\(\int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx\) [1436]

Optimal result
Mathematica [C] (warning: unable to verify)
Rubi [A] (verified)
Maple [B] (warning: unable to verify)
Fricas [F(-1)]
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 37, antiderivative size = 568 \[ \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx=-\frac {2 a}{\left (a^2-b^2\right ) d f g \sqrt {g \cos (e+f x)} \sqrt {d \sin (e+f x)}}+\frac {2 b^2 (g \cos (e+f x))^{3/2}}{a \left (a^2-b^2\right ) d f g^3 \sqrt {d \sin (e+f x)}}-\frac {2 \sqrt {2} b^3 \operatorname {EllipticPi}\left (-\frac {\sqrt {-a+b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {1+\sin (e+f x)}}\right ),-1\right ) \sqrt {\sin (e+f x)}}{a (-a+b)^{3/2} (a+b)^{3/2} d f g^{3/2} \sqrt {d \sin (e+f x)}}+\frac {2 \sqrt {2} b^3 \operatorname {EllipticPi}\left (\frac {\sqrt {-a+b}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {1+\sin (e+f x)}}\right ),-1\right ) \sqrt {\sin (e+f x)}}{a (-a+b)^{3/2} (a+b)^{3/2} d f g^{3/2} \sqrt {d \sin (e+f x)}}-\frac {2 b \sqrt {d \sin (e+f x)}}{\left (a^2-b^2\right ) d^2 f g \sqrt {g \cos (e+f x)}}+\frac {4 a (d \sin (e+f x))^{3/2}}{\left (a^2-b^2\right ) d^3 f g \sqrt {g \cos (e+f x)}}-\frac {4 a \sqrt {g \cos (e+f x)} E\left (\left .e-\frac {\pi }{4}+f x\right |2\right ) \sqrt {d \sin (e+f x)}}{\left (a^2-b^2\right ) d^2 f g^2 \sqrt {\sin (2 e+2 f x)}}+\frac {2 b^2 \sqrt {g \cos (e+f x)} E\left (\left .e-\frac {\pi }{4}+f x\right |2\right ) \sqrt {d \sin (e+f x)}}{a \left (a^2-b^2\right ) d^2 f g^2 \sqrt {\sin (2 e+2 f x)}} \] Output:

-2*a/(a^2-b^2)/d/f/g/(g*cos(f*x+e))^(1/2)/(d*sin(f*x+e))^(1/2)+2*b^2*(g*co 
s(f*x+e))^(3/2)/a/(a^2-b^2)/d/f/g^3/(d*sin(f*x+e))^(1/2)-2*2^(1/2)*b^3*Ell 
ipticPi((g*cos(f*x+e))^(1/2)/g^(1/2)/(1+sin(f*x+e))^(1/2),-(-a+b)^(1/2)/(a 
+b)^(1/2),I)*sin(f*x+e)^(1/2)/a/(-a+b)^(3/2)/(a+b)^(3/2)/d/f/g^(3/2)/(d*si 
n(f*x+e))^(1/2)+2*2^(1/2)*b^3*EllipticPi((g*cos(f*x+e))^(1/2)/g^(1/2)/(1+s 
in(f*x+e))^(1/2),(-a+b)^(1/2)/(a+b)^(1/2),I)*sin(f*x+e)^(1/2)/a/(-a+b)^(3/ 
2)/(a+b)^(3/2)/d/f/g^(3/2)/(d*sin(f*x+e))^(1/2)-2*b*(d*sin(f*x+e))^(1/2)/( 
a^2-b^2)/d^2/f/g/(g*cos(f*x+e))^(1/2)+4*a*(d*sin(f*x+e))^(3/2)/(a^2-b^2)/d 
^3/f/g/(g*cos(f*x+e))^(1/2)+4*a*(g*cos(f*x+e))^(1/2)*EllipticE(cos(e+1/4*P 
i+f*x),2^(1/2))*(d*sin(f*x+e))^(1/2)/(a^2-b^2)/d^2/f/g^2/sin(2*f*x+2*e)^(1 
/2)-2*b^2*(g*cos(f*x+e))^(1/2)*EllipticE(cos(e+1/4*Pi+f*x),2^(1/2))*(d*sin 
(f*x+e))^(1/2)/a/(a^2-b^2)/d^2/f/g^2/sin(2*f*x+2*e)^(1/2)
 

Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.

