Integrand size = 21, antiderivative size = 192 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac {\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac {2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}+\frac {2 a \left (8 a^2-3 b^2\right ) \tan (c+d x)}{21 d}+\frac {4 a \left (8 a^2-3 b^2\right ) \tan ^3(c+d x)}{63 d}+\frac {2 a \left (8 a^2-3 b^2\right ) \tan ^5(c+d x)}{105 d} \] Output:
2/63*b*(4*a^2-b^2)*sec(d*x+c)^5/d+1/9*sec(d*x+c)^9*(b+a*sin(d*x+c))*(a+b*s in(d*x+c))^2/d+2/63*sec(d*x+c)^7*(a+b*sin(d*x+c))*(3*a*b+(4*a^2-b^2)*sin(d *x+c))/d+2/21*a*(8*a^2-3*b^2)*tan(d*x+c)/d+4/63*a*(8*a^2-3*b^2)*tan(d*x+c) ^3/d+2/105*a*(8*a^2-3*b^2)*tan(d*x+c)^5/d
Time = 5.43 (sec) , antiderivative size = 299, normalized size of antiderivative = 1.56 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {\sec ^9(c+d x) \left (3440640 a^2 b+409600 b^3+3150 b \left (-147 a^2+23 b^2\right ) \cos (c+d x)-737280 b^3 \cos (2 (c+d x))-308700 a^2 b \cos (3 (c+d x))+48300 b^3 \cos (3 (c+d x))-132300 a^2 b \cos (5 (c+d x))+20700 b^3 \cos (5 (c+d x))-33075 a^2 b \cos (7 (c+d x))+5175 b^3 \cos (7 (c+d x))-3675 a^2 b \cos (9 (c+d x))+575 b^3 \cos (9 (c+d x))+2064384 a^3 \sin (c+d x)+3096576 a b^2 \sin (c+d x)+1376256 a^3 \sin (3 (c+d x))-516096 a b^2 \sin (3 (c+d x))+589824 a^3 \sin (5 (c+d x))-221184 a b^2 \sin (5 (c+d x))+147456 a^3 \sin (7 (c+d x))-55296 a b^2 \sin (7 (c+d x))+16384 a^3 \sin (9 (c+d x))-6144 a b^2 \sin (9 (c+d x))\right )}{10321920 d} \] Input:
Integrate[Sec[c + d*x]^10*(a + b*Sin[c + d*x])^3,x]
Output:
(Sec[c + d*x]^9*(3440640*a^2*b + 409600*b^3 + 3150*b*(-147*a^2 + 23*b^2)*C os[c + d*x] - 737280*b^3*Cos[2*(c + d*x)] - 308700*a^2*b*Cos[3*(c + d*x)] + 48300*b^3*Cos[3*(c + d*x)] - 132300*a^2*b*Cos[5*(c + d*x)] + 20700*b^3*C os[5*(c + d*x)] - 33075*a^2*b*Cos[7*(c + d*x)] + 5175*b^3*Cos[7*(c + d*x)] - 3675*a^2*b*Cos[9*(c + d*x)] + 575*b^3*Cos[9*(c + d*x)] + 2064384*a^3*Si n[c + d*x] + 3096576*a*b^2*Sin[c + d*x] + 1376256*a^3*Sin[3*(c + d*x)] - 5 16096*a*b^2*Sin[3*(c + d*x)] + 589824*a^3*Sin[5*(c + d*x)] - 221184*a*b^2* Sin[5*(c + d*x)] + 147456*a^3*Sin[7*(c + d*x)] - 55296*a*b^2*Sin[7*(c + d* x)] + 16384*a^3*Sin[9*(c + d*x)] - 6144*a*b^2*Sin[9*(c + d*x)]))/(10321920 *d)
Time = 0.76 (sec) , antiderivative size = 170, normalized size of antiderivative = 0.89, number of steps used = 12, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.524, Rules used = {3042, 3170, 27, 3042, 3340, 25, 3042, 3148, 3042, 4254, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {(a+b \sin (c+d x))^3}{\cos (c+d x)^{10}}dx\) |
| \(\Big \downarrow \) 3170 |
| \(\displaystyle \frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}-\frac {1}{9} \int -2 \sec ^8(c+d x) (a+b \sin (c+d x)) \left (4 a^2+3 b \sin (c+d x) a-b^2\right )dx\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {2}{9} \int \sec ^8(c+d x) (a+b \sin (c+d x)) \left (4 a^2+3 b \sin (c+d x) a-b^2\right )dx+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {2}{9} \int \frac {(a+b \sin (c+d x)) \left (4 a^2+3 b \sin (c+d x) a-b^2\right )}{\cos (c+d x)^8}dx+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}\) |
