Integrand size = 29, antiderivative size = 244 \[ \int \frac {\cot ^4(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx=\frac {2 b^2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^6 d}+\frac {b \left (3 a^4-12 a^2 b^2+8 b^4\right ) \text {arctanh}(\cos (c+d x))}{8 a^6 d}-\frac {\left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{15 a^5 d}-\frac {b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 a^4 d}+\frac {\left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{15 a^3 d}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d} \] Output:
2*b^2*(a^2-b^2)^(3/2)*arctan((b+a*tan(1/2*d*x+1/2*c))/(a^2-b^2)^(1/2))/a^6 /d+1/8*b*(3*a^4-12*a^2*b^2+8*b^4)*arctanh(cos(d*x+c))/a^6/d-1/15*(3*a^4-20 *a^2*b^2+15*b^4)*cot(d*x+c)/a^5/d-1/8*b*(5*a^2-4*b^2)*cot(d*x+c)*csc(d*x+c )/a^4/d+1/15*(6*a^2-5*b^2)*cot(d*x+c)*csc(d*x+c)^2/a^3/d+1/4*b*cot(d*x+c)* csc(d*x+c)^3/a^2/d-1/5*cot(d*x+c)*csc(d*x+c)^4/a/d
Leaf count is larger than twice the leaf count of optimal. \(507\) vs. \(2(244)=488\).
Time = 3.19 (sec) , antiderivative size = 507, normalized size of antiderivative = 2.08 \[ \int \frac {\cot ^4(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx=\frac {1920 b^2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )-32 \left (3 a^5-20 a^3 b^2+15 a b^4\right ) \cot \left (\frac {1}{2} (c+d x)\right )-150 a^4 b \csc ^2\left (\frac {1}{2} (c+d x)\right )+120 a^2 b^3 \csc ^2\left (\frac {1}{2} (c+d x)\right )+15 a^4 b \csc ^4\left (\frac {1}{2} (c+d x)\right )+360 a^4 b \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )-1440 a^2 b^3 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )+960 b^5 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )-360 a^4 b \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )+1440 a^2 b^3 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )-960 b^5 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )+150 a^4 b \sec ^2\left (\frac {1}{2} (c+d x)\right )-120 a^2 b^3 \sec ^2\left (\frac {1}{2} (c+d x)\right )-15 a^4 b \sec ^4\left (\frac {1}{2} (c+d x)\right )-336 a^5 \csc ^3(c+d x) \sin ^4\left (\frac {1}{2} (c+d x)\right )+320 a^3 b^2 \csc ^3(c+d x) \sin ^4\left (\frac {1}{2} (c+d x)\right )+21 a^5 \csc ^4\left (\frac {1}{2} (c+d x)\right ) \sin (c+d x)-20 a^3 b^2 \csc ^4\left (\frac {1}{2} (c+d x)\right ) \sin (c+d x)-3 a^5 \csc ^6\left (\frac {1}{2} (c+d x)\right ) \sin (c+d x)+96 a^5 \tan \left (\frac {1}{2} (c+d x)\right )-640 a^3 b^2 \tan \left (\frac {1}{2} (c+d x)\right )+480 a b^4 \tan \left (\frac {1}{2} (c+d x)\right )+6 a^5 \sec ^4\left (\frac {1}{2} (c+d x)\right ) \tan \left (\frac {1}{2} (c+d x)\right )}{960 a^6 d} \] Input:
Integrate[(Cot[c + d*x]^4*Csc[c + d*x]^2)/(a + b*Sin[c + d*x]),x]
Output:
(1920*b^2*(a^2 - b^2)^(3/2)*ArcTan[(b + a*Tan[(c + d*x)/2])/Sqrt[a^2 - b^2 ]] - 32*(3*a^5 - 20*a^3*b^2 + 15*a*b^4)*Cot[(c + d*x)/2] - 150*a^4*b*Csc[( c + d*x)/2]^2 + 120*a^2*b^3*Csc[(c + d*x)/2]^2 + 15*a^4*b*Csc[(c + d*x)/2] ^4 + 360*a^4*b*Log[Cos[(c + d*x)/2]] - 1440*a^2*b^3*Log[Cos[(c + d*x)/2]] + 960*b^5*Log[Cos[(c + d*x)/2]] - 360*a^4*b*Log[Sin[(c + d*x)/2]] + 1440*a ^2*b^3*Log[Sin[(c + d*x)/2]] - 960*b^5*Log[Sin[(c + d*x)/2]] + 150*a^4*b*S ec[(c + d*x)/2]^2 - 120*a^2*b^3*Sec[(c + d*x)/2]^2 - 15*a^4*b*Sec[(c + d*x )/2]^4 - 336*a^5*Csc[c + d*x]^3*Sin[(c + d*x)/2]^4 + 320*a^3*b^2*Csc[c + d *x]^3*Sin[(c + d*x)/2]^4 + 21*a^5*Csc[(c + d*x)/2]^4*Sin[c + d*x] - 20*a^3 *b^2*Csc[(c + d*x)/2]^4*Sin[c + d*x] - 3*a^5*Csc[(c + d*x)/2]^6*Sin[c + d* x] + 96*a^5*Tan[(c + d*x)/2] - 640*a^3*b^2*Tan[(c + d*x)/2] + 480*a*b^4*Ta n[(c + d*x)/2] + 6*a^5*Sec[(c + d*x)/2]^4*Tan[(c + d*x)/2])/(960*a^6*d)
