Integrand size = 29, antiderivative size = 77 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^3 \tan ^2(c+d x) \, dx=3 a^3 x-\frac {3 a^3 \cos (c+d x)}{d}-\frac {2 a^5 \cos ^3(c+d x)}{d (a-a \sin (c+d x))^2}+\frac {\sec ^3(c+d x) (a+a \sin (c+d x))^3}{3 d} \] Output:
3*a^3*x-3*a^3*cos(d*x+c)/d-2*a^5*cos(d*x+c)^3/d/(a-a*sin(d*x+c))^2+1/3*sec (d*x+c)^3*(a+a*sin(d*x+c))^3/d
Time = 7.16 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.73 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^3 \tan ^2(c+d x) \, dx=\frac {a^3 (1+\sin (c+d x))^3 \left (9 c+9 d x-3 \cos (c+d x)+\frac {2}{\left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^2}+\frac {2 \sin \left (\frac {1}{2} (c+d x)\right ) (-11+13 \sin (c+d x))}{\left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^3}\right )}{3 d \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^6} \] Input:
Integrate[Sec[c + d*x]^2*(a + a*Sin[c + d*x])^3*Tan[c + d*x]^2,x]
Output:
(a^3*(1 + Sin[c + d*x])^3*(9*c + 9*d*x - 3*Cos[c + d*x] + 2/(Cos[(c + d*x) /2] - Sin[(c + d*x)/2])^2 + (2*Sin[(c + d*x)/2]*(-11 + 13*Sin[c + d*x]))/( Cos[(c + d*x)/2] - Sin[(c + d*x)/2])^3))/(3*d*(Cos[(c + d*x)/2] + Sin[(c + d*x)/2])^6)
Time = 0.59 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.14, number of steps used = 9, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.310, Rules used = {3042, 3350, 3042, 3149, 3042, 3159, 3042, 3161, 24}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \tan ^2(c+d x) \sec ^2(c+d x) (a \sin (c+d x)+a)^3 \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {\sin (c+d x)^2 (a \sin (c+d x)+a)^3}{\cos (c+d x)^4}dx\) |
| \(\Big \downarrow \) 3350 |
| \(\displaystyle \frac {\sec ^3(c+d x) (a \sin (c+d x)+a)^3}{3 d}-\int \sec ^2(c+d x) (\sin (c+d x) a+a)^3dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\sec ^3(c+d x) (a \sin (c+d x)+a)^3}{3 d}-\int \frac {(\sin (c+d x) a+a)^3}{\cos (c+d x)^2}dx\) |
| \(\Big \downarrow \) 3149 |
| \(\displaystyle \frac {\sec ^3(c+d x) (a \sin (c+d x)+a)^3}{3 d}-a^6 \int \frac {\cos ^4(c+d x)}{(a-a \sin (c+d x))^3}dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\sec ^3(c+d x) (a \sin (c+d x)+a)^3}{3 d}-a^6 \int \frac {\cos (c+d x)^4}{(a-a \sin (c+d x))^3}dx\) |
| \(\Big \downarrow \) 3159 |
| \(\displaystyle \frac {\sec ^3(c+d x) (a \sin (c+d x)+a)^3}{3 d}-a^6 \left (\frac {2 \cos ^3(c+d x)}{a d (a-a \sin (c+d x))^2}-\frac {3 \int \frac {\cos ^2(c+d x)}{a-a \sin (c+d x)}dx}{a^2}\right )\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\sec ^3(c+d x) (a \sin (c+d x)+a)^3}{3 d}-a^6 \left (\frac {2 \cos ^3(c+d x)}{a d (a-a \sin (c+d x))^2}-\frac {3 \int \frac {\cos (c+d x)^2}{a-a \sin (c+d x)}dx}{a^2}\right )\) |
| \(\Big \downarrow \) 3161 |
| \(\displaystyle \frac {\sec ^3(c+d x) (a \sin (c+d x)+a)^3}{3 d}-a^6 \left (\frac {2 \cos ^3(c+d x)}{a d (a-a \sin (c+d x))^2}-\frac {3 \left (\frac {\int 1dx}{a}-\frac {\cos (c+d x)}{a d}\right )}{a^2}\right )\) |
| \(\Big \downarrow \) 24 |
| \(\displaystyle \frac {\sec ^3(c+d x) (a \sin (c+d x)+a)^3}{3 d}-a^6 \left (\frac {2 \cos ^3(c+d x)}{a d (a-a \sin (c+d x))^2}-\frac {3 \left (\frac {x}{a}-\frac {\cos (c+d x)}{a d}\right )}{a^2}\right )\) |
Input:
Int[Sec[c + d*x]^2*(a + a*Sin[c + d*x])^3*Tan[c + d*x]^2,x]
Output:
(Sec[c + d*x]^3*(a + a*Sin[c + d*x])^3)/(3*d) - a^6*((-3*(x/a - Cos[c + d* x]/(a*d)))/a^2 + (2*Cos[c + d*x]^3)/(a*d*(a - a*Sin[c + d*x])^2))