| \(\Big \downarrow \) 3340 |
| \(\displaystyle \frac {2}{9} \left (\frac {\sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{7 d}-\frac {1}{7} \int -\sec ^6(c+d x) \left (3 a \left (8 a^2-3 b^2\right )+5 b \left (4 a^2-b^2\right ) \sin (c+d x)\right )dx\right )+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \frac {2}{9} \left (\frac {1}{7} \int \sec ^6(c+d x) \left (3 a \left (8 a^2-3 b^2\right )+5 b \left (4 a^2-b^2\right ) \sin (c+d x)\right )dx+\frac {\sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{7 d}\right )+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {2}{9} \left (\frac {1}{7} \int \frac {3 a \left (8 a^2-3 b^2\right )+5 b \left (4 a^2-b^2\right ) \sin (c+d x)}{\cos (c+d x)^6}dx+\frac {\sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{7 d}\right )+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}\) |
| \(\Big \downarrow \) 3148 |
| \(\displaystyle \frac {2}{9} \left (\frac {1}{7} \left (3 a \left (8 a^2-3 b^2\right ) \int \sec ^6(c+d x)dx+\frac {b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{d}\right )+\frac {\sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{7 d}\right )+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {2}{9} \left (\frac {1}{7} \left (3 a \left (8 a^2-3 b^2\right ) \int \csc \left (c+d x+\frac {\pi }{2}\right )^6dx+\frac {b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{d}\right )+\frac {\sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{7 d}\right )+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}\) |
| \(\Big \downarrow \) 4254 |
| \(\displaystyle \frac {2}{9} \left (\frac {1}{7} \left (\frac {b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{d}-\frac {3 a \left (8 a^2-3 b^2\right ) \int \left (\tan ^4(c+d x)+2 \tan ^2(c+d x)+1\right )d(-\tan (c+d x))}{d}\right )+\frac {\sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{7 d}\right )+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle \frac {2}{9} \left (\frac {\sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{7 d}+\frac {1}{7} \left (\frac {b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{d}-\frac {3 a \left (8 a^2-3 b^2\right ) \left (-\frac {1}{5} \tan ^5(c+d x)-\frac {2}{3} \tan ^3(c+d x)-\tan (c+d x)\right )}{d}\right )\right )+\frac {\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d}\) |
Input:
Int[Sec[c + d*x]^10*(a + b*Sin[c + d*x])^3,x]
Output:
(Sec[c + d*x]^9*(b + a*Sin[c + d*x])*(a + b*Sin[c + d*x])^2)/(9*d) + (2*(( Sec[c + d*x]^7*(a + b*Sin[c + d*x])*(3*a*b + (4*a^2 - b^2)*Sin[c + d*x]))/ (7*d) + ((b*(4*a^2 - b^2)*Sec[c + d*x]^5)/d - (3*a*(8*a^2 - 3*b^2)*(-Tan[c + d*x] - (2*Tan[c + d*x]^3)/3 - Tan[c + d*x]^5/5))/d)/7))/9
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)]), x_Symbol] :> Simp[(-b)*((g*Cos[e + f*x])^(p + 1)/(f*g*(p + 1))), x] + Simp[a Int[(g*Cos[e + f*x])^p, x], x] /; FreeQ[{a, b, e, f, g, p}, x] && (IntegerQ[2*p] || NeQ[a^2 - b^2, 0])