Time = 1.99 (sec) , antiderivative size = 276, normalized size of antiderivative = 1.13, number of steps used = 18, number of rules used = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.586, Rules used = {3042, 3372, 3042, 3534, 25, 3042, 3534, 3042, 3534, 27, 3042, 3480, 3042, 3139, 1083, 217, 4257}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\cot ^4(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {\cos (c+d x)^4}{\sin (c+d x)^6 (a+b \sin (c+d x))}dx\) |
\(\Big \downarrow \) 3372 |
\(\displaystyle -\frac {\int \frac {\csc ^4(c+d x) \left (-5 \left (4 a^2-3 b^2\right ) \sin ^2(c+d x)-a b \sin (c+d x)+4 \left (6 a^2-5 b^2\right )\right )}{a+b \sin (c+d x)}dx}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {\int \frac {-5 \left (4 a^2-3 b^2\right ) \sin (c+d x)^2-a b \sin (c+d x)+4 \left (6 a^2-5 b^2\right )}{\sin (c+d x)^4 (a+b \sin (c+d x))}dx}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3534 |
\(\displaystyle -\frac {\frac {\int -\frac {\csc ^3(c+d x) \left (-8 b \left (6 a^2-5 b^2\right ) \sin ^2(c+d x)+a \left (12 a^2-5 b^2\right ) \sin (c+d x)+15 b \left (5 a^2-4 b^2\right )\right )}{a+b \sin (c+d x)}dx}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\frac {-\frac {\int \frac {\csc ^3(c+d x) \left (-8 b \left (6 a^2-5 b^2\right ) \sin ^2(c+d x)+a \left (12 a^2-5 b^2\right ) \sin (c+d x)+15 b \left (5 a^2-4 b^2\right )\right )}{a+b \sin (c+d x)}dx}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {-\frac {\int \frac {-8 b \left (6 a^2-5 b^2\right ) \sin (c+d x)^2+a \left (12 a^2-5 b^2\right ) \sin (c+d x)+15 b \left (5 a^2-4 b^2\right )}{\sin (c+d x)^3 (a+b \sin (c+d x))}dx}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3534 |
\(\displaystyle -\frac {-\frac {\frac {\int \frac {\csc ^2(c+d x) \left (15 b^2 \left (5 a^2-4 b^2\right ) \sin ^2(c+d x)-a b \left (21 a^2-20 b^2\right ) \sin (c+d x)+8 \left (3 a^4-20 b^2 a^2+15 b^4\right )\right )}{a+b \sin (c+d x)}dx}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {-\frac {\frac {\int \frac {15 b^2 \left (5 a^2-4 b^2\right ) \sin (c+d x)^2-a b \left (21 a^2-20 b^2\right ) \sin (c+d x)+8 \left (3 a^4-20 b^2 a^2+15 b^4\right )}{\sin (c+d x)^2 (a+b \sin (c+d x))}dx}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3534 |
\(\displaystyle -\frac {-\frac {\frac {\frac {\int -\frac {15 \csc (c+d x) \left (b \left (3 a^4-12 b^2 a^2+8 b^4\right )-a b^2 \left (5 a^2-4 b^2\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)}dx}{a}-\frac {8 \left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {-\frac {\frac {-\frac {15 \int \frac {\csc (c+d x) \left (b \left (3 a^4-12 b^2 a^2+8 b^4\right )-a b^2 \left (5 a^2-4 b^2\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)}dx}{a}-\frac {8 \left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {-\frac {\frac {-\frac {15 \int \frac {b \left (3 a^4-12 b^2 a^2+8 b^4\right )-a b^2 \left (5 a^2-4 b^2\right ) \sin (c+d x)}{\sin (c+d x) (a+b \sin (c+d x))}dx}{a}-\frac {8 \left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3480 |
\(\displaystyle -\frac {-\frac {\frac {-\frac {15 \left (\frac {b \left (3 a^4-12 a^2 b^2+8 b^4\right ) \int \csc (c+d x)dx}{a}-\frac {8 b^2 \left (a^2-b^2\right )^2 \int \frac {1}{a+b \sin (c+d x)}dx}{a}\right )}{a}-\frac {8 \left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {-\frac {\frac {-\frac {15 \left (\frac {b \left (3 a^4-12 a^2 b^2+8 b^4\right ) \int \csc (c+d x)dx}{a}-\frac {8 b^2 \left (a^2-b^2\right )^2 \int \frac {1}{a+b \sin (c+d x)}dx}{a}\right )}{a}-\frac {8 \left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 3139 |
