Integrand size = 27, antiderivative size = 303 \[ \int \frac {\cos (c+d x) \cot ^5(c+d x)}{(a+b \sin (c+d x))^2} \, dx=-\frac {10 b \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^6 d}-\frac {5 \left (3 a^4-12 a^2 b^2+8 b^4\right ) \text {arctanh}(\cos (c+d x))}{8 a^6 d}+\frac {\left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{3 a^5 b d}+\frac {5 \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{3 a^3 d (a+b \sin (c+d x))}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))} \] Output:
-10*b*(a^2-b^2)^(3/2)*arctan((b+a*tan(1/2*d*x+1/2*c))/(a^2-b^2)^(1/2))/a^6 /d-5/8*(3*a^4-12*a^2*b^2+8*b^4)*arctanh(cos(d*x+c))/a^6/d+1/3*(3*a^4-20*a^ 2*b^2+15*b^4)*cot(d*x+c)/a^5/b/d+5/8*(5*a^2-4*b^2)*cot(d*x+c)*csc(d*x+c)/a ^4/d-cot(d*x+c)/b/d/(a+b*sin(d*x+c))-1/3*(6*a^2-5*b^2)*cot(d*x+c)*csc(d*x+ c)/a^3/d/(a+b*sin(d*x+c))+5/12*b*cot(d*x+c)*csc(d*x+c)^2/a^2/d/(a+b*sin(d* x+c))-1/4*cot(d*x+c)*csc(d*x+c)^3/a/d/(a+b*sin(d*x+c))
Time = 6.65 (sec) , antiderivative size = 487, normalized size of antiderivative = 1.61 \[ \int \frac {\cos (c+d x) \cot ^5(c+d x)}{(a+b \sin (c+d x))^2} \, dx=-\frac {10 b \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {\sec \left (\frac {1}{2} (c+d x)\right ) \left (b \cos \left (\frac {1}{2} (c+d x)\right )+a \sin \left (\frac {1}{2} (c+d x)\right )\right )}{\sqrt {a^2-b^2}}\right )}{a^6 d}+\frac {\left (-7 a^2 b \cos \left (\frac {1}{2} (c+d x)\right )+6 b^3 \cos \left (\frac {1}{2} (c+d x)\right )\right ) \csc \left (\frac {1}{2} (c+d x)\right )}{3 a^5 d}+\frac {3 \left (3 a^2-4 b^2\right ) \csc ^2\left (\frac {1}{2} (c+d x)\right )}{32 a^4 d}+\frac {b \cot \left (\frac {1}{2} (c+d x)\right ) \csc ^2\left (\frac {1}{2} (c+d x)\right )}{12 a^3 d}-\frac {\csc ^4\left (\frac {1}{2} (c+d x)\right )}{64 a^2 d}-\frac {5 \left (3 a^4-12 a^2 b^2+8 b^4\right ) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )}{8 a^6 d}+\frac {5 \left (3 a^4-12 a^2 b^2+8 b^4\right ) \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )}{8 a^6 d}-\frac {3 \left (3 a^2-4 b^2\right ) \sec ^2\left (\frac {1}{2} (c+d x)\right )}{32 a^4 d}+\frac {\sec ^4\left (\frac {1}{2} (c+d x)\right )}{64 a^2 d}+\frac {\sec \left (\frac {1}{2} (c+d x)\right ) \left (7 a^2 b \sin \left (\frac {1}{2} (c+d x)\right )-6 b^3 \sin \left (\frac {1}{2} (c+d x)\right )\right )}{3 a^5 d}+\frac {a^4 \cos (c+d x)-2 a^2 b^2 \cos (c+d x)+b^4 \cos (c+d x)}{a^5 d (a+b \sin (c+d x))}-\frac {b \sec ^2\left (\frac {1}{2} (c+d x)\right ) \tan \left (\frac {1}{2} (c+d x)\right )}{12 a^3 d} \] Input:
Integrate[(Cos[c + d*x]*Cot[c + d*x]^5)/(a + b*Sin[c + d*x])^2,x]
Output:
(-10*b*(a^2 - b^2)^(3/2)*ArcTan[(Sec[(c + d*x)/2]*(b*Cos[(c + d*x)/2] + a* Sin[(c + d*x)/2]))/Sqrt[a^2 - b^2]])/(a^6*d) + ((-7*a^2*b*Cos[(c + d*x)/2] + 6*b^3*Cos[(c + d*x)/2])*Csc[(c + d*x)/2])/(3*a^5*d) + (3*(3*a^2 - 4*b^2 )*Csc[(c + d*x)/2]^2)/(32*a^4*d) + (b*Cot[(c + d*x)/2]*Csc[(c + d*x)/2]^2) /(12*a^3*d) - Csc[(c + d*x)/2]^4/(64*a^2*d) - (5*(3*a^4 - 12*a^2*b^2 + 8*b ^4)*Log[Cos[(c + d*x)/2]])/(8*a^6*d) + (5*(3*a^4 - 12*a^2*b^2 + 8*b^4)*Log [Sin[(c + d*x)/2]])/(8*a^6*d) - (3*(3*a^2 - 4*b^2)*Sec[(c + d*x)/2]^2)/(32 *a^4*d) + Sec[(c + d*x)/2]^4/(64*a^2*d) + (Sec[(c + d*x)/2]*(7*a^2*b*Sin[( c + d*x)/2] - 6*b^3*Sin[(c + d*x)/2]))/(3*a^5*d) + (a^4*Cos[c + d*x] - 2*a ^2*b^2*Cos[c + d*x] + b^4*Cos[c + d*x])/(a^5*d*(a + b*Sin[c + d*x])) - (b* Sec[(c + d*x)/2]^2*Tan[(c + d*x)/2])/(12*a^3*d)