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[(-(g*Cos[e + f*x])^(p + 1))*(a + b*Sin[e + f*x ])^(m - 1)*((b + a*Sin[e + f*x])/(f*g*(p + 1))), x] + Simp[1/(g^2*(p + 1)) Int[(g*Cos[e + f*x])^(p + 2)*(a + b*Sin[e + f*x])^(m - 2)*(b^2*(m - 1) + a^2*(p + 2) + a*b*(m + p + 1)*Sin[e + f*x]), x], x] /; FreeQ[{a, b, e, f, g }, x] && NeQ[a^2 - b^2, 0] && GtQ[m, 1] && LtQ[p, -1] && (IntegersQ[2*m, 2* p] || IntegerQ[m])
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-(g* Cos[e + f*x])^(p + 1))*(a + b*Sin[e + f*x])^m*((d + c*Sin[e + f*x])/(f*g*(p + 1))), x] + Simp[1/(g^2*(p + 1)) Int[(g*Cos[e + f*x])^(p + 2)*(a + b*Si n[e + f*x])^(m - 1)*Simp[a*c*(p + 2) + b*d*m + b*c*(m + p + 2)*Sin[e + f*x] , x], x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[a^2 - b^2, 0] && GtQ [m, 0] && LtQ[p, -1] && IntegerQ[2*m] && !(EqQ[m, 1] && NeQ[c^2 - d^2, 0] && SimplerQ[c + d*x, a + b*x])
Int[csc[(c_.) + (d_.)*(x_)]^(n_), x_Symbol] :> Simp[-d^(-1) Subst[Int[Exp andIntegrand[(1 + x^2)^(n/2 - 1), x], x], x, Cot[c + d*x]], x] /; FreeQ[{c, d}, x] && IGtQ[n/2, 0]
Result contains complex when optimal does not.
Time = 1.03 (sec) , antiderivative size = 230, normalized size of antiderivative = 1.20
| method | result | size |
| risch | \(-\frac {32 \left (945 i a \,b^{2} {\mathrm e}^{10 i \left (d x +c \right )}+180 b^{3} {\mathrm e}^{11 i \left (d x +c \right )}-1008 i a^{3} {\mathrm e}^{8 i \left (d x +c \right )}-567 i a \,b^{2} {\mathrm e}^{8 i \left (d x +c \right )}-1680 a^{2} b \,{\mathrm e}^{9 i \left (d x +c \right )}-200 b^{3} {\mathrm e}^{9 i \left (d x +c \right )}-672 i a^{3} {\mathrm e}^{6 i \left (d x +c \right )}+252 i a \,b^{2} {\mathrm e}^{6 i \left (d x +c \right )}+180 b^{3} {\mathrm e}^{7 i \left (d x +c \right )}-288 i a^{3} {\mathrm e}^{4 i \left (d x +c \right )}+108 i a \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-72 i a^{3} {\mathrm e}^{2 i \left (d x +c \right )}+27 i a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-8 i a^{3}+3 i a \,b^{2}\right )}{315 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{9}}\) | \(230\) |
| derivativedivides | \(\frac {-a^{3} \left (-\frac {128}{315}-\frac {\sec \left (d x +c \right )^{8}}{9}-\frac {8 \sec \left (d x +c \right )^{6}}{63}-\frac {16 \sec \left (d x +c \right )^{4}}{105}-\frac {64 \sec \left (d x +c \right )^{2}}{315}\right ) \tan \left (d x +c \right )+\frac {a^{2} b}{3 \cos \left (d x +c \right )^{9}}+3 a \,b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{9 \cos \left (d x +c \right )^{9}}+\frac {2 \sin \left (d x +c \right )^{3}}{21 \cos \left (d x +c \right )^{7}}+\frac {8 \sin \left (d x +c \right )^{3}}{105 \cos \left (d x +c \right )^{5}}+\frac {16 \sin \left (d x +c \right )^{3}}{315 \cos \left (d x +c \right )^{3}}\right )+b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{9 \cos \left (d x +c \right )^{9}}+\frac {5 \sin \left (d x +c \right )^{4}}{63 \cos \left (d x +c \right )^{7}}+\frac {\sin \left (d x +c \right )^{4}}{21 \cos \left (d x +c \right )^{5}}+\frac {\sin \left (d x +c \right )^{4}}{63 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{4}}{63 \cos \left (d x +c \right )}-\frac {\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )}{63}\right )}{d}\) | \(265\) |