Time = 27.32 (sec) , antiderivative size = 1707, normalized size of antiderivative = 3.01 \[ \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx =\text {Too large to display} \] Input:

Integrate[1/((g*Cos[e + f*x])^(3/2)*(d*Sin[e + f*x])^(3/2)*(a + b*Sin[e + 
f*x])),x]
 

Output:

(Cos[e + f*x]^2*Sin[e + f*x]^2*((-2*Cot[e + f*x])/a + (2*Sec[e + f*x]*(-b 
+ a*Sin[e + f*x]))/(a^2 - b^2)))/(f*(g*Cos[e + f*x])^(3/2)*(d*Sin[e + f*x] 
)^(3/2)) - (Cos[e + f*x]^(3/2)*Sin[e + f*x]^(3/2)*((-2*(4*a^3 - 2*a*b^2)*( 
-(b*AppellF1[3/4, -1/4, 1, 7/4, Cos[e + f*x]^2, (b^2*Cos[e + f*x]^2)/(-a^2 
 + b^2)]) + a*AppellF1[3/4, 1/4, 1, 7/4, Cos[e + f*x]^2, (b^2*Cos[e + f*x] 
^2)/(-a^2 + b^2)])*Cos[e + f*x]^(3/2)*(a + b*Sqrt[1 - Cos[e + f*x]^2])*Sin 
[e + f*x]^(3/2))/(3*(a^2 - b^2)*(1 - Cos[e + f*x]^2)^(3/4)*(a + b*Sin[e + 
f*x])) + ((2*a^2*b - 2*b^3)*Sqrt[Tan[e + f*x]]*((3*Sqrt[2]*a^(3/2)*(-2*Arc 
Tan[1 - (Sqrt[2]*(a^2 - b^2)^(1/4)*Sqrt[Tan[e + f*x]])/Sqrt[a]] + 2*ArcTan 
[1 + (Sqrt[2]*(a^2 - b^2)^(1/4)*Sqrt[Tan[e + f*x]])/Sqrt[a]] - Log[-a + Sq 
rt[2]*Sqrt[a]*(a^2 - b^2)^(1/4)*Sqrt[Tan[e + f*x]] - Sqrt[a^2 - b^2]*Tan[e 
 + f*x]] + Log[a + Sqrt[2]*Sqrt[a]*(a^2 - b^2)^(1/4)*Sqrt[Tan[e + f*x]] + 
Sqrt[a^2 - b^2]*Tan[e + f*x]]))/(a^2 - b^2)^(1/4) - 8*b*AppellF1[3/4, 1/2, 
 1, 7/4, -Tan[e + f*x]^2, ((-a^2 + b^2)*Tan[e + f*x]^2)/a^2]*Tan[e + f*x]^ 
(3/2))*(b*Tan[e + f*x] + a*Sqrt[1 + Tan[e + f*x]^2]))/(12*a^2*Cos[e + f*x] 
^(3/2)*Sqrt[Sin[e + f*x]]*(a + b*Sin[e + f*x])*(1 + Tan[e + f*x]^2)^(3/2)) 
 + ((-2*a^2*b + b^3)*Cos[2*(e + f*x)]*Sqrt[Tan[e + f*x]]*(b*Tan[e + f*x] + 
 a*Sqrt[1 + Tan[e + f*x]^2])*(56*b*(-3*a^2 + b^2)*AppellF1[3/4, 1/2, 1, 7/ 
4, -Tan[e + f*x]^2, (-1 + b^2/a^2)*Tan[e + f*x]^2]*Tan[e + f*x]^(3/2) + 24 
*b*(-a^2 + b^2)*AppellF1[7/4, 1/2, 1, 11/4, -Tan[e + f*x]^2, (-1 + b^2/...
 