\(\displaystyle -\frac {-\frac {\frac {-\frac {15 \left (\frac {b \left (3 a^4-12 a^2 b^2+8 b^4\right ) \int \csc (c+d x)dx}{a}-\frac {16 b^2 \left (a^2-b^2\right )^2 \int \frac {1}{a \tan ^2\left (\frac {1}{2} (c+d x)\right )+2 b \tan \left (\frac {1}{2} (c+d x)\right )+a}d\tan \left (\frac {1}{2} (c+d x)\right )}{a d}\right )}{a}-\frac {8 \left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 1083 |
\(\displaystyle -\frac {-\frac {\frac {-\frac {15 \left (\frac {32 b^2 \left (a^2-b^2\right )^2 \int \frac {1}{-\left (2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )^2-4 \left (a^2-b^2\right )}d\left (2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a d}+\frac {b \left (3 a^4-12 a^2 b^2+8 b^4\right ) \int \csc (c+d x)dx}{a}\right )}{a}-\frac {8 \left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle -\frac {-\frac {\frac {-\frac {15 \left (\frac {b \left (3 a^4-12 a^2 b^2+8 b^4\right ) \int \csc (c+d x)dx}{a}-\frac {16 b^2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {2 a \tan \left (\frac {1}{2} (c+d x)\right )+2 b}{2 \sqrt {a^2-b^2}}\right )}{a d}\right )}{a}-\frac {8 \left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}}{20 a^2}+\frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
\(\Big \downarrow \) 4257 |
\(\displaystyle \frac {b \cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac {-\frac {4 \left (6 a^2-5 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{3 a d}-\frac {\frac {-\frac {15 \left (-\frac {16 b^2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {2 a \tan \left (\frac {1}{2} (c+d x)\right )+2 b}{2 \sqrt {a^2-b^2}}\right )}{a d}-\frac {b \left (3 a^4-12 a^2 b^2+8 b^4\right ) \text {arctanh}(\cos (c+d x))}{a d}\right )}{a}-\frac {8 \left (3 a^4-20 a^2 b^2+15 b^4\right ) \cot (c+d x)}{a d}}{2 a}-\frac {15 b \left (5 a^2-4 b^2\right ) \cot (c+d x) \csc (c+d x)}{2 a d}}{3 a}}{20 a^2}-\frac {\cot (c+d x) \csc ^4(c+d x)}{5 a d}\) |
Input:
Int[(Cot[c + d*x]^4*Csc[c + d*x]^2)/(a + b*Sin[c + d*x]),x]
Output:
(b*Cot[c + d*x]*Csc[c + d*x]^3)/(4*a^2*d) - (Cot[c + d*x]*Csc[c + d*x]^4)/ (5*a*d) - ((-4*(6*a^2 - 5*b^2)*Cot[c + d*x]*Csc[c + d*x]^2)/(3*a*d) - (((- 15*((-16*b^2*(a^2 - b^2)^(3/2)*ArcTan[(2*b + 2*a*Tan[(c + d*x)/2])/(2*Sqrt [a^2 - b^2])])/(a*d) - (b*(3*a^4 - 12*a^2*b^2 + 8*b^4)*ArcTanh[Cos[c + d*x ]])/(a*d)))/a - (8*(3*a^4 - 20*a^2*b^2 + 15*b^4)*Cot[c + d*x])/(a*d))/(2*a ) - (15*b*(5*a^2 - 4*b^2)*Cot[c + d*x]*Csc[c + d*x])/(2*a*d))/(3*a))/(20*a ^2)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Simp[-2 Subst[I nt[1/Simp[b^2 - 4*a*c - x^2, x], x], x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x]
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{e = Fre eFactors[Tan[(c + d*x)/2], x]}, Simp[2*(e/d) Subst[Int[1/(a + 2*b*e*x + a *e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}, x] && NeQ [a^2 - b^2, 0]
Int[cos[(e_.) + (f_.)*(x_)]^4*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[Cos[e + f*x]*(a + b* Sin[e + f*x])^(m + 1)*((d*Sin[e + f*x])^(n + 1)/(a*d*f*(n + 1))), x] + (-Si mp[b*(m + n + 2)*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m + 1)*((d*Sin[e + f*x] )^(n + 2)/(a^2*d^2*f*(n + 1)*(n + 2))), x] - Simp[1/(a^2*d^2*(n + 1)*(n + 2 )) Int[(a + b*Sin[e + f*x])^m*(d*Sin[e + f*x])^(n + 2)*Simp[a^2*n*(n + 2) - b^2*(m + n + 2)*(m + n + 3) + a*b*m*Sin[e + f*x] - (a^2*(n + 1)*(n + 2) - b^2*(m + n + 2)*(m + n + 4))*Sin[e + f*x]^2, x], x], x]) /; FreeQ[{a, b, d, e, f, m}, x] && NeQ[a^2 - b^2, 0] && (IGtQ[m, 0] || IntegersQ[2*m, 2*n]) && !m < -1 && LtQ[n, -1] && (LtQ[n, -2] || EqQ[m + n + 4, 0])