Time = 2.52 (sec) , antiderivative size = 377, normalized size of antiderivative = 1.24, number of steps used = 18, number of rules used = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.630, Rules used = {3042, 3375, 27, 3042, 3534, 3042, 3534, 3042, 3534, 27, 3042, 3480, 3042, 3139, 1083, 217, 4257}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {\cos (c+d x) \cot ^5(c+d x)}{(a+b \sin (c+d x))^2} \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {\cos (c+d x)^6}{\sin (c+d x)^5 (a+b \sin (c+d x))^2}dx\) |
| \(\Big \downarrow \) 3375 |
| \(\displaystyle \frac {\int -\frac {2 \csc ^3(c+d x) \left (-3 \left (4 a^2-5 b^2\right ) \sin ^2(c+d x) b^2+\left (27 a^2-20 b^2\right ) b^2+2 a \left (6 a^2-b^2\right ) \sin (c+d x) b\right )}{(a+b \sin (c+d x))^2}dx}{24 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {\int \frac {\csc ^3(c+d x) \left (-3 \left (4 a^2-5 b^2\right ) \sin ^2(c+d x) b^2+\left (27 a^2-20 b^2\right ) b^2+2 a \left (6 a^2-b^2\right ) \sin (c+d x) b\right )}{(a+b \sin (c+d x))^2}dx}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {\int \frac {-3 \left (4 a^2-5 b^2\right ) \sin (c+d x)^2 b^2+\left (27 a^2-20 b^2\right ) b^2+2 a \left (6 a^2-b^2\right ) \sin (c+d x) b}{\sin (c+d x)^3 (a+b \sin (c+d x))^2}dx}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3534 |
| \(\displaystyle -\frac {\frac {\int \frac {\csc ^3(c+d x) \left (-8 \left (6 a^4-11 b^2 a^2+5 b^4\right ) \sin ^2(c+d x) b^2+15 \left (5 a^4-9 b^2 a^2+4 b^4\right ) b^2+a \left (12 a^4-17 b^2 a^2+5 b^4\right ) \sin (c+d x) b\right )}{a+b \sin (c+d x)}dx}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {\frac {\int \frac {-8 \left (6 a^4-11 b^2 a^2+5 b^4\right ) \sin (c+d x)^2 b^2+15 \left (5 a^4-9 b^2 a^2+4 b^4\right ) b^2+a \left (12 a^4-17 b^2 a^2+5 b^4\right ) \sin (c+d x) b}{\sin (c+d x)^3 (a+b \sin (c+d x))}dx}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3534 |
| \(\displaystyle -\frac {\frac {\frac {\int \frac {\csc ^2(c+d x) \left (15 \left (5 a^4-9 b^2 a^2+4 b^4\right ) \sin ^2(c+d x) b^3-a \left (21 a^4-41 b^2 a^2+20 b^4\right ) \sin (c+d x) b^2+8 \left (3 a^6-23 b^2 a^4+35 b^4 a^2-15 b^6\right ) b\right )}{a+b \sin (c+d x)}dx}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {\frac {\frac {\int \frac {15 \left (5 a^4-9 b^2 a^2+4 b^4\right ) \sin (c+d x)^2 b^3-a \left (21 a^4-41 b^2 a^2+20 b^4\right ) \sin (c+d x) b^2+8 \left (3 a^6-23 b^2 a^4+35 b^4 a^2-15 b^6\right ) b}{\sin (c+d x)^2 (a+b \sin (c+d x))}dx}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3534 |
| \(\displaystyle -\frac {\frac {\frac {\frac {\int -\frac {15 \csc (c+d x) \left (b^2 \left (3 a^6-15 b^2 a^4+20 b^4 a^2-8 b^6\right )-a b^3 \left (5 a^4-9 b^2 a^2+4 b^4\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)}dx}{a}-\frac {8 b \left (3 a^6-23 a^4 b^2+35 a^2 b^4-15 b^6\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle -\frac {\frac {\frac {-\frac {15 \int \frac {\csc (c+d x) \left (b^2 \left (3 a^6-15 b^2 a^4+20 b^4 a^2-8 b^6\right )-a b^3 \left (5 a^4-9 b^2 a^2+4 b^4\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)}dx}{a}-\frac {8 b \left (3 a^6-23 a^4 b^2+35 a^2 b^4-15 b^6\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {\frac {\frac {-\frac {15 \int \frac {b^2 \left (3 a^6-15 b^2 a^4+20 b^4 a^2-8 b^6\right )-a b^3 \left (5 a^4-9 b^2 a^2+4 b^4\right ) \sin (c+d x)}{\sin (c+d x) (a+b \sin (c+d x))}dx}{a}-\frac {8 b \left (3 a^6-23 a^4 b^2+35 a^2 b^4-15 b^6\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3480 |
