) a}{b}+\frac {a}{b}-\frac {\sqrt {2} \sqrt {a \sin (e+f x)} \sqrt {a}}{\sqrt {b} \sqrt {b \cos (e+f x)}}\right )}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 \sqrt {2} \sqrt {a} \sqrt {b}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {a}+\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}\right )}{\sqrt {b} \left (\frac {\tan (e+f x) a}{b}+\frac {a}{b}+\frac {\sqrt {2} \sqrt {a \sin (e+f x)} \sqrt {a}}{\sqrt {b} \sqrt {b \cos (e+f x)}}\right )}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 \sqrt {2} \sqrt {a} \sqrt {b}}}{2 b}\right )}{2 f}-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3 a^3 b \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}+1\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}}{2 b}-\frac {\frac {\int \frac {\sqrt {2} \sqrt {a}-\frac {2 \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{\frac {\tan (e+f x) a}{b}+\frac {a}{b}-\frac {\sqrt {2} \sqrt {a \sin (e+f x)} \sqrt {a}}{\sqrt {b} \sqrt {b \cos (e+f x)}}}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 \sqrt {2} \sqrt {a} b}+\frac {\int \frac {\sqrt {a}+\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{\frac {\tan (e+f x) a}{b}+\frac {a}{b}+\frac {\sqrt {2} \sqrt {a \sin (e+f x)} \sqrt {a}}{\sqrt {b} \sqrt {b \cos (e+f x)}}}d\frac {\sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}}{2 \sqrt {a} b}}{2 b}\right )}{2 f}-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {\frac {7}{8} a^2 \left (\frac {3 a^3 b \sqrt {b \cos (e+f x)} \sqrt {b \sec (e+f x)} \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}+1\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {a} \sqrt {b \cos (e+f x)}}\right )}{\sqrt {2} \sqrt {a} \sqrt {b}}}{2 b}-\frac {\frac {\log \left (\frac {\sqrt {2} \sqrt {a} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}+a \tan (e+f x)+a\right )}{2 \sqrt {2} \sqrt {a} \sqrt {b}}-\frac {\log \left (-\frac {\sqrt {2} \sqrt {a} \sqrt {b} \sqrt {a \sin (e+f x)}}{\sqrt {b \cos (e+f x)}}+a \tan (e+f x)+a\right )}{2 \sqrt {2} \sqrt {a} \sqrt {b}}}{2 b}\right )}{2 f}-\frac {a b (a \sin (e+f x))^{3/2}}{2 f \sqrt {b \sec (e+f x)}}\right )-\frac {a b (a \sin (e+f x))^{7/2}}{4 f \sqrt {b \sec (e+f x)}}}{12 b^2}+\frac {(a \sin (e+f x))^{11/2}}{6 a b f \sqrt {b \sec (e+f x)}}\)

Input:

Int[(a*Sin[e + f*x])^(9/2)/(b*Sec[e + f*x])^(3/2),x]
 

Output:

(a*Sin[e + f*x])^(11/2)/(6*a*b*f*Sqrt[b*Sec[e + f*x]]) + (-1/4*(a*b*(a*Sin 
[e + f*x])^(7/2))/(f*Sqrt[b*Sec[e + f*x]]) + (7*a^2*((3*a^3*b*Sqrt[b*Cos[e 
 + f*x]]*((-(ArcTan[1 - (Sqrt[2]*Sqrt[b]*Sqrt[a*Sin[e + f*x]])/(Sqrt[a]*Sq 
rt[b*Cos[e + f*x]])]/(Sqrt[2]*Sqrt[a]*Sqrt[b])) + ArcTan[1 + (Sqrt[2]*Sqrt 
[b]*Sqrt[a*Sin[e + f*x]])/(Sqrt[a]*Sqrt[b*Cos[e + f*x]])]/(Sqrt[2]*Sqrt[a] 
*Sqrt[b]))/(2*b) - (-1/2*Log[a - (Sqrt[2]*Sqrt[a]*Sqrt[b]*Sqrt[a*Sin[e + f 
*x]])/Sqrt[b*Cos[e + f*x]] + a*Tan[e + f*x]]/(Sqrt[2]*Sqrt[a]*Sqrt[b]) + L 
og[a + (Sqrt[2]*Sqrt[a]*Sqrt[b]*Sqrt[a*Sin[e + f*x]])/Sqrt[b*Cos[e + f*x]] 
 + a*Tan[e + f*x]]/(2*Sqrt[2]*Sqrt[a]*Sqrt[b]))/(2*b))*Sqrt[b*Sec[e + f*x] 
])/(2*f) - (a*b*(a*Sin[e + f*x])^(3/2))/(2*f*Sqrt[b*Sec[e + f*x]])))/8)/(1 
2*b^2)
 

Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 826
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 
2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s)   Int[(r + s*x^2)/(a + b*x^ 
4), x], x] - Simp[1/(2*s)   Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ 
a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] 
 && AtomQ[SplitProduct[SumBaseQ, b]]))
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3054
Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> With[{k = Denominator[m]}, Simp[k*a*(b/f)   Subst[Int[x^(k 
*(m + 1) - 1)/(a^2 + b^2*x^(2*k)), x], x, (a*Sin[e + f*x])^(1/k)/(b*Cos[e + 
 f*x])^(1/k)], x]] /; FreeQ[{a, b, e, f}, x] && EqQ[m + n, 0] && GtQ[m, 0] 
&& LtQ[m, 1]
 

rule 3062
Int[((b_.)*sec[(e_.) + (f_.)*(x_)])^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> Simp[(a*Sin[e + f*x])^(m + 1)*((b*Sec[e + f*x])^(n + 1)/(a 
*b*f*(m - n))), x] - Simp[(n + 1)/(b^2*(m - n))   Int[(a*Sin[e + f*x])^m*(b 
*Sec[e + f*x])^(n + 2), x], x] /; FreeQ[{a, b, e, f, m}, x] && LtQ[n, -1] & 
& NeQ[m - n, 0] && IntegersQ[2*m, 2*n]
 

rule 3063
Int[((b_.)*sec[(e_.) + (f_.)*(x_)])^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> Simp[(-a)*b*(a*Sin[e + f*x])^(m - 1)*((b*Sec[e + f*x])^(n 
- 1)/(f*(m - n))), x] + Simp[a^2*((m - 1)/(m - n))   Int[(a*Sin[e + f*x])^( 
m - 2)*(b*Sec[e + f*x])^n, x], x] /; FreeQ[{a, b, e, f, n}, x] && GtQ[m, 1] 
 && NeQ[m - n, 0] && IntegersQ[2*m, 2*n]
 

rule 3065
Int[((b_.)*sec[(e_.) + (f_.)*(x_)])^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> Simp[(b*Cos[e + f*x])^n*(b*Sec[e + f*x])^n   Int[(a*Sin[e 
+ f*x])^m/(b*Cos[e + f*x])^n, x], x] /; FreeQ[{a, b, e, f, m, n}, x] && Int 
egerQ[m - 1/2] && IntegerQ[n - 1/2]
 
Maple [A] (verified)

Time = 1.22 (sec) , antiderivative size = 449, normalized size of antiderivative = 1.15

