Integrand size = 36, antiderivative size = 89 \[ \int (g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^m (c-c \sin (e+f x)) \, dx=-\frac {2^{\frac {9}{4}+m} a c (g \cos (e+f x))^{9/2} \operatorname {Hypergeometric2F1}\left (\frac {9}{4},-\frac {1}{4}-m,\frac {13}{4},\frac {1}{2} (1-\sin (e+f x))\right ) (1+\sin (e+f x))^{-\frac {5}{4}-m} (a+a \sin (e+f x))^{-1+m}}{9 f g^3} \] Output:
-1/9*2^(9/4+m)*a*c*(g*cos(f*x+e))^(9/2)*hypergeom([9/4, -1/4-m],[13/4],1/2 -1/2*sin(f*x+e))*(1+sin(f*x+e))^(-5/4-m)*(a+a*sin(f*x+e))^(-1+m)/f/g^3
Time = 1.42 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.21 \[ \int (g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^m (c-c \sin (e+f x)) \, dx=\frac {2 c (g \cos (e+f x))^{5/2} (1+\sin (e+f x))^{-\frac {5}{4}-m} (a (1+\sin (e+f x)))^m \left (-2^{\frac {5}{4}+m} \operatorname {Hypergeometric2F1}\left (\frac {5}{4},-\frac {1}{4}-m,\frac {9}{4},\frac {1}{2} (1-\sin (e+f x))\right )+(1+\sin (e+f x))^{\frac {5}{4}+m}\right )}{f g (5+2 m)} \] Input:
Integrate[(g*Cos[e + f*x])^(3/2)*(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x ]),x]
Output:
(2*c*(g*Cos[e + f*x])^(5/2)*(1 + Sin[e + f*x])^(-5/4 - m)*(a*(1 + Sin[e + f*x]))^m*(-(2^(5/4 + m)*Hypergeometric2F1[5/4, -1/4 - m, 9/4, (1 - Sin[e + f*x])/2]) + (1 + Sin[e + f*x])^(5/4 + m)))/(f*g*(5 + 2*m))
Time = 0.48 (sec) , antiderivative size = 91, normalized size of antiderivative = 1.02, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3042, 3319, 3042, 3168, 80, 79}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (c-c \sin (e+f x)) (g \cos (e+f x))^{3/2} (a \sin (e+f x)+a)^m \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int (c-c \sin (e+f x)) (g \cos (e+f x))^{3/2} (a \sin (e+f x)+a)^mdx\) |
\(\Big \downarrow \) 3319 |
\(\displaystyle \frac {a c \int (g \cos (e+f x))^{7/2} (\sin (e+f x) a+a)^{m-1}dx}{g^2}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {a c \int (g \cos (e+f x))^{7/2} (\sin (e+f x) a+a)^{m-1}dx}{g^2}\) |
\(\Big \downarrow \) 3168 |
\(\displaystyle \frac {a^3 c (g \cos (e+f x))^{9/2} \int (a-a \sin (e+f x))^{5/4} (\sin (e+f x) a+a)^{m+\frac {1}{4}}d\sin (e+f x)}{f g^3 (a-a \sin (e+f x))^{9/4} (a \sin (e+f x)+a)^{9/4}}\) |
\(\Big \downarrow \) 80 |
\(\displaystyle \frac {a^3 c 2^{m+\frac {1}{4}} (g \cos (e+f x))^{9/2} (\sin (e+f x)+1)^{-m-\frac {1}{4}} (a \sin (e+f x)+a)^{m-2} \int \left (\frac {1}{2} \sin (e+f x)+\frac {1}{2}\right )^{m+\frac {1}{4}} (a-a \sin (e+f x))^{5/4}d\sin (e+f x)}{f g^3 (a-a \sin (e+f x))^{9/4}}\) |
\(\Big \downarrow \) 79 |
\(\displaystyle -\frac {a^2 c 2^{m+\frac {9}{4}} (g \cos (e+f x))^{9/2} (\sin (e+f x)+1)^{-m-\frac {1}{4}} (a \sin (e+f x)+a)^{m-2} \operatorname {Hypergeometric2F1}\left (\frac {9}{4},-m-\frac {1}{4},\frac {13}{4},\frac {1}{2} (1-\sin (e+f x))\right )}{9 f g^3}\) |
Input:
Int[(g*Cos[e + f*x])^(3/2)*(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x]),x]
Output:
-1/9*(2^(9/4 + m)*a^2*c*(g*Cos[e + f*x])^(9/2)*Hypergeometric2F1[9/4, -1/4 - m, 13/4, (1 - Sin[e + f*x])/2]*(1 + Sin[e + f*x])^(-1/4 - m)*(a + a*Sin [e + f*x])^(-2 + m))/(f*g^3)
Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(( a + b*x)^(m + 1)/(b*(m + 1)*(b/(b*c - a*d))^n))*Hypergeometric2F1[-n, m + 1 , m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m, n}, x] && !IntegerQ[m] && !IntegerQ[n] && GtQ[b/(b*c - a*d), 0] && (RationalQ[m] || !(RationalQ[n] && GtQ[-d/(b*c - a*d), 0]))
Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(c + d*x)^FracPart[n]/((b/(b*c - a*d))^IntPart[n]*(b*((c + d*x)/(b*c - a*d))) ^FracPart[n]) Int[(a + b*x)^m*Simp[b*(c/(b*c - a*d)) + b*d*(x/(b*c - a*d) ), x]^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && !IntegerQ[m] && !Integ erQ[n] && (RationalQ[m] || !SimplerQ[n + 1, m + 1])
