\(\int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx\) [759]

Optimal result

Integrand size = 27, antiderivative size = 390 \[ \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx=\frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b \left (a^2-b^2\right ) f (a+b \sin (e+f x))}-\frac {\left (2 a b c d-3 a^2 d^2-b^2 \left (c^2-2 d^2\right )\right ) E\left (\frac {1}{2} \left (e-\frac {\pi }{2}+f x\right )|\frac {2 d}{c+d}\right ) \sqrt {c+d \sin (e+f x)}}{b^2 \left (a^2-b^2\right ) f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}+\frac {(b c-a d) \left (2 a b c d+3 a^2 d^2-b^2 \left (c^2+4 d^2\right )\right ) \operatorname {EllipticF}\left (\frac {1}{2} \left (e-\frac {\pi }{2}+f x\right ),\frac {2 d}{c+d}\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}{b^3 \left (a^2-b^2\right ) f \sqrt {c+d \sin (e+f x)}}+\frac {(b c-a d)^2 \left (2 a b c+3 a^2 d-5 b^2 d\right ) \operatorname {EllipticPi}\left (\frac {2 b}{a+b},\frac {1}{2} \left (e-\frac {\pi }{2}+f x\right ),\frac {2 d}{c+d}\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}{(a-b) b^3 (a+b)^2 f \sqrt {c+d \sin (e+f x)}} \] Output:

(-a*d+b*c)^2*cos(f*x+e)*(c+d*sin(f*x+e))^(1/2)/b/(a^2-b^2)/f/(a+b*sin(f*x+ 
e))+(2*a*b*c*d-3*a^2*d^2-b^2*(c^2-2*d^2))*EllipticE(cos(1/2*e+1/4*Pi+1/2*f 
*x),2^(1/2)*(d/(c+d))^(1/2))*(c+d*sin(f*x+e))^(1/2)/b^2/(a^2-b^2)/f/((c+d* 
sin(f*x+e))/(c+d))^(1/2)+(-a*d+b*c)*(2*a*b*c*d+3*a^2*d^2-b^2*(c^2+4*d^2))* 
InverseJacobiAM(1/2*e-1/4*Pi+1/2*f*x,2^(1/2)*(d/(c+d))^(1/2))*((c+d*sin(f* 
x+e))/(c+d))^(1/2)/b^3/(a^2-b^2)/f/(c+d*sin(f*x+e))^(1/2)-(-a*d+b*c)^2*(3* 
a^2*d+2*a*b*c-5*b^2*d)*EllipticPi(cos(1/2*e+1/4*Pi+1/2*f*x),2*b/(a+b),2^(1 
/2)*(d/(c+d))^(1/2))*((c+d*sin(f*x+e))/(c+d))^(1/2)/(a-b)/b^3/(a+b)^2/f/(c 
+d*sin(f*x+e))^(1/2)
 

Mathematica [C] (warning: unable to verify)

Result contains complex when optimal does not.