| \(\displaystyle -\frac {\frac {\frac {-\frac {15 \left (\frac {b^2 \left (3 a^6-15 a^4 b^2+20 a^2 b^4-8 b^6\right ) \int \csc (c+d x)dx}{a}-\frac {8 b^3 \left (a^2-b^2\right )^3 \int \frac {1}{a+b \sin (c+d x)}dx}{a}\right )}{a}-\frac {8 b \left (3 a^6-23 a^4 b^2+35 a^2 b^4-15 b^6\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\frac {\frac {\frac {-\frac {15 \left (\frac {b^2 \left (3 a^6-15 a^4 b^2+20 a^2 b^4-8 b^6\right ) \int \csc (c+d x)dx}{a}-\frac {8 b^3 \left (a^2-b^2\right )^3 \int \frac {1}{a+b \sin (c+d x)}dx}{a}\right )}{a}-\frac {8 b \left (3 a^6-23 a^4 b^2+35 a^2 b^4-15 b^6\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 3139 |
| \(\displaystyle -\frac {\frac {\frac {-\frac {15 \left (\frac {b^2 \left (3 a^6-15 a^4 b^2+20 a^2 b^4-8 b^6\right ) \int \csc (c+d x)dx}{a}-\frac {16 b^3 \left (a^2-b^2\right )^3 \int \frac {1}{a \tan ^2\left (\frac {1}{2} (c+d x)\right )+2 b \tan \left (\frac {1}{2} (c+d x)\right )+a}d\tan \left (\frac {1}{2} (c+d x)\right )}{a d}\right )}{a}-\frac {8 b \left (3 a^6-23 a^4 b^2+35 a^2 b^4-15 b^6\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 1083 |
| \(\displaystyle -\frac {\frac {\frac {-\frac {15 \left (\frac {32 b^3 \left (a^2-b^2\right )^3 \int \frac {1}{-\left (2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )^2-4 \left (a^2-b^2\right )}d\left (2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a d}+\frac {b^2 \left (3 a^6-15 a^4 b^2+20 a^2 b^4-8 b^6\right ) \int \csc (c+d x)dx}{a}\right )}{a}-\frac {8 b \left (3 a^6-23 a^4 b^2+35 a^2 b^4-15 b^6\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 217 |
| \(\displaystyle -\frac {\frac {\frac {-\frac {15 \left (\frac {b^2 \left (3 a^6-15 a^4 b^2+20 a^2 b^4-8 b^6\right ) \int \csc (c+d x)dx}{a}-\frac {16 b^3 \left (a^2-b^2\right )^{5/2} \arctan \left (\frac {2 a \tan \left (\frac {1}{2} (c+d x)\right )+2 b}{2 \sqrt {a^2-b^2}}\right )}{a d}\right )}{a}-\frac {8 b \left (3 a^6-23 a^4 b^2+35 a^2 b^4-15 b^6\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}+\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}}{12 a^2 b^2}+\frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
| \(\Big \downarrow \) 4257 |
| \(\displaystyle \frac {5 b \cot (c+d x) \csc ^2(c+d x)}{12 a^2 d (a+b \sin (c+d x))}-\frac {\frac {4 b^2 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc (c+d x)}{a d (a+b \sin (c+d x))}+\frac {\frac {-\frac {15 \left (-\frac {16 b^3 \left (a^2-b^2\right )^{5/2} \arctan \left (\frac {2 a \tan \left (\frac {1}{2} (c+d x)\right )+2 b}{2 \sqrt {a^2-b^2}}\right )}{a d}-\frac {b^2 \left (3 a^6-15 a^4 b^2+20 a^2 b^4-8 b^6\right ) \text {arctanh}(\cos (c+d x))}{a d}\right )}{a}-\frac {8 b \left (3 a^6-23 a^4 b^2+35 a^2 b^4-15 b^6\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b^2 \left (5 a^4-9 a^2 b^2+4 b^4\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{a \left (a^2-b^2\right )}}{12 a^2 b^2}-\frac {\cot (c+d x)}{b d (a+b \sin (c+d x))}-\frac {\cot (c+d x) \csc ^3(c+d x)}{4 a d (a+b \sin (c+d x))}\) |
Input:
Int[(Cos[c + d*x]*Cot[c + d*x]^5)/(a + b*Sin[c + d*x])^2,x]
Output:
-(Cot[c + d*x]/(b*d*(a + b*Sin[c + d*x]))) + (5*b*Cot[c + d*x]*Csc[c + d*x ]^2)/(12*a^2*d*(a + b*Sin[c + d*x])) - (Cot[c + d*x]*Csc[c + d*x]^3)/(4*a* d*(a + b*Sin[c + d*x])) - ((((-15*((-16*b^3*(a^2 - b^2)^(5/2)*ArcTan[(2*b + 2*a*Tan[(c + d*x)/2])/(2*Sqrt[a^2 - b^2])])/(a*d) - (b^2*(3*a^6 - 15*a^4 *b^2 + 20*a^2*b^4 - 8*b^6)*ArcTanh[Cos[c + d*x]])/(a*d)))/a - (8*b*(3*a^6 - 23*a^4*b^2 + 35*a^2*b^4 - 15*b^6)*Cot[c + d*x])/(a*d))/(2*a) - (15*b^2*( 5*a^4 - 9*a^2*b^2 + 4*b^4)*Cot[c + d*x]*Csc[c + d*x])/(2*a*d))/(a*(a^2 - b ^2)) + (4*b^2*(6*a^2 - 5*b^2)*Cot[c + d*x]*Csc[c + d*x])/(a*d*(a + b*Sin[c + d*x])))/(12*a^2*b^2)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Simp[-2 Subst[I nt[1/Simp[b^2 - 4*a*c - x^2, x], x], x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x]
