Integrand size = 25, antiderivative size = 65 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=-\frac {a \cos ^6(c+d x)}{6 d}+\frac {a \sin ^3(c+d x)}{3 d}-\frac {2 a \sin ^5(c+d x)}{5 d}+\frac {a \sin ^7(c+d x)}{7 d} \] Output:
-1/6*a*cos(d*x+c)^6/d+1/3*a*sin(d*x+c)^3/d-2/5*a*sin(d*x+c)^5/d+1/7*a*sin( d*x+c)^7/d
Time = 0.14 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.20 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=-\frac {a (350+525 \cos (2 (c+d x))+210 \cos (4 (c+d x))+35 \cos (6 (c+d x))-525 \sin (c+d x)+35 \sin (3 (c+d x))+63 \sin (5 (c+d x))+15 \sin (7 (c+d x)))}{6720 d} \] Input:
Integrate[Cos[c + d*x]^5*Sin[c + d*x]*(a + a*Sin[c + d*x]),x]
Output:
-1/6720*(a*(350 + 525*Cos[2*(c + d*x)] + 210*Cos[4*(c + d*x)] + 35*Cos[6*( c + d*x)] - 525*Sin[c + d*x] + 35*Sin[3*(c + d*x)] + 63*Sin[5*(c + d*x)] + 15*Sin[7*(c + d*x)]))/d
Time = 0.38 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.91, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {3042, 3313, 3042, 3044, 244, 2009, 3045, 15}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sin (c+d x) \cos ^5(c+d x) (a \sin (c+d x)+a) \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \sin (c+d x) \cos (c+d x)^5 (a \sin (c+d x)+a)dx\) |
\(\Big \downarrow \) 3313 |
\(\displaystyle a \int \cos ^5(c+d x) \sin ^2(c+d x)dx+a \int \cos ^5(c+d x) \sin (c+d x)dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle a \int \cos (c+d x)^5 \sin (c+d x)dx+a \int \cos (c+d x)^5 \sin (c+d x)^2dx\) |
\(\Big \downarrow \) 3044 |
\(\displaystyle \frac {a \int \sin ^2(c+d x) \left (1-\sin ^2(c+d x)\right )^2d\sin (c+d x)}{d}+a \int \cos (c+d x)^5 \sin (c+d x)dx\) |
\(\Big \downarrow \) 244 |
\(\displaystyle \frac {a \int \left (\sin ^6(c+d x)-2 \sin ^4(c+d x)+\sin ^2(c+d x)\right )d\sin (c+d x)}{d}+a \int \cos (c+d x)^5 \sin (c+d x)dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle a \int \cos (c+d x)^5 \sin (c+d x)dx+\frac {a \left (\frac {1}{7} \sin ^7(c+d x)-\frac {2}{5} \sin ^5(c+d x)+\frac {1}{3} \sin ^3(c+d x)\right )}{d}\) |
\(\Big \downarrow \) 3045 |
\(\displaystyle \frac {a \left (\frac {1}{7} \sin ^7(c+d x)-\frac {2}{5} \sin ^5(c+d x)+\frac {1}{3} \sin ^3(c+d x)\right )}{d}-\frac {a \int \cos ^5(c+d x)d\cos (c+d x)}{d}\) |
\(\Big \downarrow \) 15 |
\(\displaystyle \frac {a \left (\frac {1}{7} \sin ^7(c+d x)-\frac {2}{5} \sin ^5(c+d x)+\frac {1}{3} \sin ^3(c+d x)\right )}{d}-\frac {a \cos ^6(c+d x)}{6 d}\) |
Input:
Int[Cos[c + d*x]^5*Sin[c + d*x]*(a + a*Sin[c + d*x]),x]
Output:
-1/6*(a*Cos[c + d*x]^6)/d + (a*(Sin[c + d*x]^3/3 - (2*Sin[c + d*x]^5)/5 + Sin[c + d*x]^7/7))/d
Int[(a_.)*(x_)^(m_.), x_Symbol] :> Simp[a*(x^(m + 1)/(m + 1)), x] /; FreeQ[ {a, m}, x] && NeQ[m, -1]
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Int[Expand Integrand[(c*x)^m*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, m}, x] && IGtQ[p , 0]
Int[cos[(e_.) + (f_.)*(x_)]^(n_.)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_.), x_ Symbol] :> Simp[1/(a*f) Subst[Int[x^m*(1 - x^2/a^2)^((n - 1)/2), x], x, a *Sin[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n - 1)/2] && !(I ntegerQ[(m - 1)/2] && LtQ[0, m, n])
Int[(cos[(e_.) + (f_.)*(x_)]*(a_.))^(m_.)*sin[(e_.) + (f_.)*(x_)]^(n_.), x_ Symbol] :> Simp[-(a*f)^(-1) Subst[Int[x^m*(1 - x^2/a^2)^((n - 1)/2), x], x, a*Cos[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n - 1)/2] && !(IntegerQ[(m - 1)/2] && GtQ[m, 0] && LeQ[m, n])
Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((a_ ) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[a Int[Cos[e + f*x]^ p*(d*Sin[e + f*x])^n, x], x] + Simp[b/d Int[Cos[e + f*x]^p*(d*Sin[e + f*x ])^(n + 1), x], x] /; FreeQ[{a, b, d, e, f, n, p}, x] && IntegerQ[(p - 1)/2 ] && IntegerQ[n] && ((LtQ[p, 0] && NeQ[a^2 - b^2, 0]) || LtQ[0, n, p - 1] | | LtQ[p + 1, -n, 2*p + 1])
Time = 14.82 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.03
method | result | size |
derivativedivides | \(\frac {a \left (\frac {\sin \left (d x +c \right )^{7}}{7}+\frac {\sin \left (d x +c \right )^{6}}{6}-\frac {2 \sin \left (d x +c \right )^{5}}{5}-\frac {\sin \left (d x +c \right )^{4}}{2}+\frac {\sin \left (d x +c \right )^{3}}{3}+\frac {\sin \left (d x +c \right )^{2}}{2}\right )}{d}\) | \(67\) |
default | \(\frac {a \left (\frac {\sin \left (d x +c \right )^{7}}{7}+\frac {\sin \left (d x +c \right )^{6}}{6}-\frac {2 \sin \left (d x +c \right )^{5}}{5}-\frac {\sin \left (d x +c \right )^{4}}{2}+\frac {\sin \left (d x +c \right )^{3}}{3}+\frac {\sin \left (d x +c \right )^{2}}{2}\right )}{d}\) | \(67\) |
parallelrisch | \(-\frac {a \left (15 \sin \left (7 d x +7 c \right )+35 \sin \left (3 d x +3 c \right )+63 \sin \left (5 d x +5 c \right )-525 \sin \left (d x +c \right )+525 \cos \left (2 d x +2 c \right )+35 \cos \left (6 d x +6 c \right )+210 \cos \left (4 d x +4 c \right )-770\right )}{6720 d}\) | \(83\) |
risch | \(\frac {5 a \sin \left (d x +c \right )}{64 d}-\frac {a \sin \left (7 d x +7 c \right )}{448 d}-\frac {a \cos \left (6 d x +6 c \right )}{192 d}-\frac {3 a \sin \left (5 d x +5 c \right )}{320 d}-\frac {a \cos \left (4 d x +4 c \right )}{32 d}-\frac {a \sin \left (3 d x +3 c \right )}{192 d}-\frac {5 a \cos \left (2 d x +2 c \right )}{64 d}\) | \(104\) |
norman | \(\frac {\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{d}+\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{12}}{d}+\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{d}+\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{10}}{d}+\frac {8 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3 d}-\frac {32 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{15 d}+\frac {304 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{35 d}-\frac {32 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}}{15 d}+\frac {8 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{11}}{3 d}+\frac {20 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{3 d}+\frac {20 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}}{3 d}}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{7}}\) | \(205\) |
orering | \(\text {Expression too large to display}\) | \(1153\) |
Input:
int(cos(d*x+c)^5*sin(d*x+c)*(a+a*sin(d*x+c)),x,method=_RETURNVERBOSE)
Output:
a/d*(1/7*sin(d*x+c)^7+1/6*sin(d*x+c)^6-2/5*sin(d*x+c)^5-1/2*sin(d*x+c)^4+1 /3*sin(d*x+c)^3+1/2*sin(d*x+c)^2)
Time = 0.08 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.95 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=-\frac {35 \, a \cos \left (d x + c\right )^{6} + 2 \, {\left (15 \, a \cos \left (d x + c\right )^{6} - 3 \, a \cos \left (d x + c\right )^{4} - 4 \, a \cos \left (d x + c\right )^{2} - 8 \, a\right )} \sin \left (d x + c\right )}{210 \, d} \] Input:
integrate(cos(d*x+c)^5*sin(d*x+c)*(a+a*sin(d*x+c)),x, algorithm="fricas")
Output:
-1/210*(35*a*cos(d*x + c)^6 + 2*(15*a*cos(d*x + c)^6 - 3*a*cos(d*x + c)^4 - 4*a*cos(d*x + c)^2 - 8*a)*sin(d*x + c))/d
Time = 0.49 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.38 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\begin {cases} \frac {8 a \sin ^{7}{\left (c + d x \right )}}{105 d} + \frac {4 a \sin ^{5}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{15 d} + \frac {a \sin ^{3}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{3 d} - \frac {a \cos ^{6}{\left (c + d x \right )}}{6 d} & \text {for}\: d \neq 0 \\x \left (a \sin {\left (c \right )} + a\right ) \sin {\left (c \right )} \cos ^{5}{\left (c \right )} & \text {otherwise} \end {cases} \] Input:
integrate(cos(d*x+c)**5*sin(d*x+c)*(a+a*sin(d*x+c)),x)
Output:
Piecewise((8*a*sin(c + d*x)**7/(105*d) + 4*a*sin(c + d*x)**5*cos(c + d*x)* *2/(15*d) + a*sin(c + d*x)**3*cos(c + d*x)**4/(3*d) - a*cos(c + d*x)**6/(6 *d), Ne(d, 0)), (x*(a*sin(c) + a)*sin(c)*cos(c)**5, True))
Time = 0.03 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.11 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {30 \, a \sin \left (d x + c\right )^{7} + 35 \, a \sin \left (d x + c\right )^{6} - 84 \, a \sin \left (d x + c\right )^{5} - 105 \, a \sin \left (d x + c\right )^{4} + 70 \, a \sin \left (d x + c\right )^{3} + 105 \, a \sin \left (d x + c\right )^{2}}{210 \, d} \] Input:
integrate(cos(d*x+c)^5*sin(d*x+c)*(a+a*sin(d*x+c)),x, algorithm="maxima")
Output:
1/210*(30*a*sin(d*x + c)^7 + 35*a*sin(d*x + c)^6 - 84*a*sin(d*x + c)^5 - 1 05*a*sin(d*x + c)^4 + 70*a*sin(d*x + c)^3 + 105*a*sin(d*x + c)^2)/d
Time = 0.15 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.11 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {30 \, a \sin \left (d x + c\right )^{7} + 35 \, a \sin \left (d x + c\right )^{6} - 84 \, a \sin \left (d x + c\right )^{5} - 105 \, a \sin \left (d x + c\right )^{4} + 70 \, a \sin \left (d x + c\right )^{3} + 105 \, a \sin \left (d x + c\right )^{2}}{210 \, d} \] Input:
integrate(cos(d*x+c)^5*sin(d*x+c)*(a+a*sin(d*x+c)),x, algorithm="giac")
Output:
1/210*(30*a*sin(d*x + c)^7 + 35*a*sin(d*x + c)^6 - 84*a*sin(d*x + c)^5 - 1 05*a*sin(d*x + c)^4 + 70*a*sin(d*x + c)^3 + 105*a*sin(d*x + c)^2)/d
Time = 18.11 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.09 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {\frac {a\,{\sin \left (c+d\,x\right )}^7}{7}+\frac {a\,{\sin \left (c+d\,x\right )}^6}{6}-\frac {2\,a\,{\sin \left (c+d\,x\right )}^5}{5}-\frac {a\,{\sin \left (c+d\,x\right )}^4}{2}+\frac {a\,{\sin \left (c+d\,x\right )}^3}{3}+\frac {a\,{\sin \left (c+d\,x\right )}^2}{2}}{d} \] Input:
int(cos(c + d*x)^5*sin(c + d*x)*(a + a*sin(c + d*x)),x)
Output:
((a*sin(c + d*x)^2)/2 + (a*sin(c + d*x)^3)/3 - (a*sin(c + d*x)^4)/2 - (2*a *sin(c + d*x)^5)/5 + (a*sin(c + d*x)^6)/6 + (a*sin(c + d*x)^7)/7)/d
Time = 0.15 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.98 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {\sin \left (d x +c \right )^{2} a \left (30 \sin \left (d x +c \right )^{5}+35 \sin \left (d x +c \right )^{4}-84 \sin \left (d x +c \right )^{3}-105 \sin \left (d x +c \right )^{2}+70 \sin \left (d x +c \right )+105\right )}{210 d} \] Input:
int(cos(d*x+c)^5*sin(d*x+c)*(a+a*sin(d*x+c)),x)
Output:
(sin(c + d*x)**2*a*(30*sin(c + d*x)**5 + 35*sin(c + d*x)**4 - 84*sin(c + d *x)**3 - 105*sin(c + d*x)**2 + 70*sin(c + d*x) + 105))/(210*d)