Rubi [A] (verified)

Time = 4.00 (sec) , antiderivative size = 495, normalized size of antiderivative = 0.87, number of steps used = 26, number of rules used = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.676, Rules used = {3042, 3383, 3042, 3317, 3042, 3043, 3050, 3042, 3051, 3042, 3052, 3042, 3119, 3389, 3042, 3050, 3042, 3052, 3042, 3119, 3385, 3042, 3384, 993, 1542}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{(d \sin (e+f x))^{3/2} (g \cos (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {1}{(d \sin (e+f x))^{3/2} (g \cos (e+f x))^{3/2} (a+b \sin (e+f x))}dx\)

\(\Big \downarrow \) 3383

\(\displaystyle \frac {\int \frac {a-b \sin (e+f x)}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2}}dx}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \frac {a-b \sin (e+f x)}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2}}dx}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3317

\(\displaystyle \frac {a \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2}}dx-\frac {b \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)}}dx}{d}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {a \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2}}dx-\frac {b \int \frac {1}{(g \cos (e+f x))^{3/2} \sqrt {d \sin (e+f x)}}dx}{d}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3043

\(\displaystyle \frac {a \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2}}dx-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3050

\(\displaystyle \frac {a \left (\frac {2 \int \frac {\sqrt {d \sin (e+f x)}}{(g \cos (e+f x))^{3/2}}dx}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {a \left (\frac {2 \int \frac {\sqrt {d \sin (e+f x)}}{(g \cos (e+f x))^{3/2}}dx}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3051

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 \int \sqrt {g \cos (e+f x)} \sqrt {d \sin (e+f x)}dx}{g^2}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 \int \sqrt {g \cos (e+f x)} \sqrt {d \sin (e+f x)}dx}{g^2}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3052

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3119

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2} (a+b \sin (e+f x))}dx}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3389

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {\int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2}}dx}{a}-\frac {b \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{a d}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {\int \frac {\sqrt {g \cos (e+f x)}}{(d \sin (e+f x))^{3/2}}dx}{a}-\frac {b \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{a d}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3050

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {-\frac {2 \int \sqrt {g \cos (e+f x)} \sqrt {d \sin (e+f x)}dx}{d^2}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}-\frac {b \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{a d}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {-\frac {2 \int \sqrt {g \cos (e+f x)} \sqrt {d \sin (e+f x)}dx}{d^2}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}-\frac {b \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{a d}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3052

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {-\frac {2 \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d^2 \sqrt {\sin (2 e+2 f x)}}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}-\frac {b \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{a d}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {-\frac {2 \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)} \int \sqrt {\sin (2 e+2 f x)}dx}{d^2 \sqrt {\sin (2 e+2 f x)}}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}-\frac {b \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{a d}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3119

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d^2 f \sqrt {\sin (2 e+2 f x)}}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}-\frac {b \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {d \sin (e+f x)} (a+b \sin (e+f x))}dx}{a d}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3385

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d^2 f \sqrt {\sin (2 e+2 f x)}}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}-\frac {b \sqrt {\sin (e+f x)} \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)} (a+b \sin (e+f x))}dx}{a d \sqrt {d \sin (e+f x)}}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d^2 f \sqrt {\sin (2 e+2 f x)}}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}-\frac {b \sqrt {\sin (e+f x)} \int \frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)} (a+b \sin (e+f x))}dx}{a d \sqrt {d \sin (e+f x)}}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 3384

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {4 \sqrt {2} b g \sqrt {\sin (e+f x)} \int \frac {g \cos (e+f x)}{(\sin (e+f x)+1) \sqrt {1-\frac {\cos ^2(e+f x)}{(\sin (e+f x)+1)^2}} \left ((a+b) g^2+\frac {(a-b) \cos ^2(e+f x) g^2}{(\sin (e+f x)+1)^2}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)+1}}}{a d f \sqrt {d \sin (e+f x)}}+\frac {-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d^2 f \sqrt {\sin (2 e+2 f x)}}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 993

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {4 \sqrt {2} b g \sqrt {\sin (e+f x)} \left (\frac {\int \frac {1}{\sqrt {1-\frac {\cos ^2(e+f x)}{(\sin (e+f x)+1)^2}} \left (\sqrt {a+b} g-\frac {\sqrt {b-a} g \cos (e+f x)}{\sin (e+f x)+1}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)+1}}}{2 \sqrt {b-a}}-\frac {\int \frac {1}{\sqrt {1-\frac {\cos ^2(e+f x)}{(\sin (e+f x)+1)^2}} \left (\sqrt {a+b} g+\frac {\sqrt {b-a} \cos (e+f x) g}{\sin (e+f x)+1}\right )}d\frac {\sqrt {g \cos (e+f x)}}{\sqrt {\sin (e+f x)+1}}}{2 \sqrt {b-a}}\right )}{a d f \sqrt {d \sin (e+f x)}}+\frac {-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d^2 f \sqrt {\sin (2 e+2 f x)}}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}\right )}{g^2 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 1542