method result size
default \(\frac {\sqrt {2}\, a^{4} \left (21 \ln \left (-2 \sqrt {-\frac {2 \sin \left (f x +e \right ) \cos \left (f x +e \right )}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \cot \left (f x +e \right )+2-2 \sqrt {-\frac {2 \sin \left (f x +e \right ) \cos \left (f x +e \right )}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \csc \left (f x +e \right )-2 \cot \left (f x +e \right )\right )-21 \ln \left (2 \sqrt {-\frac {2 \sin \left (f x +e \right ) \cos \left (f x +e \right )}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \cot \left (f x +e \right )+2 \sqrt {-\frac {2 \sin \left (f x +e \right ) \cos \left (f x +e \right )}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \csc \left (f x +e \right )-2 \cot \left (f x +e \right )+2\right )-42 \arctan \left (\frac {-\sqrt {-\frac {2 \sin \left (f x +e \right ) \cos \left (f x +e \right )}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \sin \left (f x +e \right )+\cos \left (f x +e \right )-1}{-1+\cos \left (f x +e \right )}\right )+42 \arctan \left (\frac {\sqrt {-\frac {2 \sin \left (f x +e \right ) \cos \left (f x +e \right )}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \sin \left (f x +e \right )+\cos \left (f x +e \right )-1}{-1+\cos \left (f x +e \right )}\right )+4 \left (21+32 \cos \left (f x +e \right )^{5}+32 \cos \left (f x +e \right )^{4}-60 \cos \left (f x +e \right )^{3}-60 \cos \left (f x +e \right )^{2}+21 \cos \left (f x +e \right )\right ) \sin \left (f x +e \right ) \sqrt {-\frac {2 \sin \left (f x +e \right ) \cos \left (f x +e \right )}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\right ) \sqrt {a \sin \left (f x +e \right )}\, \sin \left (f x +e \right )^{9} \sec \left (\frac {f x}{2}+\frac {e}{2}\right )^{11} \csc \left (\frac {f x}{2}+\frac {e}{2}\right )^{9}}{1572864 f b \sqrt {-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{\left (\cos \left (f x +e \right )+1\right )^{2}}}\, \sqrt {b \sec \left (f x +e \right )}}\) \(449\)

Input:

int((a*sin(f*x+e))^(9/2)/(b*sec(f*x+e))^(3/2),x,method=_RETURNVERBOSE)
 

Output:

1/1572864/f*2^(1/2)*a^4/b*(21*ln(-2*(-2*sin(f*x+e)*cos(f*x+e)/(cos(f*x+e)+ 
1)^2)^(1/2)*cot(f*x+e)+2-2*(-2*sin(f*x+e)*cos(f*x+e)/(cos(f*x+e)+1)^2)^(1/ 
2)*csc(f*x+e)-2*cot(f*x+e))-21*ln(2*(-2*sin(f*x+e)*cos(f*x+e)/(cos(f*x+e)+ 
1)^2)^(1/2)*cot(f*x+e)+2*(-2*sin(f*x+e)*cos(f*x+e)/(cos(f*x+e)+1)^2)^(1/2) 
*csc(f*x+e)-2*cot(f*x+e)+2)-42*arctan((-(-2*sin(f*x+e)*cos(f*x+e)/(cos(f*x 
+e)+1)^2)^(1/2)*sin(f*x+e)+cos(f*x+e)-1)/(-1+cos(f*x+e)))+42*arctan(((-2*s 
in(f*x+e)*cos(f*x+e)/(cos(f*x+e)+1)^2)^(1/2)*sin(f*x+e)+cos(f*x+e)-1)/(-1+ 
cos(f*x+e)))+4*(21+32*cos(f*x+e)^5+32*cos(f*x+e)^4-60*cos(f*x+e)^3-60*cos( 
f*x+e)^2+21*cos(f*x+e))*sin(f*x+e)*(-2*sin(f*x+e)*cos(f*x+e)/(cos(f*x+e)+1 
)^2)^(1/2))*(a*sin(f*x+e))^(1/2)*sin(f*x+e)^9/(-sin(f*x+e)*cos(f*x+e)/(cos 
(f*x+e)+1)^2)^(1/2)/(b*sec(f*x+e))^(1/2)*sec(1/2*f*x+1/2*e)^11*csc(1/2*f*x 
+1/2*e)^9
 

Fricas [A] (verification not implemented)

