Integrand size = 21, antiderivative size = 201 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^8 \, dx=-\frac {3003 a^8 x}{16}+\frac {1001 a^8 \cos ^5(c+d x)}{10 d}-\frac {3003 a^8 \cos (c+d x) \sin (c+d x)}{16 d}-\frac {1001 a^8 \cos ^3(c+d x) \sin (c+d x)}{8 d}+\frac {2 a^{15} \cos ^{13}(c+d x)}{d (a-a \sin (c+d x))^7}+\frac {26 a^{13} \cos ^{11}(c+d x)}{d (a-a \sin (c+d x))^5}+\frac {286 a^{14} \cos ^9(c+d x)}{3 d \left (a^2-a^2 \sin (c+d x)\right )^3}+\frac {143 a^{16} \cos ^7(c+d x)}{2 d \left (a^8-a^8 \sin (c+d x)\right )} \] Output:
-3003/16*a^8*x+1001/10*a^8*cos(d*x+c)^5/d-3003/16*a^8*cos(d*x+c)*sin(d*x+c )/d-1001/8*a^8*cos(d*x+c)^3*sin(d*x+c)/d+2*a^15*cos(d*x+c)^13/d/(a-a*sin(d *x+c))^7+26*a^13*cos(d*x+c)^11/d/(a-a*sin(d*x+c))^5+286/3*a^14*cos(d*x+c)^ 9/d/(a^2-a^2*sin(d*x+c))^3+143/2*a^16*cos(d*x+c)^7/d/(a^8-a^8*sin(d*x+c))
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.07 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.27 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^8 \, dx=\frac {128 \sqrt {2} a^8 \operatorname {Hypergeometric2F1}\left (-\frac {13}{2},-\frac {1}{2},\frac {1}{2},\frac {1}{2} (1-\sin (c+d x))\right ) \sec (c+d x) \sqrt {1+\sin (c+d x)}}{d} \] Input:
Integrate[Sec[c + d*x]^2*(a + a*Sin[c + d*x])^8,x]
Output:
(128*Sqrt[2]*a^8*Hypergeometric2F1[-13/2, -1/2, 1/2, (1 - Sin[c + d*x])/2] *Sec[c + d*x]*Sqrt[1 + Sin[c + d*x]])/d
Time = 1.15 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.12, number of steps used = 17, number of rules used = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.810, Rules used = {3042, 3149, 3042, 3159, 3042, 3159, 3042, 3159, 3042, 3158, 3042, 3161, 3042, 3115, 3042, 3115, 24}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \sec ^2(c+d x) (a \sin (c+d x)+a)^8 \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {(a \sin (c+d x)+a)^8}{\cos (c+d x)^2}dx\) |
| \(\Big \downarrow \) 3149 |
| \(\displaystyle a^{16} \int \frac {\cos ^{14}(c+d x)}{(a-a \sin (c+d x))^8}dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a^{16} \int \frac {\cos (c+d x)^{14}}{(a-a \sin (c+d x))^8}dx\) |
| \(\Big \downarrow \) 3159 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \int \frac {\cos ^{12}(c+d x)}{(a-a \sin (c+d x))^6}dx}{a^2}\right )\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \int \frac {\cos (c+d x)^{12}}{(a-a \sin (c+d x))^6}dx}{a^2}\right )\) |
| \(\Big \downarrow \) 3159 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \int \frac {\cos ^{10}(c+d x)}{(a-a \sin (c+d x))^4}dx}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \int \frac {\cos (c+d x)^{10}}{(a-a \sin (c+d x))^4}dx}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3159 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \int \frac {\cos ^8(c+d x)}{(a-a \sin (c+d x))^2}dx}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \int \frac {\cos (c+d x)^8}{(a-a \sin (c+d x))^2}dx}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3158 