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_.), x_Symbol] :> Simp[a^2*((g*Cos[e + f*x])^(p + 1)/(f*g*(a + b*Sin [e + f*x])^((p + 1)/2)*(a - b*Sin[e + f*x])^((p + 1)/2))) Subst[Int[(a + b*x)^(m + (p - 1)/2)*(a - b*x)^((p - 1)/2), x], x, Sin[e + f*x]], x] /; Fre eQ[{a, b, e, f, g, m, p}, x] && EqQ[a^2 - b^2, 0] && !IntegerQ[m]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_.)*((c_) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Simp[ a^m*(c^m/g^(2*m)) Int[(g*Cos[e + f*x])^(2*m + p)*(c + d*Sin[e + f*x])^(n - m), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && EqQ[b*c + a*d, 0] && EqQ[a^2 - b^2, 0] && IntegerQ[m] && !(IntegerQ[n] && LtQ[n^2, m^2])
\[\int \left (g \cos \left (f x +e \right )\right )^{\frac {3}{2}} \left (a +a \sin \left (f x +e \right )\right )^{m} \left (c -c \sin \left (f x +e \right )\right )d x\]
Input:
int((g*cos(f*x+e))^(3/2)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e)),x)
Output:
int((g*cos(f*x+e))^(3/2)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e)),x)
\[ \int (g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^m (c-c \sin (e+f x)) \, dx=\int { -\left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (c \sin \left (f x + e\right ) - c\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} \,d x } \] Input:
integrate((g*cos(f*x+e))^(3/2)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e)),x, algo rithm="fricas")
Output:
integral(-(c*g*cos(f*x + e)*sin(f*x + e) - c*g*cos(f*x + e))*sqrt(g*cos(f* x + e))*(a*sin(f*x + e) + a)^m, x)
Timed out. \[ \int (g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^m (c-c \sin (e+f x)) \, dx=\text {Timed out} \] Input:
integrate((g*cos(f*x+e))**(3/2)*(a+a*sin(f*x+e))**m*(c-c*sin(f*x+e)),x)
Output:
Timed out
\[ \int (g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^m (c-c \sin (e+f x)) \, dx=\int { -\left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (c \sin \left (f x + e\right ) - c\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} \,d x } \] Input:
integrate((g*cos(f*x+e))^(3/2)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e)),x, algo rithm="maxima")
Output:
-integrate((g*cos(f*x + e))^(3/2)*(c*sin(f*x + e) - c)*(a*sin(f*x + e) + a )^m, x)
\[ \int (g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^m (c-c \sin (e+f x)) \, dx=\int { -\left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (c \sin \left (f x + e\right ) - c\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} \,d x } \] Input:
integrate((g*cos(f*x+e))^(3/2)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e)),x, algo rithm="giac")
Output:
integrate(-(g*cos(f*x + e))^(3/2)*(c*sin(f*x + e) - c)*(a*sin(f*x + e) + a )^m, x)
Timed out. \[ \int (g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^m (c-c \sin (e+f x)) \, dx=\int {\left (g\,\cos \left (e+f\,x\right )\right )}^{3/2}\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (c-c\,\sin \left (e+f\,x\right )\right ) \,d x \] Input:
int((g*cos(e + f*x))^(3/2)*(a + a*sin(e + f*x))^m*(c - c*sin(e + f*x)),x)
Output:
int((g*cos(e + f*x))^(3/2)*(a + a*sin(e + f*x))^m*(c - c*sin(e + f*x)), x)
\[ \int (g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^m (c-c \sin (e+f x)) \, dx=\sqrt {g}\, c g \left (-\left (\int \left (a +a \sin \left (f x +e \right )\right )^{m} \sqrt {\cos \left (f x +e \right )}\, \cos \left (f x +e \right ) \sin \left (f x +e \right )d x \right )+\int \left (a +a \sin \left (f x +e \right )\right )^{m} \sqrt {\cos \left (f x +e \right )}\, \cos \left (f x +e \right )d x \right ) \] Input:
int((g*cos(f*x+e))^(3/2)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e)),x)
Output:
sqrt(g)*c*g*( - int((sin(e + f*x)*a + a)**m*sqrt(cos(e + f*x))*cos(e + f*x )*sin(e + f*x),x) + int((sin(e + f*x)*a + a)**m*sqrt(cos(e + f*x))*cos(e + f*x),x))