\(\displaystyle \frac {a \left (\frac {2 \left (\frac {2 (d \sin (e+f x))^{3/2}}{d f g \sqrt {g \cos (e+f x)}}-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{f g^2 \sqrt {\sin (2 e+2 f x)}}\right )}{d^2}-\frac {2}{d f g \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}\right )-\frac {2 b \sqrt {d \sin (e+f x)}}{d^2 f g \sqrt {g \cos (e+f x)}}}{a^2-b^2}-\frac {b^2 \left (\frac {4 \sqrt {2} b g \sqrt {\sin (e+f x)} \left (\frac {\operatorname {EllipticPi}\left (\frac {\sqrt {b-a}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {\sin (e+f x)+1}}\right ),-1\right )}{2 \sqrt {g} \sqrt {b-a} \sqrt {a+b}}-\frac {\operatorname {EllipticPi}\left (-\frac {\sqrt {b-a}}{\sqrt {a+b}},\arcsin \left (\frac {\sqrt {g \cos (e+f x)}}{\sqrt {g} \sqrt {\sin (e+f x)+1}}\right ),-1\right )}{2 \sqrt {g} \sqrt {b-a} \sqrt {a+b}}\right )}{a d f \sqrt {d \sin (e+f x)}}+\frac {-\frac {2 E\left (\left .e+f x-\frac {\pi }{4}\right |2\right ) \sqrt {d \sin (e+f x)} \sqrt {g \cos (e+f x)}}{d^2 f \sqrt {\sin (2 e+2 f x)}}-\frac {2 (g \cos (e+f x))^{3/2}}{d f g \sqrt {d \sin (e+f x)}}}{a}\right )}{g^2 \left (a^2-b^2\right )}\)

Input:

Int[1/((g*Cos[e + f*x])^(3/2)*(d*Sin[e + f*x])^(3/2)*(a + b*Sin[e + f*x])) 
,x]
 

Output:

((-2*b*Sqrt[d*Sin[e + f*x]])/(d^2*f*g*Sqrt[g*Cos[e + f*x]]) + a*(-2/(d*f*g 
*Sqrt[g*Cos[e + f*x]]*Sqrt[d*Sin[e + f*x]]) + (2*((2*(d*Sin[e + f*x])^(3/2 
))/(d*f*g*Sqrt[g*Cos[e + f*x]]) - (2*Sqrt[g*Cos[e + f*x]]*EllipticE[e - Pi 
/4 + f*x, 2]*Sqrt[d*Sin[e + f*x]])/(f*g^2*Sqrt[Sin[2*e + 2*f*x]])))/d^2))/ 
(a^2 - b^2) - (b^2*((4*Sqrt[2]*b*g*(-1/2*EllipticPi[-(Sqrt[-a + b]/Sqrt[a 
+ b]), ArcSin[Sqrt[g*Cos[e + f*x]]/(Sqrt[g]*Sqrt[1 + Sin[e + f*x]])], -1]/ 
(Sqrt[-a + b]*Sqrt[a + b]*Sqrt[g]) + EllipticPi[Sqrt[-a + b]/Sqrt[a + b], 
ArcSin[Sqrt[g*Cos[e + f*x]]/(Sqrt[g]*Sqrt[1 + Sin[e + f*x]])], -1]/(2*Sqrt 
[-a + b]*Sqrt[a + b]*Sqrt[g]))*Sqrt[Sin[e + f*x]])/(a*d*f*Sqrt[d*Sin[e + f 
*x]]) + ((-2*(g*Cos[e + f*x])^(3/2))/(d*f*g*Sqrt[d*Sin[e + f*x]]) - (2*Sqr 
t[g*Cos[e + f*x]]*EllipticE[e - Pi/4 + f*x, 2]*Sqrt[d*Sin[e + f*x]])/(d^2* 
f*Sqrt[Sin[2*e + 2*f*x]]))/a))/((a^2 - b^2)*g^2)
 