Int[((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])/(((a_.) + (b_.)*sin[(e_.) + (f_ .)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])), x_Symbol] :> Simp[(A*b - a*B)/(b*c - a*d) Int[1/(a + b*Sin[e + f*x]), x], x] + Simp[(B*c - A*d)/ (b*c - a*d) Int[1/(c + d*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f , A, B}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(A*b^2 - a*b*B + a^2*C))*Cos[e + f*x ]*(a + b*Sin[e + f*x])^(m + 1)*((c + d*Sin[e + f*x])^(n + 1)/(f*(m + 1)*(b* c - a*d)*(a^2 - b^2))), x] + Simp[1/((m + 1)*(b*c - a*d)*(a^2 - b^2)) Int [(a + b*Sin[e + f*x])^(m + 1)*(c + d*Sin[e + f*x])^n*Simp[(m + 1)*(b*c - a* d)*(a*A - b*B + a*C) + d*(A*b^2 - a*b*B + a^2*C)*(m + n + 2) - (c*(A*b^2 - a*b*B + a^2*C) + (m + 1)*(b*c - a*d)*(A*b - a*B + b*C))*Sin[e + f*x] - d*(A *b^2 - a*b*B + a^2*C)*(m + n + 3)*Sin[e + f*x]^2, x], x], x] /; FreeQ[{a, b , c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && LtQ[m, -1] && ((EqQ[a, 0] && IntegerQ[m] && !IntegerQ [n]) || !(IntegerQ[2*n] && LtQ[n, -1] && ((IntegerQ[n] && !IntegerQ[m]) | | EqQ[a, 0])))
Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]
Time = 0.93 (sec) , antiderivative size = 379, normalized size of antiderivative = 1.55
method | result | size |
derivativedivides | \(\frac {\frac {2 b^{2} \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{a^{6} \sqrt {a^{2}-b^{2}}}+\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5} a^{4}}{5}-\frac {b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} a^{3}}{2}-a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}+\frac {4 a^{2} b^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3}+4 a^{3} b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-4 a \,b^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+2 a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-20 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{2} b^{2}+16 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{4}}{32 a^{5}}-\frac {1}{160 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}-\frac {-3 a^{2}+4 b^{2}}{96 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}-\frac {2 a^{4}-20 a^{2} b^{2}+16 b^{4}}{32 a^{5} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}+\frac {b}{64 a^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}-\frac {b \left (a^{2}-b^{2}\right )}{8 a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}-\frac {b \left (3 a^{4}-12 a^{2} b^{2}+8 b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 a^{6}}}{d}\) | \(379\) |
default | \(\frac {\frac {2 b^{2} \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{a^{6} \sqrt {a^{2}-b^{2}}}+\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5} a^{4}}{5}-\frac {b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} a^{3}}{2}-a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}+\frac {4 a^{2} b^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3}+4 a^{3} b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-4 a \,b^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+2 a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-20 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{2} b^{2}+16 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{4}}{32 a^{5}}-\frac {1}{160 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}-\frac {-3 a^{2}+4 b^{2}}{96 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}-\frac {2 a^{4}-20 a^{2} b^{2}+16 b^{4}}{32 a^{5} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}+\frac {b}{64 a^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}-\frac {b \left (a^{2}-b^{2}\right )}{8 a^{4} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}-\frac {b \left (3 a^{4}-12 a^{2} b^{2}+8 b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 a^{6}}}{d}\) | \(379\) |
