\(\int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^{7/2}} \, dx\) [496]

Optimal result
Mathematica [C] (warning: unable to verify)
Rubi [A] (verified)
Maple [B] (verified)
Fricas [C] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 25, antiderivative size = 318 \[ \int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^{7/2}} \, dx=-\frac {2 a \cos (e+f x)}{5 (c+d) f (c+d \sin (e+f x))^{5/2}}-\frac {2 a (3 c-5 d) \cos (e+f x)}{15 (c-d) (c+d)^2 f (c+d \sin (e+f x))^{3/2}}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{15 (c-d)^2 (c+d)^3 f \sqrt {c+d \sin (e+f x)}}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) E\left (\frac {1}{2} \left (e-\frac {\pi }{2}+f x\right )|\frac {2 d}{c+d}\right ) \sqrt {c+d \sin (e+f x)}}{15 (c-d)^2 d (c+d)^3 f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}+\frac {2 a (3 c-5 d) \operatorname {EllipticF}\left (\frac {1}{2} \left (e-\frac {\pi }{2}+f x\right ),\frac {2 d}{c+d}\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}{15 (c-d) d (c+d)^2 f \sqrt {c+d \sin (e+f x)}} \] Output:

-2/5*a*cos(f*x+e)/(c+d)/f/(c+d*sin(f*x+e))^(5/2)-2/15*a*(3*c-5*d)*cos(f*x+ 
e)/(c-d)/(c+d)^2/f/(c+d*sin(f*x+e))^(3/2)-2/15*a*(3*c^2-20*c*d+9*d^2)*cos( 
f*x+e)/(c-d)^2/(c+d)^3/f/(c+d*sin(f*x+e))^(1/2)+2/15*a*(3*c^2-20*c*d+9*d^2 
)*EllipticE(cos(1/2*e+1/4*Pi+1/2*f*x),2^(1/2)*(d/(c+d))^(1/2))*(c+d*sin(f* 
x+e))^(1/2)/(c-d)^2/d/(c+d)^3/f/((c+d*sin(f*x+e))/(c+d))^(1/2)+2/15*a*(3*c 
-5*d)*InverseJacobiAM(1/2*e-1/4*Pi+1/2*f*x,2^(1/2)*(d/(c+d))^(1/2))*((c+d* 
sin(f*x+e))/(c+d))^(1/2)/(c-d)/d/(c+d)^2/f/(c+d*sin(f*x+e))^(1/2)
 

Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.

Time = 7.80 (sec) , antiderivative size = 2815, normalized size of antiderivative = 8.85 \[ \int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^{7/2}} \, dx=\text {Result too large to show} \] Input:

Integrate[(a + a*Sin[e + f*x])/(c + d*Sin[e + f*x])^(7/2),x]
 

Output:

a*(((1 + Sin[e + f*x])*Sqrt[c + d*Sin[e + f*x]]*((-2*(3*c^2 - 20*c*d + 9*d 
^2)*Csc[e]*Sec[e])/(15*(c - d)^2*d*(c + d)^3*f) + (2*Csc[e]*(c*Cos[e] + d* 
Sin[f*x]))/(5*d*(c + d)*f*(c + d*Sin[e + f*x])^3) - (2*Csc[e]*(5*c*Cos[e] 
- 3*d*Cos[e] - 3*c*Sin[f*x] + 5*d*Sin[f*x]))/(15*(c - d)*(c + d)^2*f*(c + 
d*Sin[e + f*x])^2) - (2*Csc[e]*(15*c^2*Cos[e] - 12*c*d*Cos[e] + 5*d^2*Cos[ 
e] - 3*c^2*Sin[f*x] + 20*c*d*Sin[f*x] - 9*d^2*Sin[f*x]))/(15*(c - d)^2*(c 
+ d)^3*f*(c + d*Sin[e + f*x]))))/(Cos[e/2 + (f*x)/2] + Sin[e/2 + (f*x)/2]) 
^2 - (c^2*Sec[e]*(1 + Sin[e + f*x])*(-((AppellF1[-1/2, -1/2, -1/2, 1/2, -( 
(Csc[e]*(c + d*Cos[f*x - ArcTan[Cot[e]]]*Sqrt[1 + Cot[e]^2]*Sin[e]))/(d*Sq 
rt[1 + Cot[e]^2]*(1 - (c*Csc[e])/(d*Sqrt[1 + Cot[e]^2])))), -((Csc[e]*(c + 
 d*Cos[f*x - ArcTan[Cot[e]]]*Sqrt[1 + Cot[e]^2]*Sin[e]))/(d*Sqrt[1 + Cot[e 
]^2]*(-1 - (c*Csc[e])/(d*Sqrt[1 + Cot[e]^2]))))]*Cot[e]*Sin[f*x - ArcTan[C 
ot[e]]])/(Sqrt[1 + Cot[e]^2]*Sqrt[(d*Sqrt[1 + Cot[e]^2] + d*Cos[f*x - ArcT 
an[Cot[e]]]*Sqrt[1 + Cot[e]^2])/(d*Sqrt[1 + Cot[e]^2] - c*Csc[e])]*Sqrt[(d 
*Sqrt[1 + Cot[e]^2] - d*Cos[f*x - ArcTan[Cot[e]]]*Sqrt[1 + Cot[e]^2])/(d*S 
qrt[1 + Cot[e]^2] + c*Csc[e])]*Sqrt[c + d*Cos[f*x - ArcTan[Cot[e]]]*Sqrt[1 
 + Cot[e]^2]*Sin[e]])) - ((2*d*Sin[e]*(c + d*Cos[f*x - ArcTan[Cot[e]]]*Sqr 
t[1 + Cot[e]^2]*Sin[e]))/(d^2*Cos[e]^2 + d^2*Sin[e]^2) - (Cot[e]*Sin[f*x - 
 ArcTan[Cot[e]]])/Sqrt[1 + Cot[e]^2])/Sqrt[c + d*Cos[f*x - ArcTan[Cot[e]]] 
*Sqrt[1 + Cot[e]^2]*Sin[e]]))/(5*(c - d)^2*(c + d)^3*f*(Cos[e/2 + (f*x)...
 

Rubi [A] (verified)

Time = 1.67 (sec) , antiderivative size = 334, normalized size of antiderivative = 1.05, number of steps used = 18, number of rules used = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.720, Rules used = {3042, 3233, 27, 3042, 3233, 27, 3042, 3233, 27, 3042, 3231, 3042, 3134, 3042, 3132, 3142, 3042, 3140}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {a \sin (e+f x)+a}{(c+d \sin (e+f x))^{7/2}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {a \sin (e+f x)+a}{(c+d \sin (e+f x))^{7/2}}dx\)

\(\Big \downarrow \) 3233

\(\displaystyle -\frac {2 \int -\frac {5 a (c-d)+3 a \sin (e+f x) (c-d)}{2 (c+d \sin (e+f x))^{5/2}}dx}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {5 a (c-d)+3 a \sin (e+f x) (c-d)}{(c+d \sin (e+f x))^{5/2}}dx}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \frac {5 a (c-d)+3 a \sin (e+f x) (c-d)}{(c+d \sin (e+f x))^{5/2}}dx}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3233

\(\displaystyle \frac {-\frac {2 \int -\frac {3 a (5 c-3 d) (c-d)+a (3 c-5 d) \sin (e+f x) (c-d)}{2 (c+d \sin (e+f x))^{3/2}}dx}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\int \frac {3 a (5 c-3 d) (c-d)+a (3 c-5 d) \sin (e+f x) (c-d)}{(c+d \sin (e+f x))^{3/2}}dx}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\int \frac {3 a (5 c-3 d) (c-d)+a (3 c-5 d) \sin (e+f x) (c-d)}{(c+d \sin (e+f x))^{3/2}}dx}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3233

\(\displaystyle \frac {\frac {-\frac {2 \int -\frac {a (c-d) \left (15 c^2-12 d c+5 d^2\right )-a (c-d) \left (3 c^2-20 d c+9 d^2\right ) \sin (e+f x)}{2 \sqrt {c+d \sin (e+f x)}}dx}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {\int \frac {a (c-d) \left (15 c^2-12 d c+5 d^2\right )-a (c-d) \left (3 c^2-20 d c+9 d^2\right ) \sin (e+f x)}{\sqrt {c+d \sin (e+f x)}}dx}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {\int \frac {a (c-d) \left (15 c^2-12 d c+5 d^2\right )-a (c-d) \left (3 c^2-20 d c+9 d^2\right ) \sin (e+f x)}{\sqrt {c+d \sin (e+f x)}}dx}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3231