Defintions of rubi rules used

rule 993
Int[(x_)^2/(((a_) + (b_.)*(x_)^4)*Sqrt[(c_) + (d_.)*(x_)^4]), x_Symbol] :> 
With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[s/(2* 
b)   Int[1/((r + s*x^2)*Sqrt[c + d*x^4]), x], x] - Simp[s/(2*b)   Int[1/((r 
 - s*x^2)*Sqrt[c + d*x^4]), x], x]] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - 
a*d, 0]
 

rule 1542
Int[1/(((d_) + (e_.)*(x_)^2)*Sqrt[(a_) + (c_.)*(x_)^4]), x_Symbol] :> With[ 
{q = Rt[-c/a, 4]}, Simp[(1/(d*Sqrt[a]*q))*EllipticPi[-e/(d*q^2), ArcSin[q*x 
], -1], x]] /; FreeQ[{a, c, d, e}, x] && NegQ[c/a] && GtQ[a, 0]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3043
Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_.)*((a_.)*sin[(e_.) + (f_.)*(x_)])^( 
m_.), x_Symbol] :> Simp[(a*Sin[e + f*x])^(m + 1)*((b*Cos[e + f*x])^(n + 1)/ 
(a*b*f*(m + 1))), x] /; FreeQ[{a, b, e, f, m, n}, x] && EqQ[m + n + 2, 0] & 
& NeQ[m, -1]
 

rule 3050
Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> Simp[(b*Cos[e + f*x])^(n + 1)*((a*Sin[e + f*x])^(m + 1)/(a 
*b*f*(m + 1))), x] + Simp[(m + n + 2)/(a^2*(m + 1))   Int[(b*Cos[e + f*x])^ 
n*(a*Sin[e + f*x])^(m + 2), x], x] /; FreeQ[{a, b, e, f, n}, x] && LtQ[m, - 
1] && IntegersQ[2*m, 2*n]
 

rule 3051
Int[(cos[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n 
_), x_Symbol] :> Simp[(-(b*Sin[e + f*x])^(n + 1))*((a*Cos[e + f*x])^(m + 1) 
/(a*b*f*(m + 1))), x] + Simp[(m + n + 2)/(a^2*(m + 1))   Int[(b*Sin[e + f*x 
])^n*(a*Cos[e + f*x])^(m + 2), x], x] /; FreeQ[{a, b, e, f, n}, x] && LtQ[m 
, -1] && IntegersQ[2*m, 2*n]
 

rule 3052
Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(b_.)]*Sqrt[(a_.)*sin[(e_.) + (f_.)*(x_)]] 
, x_Symbol] :> Simp[Sqrt[a*Sin[e + f*x]]*(Sqrt[b*Cos[e + f*x]]/Sqrt[Sin[2*e 
 + 2*f*x]])   Int[Sqrt[Sin[2*e + 2*f*x]], x], x] /; FreeQ[{a, b, e, f}, x]
 

rule 3119
Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)* 
(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
 

rule 3317
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n 
_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[a   Int[(g*Co 
s[e + f*x])^p*(d*Sin[e + f*x])^n, x], x] + Simp[b/d   Int[(g*Cos[e + f*x])^ 
p*(d*Sin[e + f*x])^(n + 1), x], x] /; FreeQ[{a, b, d, e, f, g, n, p}, x]
 

rule 3383
Int[((cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^( 
n_))/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[1/(a^2 - b^2 
)   Int[(g*Cos[e + f*x])^p*(d*Sin[e + f*x])^n*(a - b*Sin[e + f*x]), x], x] 
- Simp[b^2/(g^2*(a^2 - b^2))   Int[(g*Cos[e + f*x])^(p + 2)*((d*Sin[e + f*x 
])^n/(a + b*Sin[e + f*x])), x], x] /; FreeQ[{a, b, d, e, f, g}, x] && NeQ[a 
^2 - b^2, 0] && IntegersQ[2*n, 2*p] && LtQ[p, -1]
 

rule 3384
Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(g_.)]/(Sqrt[sin[(e_.) + (f_.)*(x_)]]*((a_ 
) + (b_.)*sin[(e_.) + (f_.)*(x_)])), x_Symbol] :> Simp[-4*Sqrt[2]*(g/f)   S 
ubst[Int[x^2/(((a + b)*g^2 + (a - b)*x^4)*Sqrt[1 - x^4/g^2]), x], x, Sqrt[g 
*Cos[e + f*x]]/Sqrt[1 + Sin[e + f*x]]], x] /; FreeQ[{a, b, e, f, g}, x] && 
NeQ[a^2 - b^2, 0]
 