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{e = Fre eFactors[Tan[(c + d*x)/2], x]}, Simp[2*(e/d) Subst[Int[1/(a + 2*b*e*x + a *e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}, x] && NeQ [a^2 - b^2, 0]
Int[cos[(e_.) + (f_.)*(x_)]^6*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[Cos[e + f*x]*(d*Sin[ e + f*x])^(n + 1)*((a + b*Sin[e + f*x])^(m + 1)/(a*d*f*(n + 1))), x] + (-Si mp[b*(m + n + 2)*Cos[e + f*x]*(d*Sin[e + f*x])^(n + 2)*((a + b*Sin[e + f*x] )^(m + 1)/(a^2*d^2*f*(n + 1)*(n + 2))), x] - Simp[a*(n + 5)*Cos[e + f*x]*(d *Sin[e + f*x])^(n + 3)*((a + b*Sin[e + f*x])^(m + 1)/(b^2*d^3*f*(m + n + 5) *(m + n + 6))), x] + Simp[Cos[e + f*x]*(d*Sin[e + f*x])^(n + 4)*((a + b*Sin [e + f*x])^(m + 1)/(b*d^4*f*(m + n + 6))), x] + Simp[1/(a^2*b^2*d^2*(n + 1) *(n + 2)*(m + n + 5)*(m + n + 6)) Int[(d*Sin[e + f*x])^(n + 2)*(a + b*Sin [e + f*x])^m*Simp[a^4*(n + 1)*(n + 2)*(n + 3)*(n + 5) - a^2*b^2*(n + 2)*(2* n + 1)*(m + n + 5)*(m + n + 6) + b^4*(m + n + 2)*(m + n + 3)*(m + n + 5)*(m + n + 6) + a*b*m*(a^2*(n + 1)*(n + 2) - b^2*(m + n + 5)*(m + n + 6))*Sin[e + f*x] - (a^4*(n + 1)*(n + 2)*(4 + n)*(n + 5) + b^4*(m + n + 2)*(m + n + 4 )*(m + n + 5)*(m + n + 6) - a^2*b^2*(n + 1)*(n + 2)*(m + n + 5)*(2*n + 2*m + 13))*Sin[e + f*x]^2, x], x], x]) /; FreeQ[{a, b, d, e, f, m, n}, x] && Ne Q[a^2 - b^2, 0] && IntegersQ[2*m, 2*n] && NeQ[n, -1] && NeQ[n, -2] && NeQ[m + n + 5, 0] && NeQ[m + n + 6, 0] && !IGtQ[m, 0]
Int[((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])/(((a_.) + (b_.)*sin[(e_.) + (f_ .)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])), x_Symbol] :> Simp[(A*b - a*B)/(b*c - a*d) Int[1/(a + b*Sin[e + f*x]), x], x] + Simp[(B*c - A*d)/ (b*c - a*d) Int[1/(c + d*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f , A, B}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(A*b^2 - a*b*B + a^2*C))*Cos[e + f*x ]*(a + b*Sin[e + f*x])^(m + 1)*((c + d*Sin[e + f*x])^(n + 1)/(f*(m + 1)*(b* c - a*d)*(a^2 - b^2))), x] + Simp[1/((m + 1)*(b*c - a*d)*(a^2 - b^2)) Int [(a + b*Sin[e + f*x])^(m + 1)*(c + d*Sin[e + f*x])^n*Simp[(m + 1)*(b*c - a* d)*(a*A - b*B + a*C) + d*(A*b^2 - a*b*B + a^2*C)*(m + n + 2) - (c*(A*b^2 - a*b*B + a^2*C) + (m + 1)*(b*c - a*d)*(A*b - a*B + b*C))*Sin[e + f*x] - d*(A *b^2 - a*b*B + a^2*C)*(m + n + 3)*Sin[e + f*x]^2, x], x], x] /; FreeQ[{a, b , c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && LtQ[m, -1] && ((EqQ[a, 0] && IntegerQ[m] && !IntegerQ [n]) || !(IntegerQ[2*n] && LtQ[n, -1] && ((IntegerQ[n] && !IntegerQ[m]) | | EqQ[a, 0])))
Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]
Time = 1.99 (sec) , antiderivative size = 370, normalized size of antiderivative = 1.22
| method | result | size |
| derivativedivides | \(\frac {\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} a^{3}}{4}-\frac {4 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3} a^{2}}{3}-4 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a^{3}+6 a \,b^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+36 a^{2} b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-32 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{3}}{16 a^{5}}-\frac {1}{64 a^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}-\frac {-8 a^{2}+12 b^{2}}{32 a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}+\frac {\left (30 a^{4}-120 a^{2} b^{2}+80 b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 a^{6}}+\frac {b}{12 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}-\frac {b \left (9 a^{2}-8 b^{2}\right )}{4 a^{5} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}-\frac {4 \left (\frac {-\frac {b \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2}-\frac {a^{5}}{2}+a^{3} b^{2}-\frac {a \,b^{4}}{2}}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a}+\frac {5 b \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}}\right )}{a^{6}}}{d}\) | \(370\) |