\(\displaystyle \frac {\frac {\frac {\frac {a (3 c-5 d) (c-d)^2 (c+d) \int \frac {1}{\sqrt {c+d \sin (e+f x)}}dx}{d}-\frac {a (c-d) \left (3 c^2-20 c d+9 d^2\right ) \int \sqrt {c+d \sin (e+f x)}dx}{d}}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {\frac {a (3 c-5 d) (c-d)^2 (c+d) \int \frac {1}{\sqrt {c+d \sin (e+f x)}}dx}{d}-\frac {a (c-d) \left (3 c^2-20 c d+9 d^2\right ) \int \sqrt {c+d \sin (e+f x)}dx}{d}}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3134

\(\displaystyle \frac {\frac {\frac {\frac {a (3 c-5 d) (c-d)^2 (c+d) \int \frac {1}{\sqrt {c+d \sin (e+f x)}}dx}{d}-\frac {a (c-d) \left (3 c^2-20 c d+9 d^2\right ) \sqrt {c+d \sin (e+f x)} \int \sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}dx}{d \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {\frac {a (3 c-5 d) (c-d)^2 (c+d) \int \frac {1}{\sqrt {c+d \sin (e+f x)}}dx}{d}-\frac {a (c-d) \left (3 c^2-20 c d+9 d^2\right ) \sqrt {c+d \sin (e+f x)} \int \sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}dx}{d \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3132

\(\displaystyle \frac {\frac {\frac {\frac {a (3 c-5 d) (c-d)^2 (c+d) \int \frac {1}{\sqrt {c+d \sin (e+f x)}}dx}{d}-\frac {2 a (c-d) \left (3 c^2-20 c d+9 d^2\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{d f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3142

\(\displaystyle \frac {\frac {\frac {\frac {a (3 c-5 d) (c-d)^2 (c+d) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \int \frac {1}{\sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}}dx}{d \sqrt {c+d \sin (e+f x)}}-\frac {2 a (c-d) \left (3 c^2-20 c d+9 d^2\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{d f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {\frac {a (3 c-5 d) (c-d)^2 (c+d) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \int \frac {1}{\sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}}dx}{d \sqrt {c+d \sin (e+f x)}}-\frac {2 a (c-d) \left (3 c^2-20 c d+9 d^2\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{d f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

\(\Big \downarrow \) 3140

\(\displaystyle \frac {\frac {\frac {\frac {2 a (3 c-5 d) (c-d)^2 (c+d) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \operatorname {EllipticF}\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right ),\frac {2 d}{c+d}\right )}{d f \sqrt {c+d \sin (e+f x)}}-\frac {2 a (c-d) \left (3 c^2-20 c d+9 d^2\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{d f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}}{c^2-d^2}-\frac {2 a \left (3 c^2-20 c d+9 d^2\right ) \cos (e+f x)}{f (c+d) \sqrt {c+d \sin (e+f x)}}}{3 \left (c^2-d^2\right )}-\frac {2 a (3 c-5 d) \cos (e+f x)}{3 f (c+d) (c+d \sin (e+f x))^{3/2}}}{5 \left (c^2-d^2\right )}-\frac {2 a \cos (e+f x)}{5 f (c+d) (c+d \sin (e+f x))^{5/2}}\)

Input:

Int[(a + a*Sin[e + f*x])/(c + d*Sin[e + f*x])^(7/2),x]
 

Output:

(-2*a*Cos[e + f*x])/(5*(c + d)*f*(c + d*Sin[e + f*x])^(5/2)) + ((-2*a*(3*c 
 - 5*d)*Cos[e + f*x])/(3*(c + d)*f*(c + d*Sin[e + f*x])^(3/2)) + ((-2*a*(3 
*c^2 - 20*c*d + 9*d^2)*Cos[e + f*x])/((c + d)*f*Sqrt[c + d*Sin[e + f*x]]) 
+ ((-2*a*(c - d)*(3*c^2 - 20*c*d + 9*d^2)*EllipticE[(e - Pi/2 + f*x)/2, (2 
*d)/(c + d)]*Sqrt[c + d*Sin[e + f*x]])/(d*f*Sqrt[(c + d*Sin[e + f*x])/(c + 
 d)]) + (2*a*(3*c - 5*d)*(c - d)^2*(c + d)*EllipticF[(e - Pi/2 + f*x)/2, ( 
2*d)/(c + d)]*Sqrt[(c + d*Sin[e + f*x])/(c + d)])/(d*f*Sqrt[c + d*Sin[e + 
f*x]]))/(c^2 - d^2))/(3*(c^2 - d^2)))/(5*(c^2 - d^2))
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3132
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[2*(Sqrt[a 
 + b]/d)*EllipticE[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[{a, 
b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3134
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[a + 
b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c + d*x])/(a + b)]   Int[Sqrt[a/(a + b) + ( 
b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2 
, 0] &&  !GtQ[a + b, 0]
 

rule 3140
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/(d*S 
qrt[a + b]))*EllipticF[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[ 
{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3142
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[(a 
 + b*Sin[c + d*x])/(a + b)]/Sqrt[a + b*Sin[c + d*x]]   Int[1/Sqrt[a/(a + b) 
 + (b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - 
 b^2, 0] &&  !GtQ[a + b, 0]
 

rule 3231
Int[((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])/Sqrt[(a_) + (b_.)*sin[(e_.) + ( 
f_.)*(x_)]], x_Symbol] :> Simp[(b*c - a*d)/b   Int[1/Sqrt[a + b*Sin[e + f*x 
]], x], x] + Simp[d/b   Int[Sqrt[a + b*Sin[e + f*x]], x], x] /; FreeQ[{a, b 
, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0]
 

rule 3233
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
(f_.)*(x_)]), x_Symbol] :> Simp[(-(b*c - a*d))*Cos[e + f*x]*((a + b*Sin[e + 
 f*x])^(m + 1)/(f*(m + 1)*(a^2 - b^2))), x] + Simp[1/((m + 1)*(a^2 - b^2)) 
  Int[(a + b*Sin[e + f*x])^(m + 1)*Simp[(a*c - b*d)*(m + 1) - (b*c - a*d)*( 
m + 2)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c 
- a*d, 0] && NeQ[a^2 - b^2, 0] && LtQ[m, -1] && IntegerQ[2*m]
 
Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(1042\) vs. \(2(299)=598\).

Time = 2.86 (sec) , antiderivative size = 1043, normalized size of antiderivative = 3.28

method result size
default \(\text {Expression too large to display}\) \(1043\)
parts \(\text {Expression too large to display}\) \(1622\)

Input:

int((a+sin(f*x+e)*a)/(c+d*sin(f*x+e))^(7/2),x,method=_RETURNVERBOSE)
 

Output:

(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)*a*(1/d*(2/3/(c^2-d^2)/d*(-(-c-d*si 
n(f*x+e))*cos(f*x+e)^2)^(1/2)/(sin(f*x+e)+c/d)^2+8/3*d*cos(f*x+e)^2/(c^2-d 
^2)^2*c/(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)+2*(3*c^2+d^2)/(3*c^4-6*c^2 
*d^2+3*d^4)*(c/d-1)*((c+d*sin(f*x+e))/(c-d))^(1/2)*(d*(1-sin(f*x+e))/(c+d) 
)^(1/2)*(-d*(1+sin(f*x+e))/(c-d))^(1/2)/(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^ 
(1/2)*EllipticF(((c+d*sin(f*x+e))/(c-d))^(1/2),((c-d)/(c+d))^(1/2))+8/3*c* 
d/(c^2-d^2)^2*(c/d-1)*((c+d*sin(f*x+e))/(c-d))^(1/2)*(d*(1-sin(f*x+e))/(c+ 
d))^(1/2)*(-d*(1+sin(f*x+e))/(c-d))^(1/2)/(-(-c-d*sin(f*x+e))*cos(f*x+e)^2 
)^(1/2)*((-c/d-1)*EllipticE(((c+d*sin(f*x+e))/(c-d))^(1/2),((c-d)/(c+d))^( 
1/2))+EllipticF(((c+d*sin(f*x+e))/(c-d))^(1/2),((c-d)/(c+d))^(1/2))))-(c-d 
)/d*(2/5/(c^2-d^2)/d^2*(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)/(sin(f*x+e) 
+c/d)^3+16/15*c/(c^2-d^2)^2/d*(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)/(sin 
(f*x+e)+c/d)^2+2/15*cos(f*x+e)^2*d/(c^2-d^2)^3*(23*c^2+9*d^2)/(-(-c-d*sin( 
f*x+e))*cos(f*x+e)^2)^(1/2)+2*(15*c^3+17*c*d^2)/(15*c^6-45*c^4*d^2+45*c^2* 
d^4-15*d^6)*(c/d-1)*((c+d*sin(f*x+e))/(c-d))^(1/2)*(d*(1-sin(f*x+e))/(c+d) 
)^(1/2)*(-d*(1+sin(f*x+e))/(c-d))^(1/2)/(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^ 
(1/2)*EllipticF(((c+d*sin(f*x+e))/(c-d))^(1/2),((c-d)/(c+d))^(1/2))+2/15*d 
*(23*c^2+9*d^2)/(c^2-d^2)^3*(c/d-1)*((c+d*sin(f*x+e))/(c-d))^(1/2)*(d*(1-s 
in(f*x+e))/(c+d))^(1/2)*(-d*(1+sin(f*x+e))/(c-d))^(1/2)/(-(-c-d*sin(f*x+e) 
)*cos(f*x+e)^2)^(1/2)*((-c/d-1)*EllipticE(((c+d*sin(f*x+e))/(c-d))^(1/2...
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.16 (sec) , antiderivative size = 1395, normalized size of antiderivative = 4.39 \[ \int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^{7/2}} \, dx=\text {Too large to display} \] Input:

integrate((a+a*sin(f*x+e))/(c+d*sin(f*x+e))^(7/2),x, algorithm="fricas")
 

Output:

-2/45*((6*a*c^6 + 5*a*c^5*d + 30*a*c^3*d^3 - 54*a*c^2*d^4 + 45*a*c*d^5 - 3 
*(6*a*c^4*d^2 + 5*a*c^3*d^3 - 18*a*c^2*d^4 + 15*a*c*d^5)*cos(f*x + e)^2 + 
(18*a*c^5*d + 15*a*c^4*d^2 - 48*a*c^3*d^3 + 50*a*c^2*d^4 - 18*a*c*d^5 + 15 
*a*d^6 - (6*a*c^3*d^3 + 5*a*c^2*d^4 - 18*a*c*d^5 + 15*a*d^6)*cos(f*x + e)^ 
2)*sin(f*x + e))*sqrt(1/2*I*d)*weierstrassPInverse(-4/3*(4*c^2 - 3*d^2)/d^ 
2, -8/27*(8*I*c^3 - 9*I*c*d^2)/d^3, 1/3*(3*d*cos(f*x + e) - 3*I*d*sin(f*x 
+ e) - 2*I*c)/d) + (6*a*c^6 + 5*a*c^5*d + 30*a*c^3*d^3 - 54*a*c^2*d^4 + 45 
*a*c*d^5 - 3*(6*a*c^4*d^2 + 5*a*c^3*d^3 - 18*a*c^2*d^4 + 15*a*c*d^5)*cos(f 
*x + e)^2 + (18*a*c^5*d + 15*a*c^4*d^2 - 48*a*c^3*d^3 + 50*a*c^2*d^4 - 18* 
a*c*d^5 + 15*a*d^6 - (6*a*c^3*d^3 + 5*a*c^2*d^4 - 18*a*c*d^5 + 15*a*d^6)*c 
os(f*x + e)^2)*sin(f*x + e))*sqrt(-1/2*I*d)*weierstrassPInverse(-4/3*(4*c^ 
2 - 3*d^2)/d^2, -8/27*(-8*I*c^3 + 9*I*c*d^2)/d^3, 1/3*(3*d*cos(f*x + e) + 
3*I*d*sin(f*x + e) + 2*I*c)/d) + 3*(3*I*a*c^5*d - 20*I*a*c^4*d^2 + 18*I*a* 
c^3*d^3 - 60*I*a*c^2*d^4 + 27*I*a*c*d^5 + 3*(-3*I*a*c^3*d^3 + 20*I*a*c^2*d 
^4 - 9*I*a*c*d^5)*cos(f*x + e)^2 + (9*I*a*c^4*d^2 - 60*I*a*c^3*d^3 + 30*I* 
a*c^2*d^4 - 20*I*a*c*d^5 + 9*I*a*d^6 + (-3*I*a*c^2*d^4 + 20*I*a*c*d^5 - 9* 
I*a*d^6)*cos(f*x + e)^2)*sin(f*x + e))*sqrt(1/2*I*d)*weierstrassZeta(-4/3* 
(4*c^2 - 3*d^2)/d^2, -8/27*(8*I*c^3 - 9*I*c*d^2)/d^3, weierstrassPInverse( 
-4/3*(4*c^2 - 3*d^2)/d^2, -8/27*(8*I*c^3 - 9*I*c*d^2)/d^3, 1/3*(3*d*cos(f* 
x + e) - 3*I*d*sin(f*x + e) - 2*I*c)/d)) + 3*(-3*I*a*c^5*d + 20*I*a*c^4...
 