rule 3385
Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(g_.)]/(Sqrt[(d_)*sin[(e_.) + (f_.)*(x_)]] 
*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])), x_Symbol] :> Simp[Sqrt[Sin[e + f* 
x]]/Sqrt[d*Sin[e + f*x]]   Int[Sqrt[g*Cos[e + f*x]]/(Sqrt[Sin[e + f*x]]*(a 
+ b*Sin[e + f*x])), x], x] /; FreeQ[{a, b, d, e, f, g}, x] && NeQ[a^2 - b^2 
, 0]
 

rule 3389
Int[((cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^( 
n_))/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[1/a   Int[(g 
*Cos[e + f*x])^p*(d*Sin[e + f*x])^n, x], x] - Simp[b/(a*d)   Int[(g*Cos[e + 
 f*x])^p*((d*Sin[e + f*x])^(n + 1)/(a + b*Sin[e + f*x])), x], x] /; FreeQ[{ 
a, b, d, e, f, g}, x] && NeQ[a^2 - b^2, 0] && IntegersQ[2*n, 2*p] && LtQ[-1 
, p, 1] && LtQ[n, 0]
 
Maple [B] (warning: unable to verify)

Leaf count of result is larger than twice the leaf count of optimal. \(1388\) vs. \(2(498)=996\).

Time = 4.11 (sec) , antiderivative size = 1389, normalized size of antiderivative = 2.45

method result size
default \(\text {Expression too large to display}\) \(1389\)

Input:

int(1/(g*cos(f*x+e))^(3/2)/(d*sin(f*x+e))^(3/2)/(a+b*sin(f*x+e)),x,method= 
_RETURNVERBOSE)
 

Output:

1/f*((csc(f*x+e)-cot(f*x+e)+1)^(1/2)*(-2*csc(f*x+e)+2*cot(f*x+e)+2)^(1/2)* 
(-csc(f*x+e)+cot(f*x+e))^(1/2)*(-1-cos(f*x+e))*a*EllipticPi((csc(f*x+e)-co 
t(f*x+e)+1)^(1/2),-a/(b+(-a^2+b^2)^(1/2)-a),1/2*2^(1/2))*b^3+(csc(f*x+e)-c 
ot(f*x+e)+1)^(1/2)*(-2*csc(f*x+e)+2*cot(f*x+e)+2)^(1/2)*(-csc(f*x+e)+cot(f 
*x+e))^(1/2)*(1+cos(f*x+e))*a*EllipticPi((csc(f*x+e)-cot(f*x+e)+1)^(1/2),a 
/(-b+(-a^2+b^2)^(1/2)+a),1/2*2^(1/2))*b^3-2*(csc(f*x+e)-cot(f*x+e)+1)^(1/2 
)*(-2*csc(f*x+e)+2*cot(f*x+e)+2)^(1/2)*(-csc(f*x+e)+cot(f*x+e))^(1/2)*(1+c 
os(f*x+e))*a*EllipticF((csc(f*x+e)-cot(f*x+e)+1)^(1/2),1/2*2^(1/2))*(-a^2+ 
b^2)^(1/2)*b^2+4*(csc(f*x+e)-cot(f*x+e)+1)^(1/2)*(-2*csc(f*x+e)+2*cot(f*x+ 
e)+2)^(1/2)*(-csc(f*x+e)+cot(f*x+e))^(1/2)*(1+cos(f*x+e))*a*EllipticE((csc 
(f*x+e)-cot(f*x+e)+1)^(1/2),1/2*2^(1/2))*(-a^2+b^2)^(1/2)*b^2-4*(-a^2+b^2) 
^(1/2)*cos(f*x+e)*a*b^2+4*sin(f*x+e)*(-a^2+b^2)^(1/2)*a^2*b+(csc(f*x+e)-co 
t(f*x+e)+1)^(1/2)*(-2*csc(f*x+e)+2*cot(f*x+e)+2)^(1/2)*(-csc(f*x+e)+cot(f* 
x+e))^(1/2)*(-1-cos(f*x+e))*EllipticPi((csc(f*x+e)-cot(f*x+e)+1)^(1/2),-a/ 
(b+(-a^2+b^2)^(1/2)-a),1/2*2^(1/2))*(-a^2+b^2)^(1/2)*b^3+(csc(f*x+e)-cot(f 
*x+e)+1)^(1/2)*(-2*csc(f*x+e)+2*cot(f*x+e)+2)^(1/2)*(-csc(f*x+e)+cot(f*x+e 
))^(1/2)*(-1-cos(f*x+e))*EllipticPi((csc(f*x+e)-cot(f*x+e)+1)^(1/2),-a/(b+ 
(-a^2+b^2)^(1/2)-a),1/2*2^(1/2))*b^4+(csc(f*x+e)-cot(f*x+e)+1)^(1/2)*(-2*c 
sc(f*x+e)+2*cot(f*x+e)+2)^(1/2)*(-csc(f*x+e)+cot(f*x+e))^(1/2)*(-1-cos(f*x 
+e))*EllipticPi((csc(f*x+e)-cot(f*x+e)+1)^(1/2),a/(-b+(-a^2+b^2)^(1/2)+...
 