risch | \(\frac {480 i b^{4} {\mathrm e}^{2 i \left (d x +c \right )}-720 i b^{4} {\mathrm e}^{4 i \left (d x +c \right )}+240 i a^{2} b^{2} {\mathrm e}^{8 i \left (d x +c \right )}+75 a^{3} b \,{\mathrm e}^{9 i \left (d x +c \right )}-60 a \,b^{3} {\mathrm e}^{9 i \left (d x +c \right )}-560 i a^{2} b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+160 i a^{2} b^{2}-30 a^{3} b \,{\mathrm e}^{7 i \left (d x +c \right )}+120 b^{3} a \,{\mathrm e}^{7 i \left (d x +c \right )}-240 i a^{4} {\mathrm e}^{4 i \left (d x +c \right )}+880 i a^{2} b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-24 i a^{4}+480 i b^{4} {\mathrm e}^{6 i \left (d x +c \right )}-120 i b^{4}+30 b \,a^{3} {\mathrm e}^{3 i \left (d x +c \right )}-120 b^{3} a \,{\mathrm e}^{3 i \left (d x +c \right )}-720 i a^{2} b^{2} {\mathrm e}^{6 i \left (d x +c \right )}-120 i a^{4} {\mathrm e}^{8 i \left (d x +c \right )}-120 i b^{4} {\mathrm e}^{8 i \left (d x +c \right )}-75 b \,a^{3} {\mathrm e}^{i \left (d x +c \right )}+60 b^{3} a \,{\mathrm e}^{i \left (d x +c \right )}}{60 d \,a^{5} \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{5}}+\frac {3 b \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{8 a^{2} d}-\frac {3 b^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{2 d \,a^{4}}+\frac {b^{5} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{d \,a^{6}}-\frac {\sqrt {-a^{2}+b^{2}}\, b^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a -\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,a^{4}}+\frac {\sqrt {-a^{2}+b^{2}}\, b^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a -\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,a^{6}}+\frac {\sqrt {-a^{2}+b^{2}}\, b^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a +\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,a^{4}}-\frac {\sqrt {-a^{2}+b^{2}}\, b^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a +\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,a^{6}}-\frac {3 b \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{8 a^{2} d}+\frac {3 b^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{2 d \,a^{4}}-\frac {b^{5} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{d \,a^{6}}\) | \(674\) |
Input:
int(cot(d*x+c)^4*csc(d*x+c)^2/(a+b*sin(d*x+c)),x,method=_RETURNVERBOSE)
Output:
1/d*(2*b^2*(a^4-2*a^2*b^2+b^4)/a^6/(a^2-b^2)^(1/2)*arctan(1/2*(2*a*tan(1/2 *d*x+1/2*c)+2*b)/(a^2-b^2)^(1/2))+1/32/a^5*(1/5*tan(1/2*d*x+1/2*c)^5*a^4-1 /2*b*tan(1/2*d*x+1/2*c)^4*a^3-a^4*tan(1/2*d*x+1/2*c)^3+4/3*a^2*b^2*tan(1/2 *d*x+1/2*c)^3+4*a^3*b*tan(1/2*d*x+1/2*c)^2-4*a*b^3*tan(1/2*d*x+1/2*c)^2+2* a^4*tan(1/2*d*x+1/2*c)-20*tan(1/2*d*x+1/2*c)*a^2*b^2+16*tan(1/2*d*x+1/2*c) *b^4)-1/160/a/tan(1/2*d*x+1/2*c)^5-1/96*(-3*a^2+4*b^2)/a^3/tan(1/2*d*x+1/2 *c)^3-1/32*(2*a^4-20*a^2*b^2+16*b^4)/a^5/tan(1/2*d*x+1/2*c)+1/64/a^2*b/tan (1/2*d*x+1/2*c)^4-1/8*b/a^4*(a^2-b^2)/tan(1/2*d*x+1/2*c)^2-1/8/a^6*b*(3*a^ 4-12*a^2*b^2+8*b^4)*ln(tan(1/2*d*x+1/2*c)))
Leaf count of result is larger than twice the leaf count of optimal. 484 vs. \(2 (227) = 454\).