| default | \(\frac {-a^{3} \left (-\frac {128}{315}-\frac {\sec \left (d x +c \right )^{8}}{9}-\frac {8 \sec \left (d x +c \right )^{6}}{63}-\frac {16 \sec \left (d x +c \right )^{4}}{105}-\frac {64 \sec \left (d x +c \right )^{2}}{315}\right ) \tan \left (d x +c \right )+\frac {a^{2} b}{3 \cos \left (d x +c \right )^{9}}+3 a \,b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{9 \cos \left (d x +c \right )^{9}}+\frac {2 \sin \left (d x +c \right )^{3}}{21 \cos \left (d x +c \right )^{7}}+\frac {8 \sin \left (d x +c \right )^{3}}{105 \cos \left (d x +c \right )^{5}}+\frac {16 \sin \left (d x +c \right )^{3}}{315 \cos \left (d x +c \right )^{3}}\right )+b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{9 \cos \left (d x +c \right )^{9}}+\frac {5 \sin \left (d x +c \right )^{4}}{63 \cos \left (d x +c \right )^{7}}+\frac {\sin \left (d x +c \right )^{4}}{21 \cos \left (d x +c \right )^{5}}+\frac {\sin \left (d x +c \right )^{4}}{63 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{4}}{63 \cos \left (d x +c \right )}-\frac {\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )}{63}\right )}{d}\) | \(265\) |
| parallelrisch | \(-\frac {2 \left (3780 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} a^{2} b -10 b^{3}+105 a^{2} b +13230 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8} a^{2} b +315 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{17}-840 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{15} a^{3}+630 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{14} b^{3}+1050 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{12} b^{3}+4788 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{13}-5112 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{11} a^{3}+3150 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{10} b^{3}+1890 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8} b^{3}+1260 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3} a \,b^{2}+4788 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}+1890 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6} b^{3}+90 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} b^{3}+4272 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9} a \,b^{2}+8532 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7} a \,b^{2}+1512 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5} a \,b^{2}+315 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3}+8820 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{12} a^{2} b +8532 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{11} a \,b^{2}-840 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3} a^{3}+10658 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}-5112 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7} a^{3}+270 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} b^{3}+945 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{16} a^{2} b +1260 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{15} a \,b^{2}+1512 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{13} a \,b^{2}\right )}{315 d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{9}}\) | \(474\) |