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[(a/g)^(2*m) Int[(g*Cos[e + f*x])^(2*m + p)/( a - b*Sin[e + f*x])^m, x], x] /; FreeQ[{a, b, e, f, g}, x] && EqQ[a^2 - b^2 , 0] && IntegerQ[m] && LtQ[p, -1] && GeQ[2*m + p, 0]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[2*g*(g*Cos[e + f*x])^(p - 1)*((a + b*Sin[e + f *x])^(m + 1)/(b*f*(2*m + p + 1))), x] + Simp[g^2*((p - 1)/(b^2*(2*m + p + 1 ))) Int[(g*Cos[e + f*x])^(p - 2)*(a + b*Sin[e + f*x])^(m + 2), x], x] /; FreeQ[{a, b, e, f, g}, x] && EqQ[a^2 - b^2, 0] && LeQ[m, -2] && GtQ[p, 1] & & NeQ[2*m + p + 1, 0] && !ILtQ[m + p + 1, 0] && IntegersQ[2*m, 2*p]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)/((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)]), x_Symbol] :> Simp[g*((g*Cos[e + f*x])^(p - 1)/(b*f*(p - 1))), x] + Si mp[g^2/a Int[(g*Cos[e + f*x])^(p - 2), x], x] /; FreeQ[{a, b, e, f, g}, x ] && EqQ[a^2 - b^2, 0] && GtQ[p, 1] && IntegerQ[2*p]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*sin[(e_.) + (f_.)*(x_)]^2*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[b*(g*Cos[e + f*x])^( p + 1)*((a + b*Sin[e + f*x])^m/(a*f*g*m)), x] - Simp[1/g^2 Int[(g*Cos[e + f*x])^(p + 2)*(a + b*Sin[e + f*x])^m, x], x] /; FreeQ[{a, b, e, f, g, m, p }, x] && EqQ[a^2 - b^2, 0] && EqQ[m + p + 1, 0]
Result contains complex when optimal does not.
Time = 2.80 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.25
| method | result | size |
| risch | \(3 a^{3} x -\frac {a^{3} {\mathrm e}^{i \left (d x +c \right )}}{2 d}-\frac {a^{3} {\mathrm e}^{-i \left (d x +c \right )}}{2 d}-\frac {2 \left (-24 i a^{3} {\mathrm e}^{i \left (d x +c \right )}-13 a^{3}+15 a^{3} {\mathrm e}^{2 i \left (d x +c \right )}\right )}{3 \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )^{3} d}\) | \(96\) |
| derivativedivides | \(\frac {a^{3} \left (\frac {\sin \left (d x +c \right )^{6}}{3 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{6}}{\cos \left (d x +c \right )}-\left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )\right )+3 a^{3} \left (\frac {\tan \left (d x +c \right )^{3}}{3}-\tan \left (d x +c \right )+d x +c \right )+3 a^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{3 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{4}}{3 \cos \left (d x +c \right )}-\frac {\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )}{3}\right )+\frac {a^{3} \sin \left (d x +c \right )^{3}}{3 \cos \left (d x +c \right )^{3}}}{d}\) | \(184\) |
| default | \(\frac {a^{3} \left (\frac {\sin \left (d x +c \right )^{6}}{3 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{6}}{\cos \left (d x +c \right )}-\left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )\right )+3 a^{3} \left (\frac {\tan \left (d x +c \right )^{3}}{3}-\tan \left (d x +c \right )+d x +c \right )+3 a^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{3 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{4}}{3 \cos \left (d x +c \right )}-\frac {\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )}{3}\right )+\frac {a^{3} \sin \left (d x +c \right )^{3}}{3 \cos \left (d x +c \right )^{3}}}{d}\) | \(184\) |
Input:
int(sec(d*x+c)^2*(a+a*sin(d*x+c))^3*tan(d*x+c)^2,x,method=_RETURNVERBOSE)
Output:
3*a^3*x-1/2*a^3/d*exp(I*(d*x+c))-1/2*a^3/d*exp(-I*(d*x+c))-2/3*(-24*I*a^3* exp(I*(d*x+c))-13*a^3+15*a^3*exp(2*I*(d*x+c)))/(exp(I*(d*x+c))-I)^3/d
Leaf count of result is larger than twice the leaf count of optimal. 169 vs. \(2 (76) = 152\).