Time = 10.65 (sec) , antiderivative size = 986, normalized size of antiderivative = 2.53 \[ \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx=\frac {\left (-b^2 c^2 \cos (e+f x)+2 a b c d \cos (e+f x)-a^2 d^2 \cos (e+f x)\right ) \sqrt {c+d \sin (e+f x)}}{b \left (-a^2+b^2\right ) f (a+b \sin (e+f x))}+\frac {-\frac {2 \left (4 a b c^3-9 b^2 c^2 d+6 a b c d^2+a^2 d^3-2 b^2 d^3\right ) \operatorname {EllipticPi}\left (\frac {2 b}{a+b},\frac {1}{2} \left (-e+\frac {\pi }{2}-f x\right ),\frac {2 d}{c+d}\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}{(a+b) \sqrt {c+d \sin (e+f x)}}-\frac {2 i \left (4 a b c^2 d+4 a^2 c d^2-12 b^2 c d^2+4 a b d^3\right ) \cos (e+f x) \left ((b c-a d) \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {-\frac {1}{c+d}} \sqrt {c+d \sin (e+f x)}\right ),\frac {c+d}{c-d}\right )+a d \operatorname {EllipticPi}\left (\frac {b (c+d)}{b c-a d},i \text {arcsinh}\left (\sqrt {-\frac {1}{c+d}} \sqrt {c+d \sin (e+f x)}\right ),\frac {c+d}{c-d}\right )\right ) \sqrt {\frac {d-d \sin (e+f x)}{c+d}} \sqrt {-\frac {d+d \sin (e+f x)}{c-d}} (-b c+a d+b (c+d \sin (e+f x)))}{b d^2 \sqrt {-\frac {1}{c+d}} (b c-a d) (a+b \sin (e+f x)) \sqrt {1-\sin ^2(e+f x)} \sqrt {-\frac {c^2-d^2-2 c (c+d \sin (e+f x))+(c+d \sin (e+f x))^2}{d^2}}}-\frac {2 i \left (-b^2 c^2 d+2 a b c d^2-3 a^2 d^3+2 b^2 d^3\right ) \cos (e+f x) \cos (2 (e+f x)) \left (2 b (c-d) (b c-a d) E\left (i \text {arcsinh}\left (\sqrt {-\frac {1}{c+d}} \sqrt {c+d \sin (e+f x)}\right )|\frac {c+d}{c-d}\right )+d \left (-2 (a+b) (-b c+a d) \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {-\frac {1}{c+d}} \sqrt {c+d \sin (e+f x)}\right ),\frac {c+d}{c-d}\right )+\left (2 a^2-b^2\right ) d \operatorname {EllipticPi}\left (\frac {b (c+d)}{b c-a d},i \text {arcsinh}\left (\sqrt {-\frac {1}{c+d}} \sqrt {c+d \sin (e+f x)}\right ),\frac {c+d}{c-d}\right )\right )\right ) \sqrt {\frac {d-d \sin (e+f x)}{c+d}} \sqrt {-\frac {d+d \sin (e+f x)}{c-d}} (-b c+a d+b (c+d \sin (e+f x)))}{b^2 d \sqrt {-\frac {1}{c+d}} (b c-a d) (a+b \sin (e+f x)) \sqrt {1-\sin ^2(e+f x)} \left (-2 c^2+d^2+4 c (c+d \sin (e+f x))-2 (c+d \sin (e+f x))^2\right ) \sqrt {-\frac {c^2-d^2-2 c (c+d \sin (e+f x))+(c+d \sin (e+f x))^2}{d^2}}}}{4 (a-b) b (a+b) f} \] Input:

Integrate[(c + d*Sin[e + f*x])^(5/2)/(a + b*Sin[e + f*x])^2,x]
 

Output:

((-(b^2*c^2*Cos[e + f*x]) + 2*a*b*c*d*Cos[e + f*x] - a^2*d^2*Cos[e + f*x]) 
*Sqrt[c + d*Sin[e + f*x]])/(b*(-a^2 + b^2)*f*(a + b*Sin[e + f*x])) + ((-2* 
(4*a*b*c^3 - 9*b^2*c^2*d + 6*a*b*c*d^2 + a^2*d^3 - 2*b^2*d^3)*EllipticPi[( 
2*b)/(a + b), (-e + Pi/2 - f*x)/2, (2*d)/(c + d)]*Sqrt[(c + d*Sin[e + f*x] 
)/(c + d)])/((a + b)*Sqrt[c + d*Sin[e + f*x]]) - ((2*I)*(4*a*b*c^2*d + 4*a 
^2*c*d^2 - 12*b^2*c*d^2 + 4*a*b*d^3)*Cos[e + f*x]*((b*c - a*d)*EllipticF[I 
*ArcSinh[Sqrt[-(c + d)^(-1)]*Sqrt[c + d*Sin[e + f*x]]], (c + d)/(c - d)] + 
 a*d*EllipticPi[(b*(c + d))/(b*c - a*d), I*ArcSinh[Sqrt[-(c + d)^(-1)]*Sqr 
t[c + d*Sin[e + f*x]]], (c + d)/(c - d)])*Sqrt[(d - d*Sin[e + f*x])/(c + d 
)]*Sqrt[-((d + d*Sin[e + f*x])/(c - d))]*(-(b*c) + a*d + b*(c + d*Sin[e + 
f*x])))/(b*d^2*Sqrt[-(c + d)^(-1)]*(b*c - a*d)*(a + b*Sin[e + f*x])*Sqrt[1 
 - Sin[e + f*x]^2]*Sqrt[-((c^2 - d^2 - 2*c*(c + d*Sin[e + f*x]) + (c + d*S 
in[e + f*x])^2)/d^2)]) - ((2*I)*(-(b^2*c^2*d) + 2*a*b*c*d^2 - 3*a^2*d^3 + 
2*b^2*d^3)*Cos[e + f*x]*Cos[2*(e + f*x)]*(2*b*(c - d)*(b*c - a*d)*Elliptic 
E[I*ArcSinh[Sqrt[-(c + d)^(-1)]*Sqrt[c + d*Sin[e + f*x]]], (c + d)/(c - d) 
] + d*(-2*(a + b)*(-(b*c) + a*d)*EllipticF[I*ArcSinh[Sqrt[-(c + d)^(-1)]*S 
qrt[c + d*Sin[e + f*x]]], (c + d)/(c - d)] + (2*a^2 - b^2)*d*EllipticPi[(b 
*(c + d))/(b*c - a*d), I*ArcSinh[Sqrt[-(c + d)^(-1)]*Sqrt[c + d*Sin[e + f* 
x]]], (c + d)/(c - d)]))*Sqrt[(d - d*Sin[e + f*x])/(c + d)]*Sqrt[-((d + d* 
Sin[e + f*x])/(c - d))]*(-(b*c) + a*d + b*(c + d*Sin[e + f*x])))/(b^2*d...
 