Time = 0.29 (sec) , antiderivative size = 1051, normalized size of antiderivative = 4.31 \[ \int \frac {\cot ^4(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx=\text {Too large to display} \] Input:
integrate(cot(d*x+c)^4*csc(d*x+c)^2/(a+b*sin(d*x+c)),x, algorithm="fricas" )
Output:
[-1/240*(16*(3*a^5 - 20*a^3*b^2 + 15*a*b^4)*cos(d*x + c)^5 + 80*(7*a^3*b^2 - 6*a*b^4)*cos(d*x + c)^3 + 120*((a^2*b^2 - b^4)*cos(d*x + c)^4 + a^2*b^2 - b^4 - 2*(a^2*b^2 - b^4)*cos(d*x + c)^2)*sqrt(-a^2 + b^2)*log(((2*a^2 - b^2)*cos(d*x + c)^2 - 2*a*b*sin(d*x + c) - a^2 - b^2 + 2*(a*cos(d*x + c)*s in(d*x + c) + b*cos(d*x + c))*sqrt(-a^2 + b^2))/(b^2*cos(d*x + c)^2 - 2*a* b*sin(d*x + c) - a^2 - b^2))*sin(d*x + c) - 15*(3*a^4*b - 12*a^2*b^3 + 8*b ^5 + (3*a^4*b - 12*a^2*b^3 + 8*b^5)*cos(d*x + c)^4 - 2*(3*a^4*b - 12*a^2*b ^3 + 8*b^5)*cos(d*x + c)^2)*log(1/2*cos(d*x + c) + 1/2)*sin(d*x + c) + 15* (3*a^4*b - 12*a^2*b^3 + 8*b^5 + (3*a^4*b - 12*a^2*b^3 + 8*b^5)*cos(d*x + c )^4 - 2*(3*a^4*b - 12*a^2*b^3 + 8*b^5)*cos(d*x + c)^2)*log(-1/2*cos(d*x + c) + 1/2)*sin(d*x + c) - 240*(a^3*b^2 - a*b^4)*cos(d*x + c) - 30*((5*a^4*b - 4*a^2*b^3)*cos(d*x + c)^3 - (3*a^4*b - 4*a^2*b^3)*cos(d*x + c))*sin(d*x + c))/((a^6*d*cos(d*x + c)^4 - 2*a^6*d*cos(d*x + c)^2 + a^6*d)*sin(d*x + c)), -1/240*(16*(3*a^5 - 20*a^3*b^2 + 15*a*b^4)*cos(d*x + c)^5 + 80*(7*a^3 *b^2 - 6*a*b^4)*cos(d*x + c)^3 + 240*((a^2*b^2 - b^4)*cos(d*x + c)^4 + a^2 *b^2 - b^4 - 2*(a^2*b^2 - b^4)*cos(d*x + c)^2)*sqrt(a^2 - b^2)*arctan(-(a* sin(d*x + c) + b)/(sqrt(a^2 - b^2)*cos(d*x + c)))*sin(d*x + c) - 15*(3*a^4 *b - 12*a^2*b^3 + 8*b^5 + (3*a^4*b - 12*a^2*b^3 + 8*b^5)*cos(d*x + c)^4 - 2*(3*a^4*b - 12*a^2*b^3 + 8*b^5)*cos(d*x + c)^2)*log(1/2*cos(d*x + c) + 1/ 2)*sin(d*x + c) + 15*(3*a^4*b - 12*a^2*b^3 + 8*b^5 + (3*a^4*b - 12*a^2*...
\[ \int \frac {\cot ^4(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx=\int \frac {\cot ^{4}{\left (c + d x \right )} \csc ^{2}{\left (c + d x \right )}}{a + b \sin {\left (c + d x \right )}}\, dx \] Input:
integrate(cot(d*x+c)**4*csc(d*x+c)**2/(a+b*sin(d*x+c)),x)
Output:
Integral(cot(c + d*x)**4*csc(c + d*x)**2/(a + b*sin(c + d*x)), x)
Exception generated. \[ \int \frac {\cot ^4(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx=\text {Exception raised: ValueError} \] Input:
integrate(cot(d*x+c)^4*csc(d*x+c)^2/(a+b*sin(d*x+c)),x, algorithm="maxima" )
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(4*b^2-4*a^2>0)', see `assume?` f or more de
Leaf count of result is larger than twice the leaf count of optimal. 484 vs. \(2 (227) = 454\).