Time = 0.20 (sec) , antiderivative size = 559, normalized size of antiderivative = 1.43 \[ \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx=-\frac {42 \, \sqrt {2} a^{4} b \sqrt {\frac {a}{b}} \arctan \left (-\frac {\sqrt {2} \sqrt {a \sin \left (f x + e\right )} \sqrt {\frac {a}{b}} \sqrt {\frac {b}{\cos \left (f x + e\right )}} \cos \left (f x + e\right )}{a \cos \left (f x + e\right ) - a \sin \left (f x + e\right )}\right ) + 21 \, \sqrt {2} a^{4} b \sqrt {\frac {a}{b}} \arctan \left (\frac {2 \, a \cos \left (f x + e\right )^{2} - 2 \, a \cos \left (f x + e\right ) \sin \left (f x + e\right ) + \sqrt {2} \sqrt {a \sin \left (f x + e\right )} \sqrt {\frac {a}{b}} \sqrt {\frac {b}{\cos \left (f x + e\right )}} - 2 \, a}{2 \, {\left (a \cos \left (f x + e\right )^{2} + a \cos \left (f x + e\right ) \sin \left (f x + e\right ) - a\right )}}\right ) + 21 \, \sqrt {2} a^{4} b \sqrt {\frac {a}{b}} \arctan \left (-\frac {2 \, a \cos \left (f x + e\right )^{2} - 2 \, a \cos \left (f x + e\right ) \sin \left (f x + e\right ) - \sqrt {2} \sqrt {a \sin \left (f x + e\right )} \sqrt {\frac {a}{b}} \sqrt {\frac {b}{\cos \left (f x + e\right )}} - 2 \, a}{2 \, {\left (a \cos \left (f x + e\right )^{2} + a \cos \left (f x + e\right ) \sin \left (f x + e\right ) - a\right )}}\right ) + 21 \, \sqrt {2} a^{4} b \sqrt {\frac {a}{b}} \log \left (2 \, \sqrt {2} {\left (\cos \left (f x + e\right )^{2} + \cos \left (f x + e\right ) \sin \left (f x + e\right )\right )} \sqrt {a \sin \left (f x + e\right )} \sqrt {\frac {a}{b}} \sqrt {\frac {b}{\cos \left (f x + e\right )}} + 4 \, a \cos \left (f x + e\right ) \sin \left (f x + e\right ) + a\right ) - 21 \, \sqrt {2} a^{4} b \sqrt {\frac {a}{b}} \log \left (-2 \, \sqrt {2} {\left (\cos \left (f x + e\right )^{2} + \cos \left (f x + e\right ) \sin \left (f x + e\right )\right )} \sqrt {a \sin \left (f x + e\right )} \sqrt {\frac {a}{b}} \sqrt {\frac {b}{\cos \left (f x + e\right )}} + 4 \, a \cos \left (f x + e\right ) \sin \left (f x + e\right ) + a\right ) - 16 \, {\left (32 \, a^{4} \cos \left (f x + e\right )^{5} - 60 \, a^{4} \cos \left (f x + e\right )^{3} + 21 \, a^{4} \cos \left (f x + e\right )\right )} \sqrt {a \sin \left (f x + e\right )} \sqrt {\frac {b}{\cos \left (f x + e\right )}} \sin \left (f x + e\right )}{3072 \, b^{2} f} \] Input:

integrate((a*sin(f*x+e))^(9/2)/(b*sec(f*x+e))^(3/2),x, algorithm="fricas")
 

Output:

-1/3072*(42*sqrt(2)*a^4*b*sqrt(a/b)*arctan(-sqrt(2)*sqrt(a*sin(f*x + e))*s 
qrt(a/b)*sqrt(b/cos(f*x + e))*cos(f*x + e)/(a*cos(f*x + e) - a*sin(f*x + e 
))) + 21*sqrt(2)*a^4*b*sqrt(a/b)*arctan(1/2*(2*a*cos(f*x + e)^2 - 2*a*cos( 
f*x + e)*sin(f*x + e) + sqrt(2)*sqrt(a*sin(f*x + e))*sqrt(a/b)*sqrt(b/cos( 
f*x + e)) - 2*a)/(a*cos(f*x + e)^2 + a*cos(f*x + e)*sin(f*x + e) - a)) + 2 
1*sqrt(2)*a^4*b*sqrt(a/b)*arctan(-1/2*(2*a*cos(f*x + e)^2 - 2*a*cos(f*x + 
e)*sin(f*x + e) - sqrt(2)*sqrt(a*sin(f*x + e))*sqrt(a/b)*sqrt(b/cos(f*x + 
e)) - 2*a)/(a*cos(f*x + e)^2 + a*cos(f*x + e)*sin(f*x + e) - a)) + 21*sqrt 
(2)*a^4*b*sqrt(a/b)*log(2*sqrt(2)*(cos(f*x + e)^2 + cos(f*x + e)*sin(f*x + 
 e))*sqrt(a*sin(f*x + e))*sqrt(a/b)*sqrt(b/cos(f*x + e)) + 4*a*cos(f*x + e 
)*sin(f*x + e) + a) - 21*sqrt(2)*a^4*b*sqrt(a/b)*log(-2*sqrt(2)*(cos(f*x + 
 e)^2 + cos(f*x + e)*sin(f*x + e))*sqrt(a*sin(f*x + e))*sqrt(a/b)*sqrt(b/c 
os(f*x + e)) + 4*a*cos(f*x + e)*sin(f*x + e) + a) - 16*(32*a^4*cos(f*x + e 
)^5 - 60*a^4*cos(f*x + e)^3 + 21*a^4*cos(f*x + e))*sqrt(a*sin(f*x + e))*sq 
rt(b/cos(f*x + e))*sin(f*x + e))/(b^2*f)
 

Sympy [F(-1)]

Timed out. \[ \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx=\text {Timed out} \] Input:

integrate((a*sin(f*x+e))**(9/2)/(b*sec(f*x+e))**(3/2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx=\int { \frac {\left (a \sin \left (f x + e\right )\right )^{\frac {9}{2}}}{\left (b \sec \left (f x + e\right )\right )^{\frac {3}{2}}} \,d x } \] Input:

integrate((a*sin(f*x+e))^(9/2)/(b*sec(f*x+e))^(3/2),x, algorithm="maxima")
 

Output:

integrate((a*sin(f*x + e))^(9/2)/(b*sec(f*x + e))^(3/2), x)
 

Giac [F]

\[ \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx=\int { \frac {\left (a \sin \left (f x + e\right )\right )^{\frac {9}{2}}}{\left (b \sec \left (f x + e\right )\right )^{\frac {3}{2}}} \,d x } \] Input:

integrate((a*sin(f*x+e))^(9/2)/(b*sec(f*x+e))^(3/2),x, algorithm="giac")
 

Output:

integrate((a*sin(f*x + e))^(9/2)/(b*sec(f*x + e))^(3/2), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx=\int \frac {{\left (a\,\sin \left (e+f\,x\right )\right )}^{9/2}}{{\left (\frac {b}{\cos \left (e+f\,x\right )}\right )}^{3/2}} \,d x \] Input:

int((a*sin(e + f*x))^(9/2)/(b/cos(e + f*x))^(3/2),x)
 

Output:

int((a*sin(e + f*x))^(9/2)/(b/cos(e + f*x))^(3/2), x)
 

Reduce [F]

\[ \int \frac {(a \sin (e+f x))^{9/2}}{(b \sec (e+f x))^{3/2}} \, dx=\frac {\sqrt {b}\, \sqrt {a}\, \left (\int \frac {\sqrt {\sin \left (f x +e \right )}\, \sqrt {\sec \left (f x +e \right )}\, \sin \left (f x +e \right )^{4}}{\sec \left (f x +e \right )^{2}}d x \right ) a^{4}}{b^{2}} \] Input:

int((a*sin(f*x+e))^(9/2)/(b*sec(f*x+e))^(3/2),x)
                                                                                    
                                                                                    
 

Output:

(sqrt(b)*sqrt(a)*int((sqrt(sin(e + f*x))*sqrt(sec(e + f*x))*sin(e + f*x)** 
4)/sec(e + f*x)**2,x)*a**4)/b**2