Rubi [A] (verified)

Time = 3.08 (sec) , antiderivative size = 393, normalized size of antiderivative = 1.01, number of steps used = 17, number of rules used = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.630, Rules used = {3042, 3271, 27, 3042, 3538, 3042, 3134, 3042, 3132, 3481, 3042, 3142, 3042, 3140, 3286, 3042, 3284}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2}dx\)

\(\Big \downarrow \) 3271

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\int \frac {a^2 d^3+5 b^2 c^2 d+\left (-\left (\left (c^2-2 d^2\right ) b^2\right )+2 a c d b-3 a^2 d^2\right ) \sin ^2(e+f x) d-2 \left (c d a^2+b \left (c^2+d^2\right ) a-3 b^2 c d\right ) \sin (e+f x) d-2 a b c \left (c^2+2 d^2\right )}{2 (a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\int \frac {a^2 d^3+5 b^2 c^2 d+\left (-\left (\left (c^2-2 d^2\right ) b^2\right )+2 a c d b-3 a^2 d^2\right ) \sin ^2(e+f x) d-2 \left (c d a^2+b \left (c^2+d^2\right ) a-3 b^2 c d\right ) \sin (e+f x) d-2 a b c \left (c^2+2 d^2\right )}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\int \frac {a^2 d^3+5 b^2 c^2 d+\left (-\left (\left (c^2-2 d^2\right ) b^2\right )+2 a c d b-3 a^2 d^2\right ) \sin (e+f x)^2 d-2 \left (c d a^2+b \left (c^2+d^2\right ) a-3 b^2 c d\right ) \sin (e+f x) d-2 a b c \left (c^2+2 d^2\right )}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3538

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {\left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \int \sqrt {c+d \sin (e+f x)}dx}{b}-\frac {\int \frac {d (b c-a d) \left (3 c d a^2+b \left (c^2+d^2\right ) a-5 b^2 c d\right )+d (b c-a d) \left (-\left (\left (c^2+4 d^2\right ) b^2\right )+2 a c d b+3 a^2 d^2\right ) \sin (e+f x)}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {\left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \int \sqrt {c+d \sin (e+f x)}dx}{b}-\frac {\int \frac {d (b c-a d) \left (3 c d a^2+b \left (c^2+d^2\right ) a-5 b^2 c d\right )+d (b c-a d) \left (-\left (\left (c^2+4 d^2\right ) b^2\right )+2 a c d b+3 a^2 d^2\right ) \sin (e+f x)}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3134