Input:
int(sec(d*x+c)^10*(a+b*sin(d*x+c))^3,x,method=_RETURNVERBOSE)
Output:
-32/315*(945*I*a*b^2*exp(10*I*(d*x+c))+180*b^3*exp(11*I*(d*x+c))-1008*I*a^ 3*exp(8*I*(d*x+c))-567*I*a*b^2*exp(8*I*(d*x+c))-1680*a^2*b*exp(9*I*(d*x+c) )-200*b^3*exp(9*I*(d*x+c))-672*I*a^3*exp(6*I*(d*x+c))+252*I*a*b^2*exp(6*I* (d*x+c))+180*b^3*exp(7*I*(d*x+c))-288*I*a^3*exp(4*I*(d*x+c))+108*I*a*b^2*e xp(4*I*(d*x+c))-72*I*a^3*exp(2*I*(d*x+c))+27*I*a*b^2*exp(2*I*(d*x+c))-8*I* a^3+3*I*a*b^2)/d/(exp(2*I*(d*x+c))+1)^9
Time = 0.11 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.76 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=-\frac {45 \, b^{3} \cos \left (d x + c\right )^{2} - 105 \, a^{2} b - 35 \, b^{3} - {\left (16 \, {\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{8} + 8 \, {\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{6} + 6 \, {\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{4} + 35 \, a^{3} + 105 \, a b^{2} + 5 \, {\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{315 \, d \cos \left (d x + c\right )^{9}} \] Input:
integrate(sec(d*x+c)^10*(a+b*sin(d*x+c))^3,x, algorithm="fricas")
Output:
-1/315*(45*b^3*cos(d*x + c)^2 - 105*a^2*b - 35*b^3 - (16*(8*a^3 - 3*a*b^2) *cos(d*x + c)^8 + 8*(8*a^3 - 3*a*b^2)*cos(d*x + c)^6 + 6*(8*a^3 - 3*a*b^2) *cos(d*x + c)^4 + 35*a^3 + 105*a*b^2 + 5*(8*a^3 - 3*a*b^2)*cos(d*x + c)^2) *sin(d*x + c))/(d*cos(d*x + c)^9)
Timed out. \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\text {Timed out} \] Input:
integrate(sec(d*x+c)**10*(a+b*sin(d*x+c))**3,x)
Output:
Timed out
Time = 0.04 (sec) , antiderivative size = 145, normalized size of antiderivative = 0.76 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {{\left (35 \, \tan \left (d x + c\right )^{9} + 180 \, \tan \left (d x + c\right )^{7} + 378 \, \tan \left (d x + c\right )^{5} + 420 \, \tan \left (d x + c\right )^{3} + 315 \, \tan \left (d x + c\right )\right )} a^{3} + 3 \, {\left (35 \, \tan \left (d x + c\right )^{9} + 135 \, \tan \left (d x + c\right )^{7} + 189 \, \tan \left (d x + c\right )^{5} + 105 \, \tan \left (d x + c\right )^{3}\right )} a b^{2} - \frac {5 \, {\left (9 \, \cos \left (d x + c\right )^{2} - 7\right )} b^{3}}{\cos \left (d x + c\right )^{9}} + \frac {105 \, a^{2} b}{\cos \left (d x + c\right )^{9}}}{315 \, d} \] Input:
integrate(sec(d*x+c)^10*(a+b*sin(d*x+c))^3,x, algorithm="maxima")
Output:
1/315*((35*tan(d*x + c)^9 + 180*tan(d*x + c)^7 + 378*tan(d*x + c)^5 + 420* tan(d*x + c)^3 + 315*tan(d*x + c))*a^3 + 3*(35*tan(d*x + c)^9 + 135*tan(d* x + c)^7 + 189*tan(d*x + c)^5 + 105*tan(d*x + c)^3)*a*b^2 - 5*(9*cos(d*x + c)^2 - 7)*b^3/cos(d*x + c)^9 + 105*a^2*b/cos(d*x + c)^9)/d
Leaf count of result is larger than twice the leaf count of optimal. 473 vs. \(2 (180) = 360\).