| default | \(\frac {\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} a^{3}}{4}-\frac {4 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3} a^{2}}{3}-4 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a^{3}+6 a \,b^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+36 a^{2} b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-32 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{3}}{16 a^{5}}-\frac {1}{64 a^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}-\frac {-8 a^{2}+12 b^{2}}{32 a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}+\frac {\left (30 a^{4}-120 a^{2} b^{2}+80 b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 a^{6}}+\frac {b}{12 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}-\frac {b \left (9 a^{2}-8 b^{2}\right )}{4 a^{5} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}-\frac {4 \left (\frac {-\frac {b \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2}-\frac {a^{5}}{2}+a^{3} b^{2}-\frac {a \,b^{4}}{2}}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a}+\frac {5 b \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}}\right )}{a^{6}}}{d}\) | \(370\) |
| risch | \(\frac {i \left (120 b^{5}+680 a^{2} b^{3} {\mathrm e}^{2 i \left (d x +c \right )}-30 b \,a^{4} {\mathrm e}^{8 i \left (d x +c \right )}+600 a^{2} b^{3} {\mathrm e}^{6 i \left (d x +c \right )}-90 b \,a^{4} {\mathrm e}^{6 i \left (d x +c \right )}-120 a^{2} b^{3} {\mathrm e}^{8 i \left (d x +c \right )}-24 i a^{5} {\mathrm e}^{9 i \left (d x +c \right )}-144 i a^{5} {\mathrm e}^{5 i \left (d x +c \right )}+96 i a^{5} {\mathrm e}^{7 i \left (d x +c \right )}+600 i a \,b^{4} {\mathrm e}^{3 i \left (d x +c \right )}+75 i a^{3} b^{2} {\mathrm e}^{9 i \left (d x +c \right )}-60 i a \,b^{4} {\mathrm e}^{9 i \left (d x +c \right )}-510 i a^{3} b^{2} {\mathrm e}^{7 i \left (d x +c \right )}-770 i a^{3} b^{2} {\mathrm e}^{3 i \left (d x +c \right )}+360 i a \,b^{4} {\mathrm e}^{7 i \left (d x +c \right )}-160 a^{2} b^{3}+24 a^{4} b +150 a^{4} b \,{\mathrm e}^{4 i \left (d x +c \right )}-150 a^{4} b \,{\mathrm e}^{2 i \left (d x +c \right )}-24 i a^{5} {\mathrm e}^{i \left (d x +c \right )}+96 i a^{5} {\mathrm e}^{3 i \left (d x +c \right )}-1000 a^{2} b^{3} {\mathrm e}^{4 i \left (d x +c \right )}-480 b^{5} {\mathrm e}^{6 i \left (d x +c \right )}+120 b^{5} {\mathrm e}^{8 i \left (d x +c \right )}+720 b^{5} {\mathrm e}^{4 i \left (d x +c \right )}-480 b^{5} {\mathrm e}^{2 i \left (d x +c \right )}-180 i a \,b^{4} {\mathrm e}^{i \left (d x +c \right )}+960 i a^{3} b^{2} {\mathrm e}^{5 i \left (d x +c \right )}+245 i a^{3} b^{2} {\mathrm e}^{i \left (d x +c \right )}-720 i a \,b^{4} {\mathrm e}^{5 i \left (d x +c \right )}\right )}{12 \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{4} b \left (b \,{\mathrm e}^{2 i \left (d x +c \right )}-b +2 i a \,{\mathrm e}^{i \left (d x +c \right )}\right ) d \,a^{5}}-\frac {15 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{8 d \,a^{2}}+\frac {15 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right ) b^{2}}{2 