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {\left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} \int \sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}dx}{b \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\int \frac {d (b c-a d) \left (3 c d a^2+b \left (c^2+d^2\right ) a-5 b^2 c d\right )+d (b c-a d) \left (-\left (\left (c^2+4 d^2\right ) b^2\right )+2 a c d b+3 a^2 d^2\right ) \sin (e+f x)}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {\left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} \int \sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}dx}{b \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\int \frac {d (b c-a d) \left (3 c d a^2+b \left (c^2+d^2\right ) a-5 b^2 c d\right )+d (b c-a d) \left (-\left (\left (c^2+4 d^2\right ) b^2\right )+2 a c d b+3 a^2 d^2\right ) \sin (e+f x)}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3132

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {2 \left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{b f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\int \frac {d (b c-a d) \left (3 c d a^2+b \left (c^2+d^2\right ) a-5 b^2 c d\right )+d (b c-a d) \left (-\left (\left (c^2+4 d^2\right ) b^2\right )+2 a c d b+3 a^2 d^2\right ) \sin (e+f x)}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3481

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {2 \left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{b f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\frac {d \left (3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2+4 d^2\right )\right )\right ) (b c-a d) \int \frac {1}{\sqrt {c+d \sin (e+f x)}}dx}{b}+\frac {d \left (3 a^2 d+2 a b c-5 b^2 d\right ) (b c-a d)^2 \int \frac {1}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b}}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {2 \left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{b f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\frac {d \left (3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2+4 d^2\right )\right )\right ) (b c-a d) \int \frac {1}{\sqrt {c+d \sin (e+f x)}}dx}{b}+\frac {d \left (3 a^2 d+2 a b c-5 b^2 d\right ) (b c-a d)^2 \int \frac {1}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b}}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3142

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {2 \left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{b f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\frac {d \left (3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2+4 d^2\right )\right )\right ) (b c-a d) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \int \frac {1}{\sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}}dx}{b \sqrt {c+d \sin (e+f x)}}+\frac {d \left (3 a^2 d+2 a b c-5 b^2 d\right ) (b c-a d)^2 \int \frac {1}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b}}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {2 \left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{b f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\frac {d \left (3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2+4 d^2\right )\right )\right ) (b c-a d) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \int \frac {1}{\sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}}dx}{b \sqrt {c+d \sin (e+f x)}}+\frac {d \left (3 a^2 d+2 a b c-5 b^2 d\right ) (b c-a d)^2 \int \frac {1}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b}}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3140

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {2 \left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{b f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\frac {d \left (3 a^2 d+2 a b c-5 b^2 d\right ) (b c-a d)^2 \int \frac {1}{(a+b \sin (e+f x)) \sqrt {c+d \sin (e+f x)}}dx}{b}+\frac {2 d \left (3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2+4 d^2\right )\right )\right ) (b c-a d) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \operatorname {EllipticF}\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right ),\frac {2 d}{c+d}\right )}{b f \sqrt {c+d \sin (e+f x)}}}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3286

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {2 \left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{b f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\frac {d \left (3 a^2 d+2 a b c-5 b^2 d\right ) (b c-a d)^2 \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \int \frac {1}{(a+b \sin (e+f x)) \sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}}dx}{b \sqrt {c+d \sin (e+f x)}}+\frac {2 d \left (3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2+4 d^2\right )\right )\right ) (b c-a d) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \operatorname {EllipticF}\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right ),\frac {2 d}{c+d}\right )}{b f \sqrt {c+d \sin (e+f x)}}}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {2 \left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{b f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\frac {d \left (3 a^2 d+2 a b c-5 b^2 d\right ) (b c-a d)^2 \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \int \frac {1}{(a+b \sin (e+f x)) \sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}}dx}{b \sqrt {c+d \sin (e+f x)}}+\frac {2 d \left (3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2+4 d^2\right )\right )\right ) (b c-a d) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \operatorname {EllipticF}\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right ),\frac {2 d}{c+d}\right )}{b f \sqrt {c+d \sin (e+f x)}}}{b d}}{2 b \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3284

\(\displaystyle \frac {(b c-a d)^2 \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{b f \left (a^2-b^2\right ) (a+b \sin (e+f x))}-\frac {\frac {2 \left (-3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2-2 d^2\right )\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{b f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\frac {2 d \left (3 a^2 d^2+2 a b c d-\left (b^2 \left (c^2+4 d^2\right )\right )\right ) (b c-a d) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \operatorname {EllipticF}\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right ),\frac {2 d}{c+d}\right )}{b f \sqrt {c+d \sin (e+f x)}}+\frac {2 d \left (3 a^2 d+2 a b c-5 b^2 d\right ) (b c-a d)^2 \sqrt {\frac {c+d \sin (e+f x)}{c+d}} \operatorname {EllipticPi}\left (\frac {2 b}{a+b},\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right ),\frac {2 d}{c+d}\right )}{b f (a+b) \sqrt {c+d \sin (e+f x)}}}{b d}}{2 b \left (a^2-b^2\right )}\)