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \left (\frac {7 \int \frac {\cos ^6(c+d x)}{a-a \sin (c+d x)}dx}{6 a}-\frac {\cos ^7(c+d x)}{6 d \left (a^2-a^2 \sin (c+d x)\right )}\right )}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \left (\frac {7 \int \frac {\cos (c+d x)^6}{a-a \sin (c+d x)}dx}{6 a}-\frac {\cos ^7(c+d x)}{6 d \left (a^2-a^2 \sin (c+d x)\right )}\right )}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3161 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \left (\frac {7 \left (\frac {\int \cos ^4(c+d x)dx}{a}-\frac {\cos ^5(c+d x)}{5 a d}\right )}{6 a}-\frac {\cos ^7(c+d x)}{6 d \left (a^2-a^2 \sin (c+d x)\right )}\right )}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \left (\frac {7 \left (\frac {\int \sin \left (c+d x+\frac {\pi }{2}\right )^4dx}{a}-\frac {\cos ^5(c+d x)}{5 a d}\right )}{6 a}-\frac {\cos ^7(c+d x)}{6 d \left (a^2-a^2 \sin (c+d x)\right )}\right )}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3115 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \left (\frac {7 \left (\frac {\frac {3}{4} \int \cos ^2(c+d x)dx+\frac {\sin (c+d x) \cos ^3(c+d x)}{4 d}}{a}-\frac {\cos ^5(c+d x)}{5 a d}\right )}{6 a}-\frac {\cos ^7(c+d x)}{6 d \left (a^2-a^2 \sin (c+d x)\right )}\right )}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \left (\frac {7 \left (\frac {\frac {3}{4} \int \sin \left (c+d x+\frac {\pi }{2}\right )^2dx+\frac {\sin (c+d x) \cos ^3(c+d x)}{4 d}}{a}-\frac {\cos ^5(c+d x)}{5 a d}\right )}{6 a}-\frac {\cos ^7(c+d x)}{6 d \left (a^2-a^2 \sin (c+d x)\right )}\right )}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 3115 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \left (\frac {7 \left (\frac {\frac {3}{4} \left (\frac {\int 1dx}{2}+\frac {\sin (c+d x) \cos (c+d x)}{2 d}\right )+\frac {\sin (c+d x) \cos ^3(c+d x)}{4 d}}{a}-\frac {\cos ^5(c+d x)}{5 a d}\right )}{6 a}-\frac {\cos ^7(c+d x)}{6 d \left (a^2-a^2 \sin (c+d x)\right )}\right )}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 24 |
| \(\displaystyle a^{16} \left (\frac {2 \cos ^{13}(c+d x)}{a d (a-a \sin (c+d x))^7}-\frac {13 \left (\frac {11 \left (\frac {3 \left (\frac {7 \left (\frac {\frac {\sin (c+d x) \cos ^3(c+d x)}{4 d}+\frac {3}{4} \left (\frac {\sin (c+d x) \cos (c+d x)}{2 d}+\frac {x}{2}\right )}{a}-\frac {\cos ^5(c+d x)}{5 a d}\right )}{6 a}-\frac {\cos ^7(c+d x)}{6 d \left (a^2-a^2 \sin (c+d x)\right )}\right )}{a^2}-\frac {2 \cos ^9(c+d x)}{3 a d (a-a \sin (c+d x))^3}\right )}{a^2}-\frac {2 \cos ^{11}(c+d x)}{a d (a-a \sin (c+d x))^5}\right )}{a^2}\right )\) |
Input:
Int[Sec[c + d*x]^2*(a + a*Sin[c + d*x])^8,x]
Output:
a^16*((2*Cos[c + d*x]^13)/(a*d*(a - a*Sin[c + d*x])^7) - (13*((-2*Cos[c + d*x]^11)/(a*d*(a - a*Sin[c + d*x])^5) + (11*((-2*Cos[c + d*x]^9)/(3*a*d*(a - a*Sin[c + d*x])^3) + (3*(-1/6*Cos[c + d*x]^7/(d*(a^2 - a^2*Sin[c + d*x] )) + (7*(-1/5*Cos[c + d*x]^5/(a*d) + ((Cos[c + d*x]^3*Sin[c + d*x])/(4*d) + (3*(x/2 + (Cos[c + d*x]*Sin[c + d*x])/(2*d)))/4)/a))/(6*a)))/a^2))/a^2)) /a^2)
Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*Cos[c + d* x]*((b*Sin[c + d*x])^(n - 1)/(d*n)), x] + Simp[b^2*((n - 1)/n) Int[(b*Sin [c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && IntegerQ[ 2*n]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[(a/g)^(2*m) Int[(g*Cos[e + f*x])^(2*m + p)/( a - b*Sin[e + f*x])^m, x], x] /; FreeQ[{a, b, e, f, g}, x] && EqQ[a^2 - b^2 , 0] && IntegerQ[m] && LtQ[p, -1] && GeQ[2*m + p, 0]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[g*(g*Cos[e + f*x])^(p - 1)*((a + b*Sin[e + f*x ])^(m + 1)/(b*f*(m + p))), x] + Simp[g^2*((p - 1)/(a*(m + p))) Int[(g*Cos [e + f*x])^(p - 2)*(a + b*Sin[e + f*x])^(m + 1), x], x] /; FreeQ[{a, b, e, f, g}, x] && EqQ[a^2 - b^2, 0] && LtQ[m, -1] && GtQ[p, 1] && (GtQ[m, -2] || EqQ[2*m + p + 1, 0] || (EqQ[m, -2] && IntegerQ[p])) && NeQ[m + p, 0] && In tegersQ[2*m, 2*p]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[2*g*(g*Cos[e + f*x])^(p - 1)*((a + b*Sin[e + f *x])^(m + 1)/(b*f*(2*m + p + 1))), x] + Simp[g^2*((p - 1)/(b^2*(2*m + p + 1 ))) Int[(g*Cos[e + f*x])^(p - 2)*(a + b*Sin[e + f*x])^(m + 2), x], x] /; FreeQ[{a, b, e, f, g}, x] && EqQ[a^2 - b^2, 0] && LeQ[m, -2] && GtQ[p, 1] & & NeQ[2*m + p + 1, 0] && !ILtQ[m + p + 1, 0] && IntegersQ[2*m, 2*p]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)/((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)]), x_Symbol] :> Simp[g*((g*Cos[e + f*x])^(p - 1)/(b*f*(p - 1))), x] + Si mp[g^2/a Int[(g*Cos[e + f*x])^(p - 2), x], x] /; FreeQ[{a, b, e, f, g}, x ] && EqQ[a^2 - b^2, 0] && GtQ[p, 1] && IntegerQ[2*p]
Time = 0.82 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.55
| method | result | size |
| parallelrisch | \(\frac {a^{8} \left (411840-5824 \cos \left (4 d x +4 c \right )+276705 \sin \left (d x +c \right )+566272 \cos \left (d x +c \right )+30030 \sin \left (3 d x +3 c \right )+160160 \cos \left (2 d x +2 c \right )+5 \sin \left (7 d x +7 c \right )+96 \cos \left (6 d x +6 c \right )-910 \sin \left (5 d x +5 c \right )-360360 \cos \left (d x +c \right ) d x \right )}{1920 d \cos \left (d x +c \right )}\) | \(111\) |
| risch | \(-\frac {3003 a^{8} x}{16}+\frac {173 a^{8} {\mathrm e}^{i \left (d x +c \right )}}{2 d}+\frac {173 a^{8} {\mathrm e}^{-i \left (d x +c \right )}}{2 d}+\frac {256 a^{8}}{d \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}+\frac {a^{8} \sin \left (6 d x +6 c \right )}{192 d}+\frac {a^{8} \cos \left (5 d x +5 c \right )}{10 d}-\frac {61 a^{8} \sin \left (4 d x +4 c \right )}{64 d}-\frac {37 a^{8} \cos \left (3 d x +3 c \right )}{6 d}+\frac {2063 a^{8} \sin \left (2 d x +2 c \right )}{64 d}\) | \(149\) |