Time = 0.28 (sec) , antiderivative size = 484, normalized size of antiderivative = 1.98 \[ \int \frac {\cot ^4(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx =\text {Too large to display} \] Input:
integrate(cot(d*x+c)^4*csc(d*x+c)^2/(a+b*sin(d*x+c)),x, algorithm="giac")
Output:
1/960*((6*a^4*tan(1/2*d*x + 1/2*c)^5 - 15*a^3*b*tan(1/2*d*x + 1/2*c)^4 - 3 0*a^4*tan(1/2*d*x + 1/2*c)^3 + 40*a^2*b^2*tan(1/2*d*x + 1/2*c)^3 + 120*a^3 *b*tan(1/2*d*x + 1/2*c)^2 - 120*a*b^3*tan(1/2*d*x + 1/2*c)^2 + 60*a^4*tan( 1/2*d*x + 1/2*c) - 600*a^2*b^2*tan(1/2*d*x + 1/2*c) + 480*b^4*tan(1/2*d*x + 1/2*c))/a^5 - 120*(3*a^4*b - 12*a^2*b^3 + 8*b^5)*log(abs(tan(1/2*d*x + 1 /2*c)))/a^6 + 1920*(a^4*b^2 - 2*a^2*b^4 + b^6)*(pi*floor(1/2*(d*x + c)/pi + 1/2)*sgn(a) + arctan((a*tan(1/2*d*x + 1/2*c) + b)/sqrt(a^2 - b^2)))/(sqr t(a^2 - b^2)*a^6) + (822*a^4*b*tan(1/2*d*x + 1/2*c)^5 - 3288*a^2*b^3*tan(1 /2*d*x + 1/2*c)^5 + 2192*b^5*tan(1/2*d*x + 1/2*c)^5 - 60*a^5*tan(1/2*d*x + 1/2*c)^4 + 600*a^3*b^2*tan(1/2*d*x + 1/2*c)^4 - 480*a*b^4*tan(1/2*d*x + 1 /2*c)^4 - 120*a^4*b*tan(1/2*d*x + 1/2*c)^3 + 120*a^2*b^3*tan(1/2*d*x + 1/2 *c)^3 + 30*a^5*tan(1/2*d*x + 1/2*c)^2 - 40*a^3*b^2*tan(1/2*d*x + 1/2*c)^2 + 15*a^4*b*tan(1/2*d*x + 1/2*c) - 6*a^5)/(a^6*tan(1/2*d*x + 1/2*c)^5))/d
Time = 19.81 (sec) , antiderivative size = 1082, normalized size of antiderivative = 4.43 \[ \int \frac {\cot ^4(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx=\text {Too large to display} \] Input:
int(cot(c + d*x)^4/(sin(c + d*x)^2*(a + b*sin(c + d*x))),x)
Output:
tan(c/2 + (d*x)/2)^5/(160*a*d) + (tan(c/2 + (d*x)/2)^2*(b/(32*a^2) + (b*(3 /(32*a) - b^2/(8*a^3)))/a))/d - (tan(c/2 + (d*x)/2)*(b^2/(8*a^3) - 1/(16*a ) + (2*b*(b/(16*a^2) + (2*b*(3/(32*a) - b^2/(8*a^3)))/a))/a))/d - (tan(c/2 + (d*x)/2)^3*(1/(32*a) - b^2/(24*a^3)))/d - (b*tan(c/2 + (d*x)/2)^4)/(64* a^2*d) + (tan(c/2 + (d*x)/2)^2*(a^4 - (4*a^2*b^2)/3) - tan(c/2 + (d*x)/2)^ 4*(2*a^4 + 16*b^4 - 20*a^2*b^2) - a^4/5 + tan(c/2 + (d*x)/2)^3*(4*a*b^3 - 4*a^3*b) + (a^3*b*tan(c/2 + (d*x)/2))/2)/(32*a^5*d*tan(c/2 + (d*x)/2)^5) - (log(tan(c/2 + (d*x)/2))*((3*a^4*b)/8 + b^5 - (3*a^2*b^3)/2))/(a^6*d) + ( b^2*atan(((b^2*(-(a + b)^3*(a - b)^3)^(1/2)*((tan(c/2 + (d*x)/2)*(3*a^10*b - 32*a^4*b^7 + 64*a^6*b^5 - 34*a^8*b^3))/(4*a^9) - (16*a^6*b^6 - 28*a^8*b ^4 + 11*a^10*b^2)/(4*a^10) + (b^2*(2*a^2*b - (tan(c/2 + (d*x)/2)*(24*a^12 - 32*a^10*b^2))/(4*a^9))*(-(a + b)^3*(a - b)^3)^(1/2))/a^6)*1i)/a^6 - (b^2 *(-(a + b)^3*(a - b)^3)^(1/2)*((16*a^6*b^6 - 28*a^8*b^4 + 11*a^10*b^2)/(4* a^10) - (tan(c/2 + (d*x)/2)*(3*a^10*b - 32*a^4*b^7 + 64*a^6*b^5 - 34*a^8*b ^3))/(4*a^9) + (b^2*(2*a^2*b - (tan(c/2 + (d*x)/2)*(24*a^12 - 32*a^10*b^2) )/(4*a^9))*(-(a + b)^3*(a - b)^3)^(1/2))/a^6)*1i)/a^6)/((8*b^11 - 28*a^2*b ^9 + 35*a^4*b^7 - 18*a^6*b^5 + 3*a^8*b^3)/(2*a^10) + (tan(c/2 + (d*x)/2)*( 8*b^10 - 26*a^2*b^8 + 28*a^4*b^6 - 10*a^6*b^4))/(2*a^9) + (b^2*(-(a + b)^3 *(a - b)^3)^(1/2)*((tan(c/2 + (d*x)/2)*(3*a^10*b - 32*a^4*b^7 + 64*a^6*b^5 - 34*a^8*b^3))/(4*a^9) - (16*a^6*b^6 - 28*a^8*b^4 + 11*a^10*b^2)/(4*a^...