Sympy [F(-1)]

Timed out. \[ \int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^{7/2}} \, dx=\text {Timed out} \] Input:

integrate((a+a*sin(f*x+e))/(c+d*sin(f*x+e))**(7/2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^{7/2}} \, dx=\int { \frac {a \sin \left (f x + e\right ) + a}{{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac {7}{2}}} \,d x } \] Input:

integrate((a+a*sin(f*x+e))/(c+d*sin(f*x+e))^(7/2),x, algorithm="maxima")
 

Output:

integrate((a*sin(f*x + e) + a)/(d*sin(f*x + e) + c)^(7/2), x)
 

Giac [F]

\[ \int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^{7/2}} \, dx=\int { \frac {a \sin \left (f x + e\right ) + a}{{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac {7}{2}}} \,d x } \] Input:

integrate((a+a*sin(f*x+e))/(c+d*sin(f*x+e))^(7/2),x, algorithm="giac")
 

Output:

integrate((a*sin(f*x + e) + a)/(d*sin(f*x + e) + c)^(7/2), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^{7/2}} \, dx=\int \frac {a+a\,\sin \left (e+f\,x\right )}{{\left (c+d\,\sin \left (e+f\,x\right )\right )}^{7/2}} \,d x \] Input:

int((a + a*sin(e + f*x))/(c + d*sin(e + f*x))^(7/2),x)
 

Output:

int((a + a*sin(e + f*x))/(c + d*sin(e + f*x))^(7/2), x)
 

Reduce [F]

\[ \int \frac {a+a \sin (e+f x)}{(c+d \sin (e+f x))^{7/2}} \, dx=a \left (\int \frac {\sqrt {\sin \left (f x +e \right ) d +c}}{\sin \left (f x +e \right )^{4} d^{4}+4 \sin \left (f x +e \right )^{3} c \,d^{3}+6 \sin \left (f x +e \right )^{2} c^{2} d^{2}+4 \sin \left (f x +e \right ) c^{3} d +c^{4}}d x +\int \frac {\sqrt {\sin \left (f x +e \right ) d +c}\, \sin \left (f x +e \right )}{\sin \left (f x +e \right )^{4} d^{4}+4 \sin \left (f x +e \right )^{3} c \,d^{3}+6 \sin \left (f x +e \right )^{2} c^{2} d^{2}+4 \sin \left (f x +e \right ) c^{3} d +c^{4}}d x \right ) \] Input:

int((a+a*sin(f*x+e))/(c+d*sin(f*x+e))^(7/2),x)
 

Output:

a*(int(sqrt(sin(e + f*x)*d + c)/(sin(e + f*x)**4*d**4 + 4*sin(e + f*x)**3* 
c*d**3 + 6*sin(e + f*x)**2*c**2*d**2 + 4*sin(e + f*x)*c**3*d + c**4),x) + 
int((sqrt(sin(e + f*x)*d + c)*sin(e + f*x))/(sin(e + f*x)**4*d**4 + 4*sin( 
e + f*x)**3*c*d**3 + 6*sin(e + f*x)**2*c**2*d**2 + 4*sin(e + f*x)*c**3*d + 
 c**4),x))