Input:

Int[(c + d*Sin[e + f*x])^(5/2)/(a + b*Sin[e + f*x])^2,x]
 

Output:

((b*c - a*d)^2*Cos[e + f*x]*Sqrt[c + d*Sin[e + f*x]])/(b*(a^2 - b^2)*f*(a 
+ b*Sin[e + f*x])) - ((2*(2*a*b*c*d - 3*a^2*d^2 - b^2*(c^2 - 2*d^2))*Ellip 
ticE[(e - Pi/2 + f*x)/2, (2*d)/(c + d)]*Sqrt[c + d*Sin[e + f*x]])/(b*f*Sqr 
t[(c + d*Sin[e + f*x])/(c + d)]) - ((2*d*(b*c - a*d)*(2*a*b*c*d + 3*a^2*d^ 
2 - b^2*(c^2 + 4*d^2))*EllipticF[(e - Pi/2 + f*x)/2, (2*d)/(c + d)]*Sqrt[( 
c + d*Sin[e + f*x])/(c + d)])/(b*f*Sqrt[c + d*Sin[e + f*x]]) + (2*d*(b*c - 
 a*d)^2*(2*a*b*c + 3*a^2*d - 5*b^2*d)*EllipticPi[(2*b)/(a + b), (e - Pi/2 
+ f*x)/2, (2*d)/(c + d)]*Sqrt[(c + d*Sin[e + f*x])/(c + d)])/(b*(a + b)*f* 
Sqrt[c + d*Sin[e + f*x]]))/(b*d))/(2*b*(a^2 - b^2))
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3132

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[2*(Sqrt[a 
 + b]/d)*EllipticE[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[{a, 
b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3134

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[a + 
b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c + d*x])/(a + b)]   Int[Sqrt[a/(a + b) + ( 
b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2 
, 0] &&  !GtQ[a + b, 0]
 

rule 3140

Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/(d*S 
qrt[a + b]))*EllipticF[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[ 
{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3142

Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[(a 
 + b*Sin[c + d*x])/(a + b)]/Sqrt[a + b*Sin[c + d*x]]   Int[1/Sqrt[a/(a + b) 
 + (b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - 
 b^2, 0] &&  !GtQ[a + b, 0]
 

rule 3271

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
 (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(-(b^2*c^2 - 2*a*b*c*d + a^2*d^2))*Co 
s[e + f*x]*(a + b*Sin[e + f*x])^(m - 2)*((c + d*Sin[e + f*x])^(n + 1)/(d*f* 
(n + 1)*(c^2 - d^2))), x] + Simp[1/(d*(n + 1)*(c^2 - d^2))   Int[(a + b*Sin 
[e + f*x])^(m - 3)*(c + d*Sin[e + f*x])^(n + 1)*Simp[b*(m - 2)*(b*c - a*d)^ 
2 + a*d*(n + 1)*(c*(a^2 + b^2) - 2*a*b*d) + (b*(n + 1)*(a*b*c^2 + c*d*(a^2 
+ b^2) - 3*a*b*d^2) - a*(n + 2)*(b*c - a*d)^2)*Sin[e + f*x] + b*(b^2*(c^2 - 
 d^2) - m*(b*c - a*d)^2 + d*n*(2*a*b*c - d*(a^2 + b^2)))*Sin[e + f*x]^2, x] 
, x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - 
b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 2] && LtQ[n, -1] && (IntegerQ[m] || 
IntegersQ[2*m, 2*n])
 

rule 3284

Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) 
 + (f_.)*(x_)]]), x_Symbol] :> Simp[(2/(f*(a + b)*Sqrt[c + d]))*EllipticPi[ 
2*(b/(a + b)), (1/2)*(e - Pi/2 + f*x), 2*(d/(c + d))], x] /; FreeQ[{a, b, c 
, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 
0] && GtQ[c + d, 0]
 