Time = 0.18 (sec) , antiderivative size = 366, normalized size of antiderivative = 1.50 \[ \int \frac {\cot ^4(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx=\frac {240 \sqrt {a^{2}-b^{2}}\, \mathit {atan} \left (\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) a +b}{\sqrt {a^{2}-b^{2}}}\right ) \sin \left (d x +c \right )^{5} a^{2} b^{2}-240 \sqrt {a^{2}-b^{2}}\, \mathit {atan} \left (\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) a +b}{\sqrt {a^{2}-b^{2}}}\right ) \sin \left (d x +c \right )^{5} b^{4}-24 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{4} a^{5}+160 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{4} a^{3} b^{2}-120 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{4} a \,b^{4}-75 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{3} a^{4} b +60 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{3} a^{2} b^{3}+48 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2} a^{5}-40 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2} a^{3} b^{2}+30 \cos \left (d x +c \right ) \sin \left (d x +c \right ) a^{4} b -24 \cos \left (d x +c \right ) a^{5}-45 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \sin \left (d x +c \right )^{5} a^{4} b +180 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \sin \left (d x +c \right )^{5} a^{2} b^{3}-120 \,\mathrm {log}\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \sin \left (d x +c \right )^{5} b^{5}}{120 \sin \left (d x +c \right )^{5} a^{6} d} \] Input:
int(cot(d*x+c)^4*csc(d*x+c)^2/(a+b*sin(d*x+c)),x)
Output:
(240*sqrt(a**2 - b**2)*atan((tan((c + d*x)/2)*a + b)/sqrt(a**2 - b**2))*si n(c + d*x)**5*a**2*b**2 - 240*sqrt(a**2 - b**2)*atan((tan((c + d*x)/2)*a + b)/sqrt(a**2 - b**2))*sin(c + d*x)**5*b**4 - 24*cos(c + d*x)*sin(c + d*x) **4*a**5 + 160*cos(c + d*x)*sin(c + d*x)**4*a**3*b**2 - 120*cos(c + d*x)*s in(c + d*x)**4*a*b**4 - 75*cos(c + d*x)*sin(c + d*x)**3*a**4*b + 60*cos(c + d*x)*sin(c + d*x)**3*a**2*b**3 + 48*cos(c + d*x)*sin(c + d*x)**2*a**5 - 40*cos(c + d*x)*sin(c + d*x)**2*a**3*b**2 + 30*cos(c + d*x)*sin(c + d*x)*a **4*b - 24*cos(c + d*x)*a**5 - 45*log(tan((c + d*x)/2))*sin(c + d*x)**5*a* *4*b + 180*log(tan((c + d*x)/2))*sin(c + d*x)**5*a**2*b**3 - 120*log(tan(( c + d*x)/2))*sin(c + d*x)**5*b**5)/(120*sin(c + d*x)**5*a**6*d)