Fricas [F(-1)]

Timed out. \[ \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx=\text {Timed out} \] Input:

integrate(1/(g*cos(f*x+e))^(3/2)/(d*sin(f*x+e))^(3/2)/(a+b*sin(f*x+e)),x, 
algorithm="fricas")
 

Output:

Timed out
 

Sympy [F(-1)]

Timed out. \[ \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx=\text {Timed out} \] Input:

integrate(1/(g*cos(f*x+e))**(3/2)/(d*sin(f*x+e))**(3/2)/(a+b*sin(f*x+e)),x 
)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx=\int { \frac {1}{\left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (b \sin \left (f x + e\right ) + a\right )} \left (d \sin \left (f x + e\right )\right )^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/(g*cos(f*x+e))^(3/2)/(d*sin(f*x+e))^(3/2)/(a+b*sin(f*x+e)),x, 
algorithm="maxima")
 

Output:

integrate(1/((g*cos(f*x + e))^(3/2)*(b*sin(f*x + e) + a)*(d*sin(f*x + e))^ 
(3/2)), x)
 

Giac [F]

\[ \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx=\int { \frac {1}{\left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (b \sin \left (f x + e\right ) + a\right )} \left (d \sin \left (f x + e\right )\right )^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/(g*cos(f*x+e))^(3/2)/(d*sin(f*x+e))^(3/2)/(a+b*sin(f*x+e)),x, 
algorithm="giac")
 

Output:

integrate(1/((g*cos(f*x + e))^(3/2)*(b*sin(f*x + e) + a)*(d*sin(f*x + e))^ 
(3/2)), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx=\int \frac {1}{{\left (g\,\cos \left (e+f\,x\right )\right )}^{3/2}\,{\left (d\,\sin \left (e+f\,x\right )\right )}^{3/2}\,\left (a+b\,\sin \left (e+f\,x\right )\right )} \,d x \] Input:

int(1/((g*cos(e + f*x))^(3/2)*(d*sin(e + f*x))^(3/2)*(a + b*sin(e + f*x))) 
,x)
 

Output:

int(1/((g*cos(e + f*x))^(3/2)*(d*sin(e + f*x))^(3/2)*(a + b*sin(e + f*x))) 
, x)
 

Reduce [F]

\[ \int \frac {1}{(g \cos (e+f x))^{3/2} (d \sin (e+f x))^{3/2} (a+b \sin (e+f x))} \, dx=\frac {\sqrt {g}\, \sqrt {d}\, \left (\int \frac {\sqrt {\sin \left (f x +e \right )}\, \sqrt {\cos \left (f x +e \right )}}{\cos \left (f x +e \right )^{2} \sin \left (f x +e \right )^{3} b +\cos \left (f x +e \right )^{2} \sin \left (f x +e \right )^{2} a}d x \right )}{d^{2} g^{2}} \] Input:

int(1/(g*cos(f*x+e))^(3/2)/(d*sin(f*x+e))^(3/2)/(a+b*sin(f*x+e)),x)
 

Output:

(sqrt(g)*sqrt(d)*int((sqrt(sin(e + f*x))*sqrt(cos(e + f*x)))/(cos(e + f*x) 
**2*sin(e + f*x)**3*b + cos(e + f*x)**2*sin(e + f*x)**2*a),x))/(d**2*g**2)