rule 3286

Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) 
 + (f_.)*(x_)]]), x_Symbol] :> Simp[Sqrt[(c + d*Sin[e + f*x])/(c + d)]/Sqrt 
[c + d*Sin[e + f*x]]   Int[1/((a + b*Sin[e + f*x])*Sqrt[c/(c + d) + (d/(c + 
 d))*Sin[e + f*x]]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a* 
d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] &&  !GtQ[c + d, 0]
 

rule 3481

Int[(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) 
+ (f_.)*(x_)]))/((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[ 
B/d   Int[(a + b*Sin[e + f*x])^m, x], x] - Simp[(B*c - A*d)/d   Int[(a + b* 
Sin[e + f*x])^m/(c + d*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, A, 
 B, m}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]
 

rule 3538

Int[((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^ 
2)/(Sqrt[(a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)]]*((c_.) + (d_.)*sin[(e_.) + 
(f_.)*(x_)])), x_Symbol] :> Simp[C/(b*d)   Int[Sqrt[a + b*Sin[e + f*x]], x] 
, x] - Simp[1/(b*d)   Int[Simp[a*c*C - A*b*d + (b*c*C - b*B*d + a*C*d)*Sin[ 
e + f*x], x]/(Sqrt[a + b*Sin[e + f*x]]*(c + d*Sin[e + f*x])), x], x] /; Fre 
eQ[{a, b, c, d, e, f, A, B, C}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0 
] && NeQ[c^2 - d^2, 0]
 

Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(1356\) vs. \(2(384)=768\).

Time = 21.45 (sec) , antiderivative size = 1357, normalized size of antiderivative = 3.48

method	result	size
default	\(\text {Expression too large to display}\)	\(1357\)

Input:

int((c+d*sin(f*x+e))^(5/2)/(a+b*sin(f*x+e))^2,x,method=_RETURNVERBOSE)
 

Output:

(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)*(d^2/b^3*(2*b*d*(c/d-1)*((c+d*sin( 
f*x+e))/(c-d))^(1/2)*(d*(1-sin(f*x+e))/(c+d))^(1/2)*(-d*(1+sin(f*x+e))/(c- 
d))^(1/2)/(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)*((-c/d-1)*EllipticE(((c+ 
d*sin(f*x+e))/(c-d))^(1/2),((c-d)/(c+d))^(1/2))+EllipticF(((c+d*sin(f*x+e) 
)/(c-d))^(1/2),((c-d)/(c+d))^(1/2)))-4*a*d*(c/d-1)*((c+d*sin(f*x+e))/(c-d) 
)^(1/2)*(d*(1-sin(f*x+e))/(c+d))^(1/2)*(-d*(1+sin(f*x+e))/(c-d))^(1/2)/(-( 
-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)*EllipticF(((c+d*sin(f*x+e))/(c-d))^(1 
/2),((c-d)/(c+d))^(1/2))+6*b*c*(c/d-1)*((c+d*sin(f*x+e))/(c-d))^(1/2)*(d*( 
1-sin(f*x+e))/(c+d))^(1/2)*(-d*(1+sin(f*x+e))/(c-d))^(1/2)/(-(-c-d*sin(f*x 
+e))*cos(f*x+e)^2)^(1/2)*EllipticF(((c+d*sin(f*x+e))/(c-d))^(1/2),((c-d)/( 
c+d))^(1/2)))-(a^3*d^3-3*a^2*b*c*d^2+3*a*b^2*c^2*d-b^3*c^3)/b^3*(-b^2/(a^3 
*d-a^2*b*c-a*b^2*d+b^3*c)*(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)/(a+b*sin 
(f*x+e))-a*d/(a^3*d-a^2*b*c-a*b^2*d+b^3*c)*(c/d-1)*((c+d*sin(f*x+e))/(c-d) 
)^(1/2)*(d*(1-sin(f*x+e))/(c+d))^(1/2)*(-d*(1+sin(f*x+e))/(c-d))^(1/2)/(-( 
-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)*EllipticF(((c+d*sin(f*x+e))/(c-d))^(1 
/2),((c-d)/(c+d))^(1/2))-b*d/(a^3*d-a^2*b*c-a*b^2*d+b^3*c)*(c/d-1)*((c+d*s 
in(f*x+e))/(c-d))^(1/2)*(d*(1-sin(f*x+e))/(c+d))^(1/2)*(-d*(1+sin(f*x+e))/ 
(c-d))^(1/2)/(-(-c-d*sin(f*x+e))*cos(f*x+e)^2)^(1/2)*((-c/d-1)*EllipticE(( 
(c+d*sin(f*x+e))/(c-d))^(1/2),((c-d)/(c+d))^(1/2))+EllipticF(((c+d*sin(f*x 
+e))/(c-d))^(1/2),((c-d)/(c+d))^(1/2)))+(3*a^2*d-2*a*b*c-b^2*d)/(a^3*d-...
 