Time = 0.17 (sec) , antiderivative size = 473, normalized size of antiderivative = 2.46 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx =\text {Too large to display} \] Input:
integrate(sec(d*x+c)^10*(a+b*sin(d*x+c))^3,x, algorithm="giac")
Output:
-2/315*(315*a^3*tan(1/2*d*x + 1/2*c)^17 + 945*a^2*b*tan(1/2*d*x + 1/2*c)^1 6 - 840*a^3*tan(1/2*d*x + 1/2*c)^15 + 1260*a*b^2*tan(1/2*d*x + 1/2*c)^15 + 630*b^3*tan(1/2*d*x + 1/2*c)^14 + 4788*a^3*tan(1/2*d*x + 1/2*c)^13 + 1512 *a*b^2*tan(1/2*d*x + 1/2*c)^13 + 8820*a^2*b*tan(1/2*d*x + 1/2*c)^12 + 1050 *b^3*tan(1/2*d*x + 1/2*c)^12 - 5112*a^3*tan(1/2*d*x + 1/2*c)^11 + 8532*a*b ^2*tan(1/2*d*x + 1/2*c)^11 + 3150*b^3*tan(1/2*d*x + 1/2*c)^10 + 10658*a^3* tan(1/2*d*x + 1/2*c)^9 + 4272*a*b^2*tan(1/2*d*x + 1/2*c)^9 + 13230*a^2*b*t an(1/2*d*x + 1/2*c)^8 + 1890*b^3*tan(1/2*d*x + 1/2*c)^8 - 5112*a^3*tan(1/2 *d*x + 1/2*c)^7 + 8532*a*b^2*tan(1/2*d*x + 1/2*c)^7 + 1890*b^3*tan(1/2*d*x + 1/2*c)^6 + 4788*a^3*tan(1/2*d*x + 1/2*c)^5 + 1512*a*b^2*tan(1/2*d*x + 1 /2*c)^5 + 3780*a^2*b*tan(1/2*d*x + 1/2*c)^4 + 270*b^3*tan(1/2*d*x + 1/2*c) ^4 - 840*a^3*tan(1/2*d*x + 1/2*c)^3 + 1260*a*b^2*tan(1/2*d*x + 1/2*c)^3 + 90*b^3*tan(1/2*d*x + 1/2*c)^2 + 315*a^3*tan(1/2*d*x + 1/2*c) + 105*a^2*b - 10*b^3)/((tan(1/2*d*x + 1/2*c)^2 - 1)^9*d)
Time = 16.56 (sec) , antiderivative size = 275, normalized size of antiderivative = 1.43 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {b^3}{9\,d\,{\cos \left (c+d\,x\right )}^9}-\frac {b^3}{7\,d\,{\cos \left (c+d\,x\right )}^7}+\frac {a^2\,b}{3\,d\,{\cos \left (c+d\,x\right )}^9}+\frac {128\,a^3\,\sin \left (c+d\,x\right )}{315\,d\,\cos \left (c+d\,x\right )}+\frac {64\,a^3\,\sin \left (c+d\,x\right )}{315\,d\,{\cos \left (c+d\,x\right )}^3}+\frac {16\,a^3\,\sin \left (c+d\,x\right )}{105\,d\,{\cos \left (c+d\,x\right )}^5}+\frac {8\,a^3\,\sin \left (c+d\,x\right )}{63\,d\,{\cos \left (c+d\,x\right )}^7}+\frac {a^3\,\sin \left (c+d\,x\right )}{9\,d\,{\cos \left (c+d\,x\right )}^9}-\frac {16\,a\,b^2\,\sin \left (c+d\,x\right )}{105\,d\,\cos \left (c+d\,x\right )}-\frac {8\,a\,b^2\,\sin \left (c+d\,x\right )}{105\,d\,{\cos \left (c+d\,x\right )}^3}-\frac {2\,a\,b^2\,\sin \left (c+d\,x\right )}{35\,d\,{\cos \left (c+d\,x\right )}^5}-\frac {a\,b^2\,\sin \left (c+d\,x\right )}{21\,d\,{\cos \left (c+d\,x\right )}^7}+\frac {a\,b^2\,\sin \left (c+d\,x\right )}{3\,d\,{\cos \left (c+d\,x\right )}^9} \] Input:
int((a + b*sin(c + d*x))^3/cos(c + d*x)^10,x)
Output:
b^3/(9*d*cos(c + d*x)^9) - b^3/(7*d*cos(c + d*x)^7) + (a^2*b)/(3*d*cos(c + d*x)^9) + (128*a^3*sin(c + d*x))/(315*d*cos(c + d*x)) + (64*a^3*sin(c + d *x))/(315*d*cos(c + d*x)^3) + (16*a^3*sin(c + d*x))/(105*d*cos(c + d*x)^5) + (8*a^3*sin(c + d*x))/(63*d*cos(c + d*x)^7) + (a^3*sin(c + d*x))/(9*d*co s(c + d*x)^9) - (16*a*b^2*sin(c + d*x))/(105*d*cos(c + d*x)) - (8*a*b^2*si n(c + d*x))/(105*d*cos(c + d*x)^3) - (2*a*b^2*sin(c + d*x))/(35*d*cos(c + d*x)^5) - (a*b^2*sin(c + d*x))/(21*d*cos(c + d*x)^7) + (a*b^2*sin(c + d*x) )/(3*d*cos(c + d*x)^9)
Time = 0.17 (sec) , antiderivative size = 378, normalized size of antiderivative = 1.97 \[ \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx=\frac {-105 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{8} a^{2} b +10 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{8} b^{3}+420 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{6} a^{2} b -40 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{6} b^{3}-630 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{4} a^{2} b +60 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{4} b^{3}+420 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2} a^{2} b -40 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2} b^{3}-105 \cos \left (d x +c \right ) a^{2} b +10 \cos \left (d x +c \right ) b^{3}+128 \sin \left (d x +c \right )^{9} a^{3}-48 \sin \left (d x +c \right )^{9} a \,b^{2}-576 \sin \left (d x +c \right )^{7} a^{3}+216 \sin \left (d x +c \right )^{7} a \,b^{2}+1008 \sin \left (d x +c \right )^{5} a^{3}-378 \sin \left (d x +c \right )^{5} a \,b^{2}-840 \sin \left (d x +c \right )^{3} a^{3}+315 \sin \left (d x +c \right )^{3} a \,b^{2}+45 \sin \left (d x +c \right )^{2} b^{3}+315 \sin \left (d x +c \right ) a^{3}+105 a^{2} b -10 b^{3}}{315 \cos \left (d x +c \right ) d \left (\sin \left (d x +c \right )^{8}-4 \sin \left (d x +c \right )^{6}+6 \sin \left (d x +c \right )^{4}-4 \sin \left (d x +c \right )^{2}+1\right )} \] Input:
int(sec(d*x+c)^10*(a+b*sin(d*x+c))^3,x)
Output:
( - 105*cos(c + d*x)*sin(c + d*x)**8*a**2*b + 10*cos(c + d*x)*sin(c + d*x) **8*b**3 + 420*cos(c + d*x)*sin(c + d*x)**6*a**2*b - 40*cos(c + d*x)*sin(c + d*x)**6*b**3 - 630*cos(c + d*x)*sin(c + d*x)**4*a**2*b + 60*cos(c + d*x )*sin(c + d*x)**4*b**3 + 420*cos(c + d*x)*sin(c + d*x)**2*a**2*b - 40*cos( c + d*x)*sin(c + d*x)**2*b**3 - 105*cos(c + d*x)*a**2*b + 10*cos(c + d*x)* b**3 + 128*sin(c + d*x)**9*a**3 - 48*sin(c + d*x)**9*a*b**2 - 576*sin(c + d*x)**7*a**3 + 216*sin(c + d*x)**7*a*b**2 + 1008*sin(c + d*x)**5*a**3 - 37 8*sin(c + d*x)**5*a*b**2 - 840*sin(c + d*x)**3*a**3 + 315*sin(c + d*x)**3* a*b**2 + 45*sin(c + d*x)**2*b**3 + 315*sin(c + d*x)*a**3 + 105*a**2*b - 10 *b**3)/(315*cos(c + d*x)*d*(sin(c + d*x)**8 - 4*sin(c + d*x)**6 + 6*sin(c + d*x)**4 - 4*sin(c + d*x)**2 + 1))