Time = 0.08 (sec) , antiderivative size = 169, normalized size of antiderivative = 2.19 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^3 \tan ^2(c+d x) \, dx=-\frac {3 \, a^{3} \cos \left (d x + c\right )^{3} + 18 \, a^{3} d x + 2 \, a^{3} - {\left (9 \, a^{3} d x + 16 \, a^{3}\right )} \cos \left (d x + c\right )^{2} + {\left (9 \, a^{3} d x - 17 \, a^{3}\right )} \cos \left (d x + c\right ) - {\left (18 \, a^{3} d x - 3 \, a^{3} \cos \left (d x + c\right )^{2} - 2 \, a^{3} + {\left (9 \, a^{3} d x - 19 \, a^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{3 \, {\left (d \cos \left (d x + c\right )^{2} - d \cos \left (d x + c\right ) + {\left (d \cos \left (d x + c\right ) + 2 \, d\right )} \sin \left (d x + c\right ) - 2 \, d\right )}} \] Input:
integrate(sec(d*x+c)^2*(a+a*sin(d*x+c))^3*tan(d*x+c)^2,x, algorithm="frica s")
Output:
-1/3*(3*a^3*cos(d*x + c)^3 + 18*a^3*d*x + 2*a^3 - (9*a^3*d*x + 16*a^3)*cos (d*x + c)^2 + (9*a^3*d*x - 17*a^3)*cos(d*x + c) - (18*a^3*d*x - 3*a^3*cos( d*x + c)^2 - 2*a^3 + (9*a^3*d*x - 19*a^3)*cos(d*x + c))*sin(d*x + c))/(d*c os(d*x + c)^2 - d*cos(d*x + c) + (d*cos(d*x + c) + 2*d)*sin(d*x + c) - 2*d )
\[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^3 \tan ^2(c+d x) \, dx=a^{3} \left (\int \tan ^{2}{\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}\, dx + \int 3 \sin {\left (c + d x \right )} \tan ^{2}{\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}\, dx + \int 3 \sin ^{2}{\left (c + d x \right )} \tan ^{2}{\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}\, dx + \int \sin ^{3}{\left (c + d x \right )} \tan ^{2}{\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}\, dx\right ) \] Input:
integrate(sec(d*x+c)**2*(a+a*sin(d*x+c))**3*tan(d*x+c)**2,x)
Output:
a**3*(Integral(tan(c + d*x)**2*sec(c + d*x)**2, x) + Integral(3*sin(c + d* x)*tan(c + d*x)**2*sec(c + d*x)**2, x) + Integral(3*sin(c + d*x)**2*tan(c + d*x)**2*sec(c + d*x)**2, x) + Integral(sin(c + d*x)**3*tan(c + d*x)**2*s ec(c + d*x)**2, x))
Time = 0.11 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.39 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^3 \tan ^2(c+d x) \, dx=\frac {a^{3} \tan \left (d x + c\right )^{3} + 3 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, d x + 3 \, c - 3 \, \tan \left (d x + c\right )\right )} a^{3} - a^{3} {\left (\frac {6 \, \cos \left (d x + c\right )^{2} - 1}{\cos \left (d x + c\right )^{3}} + 3 \, \cos \left (d x + c\right )\right )} - \frac {3 \, {\left (3 \, \cos \left (d x + c\right )^{2} - 1\right )} a^{3}}{\cos \left (d x + c\right )^{3}}}{3 \, d} \] Input:
integrate(sec(d*x+c)^2*(a+a*sin(d*x+c))^3*tan(d*x+c)^2,x, algorithm="maxim a")
Output:
1/3*(a^3*tan(d*x + c)^3 + 3*(tan(d*x + c)^3 + 3*d*x + 3*c - 3*tan(d*x + c) )*a^3 - a^3*((6*cos(d*x + c)^2 - 1)/cos(d*x + c)^3 + 3*cos(d*x + c)) - 3*( 3*cos(d*x + c)^2 - 1)*a^3/cos(d*x + c)^3)/d
Time = 0.48 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.13 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^3 \tan ^2(c+d x) \, dx=\frac {9 \, {\left (d x + c\right )} a^{3} - \frac {6 \, a^{3}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1} + \frac {2 \, {\left (9 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 24 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 11 \, a^{3}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right )}^{3}}}{3 \, d} \] Input:
integrate(sec(d*x+c)^2*(a+a*sin(d*x+c))^3*tan(d*x+c)^2,x, algorithm="giac" )
Output:
1/3*(9*(d*x + c)*a^3 - 6*a^3/(tan(1/2*d*x + 1/2*c)^2 + 1) + 2*(9*a^3*tan(1 /2*d*x + 1/2*c)^2 - 24*a^3*tan(1/2*d*x + 1/2*c) + 11*a^3)/(tan(1/2*d*x + 1 /2*c) - 1)^3)/d
Time = 34.02 (sec) , antiderivative size = 212, normalized size of antiderivative = 2.75 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^3 \tan ^2(c+d x) \, dx=3\,a^3\,x+\frac {3\,a^3\,\left (c+d\,x\right )-\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (9\,a^3\,\left (c+d\,x\right )-\frac {a^3\,\left (27\,c+27\,d\,x-66\right )}{3}\right )-\frac {a^3\,\left (9\,c+9\,d\,x-28\right )}{3}+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (9\,a^3\,\left (c+d\,x\right )-\frac {a^3\,\left (27\,c+27\,d\,x-18\right )}{3}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (12\,a^3\,\left (c+d\,x\right )-\frac {a^3\,\left (36\,c+36\,d\,x-54\right )}{3}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (12\,a^3\,\left (c+d\,x\right )-\frac {a^3\,\left (36\,c+36\,d\,x-58\right )}{3}\right )}{d\,{\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-1\right )}^3\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )} \] Input:
int((tan(c + d*x)^2*(a + a*sin(c + d*x))^3)/cos(c + d*x)^2,x)
Output:
3*a^3*x + (3*a^3*(c + d*x) - tan(c/2 + (d*x)/2)*(9*a^3*(c + d*x) - (a^3*(2 7*c + 27*d*x - 66))/3) - (a^3*(9*c + 9*d*x - 28))/3 + tan(c/2 + (d*x)/2)^4 *(9*a^3*(c + d*x) - (a^3*(27*c + 27*d*x - 18))/3) - tan(c/2 + (d*x)/2)^3*( 12*a^3*(c + d*x) - (a^3*(36*c + 36*d*x - 54))/3) + tan(c/2 + (d*x)/2)^2*(1 2*a^3*(c + d*x) - (a^3*(36*c + 36*d*x - 58))/3))/(d*(tan(c/2 + (d*x)/2) - 1)^3*(tan(c/2 + (d*x)/2)^2 + 1))
Time = 0.19 (sec) , antiderivative size = 169, normalized size of antiderivative = 2.19 \[ \int \sec ^2(c+d x) (a+a \sin (c+d x))^3 \tan ^2(c+d x) \, dx=\frac {a^{3} \left (-3 \cos \left (d x +c \right ) \sin \left (d x +c \right )^{2}+9 \cos \left (d x +c \right ) \sin \left (d x +c \right ) d x +11 \cos \left (d x +c \right ) \sin \left (d x +c \right )-9 \cos \left (d x +c \right ) d x -6 \cos \left (d x +c \right )+3 \sin \left (d x +c \right )^{3}+9 \sin \left (d x +c \right )^{2} d x -24 \sin \left (d x +c \right )^{2}-18 \sin \left (d x +c \right ) d x +11 \sin \left (d x +c \right )+9 d x +6\right )}{3 d \left (\cos \left (d x +c \right ) \sin \left (d x +c \right )-\cos \left (d x +c \right )+\sin \left (d x +c \right )^{2}-2 \sin \left (d x +c \right )+1\right )} \] Input:
int(sec(d*x+c)^2*(a+a*sin(d*x+c))^3*tan(d*x+c)^2,x)
Output:
(a**3*( - 3*cos(c + d*x)*sin(c + d*x)**2 + 9*cos(c + d*x)*sin(c + d*x)*d*x + 11*cos(c + d*x)*sin(c + d*x) - 9*cos(c + d*x)*d*x - 6*cos(c + d*x) + 3* sin(c + d*x)**3 + 9*sin(c + d*x)**2*d*x - 24*sin(c + d*x)**2 - 18*sin(c + d*x)*d*x + 11*sin(c + d*x) + 9*d*x + 6))/(3*d*(cos(c + d*x)*sin(c + d*x) - cos(c + d*x) + sin(c + d*x)**2 - 2*sin(c + d*x) + 1))