| derivativedivides | \(\frac {a^{8} \left (\frac {\sin \left (d x +c \right )^{9}}{\cos \left (d x +c \right )}+\left (\sin \left (d x +c \right )^{7}+\frac {7 \sin \left (d x +c \right )^{5}}{6}+\frac {35 \sin \left (d x +c \right )^{3}}{24}+\frac {35 \sin \left (d x +c \right )}{16}\right ) \cos \left (d x +c \right )-\frac {35 d x}{16}-\frac {35 c}{16}\right )+8 a^{8} \left (\frac {\sin \left (d x +c \right )^{8}}{\cos \left (d x +c \right )}+\left (\frac {16}{5}+\sin \left (d x +c \right )^{6}+\frac {6 \sin \left (d x +c \right )^{4}}{5}+\frac {8 \sin \left (d x +c \right )^{2}}{5}\right ) \cos \left (d x +c \right )\right )+28 a^{8} \left (\frac {\sin \left (d x +c \right )^{7}}{\cos \left (d x +c \right )}+\left (\sin \left (d x +c \right )^{5}+\frac {5 \sin \left (d x +c \right )^{3}}{4}+\frac {15 \sin \left (d x +c \right )}{8}\right ) \cos \left (d x +c \right )-\frac {15 d x}{8}-\frac {15 c}{8}\right )+56 a^{8} \left (\frac {\sin \left (d x +c \right )^{6}}{\cos \left (d x +c \right )}+\left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )\right )+70 a^{8} \left (\frac {\sin \left (d x +c \right )^{5}}{\cos \left (d x +c \right )}+\left (\sin \left (d x +c \right )^{3}+\frac {3 \sin \left (d x +c \right )}{2}\right ) \cos \left (d x +c \right )-\frac {3 d x}{2}-\frac {3 c}{2}\right )+56 a^{8} \left (\frac {\sin \left (d x +c \right )^{4}}{\cos \left (d x +c \right )}+\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )\right )+28 a^{8} \left (\tan \left (d x +c \right )-d x -c \right )+\frac {8 a^{8}}{\cos \left (d x +c \right )}+a^{8} \tan \left (d x +c \right )}{d}\) | \(389\) |
| default | \(\frac {a^{8} \left (\frac {\sin \left (d x +c \right )^{9}}{\cos \left (d x +c \right )}+\left (\sin \left (d x +c \right )^{7}+\frac {7 \sin \left (d x +c \right )^{5}}{6}+\frac {35 \sin \left (d x +c \right )^{3}}{24}+\frac {35 \sin \left (d x +c \right )}{16}\right ) \cos \left (d x +c \right )-\frac {35 d x}{16}-\frac {35 c}{16}\right )+8 a^{8} \left (\frac {\sin \left (d x +c \right )^{8}}{\cos \left (d x +c \right )}+\left (\frac {16}{5}+\sin \left (d x +c \right )^{6}+\frac {6 \sin \left (d x +c \right )^{4}}{5}+\frac {8 \sin \left (d x +c \right )^{2}}{5}\right ) \cos \left (d x +c \right )\right )+28 a^{8} \left (\frac {\sin \left (d x +c \right )^{7}}{\cos \left (d x +c \right )}+\left (\sin \left (d x +c \right )^{5}+\frac {5 \sin \left (d x +c \right )^{3}}{4}+\frac {15 \sin \left (d x +c \right )}{8}\right ) \cos \left (d x +c \right )-\frac {15 d x}{8}-\frac {15 c}{8}\right )+56 a^{8} \left (\frac {\sin \left (d x +c \right )^{6}}{\cos \left (d x +c \right )}+\left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )\right )+70 a^{8} \left (\frac {\sin \left (d x +c \right )^{5}}{\cos \left (d x +c \right )}+\left (\sin \left (d x +c \right )^{3}+\frac {3 \sin \left (d x +c \right )}{2}\right ) \cos \left (d x +c \right )-\frac {3 d x}{2}-\frac {3 c}{2}\right )+56 a^{8} \left (\frac {\sin \left (d x +c \right )^{4}}{\cos \left (d x +c \right )}+\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )\right )+28 a^{8} \left (\tan \left (d x +c \right )-d x -c \right )+\frac {8 a^{8}}{\cos \left (d x +c \right )}+a^{8} \tan \left (d x +c \right )}{d}\) | \(389\) |
Input:
int(sec(d*x+c)^2*(a+a*sin(d*x+c))^8,x,method=_RETURNVERBOSE)
Output:
1/1920/d*a^8*(411840-5824*cos(4*d*x+4*c)+276705*sin(d*x+c)+566272*cos(d*x+ c)+30030*sin(3*d*x+3*c)+160160*cos(2*d*x+2*c)+5*sin(7*d*x+7*c)+96*cos(6*d* x+6*c)-910*sin(5*d*x+5*c)-360360*cos(d*x+c)*d*x)/cos(d*x+c)
Time = 0.09 (sec) , antiderivative size = 231, normalized size of antiderivative = 1.15 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^8 \, dx=\frac {40 \, a^{8} \cos \left (d x + c\right )^{7} + 384 \, a^{8} \cos \left (d x + c\right )^{6} - 1526 \, a^{8} \cos \left (d x + c\right )^{5} - 6400 \, a^{8} \cos \left (d x + c\right )^{4} + 11865 \, a^{8} \cos \left (d x + c\right )^{3} - 45045 \, a^{8} d x + 46080 \, a^{8} \cos \left (d x + c\right )^{2} + 30720 \, a^{8} - 15 \, {\left (3003 \, a^{8} d x - 4027 \, a^{8}\right )} \cos \left (d x + c\right ) + {\left (40 \, a^{8} \cos \left (d x + c\right )^{6} - 344 \, a^{8} \cos \left (d x + c\right )^{5} - 1870 \, a^{8} \cos \left (d x + c\right )^{4} + 4530 \, a^{8} \cos \left (d x + c\right )^{3} + 45045 \, a^{8} d x + 16395 \, a^{8} \cos \left (d x + c\right )^{2} - 29685 \, a^{8} \cos \left (d x + c\right ) + 30720 \, a^{8}\right )} \sin \left (d x + c\right )}{240 \, {\left (d \cos \left (d x + c\right ) - d \sin \left (d x + c\right ) + d\right )}} \] Input:
integrate(sec(d*x+c)^2*(a+a*sin(d*x+c))^8,x, algorithm="fricas")
Output:
1/240*(40*a^8*cos(d*x + c)^7 + 384*a^8*cos(d*x + c)^6 - 1526*a^8*cos(d*x + c)^5 - 6400*a^8*cos(d*x + c)^4 + 11865*a^8*cos(d*x + c)^3 - 45045*a^8*d*x + 46080*a^8*cos(d*x + c)^2 + 30720*a^8 - 15*(3003*a^8*d*x - 4027*a^8)*cos (d*x + c) + (40*a^8*cos(d*x + c)^6 - 344*a^8*cos(d*x + c)^5 - 1870*a^8*cos (d*x + c)^4 + 4530*a^8*cos(d*x + c)^3 + 45045*a^8*d*x + 16395*a^8*cos(d*x + c)^2 - 29685*a^8*cos(d*x + c) + 30720*a^8)*sin(d*x + c))/(d*cos(d*x + c) - d*sin(d*x + c) + d)
Timed out. \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^8 \, dx=\text {Timed out} \] Input:
integrate(sec(d*x+c)**2*(a+a*sin(d*x+c))**8,x)
Output:
Timed out
Time = 0.12 (sec) , antiderivative size = 331, normalized size of antiderivative = 1.65 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^8 \, dx=\frac {384 \, {\left (\cos \left (d x + c\right )^{5} - 5 \, \cos \left (d x + c\right )^{3} + \frac {5}{\cos \left (d x + c\right )} + 15 \, \cos \left (d x + c\right )\right )} a^{8} - 4480 \, {\left (\cos \left (d x + c\right )^{3} - \frac {3}{\cos \left (d x + c\right )} - 6 \, \cos \left (d x + c\right )\right )} a^{8} - 5 \, {\left (105 \, d x + 105 \, c - \frac {87 \, \tan \left (d x + c\right )^{5} + 136 \, \tan \left (d x + c\right )^{3} + 57 \, \tan \left (d x + c\right )}{\tan \left (d x + c\right )^{6} + 3 \, \tan \left (d x + c\right )^{4} + 3 \, \tan \left (d x + c\right )^{2} + 1} - 48 \, \tan \left (d x + c\right )\right )} a^{8} - 840 \, {\left (15 \, d x + 15 \, c - \frac {9 \, \tan \left (d x + c\right )^{3} + 7 \, \tan \left (d x + c\right )}{\tan \left (d x + c\right )^{4} + 2 \, \tan \left (d x + c\right )^{2} + 1} - 8 \, \tan \left (d x + c\right )\right )} a^{8} - 8400 \, {\left (3 \, d x + 3 \, c - \frac {\tan \left (d x + c\right )}{\tan \left (d x + c\right )^{2} + 1} - 2 \, \tan \left (d x + c\right )\right )} a^{8} - 6720 \, {\left (d x + c - \tan \left (d x + c\right )\right )} a^{8} + 13440 \, a^{8} {\left (\frac {1}{\cos \left (d x + c\right )} + \cos \left (d x + c\right )\right )} + 240 \, a^{8} \tan \left (d x + c\right ) + \frac {1920 \, a^{8}}{\cos \left (d x + c\right )}}{240 \, d} \] Input:
integrate(sec(d*x+c)^2*(a+a*sin(d*x+c))^8,x, algorithm="maxima")
Output:
1/240*(384*(cos(d*x + c)^5 - 5*cos(d*x + c)^3 + 5/cos(d*x + c) + 15*cos(d* x + c))*a^8 - 4480*(cos(d*x + c)^3 - 3/cos(d*x + c) - 6*cos(d*x + c))*a^8 - 5*(105*d*x + 105*c - (87*tan(d*x + c)^5 + 136*tan(d*x + c)^3 + 57*tan(d* x + c))/(tan(d*x + c)^6 + 3*tan(d*x + c)^4 + 3*tan(d*x + c)^2 + 1) - 48*ta n(d*x + c))*a^8 - 840*(15*d*x + 15*c - (9*tan(d*x + c)^3 + 7*tan(d*x + c)) /(tan(d*x + c)^4 + 2*tan(d*x + c)^2 + 1) - 8*tan(d*x + c))*a^8 - 8400*(3*d *x + 3*c - tan(d*x + c)/(tan(d*x + c)^2 + 1) - 2*tan(d*x + c))*a^8 - 6720* (d*x + c - tan(d*x + c))*a^8 + 13440*a^8*(1/cos(d*x + c) + cos(d*x + c)) + 240*a^8*tan(d*x + c) + 1920*a^8/cos(d*x + c))/d
Time = 0.18 (sec) , antiderivative size = 231, normalized size of antiderivative = 1.15 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^8 \, dx=-\frac {45045 \, {\left (d x + c\right )} a^{8} + \frac {61440 \, a^{8}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1} + \frac {2 \, {\left (14565 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 28800 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{10} + 50855 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 174720 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} + 36930 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 400640 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 36930 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 426240 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 50855 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 211584 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 14565 \, a^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 40064 \, a^{8}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{6}}}{240 \, d} \] Input:
integrate(sec(d*x+c)^2*(a+a*sin(d*x+c))^8,x, algorithm="giac")
Output:
-1/240*(45045*(d*x + c)*a^8 + 61440*a^8/(tan(1/2*d*x + 1/2*c) - 1) + 2*(14 565*a^8*tan(1/2*d*x + 1/2*c)^11 - 28800*a^8*tan(1/2*d*x + 1/2*c)^10 + 5085 5*a^8*tan(1/2*d*x + 1/2*c)^9 - 174720*a^8*tan(1/2*d*x + 1/2*c)^8 + 36930*a ^8*tan(1/2*d*x + 1/2*c)^7 - 400640*a^8*tan(1/2*d*x + 1/2*c)^6 - 36930*a^8* tan(1/2*d*x + 1/2*c)^5 - 426240*a^8*tan(1/2*d*x + 1/2*c)^4 - 50855*a^8*tan (1/2*d*x + 1/2*c)^3 - 211584*a^8*tan(1/2*d*x + 1/2*c)^2 - 14565*a^8*tan(1/ 2*d*x + 1/2*c) - 40064*a^8)/(tan(1/2*d*x + 1/2*c)^2 + 1)^6)/d
Time = 30.56 (sec) , antiderivative size = 513, normalized size of antiderivative = 2.55 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^8 \, dx =\text {Too large to display} \] Input:
int((a + a*sin(c + d*x))^8/cos(c + d*x)^2,x)
Output:
- (3003*a^8*x)/16 - ((3003*a^8*(c + d*x))/16 - tan(c/2 + (d*x)/2)*((3003*a ^8*(c + d*x))/16 - (a^8*(45045*c + 45045*d*x - 50998))/240) - (a^8*(45045* c + 45045*d*x - 141568))/240 + tan(c/2 + (d*x)/2)^12*((3003*a^8*(c + d*x)) /16 - (a^8*(45045*c + 45045*d*x - 90570))/240) - tan(c/2 + (d*x)/2)^11*((9 009*a^8*(c + d*x))/8 - (a^8*(270270*c + 270270*d*x - 86730))/240) - tan(c/ 2 + (d*x)/2)^3*((9009*a^8*(c + d*x))/8 - (a^8*(270270*c + 270270*d*x - 321 458))/240) + tan(c/2 + (d*x)/2)^10*((9009*a^8*(c + d*x))/8 - (a^8*(270270* c + 270270*d*x - 527950))/240) + tan(c/2 + (d*x)/2)^2*((9009*a^8*(c + d*x) )/8 - (a^8*(270270*c + 270270*d*x - 762678))/240) - tan(c/2 + (d*x)/2)^9*( (45045*a^8*(c + d*x))/16 - (a^8*(675675*c + 675675*d*x - 451150))/240) - t an(c/2 + (d*x)/2)^5*((45045*a^8*(c + d*x))/16 - (a^8*(675675*c + 675675*d* x - 778620))/240) - tan(c/2 + (d*x)/2)^7*((15015*a^8*(c + d*x))/4 - (a^8*( 900900*c + 900900*d*x - 875140))/240) + tan(c/2 + (d*x)/2)^8*((45045*a^8*( c + d*x))/16 - (a^8*(675675*c + 675675*d*x - 1344900))/240) + tan(c/2 + (d *x)/2)^4*((45045*a^8*(c + d*x))/16 - (a^8*(675675*c + 675675*d*x - 1672370 ))/240) + tan(c/2 + (d*x)/2)^6*((15015*a^8*(c + d*x))/4 - (a^8*(900900*c + 900900*d*x - 1956220))/240))/(d*(tan(c/2 + (d*x)/2) - 1)*(tan(c/2 + (d*x) /2)^2 + 1)^6)
Time = 0.17 (sec) , antiderivative size = 220, normalized size of antiderivative = 1.09 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^8 \, dx=\frac {a^{8} \left (40 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{6}+344 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{5}+1406 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{4}+3842 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{3}+8933 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2}+25499 \cos \left (d x +c \right ) \sin \left (d x +c \right )-45045 \cos \left (d x +c \right ) d x -90570 \cos \left (d x +c \right )-40 \sin \left (d x +c \right )^{7}-384 \sin \left (d x +c \right )^{6}-1750 \sin \left (d x +c \right )^{5}-5248 \sin \left (d x +c \right )^{4}-12775 \sin \left (d x +c \right )^{3}-34432 \sin \left (d x +c \right )^{2}-45045 \sin \left (d x +c \right ) d x +25499 \sin \left (d x +c \right )+45045 d x +90570\right )}{240 d \left (\cos \left (d x +c \right )+\sin \left (d x +c \right )-1\right )} \] Input:
int(sec(d*x+c)^2*(a+a*sin(d*x+c))^8,x)
Output:
(a**8*(40*cos(c + d*x)*sin(c + d*x)**6 + 344*cos(c + d*x)*sin(c + d*x)**5 + 1406*cos(c + d*x)*sin(c + d*x)**4 + 3842*cos(c + d*x)*sin(c + d*x)**3 + 8933*cos(c + d*x)*sin(c + d*x)**2 + 25499*cos(c + d*x)*sin(c + d*x) - 4504 5*cos(c + d*x)*d*x - 90570*cos(c + d*x) - 40*sin(c + d*x)**7 - 384*sin(c + d*x)**6 - 1750*sin(c + d*x)**5 - 5248*sin(c + d*x)**4 - 12775*sin(c + d*x )**3 - 34432*sin(c + d*x)**2 - 45045*sin(c + d*x)*d*x + 25499*sin(c + d*x) + 45045*d*x + 90570))/(240*d*(cos(c + d*x) + sin(c + d*x) - 1))