a^{4} d}-\frac {5 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right ) b^{4}}{a^{6} d}+\frac {5 i \sqrt {a^{2}-b^{2}}\, b \ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {i \left (\sqrt {a^{2}-b^{2}}-a \right )}{b}\right )}{d \,a^{4}}-\frac {5 i \sqrt {a^{2}-b^{2}}\, b^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {i \left (\sqrt {a^{2}-b^{2}}-a \right )}{b}\right )}{d \,a^{6}}-\frac {5 i \sqrt {a^{2}-b^{2}}\, b \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}+a \right )}{b}\right )}{d \,a^{4}}+\frac {5 i \sqrt {a^{2}-b^{2}}\, b^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}+a \right )}{b}\right )}{d \,a^{6}}+\frac {15 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{8 d \,a^{2}}-\frac {15 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right ) b^{2}}{2 a^{4} d}+\frac {5 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right ) b^{4}}{a^{6} d}\) | \(850\) |
Input:
int(cos(d*x+c)*cot(d*x+c)^5/(a+b*sin(d*x+c))^2,x,method=_RETURNVERBOSE)
Output:
1/d*(1/16/a^5*(1/4*tan(1/2*d*x+1/2*c)^4*a^3-4/3*b*tan(1/2*d*x+1/2*c)^3*a^2 -4*tan(1/2*d*x+1/2*c)^2*a^3+6*a*b^2*tan(1/2*d*x+1/2*c)^2+36*a^2*b*tan(1/2* d*x+1/2*c)-32*tan(1/2*d*x+1/2*c)*b^3)-1/64/a^2/tan(1/2*d*x+1/2*c)^4-1/32*( -8*a^2+12*b^2)/a^4/tan(1/2*d*x+1/2*c)^2+1/16/a^6*(30*a^4-120*a^2*b^2+80*b^ 4)*ln(tan(1/2*d*x+1/2*c))+1/12/a^3*b/tan(1/2*d*x+1/2*c)^3-1/4*b*(9*a^2-8*b ^2)/a^5/tan(1/2*d*x+1/2*c)-4/a^6*((-1/2*b*(a^4-2*a^2*b^2+b^4)*tan(1/2*d*x+ 1/2*c)-1/2*a^5+a^3*b^2-1/2*a*b^4)/(tan(1/2*d*x+1/2*c)^2*a+2*b*tan(1/2*d*x+ 1/2*c)+a)+5/2*b*(a^4-2*a^2*b^2+b^4)/(a^2-b^2)^(1/2)*arctan(1/2*(2*a*tan(1/ 2*d*x+1/2*c)+2*b)/(a^2-b^2)^(1/2))))
Leaf count of result is larger than twice the leaf count of optimal. 746 vs. \(2 (286) = 572\).
Time = 0.31 (sec) , antiderivative size = 1576, normalized size of antiderivative = 5.20 \[ \int \frac {\cos (c+d x) \cot ^5(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Too large to display} \] Input:
integrate(cos(d*x+c)*cot(d*x+c)^5/(a+b*sin(d*x+c))^2,x, algorithm="fricas" )
Output:
[1/48*(16*(3*a^5 - 20*a^3*b^2 + 15*a*b^4)*cos(d*x + c)^5 - 10*(15*a^5 - 68 *a^3*b^2 + 48*a*b^4)*cos(d*x + c)^3 - 120*((a^3*b - a*b^3)*cos(d*x + c)^4 + a^3*b - a*b^3 - 2*(a^3*b - a*b^3)*cos(d*x + c)^2 + ((a^2*b^2 - b^4)*cos( d*x + c)^4 + a^2*b^2 - b^4 - 2*(a^2*b^2 - b^4)*cos(d*x + c)^2)*sin(d*x + c ))*sqrt(-a^2 + b^2)*log(-((2*a^2 - b^2)*cos(d*x + c)^2 - 2*a*b*sin(d*x + c ) - a^2 - b^2 - 2*(a*cos(d*x + c)*sin(d*x + c) + b*cos(d*x + c))*sqrt(-a^2 + b^2))/(b^2*cos(d*x + c)^2 - 2*a*b*sin(d*x + c) - a^2 - b^2)) + 30*(3*a^ 5 - 12*a^3*b^2 + 8*a*b^4)*cos(d*x + c) - 15*(3*a^5 - 12*a^3*b^2 + 8*a*b^4 + (3*a^5 - 12*a^3*b^2 + 8*a*b^4)*cos(d*x + c)^4 - 2*(3*a^5 - 12*a^3*b^2 + 8*a*b^4)*cos(d*x + c)^2 + (3*a^4*b - 12*a^2*b^3 + 8*b^5 + (3*a^4*b - 12*a^ 2*b^3 + 8*b^5)*cos(d*x + c)^4 - 2*(3*a^4*b - 12*a^2*b^3 + 8*b^5)*cos(d*x + c)^2)*sin(d*x + c))*log(1/2*cos(d*x + c) + 1/2) + 15*(3*a^5 - 12*a^3*b^2 + 8*a*b^4 + (3*a^5 - 12*a^3*b^2 + 8*a*b^4)*cos(d*x + c)^4 - 2*(3*a^5 - 12* a^3*b^2 + 8*a*b^4)*cos(d*x + c)^2 + (3*a^4*b - 12*a^2*b^3 + 8*b^5 + (3*a^4 *b - 12*a^2*b^3 + 8*b^5)*cos(d*x + c)^4 - 2*(3*a^4*b - 12*a^2*b^3 + 8*b^5) *cos(d*x + c)^2)*sin(d*x + c))*log(-1/2*cos(d*x + c) + 1/2) + 10*((17*a^4* b - 12*a^2*b^3)*cos(d*x + c)^3 - 3*(5*a^4*b - 4*a^2*b^3)*cos(d*x + c))*sin (d*x + c))/(a^7*d*cos(d*x + c)^4 - 2*a^7*d*cos(d*x + c)^2 + a^7*d + (a^6*b *d*cos(d*x + c)^4 - 2*a^6*b*d*cos(d*x + c)^2 + a^6*b*d)*sin(d*x + c)), 1/4 8*(16*(3*a^5 - 20*a^3*b^2 + 15*a*b^4)*cos(d*x + c)^5 - 10*(15*a^5 - 68*...