Fricas [F(-1)]

Timed out. \[ \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx=\text {Timed out} \] Input:

integrate((c+d*sin(f*x+e))^(5/2)/(a+b*sin(f*x+e))^2,x, algorithm="fricas")
 

Output:

Timed out
 

Sympy [F(-1)]

Timed out. \[ \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx=\text {Timed out} \] Input:

integrate((c+d*sin(f*x+e))**(5/2)/(a+b*sin(f*x+e))**2,x)
                                                                                    
                                                                                    
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx=\int { \frac {{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac {5}{2}}}{{\left (b \sin \left (f x + e\right ) + a\right )}^{2}} \,d x } \] Input:

integrate((c+d*sin(f*x+e))^(5/2)/(a+b*sin(f*x+e))^2,x, algorithm="maxima")
 

Output:

integrate((d*sin(f*x + e) + c)^(5/2)/(b*sin(f*x + e) + a)^2, x)
 

Giac [F]

\[ \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx=\int { \frac {{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac {5}{2}}}{{\left (b \sin \left (f x + e\right ) + a\right )}^{2}} \,d x } \] Input:

integrate((c+d*sin(f*x+e))^(5/2)/(a+b*sin(f*x+e))^2,x, algorithm="giac")
 

Output:

integrate((d*sin(f*x + e) + c)^(5/2)/(b*sin(f*x + e) + a)^2, x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx=\int \frac {{\left (c+d\,\sin \left (e+f\,x\right )\right )}^{5/2}}{{\left (a+b\,\sin \left (e+f\,x\right )\right )}^2} \,d x \] Input:

int((c + d*sin(e + f*x))^(5/2)/(a + b*sin(e + f*x))^2,x)
 

Output:

int((c + d*sin(e + f*x))^(5/2)/(a + b*sin(e + f*x))^2, x)
 

Reduce [F]

\[ \int \frac {(c+d \sin (e+f x))^{5/2}}{(a+b \sin (e+f x))^2} \, dx=\left (\int \frac {\sqrt {\sin \left (f x +e \right ) d +c}}{\sin \left (f x +e \right )^{2} b^{2}+2 \sin \left (f x +e \right ) a b +a^{2}}d x \right ) c^{2}+\left (\int \frac {\sqrt {\sin \left (f x +e \right ) d +c}\, \sin \left (f x +e \right )^{2}}{\sin \left (f x +e \right )^{2} b^{2}+2 \sin \left (f x +e \right ) a b +a^{2}}d x \right ) d^{2}+2 \left (\int \frac {\sqrt {\sin \left (f x +e \right ) d +c}\, \sin \left (f x +e \right )}{\sin \left (f x +e \right )^{2} b^{2}+2 \sin \left (f x +e \right ) a b +a^{2}}d x \right ) c d \] Input:

int((c+d*sin(f*x+e))^(5/2)/(a+b*sin(f*x+e))^2,x)
 

Output:

int(sqrt(sin(e + f*x)*d + c)/(sin(e + f*x)**2*b**2 + 2*sin(e + f*x)*a*b + 
a**2),x)*c**2 + int((sqrt(sin(e + f*x)*d + c)*sin(e + f*x)**2)/(sin(e + f* 
x)**2*b**2 + 2*sin(e + f*x)*a*b + a**2),x)*d**2 + 2*int((sqrt(sin(e + f*x) 
*d + c)*sin(e + f*x))/(sin(e + f*x)**2*b**2 + 2*sin(e + f*x)*a*b + a**2),x 
)*c*d