\[ \int \frac {\cos (c+d x) \cot ^5(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\int \frac {\cos {\left (c + d x \right )} \cot ^{5}{\left (c + d x \right )}}{\left (a + b \sin {\left (c + d x \right )}\right )^{2}}\, dx \] Input:
integrate(cos(d*x+c)*cot(d*x+c)**5/(a+b*sin(d*x+c))**2,x)
Output:
Integral(cos(c + d*x)*cot(c + d*x)**5/(a + b*sin(c + d*x))**2, x)
Exception generated. \[ \int \frac {\cos (c+d x) \cot ^5(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Exception raised: ValueError} \] Input:
integrate(cos(d*x+c)*cot(d*x+c)^5/(a+b*sin(d*x+c))^2,x, algorithm="maxima" )
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(4*b^2-4*a^2>0)', see `assume?` f or more de
Time = 0.23 (sec) , antiderivative size = 475, normalized size of antiderivative = 1.57 \[ \int \frac {\cos (c+d x) \cot ^5(c+d x)}{(a+b \sin (c+d x))^2} \, dx =\text {Too large to display} \] Input:
integrate(cos(d*x+c)*cot(d*x+c)^5/(a+b*sin(d*x+c))^2,x, algorithm="giac")
Output:
1/192*(120*(3*a^4 - 12*a^2*b^2 + 8*b^4)*log(abs(tan(1/2*d*x + 1/2*c)))/a^6 - 1920*(a^4*b - 2*a^2*b^3 + b^5)*(pi*floor(1/2*(d*x + c)/pi + 1/2)*sgn(a) + arctan((a*tan(1/2*d*x + 1/2*c) + b)/sqrt(a^2 - b^2)))/(sqrt(a^2 - b^2)* a^6) + 384*(a^4*b*tan(1/2*d*x + 1/2*c) - 2*a^2*b^3*tan(1/2*d*x + 1/2*c) + b^5*tan(1/2*d*x + 1/2*c) + a^5 - 2*a^3*b^2 + a*b^4)/((a*tan(1/2*d*x + 1/2* c)^2 + 2*b*tan(1/2*d*x + 1/2*c) + a)*a^6) + (3*a^6*tan(1/2*d*x + 1/2*c)^4 - 16*a^5*b*tan(1/2*d*x + 1/2*c)^3 - 48*a^6*tan(1/2*d*x + 1/2*c)^2 + 72*a^4 *b^2*tan(1/2*d*x + 1/2*c)^2 + 432*a^5*b*tan(1/2*d*x + 1/2*c) - 384*a^3*b^3 *tan(1/2*d*x + 1/2*c))/a^8 - (750*a^4*tan(1/2*d*x + 1/2*c)^4 - 3000*a^2*b^ 2*tan(1/2*d*x + 1/2*c)^4 + 2000*b^4*tan(1/2*d*x + 1/2*c)^4 + 432*a^3*b*tan (1/2*d*x + 1/2*c)^3 - 384*a*b^3*tan(1/2*d*x + 1/2*c)^3 - 48*a^4*tan(1/2*d* x + 1/2*c)^2 + 72*a^2*b^2*tan(1/2*d*x + 1/2*c)^2 - 16*a^3*b*tan(1/2*d*x + 1/2*c) + 3*a^4)/(a^6*tan(1/2*d*x + 1/2*c)^4))/d
Time = 22.49 (sec) , antiderivative size = 1117, normalized size of antiderivative = 3.69 \[ \int \frac {\cos (c+d x) \cot ^5(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Too large to display} \] Input:
int((cos(c + d*x)*cot(c + d*x)^5)/(a + b*sin(c + d*x))^2,x)
Output:
tan(c/2 + (d*x)/2)^4/(64*a^2*d) + (tan(c/2 + (d*x)/2)^4*(36*a^4 + 96*b^4 - 142*a^2*b^2) - a^4/4 + tan(c/2 + (d*x)/2)^2*((15*a^4)/4 - (10*a^2*b^2)/3) + tan(c/2 + (d*x)/2)^3*(20*a*b^3 - (80*a^3*b)/3) - (4*tan(c/2 + (d*x)/2)^ 5*(a^4*b - 8*b^5 + 8*a^2*b^3))/a + (5*a^3*b*tan(c/2 + (d*x)/2))/6)/(d*(16* a^6*tan(c/2 + (d*x)/2)^4 + 16*a^6*tan(c/2 + (d*x)/2)^6 + 32*a^5*b*tan(c/2 + (d*x)/2)^5)) - (tan(c/2 + (d*x)/2)^2*((32*a^2 + 64*b^2)/(512*a^4) + 3/(1 6*a^2) - b^2/(2*a^4)))/d + (tan(c/2 + (d*x)/2)*((b*(32*a^2 + 64*b^2))/(64* a^5) - b/(4*a^3) + (4*b*((32*a^2 + 64*b^2)/(256*a^4) + 3/(8*a^2) - b^2/a^4 ))/a))/d - (b*tan(c/2 + (d*x)/2)^3)/(12*a^3*d) + (log(tan(c/2 + (d*x)/2))* (15*a^4 + 40*b^4 - 60*a^2*b^2))/(8*a^6*d) - (b*atan(((b*(-(a + b)^3*(a - b )^3)^(1/2)*((tan(c/2 + (d*x)/2)*(15*a^10 - 160*a^4*b^6 + 320*a^6*b^4 - 170 *a^8*b^2))/(4*a^9) - (55*a^10*b + 80*a^6*b^5 - 140*a^8*b^3)/(4*a^10) + (5* b*(2*a^2*b - (tan(c/2 + (d*x)/2)*(24*a^12 - 32*a^10*b^2))/(4*a^9))*(-(a + b)^3*(a - b)^3)^(1/2))/a^6)*5i)/a^6 - (b*(-(a + b)^3*(a - b)^3)^(1/2)*((55 *a^10*b + 80*a^6*b^5 - 140*a^8*b^3)/(4*a^10) - (tan(c/2 + (d*x)/2)*(15*a^1 0 - 160*a^4*b^6 + 320*a^6*b^4 - 170*a^8*b^2))/(4*a^9) + (5*b*(2*a^2*b - (t an(c/2 + (d*x)/2)*(24*a^12 - 32*a^10*b^2))/(4*a^9))*(-(a + b)^3*(a - b)^3) ^(1/2))/a^6)*5i)/a^6)/((75*a^8*b + 200*b^9 - 700*a^2*b^7 + 875*a^4*b^5 - 4 50*a^6*b^3)/(2*a^10) + (tan(c/2 + (d*x)/2)*(200*b^8 - 650*a^2*b^6 + 700*a^ 4*b^4 - 250*a^6*b^2))/(2*a^9) + (5*b*(-(a + b)^3*(a - b)^3)^(1/2)*((tan...
Time = 0.19 (sec) , antiderivative size = 553, normalized size of antiderivative = 1.83 \[ \int \frac {\cos (c+d x) \cot ^5(c+d x)}{(a+b \sin (c+d x))^2} \, dx =\text {Too large to display} \] Input:
int(cos(d*x+c)*cot(d*x+c)^5/(a+b*sin(d*x+c))^2,x)
Output:
( - 240*sqrt(a**2 - b**2)*atan((tan((c + d*x)/2)*a + b)/sqrt(a**2 - b**2)) *sin(c + d*x)**5*a**2*b**2 + 240*sqrt(a**2 - b**2)*atan((tan((c + d*x)/2)* a + b)/sqrt(a**2 - b**2))*sin(c + d*x)**5*b**4 - 240*sqrt(a**2 - b**2)*ata n((tan((c + d*x)/2)*a + b)/sqrt(a**2 - b**2))*sin(c + d*x)**4*a**3*b + 240 *sqrt(a**2 - b**2)*atan((tan((c + d*x)/2)*a + b)/sqrt(a**2 - b**2))*sin(c + d*x)**4*a*b**3 + 24*cos(c + d*x)*sin(c + d*x)**4*a**5 - 160*cos(c + d*x) *sin(c + d*x)**4*a**3*b**2 + 120*cos(c + d*x)*sin(c + d*x)**4*a*b**4 - 85* cos(c + d*x)*sin(c + d*x)**3*a**4*b + 60*cos(c + d*x)*sin(c + d*x)**3*a**2 *b**3 + 27*cos(c + d*x)*sin(c + d*x)**2*a**5 - 20*cos(c + d*x)*sin(c + d*x )**2*a**3*b**2 + 10*cos(c + d*x)*sin(c + d*x)*a**4*b - 6*cos(c + d*x)*a**5 + 45*log(tan((c + d*x)/2))*sin(c + d*x)**5*a**4*b - 180*log(tan((c + d*x) /2))*sin(c + d*x)**5*a**2*b**3 + 120*log(tan((c + d*x)/2))*sin(c + d*x)**5 *b**5 + 45*log(tan((c + d*x)/2))*sin(c + d*x)**4*a**5 - 180*log(tan((c + d *x)/2))*sin(c + d*x)**4*a**3*b**2 + 120*log(tan((c + d*x)/2))*sin(c + d*x) **4*a*b**4)/(24*sin(c + d*x)**4*a**6*d*(sin(c + d*x)*b + a))